A paper airplane contest is being held. The following results are found: 80% of the participants used a triangle shape. The triangle shaped planes only won their trials 16% of the time. The other shaped planes won their trials 36% of the time. Create a tree diagram for this situation: What is the probability that a triangle plane won overall?Out of 100 planes, which shape has the most winners?A winning plane is selected at random, what is the chance it is triangle shaped?

Answers

Answer 1

Given:

Percent of participants that used triangles shape = 80% = 0.80

The triangles shaped won their trials 16% of the time = 0.16

The other shaped plane won their trials 36% of the time = 0.36

Thus, we have:

Percent of participants who used other shapes = 100% - 80% = 20% = 0.20

Amount of time the triangle shaped plane lost = 100% - 16% =84% = 0.84

Amount of time the other shaped plane lost = 100% - 36% = 64% = 0.64

Let's solve for the following:

• (a) Create a tree diagram for this situation.

We have the tree diagram below:

• (b) What is the probability that a triangle plane won overall?

To find the probability that a triangle plane won overall, we have:

[tex]P(\text{triangle)}=\frac{0.8\times0.16}{(0.8\times0.16)+(0.2\times0.36)}=\frac{0.128}{0.128+0.072}=0.64[/tex]

• (c) Out of 100 planes, which shape has the most winners?

Given that 80% used triangle, the number of planes with triangle shape will be:

0.8 x 100 = 80 planes

Number of planes with other shape:

0.2 x 100 = 20 planes

Number of winners for traingles:

0.16 x 80 = 12.8

Number of winners for other shape:

0.36 x 20 = 7.2

Therefore, the shape with the most winners is the triangle shape.

• (d),. A winning plane is selected at random, what is the chance it is triangle shaped?

To find the probability a winning plane selected at random is triangle shaped, wehave:

[tex]P(\text{triangle)}=\frac{12.8}{12.8+7.2}=\frac{12.8}{20}=0.64[/tex]

ANSWER:

(b) 0.64

(c) Triangle shape

(d) 0.64



A Paper Airplane Contest Is Being Held. The Following Results Are Found: 80% Of The Participants Used

Related Questions

Finding a final amount in a word problem on exponential growth or decay

Answers

Answer:

19g

Explanation:

Given the starting amount as 155grams, the below amount will be left after the 1st half life;

[tex]\frac{155g}{2}=77.5g[/tex]

After the 2nd half-life, the below amount will remain;

[tex]\frac{77.5g}{2}=38.75g[/tex]

After the 3rd half-life, the below amount will remain;

[tex]\begin{gathered} \frac{38.75}{2}=19.375g\approx19g\text{ (rounding to the nearest gram)} \\ \end{gathered}[/tex]

This relation map is the musician to the instrument they play. is this relation a function?

Answers

[tex]The\text{ relationship is not a function because Rafeal has two different results}[/tex]

Factoring

64v^4-225w^10


I come up with

(8v^2+15w^2)(8v^2-15w^5) can I simplify it?

Answers

Your answer can't be simplified but it's also slightly incorrect. No worries!

You can simplify (64v^4 - 225w^10) by applying the difference of squares --> a^2 - b^2 = (a + b)(a - b)

Here, (64v^4) is a^2, and (225w^10) is b^2.

[tex]\sqrt{64v^4 }[/tex] = a = 8v^2

[tex]\sqrt{225w^{10} }[/tex] = b = 15w^5

Substitute the values:

(8v^2 + 15w^5)(8v^2 - 15w^5)

Therefore, the factorization of [tex]64x^{4} -225w^{10}[/tex] is:

[tex](8v^{2} + 15w^5)(8v^2-15w^5)[/tex]

The factorization is already the simplest. It can't be simplified further.

Abby scored 88, 91, 95, and 89 on her first four history quizzes. What score does Abby need to get on her fifth quiz to have an average of exactly 90 on her history quizzes? a.85b.86c.87a.88

Answers

Solution

For this case we can use the definition of average given by:

[tex]\text{Mean}=\frac{x_1+x_2+x_3+x_4+x_5}{5}[/tex]

The final score needs to be 90 so we can do this:

[tex]90=\frac{88+91+95+89+x_5}{5}[/tex]

And solving for x5 we got:

5*90 = 88+91+95+89+ x5

x5= 450 - 88- 91- 95 -89 = 87

Final answer:

c.87

Could you help me with this please is from apex

Answers

Answer:

Completing the table we have;

Explanation:

Given the table in the attached image, we want to complete the table;

[tex]\text{Interest is 1\% compounded monthly}[/tex]

For period 1;

simple interest;

[tex]i_1=Prt=100\times0.01\times1=\text{ \$1.00}[/tex]

Compound interest;

[tex]\begin{gathered} f_1=P(1+\frac{r}{n})^{nt}=100(1+\frac{1}{12})^{1(12)}=\text{ \$}101.00 \\ \text{ Interest = }101.00-100=\text{ \$1.00} \end{gathered}[/tex]

For period 2;

simple interest;

[tex]i_2=Prt=100\times0.01\times1=\text{ \$1.00}[/tex]

compound interest;

[tex]\begin{gathered} f_2=P(1+\frac{r}{n})^{nt} \\ P=f_1=101.00 \\ =101(1+\frac{1}{12})^{1(12)}=\text{ \$}102.01 \\ \text{Interest}=102.01-101=\text{ \$}1.01 \end{gathered}[/tex]

Total interest

simple interest;

[tex]i_t=i_1+i_2=1+1=\text{ \$2.00}[/tex]

Compound Interest;

[tex]\text{ Total interest}=1.00+1.01=\text{ \$2.01}[/tex]

Therefore, completing the table we have;

Picture of question linked. The choices for the answer are -infinity, infinity, and 0

Answers

[tex]f(x)=-x^9-3x^5-5x^3+1[/tex]

The behavior of any polynomial function is determined by the exponent and the signal of the first term of the function.

In the case of f(x), the leading term is negative, and its expoent is odd. Therefore, when x is negative, the leading term will be positive and, when x is positive, the leading term is negative.

Therefore, we have:

[tex]\begin{gathered} As\text{ }x\rightarrow-\infty,\text{ }f(x)\rightarrow\infty \\ As\text{ }x\rightarrow\infty,\text{ }f(x)\rightarrow-\infty \end{gathered}[/tex]

How would you use the Pythagorean Theorem to find the missing length in the triangle shown? Find the missing length.

Answers

The given triangle is a right angle triangle. The pythagorean theorem is expressed as

hypotenuse^2 = one leg^2 + other leg^2

From the diagram,

hypotenuse = AB = c

one leg = BC = 9

other leg = AC = 12

By applying the pythagorean theorem, we have

[tex]\begin{gathered} c^2=9^2+12^2\text{ = 81 + 144} \\ c^2\text{ = 225} \\ c\text{ = }\sqrt[]{225} \\ c\text{ = 15} \end{gathered}[/tex]

The missing length is 15 cm

Create an equation that models the table below. Use the variables in the table for your equation. Write your equation with 'S' isolated.

Answers

The table show piszzas (P) on the left column and the slices of Pepperonin (S) on the right column.

To determine the equation models first check the ratio S/P to determine whether they are proportinal or not.

[tex]\begin{gathered} \frac{36}{3}=12 \\ \frac{96}{8}=12 \\ \frac{228}{19}=12 \end{gathered}[/tex]

Now as the ratios are constant it mean the variation is linear and the relationship is proportional.

Thus the model equation can be determine as,

[tex]\begin{gathered} \frac{S}{P}=12 \\ S=12P \end{gathered}[/tex]

Thus, the above equation gives the required model equation.

Find the perimeter of LMNPQ if the perimeter of ABCDE = 25.2 cm and ABCDE = LMNPQ

Answers

If two polygons are similar with the lengths of corresponding sides, we need to find the ratio between both figures:

Then:

[tex]\frac{SIDE\text{ PQ}}{\text{SIDE DE}}=\frac{25}{15}=\frac{5}{3}=\text{ 1,666}[/tex]

So, the ratio is 5:3

The perimeter of LMNPQ is the same to say :

P of ABCDE = 25.2cm

Use the ratio

P of LMNPQ = 25.2 (5/3) cm

Then P = 42 cm

What are all the factors of 54?

Answers

To find the factors of a number, we can look for factors to divide it by subsequently.

It is easier to start with lower factors.

Let's start by "2".

Since "54" is even, it is divisable by "2":

[tex]\frac{54}{2}=27[/tex]

So "2" is one of the factors.

Now, we have got 27. It is not even anymore, but it is divisable by "3":

[tex]\frac{27}{3}=9[/tex]

So "3" is another factor.

Now we have got "9" and it is also divisable by "3":

[tex]\frac{9}{3}=3[/tex]

So there is another "3" factor.

And since we have got now another "3", we know it is divisable by "3":

[tex]\frac{3}{3}=1[/tex]

Now we have got to "1", so we found all the prime factors:

[tex]54=2\cdot3\cdot3\cdot3[/tex]

Now,, we need to combine them to find all possible combinations.

We will start from low to high.

"1" is always a factor.

There is "2" there, so it is also a factor.

Then we have "3" as another factor.

There is no need to combine "1" with another factor, so we will start b combining 2 and 3:

[tex]2\cdot3=6[/tex]

So, "6" is another factor.

We can combine 3 with 3:

[tex]3\cdot3=9[/tex]

"9" is another factor.

Now we start combining three of them:

[tex]\begin{gathered} 2\cdot3\cdot3=6\cdot3=18 \\ 3\cdot3\cdot3=9\cdot3=27 \end{gathered}[/tex]

So, "18" and "27" are factors.

And now we combine 4 of them, but this is get us back to "54" which is the last factor.

So, the factors of 54 are: 1, 2, 3, 6, 9, 18, 27, 54.

Answer:

Step-by-step explanation:

1 × 54 = 54, (1, 54) is a pair factor of 54.

2 × 27 = 54, (2, 27) is a pair factor of 54

3 × 18 = 54, (3, 18) is a pair factor of 54

6 × 9 = 54, (6, 9) is a pair factor of 54

Therefore, the positive pair factors are (1, 54), (2, 27),(3, 18) and (6, 9).

You have 4/5 of a pizza left over from your pool party. If you sent 4/9 of the leftover pizza home with your friends how much of the pizza do you have left in the box

Answers

If I sent 4/9 of the leftover pizza home with your friends the pizza do I have left in the box is 16/45.

What is pizza?

Pizza is an Italian food consisting of a typically flat, spherical foundation composed of leavened wheat dough that is topped with cheese, tomatoes, and frequently a number of additional toppings. Following that, the pizza is baked at a high temperature, typically in a wood-fired oven. A small pizza is also known as a pizzetta. A pizza maker is referred to as a pizzaiolo.

To get the quantity of the leftover pizza, we need to subtract the pizza sent by me to home from the total pizza I had in my lunch box.

So,

Pizza I have left = Pizza in lunch box - Pizza I have sent

Pizza I have left = 4/5 - 4/9  

Pizza I have left = (4(9) - 4(5))/45

Therefore, Pizza I have left is 16/45.

To know more about Pizza, go to link

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Angles A and B are adjacent on a straight line. Angle A has a measure of (2r +20) and angle B has a measure of 130.. What is the measure of r?

Answers

When two angles are adjacent on a straight line, then the sum of the two angles equals 180 (that is sum of angles on a straight line). Therefore;

[tex]\begin{gathered} (2r+20)+130=180 \\ \text{Subtract 130 from both sides and you'll have} \\ 2r+20=50 \\ \text{Subtract 20 from both sides and you'll have} \\ 2r=30 \\ \text{Divide both sides by 2 and you'll have} \\ r=15 \end{gathered}[/tex]

The measure of r is 15

Not sure on how to do this. Could really use some help.

Answers

We will have the following:

We will recall that the surface area of a sphere is given by:

[tex]A_s=4\pi r^2[/tex]

So, the surface area of the given sphere will be:

[tex]\begin{gathered} A_s=4\pi(\sqrt{\frac{7}{3.14}})^2\Rightarrow A_s=4(3.14)\ast\frac{7}{3.14} \\ \\ \Rightarrow A_s=4\ast7\Rightarrow A=28 \end{gathered}[/tex]

So, the surface area of the sphere will be 28 yd^2.

*The reason we can use "mental math" is that we are using an approximation of pi, which makes it so it cancels with the 3.14 in the denominator after a point; leaving a simple multiplication at the very end.

The height of the Empire State Building is 1250 feet tall. Your friend, who is 75 inches tall, is standing nearby and casts a shadow that is 33 inches long. What is the length of the shadow of the Empire State Building? Please help me draw triangles

Answers

Answer:

The length of the building's shadow = 550.66 ft

Explanations:

The height of the Empie State Building = 1250 feet

The friend's height = 75 inches

The length of the friend's shadow = 33 inches

[tex]\frac{Actual\text{ height of the friend}}{\text{Length of the friend's shadow}}=\text{ }\frac{Height\text{ of the building}}{\text{Length of the building's shadow}}[/tex][tex]\begin{gathered} \frac{75}{33}=\text{ }\frac{1250}{\text{Length of the building's shadow}} \\ 2.27\text{ = }\frac{1250}{\text{Length of the building's shadow}} \\ \text{Length of the building's shadow = }\frac{1250}{2.27} \\ \text{Length of the building's shadow = }550.66\text{ f}et \end{gathered}[/tex]

Hello everybody! I would really appreciate it if Somebody could give me the answer for this question and give a brief explanation on how they got it. Look at the photo for instructions!

Answers

Recall that the constant of variation of a straight line is the slope of the line.

To compute the slope we will use the following formula for the slope of a line:

[tex]s=\frac{y_2-y_1}{x_2-x_1}\text{.}[/tex]

Now, notice that points (-1,3) and (1,-3) are on the line, then substituting these points in the above formula we get:

[tex]s=\frac{3-(-3)}{-1-1}=\frac{6}{-2}=-3.[/tex]

Answer: -3.

Estimate the time it would take you to drive 278 miles at38 miles per hour. Round to the nearest hour

Answers

Speed formula:

[tex]s=\frac{d}{t}[/tex]

d is the distance

t is the time

As you need to find a time having the distance and speed, solve the equation above for t:

[tex]\begin{gathered} t\cdot s=d \\ t=\frac{d}{s} \end{gathered}[/tex]

Use the given data to find the time:

[tex]\begin{gathered} t=\frac{278mi}{38mi/h} \\ \\ t=7.31h \\ \\ t=7h \end{gathered}[/tex]Then, it would take you 7 hours to drive 278 mi at 38mi/h

I need answer for this word problems you have to shown that you can make several lattes then you add milk and begin to stirring. you use a total of 30 ounces of liquid. write an equation that represents the situation and explain what the variable represents.

Answers

hello

the question here is a word problem and we can either use alphabhets to represent the variables.

let lattes be represented by x and milk be represented by y

[tex]x+y=30[/tex]

since the total ounce of liquid is equals to 30, we equate the whole sentence to 30.

What is 16.02+8.5+14 ?? i want to know for a home work

Answers

Given:

[tex]16.02\text{ + 8.5 + 14}[/tex]

To solve,

Step 1:

Express each value to a common decimal place.

We can express each value to two decimal places.

Thus, we have

[tex]16.02+8.50+14.00[/tex]

Step 2:

Sum up the values.

Hence, 16.02 + 8.5 + 14 gives 38.52.

In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units. Find BC.

Answers

Answer:

29 units

Step-by-step explanation:

BC is a side of ACB, which is a 45 45 90 triangle. BC = AB/sqrt2

If In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units. Then BC is 29 units

What is Trigonometry?

Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.

Given,

In △ABC, m∠A=45°. The altitude divides side AB into two parts of 20 and 21 units.

We need to find BC

In triangle ACD,

tan 45° = CD/AD

CD = tan 45° x AD

= 1 x 20= 20 units

In triangle CDB,

tanФ = CD/BD

Ф = tan⁻¹(CD/BD)

= tan⁻¹(20/21)

= 43.6°

so, sin 43.6° = CD/BC

BC = CD/sin 43.6°

= 20/0.689

= 29 units

Hence the length of BC will be 29 units.

To learn more on trigonometry click:

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Find the measures in the parallelogram4. Find AB and AC

Answers

Okay, here we have this:

Considering that in a parallelogram the opposite sides are congruent, we obtain the following:

AB=CD

AB=9 units

AC=BD

AC=4 units

on a horizontal line segment, point A is located at 21, point b is located at 66. point p is a point that divides segment ab in a ratio of 3:2 from a to b where is point p located

Answers

We have a one-dimensional horizontal line segment. Three points are indicated on the line as follows:

In the above sketch we have first denoted a reference point at the extreme left hand as ( Ref = 0 ). This is classified as the origin. The point ( A ) is located on the same line and is at a distance of ( 21 units ) from Reference ( Ref ). The point ( B ) is located on the same line and is at a distance of ( 66 units ) from Reference ( Ref ).

The point is located on the line segment ( AB ) in such a way that it given as ratio of length of line segment ( AB ). The ratio of point ( P ) from point ( A ) and from ( P ) to ( B ) is given as:

[tex]\textcolor{#FF7968}{\frac{AP}{PB}}\text{\textcolor{#FF7968}{ = }}\textcolor{#FF7968}{\frac{3}{2}\ldots}\text{\textcolor{#FF7968}{ Eq1}}[/tex]

The length of line segment ( AB ) can be calculated as follows:

[tex]\begin{gathered} AB\text{ = OB - OA } \\ AB\text{ = ( 66 ) - ( 21 ) } \\ \textcolor{#FF7968}{AB}\text{\textcolor{#FF7968}{ = 45 units}} \end{gathered}[/tex]

We can form a relation for the line segment ( AB ) in terms of segments related to point ( P ) as follows:

[tex]\begin{gathered} \textcolor{#FF7968}{AB}\text{\textcolor{#FF7968}{ = AP + PB }}\textcolor{#FF7968}{\ldots}\text{\textcolor{#FF7968}{ Eq2}} \\ \end{gathered}[/tex]

We were given a ratio of line segments as ( Eq1 ) and we developed an equation relating the entire line segment ( AB ) in terms two smaller line segments as ( Eq2 ).

We have two equation that we can solve simultaneously:

[tex]\begin{gathered} \textcolor{#FF7968}{\frac{AP}{PB}}\text{\textcolor{#FF7968}{ = }}\textcolor{#FF7968}{\frac{3}{2\text{ }}\ldots}\text{\textcolor{#FF7968}{ Eq1}} \\ \textcolor{#FF7968}{AB}\text{\textcolor{#FF7968}{ = AP + PB }}\textcolor{#FF7968}{\ldots Eq2} \end{gathered}[/tex]

Step 1: Use Eq1 and express AP in terms of PB.

[tex]AP\text{ = }\frac{3}{2}\cdot PB[/tex]

Step 2: Substitute ( AP ) in terms of ( PB ) into Eq2

[tex]AB\text{ = }\frac{3}{2}\cdot PB\text{ + PB}[/tex]

We already determined the length of the line segment ( AB ). Substitute the value in the above expression and solve for ( PB ).

Step 3: Solve for PB

[tex]\begin{gathered} 45\text{ = }\frac{5}{2}\cdot PB \\ \textcolor{#FF7968}{PB}\text{\textcolor{#FF7968}{ = 18 units}} \end{gathered}[/tex]

Step 4: Solve for AP

[tex]\begin{gathered} AP\text{ = }\frac{3}{2}\cdot\text{ ( 18 )} \\ \textcolor{#FF7968}{AP}\text{\textcolor{#FF7968}{ = 27 units}} \end{gathered}[/tex]

Step 5: Locate the point ( P )

All the points on the line segment are located with respect to the Reference of origin ( Ref = 0 ). We will also express the position of point ( P ).

Taking a look at point ( P ) in the diagram given initially we can augment two line segments ( OA and AP ) as follows:

[tex]\begin{gathered} OP\text{ = OA + AP} \\ OP\text{ = 21 + 27} \\ \textcolor{#FF7968}{OP}\text{\textcolor{#FF7968}{ = 48 units}} \end{gathered}[/tex]

The point ( P ) is located at.

Answer:

[tex]\textcolor{#FF7968}{48}\text{\textcolor{#FF7968}{ }}[/tex]

it snowed 20 inches in 10 days in Montreal. Find the unit rate.

Answers

the expression is

[tex]\frac{20}{10}[/tex]

We must divide each value by the value of the denominator to obtain the unit ratio

so

[tex]\frac{\frac{20}{10}}{\frac{10}{10}}=\frac{2}{1}=2[/tex]

the unit ratio is 2 inches per day

Picture explains it all

Answers

Answer: .1$ so 10cents

Step-by-step explanation:

Answer is $0.10 for 10 pieces

Step by step

$10/1000 pieces = $0.01 per piece of candy

Multiply your rate x 10 pieces = $0.10

Basically, the question is asking to solve a problem about rectangular prisms. It says the the shape of one box, with (h) height in feet, has a volume defined by the function:V(h) = h (h-5)(h-6)It says to graph the function. What is the maximum volume for the domain 0

Answers

The function representing the volume of the rectangular prism is given to be:

[tex]V(h)=h(h-5)(h-6)[/tex]

Since we are expected to find the volume using the graph, we can prepare a table of values for the function using values of h as integers from 1 - 5, such that:

[tex]\begin{gathered} At\text{ }h=1 \\ V(1)=1(1-5)(1-6)=-4\times-5=20 \end{gathered}[/tex]

The completed table is shown below:

Hence, we can plot these points on a graph using a graphing calculator for ease of work. This is shown below:

The maximum volume of the prism is represented by the highest point on the graph. The graph's highest point is at:

[tex]h=1.811[/tex]

The corresponding value for the volume as can be seen on the graph is:

[tex]V=24.193[/tex]

This is the maximum volume of the prism.

To the nearest cubic foot, the maximum volume of the rectangular prism is 24 cubic feet.

I need help with question 4-8, can you please help me?Use f(X) as g(X) for question 5 and 6

Answers

Question 4

The x values for which g(x) = 3

From the graph, we have this value to be:

[tex]0\text{ }\leq\text{ x }\leq\text{ 2}[/tex]

Question 5

f(x) = 6, What is x?

From the graph, we can determine the value of x corresponding to f(x)= 6:

[tex]x\text{ = }4[/tex]

Question 6:

f(x)= 0, What is x?

From the graph, we can determine the value of x corresponding to f(x) = 0

[tex]x\text{ = 7}[/tex]

Question 7

The domain of the function:

The domain is the set of allowable inputs.

[tex]\lbrack0,\text{ 12\rbrack}[/tex]

Question 8

The range is the set outputs

[tex]\lbrack0,\text{ 6\rbrack}[/tex]

when his bus arrives Calvin is 40 ft east of the corner the door of the bus is 30 feet north of the corner how far will Calvin run directly across the field to the bus

Answers

Since this situation can be represented by a right triangle, we can use the pythagorean theorem. Doing so, we have:

[tex]\begin{gathered} a^2+b^2=c^2\text{ } \\ (30)^2+(40)^2=c^2\text{ (Replacing)} \\ 900+1600=c^2\text{ (Raising both numbers to the power of 2)} \\ 2500=c^2\text{ (Adding)} \\ \sqrt[]{2500}=\sqrt[]{c^2} \\ 50=c\text{ (Taking the square root of both sides)} \\ \text{The answer is 50 ft} \end{gathered}[/tex]

Can you please help with 44For the following exercise, sketch a graph of the hyperbola, labeling vertices and foci

Answers

We have the following equation of a hyperbola:

[tex]4x^2+16x-4y^2+16y+16=0[/tex]

Let's divide all the equations by 4, just to simplify it

[tex]x^2+4x-y^2+4y+4=0[/tex]

Just to make it easier, let's put the term if "x" isolated

[tex]x^2+4x=y^2-4y-4[/tex]

Now we can complete squares on both sides, just remember that

[tex]\begin{gathered} (a+b)^2=a^2+2ab+b^2 \\ \\ (a-b)^2=a^2-2ab+b^2 \end{gathered}[/tex]

Now let's complete it!

[tex]\begin{gathered} x^2+4x=y^2-4y-4\text{ complete adding 4 on both sides} \\ \\ x^2+4x+4=y^2-4y-4+4 \\ \\ (x+2)^2=y^2-4y \\ \end{gathered}[/tex]

We already completed one side, now let's complete the side with y^2, see that we will add 4 again, then

[tex]\begin{gathered} (x+2)^2=y^2-4y \\ \\ (x+2)^2+4=y^2-4y+4 \\ \\ (x+2)^2+4=(y-2)^2 \end{gathered}[/tex]

And now we can write it using the standard equation!

[tex]\begin{gathered} (y-2)^2-(x+2)^2=4 \\ \\ (y-2)^2-(x+2)^2=4 \\ \\ \frac{(y-2)^2}{4}-\frac{(x+2)^2}{4}=1 \end{gathered}[/tex]

And now we can graph it like all other hyperbolas, the vertices will be:

[tex](-2,4)\text{ and }(-2,0)[/tex]

And the foci

[tex]\begin{gathered} c^2=a^2+b^2 \\ \\ c^2=2^2+2^2 \\ \\ c^2=2\cdot2^2 \\ \\ c^{}=2\, \sqrt[]{2} \end{gathered}[/tex]

Then the foci are

[tex](-2,2+2\, \sqrt[]{2})\text{ and }(-2,2-2\, \sqrt[]{2})[/tex]

Now we can plot the hyperbola!

A middle school football game has four 12-minute quarters. Jason plays 8 minutes in each quarter.Which ratio represents Jason's playing time compared to the total number of minutes of playing time possible?1 to 3 2 to 33 to 24 to 1I’m

Answers

The total minutes in the game is 48. The total playing game for Jason is 32. The ratio is

[tex]\frac{32}{48}[/tex]

Simplifying it, we have

[tex]\frac{32}{48}=\frac{16}{24}=\frac{8}{12}=\frac{4}{6}=\frac{2}{3}[/tex]

So, the playing ratio is 2 to 3 for Jason.

I absolutely dont understand Division Property of Equality please help

Answers

We have the following equation.

[tex]20,000-1.8939m=10,000[/tex]

Where m is the number of feet in a mile.

Let us subtract 20,000 from both sides of the equation then simplify

[tex]\begin{gathered} -20,000+20,000-1.8939m=10,000-20,000 \\ -1.8939m=-10,000 \end{gathered}[/tex]

The negative sign cancels out and the equation becomes

[tex]\text{1}.8939m=10,000[/tex]

Finally, we can apply the Division Property of Equality which states that when we divide both sides of the equation with same number then the equation remains valid.

Let us divide both sides of the equation by 1.8939 then simplify

[tex]\begin{gathered} \frac{1.8939m}{1.8939}=\frac{10,000}{1.8939} \\ m=\frac{10,000}{1.8939} \\ m\approx5280 \end{gathered}[/tex]

Therefore, there are 5280 feet in a mile (rounded to nearest whole number)

The Wong family and the Nguyen family each used their sprinklers last summer. The water output rate for the Wong familys sprinkler was 35 L per hour. The water output for the Nguyen familys sprinkler was 20 L per hour. The families used their spirit for a combined total of 75 hours, resulting in a total water output of 2100 L. How long was each sprinkler used?

Answers

Let W be the time of the wong family and N the time of the Nguyen family. We are told that the output rate of the Wong family is 35 L/h and the output for the Nguyen family is 20 L/h, if the total water output is 2100 L, then we can write this mathematically as:

[tex]35W+20N=2100,(1)[/tex]

Where "35W" is the total water output of the wong family and "20N" is the total water output of the Nguyen family. The two outputs combined must be 2100. We are also told that the total time is 75 hours, therefore we have:

[tex]W+N=75,(2)[/tex]

We get a system of two equations and two variables. We can solve for "W" in equation (2), by subtracting "N" from both sides:

[tex]W=75-N[/tex]

Now we can replace this value in equation (1):

[tex]35(75-N)+20N=2100[/tex]

Now we apply the distributive property:

[tex]2625-35N+20N=2100[/tex]

Now we add like terms;

[tex]2625-15N=2100[/tex]

Now we subtract 2625 from both sides:

[tex]\begin{gathered} -15N=2100-2625 \\ -15N=-525 \end{gathered}[/tex]

Now we divide both sides by 15:

[tex]N=-\frac{525}{-15}=35[/tex]

Now we replace this value in equation (2) where we already solved for W:

[tex]\begin{gathered} W=75-35 \\ W=40 \end{gathered}[/tex]

Therefore, the time for the Wong family is 40 hours and the Nguyen family is 35 hours.

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