A metal ball is hanging from the ceiling through an insulating thread. This ball is attracted to a positively charged rod that is held near the ball and thus the charge of the ball must be Negative or Neutral.
Study and theory appliedWhether any object is made up of conductive or nonconductive material, it affects how it behaves once it has been charged.
Electrons can move freely between particles when they are in conductors, which are substances. Charge can be transported across the whole surface of an object constructed of a conducting substance.
Charge is swiftly dispersed all across the full surface of the object if it is applied to it at a specific point. The motion of the electrons causes the distribution of charge.
A charged conductor can even transfer its charge to any another object if it comes into contact with that other object. When one object is constructed of a conducting substance, the charge can be transferred from one object to another more easily.
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A driver starts his parked car and within 5 hr reaches a speed of 60 km/h, as he travels east. what is his acceleration?
Answer:
change in speed) / (time for the change)
and the direction of the change.
Acceleration = (60 - 0) km per hour / 5 sec = 12 km per hour per second, east.
I hear teachers all over the country complaining about that ugly unit.
It has to be changed to a more familiar unit of acceleration.
(12 km/hour) x (1 hour/3600sec) = 12,000/3600 = 3-1/3 meter/sec.
His acceleration is 3-1/3 meters per second² .
Explanation:
a
Answer:
u=0
v=60 km/ hr
60 \times 1000 \\ 60 \times 60 = 1800
t =5
t = 5 \times3600 = 18000
a= ?
a = v - u \div t
= 1800 - 0 \div 18000 \\
1m/s^2\: ans
An object has a 2 c charge. the object breaks into two pieces. one piece has a charge of -5 c. what is the exact charge (in c) of the other piece? do not include units with your answer.
An object has a 2 c charge. the object breaks into two pieces. one piece has a charge of -5 c is 7
What is charge?Charge is the traveling longitudinal wave energy. Mass and charge are the indeed related and can be simplified to a single energy equation. To relate mass and charge, Coulombs can be explained as the wave amplitude, which is measured as a distance (meters). If one assumes a substance in vacuum of space that has a physical property of kilograms, and moves as waves, then mass and charge can be described as their motion. In EWT, this substance is referred to as the ether and its components as granules.
Let's call Q the initial charge of object, which is:
Q=2c
When it breaks, two pieces will have charge and , and since the total charge must be conserved, the sum of these two charges must be equal to the initial charge of the object:
Q=Q1+Q2
We also know charge of one of the two pieces:
Q1=-5
So, by substituting Q and Q1 into the equation, we can find charge of the second piece, Q2:
Q2=Q-Q1=2-(-5)=+7
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a bullet in a gun is accelerated from the firing chamber to the end of the barrel at an average rate of 6.3 cross times 10 to the power of 5 space m divided by s to the power of 2 space end exponent for 8.1 cross times 10 to the power of negative 4 end exponent space s. what is the bullet’s final velocity when it leaves the barrel, commonly known as the muzzle velocity?
The muzzle velocity of the bullet is 510.3 m/s.
What is muzzle velocity?The projectile's speed when it exits the gun's muzzle is known as muzzle velocity.
The quality (burn speed, expansion) and quantity of the propellant, the mass of the projectile, and the length of the barrel all affect the muzzle velocity of conventional firearms. While a slower burning propellant can use a heavier projectile, it requires a longer barrel to burn completely.
Apply the kinematics equation,
v=u+at
Here v is the final velocity, u is the initial velocity, a is the acceleration and t is the time interval during which a body is under acceleration.
The muzzle velocity of a bullet is the velocity with which the bullet leaves contact with the barrel of the gun.
The muzzle velocity or the final velocity of the bullet will be
v=u+at
v=0+(6.3×[tex]10^{5}[/tex])(8.1×[tex]10^{-4}[/tex])
=50.3 m/s
Therefore, the muzzle velocity of the bullet is 510.3 m/s.
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An object is dropped from the top of a building and hits the ground 3 seconds after it is released. what is the approximate speed of the object at the instant it hits the ground?
Once the object is dropped ,The only force acting on it is gravity.so acceleration due to gravity is 9.8 m/[tex]s^{2}[/tex].
Given,
Initial velocity = u = 0
Time taken = t = 0
Acceleration = g = 9.8 m/[tex]s^{2}[/tex]
Using [tex]3^{rd}[/tex] equation of motion ,
v = u + at
v =( 0 )+ (9.8) *(3)
v = 29.4
v≈ 30 m/s
So, the speed of object is 30 m/s.
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11. the square of the speed of an object undergoing a uniform acceleration a is some function of a and the displacement s, according to the expression given by
v^2 = k am sn,
where k is a dimensionless constant.
we have to tell the whether it is dimensional or dimensionless
v = m/sec dimesions
a = m/sec^2 dimesion, m = m
v^2 = m^2 / sec^2 = k m/sec^2 * m
k = dimesionless constant.
Dimension is a measurable extent, such as the three principal dimensions of an object of width, height, and depthdimension is of many types radial, angular, linear etc.Reference Dimensions is a Dimension without a tolerance, used for information purposes only. A reference is a repeat of a given dimension or established from other values one dimension is practically not found.To know more about Dimension visit : https://brainly.com/question/1374629
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A light-rail train going from one station to the next on a straight section of track accelerates from rest at 1.1 m/s2 for 20 s. it then proceeds at constant speed for 1100 m before slowing down at 2.2 m/s2 until it stops at the station. what is the distance between the stations?
The distance between the stations is 1320 m
How to determine the distance travelled in the first 20 sWe'll begin by calculating the distance travelled by the train in the first 20 s. This can be obtained as follow:
Initial velocity (u) = 0 m/sAcceleration (a) = 1.1 m/s²Time (t) = 20 sDistance (s) =?s = ut + ½at²
s = (0 × 20) + (½ × 1.1 × 20²)
s = 0 + 220
s = 220 m
How to determine the distance between the stationsThe distance between the stations can be obtained as illustrated below:
Distance in the 1st 20 s = 220 mDistance in the remaining journey = 1100 mTotal distance =?Total distance = 220 + 110
Total distance = 1320
Thus, the distance between both stations is 1320 m
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If a bird catches its prey from a height which is initially at rest them the momentum is conserved for
The momentum of both the engaged animals—a bird and its prey—is conserved.
What does linear momentum conservation mean?
If there is no external force acting on the colliding objects, the total momentum before and after the collision will be the same, according to the conservation of momentum principle.
Initial momentum is the same as final momentum.
As a result, both the engaged animals—a bird and its prey—keep their momentum.
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How much work, , must be done on a system to decrease its volume from 17.0 l to 9.0 l by exerting a constant pressure of 4.0 atm? =
By applying the specified constant pressure, the system's work done to reduce its volume from start to final is 32 l atm.
Initial volume v1 = 17.0 l
final volume v2 = 9.0 l
Pressure P= 4.0 atm
When a gas expands, there is an amount of work that is done that is equal to the product of the gas's pressure and its volume change.
We apply the formula for work done by gas against a constant external pressure.
expression: Work done = -(P. d V)
Therefore substituting the values :
Work done = - P (v2 - v1)
= - 4.0 x (-8.0) l atm
= 32 l atm.
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A cross-country skier moves 36 meters eastward, then 44
meters westward, and finally 22 meters eastward.
What is the magnitude and direction of the displacement ?
Answer:
d = 102 m
Explanation:
distance = 36 m + 44 m + 22 m
Distance = 102 m
How many of the 900 positive 3-digit numbers have a units digit of 2 and are the square of an integer?
The simple solution is to count all the integers that only have odd digits and subtract them from 900. Final solution: 900 – 125 = 775.
What are odd digits?Odd and even numbers have opposite parities, therefore 13 is an example of an odd number. In particular, zero has an even parity. The parity of any pair of consecutive integers is opposite. The last digit of an integer stated in the decimal numeral system determines whether the value is even or odd. That example, an odd number is one where the last digit is one, three, five, seven, or nine; otherwise, an even number is one where the last digit is one, two, four, six, or eight.
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A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is?
A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is
the coefficient of restitution is 0.8.Given that
A ball hits a wall going 10 m/s, and bounces off going 8 m/s.To find
the coefficient of restitutionSo according the question
We have
The initial velocity of approach towards the wall isu = 10 m/s.
The final velocity of separation from the wall after the collision isv = 7 m/s.
Now, We have to find the coefficient of restitution
We know that,
[tex]n = \frac{velocity \;\;of \; \;separation}{velocity \;of \;approach}[/tex]
So,
[tex]n = \frac{8}{10}[/tex]
n = 0.8
The coefficient of restitution is 0.8.
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A ______ focal length lens makes the background and foreground appear closer together.
Short focal length lens makes the background and foreground appear closer together.
What is a short focal length made lens?Short focal length lenses are sometimes known as wide-angle or wide-field lenses, which accurately defines their key characteristic—they view a larger angle of a scene than is typical.
When your eyes are fixed in one place and you look at a scene, a lens with a typical focal length captures what you see.
Are shorter focal lengths preferable?The angle of view is narrower, and the magnification is higher the longer the focal length.
What are short lenses used for?A shorter focal length results in a wider angle of view and a lower magnification.
Because they provide a broad field of view, short focal length lenses are frequently utilized in architectural, documentary, and landscape photography. These telephoto lenses enable
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why did scientists using classical, newtonian physics have difficulty explaining the photoelectric effect
The correct answer is :
According to classical electrodynamics, light energy is a wave that is absorbed by atoms in a manner similar to how an object absorbs radiant heat. So, the atoms of a metal would absorb more energy the brighter the light was. It would be feasible for an electron in a metal to break free from its atoms if it received enough energy from the incoming wave. The more energy absorbed, the more energetic the metal's released electrons would be. Additionally, no electrons could conceivably be ejected until each atom had enough light energy. Light intensity was far more important than light frequency.
In many respects, the photo-electric effect contradicted this strategy:
If the light was below a specific frequency, no matter how bright it was, no electrons were released. Increased light intensity increased the number of electrons that were released, but not their energy, if the light was above this frequency.Regardless of how weak the light was, electrons were nearly immediately emitted from the metal. Even though the intensity of the light was reduced, an increase in its frequency led to more energising electrons leaving the metal.To learn more about photo-electric effect refer the link:
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During each cycle of operation, a refrigerator absorbs 230 j of heat from the freezer and expels 356 j of heat to the room. how much work input is required in each cycle?
126 J work input is required in each cycle .
Work is the product of the component of the force in the direction of the displacement and the magnitude of this displacement.
Mathematically, the above statement is expressed as follows:
W = (F cos θ) d = F. d
Where,
W is the work done by the force.
F is the force, d is the displacement caused by force
θ is the angle between the force vector and the displacement vector
The dimension of work is the same as that of energy and is given as, [ML2T–2].
Given,
refrigerator absorbs 230 J of heat from the freezer
expels 356 J of heat to the room
work input is required in each cycle = 356 - 230
= 126 J.
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Make the following prefix conversions.
600,000 cm = Km
0.06
60
6
0.6
Answer: 6 km
works on odyseyware
The answer would be is 6 km
An accelerometer is made with a crystal of natural frequency 20 khz. the damping ratio of the accelerometer is found to be 0.71. determine the upper cutoff frequency of the accelerometer for 1 accuracy.
The upper cutoff accelerometer is made with a crystal of natural frequency of the accelerometer is 7.334 KHz.
What is accelerometer?An accelerometer is a tool that precisely measures acceleration. Proper acceleration is the acceleration of a body in its own instantaneous rest frame, as opposed to coordinate acceleration, which is acceleration in a fixed coordinate system.
Accelerometers are devices that measure the acceleration or vibration of a structure. They have a transducer that converts mechanical force caused by vibration or a change in motion into an electrical current by using the piezoelectric effect.
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How is gravity helping to widen the valley of the Colorado River through the Grand Canyon?
Gravity helps to widen the valley of the Colorado River through the Grand Canyon through the forces which increases the pressure thereby leading to it being eroded.
What is Gravity?This is referred to as the force of attraction which occurs on objects which draws them toward the center of the planet.
Gravity acts downwards on all bodies on earth which is why the Colorado River erodes downward. This then results in the movement of materials from high to low areas.
This the leads to the continual widening of the valley of the Colorado River through the Grand Canyon and is therefore referred to as the most appropriate answer.
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you walk 3 km due east, then 2.5 km due south, then 11 km due west. how far are you from your start position?
If you walk 3 km due east, then 2.5 km due south, then 11 km due west, then you are 9.34 km far from the starting point.
Pythagoras theorem applicationIf you connect all the paths, it will make a triangle. If you join your current position with the start position, then you get the triangle ADE.
This question can be solved by using the application of Pythagoras theorem.
This theorem states that in a right-angled triangle, square of longest side is equal to the sum of the individual squares of the other two sides
Here, AD is the same as BC = 2.5km
and then EC = 11km and DC = AB = 3km
ED= EC-DC = 9 km
In the triangle ADE, according to Pythagoras theorem,
AE^2 = AD^2 + ED^2
so, AE = sqrt (9^2 + 2.5^2)
⇒ AE= sqrt (81 + 6.25)
⇒ AE = 9.34 km
Thus, you are about 9.34 km distance from your start point.
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19. Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s. How far did he travel during this time?
Jorge was driving at 20m/s. He accelerated at a rate of 2m/s² for 10s.
So he travel ---m during this time.
Jorge was driving at 20m/s, so speed = 20 units
He accelerated at a rate of 2m/s² so acceleration = 2 units
Time taken by Jorge is 10 units.
We know by Newton's 2nd equation of motion that
S= ut + (1/2)*a*t*t
where S is distance, a is acceleration, u is initial velocity and t is time.
So S=?
Time t = 10
Acceleration a =2
Initial Velocity u = 20
Hence distance travelled by Jorge is S=300 m
Thus Jorge travelled 300m during this time at speed 20m/s accelerated at a rate of 2m/s² for 10s.
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a boat is stationary at 12\, \text{meters}12meters12, start text, m, e, t, e, r, s, end text away from a dock. the boat then begins to move toward the dock with an acceleration of 5.0\, \dfrac{\text{m}}{\text{s}^2}5.0 s 2 m 5, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction. how long will it take the boat to reach the dock?
The time taken for the boat to reach the dock is 2.19 s
Data obtained from the questionFrom the question given above, the following data were obtained:
Initial velocity (u) = 0 m/sDistance (s) = 12 mAcceleration (a) = 5 m/s² Time (t) = ?How to determine the timeThe time taken for the boat to reach the dock can be obtained as illustrated below:
s = ut + ½at²
12 = (0 × t) + (½ × 5 × t²)
12 = 0 + 2.5t²
12 = 2.5t²
Divide both side by 2.5
t² = 12 / 2.5
Take the square root of both side
t = √(12 / 2.5)
t = 2.19 s
Thus, the time taken is 2.19 s
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A soccer ball was kicked toward the goal. The horizontal component of velocity was 22 m/s and the vertical component was 12 m/s. What is the magnitude of the resultant velocity of the soccer ball?.
The magnitude of the resultant velocity of the soccer ball is: 25.059 m/s
The formula for projectile motion that we will use to solve this exercise is:
vf= √[v(x)² + v(y)²]
Where:
vf= final velocityv(x)= horizontal component of velocityv(y)= vertical component of velocityInformation about the problem:
v(x)= 22 m/sv(y)= 12 m/svf=?Applying the final velocity formula we have:
vf= √[v(x)² + v(y)²]
vf= √[(22 m/s)² + (12 m/s)²]
vf= √[484 m²/s² + 144 m²/s²]
vf= √[628 m²/s²]
vf= 25.059 m/s
What is projectile motion?The projectile motion is the motion whose trajectory describes a parabola having a horizontal and a vertical component of motion.
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When randomly arranged low energy protons enter the magnetic field they become static and ______________ with the main magnetic field and net magnetization.
When randomly arranged low-energy protons enter the magnetic field they become static and parallel with the main magnetic field and net magnetization.
What is net magnetization?The magnetic moments of each individual hydrogen atom are added to create the net magnetization vector in MRI. Individual magnetic moments are arbitrarily oriented when there is no external magnetic field, and because they are in opposition, the net magnetization vector is thought to be zero.
How magnetization m is connected with the magnetic field?The intensity of magnetization, or just magnetization, is the term used to describe the magnetic dipole moment per unit volume of a substance (M). The relationship between the applied magnetic field (H) and the material's internal magnetic flux density or magnetic induction (B) is linear.
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a hockey player is standing on his skates on a frozen pond when an opposing player, moving with a uniform speed of 2.0 m/s, skates by with the puck. after 1.40 s, the first player makes up his mind to chase his opponent. if he accelerates uniformly at 0.22 m/s2, determine each of the following.
A hockey player is standing on his skates on a frozen pond, if he accelerates uniformly at 0.22 m/s2, the player will catch his opponent in 19.49 seconds.
Uniform Motion
The object's uniform motion should follow the following rules as provided
vt = vo + at
vt² = vo² + 2a . s
s = vo*t + 1/2*a*t²
Here vt is seen as the final velocity, vo = initial velocity
a= acceleration t= time and s= displacemnt
according to the question,
v = 2
t= 1.4
vo= 0 m/s
a = 0.22 m/s²
The distance between the players is seen as
Vt= 2x 1.4 = 2.8 m
The player will thus catch his opponent with the same distance. This means,
Sopponent = Splayer
so + vt = vo*t + 1/2 at²
⇒ 2.8 + 2.t = 0 . t + 1/2 . 0.22 . t²
⇒ 0.11t² - 2t - 2.8 = 0
⇒ t = 19.49 s
on solving the above quadratic equation, we calculate the possible root as 19.49 seconds.
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Find the maximum height ymax reached by the rocket. ignore air resistance and assume a constant acceleration due to gravity equal to 9.80 m/s2 .
Answer:
11,907 m is the maximum height ymax reached by the rocket.
Explanation:
The equations which relate displacement, velocity, acceleration and time are known as Equation of Kinematics. In this problem we use second and third equation of kinematics solve,
s = vit+1/2at2
V2f − V2i=2as
It is important to note from the information provided in the question
Acceleration in the first phase a1=49.0m/s2
Time for acceleration t=9.00s
Acceleration in the second phase a2=−9.8 ms-2
Height reached in first phase
y1=vit+1/2a1t2
y1 =0ms-1 × 9.00s + 12×49.0 ms-2 × (9.00s)2
=1984.5m
velocity at the end of first phase
v1=49.0 ms-2 × 9.00s
=441m/s
Now height reached in the second phase
V2f − V21 = 2a2y2
At maximum height final velocity is zero.
=02−(441.0m/s)2
=2(−9.80 ms-2) y2
y2=(0-(441.0 ms-2))/(2×(-9.80ms-2))
=9922.5m
So, the maximum height ymax reached by the rocket
ymax = y1+y2
ymax =1984.5m+9922.5m
=11907m
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two vectors, one with a magnitude of 14 units and one with a magnitude of 5 units, are both pointing east. what is the resultant of these two vectors?
The resultant of these two vectors is 19 units of two vectors, one with a magnitude of 14 units and one with a magnitude of 5 units, are both pointing east.
Explanation
As we know R = A + B
where is R resultant A and B are vectors is possible only if the both the vectors are in the same direction.
Therefore, R = 14 + 5
19 units
What is resultant force?A resultant force is the single force and corresponding torque that are created when a system of forces and torques acting on a rigid body is added together using vectors in physics and engineering. A consequent force, also known as a resultant force-torque, is one that acts on a rigid body in the same way as the initial system of forces.
Through computational analysis or (in the case of sufficiently simple systems) a free body diagram, the resultant force on a body is calculated and visualized.
The resultant force's location of application defines the torque it produces. Some people use the term resultant force-torque to describe the forces and torques acting on a rigid body; the word resultant force should be understood to include both.
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electricity is distributed from electrical substations to neighborhoods at 16000 v. this is a 60 hz oscillating (ac) voltage. neighborhood transformers, seen on utility poles, step this voltage down to the 120 v that is delivered to your house.
The correct answer is 1.575 A.
a)
From Transformer turns ration
N_s/N_p =V_s/V_p
=>N_p =N_s × (V_p/V_s) =100 × (1.6 × 10^4/120)
N_P=1.33 × 10^4 Turns
b)
P_out =P_in
V_sI_s =V_PI_P
210 × 120 =(1.6 × 10^4)I_p
I_p=1.575 A
What is the working principle of an electric generator?
The generator is composed of a coil with many copper wires coiled around an iron core that is rectangular in shape. The armature is the term for this coil. This armature's purpose is to boost the magnetic flux. The armature revolves between two powerful permanent magnets that have been set. Here, the magnetic lines that are created are orthogonal to the axis of the armature. Two slip rings are further attached to the armature's arms. Two metallic brushes are also linked to the slip rings, which aid in moving current from the armature to the slip rings. These rings are employed for creating moveable contact. Last but not least, the current flows via a load resistance that is wired in parallel with and across the two slip rings.
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Where on the x-axis can a third positive charge be placed so that the net electric force on it is zero?
A third positive charge [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex] can be placed on the x-axis so that the net electric force on it is zero.
whilst -factor charges are in touch, there may be
[tex]F = k \frac{q_{1}q_{2} }{ r^{2} }[/tex]
Where
[tex]k = 9 * 10^{9} Nm^{2}C^{-1}[/tex] = the coulomb constant.
The charges' magnitudes are [tex]q_{1}[/tex] and [tex]q_{2}[/tex].
r is the separation of the charges.
Let,
The third charge equals Q at, x equals x from the source.
because there is no net force acting on the third charge.
Hence,
[tex]f_{1} + f_{2} = 0[/tex]
⇒ [tex]k\frac{(2q)Q}{x^{2} }-k\frac{qQ}{(2a-x)^{2} } = 0[/tex]
⇒ [tex]\frac{2}{x^{2} } - \frac{1}{(2a-x)^{2} } = 0[/tex]
⇒ [tex]\frac{2}{x^{2} } = \frac{1}{(2a-x)^{2} }[/tex]
⇒ [tex]\frac{\sqrt{2} }{x} = \frac{1}{2a-x}[/tex]
⇒ [tex]2\sqrt{2}a - \sqrt{2} = x[/tex]
⇒ [tex]x = \frac{2\sqrt{2}a }{1+\sqrt{2} }[/tex]
handiest when forces resulting from previous prices cancel every different out will the pressure on a third fee be 0.
at the same time as the pressure between identical costs is repulsive and is interpreted as high-quality, the pressure between two opposing expenses is attracted and is interpreted as bad.
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Which of the following correctly describes the axes and units of
a position-time graph?
A position-time graph shows how far an object has traveled from its starting position at any given time since it started moving.
The graph on which the immediate function x of a particle is plotted at the y-axis and the time t on the x-axis is called the position-time graph.
The distinction between them is that the velocity-time graph famous the speed of an item and whether it's miles slowing down or dashing up, whilst the position-time graph describes the motion of an item over a period of time.
Position-time graph and displacement-time graph is same. but each are different from distance-time graph. role-time graph and displacement-time graph may be bad. Distance-time graph can by no means be negative.
The shapes of the position-time graph for these basic varieties of motion - consistent pace movement and multiplied movement i.e., converting speed - monitor an vital precept. The precept is that the slope of the road on a position-time graph well-known shows beneficial statistics about the speed of the item.
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light strikes a 5.0-cm thick sheet of glass at an angle of incidence in air of 50°. the sheet has parallel faces and the glass has an index of refraction 1.50. a. what is the angle of refraction in the glass? b. after traveling through the glass the light re-emerges into the air. what is the final angle of refraction in air? c. as it leaves the glass, by what distance is the path of the ray is displaced from what it was before entering the glass?
The angle of refraction in the glass is 30°.
Calculationi= 50°
u= 1.50
u1sini=u2sinr
⇒sinr =[tex]\frac{sin 50}{1.5\\}[/tex]
=0.50=1/2
so angle r = [tex]sin^{-1}[/tex](0.5) =30°
Then we have to calculate r final.
[tex]u_{glass}[/tex]sini= [tex]u_{air}[/tex] sinr
⇒ r = [tex]sin^{-1}[/tex] (1.5 x [tex]\frac{\sqrt{3} }{2}[/tex])
[tex]sin^{-1}[/tex](1.29) = 0.0225
Then the displacement can be calculated as follows:
T= thickness = 5cm
s= t (1- 1/u)
s= 2cm
Thus, all the values have been found out.
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what is a set of particles or interacting components considered to be a distinct physical entity for the purpose of study.
a system is a collection of particles or interacting parts that is regarded as a unique physical entity for the purposes of study.
What is a physical entity?It is an entity that has a physical existence. An entity is something that exists in itself, real or potential, concrete or abstract, physical or not. It does not have to be of material existence. In particular, legal abstractions and fictions are generally considered entities. Also, in general, an entity is not considered animate. The word entitative is the adjective form of the nominal entity. Something entity is considered for itself. In philosophy, ontology consists in recognizing entities. The words ontic and entity derive from the present participles of ancient Greek and Latin, respectively, meaning being.
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