Reaction: 2K2O+4MnO2+3O2(g) 4KMnO4 (aq)
If you start with 291(g) of MnO2, how many moles of NaOH will you start with? (The molar mass of MnO2 is 87 for every 1 mole)
The number of moles of [tex]MnO_2[/tex] required is 3.345 moles.
In the given reaction, the balanced equation shows that for every 4 moles of [tex]MnO_2[/tex], 4 moles of [tex]KMnO_4[/tex] are produced. Therefore, we can use the stoichiometry of the reaction to calculate the moles of [tex]MnO_2[/tex] and the moles of [tex]KMnO_4[/tex]
Given:
Mass of [tex]MnO_2[/tex] = 291 g
Molar mass of[tex]MnO_2[/tex] = 87 g/mol
To find the moles of [tex]MnO_2[/tex], we use the formula:
Moles = Mass / Molar mass
Moles of [tex]MnO_2[/tex] = 291 g / 87 g/mol = 3.345 mol
Now, since the stoichiometry of the reaction tells us that the ratio of [tex]MnO_2[/tex]to [tex]KMnO_4[/tex] is 4:4, we can conclude that 3.345 moles of [tex]MnO_2[/tex]will produce an equal number of moles of [tex]KMnO_4[/tex]
Therefore, the moles of [tex]KMnO_4[/tex] produced will also be 3.345 mol.
However, the question asks for the moles of NaOH, which is not directly related to the given reaction. We cannot determine the moles of NaOH based on the information provided.
To find the moles of NaOH, we would need additional information or another relevant equation that includes NaOH.
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I need help with budgeting someone who works as a Master Business Administrator but it’s entrepreneurship I need help with the Gross annual salary then I have to subtract the federal tax by 19%
Basically multiply gross annual salary by .19 then subtract the amount
Subtract the tax of 11%
Subtract THE fICA tax of 8%
Multiple the gross jayla salary by .08 then subtract the amount
Then I have to find the NEt Annual Salary
then it says mutual the monthly net income then divide the net annual salary by 12
Then I have to find the monthly expense of being a MBA (entrepreneur)
Like mortgage for mortgage I have to go to Zillow and ask for my “debts” this would be any credit card debt , student loans, car payments etc then I have to find utilities, cable , internet , cell phone , car pay , student loans , groceries , car gasoline , health insurance, auto insurance,home insurance, entertainment, hair cuts /nails /beauty , Gym membership , clothes , gifts , vacation fund I have to multiply my month net income by 0.1 to find all these it all depends on how much I make and last but not least I have to find the projected monthly expense
IF YOU can help with me all of these I will sure to mark you BRAINLIEST
I can give you a general approach to budgeting based on the guidelines you provided.
First, let's assume that the gross annual salary of the MBA entrepreneur is $100,000.
Federal Tax:
19% of $100,000 = $19,000
Net Salary:
$100,000 - $19,000 = $81,000
State Tax:
Assuming the state tax rate is 11%:
11% of $81,000 = $8,910
Net Salary:
$81,000 - $8,910 = $72,090
FICA Tax:
Assuming the FICA tax rate is 8%:
8% of $81,000 = $6,480
Net Salary:
$81,000 - $6,480 = $74,520
Monthly Net Income:
$74,520 divided by 12 = $6,210
Monthly Expenses:
Assuming a debt of $1,000 per month (credit card/student loans/car payments),
Utilities: $150
Cable and Internet: $100
Cell Phone: $50
Car Payment: $400
Groceries: $400
Car Gasoline: $150
Health Insurance: $400
Auto Insurance: $150
Home Insurance: $100
Entertainment: $200
Haircuts/Nails/Beauty: $100
Gym Membership: $50
Clothes: $100
Gifts: $100
Vacation Fund: $200
Total Monthly Expenses:
$2,900
Projected Monthly Expense:
10% of $6,210 = $621
Note that this is just an example, and your budget may differ depending on your specific circumstances and location. It's essential to track your actual expenses carefully to make sure you're sticking to your budget and adjusting it as needed.
Answer:
I apologize if this is not what you wanted! If you want a different answer or would like me to change it please let me know :)
Explanation:
For housing, I should be spending no more than 30% of my monthly net income. This includes rent, mortgage payments, and utilities. For transportation, I should be spending no more than 15% of my monthly net income. This includes car payments, gas, and insurance. For food, I should be spending no more than 10% of my monthly net income. This includes groceries and eating out. For savings, I should be spending no more than 10% of my monthly net income. This includes retirement savings, emergency funds, and other investments. For debt payments, I should be spending no more than 10% of my monthly net income. This includes student loans, credit cards, and other debts. For entertainment, I should be spending no more than 5% of my monthly net income. This includes movies, concerts, and other leisure activities.
In addition to these categories, I may also need to budget for other expenses. This could include medical bills, clothing, and other miscellaneous expenses. It is important to remember that these percentages are just guidelines and may need to be adjusted depending on my individual situation.
Scenario : I would like to save for a new cell phone which variable expense can I cut back ? How much should I save for a month on the phone?
If I would like to save for a new cell phone, I can cut back on my variable expenses. I can reduce my spending on entertainment, clothing, and miscellaneous expenses. I should aim to save at least 5% of my net annual salary for a new cell phone. This would be approximately $1,000 per year, or $83.33 per month.
id k what to do for the other two, but i hope this helps you! :))))))
What is happening in the picture?
A)
Sunlight is reacting with waste gases produced by cellular respiration from the trees to produce chemical smog.
B)
Sunlight is reacting with waste gases produced by cellular respiration from the trees and by vehicles burning fossil fuels to produce chemical smog.
C)
Sunlight is reacting with water vapor produced by vehicles burning fossil fuels to produce photochemical smog.
D)
Sunlight is reacting with waste gases produced by vehicles burning fossil fuels to produce photochemical smog.
The most likely option based on common knowledge is sunlight is reacting with waste gases produced by vehicles burning fossil fuels to produce photochemical smog.
Photochemical smog is a type of air pollution that is formed when sunlight reacts with pollutants released from vehicle exhaust and other sources, such as industrial emissions. This reaction produces a mixture of harmful chemicals, including ground-level ozone and various secondary pollutants.
However, it's important to note that a definitive answer would require specific information about the picture in question, as different scenarios may lead to different outcomes.
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CHEM FINAL TOMORROW, NEED IMMEDIATE HELP!!! There are a few topics I don't understand, if someone could give a short explanation of how to do these kinds of problems, it would help so much. I'll be posting a few more of these on my page, so feel free to check those out if you would like. Thanks!
The mass of [tex]O_2[/tex] needed to produce 8.65 x [tex]10^{23[/tex] atoms of silver is 22.96 grams.
Stoichiometric calculationIn the given balanced equation, it is stated that 2 moles of [tex]Ag_2O[/tex] produce 4 moles of Ag and 1 mole of [tex]O_2[/tex].
First, let's calculate the number of moles of Ag:
8.65 x [tex]10^{23[/tex] atoms of Ag / (6.022 x [tex]10^{23[/tex] atoms/mol) = 1.435 moles of Ag
Since 2 moles of [tex]Ag_2O[/tex] produce 1 mole of [tex]O_2[/tex], the number of moles of [tex]O_2[/tex] needed is half of the moles of [tex]Ag_2O[/tex].
Number of moles of [tex]O_2[/tex]= 1.435 moles of [tex]Ag_2O[/tex] / 2 = 0.7175 moles
Now, we'll use the molar mass of [tex]O_2[/tex] to find the mass:
Molar mass = 32.00 g/mol
Mass of [tex]O_2[/tex] = number of moles × molar mass
= 0.7175 moles × 32.00 g/mol = 22.96 g
Therefore, the mass of [tex]O_2[/tex] needed to produce 8.65 x [tex]10^{23[/tex] atoms of silver is 22.96 grams.
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Identify the type of reaction and predict the product: Calcium + water -->
Answer:
Exothermic Reaction
Product = Calcium hydroxide + hydrogen
Explanation:
Water arrived on earth in the form of
Answer:
the water arrives on the earth in the form of water rich objects(planetesimals)
Select all of the equations which demonstrate the law of conservation of mass.
A Mg + S → MgS2
B C + O2 → C2O
C 4Cu + O2 → 2Cu2O
D 2H2 + O2 → 2H2O
E H2SO4 + Zn → 4ZnSO + H2
The equations (C + O2 → C2O), C (4Cu + O2 → 2Cu2O), and D (2H2 + O2 → 2H2O) demonstrate the law of conservation of mass. Option B.
The law of conservation of mass states that in a chemical reaction, the total mass of the reactants is equal to the total mass of the products. Let's analyze each equation to determine if it demonstrates the conservation of mass:
A Mg + S → MgS2:
This equation does not demonstrate the conservation of mass. The reactants contain one magnesium atom and one sulfur atom, while the product contains one magnesium atom and two sulfur atoms.
The number of atoms on the left side is not equal to the number of atoms on the right side, violating the law of conservation of mass.
B C + O2 → C2O:
This equation demonstrates the conservation of mass. The reactants contain one carbon atom and two oxygen atoms, while the product contains two carbon atoms and two oxygen atoms. The number of atoms on the left side is equal to the number of atoms on the right side, satisfying the law of conservation of mass.
C 4Cu + O2 → 2Cu2O:
This equation demonstrates the conservation of mass. The reactants contain four copper atoms and two oxygen atoms, while the product contains four copper atoms and two oxygen atoms.
The number of atoms on the left side is equal to the number of atoms on the right side, satisfying the law of conservation of mass.
D 2H2 + O2 → 2H2O:
This equation demonstrates the conservation of mass. The reactants contain four hydrogen atoms and two oxygen atoms, while the product contains four hydrogen atoms and two oxygen atoms. The number of atoms on the left side is equal to the number of atoms on the right side, satisfying the law of conservation of mass.
E H2SO4 + Zn → 4ZnSO + H2:
This equation does not demonstrate the conservation of mass. The reactants contain one sulfur atom, while the products contain four sulfur atoms.
The number of atoms on the left side is not equal to the number of atoms on the right side, violating the law of conservation of mass. So Option B is correct.
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C2N2H8 empirical formula
Answer:
[tex]\huge\boxed{\sf CNH_4}[/tex]
Explanation:
Empirical formula:The simplest whole number ratio of atoms in a compound is known as empirical formula.Solution:Given compound us,
C₂N₂H₈
Ratio:= 2 : 2 : 8
Divide by 2= 2 ÷ 2 : 2 ÷ 2 : 8 ÷ 2
= 1 : 1 : 4
So, we can write the formula as:
= CNH₄[tex]\rule[225]{225}{2}[/tex]
How many molecules of. C6H1206 are needed to produce 18 molecules of co2
A.3
B.9
C.12
D.18
Answer: A : 3
Explanation: 18 CO2 / 6 CO2 = 3 C6H12O6
Answer:
A = 3.
Explanation:
Here is how:
To determine the number of molecules of C6H12O6 (glucose) needed to produce 18 molecules of CO2, we need to consider the balanced chemical equation for the complete combustion of glucose:
C6H12O6 + 6O2 -> 6CO2 + 6H2O
From the balanced equation, we can see that 1 molecule of glucose (C6H12O6) produces 6 molecules of CO2. Therefore, we can set up a proportion to find the number of glucose molecules needed:
1 molecule of glucose produces 6 molecules of CO2
x molecules of glucose produce 18 molecules of CO2
Using the proportion:
1/6 = x/18
To solve for x, we can cross-multiply:
6x = 18
Dividing both sides by 6:
x = 3
Therefore, 3 molecules of C6H12O6 are needed to produce 18 molecules of CO2.
If you placed 413g of Bal2 in a beaker and filled it with water to a total volume of 750ml, calculate the molarity of the solution
To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.
Given:
Mass of Bal2 = 413 g
Volume of solution = 750 ml = 0.75 L
1. Calculate the number of moles of Bal2:
First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):
Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)
Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)
Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol
Molar mass of Bal2 = 264.61 g/mol
Now we can calculate the number of moles of Bal2:
Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2
Moles of Bal2 = 413 g / 264.61 g/mol
Moles of Bal2 ≈ 1.561 mol
2. Calculate the molarity of the solution:
Molarity (M) = Moles of solute / Volume of solution (in liters)
Molarity (M) = 1.561 mol / 0.75 L
Molarity (M) ≈ 2.081 M
Therefore, the molarity of the solution is approximately 2.081 M.
The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.
The molar mass of BaI₂ is:
Ba (barium) atomic mass = 137.33 g/mol
I (iodine) atomic mass = 126.90 g/mol
Molar mass of BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)
= 137.33 + 2 × 126.90
= 137.33 + 253.80
= 391.13 g/mol
Given that the mass of BaI₂ is 413 g,
Number of moles = Mass / Molar mass
= 413 g / 391.13 g/mol
= 1.056 moles
Volume of solution = 750 ml = 750/1000 = 0.75 L
Finally, one can calculate the molarity of the solution using the formula:
Molarity = Number of moles / Volume of solution
= 1.056 moles / 0.75 L
= 1.408 M
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how many grams of agcl will form by adding enough agno3 to react fully with 1500 ml of 0.400 m bacl2 solution?
Answer:
85.99 grams of AgCl will be formed.
Explanation:
To determine the grams of AgCl formed in the reaction, we need to consider the stoichiometry of the reaction between silver nitrate (AgNO3) and barium chloride (BaCl2):
AgNO3 + BaCl2 -> AgCl + Ba(NO3)2
The balanced equation shows that the molar ratio between AgNO3 and AgCl is 1:1. This means that 1 mole of AgNO3 produces 1 mole of AgCl.
Given:
Volume of BaCl2 solution = 1500 ml = 1.5 L
Molarity of BaCl2 solution = 0.400 M
First, we need to calculate the number of moles of BaCl2 present in the solution:
moles of BaCl2 = volume of BaCl2 solution * molarity of BaCl2 solution
= 1.5 L * 0.400 M
= 0.600 moles
Since the molar ratio between BaCl2 and AgNO3 is 1:1, the number of moles of AgNO3 needed for complete reaction is also 0.600 moles.
Now, using the molar mass of AgCl, which is 143.32 g/mol, we can calculate the grams of AgCl formed:
grams of AgCl = moles of AgNO3 * molar mass of AgCl
= 0.600 moles * 143.32 g/mol
= 85.99 grams
Therefore, by adding enough AgNO3 to react fully with the 1500 ml of 0.400 M BaCl2 solution, approximately 85.99 grams of AgCl will be formed.
What volume of 3.0 M KOH contains 2.1 g?
Answer: about 12.5 mL is the estimated volume of a solution containing 2.1 g of KOH with a concentration of 3.0 M.
which stament is true about endothermic and exothermic reactions? 1. Energy is absorbed 2. energy is released in an endothermic reaction. 3. the products have more potential energy than the reactants in an exothermic reaction. 4. the products have more potential energy than the reactant in an endothermic reaction.
Answer:
Overall, energy is released in exothermic and absorbed in endothermic reactions. Therefore, "a" is the correct statement. The other statements are all incorrect.
Explanation:
u suck
A teacher showed this animal to studenst on a field trip
If a teacher showed an animal to students on a field trip. The tool will allow the students to best see the animal up close is the hand lens.
Option D is correct.
What is a Hand lens?A hand lens is known as a magnifying glass which is a convex lens that is used to produce a magnified image of an object. The lens is usually mounted in a frame with a handle.
A hand lens has two essential properties which are its focal length and its diameter.
The students will therefore require a hand lens to look up the animal close.
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#complete question:
A teacher showed this animal to students on a field trip. Which tool will allow the students to best see the animal up close? O A Tape measure O B Graduated cylinder O c. Notebook O D. Hand lens