The electric field in front of the wall will be 4.61 × 10⁹ N/C.
What is the electric field?An electrostatic force is a natural environment that covers electric polarization and acts as an attractor or repellent to all other energetic particles in the vicinity. It can also refer to a network of charged particles' test performance.
The electric field is given as,
E = σ / 2ε₀
Where σ is the charge per unit area, ε is the permeability (8.85 x 10⁻¹² N-m² / C²).
A non-conducting wall carries a charge with a uniform density of 8.15 µc / square cm.
The charge per unit area of the wall will be
σ = 8.15 × 10⁻⁶ C/cm²
σ = (8.15 × 10⁻⁶ C/cm²) × (100 cm / m)²
σ = 8.15 × 10⁻² C/m²
Then, at a distance of 2.00 cm, the electric field will be
E = 8.15 × 10⁻² / 2(8.85 x 10⁻¹²)
E = 4.61 × 10⁹ N/C.
The electric field in front of the wall will be 4.61 × 10⁹ N/C.
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a copper cube has a mass of 153.6g the density of copper is 8.96g/cm3 calculate both the volume of the cube in cm3 and also the edge length in cm
The Volume of Copper Cube with mass 153.6 g and density 8.96 g/cm³ is 17.14 cm³ and its Edge is 2.58 cm long.
We have a Copper Cube of mass 153.6 g and density 8.96 g/cm³.
We have to calculate the volume and length of the cube in cm³ and cm respectively.
How is density and mass of body related ?The density and mass of body are related as follows -
M = ρV
Where -
M - mass of body
ρ - density of body
According to the question, we have →
Mass of copper cube = 153.6 g
Density of copper cube = 8.96 g/cm³
Using the formula discussed above -
M = ρV
V = M/ρ = 153.6/8.96 = 17.14 cm³
We know that the volume of cube is -
V = a x a x a
a³ = 17.14 cm³
a = 2.58 cm
Hence, the Volume of Cube is 17.14 cm³ and its Edge is 2.58 cm long.
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a torque of 12 n ∙ m is applied to a solid, uniform disk of radius 0.50 m. if the disk accelerates at 1.60 rad/s^2, what is the mass of the disk?
Mass of disc m =16.84 kg
Moment of inertia of disc about axis perpendicular to the plane of disc and passing through its centre = MR²/2
12 = MR²/2 × 5.7
12 = M(0.5)²/2 × 5.7
Mass = 12 × 2 /5.7 × 0.5² = 16.84 Kg
The atomic mass of an detail is described because the weighted common mass of that detail’sThe atomic mass of an detail is described because the weighted common mass of that detail’s is False
Atomic mass (Also referred to as Atomic Weight, even though this denomination is incorrect, for the reason that mass is belongings of the frame and the burden relies upon at the gravity) Mass of an atom similar to a positive chemical detail). mean "unit of atomic mass". This unit is likewise typically referred to as Dalton (Da) in honor of the English chemist John Dalton.
It is equal to 1 12th of the mass of the nucleus of the maximum ample isotope of carbon, carbon-12. It corresponds more or less to the mass of a proton (or a hydrogen atom). It is abbreviated as "uma", even though it could additionally be located with the aid of using its English acronym "amu" (Atomic Mass Unit). However, the advocated image is simply "u".
The atomic masses of chemical factors are typically calculated using the weighted average of the masses of the exceptional isotopes of each detail while taking into account the relative abundance of each one. This is the cause of the discrepancy between an element's atomic mass in umas and the range of nucleons that contains the nucleus of its maximum uncommon place isotope.
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An auto dealer has 4 different cars and 6 different trucks. how many ways are there to select two vehicles?
There are C different ways to choose two different automobiles (12, 2).
In mathematics, a choice is made from a set of various components where the order of the choices is unimportant (unlike permutations).
For instance, there are three conceivable combinations of two given fruits, such as an apple, an orange, and a pear: an apple and a pear; an orange and an apple; or an orange and a pear. Formally speaking, a set S's k unique components make up a subset known as a k-combination. In other words, two combinations are same only if all of their members are the same.
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. A 2 kg ball is thrown with an acceleration of 40 m/s². What is the
force exerted on the ball?
When a 2 kg ball is thrown with an acceleration of 40 m/s². The
force exerted on the ball is 80 N.
According to Newton's second law of motion
F = ma
where, F = force exerted on the object, m = mass of an object and a = acceleration of the object.
Here, m = 2 kg, a = 40 m/s². so, F = ?
Therefore, force (F) exerted on the ball = 40x2 = 80 N
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What would the shape of the graph be if a speed of 50.0 km/hr is maintained from
10 s to 20 s? I
Answer:
The graph would increase constantly as shown above until it reached 50m/s. At 10s, the graph would be flat at 50m/s until 20s.
Explanation:
A flat slab of styrofoam, with a density of 32 kg/m3, floats on a lake. what minimum volume must the slab have so that a 45 kg boy can sit on the slab without it sinking?
Minimum volume must the slab have so that a 45 kg boy can sit on the slab without it sinking is 0.465 m³.
What is buoyant force?
The buoyant force is the upward force exerted on an item that is fully or partially submerged in a fluid. This upward thrust is also known as an upthrust. Because of the buoyant force, a body submerged partially or entirely in a fluid appears to be lighter or to lose weight.
Given:
Density of the styrofoam, ρ' = 32 kg/m³
Now, let the volume of the slab = V
the submerged volume be = V ;
now, the volume of water displaced will be V
thus,
the buoyant force acting will be = ρVg
{where,
ρ is the density of water
g is the acceleration due to gravity}
now,
total downward force acting = weight of the boy + weight of the slab
total downward force acting =45 × g + ρ' × V × g
For the no sinking condition, buoyant force should be equal to the total downward force.
thus,
ρ × V × g = 45 × g + ρ' × V × g
or
ρ × V = 45 + ρ' × V
on substituting the values
V ( 1000 - 32 ) = 45 ;
or
V = 0.465 m³
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A piece of copper foil has a mass of 3.1118 g, a length of 12.10 cm, and a width of 11.67 cm. assuming the foil has a uniform thickness, what is its thickness in units of mm?
The correct answer is 0.024cm.
The density of a substance determines how heavy it will be in a given volume. It is technically the mass of that material per unit volume. It is implied by this that a specific material weighs a specific quantity relative to its volume.
A substance's density determined how heavy it would be at a particular size. It is an inherent quality that is not affected by geography, such as a shift in the globe.
density of copper = 8.93 g/cm3
mass = 3.1118 g
Density= mass/volume
8.93= 3.1118 /volume
volume=3.1118/8.93
=0.348 cm^3
Volume = l×b×t
T= volume/ l×b
=0.348 cm^3/12.10×11.67
=0.348 /141.2
=0.0024×10mm
=0.024cm
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a 0.900 kgkg block is attached to a spring with spring constant 13.0 n/mn/m . while the block is sitting at rest, a student hits it with a hammer and almost instantaneously gives it a speed of 41.0 cm/scm/s . what are
A 0.900 kg block that is attached to a spring with spring constant 13.0 n/m when hit with the hammer has the amplitude of oscillation as 11.637 x 10^-3 cm.
Concept of spring force:When an object’s motion repeats in a predetermined cycle, it is said to be in periodic motion. The motion described here is an oscillation.
Spring and pendulum motion are two straightforward instances of oscillations, but there are numerous additional instances as well.
The fact that the item is in a stable equilibrium position is a key characteristic of periodic motion. A restorative force that is pointed in that direction as well. The application of force occurs in spring.
If x is the compression of the spring after it is hit,
1/2 k x² = 1/2 m v²
13 x² = .90 x (41 x 10⁻²)² 1681
x² = 116.37 x 10⁻⁴
x = 11.637 x 10^-5m
11.637 x 10^-3 cm
Amplitude of oscillation = 11.637 x 10^-3 cm
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a rower wanted to determine the speed of a river's current prior to going down a particular section of the river. she released a tracker into the river. the tracker sent her back the following information: after 4 seconds since the tracker was released into the river the tracker had traveled 7 meters. after 10.6 seconds since the tracker was released into the river the tracker had traveled 17.5 meters. assuming the river was flowing at a constant speed, what was the speed of the current on this section of the river?
The part of river's current moves at a 1.486 m/s speed.
the distance between two points, objects, lines, etc. Remoteness is the quality of being physically separated from another thing or person. a line drawn in the universe. To walk seven miles in one hour would be too time-consuming.
The difference between the change in distance and the change in time is used to compute the rate of change.
Rate: times the distance Time
The distance is 16.5 miles, and the time is 5.5 hours.
If we enter this into the formula above, it yields:
16.5 - 5.5 / 10.9 - 3.5 = 11/7.4 = 1.486 m/s is the rate of change.
Calculations show that the constant rate of change is 1.486 m/s.
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A cheetah is running at a speed of 18.0 m/s in a direction of 54° north of west. Find the components of the cheetah's velocity along the following directions.
(a) the velocity component due north
b) the velocity component due west
The velocity component due north of the cheetah is 14.56 m/s.
The velocity component due west is 10.58 m/s.
Component's of the cheetah's velocity
The component's of the cheetah's velocity is calculated as follows;
velocity component due northVy = V sinθ
Vy = 18 m/s x sin(54)
Vy = 14.56 m/s
velocity component due westVx = V cosθ
Vx = 18 m/s x cos(54)
Vx = 10.58 m/s
Thus, the velocity component due north of the cheetah is 14.56 m/s.
The velocity component due west is 10.58 m/s.
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Ice is melting a.conclusion b.observation c.experimentation d.inference
Answer:
b. Observation
Explanation:
You see ice melt in an experiment, so you record that as one of your observations.
8. Paige dropped a ball out of a car while her friend Destiny was traveling at a velocity of 25
m/s. The ball underwent a deceleration of -2m/s² and rolled to a stop on the pavement. How
long did it take the ball to stop?
Answer:
I think it's 12.5s
Explanation:
Bare with me, because I just started physics, but I think I have the answer right... Hopefully.
starting with your knowns, we know velocity is 25 m/s from the problem. you also can figure out your acceleration, -2 m/s.
You're looking for the time it takes until the ball stops rolling. Your time is unknown.
Your equation would be a=v/t (acceleration being a, velocity being v, and time being t)
You have to solve for t giving you t=v/a
Now you have to fill in your numbers. t=25m/s divided by -2m/s^2
Your answer should end up as -12.5
You have to solve for your units, but since you're finding time it's pretty straightforward in knowing you're dealing with seconds.
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What are some best practices for different exercises and sports performed:
at high altitude?
in hot weather?
in cold weather?
the g string on a guitar is a 0.44-mm-diameter steel string with a linear density of 1.1 g/m . when the string is properly tuned to 196 hz, the wave speed on the string is 250 m/s. tuning is done by turning the tuning screw, which slowly tightens-and stretches-the string.
The g - string will stretch by 0.0016 mm.
We have a g - string of a guitar with given specifications.
We have to determine how many mm does a 75-cm-long g - string stretch when it’s first tuned.
According to the question -
The force of tension in the string -
[tex]$v = \sqrt{\frac{T}{\mu} }[/tex]
T = [tex]$v^{2} \mu[/tex] = 250 x 250 x 0.0011 = 68.75 N
The Yung modulus of steel = 2 x [tex]10^{11}[/tex] N/[tex]m^{2}[/tex]
the amount by which the g - string will be stretched is given by -
[tex]$\delta L = \frac{LT}{Y(\pi r^{2})}[/tex]
Substituting the values -
[tex]$\delta L = \frac{0.75\times 68.75 }{(2\times 10^{11} )\times (\pi (2.2 \times 10^{-4}\times 2.2\times 10^{-4}) )}[/tex]
[tex]\delta L=[/tex] 0.0016mm
Hence, the g - string will stretch by 0.0016 mm.
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[ The given question is incomplete. The complete question is
" The G string on a guitar is a 0.46-mm-diameter steel string
with a linear density of 1.1 g/m. When the string is properly
tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning
is done by turning the tuning screw, which slowly tightens—and
stretches—the string. By how many mm does a 75-cm-long G
string stretch when it’s first tuned? "]
what is fmin,1, the lowest frequency that will produce the maximum intensity (imax) at the observer, assuming the observer would still hear the intensity of 6 w/m2 when either s1 or s2 is sounded alone?
The lowest 19.152 [tex]\frac{w}{m^{2} }[/tex] frequency that will produce the maximum intensity (Imax) at the observer, assuming the observer will still hear an intensity of 6 w/m2 when [tex]S_{1}[/tex] or [tex]S_{2}[/tex] is heard alone.
We have [tex]I_{1} =I_{2}[/tex]
[tex]= 6 w/m^{2}[/tex]
Path difference
δ = 5.6568 - 4
δ = 1.6568 m
v = 335 m/s
Intensity I = [tex]4I_{1} cos^{2}[/tex](πδ/λ)
[tex]= 4I_{1} cos^{2}[/tex](πδf/v)
[tex]= 4 * 6 cos^{2}(\frac{\pi *1.6568*30}{335} )[/tex]
I = 19.152 [tex]\frac{w}{m^{2} }[/tex]
the lowest frequency is selected to cowl the N-point signal at its coarsest scale with the aid of the default wavelet's two-time popular deviations. the very best frequency wavelet bandpass filter out loses half of of its height importance at the Nyquist frequency because of the most frequency.
guy's voice has the lowest frequency in comparison to other sounds seeing that frequency and pitch cross hand in hand. Pitch denotes the voice's shrillness. the man's voice is the selection with the least strident tone. It, therefore, has the bottom pitch of all and for this reason the bottom frequency.
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What is the hybridization of the xe atom in the xecl4 molecule?
a. sp
b. sp2
c. sp3
d. sp3 d
e. sp3 d 2
Answer:
sp3 d 2
Explanation:
vector a has a magnitude of 31 units and points in the positive y-direction. when vector b is added to a, the resultant vector a b points in the negative y-direction with a magnitude of 16 units. find the magnitude and direction of b.
The correct answer is 47 units.
Arrows typically serve as a vector's geometric representation. The magnitude of the vector is determined by its length and the direction in which the arrow is pointing. When two vectors have the same magnitude and direction, they are said to be equal. Additionally, the magnitude and direction of vectors are unaffected by the vector's position.
A quantity with both magnitude and direction is referred to as a vector quantity. One example of a vector quantity is velocity. A two-dimensional vector can be expressed as,
A=A_Xi+A_Yj
Vector A=31 j
A+B=-16 j
Thus vector B is
B=(A+B)-A
B=(-16j)-31j
B=(-47)j
As a result, vector B has a magnitude of 47 units and is oriented in a negative Y direction.
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If h is the water's height, the volume of the water is v = r2h. we must find dv/dt. differentiating both sides of the equation gives the following. dv dt = r2
If h is the height of the water, then the volume of water is v = r2h. We get [tex]dv/dt[/tex] equal to 0.00994 m/min.
Here, radius = 8m
We have, [tex]V = \pir2h[/tex]
[tex]dV/dT= (\pir2) dh/dt[/tex]
[tex]dV/dT= (\pi82) dh/dt[/tex]
[tex]dV/dT= (\pi64) dh/dt[/tex]
Given [tex]dV/dT = 2[/tex]
Therefore, [tex]dh/dt = 2/(64\pi) = 0.00994 m/min[/tex]
From the definition = a by way of integrating the preliminary velocity, v(0), and the consistent acceleration, one might also find the velocity at a later time, t.
(value of acceleration) means the rate of change of significance of the speed with recognize to time. then again |
| approach the magnitude of the price of change in speed with recognize to time (i.e. the importance of acceleration).
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A hiker walks 4.24m, north and 13.32 m, E. What is the magnitude of his resultant displacement.
Answer:the magnitude of the hikers resultant displacement
Explanation:
Let b be the basis of r2 consisting of the vectors [ 4 ] 2 and [ -2 ] 5 , and let r be the basis consisting of [ 2 ] -3 and [ -1 ] 2 . find a matrix p such that [x]r=p[x]b for all x in r2.
The value of matrix p will be[tex]\left[\begin{array}{ccc}9&1\\14&4\end{array}\right][/tex].
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You toss a ball straight up, and it reaches a maximum height h above the launch position. If you want to double the length of the time interval during which the ball stays in the air above the launch position, to what maximum height do you have to throw it? Express your answer in terms of h.
With the use of formula, the maximum height reached by the ball in term of h is 4h
What is a Projectile ?A projectile is any object thrown into the space or atmosphere which take a trajectory path.
If you toss a ball straight up, and it reaches a maximum height h above the launch position, Then the maximum height reach will be
v² = u² - 2gh
But at maximum height, v = 0
u² = 2gh
h = u² / 2g ...... (1)
Also, the time taken will be;
v = u - gt
since v = 0,
u = gt
Substitute u into equation 1
h = (gt)² / 2g
If you want to double the length of the time interval during which the ball stays in the air above the launch position, then,
u = g2t and the maximum height will be
H = (g2t)² / 2g
H = 4g²t² / 2g
H = 4(gt)² / 2g
but h = (gt)² / 2g
H = 4h
Therefore, the maximum height you have to throw it in terms of h will be 4h.
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Static charges are not dangerous
true
false
Answer:
false
Explanation:
ecosystem A and wcosystem B have the same eight species, but ecosystem B has more distribution of species than ecosystem B. which ecosystem is mor diverse? expliain you reasoning.
Ecosystem A has more diversity, because it has greater species evenness than Ecosystem B.
Ecosystem :All the organisms and the physical setting they interact with make up an ecosystem. The nutrient cycles and energy flows connect these biotic and abiotic elements. Photosynthesis is how energy reaches the system and is absorbed by plant tissue.
Types of Ecosystem :Forest Ecosystem.
Grassland Ecosystem.
Tundra Ecosystem.
Desert Ecosystem.
What are the functions of ecosystem?Fundamentally, the way an ecosystem works is through the transfer of nutrients and energy up the food chain. The planet's plant and animal life, as well as the breakdown of organic matter and the creation of biomass, are all supported by these exchanges.
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For the theory of special relativity to apply, how should a reference frame be chosen?
1905, Albert Einstein. The theory of special relativity explains how speed affects space, time, and mass. Small amounts of mass (m) can be interchangeable with large amounts of energy (E), as defined by the classic equation E = mc2, according to the theory, which offers a means for the speed of light to define the link between energy and matter.
When talking about extremely high energy, incredibly fast speeds, and astronomical distances without the difficulties of gravity, special relativity is typically employed. With the publication of his general relativity article in 1915, Einstein formally incorporated gravity into his ideas.
The mass of an object and the energy needed to move it both grow unlimited as it gets for any matter to go faster than light travels. This cosmic speed limit inspires new realms of physics and science fiction, as people consider travel across vast distance closer to the speed of light. Therefore, it is not possible.
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A projectile is fired straight up from the south pole of earth with an initial speed vi = 15km/s. find the speed of the projectil when it is very far from the earth, neglecting air resistance
The calculated value is 2.5×10⁷ m.
Velocity is a term that describes the speed and direction of a point's motion. For example, a circular path's direction is always perpendicular to a line from the point to the circle's center. A point always moves in a direction that is tangent to its path (a radius). A vector measurement of the rate and direction of motion is what is meant by the term "velocity." Simply said, velocity is the rate of movement in a single direction.
From energy conservation, since the velocity will be 0 at highest point,
1/2 m (10000) ²− GMm/R
=− GMm/d
=10⁸/2 −(9.8) (6400000)
=−(9.8) *(6400000) ²/d
d≈2.5×107 m
Answer is 2.5×10⁷ m.
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A student placed a short candle and a slightly taller candle in a small dish filled with baking soda as
shown in the figure. The child then lights both the candles and poured vinegar into the dish of baking
soda.
Baking Soda +
Vinegar
(a) What happens to the candles? Why? In what order?
(b) Mention one precaution the student needs to follow while pouring the vinegar into the dish of
baking soda.
a) As carbon dioxide is formed the shorter candle's flame goes off first, followed by the taller candle. This shows, that in absence of air, the flame goes off. Hence, the air is necessary for combustion.
b) Although both reactants are common home chemicals and foods, care should be taken to avoid splashing in the eyes, and protective clothing should be used. The reaction's byproducts can be disposed of by thoroughly filling the sink with water and washing down the sink with no chemicals touched.
Baking soda and vinegar react with one another to create carbon dioxide gas. The carbon dioxide gas sinks to the bottom of the bowl because it is heavier than the air around it. More and more carbon dioxide gas is produced as the reaction progresses, progressively filling the bowl as it does so. The flame will go out owing to a shortage of oxygen once the level of carbon dioxide reaches that of the flame.
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you sit in a car that is moving at an average speed of 86.4 km/h. during the 3.3 s that you glance out the window, how far has the car traveled?
The distance travelled or how far the car has travelled in 3.3 second at constant speed of 86.4 km/h is 79.2 m.
What is speed?The speed of an object, also known as v in kinematics, is a scalar quantity that refers to the size of the change in that object's position over time. The average speed of an object over a period of time is calculated by dividing its distance traveled by the length of the interval. Velocity and speed are different concepts. Distance divided by time is the dimension of speed. The meter per second (m/s) is the metric unit used to measure speed.
Speed of car= 86.4 km/h
Since time is given in seconds, converting to km/h to m/s. For converting km/h to m/s, dividing the value given in km/h by 3.6
86.4 km/h= 86.4/3.6 m/s
= 24 m/s
Distance travelled= Velocity* Time
= 24 * 3.3
= 79.2 m
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Calculate the potential energy of a person who weighs 80n standing on top of the sunshine bridge 300 meters in the air
73.5 kilojoules are the answer. Since we can compute potential energy, we can convert 250 into 9.8 into 30 into 73500 joules, or u equal to m g h. Consequently, the body's potential energy will be 73500 joules, which is the necessary amount.
This potential energy calculator allows us to calculate the amount of energy that an elevated object has stored inside it. The full name of this effect is gravitational potential energy, and it refers to the energy that an item stores as a result of its height or vertical position.
The great wrecking ball of the crane. The ball's gravitational potential energy depends on both its mass and how high it is elevated. The relationship between gravitational potential energy and an object's mass and height is seen in the following equation:
PE Gravity equals (m, h, and g). The formula is rather simple to comprehend. The height of a non-raised object will be zero, and as a result, it will have no potential energy.
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NEED HELP ASAP CURRENTLY FAILING!!!
You need to be at the Houston International Airport by 4pm to make your flight. You are currently in Helotes
which is 213 miles away. If you leave at 12:30 pm, what will your average speed need to be to make it to the airport on
time
Explanation:
12:30pm -> 04:00pm = 3hrs 30mins
3hr 30mins= 3.5hrs
average speed=total distance/total time
=213÷3.5
=60.8571428571
round to 2 decimal places
=60.86 mph
a helicopter blade spins at exactly 80 revolutions per minute. its tip is 4.00 m from the center of rotation.
The linear speed of the helicopter blade is 33.51 m.
Tangential or linear speed of the bladeThe tangential speed of the helicopter blade is calculated as follows;
v = ωr
where;
ω is angular speed in radian per secondr is the radius of the circular pathω = 80 rev/min
ω = 80 x 2π rad/rev x 1 min/60s
ω = 8.378 rad/s
v = 8.378 rad/s x 4 m
v = 33.51 m
Thus, the linear speed of the helicopter blade is 33.51 m.
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The complete question is below:
Find the tangential speed of the helicopter's blade.