a mass of 2.00 kg rest on a rough horizontal table. The coefficient of static friction between the block and the table is 0.60. The block is attached to a hanging mass by a string that goes over a smooth pulley,as shown in the diagram. Determine the largest mass that can hang in this way without forcing the block to slide.

Answers

Answer 1

Answer:

1.2 kg

__________________________________________________________

We are given:

Mass of the block = 2 kg

Coefficient of Static Friction = 0.6

__________________________________________________________

Friction Force on the Block:

Finding the Normal Force:

We know that the normal force will be equal and opposite to the weight of the 2 kg block

So, Normal Force = mg

replacing the variables with the given values

Normal Force = (2)(9.8)                    [Taking g = 9.8]

Normal Force = 19.6 N

Friction force on the Block:

We know that:

Coefficient of Static Friction =  Static Friction Force/Normal Force

replacing the variables

0.6 = Static Friction force / 19.6

Static Friction force = 0.6*19.6 N                 [Multiplying both sides by 19.6]

Static Friction force = 11.76 N

__________________________________________________________

Largest Mass that can Hang:

We know that the Static Friction force is 11.76 N, this means that a force of 11.76 N will be applied to keep the object at rest

So, if the weight of the second block is less than the static friction force, it will hang

Weight of the second block ≤ 11.76

We know that weight = mg

mg ≤ 11.76

m(9.8) ≤ 11.76                                                   [since g = 9.8]

m ≤ 1.2 kg                                                        [dividing both sides by 9.8]

From this, we can say that the maximum mass of the second block is 1.2 Kg

A Mass Of 2.00 Kg Rest On A Rough Horizontal Table. The Coefficient Of Static Friction Between The Block

Related Questions

If two exactly the same cars are driving down a road, which one would have the most kinetic energy. The one that is moving faster, the one that is moving downhill, the one that is moving uphill, or the one that is moving slower.

Answers

Answer: the car that is moving downhill

Explanation:

The free-body diagram below shows the forces acting on a bicycle as the
rider pedals to the right. The vectors are not drawn to scale. The bicycle has a
weight of 800 N and a pedaling force of 250 N. As it moves, it encounters 75
N of air resistance. What is the net force on the bicycle in the x-direction?

Answers

Answer:

175 N to the right

Explanation:

I am taking the quiz and this is the correct answer. The pedaling force if 250 N but when it encounters 75 N of air resistance, it reduces to 175 N. This is because the air resistance is going opposite of you.

The weight of the bike and the cyclist are a force that the Earth applies to both of them and that acts vertically and downward, causing an action on the ground. The pedal-pushing force is transmitted from the crank arm to the chainring axis via the transmission forces.

What forces acting on a moving bicycle?

When we press the pedals, the force travels to the back wheel, which then applies pressure to the ground. Strength of action. The pavement responds by exerting a force in the opposite direction but in the same direction on the back wheel. Hence, always move forward.

Therefore, Walking and biking are made possible through la friction. The friction created by the tire's pressure on the ground, It prevents the tire from rotating and keeps the lowest part of the wheel on the ground. The wheel is driven by this force, which is transferred to the wheel axle.

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The fact that our preconceived ideas contribute to our ability to process new information best illustrates the importance of: the serial position effect. O repression iconic memory . semantic encoding . retroactive interference .

Answers

Answer:

It’s a

Explanation:

Don’t actually put that i needed the points mb

advantage of compound pendulum

Answers

hello you have a great day okay bye

Which of the following is not an example of work being done on an object?

Pushing on a rock that will not move

Paddeling a canoe down a river

Lifting a bag of groceries

Throwing a ball across a field​

Answers

Answer:

Lifting a bag of groceries

Answer:

paddeling a canoe down a river :D or throwing a ball across a field

Explanation:

The effect of gravity on a falling object can be modeled by a ball dropped from different heights. What is a limitation of this model?

A. Not all objects bounce, even though balls do.

B. Some balls float in water, while others sink.

C. The ball can be dropped from varying heights.

D. Friction with air also affects the fall of the object.

Correct answer is D

Answers

Answer:

D.

Explanation:

try it..  *lil uzi vert's voice*

The limitation of the model of a ball dropped from different heights is that friction with air also affects the fall of the object. Hence, option (D) is correct.

What is Galileo's Leaning Tower of Pisa experiment?

According to a biography written by Galileo's student Vincenzo Viviani in 1654 and published in 1717, between 1589 and 1592, the Italian scientist Galileo Galilei, who was then a professor of mathematics at the University of Pisa, is said to have dropped two spheres with the same volume but different masses from the Leaning Tower of Pisa to show that their time of descent was independent of their mass. A few decades previously, Italian experimenters had already proven the fundamental tenet.

Galileo, it is said, discovered through this experiment that the items fell with the same acceleration, confirming his prediction and refuting Aristotle's theory of gravity in the process (which states that objects fall at speed proportional to their mass). The majority of historians believe it to have been more of a thought experiment than a physical test.

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what is the potential energy of a 30kg rock that falls 15 meters

Answers

Answer:

4500 J

Explanation:

The potential energy of a body can be found by using the formula

PE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 10 m/s²

From the question we have

PE = 30 × 10 × 15

We have the final answer as

4500 J

Hope this helps you

What is the error in this representation of the steps involved in gene therapy?

Answers

ahh i hope this helps lol

Answer:

a

Explanation:

How was the Periodic Table of Elements developed and how are the elements arranged on it?

Answers

Answer:

In 1869 Russian chemist Dimitri Mendeleev started the development of the periodic table, arranging chemical elements by atomic mass. He predicted the discovery of other elements, and left spaces open in his periodic table for them.

Explanation:

Answer: Mendeleev first published a table of elements arranged according to increasing atomic masses. He noticed that some elements near each other had differing properties, but elements in vertical columns had similar properties. Moseley then rearranged the table according to atomic numbers and this eliminated the discrepancies found in Mendeleev’s attempt. Today’s version of the periodic table displays elements in order based on their atomic number; the atomic number indicates the number of protons within the atoms of a particular element. Rows are called periods and columns are called groups. Elements in the same group have similar properties. Elements are grouped into nine categories: noble gases, halogens, nonmetals, alkali metals, alkaline earth metals, transition metals, other metals, metalloids, and rare earth elements.

Galaxy B moves away from galaxy A at 0.577 times the speed of light. Galaxy C moves away from galaxy B in the same direction at 0.731 times the speed of light. How fast does galaxy C recede from galaxy A?

Answers

Answer:

The value is  [tex]p = 0.7556 c[/tex]

Explanation:

From the question we are told that

   The speed at which galaxy B moves away from galaxy A is  [tex]v = 0.577c[/tex]

Here c is the speed of light with value  [tex]c = 3.0 *10^{8} \ m/s[/tex]

     The speed at which galaxy C moves away from galaxy B is  [tex]u = 0.731 c[/tex]

Generally from the equation of  relative speed we have that  

     [tex]u = \frac{p - v}{ 1 - \frac{ p * v}{c^2} }[/tex]

Here p is the velocity at which galaxy C recede from galaxy A so

     [tex]0.731c = \frac{p - 0.577c }{ 1 - \frac{ p * 0.577c}{c^2} }[/tex]

=>   [tex]0.731c [1 - \frac{ p * 0.577}{c}] = p - 0.577c[/tex]

=>   [tex]0.731c - 0.4218 p = p - 0.577c[/tex]

=>   [tex]0.731c + 0.577c = p + 0.4218 p[/tex]

=>   [tex]1.308 c = 1.731 p[/tex]

=>    [tex]p = 0.7556 c[/tex]

What is the magnitude of the centripetal force that must be applied in order for a 2kg ball on a 2.0 m string to spin with uniform circular motion at 5.0 m/s

Answers

The ball needs to accelerate with a magnitude a (pointed towards the center of the circle) of

a = (5.0 m/s)² / (2.0 m) = 12.5 m/s²

Then the required tension F in the string would need to be

F = (2 kg) (12.5 m/s²) = 25 N

because centripetal force equals mv^2/r, we can plug in our known values to result in (2(5)^2)/2, which is equal to 25 n.

A fish swims to a depth of 50.00 meters in the ocean. Assuming the density of sea water is 1.0251.025 g·cm^{-3}g⋅cm −3 , calculate how much water pressure the fish is experiencing at this depth in units of kPa.

Answers

Answer:

The fish is experiencing a water pressure of 502.8 kPa.

Explanation:

The water pressure the fish is experiencing can be found as follows:

[tex]P = \rho gh[/tex]  (1)

Where:

g: is the gravity = 9.81 m/s²

h: is the height (depth) = 50.0 m

ρ: is the seawater's density = 1.025 g/cm³  

By replacing the above values into equation (1) we have:

[tex] P = \rho gh = 1.025 \frac{g}{cm^{3}}*\frac{1 kg}{1000 g}*\frac{(100cm)^{3}}{1 m^{3}}*9.81 m/s^{2}*50.0 m = 502.8 kPa [/tex]        

Therefore, the fish is experiencing a water pressure of 502.8 kPa.

I hope it helps you!        

A circuit can only light up a lightbulb if there is a ______ path for electricity to travel from one end of the energy source to the other end.

Answers

Answer:

Continuous

Explanation:

A circuit can only light up a lightbulb if there is a continuous path for electricity to travel from one end of the energy source to the other end.

Answer:

continuios

Explanation:

A circuit component that is a composed of a semiconductor layer sandwiched between two other semiconductor layers is a(n)?

Answers

Explanation:

It's a transistor. Hope that helps!

Answer:

D. Transistor

Explanation:

Edge 2021

A fluid of density rho = 900 kg/m3 flows along a pipe of constant diameter from point A to point B. Gauge pressure at point A is equal to zero, and absolute pressure at point B is 30% lower than pressure at point A. What is the height difference, Δh, between points A and B?
a. Δh = 8.09 m with point A above point B.
b. Δh = 344 m with point B above point A.
c. Δh = 303 m with point B above point A.
d. Δh = 3.44 m with point A above point B.

Answers

The height difference between points A and B is : ( B ) Δh = 3.44 m with point B above point A.

Given data :

fluid density = 900 kg/m³

Diameter of pipe = constant

Gauge pressure at Point A = 0

Gauge pressure at point B = 30% lower

Determine the height difference between points A and B

first step : determine absolute pressure

Pa (absolute pressure )= gauge pressure + atmospheric pressure

                                      = 0 + patm

Therefore : Pa = Patm

Also;

Pressure at point B ( Pb ) = Pa - 30%Pa

                                          = 0.7 Patm

Hence ; Pa - Pb = 0.3 Patm ----- ( 1 )

Final step : Determine the height difference

we will apply the formula below from equation ( 1 )

p *g * Δh = 0.3 * 1.013 * 10⁵      ( note : Patm = 1.013 * 10⁵ )

900 * 9.81 * Δh = 0.3 * 1.013 * 10⁵

therefore :

Δh = ( 0.3 * 1.013 * 10⁵ ) / ( 900 * 9.81 )

     = 3.44 m

Hence we can conclude that The height difference between points A and B is Δh = 3.44 m with point B above point A.

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An object with a mass of 32 kg has an initial energy of 500). At the end of the experimentthe velocity of the object is recorded as 5.1 m/s . the object travelled 50 m to get to this point, what was the average force of friction on object during the tripAssume no potential energy Show all work

Answers

Answer:

 F = 1.68 N

Explanation:

Let's solve this exercise in parts.

Let's use the concept of conservation of the mechanical nerve

initial

    Em₀ = 500 J

The energy is totally kinetic

     Em₀ = K = ½ m v₀²

     v₀ = [tex]\sqrt{\frac{2 Em_{o} }{m} }[/tex]

     v₀ = √ (2 500/32)

     v₀ = 5.59 m / s

now with kinematics we can find a space

      v² = v₀² - 2 a x

the negative sign is because the body is stopping

       a =[tex]( \frac{v_{o}^{2} - v^{2} }{2x} )[/tex]  

let's calculate

       a = (5.59² - 5.1²) / 2 50  

       a = 0.0524 m / s²

Finally let's use Newton's second law

     F = ma

     F = 32 0.0524

     F = 1.68 N

What is the acceleration of the the object during the first 4 seconds?

Answers

Answer:

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

Explanation:

What this formula is telling us is that if we know the acceleration of an object, and the ... we can plug in our acceleration of 12.5 m/s2 for a, and 4 seconds for t.

Velocity (m/s) over time (s) graph

Velocity (m/s) over time (s) graph

We could write out our average acceleration as:

a = Δv/ Δta=Δv/Δta, equals, Δ, v, slash, Δ, t

a = (15 m/s - 0 m/s) / 0.2 seconds

a = 15 m/s / 0.2 seconds

a = 75 m/s / second

A 65-cm segment of conducting wire carries a current of 0.35 A. The wire is placed in a uniform magnetic field that has a magnitude of 1.24 T. What is the angle between the wire segment and the magnetic field if the force on the wire is 0.26 N?
a. 37°.
b. 43°.
c. 23°.
d. 53°.
e. 67°.

Answers

Answer:

e) 67°

Explanation:

the force on the wire can be calculated using the expression below

F = BILsinФ

But we are looking for the angle between the wire segment and the magnetic field, then we can make Ф the subject of the formula from the above expresion, then we have,

Ф =sin⁻¹ (F/BIL)

The parameters is defined as

I =current that is been carried by the wire= 0.35 A

Ф = angle between the wire segment and the magnetic field, which is the unknown?

L = length of the wire=65 cm

B = magnetic field = 1.24

F= force on the wire = 0.26 N,

Ф =sin⁻¹ (F/BIL)

Ф =sin⁻¹ X .....................eqn(#)

Where X= (F/BIL)

We can calculate for X= (F/BIL), from eqn(#) by substituting value of Force, Lenght and

magnetic field

X=(F/BIL)= 0.26/(1.24×0.35×0.65)

= 0.26/0.2821

=0.922

Then substitute X into eqn (Ф =sin⁻¹ X)

Then

Ф =sin⁻¹ (0.922)

Ф=66.42°

Ф=67° approximately

Therefore, the angle between the wire segment and the magnetic field is 67°

If the magnitude of the electric field of an electromagnetic wave is 3x10^3 V/m, what is the the magntude of the magnetic field?
a. 1.1 x 10^-12 T
b. 9 x 10^11 T
c. 10^5 T
d. 10^-5 T
e. 3 x 10^3 T

Answers

Answer:

The value of the  magnetic field is [tex]B = 1.0*10^{-5} \ T[/tex]

The correct option is d

Explanation:

From the question we are told that  

    The magnitude of the electric field is  [tex]E = 3*10^{3} \ V/m[/tex]

     Generally the magnitude of  the magnetic field is mathematically represented as

        [tex]B = \frac{E}{c}[/tex]

Here  c is the speed of  light [tex]c = 3.0*10^{8} \ m/s[/tex]

=>     [tex]B = \frac{E}{c}[/tex]

=>      [tex]B = \frac{3.0*10^{3}}{ 3.0*10^{8}}[/tex]

=>      [tex]B = 1.0*10^{-5} \ T[/tex]

convert 100 Newton into dyne​

Answers

Answer:10000000

Explanation:

It would actually be 10 million dyne

The Steamboat Geyser in Yellowstone National Park shoots water into the air at 48.0 m/s. How
high will the water spray into the air?

Answers

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

Given;

initial velocity of the water, u = 48 m/s

at maximum height the final velocity will be zero, v = 0

the water is going upwards, i.e in the negative direction of gravity, g = -9.8 m/s².

The maximum height reached by the water is calculated as follows;

v² = u² + 2gh

where;

h is the maximum height reached by the water

0 = u² + 2gh

0 = (48)² + ( 2 x -9.8 x h)

0 = 2304 - 19.6h

19.6h = 2304

h = 2304 / 19.6

h = 117.55 m

Therefore, the maximum height reached by the water is 117.55 m.

Answer:

The maximum height reached by the water is 117.55 m.

Explanation:

The force of gravity between any two ordinary objects on the earth is.......
A) stronger when closer to the earth
B) stronger if the objects are closer to each other C) always downward
D) stronger than the force of gravity from the earth​

Answers

Answer:

c

Explanation: beacuse newtons law of phisics says ''what goes up must come down''

The force of gravity between any two ordinary objects on the earth is stronger if the objects are closer to each other.

The force of gravity between two object on the earth surface is given Newton's law of universal gravitation;

[tex]F= \frac{Gm_1m_2}{r^2}[/tex]

where;

G is gravitational constantm₁ and m₂ are the masses of the two objectsr is the distance between the two objects

The distance between the object is inversely proportional to the force of gravity between the objects. The smaller the distance between the two objects, the greater the force of gravity and vice versa.

Thus, we can conclude that the force of gravity between any two ordinary objects on the earth is stronger if the objects are closer to each other.

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Hello! How do you answer a question? I will give you 25 points if you answer it. :)

Answers

Answer:

press add answer and it will let you answer the question

Explanation:

Answer:

you click on the question, then you click answer, then type what you want, and click the green button on the top right saying dd your answer

Explanation:

Jadeen says that you can increase the resistance of a copper wire by hammering the wire to make it narrower and longer. Arnell says that you can increase its resistance by heating the wire. Which one, if either, is correct, and why?
1) Arnell, because the conductivity of the wire increases when it is heated.
2) Arnell, because the conductivity of the wire decreases when it is heated.
3) Jadeen, because the conductivity of a wire is directly proportional to its area and inversely proportional to its length.
4) Jadeen, because the conductivity of a copper wire does not increase and might decrease when it is hammered.
5) Both are correct because (b) and (d) are both correct.

Answers

Answer:

The answer is "Option 5".

Explanation:

Jadeen claims that only by hitting the wire to make it thinner and wider, it can improve a copper wire's strength, which is why a copper wire's permeability doesn't quite improve and can reduce once it is pounded. Arnell says so by heating its wire, it can improve its strength, and when it is heated, the wire's permeability reduces.

How much more efficient is organic farming than "regular" farming?

Answers

Answer:

Organic systems used 45% less energy overall than conventional systems. Production efficiency was 28% higher in the organic systems, with the conventional no-till system being the least efficient in terms of energy usage.

Answer: 65%

Explanation: i took the quiz

A projectile is fired horizontally from a height of 10 m above level ground. The projectile lands a horizontal distance of 15 m from where it was launched.
-Find the hang time for the projectile.
-Find the initial speed of a projectile.
-What are the x and y components of the projectile’s velocity the moment before it strikes the ground?
-At what speed will the projectile strike the ground?

Answers

Answer:

a)t  = 1,43 s

b) V = 10,49 m/s

c) V₀ₓ = 10,49 m/s   ;    V₀y = 14,01 m/s

d) Vf = 17,5 m/s

Explanation:

According to the problem statement

V₀ = V₀ₓ    and  V₀y = 0

And at the end of the movement t = ?  the distance y = 10 m

Therefore as

h = V₀y - (1/2)*g*t²

Vertical distance y = h = 10 = V₀y*t - 0,5 (-9,8)*t²

10 = 4,9*t²

t² = 10/4,9    ⇒  t² = 2,04 s

t  = 1,43 s

a) 1,43 s is the time of movement

b) V₀ = V₀ₓ        V₀y = 0     and  V₀ₓ = Vₓ     ( constant )

Just before touching the ground, the horizontal distance is

hd = 15 = Vₓ * t

Then  15 /1,43 = Vₓ = V₀ₓ

Vₓ = 10,49 m/s

Then initial speed is V = 10,49 m/s    since V₀y = 0

Vf² = Vₓ² + Vy²

Vyf = V₀y - g*t

Vyf =  0 - 9,8 *1,43

Vyf = - 14,01 m/s

And finally the speed when the projectile strike the ground is:

Vf² = Vₓ² + Vy²

Vf = √ (10,49)² + (14,01)²

Vf = 17,50 m/s

A rocket falls from the apogee (0 meters per second) until it hits the ground with a speed of 10 meters per second. Gravity pulled it down with an acceleration of 9.8m/s^2. The time during which the ball is in free fall is approximately what time?

Answers

Answer:

Approximately 1.02 seconds

Explanation:

Use the final velocity (vf) formula for a uniformly accelerated movement under "g" (acceleration of gravity):

[tex]v_f=v_i+g\,*\,t[/tex]

in our case:

[tex]10=0+9.8\,*\,t\\t=10/9.8\\t\approx 1.02\,\,sec[/tex]

Collision Lab
This activity will help you meet these educational goals:

You will explain or predict phenomena by exploring qualitative relationships between variables.
You will use positive and negative numbers to represent quantities in real-world contexts.
Directions
Read the instructions for this self-checked activity. Type in your response to each question, and check your answers. At the end of the activity, write a brief evaluation of your work.
Activity
Open this collision simulator and click Introduction. You’ll use the simulator to explore and compare elastic collisions and inelastic collisions. The mass and starting velocity of the colliding objects are kept constant. Follow the instructions in each part, and then answer the questions that follow. Use the math review if you need help with adding and subtracting negative numbers.

Question 1: Elastic Collisions
In this question, you will investigate elastic (bouncy) collisions. Be sure that the slider is to the extreme right (elasticity 100%).

Part A
Click Show Values in the upper-right corner. Study the boxes on the screen. What are the mass and initial velocity of ball 1 and ball 2?

I NEED HELP!


Part B
Part B
Click Play, and watch the balls collide. Then click Pause. What are the final velocities of ball 1 and ball 2?


The number line shows the starting and ending velocities for ball 1. What’s the change in velocity of ball 1? Calculate the value mathematically, and check it using the number line.

a number line showing an ending velocity of -0.50 meter/second and a starting velocity of 1.00 meter/second

Answers

Answer:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

Explanation:

Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

What is Collision?

A collision is any situation in which two or more bodies quickly exert forces on one another. Despite the fact that the most common usage of the word "collision" refers to situations in which two or more objects clash violently, the scientific usage of the word makes no such assumptions.

The following are a few instances of physical encounters that scientists might classify as collisions. Legs of an insect are said to collide with a leaf when it falls on one.

Every contact of a cat's paws with the ground while it strides across a lawn is seen as a collision, as is every brush of its fur with a blade of grass.

Therefore, Ball 1 has a mass of 0.5 kilogram and an initial velocity of 1.00 meter/second. Ball 2 has a mass of 1.5 kg and an initial velocity of 0.00 meters/second.

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Type of carbon that is produced from fossil fuels

Answers

Answer:

Carbon dioxide/CO2

Explanation:

i-

Answer:

I think Carbon Dioxide

Explanation:

Because When fossil fuels are burned carbon and hydrogen react with oxygen in air to carbon dioxide (CO2) and water (H2O).

There is a bell at the top of a tower that is 45 m high. The bell weighs 190 N. The bell has ____________
energy.

Answers

Answer:

The bell has a potential energy of 8550 [J]

Explanation:

Since the belt is 45 [m] above ground level, only potential energy is available. And this energy can be calculated by means of the following equation.

[tex]E_{p}= W*h\\E_{p} = 190*45\\E_{p}=8550[J][/tex]

Other Questions
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