A moon rock collected by a U.S. Apollo mission is estimated to be 4.40 billion years old by uranium/lead dating. Assuming that the rock did not contain any lead when it was formed, what is the current mass of Pb206 in the rock, if it currently contains 1.130g of U238? The half-life of U238 is 4.47×109 years

Answers

Answer 1
First, we need to calculate how much lead (Pb206) would have been formed from the decay of the original amount of uranium (U238) in the rock, given the half-life of U238.

The decay process of U238 eventually leads to the formation of Pb206 through a series of alpha and beta decays. The decay process is as follows:

U238 → Th234 → Pa234 → U234 → Th230 → Ra226 → Rn222 → Po218 → Pb214 → Bi214 → Po214 → Pb210 → Bi210 → Po210 → Pb206

Each decay step involves the emission of alpha or beta particles, and the resulting nucleus has a different atomic number and mass number. The final product of the decay chain is Pb206, which is a stable isotope.

We can use the fact that the half-life of U238 is 4.47×10^9 years to calculate how much U238 would have decayed to Pb206 over the estimated 4.40 billion years since the rock was formed.

The half-life of U238 means that half of the original amount of U238 would have decayed to Pb206 after 4.47×10^9 years. Therefore, the fraction of U238 that has decayed to Pb206 after 4.40 billion years is:

(1/2)^(4.40/4.47) = 0.0184

This means that only 1.84% of the original amount of U238 remains, and the rest has decayed to Pb206. We can calculate the current mass of Pb206 in the rock by multiplying the current mass of U238 by this fraction:

mass of Pb206 = 1.130g × 0.0184 = 0.0208g

Therefore, the current mass of Pb206 in the moon rock is approximately 0.0208 grams.

Related Questions

Reaction: 2K2O+4MnO2+3O2(g)  4KMnO4 (aq)

If you start with 291(g) of MnO2, how many moles of NaOH will you start with? (The molar mass of MnO2 is 87 for every 1 mole)

Answers

The number of moles of [tex]MnO_2[/tex] required is  3.345 moles.

In the given reaction, the balanced equation shows that for every 4 moles of [tex]MnO_2[/tex], 4 moles of [tex]KMnO_4[/tex] are produced. Therefore, we can use the stoichiometry of the reaction to calculate the moles of [tex]MnO_2[/tex] and the moles of [tex]KMnO_4[/tex]

Given:

Mass of [tex]MnO_2[/tex] = 291 g

Molar mass of[tex]MnO_2[/tex] = 87 g/mol

To find the moles of [tex]MnO_2[/tex], we use the formula:

Moles = Mass / Molar mass

Moles of [tex]MnO_2[/tex] = 291 g / 87 g/mol = 3.345 mol

Now, since the stoichiometry of the reaction tells us that the ratio of [tex]MnO_2[/tex]to [tex]KMnO_4[/tex] is 4:4, we can conclude that 3.345 moles of [tex]MnO_2[/tex]will produce an equal number of moles of [tex]KMnO_4[/tex]

Therefore, the moles of [tex]KMnO_4[/tex] produced will also be 3.345 mol.

However, the question asks for the moles of NaOH, which is not directly related to the given reaction. We cannot determine the moles of NaOH based on the information provided.

To find the moles of NaOH, we would need additional information or another relevant equation that includes NaOH.

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I need help with budgeting someone who works as a Master Business Administrator but it’s entrepreneurship I need help with the Gross annual salary then I have to subtract the federal tax by 19%
Basically multiply gross annual salary by .19 then subtract the amount

Subtract the tax of 11%
Subtract THE fICA tax of 8%
Multiple the gross jayla salary by .08 then subtract the amount
Then I have to find the NEt Annual Salary
then it says mutual the monthly net income then divide the net annual salary by 12

Then I have to find the monthly expense of being a MBA (entrepreneur)
Like mortgage for mortgage I have to go to Zillow and ask for my “debts” this would be any credit card debt , student loans, car payments etc then I have to find utilities, cable , internet , cell phone , car pay , student loans , groceries , car gasoline , health insurance, auto insurance,home insurance, entertainment, hair cuts /nails /beauty , Gym membership , clothes , gifts , vacation fund I have to multiply my month net income by 0.1 to find all these it all depends on how much I make and last but not least I have to find the projected monthly expense

IF YOU can help with me all of these I will sure to mark you BRAINLIEST

Answers

I can give you a general approach to budgeting based on the guidelines you provided.

First, let's assume that the gross annual salary of the MBA entrepreneur is $100,000.

Federal Tax:

19% of $100,000 = $19,000

Net Salary:

$100,000 - $19,000 = $81,000

State Tax:

Assuming the state tax rate is 11%:

11% of $81,000 = $8,910

Net Salary:

$81,000 - $8,910 = $72,090

FICA Tax:

Assuming the FICA tax rate is 8%:

8% of $81,000 = $6,480

Net Salary:

$81,000 - $6,480 = $74,520

Monthly Net Income:

$74,520 divided by 12 = $6,210

Monthly Expenses:

Assuming a debt of $1,000 per month (credit card/student loans/car payments),

Utilities: $150

Cable and Internet: $100

Cell Phone: $50

Car Payment: $400

Groceries: $400

Car Gasoline: $150

Health Insurance: $400

Auto Insurance: $150

Home Insurance: $100

Entertainment: $200

Haircuts/Nails/Beauty: $100

Gym Membership: $50

Clothes: $100

Gifts: $100

Vacation Fund: $200

Total Monthly Expenses:

$2,900

Projected Monthly Expense:

10% of $6,210 = $621

Note that this is just an example, and your budget may differ depending on your specific circumstances and location. It's essential to track your actual expenses carefully to make sure you're sticking to your budget and adjusting it as needed.

Answer:

I apologize if this is not what you wanted! If you want a different answer or would like me to change it please let me know :)

Explanation:

For housing, I should be spending no more than 30% of my monthly net income. This includes rent, mortgage payments, and utilities. For transportation, I should be spending no more than 15% of my monthly net income. This includes car payments, gas, and insurance. For food, I should be spending no more than 10% of my monthly net income. This includes groceries and eating out. For savings, I should be spending no more than 10% of my monthly net income. This includes retirement savings, emergency funds, and other investments. For debt payments, I should be spending no more than 10% of my monthly net income. This includes student loans, credit cards, and other debts. For entertainment, I should be spending no more than 5% of my monthly net income. This includes movies, concerts, and other leisure activities.

In addition to these categories, I may also need to budget for other expenses. This could include medical bills, clothing, and other miscellaneous expenses. It is important to remember that these percentages are just guidelines and may need to be adjusted depending on my individual situation.

Scenario : I would like to save for a new cell phone which variable expense can I cut back ? How much should I save for a month on the phone?

If I would like to save for a new cell phone, I can cut back on my variable expenses. I can reduce my spending on entertainment, clothing, and miscellaneous expenses. I should aim to save at least 5% of my net annual salary for a new cell phone. This would be approximately $1,000 per year, or $83.33 per month.

id k what to do for the other two, but i hope this helps you! :))))))

What is happening in the picture?


A)
Sunlight is reacting with waste gases produced by cellular respiration from the trees to produce chemical smog.


B)
Sunlight is reacting with waste gases produced by cellular respiration from the trees and by vehicles burning fossil fuels to produce chemical smog.


C)
Sunlight is reacting with water vapor produced by vehicles burning fossil fuels to produce photochemical smog.


D)
Sunlight is reacting with waste gases produced by vehicles burning fossil fuels to produce photochemical smog.

Answers

The most likely option based on common knowledge is sunlight is reacting with waste gases produced by vehicles burning fossil fuels to produce photochemical smog.

Photochemical smog is a type of air pollution that is formed when sunlight reacts with pollutants released from vehicle exhaust and other sources, such as industrial emissions. This reaction produces a mixture of harmful chemicals, including ground-level ozone and various secondary pollutants.

However, it's important to note that a definitive answer would require specific information about the picture in question, as different scenarios may lead to different outcomes.

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CHEM FINAL TOMORROW, NEED IMMEDIATE HELP!!! There are a few topics I don't understand, if someone could give a short explanation of how to do these kinds of problems, it would help so much. I'll be posting a few more of these on my page, so feel free to check those out if you would like. Thanks!

Answers

The mass of [tex]O_2[/tex] needed to produce 8.65 x [tex]10^{23[/tex] atoms of silver is 22.96 grams.

Stoichiometric calculation

In the given balanced equation, it is stated that 2 moles of [tex]Ag_2O[/tex] produce 4 moles of Ag and 1 mole of [tex]O_2[/tex].

First, let's calculate the number of moles of Ag:

8.65 x [tex]10^{23[/tex] atoms of Ag / (6.022 x [tex]10^{23[/tex] atoms/mol) = 1.435 moles of Ag

Since 2 moles of  [tex]Ag_2O[/tex] produce 1 mole of  [tex]O_2[/tex], the number of moles of  [tex]O_2[/tex] needed is half of the moles of  [tex]Ag_2O[/tex].

Number of moles of  [tex]O_2[/tex]= 1.435 moles of  [tex]Ag_2O[/tex] / 2 = 0.7175 moles

Now, we'll use the molar mass of  [tex]O_2[/tex] to find the mass:

Molar mass = 32.00 g/mol

Mass of  [tex]O_2[/tex] = number of moles × molar mass

                   = 0.7175 moles × 32.00 g/mol = 22.96 g

Therefore, the mass of  [tex]O_2[/tex] needed to produce 8.65 x [tex]10^{23[/tex] atoms of silver is 22.96 grams.

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Identify the type of reaction and predict the product: Calcium + water -->

Answers

Answer:

Exothermic Reaction

Product  = Calcium hydroxide + hydrogen

Explanation:

Water arrived on earth in the form of

Answers

Answer:

the water arrives on the earth in the form of water rich objects(planetesimals)

Select all of the equations which demonstrate the law of conservation of mass.
A Mg + S → MgS2

B C + O2 → C2O

C 4Cu + O2 → 2Cu2O

D 2H2 + O2 → 2H2O

E H2SO4 + Zn → 4ZnSO + H2

Answers

The equations (C + O2 → C2O), C (4Cu + O2 → 2Cu2O), and D (2H2 + O2 → 2H2O) demonstrate the law of conservation of mass. Option B.

The law of conservation of mass states that in a chemical reaction, the total mass of the reactants is equal to the total mass of the products. Let's analyze each equation to determine if it demonstrates the conservation of mass:

A Mg + S → MgS2:

This equation does not demonstrate the conservation of mass. The reactants contain one magnesium atom and one sulfur atom, while the product contains one magnesium atom and two sulfur atoms.

The number of atoms on the left side is not equal to the number of atoms on the right side, violating the law of conservation of mass.

B C + O2 → C2O:

This equation demonstrates the conservation of mass. The reactants contain one carbon atom and two oxygen atoms, while the product contains two carbon atoms and two oxygen atoms. The number of atoms on the left side is equal to the number of atoms on the right side, satisfying the law of conservation of mass.

C 4Cu + O2 → 2Cu2O:

This equation demonstrates the conservation of mass. The reactants contain four copper atoms and two oxygen atoms, while the product contains four copper atoms and two oxygen atoms.

The number of atoms on the left side is equal to the number of atoms on the right side, satisfying the law of conservation of mass.

D 2H2 + O2 → 2H2O:

This equation demonstrates the conservation of mass. The reactants contain four hydrogen atoms and two oxygen atoms, while the product contains four hydrogen atoms and two oxygen atoms. The number of atoms on the left side is equal to the number of atoms on the right side, satisfying the law of conservation of mass.

E H2SO4 + Zn → 4ZnSO + H2:

This equation does not demonstrate the conservation of mass. The reactants contain one sulfur atom, while the products contain four sulfur atoms.

The number of atoms on the left side is not equal to the number of atoms on the right side, violating the law of conservation of mass. So Option B is correct.

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C2N2H8 empirical formula

Answers

Answer:

[tex]\huge\boxed{\sf CNH_4}[/tex]

Explanation:

Empirical formula:The simplest whole number ratio of atoms in a compound is known as empirical formula.Solution:

Given compound us,

C₂N₂H₈

Ratio:

= 2 : 2 : 8

Divide by 2

= 2 ÷ 2 : 2 ÷ 2 : 8 ÷ 2

= 1 : 1 : 4

So, we can write the formula as:

= CNH₄

[tex]\rule[225]{225}{2}[/tex]

How many molecules of. C6H1206 are needed to produce 18 molecules of co2

A.3

B.9

C.12

D.18

Answers

Answer: A : 3

Explanation: 18 CO2 / 6 CO2 = 3 C6H12O6

Answer:

A = 3.

Explanation:

Here is how:

To determine the number of molecules of C6H12O6 (glucose) needed to produce 18 molecules of CO2, we need to consider the balanced chemical equation for the complete combustion of glucose:

C6H12O6 + 6O2 -> 6CO2 + 6H2O

From the balanced equation, we can see that 1 molecule of glucose (C6H12O6) produces 6 molecules of CO2. Therefore, we can set up a proportion to find the number of glucose molecules needed:

1 molecule of glucose produces 6 molecules of CO2

x molecules of glucose produce 18 molecules of CO2

Using the proportion:

1/6 = x/18

To solve for x, we can cross-multiply:

6x = 18

Dividing both sides by 6:

x = 3

Therefore, 3 molecules of C6H12O6 are needed to produce 18 molecules of CO2.

If you placed 413g of Bal2 in a beaker and filled it with water to a total volume of 750ml, calculate the molarity of the solution

Answers

To calculate the molarity of a solution, we need to determine the number of moles of the solute (Bal2) and then divide it by the volume of the solution in liters.

Given:

Mass of Bal2 = 413 g

Volume of solution = 750 ml = 0.75 L

1. Calculate the number of moles of Bal2:

First, we need to convert the mass of Bal2 to moles using its molar mass. The molar mass of Bal2 can be calculated by summing the atomic masses of boron (B) and iodine (I):

Molar mass of Bal2 = (atomic mass of B × 1) + (atomic mass of I × 2)

Molar mass of Bal2 = (10.81 g/mol × 1) + (126.90 g/mol × 2)

Molar mass of Bal2 = 10.81 g/mol + 253.80 g/mol

Molar mass of Bal2 = 264.61 g/mol

Now we can calculate the number of moles of Bal2:

Moles of Bal2 = Mass of Bal2 / Molar mass of Bal2

Moles of Bal2 = 413 g / 264.61 g/mol

Moles of Bal2 ≈ 1.561 mol

2. Calculate the molarity of the solution:

Molarity (M) = Moles of solute / Volume of solution (in liters)

Molarity (M) = 1.561 mol / 0.75 L

Molarity (M) ≈ 2.081 M

Therefore, the molarity of the solution is approximately 2.081 M.

The molarity of the solution is approximately 1.408 M as to calculate the molarity of a solution, one must need to know the number of moles of the solute and the volume of the solution in liters.

The molar mass of BaI₂ is:

Ba (barium) atomic mass = 137.33 g/mol

I (iodine) atomic mass = 126.90 g/mol

Molar mass of  BaI₂ = (Ba atomic mass) + 2 × (I atomic mass)

= 137.33 + 2 × 126.90

= 137.33 + 253.80

= 391.13 g/mol

Given that the mass of BaI₂ is 413 g,

Number of moles = Mass / Molar mass

= 413 g / 391.13 g/mol

= 1.056 moles

Volume of solution = 750 ml = 750/1000 = 0.75 L

Finally, one can calculate the molarity of the solution using the formula:

Molarity = Number of moles / Volume of solution

= 1.056 moles / 0.75 L

= 1.408 M

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how many grams of agcl will form by adding enough agno3 to react fully with 1500 ml of 0.400 m bacl2 solution?

Answers

Answer:

85.99 grams of AgCl will be formed.

Explanation:

To determine the grams of AgCl formed in the reaction, we need to consider the stoichiometry of the reaction between silver nitrate (AgNO3) and barium chloride (BaCl2):

AgNO3 + BaCl2 -> AgCl + Ba(NO3)2

The balanced equation shows that the molar ratio between AgNO3 and AgCl is 1:1. This means that 1 mole of AgNO3 produces 1 mole of AgCl.

Given:

Volume of BaCl2 solution = 1500 ml = 1.5 L

Molarity of BaCl2 solution = 0.400 M

First, we need to calculate the number of moles of BaCl2 present in the solution:

moles of BaCl2 = volume of BaCl2 solution * molarity of BaCl2 solution

= 1.5 L * 0.400 M

= 0.600 moles

Since the molar ratio between BaCl2 and AgNO3 is 1:1, the number of moles of AgNO3 needed for complete reaction is also 0.600 moles.

Now, using the molar mass of AgCl, which is 143.32 g/mol, we can calculate the grams of AgCl formed:

grams of AgCl = moles of AgNO3 * molar mass of AgCl

= 0.600 moles * 143.32 g/mol

= 85.99 grams

Therefore, by adding enough AgNO3 to react fully with the 1500 ml of 0.400 M BaCl2 solution, approximately 85.99 grams of AgCl will be formed.

What volume of 3.0 M KOH contains 2.1 g?

Answers

Answer: about 12.5 mL is the estimated volume of a solution containing 2.1 g of KOH with a concentration of 3.0 M.

which stament is true about endothermic and exothermic reactions? 1. Energy is absorbed 2. energy is released in an endothermic reaction. 3. the products have more potential energy than the reactants in an exothermic reaction. 4. the products have more potential energy than the reactant in an endothermic reaction.

Answers

Answer:

Overall, energy is released in exothermic and absorbed in endothermic reactions. Therefore, "a" is the correct statement. The other statements are all incorrect.

Explanation:

u suck

A teacher showed this animal to studenst on a field trip

Answers

If a teacher showed an animal to students on a field trip. The  tool will allow the students to best see the animal up close is the hand lens.

Option D is correct.

What is a  Hand lens?

A hand lens is known as a magnifying glass  which is a convex lens that is used to produce a magnified image of an object. The lens is usually mounted in a frame with a handle.

A hand lens  has two essential properties which are its focal length and its diameter.

The students will therefore require a hand lens to look up the animal close.

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#complete question:

A teacher showed this animal to students on a field trip. Which tool will allow the students to best see the animal up close? O A Tape measure O B Graduated cylinder O c. Notebook O D. Hand lens

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