a leaky faucet drips 5 teaspoons of water every 3 hours how long will it take the leaky faucet to drip 75 teaspoons of water

Answers

Answer 1

∵ 5 teaspoons of water dropped every 3 hours

∵ We need to find the time taken for 75 teaspoons

→ By using the ratio method

→ Time: teaspoons

→ 3 : 5

→ h : 75

→ By using cross multiplication

∵ 5 x h = 3 x 75

∴ 5h = 225

→ Divide both sides by 5 to find h

h = 45

It will take 45 hours


Related Questions

Give the equation of the line parallel to a line through (-3, 4) and (-5, -6) that passes through the origin. y = 5x y = 5x + 1 y=-1/5x + 1 y = -1/5x y

Answers

To solve for the equation of the line parallel :

[tex]\begin{gathered} (-3,4)\Longrightarrow(x_1,y_1) \\ (-5,-6)\Longrightarrow(x_2,\text{y}_2) \end{gathered}[/tex]

For parallel line equation:

Slope-intercept form: y=mx+b, where m is the slope and b is the y-intercept

First let's find the slope of the line.

To find the slope using two points, divide the difference of the y-coordinates by the difference of the x-coordinates.

[tex]\begin{gathered} \text{slope =}\frac{y_2-y_1}{x_2-x_1} \\ \text{slope}=\frac{-6-4}{-5--3} \\ \text{slope=}\frac{-10}{-5+3}=\frac{-10}{-2} \\ \text{slope =5} \end{gathered}[/tex]

Slope= 5

[tex]\begin{gathered} y=mx+c \\ y=5x+c \\ \text{where c = y-intercept} \end{gathered}[/tex]

The y-intercept is (0, b). The equation passes through the origin, so the y-intercept is 0.

[tex]\begin{gathered} y=5x+0 \\ y=5x \end{gathered}[/tex]

Hence the

Question 5 of 10 Solve the proportion below. 23 A 6 B. 8 C. 9 D.

Answers

[tex]\frac{x}{12.6}=\frac{45}{63}[/tex]

solve for x

[tex]\begin{gathered} 12.6\times\frac{x}{12.6}=\frac{5}{7}\times12.6 \\ x=\frac{63}{7}=9 \end{gathered}[/tex]

answer: C. 9

Translate into a number sentence7. Four less than seven is greater than zero

Answers

In order to translate the words into a number sentence, first let's translate each word or expression separately:

Four less than seven: "7 - 4"

Is greater than: ">"

Zero: "0"

Therefore the number sentence will be:

[tex]7-4>0[/tex]

See attached for the problem

Answers

The areas and volumes are given as follows:

a) Area of the four sides to be painted: 2448 m².

b) Area to be covered with shingles: 1140 m².

c) Volume of concrete needed to pour a floor 16 cm deep: 174.72 m³.

d) Total surface area: 5878.4 m².

Area -> Four sides painted

The sides painted are divided as follows:

Two rectangles of dimensions 26 m and 18 m.Two rectangles of dimensions 42 m and 18 m.

Hence the total area to be painted is found as follows:

Total area = 2 x 26 x 18 + 2 x 42 x 18 = 2448 m².

(Area rectangle = base x height)

Area to be covered with shingles

This part of the problem seems incomplete, however the answer is correct.

Volume of concrete

The volume is given by:

Volume = base area x height.

Hence:

The base area is a rectangle of dimensions 26 m and 42 m.The height is of 16 cm = 0.16 m.

Hence the volume is given by:

V = 26 x 42 x 0.16 = 174.72 m³.

Surface area

The base is a rectangular prism of dimensions 26 m, 42 m and 18m, hence:

Surface area base = 2 x (26 x 42 + 26 x 18 + 42 x 18) = 4632 m².

The top is composed by:

Two rectangles of dimensions 13.6 m and 42 m.Two triangles of base 26 m and height 4 m.

Hence:

Surface area top = 2 x 13.6 x 42 + 2 x 0.5 x 26 x 4 = 1246.4 m².

Then the total surface area is:

Total surface area = 4632 + 1246.4 = 5878.4 m².

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I need help solving
This problem

Answers

Weight required to destroy a bridge cable (in ponds) The type of variable is Nominal Categorical

A frequently used category variable is gender. Categorical variables can either be ordinal or numeric.

The closing price (in dollars) of the stock is a quantitative variable, and since the price involves an absolute zero, the scale of measurement is a ratio scale

Pounds is what type of variable?

Weight is a prime example of a ratio variable (e.g., in pounds). With certainty, we may state that 20 pounds weigh twice as much as 10 pounds. Ratio variables also have an important zero-point (e.g., exactly 0 pounds means the object has no weight)..

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Suppose that the future price p(t) of a certain item is given by the following exponential function. In this function, p(t) is measured in dollars and t is the number of years from today. p(t) = 3000 * (1.019) ^ t

Answers

Explanation

The growth or decay of an original quantity C that increases or decreases in a p% per year after t years is given by the following equation:

[tex]p(t)=C\cdot(1\pm\frac{p}{100})^t[/tex]

If the quantity increases (i.e. it growths) we use the + symbol inside the parenthesis. If the quantity decreases we use the - symbol. This implies that for a growth the term that is raised to t is greater than 1 and for a decay that term is smaller than 1.

Now let's compare that generic equation with the function given by the question:

[tex]3000\cdot(1.019)^t=C\cdot(1\pm\frac{p}{100})^t[/tex]

One of the first things you can notice is that C=3000 which means that the initial price was $3000. Just to be sure that this is correct we can evaluate p(t) at t=0:

[tex]p(0)=3000\cdot(1.019)^0=3000[/tex]

So the initial price was $3000.

Now let's compare the terms inside parenthesis that are raised to t:

[tex]1.019=1\pm\frac{p}{100}[/tex]

As I stated before, if the term raised to t is greater than 1 then we are talking about a growth. 1.019 is greater than 1 so this function represents a growth. What's more, in the right side of the equation we must use the + symbol. This way we have an equation for the yearly percentage of change of the price:

[tex]1.019=1+\frac{p}{100}[/tex]

We can substract 1 from both sides of this equation:

[tex]\begin{gathered} 1.019-1=1+\frac{p}{100}-1 \\ 0.019=\frac{p}{100} \end{gathered}[/tex]

And we multiply both sides by 100:

[tex]\begin{gathered} 100\cdot0.019=\frac{p}{100}\cdot100 \\ 1.9=p \end{gathered}[/tex]

So each year the price increases in a 1.9%.

Answer

Then the answers in order are:

$3000

growth

1.9%

Add.

47+13

Enter your answer as a fraction in simplest form by filling in the boxes.

Answers

Answer: 47+13 =60

60 as a fraction should be 3/5 in simplest form.

Step-by-step explanation:

True or False? Every rectangle is a parallelogram. Every rhombus is a parallelogram. Every quadrilateral is a square. Every rectangle with four congruent sides is a square. X S True O False True O False O True False O True O False ?

Answers

Given: Different statement relating different quadrilateral

To Determine: If true or false statement

Solution

The image below summarizes the properties of a quadrilateral

From the above, we can conclude that

If the m< P is 65 degrees, then what is the measure of Arc XY

Answers

Answer:

[tex]\text{ArcXY}=115\text{ degrees}[/tex]

Step by step explanation:

We can solve this situation by the theorem of the angle formed outside of a circle by intersection:

*For two tangents:

[tex]m

Then, if m

[tex]\begin{gathered} 65=\frac{1}{2}((360-mXY)-mXY) \\ 65=\frac{1}{2}(360-\text{mXY-mXY)} \\ 65=\frac{1}{2}(360-2\text{mXY)} \\ 65=180-\text{mXY} \\ \text{mXY}=180-65 \\ \text{mXY}=115 \end{gathered}[/tex]

7(x+2)=

4(x+4)=

9(x+6)=

Answers

Answer:

Step-by-step explanation:

7(x+2) = 7x+14

7(x+2)=7x+7 times 2

4(x+4)= 4x+16

4 times x = 4x

4 times 4 = 16

= 4x+16

9(x+6) = 9x+54

9 times x = 9x

9 times 6 = 54

= 9x+54

What is the low end value, high end value, and does it have an outlier

Answers

Solution;

Given the results:

From the above data:

A) The low-end value is

[tex]0[/tex]

B) The high end value is

[tex]95[/tex]

C) Does this data set have outlier?

[tex]Yes[/tex]

D) Outlier:

[tex]95[/tex]

Fifth grade > Y.5 Compare and convert Which is more, 1/2 of a pound or 6 ounces? of a pound 2. 6 ounces neither; they are equal Submit

Answers

We should know that :

1 pound = 16 ounces

The question is :

Which is more, 1/2 of a pound or 6 ounces?

so,

1/2 of a pound = 1/2 x 16 = 8 ounces

So,

8 ounces > 6 ounces

so, the answer is option 1

The more is 1/2 of a pound

Find the value of x assume the triangles are the same

Answers

[tex]x=44[/tex]

1) In this problem, we need to find the constant of proportionality assuming these triangles are similar. So let's divide each corresponding leg:

[tex]\frac{22}{18}=\frac{33}{27}\Rightarrow\:k=\frac{11}{9}[/tex]

2) So, based on that constant of proportionality (k) we can find the missing leg.

[tex]\begin{gathered} x\div\frac{11}{9}=36 \\ \\ x\cdot\frac{9}{11}=36 \\ \\ 11\times\frac{9}{11}x=36\times11 \\ \\ 9x=396 \\ \\ \frac{9x}{9}=\frac{396}{9} \\ \\ x=44 \end{gathered}[/tex]

Note that since the triangle on the top is larger than the one on the bottom, we can tell that x must be larger than 36.

Lindsay gets paid $15 per hour at her job. If we let s be her salary and h be the number of hours she has worked, write an equation that represents the direct variation.

Answers

A linear function or a direct variation function is represented by:

[tex]y=kx[/tex]

where k is the constant rate of chante, in this case $15 per hour.

s=y= salary of Lindsay

h=x= hours she has worked

Then, the equation that represents the situation would be:

[tex]s=15h[/tex]

what is the nessecary information you need to know about a cube?

Answers

Answer: the width, length and height

Step-by-step explanation: multiply the width length and height of a cube and you get the area

14#An ecologist randomly samples 12 plants of a specific species and measures their heights. He finds that this sample has a mean of 14 cm and a standard deviation of 4 cm. If we assume that the height measurements are normally distributed, find a 95% confidence interval for the mean height of all plants of this species. Give the lower limit and upper limit of the 95% confidence interval. Carry your intermediate computations to at least three decimal places. Round your answers to one decimal place. (If necessary, consult a list of formulas.)Lower limit:Upper limit:

Answers

Answer:

Lower limit: 11.7 cm

Upper limit: 16.263

Explanation:

The formula to find the lower and upper limits of the confidence interval (given the data is normally distributed) is :

[tex]CI=\mu\pm Z^*\frac{\sigma}{\sqrt{n}}[/tex]

Where:

• μ = sample mean

,

• σ = sample standard deviation

,

• Z* = critical value of the z-distribution

,

• n = is the sample size

In this case:

• μ = 14cm

• σ = 4cm

,

• n = 12

The critical value of the z-distribution for a confidence interval of 95% is Z* = 1.96

Now, we can use the formula above to find the upper and lower limit:

[tex]CI=14\pm1.96\cdot\frac{4}{\sqrt{12}}=14\pm\frac{98\sqrt{3}}{75}=\frac{1050\pm98\sqrt{3}}{75}[/tex]

Thus:

[tex]Lower\text{ }limit=\frac{1050-98\sqrt{3}}{75}\approx11.736cm[/tex][tex]Upper\text{ }limit=\frac{1050-98\sqrt{3}}{75}\approx16.263cm[/tex]

Rounded to one decimal:

Lower limit: 11.7cm

Upper limit: 16.3cm

write an expression such that if you apply the distributive property to your expression it would give the same result presented. 8x + 12

Answers

Solution:

Let's find a expression such that if you apply the distributive property to your expression it would give the same result presented:

• 8x + 12 = 2 (4x + 6)

,

• 8x + 12 = 4 (2x + 3)

,

• 8x + 12 = 8 (x + 1.5)

Any of these expressions could be the solution to the question.

A whole pizza is cut into twelfths. If Dexter eats 1/2 of the pizza and Landry eats 1/3 of the pizza, then 3 what fraction of the pizza remains?

Answers

Explanation

Step 1

Let

A whole pizza = 1 pizza

Dexter eats 1/2

Landry eats 1/3

x= fraction of the pizza remains

Step 2

the r

In Abc,AB=5 feet and BC=3 feet.Which inequality represents all possible values for the length of AC,in feet?

Answers

The smallest value of length AC would be 5 ft - 3 ft = 2 ft while the largest length would be 5 ft + 3 ft = 8ft. The answer will be

2 < Ac < 8

What is the distance between (-5, 5) and (1, -2)

Answers

Answer:

[tex]\displaystyle d=\sqrt{85}\text{, or about 9.22 units}[/tex]

Step-by-step explanation:

          We will use the distance formula to solve.

[tex]\displaystyle d=\sqrt{(x_{2}-x_{1})^2 +(y_{2}-y_{1})^2}[/tex]

[tex]\displaystyle d=\sqrt{(1--5)^2 +(-2-5)^2}[/tex]

[tex]\displaystyle d=\sqrt{(6)^2 +(-7)^2}[/tex]

[tex]\displaystyle d=\sqrt{36+49}[/tex]

[tex]\displaystyle d=\sqrt{85}\text{, or about 9.22 units}[/tex]

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DATE IN OUT IN OUT HOURS TEMPORARY EMPLOYEE TIME CARD NAME: Eugene Mueller 8/8 7:00 4:10 8/9 6:50 11:00 DEPT Sales 8/10 8/11 12:00 4:35 Note: No overtime rate. 10:55 3:25 EMPLOYEE SIGNATURE RATE per hour: $8.50 TOTAL HOURS:

Answers

[tex]\begin{gathered} we\text{ have to count how many hours Eugene worked during his morning's shifts and during afternoon shifts} \\ \text{morning shifts:} \\ 4h\text{ and 15 minutes} \\ 4h\text{ and 10 minutes} \\ 4h\text{ and 36 min} \\ 4h \\ 3h\text{ and 50 min} \\ \text{So we have that during morning shifts he worked} \\ 4h+4h+4h+4h+3h\text{ =21h} \\ 15\min +10\min +36\min +50\min =111\min =\text{ 1h and 51 min } \\ so\text{ in the morning shifts 22h and 51 min } \\ \text{afternoon shifts } \\ 4h \\ 4h\text{ and 10 min} \\ 3h\text{ 24 min} \\ 4h\text{ and 35 min} \\ 3h\text{ and 44 min} \\ so\text{ in total } \\ 4h+4h+3h+4h+3h=18h \\ 10\min \text{ + 24min+35min+44min=113min=1h +53 min} \\ so\text{ in the afternoon shifts he worked 19h and 53 min } \\ so\text{ in total} \\ 22h+19h=41h \\ 51\min \text{ + 53 min =104 min =1h 44min} \\ he\text{ worked 42h and 44 min and that is 42.75 h} \end{gathered}[/tex]

60 cars to 24 cars The percent of change is

Answers

We can calculate the percent of change by means of the following formula:

[tex]change=\frac{x2-x1}{x1}\times100[/tex]

Where x2 is the new value and x1 is the original value.

In this case, we go from 60 to 24, then the original value (x1) was 60 and the new value (x2) is 24, by replacing these values into the above equation, we get:

[tex]change=\frac{24-60}{60}\times100=-60[/tex]

Then, the percent of change equals -60%

If a red and a blue fair six sided die are rolled what is the probability the result is 8 or divisible by 3?

Answers

SOLUTION:

Step 1:

In this question, we are given that;

If a red and a blue fair six-sided die are rolled.

What is the probability the result is 8 or divisible by 3?

Step 2:

The table for the two dice rolled together is as shown below:

Green 1 2 3 4 5 6

Red

1 2 3 4 5 6 7

2 3 4 5 6 7 8

3 4 5 6 7 8 9

4 5 6 7 8 9 10

5 6 7 8 9 10 11

6 7 8 9 10 11 12

Step 3:

The probability that the result is 8 =

[tex]\begin{gathered} =\text{ }\frac{\nu mber\text{ of 8}}{\text{Total number }} \\ =\text{ }\frac{5}{36} \end{gathered}[/tex]

Next,

The probability that the result is divisible by 3

=

[tex]\frac{12}{36}[/tex]

Finally, the probability that the result is 8 or divisible by 3, we have that:

[tex]\frac{5}{36}+\frac{12}{36}\text{ =}\frac{17}{36}[/tex]



Solve the inequality -30 10-40x and write the solution using:
Inequality Notation:

Answers

Answer:

Step-by-step explanation:

Write an equation of the line with the given slope and y-intercept.
Slope
1
6
, y−intercept (0, −2)

Answers

The equation of line is [tex]6y=6x$-$12[/tex].

The given slope is [tex]\frac{1}{6}[/tex].

The [tex]y $-$[/tex]intercept is [tex](0, $-$2)[/tex].

We have to write the equation of line using the given slope and [tex]y $-$[/tex]intercept.

The equation of line with the slope m and [tex]y $-$[/tex]intercept of [tex](0,a)[/tex] is [tex]y=mx+a[/tex].

From the question,

The value of  [tex]m=\frac{1}{6}[/tex]

The value of [tex]a= $-$2[/tex]

Now putting the value of [tex]m[/tex] and [tex]a[/tex] in the equation of line.

[tex]y=\frac{1}{6}x+( $-$2)\\y=\frac{1}{6}x$-$2[/tex]

Multiply by [tex]6[/tex] on both side

[tex]y\times6=6\times(\frac{1}{6}x$-$2)\\6y=6\times\frac{1}{6}x$-$6\times2\\6y=6x$-$12[/tex]

The equation of line is [tex]6y=6x$-$12[/tex].

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Vincent turned his head 30° to the side. Which of the following shows the angle that he turned his head?

Answers

Given data:

Vincent turned his head 30° to the side.

The figure in the option b is the angle that he turned his head.

0 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 100 1 2 3 4 5 6 7 8 9 10401234 5 6 7 8 9 10OB.C.OD. +Reset Selection

Answers

Okay, here we have this:

Considering the provided inequation, we are going to identify how can be represented on a number line, so we obtain the following:

So the first thing we will do is factor to find the solution intervals, we have:

[tex]\begin{gathered} 3x^2-27x\leq0 \\ x(x-9)\leq0 \\ 0\leq x\leq9 \end{gathered}[/tex]

According to this, we finally obtain that the solution interval is option D, because it satisfies the found interval and its endpoints are closed.

Look at this graph: 100 90 80 60 50 20 10 10 20 30 50 60 70 80 90 100 What is the slope? Simplify your answer and write it as a proper fraction, improper fraction or integer. Submit Not feeling yet These con heo

Answers

To find the slope of the line we have to use this equation:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

Now we have to replace two coordiantes in the line, so I was able to see the coordinates: (0,40) and (20,50), sothe equation become:

[tex]m=\frac{50-40}{20-0}[/tex]

and we simplify so:

[tex]m=\frac{10}{20}=\frac{1}{2}[/tex]

So the slope is 1/2

7.2. I have a question about advanced trig equations that I really need help with picture included

Answers

[tex]\theta=\frac{\pi}{6},\: \theta=\frac{11\pi}{6}[/tex]

1) Let's start out isolating the cosine by dividing both sides by 2

[tex]\begin{gathered} 2\cos \mleft(\theta\mright)=\sqrt{3} \\ \frac{2\cos\left(θ\right)}{2}=\frac{\sqrt{3}}{2} \\ \cos \mleft(\theta\mright)=\frac{\sqrt{3}}{2} \\ \end{gathered}[/tex]

2) From that we can find two general solutions in which the cosine of theta yields the square root of 3 over two:

[tex]\begin{gathered} \cos (30^{\circ})or\cos (\frac{\pi}{6})\text{ and }cos(330^{\circ}or\frac{11}{6}\pi)=\frac{\sqrt[]{3}}{2} \\ \theta=\frac{\pi}{6}+2\pi n,\: \theta=\frac{11\pi}{6}+2\pi n \end{gathered}[/tex]

But not that there is a restraint, so we can write out the solution as:

[tex]\theta=\frac{\pi}{6},\: \theta=\frac{11\pi}{6}[/tex]

Write the nth rule for the following geometric sequence. Then find the fifth term. (you are given the first term and the common ratio)1-

Answers

The formula for determining the nth term of a geometric sequence is expressed as

Tn = ar^(n - 1)

Where

a represents the first term

r represents the common ratio.

n represents the number of terms

From the information given,

a = 2, r = 3

Thus, the rule for the nth term of the geometric sequence is

Tn = 2 x 3^(n - 1)

To determine the fifth term, we would substitute n = 5 into the equation. It becomes

T5 = 2 x 3^(5 - 1)

T5 = 2 x 3^4

T5 = 162

The fifth term is 162

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