A magnifier allows one to look at a very near object by forming an image of it farther away. The object appears larger. To create a magnifier, one would use a.

Explanation:

i think is per the International System of Units is Kelvin which is represented by the symbol K.

Answer:

If the Lego building is shaken side to side, it will withstand up to 60 seconds because front to back will cause the top of the building to collapse.

Answer:

Force=10N

Velocity=13m/s

Explanation:

Given,

Mass = 5kg

initial velocity=3m/s

Final velocity=7m/s

Time=2s

Now acceleration= v-u/t

=7-3/2

=4/2

=2m/s²

So, acceleration=2m/s²

Now,

F=ma

=5*2

=10N

Since the kinetic energy is equal to the potential energy then the speed of the object is √2gh.

The term work refers to the product of force and distance moved by force while energy is the ability to do work. The question is incomplete as the figure is not shown.

We know that the kinetic energy is equal to the potential energy hence;

mgh = 1/2mv^2

gh= 1/2v^2

v = √2gh

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Conversion of succinylcoA to succinate is the reaction that link acid cycle to the electron‑transport chain and amino acid synthesis.

SuccinylCoA is converted into succinate through the hydrolytic release of coenzyme A by succinyl-CoA synthetase Also succinyl-CoA is porphyrin synthesis, where it combine with glycine by ALA synthase to form δ-aminolevulinic acid.

Succinyl CoA is catalytically converted to succinate. The enzyme stimulates the hydrolysis of succinyl CoA into succinate and ATP and this represents a remarkable point of substrate level phosphorylation. After this, it link up to the electron transport chain via citric acid cycle.

Therefore, Conversion of succinylcoA to succinate is the reaction that link citric acid cycle to the electron‑transport chain and amino acid synthesis.

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The electron‑transport chain reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis.

The electron transport chain is a set of protein complexes that link redox processes to create an electrochemical potential that leads to the production of ATP in a process known as

Both photosynthesis and cellular respiration occur in mitochondria.

As a result, the process that connects the citric acid cycle to the electron transport chain and amino acid synthesis is succinyl-CoA to succinate conversion.

Hence the electron‑transport chain reaction connects the citric acid cycle to the electron‑transport chain and amino acid synthesis.

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Comets have an extremely eccentric orbit around the Sun. They can travel hundreds of thousands of years through the solar system before returning to the Sun at perihelion. Comets, like all orbiting bodies, obey Kepler's Laws, which state that the closer they get to the Sun, the faster they move.

A comet is a dirty snowball many kilometers across that exists at a considerable distance from the Sun. However, when it gets closer to the Sun, the comet's surface warms up, causing its components to melt and vaporize, resulting in the comet's distinctive tail. The distance between the Earth and the Sun can be measured in comet tails.

Answer:

The energy of a mechanical wave can travel only through matter. The matter through which the wave travels is called the medium (plural, media). The medium in the water wave pictured above is water, a liquid. But the medium of a mechanical wave can be any state of matter, even a solid.

Explanation:

Brainlest pls if can thank you ! i hope its helped

A metal bar is in the xy-plane with one end of the bar at the origin, [tex]\[r = (3.87 \, \text{m}) \mathbf{i} + (3.21 \, \text{m}) \mathbf{j}\][/tex], [tex]\theta\approx 55.16^\circ\][/tex], magnitude of torque is 22.58 Nm.

a) Position Vector r can be calculated as:

Given:

[tex]\(x = 3.87 \, \text{m}\)[/tex]

y = 3.21 m

The position vector r for the point where the force is applied is:

[tex]\[r = (3.87 \, \text{m}) \mathbf{i} + (3.21 \, \text{m}) \mathbf{j}\][/tex]

b) Magnitude of Torque can be calculated as:

Magnitude of r:

[tex]\[|r| = \sqrt{(3.87 \, \text{m})^2 + (3.21 \, \text{m})^2} \approx 5.019 \, \text{m}\][/tex]

Magnitude of F:

[tex]\[|F| = \sqrt{(6.82 \, \text{N})^2 + (-3.24 \, \text{N})^2}\\\\ \approx 7.610 \, \text{N}\][/tex]

Calculate the dot product of r and F:

[tex]\[r \cdot F = (3.87 \, \text{m}) (6.82 \, \text{N}) + (3.21 \, \text{m}) (-3.24 \, \text{N})\\\\ \approx 16.658 \, \text{N} \cdot \text{m}\][/tex]

Calculate the angle [tex]\(\theta\)[/tex] using the dot product and magnitudes:

[tex]\[\cos(\theta) = \frac{r \cdot F}{|r| \cdot |F|} \\\\= \frac{16.658 \, \text{N} \cdot \text{m}}{(5.019 \, \text{m})(7.610 \, \text{N})}\\\\ \approx 0.5526\][/tex]

[tex]\[\theta \approx \cos^{-1}(0.5526)\\\\ \approx 55.16^\circ\][/tex]

Now calculate the magnitude of the torque using the sine of the angle:

[tex]\[|\tau| = |r| \cdot |F| \cdot \sin(\theta)\\\\ = (5.019 \, \text{m}) (7.610 \, \text{N}) \sin(55.16^\circ)\\\\ \approx 22.58 \, \text{N} \cdot \text{m}\][/tex]

c) Direction of Torque:

According to the right-hand rule, the torque points either into or out of the plane formed by r and F. Its direction is perpendicular to that plane. The sign of the angle determines the precise orientation.

In this case, since [tex]\(\theta \approx 55.16^\circ\)[/tex] is positive (counterclockwise rotation), the torque points out of the plane formed by r and F.

Thus, the direction of the torque is outward from the xy-plane.

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Your question seems incomplete, the probable complete question is:

A metal bar is in the xy-plane with one end of the bar at the origin. A force F=(6.82)i+ -3.24j is applied to the bar at the point x=3.87m , y=3.21m .

What is the position vector r for the point where the force is applied?

a Express your answer in terms of the unit vectors i and j .

b What are the magnitude of the torque with respect to the origin produced by F?

c What are direction of the torque with respect to the origin produced by F?

Two equations will be needed to solve for the energy used in this procedure.

This is defined as the ability or capacity to do work. Ice being converted to vapor requires energy and the equations are seen below:

H₂O₍s₎  ⇒ H₂O₍l₎

H₂O₍l₎ ⇒ H₂O₍g₎

These are the equations which are used to calculate energy with heat being involved in both reactions.

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The magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.

Given the data in the question;

Coulomb's law states "that the force between two electrical charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them".

It is expressed as;

[tex]F = k\frac{q_1q_2}{r^2}[/tex]

Here, [tex]q_1\ and\ q_2[/tex]  are the two electrical charges, r is the distance between them and k is the Coulomb constant (  [tex]k = 8.98755*10^9 kgm^3/s^2C^2[/tex])

To determine the electrical force between the two charges, we substitute our values into the expression above.

[tex]F = k\frac{q_1q_2}{r^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{(1C)(1C)}{(1m)^2}\\\\F = (8.98755*10^9 kgm^3/s^2C^2)*\frac{1C^2}{1m^2}\\\\F = 8.98755*10^9 kgm/s^2\\\\F = 8.98755*10^9 N[/tex]

Therefore, the magnitude of the electrical force between the two identical electrical charges is 8.98755 × 10⁹N.

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The magnitude of the electrical force between the two charges is 8.987×10⁹ N.

As per the coulomb's law,  the electrical force between any two charges separated by a distance of r is given by the formula,

[tex]F = k\dfrac{q_1q_2}{r^2}[/tex]

Given that the value of q₁ and q₂ is 1 coulomb, while the distance between them is 1 meter. Also, the value of k is 8.987×10⁹ N·m²·C⁻², therefore, the force can be written as,

[tex]F = k\dfrac{q_1q_2}{r^2}\\\\F = (8.987 \times 10^{9}) \times (\dfrac{1 \times 1}{1^2})\\\\F= 8.987 \times 10^{9}\rm\ N[/tex]

Hence, the magnitude of the electrical force between the two charges is 8.987×10⁹ N.

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The direction of the normal contact force of the road on the wheels is : ( B ) Left

The contact force of the road on the wheels will act in a direction opposite to the movement of the wheel on the road. therefore as the wheel moves forward ( right ), the contact force will move backwards ( left ) of the direction of motion.

Hence we can conclude that the direction of the normal contact force of the road on the wheels is : ( B ) Left

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Answer:

crush

Explanation:

because the body come into contact

Thermal energy is involved when water changes from one phase to the next. Option A is correct.

Latent heat is the heat needed for the phase change . When the temperature remains constant during melting or boiling, the added energy is employed in the phase change process.

The total number of water particles remains constant when water changes states throughout the water cycle.

When water alterations from one phase to the next, thermal energy is involved. Latent heat is the storage of thermal energy.

Hence, option A is correct.

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The entropy at constant pressure is always greater than that at constant volume and the change in entropy for the two processes is greater for gas B.

According to the second law of thermodynamics, entropy in the isolated system always stays the same or increases.

Since gas does work in isobaric (constant pressure) change processes, the entropy at constant pressure will be greater than that at constant volume.

Thus, for gas A the process is carried out at constant volume while for gas B that is carried out at constant pressure. The change in entropy is greater for gas B.

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Answer:

8 oz

Explanation:

In the motion of the medium particles in a longitudinal wave, the medium vibrates parallel to the direction of the wave.

A longitudinal wave is a wave that is transversing along the length. When the displacement of medium and travel of wave is the same in that condition wave is known as the longitudinal wave.

It requires some medium to travel. A mechanical and sound wave is an example of a longitudinal wave.

Hence in the motion of the medium particles in a longitudinal wave, the medium vibrates parallel to the direction of the wave.

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Answer:

d the medium vibrates parallel to the direction of the wave.

Explanation:

The time taken by the runner to do the work is 1.42 seconds.

Given the data in the question;

Power can be simply referred to as the quantity of energy transferred per unit time.

It is expressed as;

[tex]P = \frac{W}{t}[/tex]

Where W is work done and t is time elapsed.

To determine the time it took the runner to do the work, we substitute our given values into the expression above.

[tex]P = \frac{W}{t} \\\\t = \frac{W}{P} \\\\t = \frac{457J}{321W} \\\\t = \frac{457 kgm^2/s^2}{321 kgm^2/s^3}\\\\t = 1.42s[/tex]

Therefore, the time taken by the runner to do the work is 1.42 seconds.

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Answer:

2 kg

Explanation:

K.E. = 1/2 m v^2

81   = 1/2  m (9^2)

1 = 1/2 m

m = 2 kg

The acceleration of the runner in the given time is 2.06m/s².

Given the data in the question;

Since the runner begins from rest,

Acceleration of the runner; [tex]a = \ ?[/tex]

Velocity is the speed at which an object moves in a particular direction.

Acceleration is simply the rate of change of the velocity of a particle or object with respect to time. Now, we can see the relationship from the First Equation of Motion

[tex]v = u + at[/tex]

Where v is final velocity, u is initial velocity, a is acceleration and t is time elapsed.

To determine the acceleration of the runner, we substitute our given values into the equation above.

[tex]v = u + at\\\\13.4m/s = 0 + (a * 6.5s)\\\\13.4m/s = a * 6.5s\\\\a = \frac{13.4m/s}{6.5s}\\ \\a = 2.06m/s^2[/tex]

Therefore, the acceleration of the runner in the given time is 2.06m/s².

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Answer:

B. 240Ω

Explanation:

The formula between voltage, current and resistance is:

voltage = current × resistance

So resistance = voltage ÷ current

Therefore resistance = 120 ÷ 0.5

Resistance = 240Ω

Answer:

An asteroid is a minor planet of the inner Solar System. Historically, these terms have been applied to any astronomical object orbiting the Sun.

Answer:

86.73 kg

Explanation:

Remember that F=mg

Let's plugin our numbers

850N=m9.8m/s^2

850N=9.8m/s^2m

86.73=m

Answer:

yes

true

Explanation:

because earth is rotation

If the distance between the two charges is doubled, the attraction or repulsion becomes weaker.

Explanation:

Answer:

a particular level of electical potential from a power source

It is very important for your measurements that the track is level because unlevel track change the acceleration of an object.

A non-level track leads to bring change in the acceleration of an object which leads to different value of experiment.

So we can conclude that it is important for your measurements that the track is level because unlevel track change the acceleration of an object.

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The track must be level for your measurements because an unlevel track changes the acceleration of an object.

It is defined as the numerical quantity that gives an idea about object length, width, and many more. It can be used to compare two objects.

The non-level track causes changes in an object's acceleration, resulting in various experiment values.

As a result, we can deduce that now the levelness of the track is critical for your measurements, as an uneven track changes an entity's acceleration.

Thus, the track must be level for your measurements because an unlevel track changes the acceleration of an object.

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Objects with the same charge repel each other, and objects with opposite charges attract each other

According to Coulomb, the electric force for charges at rest has the following properties: Like charges repel each other; unlike charges attract. Thus, two negative charges repel one another, while a positive charge attracts a negative charge. The attraction or repulsion acts along the line between the two charges.

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Answer:

both

Explanation:

gravity is the same for both

A ball rolls down an inclined plane, starting from rest. if the total time it takes to reach the end of the inclined plane is t, how much time has elapsed when it is halfway down the incline 0.5t

An inclined plane is a straightforward device with a sloping surface that is used to lift heavy objects. When friction is taken into account, the force needed to move an object up an incline is less than the weight being raised. The needed force is closer to the real weight the higher the slope or incline.

The inclined plane is the most basic of all simple machines because nothing needs to move for it to function. In order to save effort, you have to move objects farther when using an inclined plane. A variety of techniques can be used to create an inclined plane. It can be as simple as a log leaning against a tree in the woods or a piece of wood placed on the edge of a stair.

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The answers to your questions are as listed below

A) The total momentum of the system is :  < - 167, 133, 87 >   kg m/s

B) Velocity of the center of mass of this system : < - 10.44 , 8.31, 5.44 > m/s

C) Total kinetic energy of the system : 5159.5 J  

D) Translational kinetic energy of the system :  1660.84 J

E) kinetic energy relative to the center of mass : 3498.66 J

Given data :

m₁ = 4 kg ,   V₁ = < 10, -5, 15 > m/s

m₂ = 9 kg,   V₂ = < -15, 5, -3 > m/s

m₃ = 3 kg    V₃ = < -24, 36, 18 > m/s.

Total momentum = Σ mv

= < 4*10 + 9*(-15) + 3*(-24), 4*(-5) + 9*5 + 3*36, 4*15 + 9 (-3) + 3*18 >

= < - 167, 133, 87 >   kg m/s

Velocity = < - 167 / 16 , 133/ 16, 87/ 16 >

              =  < - 10.44 , 8.31, 5.44 > m/s

Total Kinetic energy = 1/2 m₁v₁² + 1/2 m₂v₂²  + 1/2 m₃v₃²  --- ( 1 )

where : v² = v₁² + v₂² + v₃²

therefore

Total kinetic energy = 700 + 1165.5 + 3294

                                  = 5159.5 J  

Translational kinetic energy ( Kcm ) = 1/2 ( m₁ + m₂ + m₃ ) * Velocity²

                                                           = 1/2 ( 16 ) * (  - 10.44² + 8.31² + 5.44² )

Hence translational kinetic energy = 1660.84 J

E) The Kinetic energy of the system relative to the center of mass

Krel = Ktotal - Kcm

       = 5159.5 - 1660.84

       = 3498.66 J

Hence we can conclude that the answers to your questions are as listed above.

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first we need omega

Hence

[tex]\\ \rm\rightarrowtail \omega=\dfrac{2\pi}{T}=2\pi[/tex]

Now

Total energy:-

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}m\omega ^2A^2[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(1)(2\pi)^2(1)^2[/tex]

[tex]\\ \rm\rightarrowtail \dfrac{1}{2}(4\pi ^2[/tex]

[tex]\\ \rm\rightarrowtail 2\pi ^2[/tex]

[tex]\\ \rm\rightarrowtail 2(3.14)^2[/tex]

[tex]\\ \rm\rightarrowtail 19.72J[/tex]