Answer:
The water hits the wall at a height of 5.38 m
Explanation:
Projectile Motion
It's the type of motion that experiences an object projected near the Earth's surface and moves along a curved path exclusively under the action of gravity.
The object describes a parabolic path given by the equation:
[tex]{\displaystyle y=\tan(\theta )\cdot x-{\frac {g}{2v_{0}^{2}\cos ^{2}\theta }}\cdot x^{2}}[/tex]
Where:
y = vertical displacement
x = horizontal displacement
θ = Elevation angle
vo = Initial speed
The hose projects a water current upwards at an angle of θ=40° at a speed vo=20 m/s.
The height at which the water hits a wall located at x=8 m from the hose is:
[tex]{\displaystyle y=\tan40^\circ\cdot 8-{\frac {9.8}{2*20^{2}\cos ^{2}40^\circ }}\cdot 8^{2}}[/tex]
Calculating:
y = 5.38 m
The water hits the wall at a height of 5.38 m
will you help me please
Answer: True
Explanation: It's true because the definition of a Command economy states that it's an economy in which production, investment, prices, and incomes are determined CENTERALLY by a GOVERNMENT.Mr. D's dog Gromit jumped out of a second story window (through the screen) and fell to the ground below. The window is 15 feet high, the acceleration of gravity is 9 m/s', and there are 3.28 feet in each meter. What was the final velocity of this crazed dog? (True story, don't worry he's fine and now he knows about gravity)
Answer:
Vf = 9.46 m/s
Explanation:
In order to find the final velocity of the dog we can use third equation of motion:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height of window = (15 ft)(1 m/3.28 ft) = 4.57 m
Vf = Final Velocity of Dog = ?
Vi = Initial Velocity of Dog = 0 m/s
Therefore,
(2)(9.8 m/s²)(4.57 m) = Vf² - (0 m/s)²
Vf = √(89.572 m²/s²)
Vf = 9.46 m/s
A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it
Answer:
F = -8820 N
Explanation:
Given that,
The weight of a car, W = 19600 N
Initial speed of the car, u = 30 m/s
It is brought to rest, final velocity, v = 0
Distance, d = 100 m
We need to find the average friction force acting on it.
Firstly we find the acceleration of the car using third equation of motion. Let it is a.
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]
Average frictional force,
F = ma
m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]
F = 1960 kg × -4.5 m/s²
= -8820 N
So, the average friction force acting on it is 8820 N.
Do you think the inner planets should be explored or should the money be spent on other things? Justify your opinion.
Answer:
yes i think that inner planets should be explored because if we ever find new life or are able to live there then i think its worth takeing a risk.
Explanation:
help plz The sum of all chemical reactions that take place within an organism is known as ______________. *
Answer:
Metabolism
Explanation:
metabolism is the sum of all chemical reactions that take place within an organism
Answer:
Metabolism
Explanation:
The law of __________________________ says that people think of similar objects as belonging together.
Answer:
Explanation:is the law means that the police are the law
what is the function of brushes in D.C motor
Answer:
to transfer the voltage
Explanation:
The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.
Why do you think it is colder during the winter than the summer?
Answer:
As the earth travels around the sun during the year it maintains this tilt. Because of this tilt, in the summer we (north of the equator) are slanted more directly towards the sun so it's hotter. In the winter, we're slanted away so the sun's rays are less direct, making it colder.
A woman can lift barrels a vertical distance of 1 meter or can roll them up a 2-meter long ramp to the same elevation. If she uses the ramp, the applied force required is
Answer:
answer is 1/2 as much force required
You are standing on a moving bus, facing forward, and you suddenly fall forward. You can imply form this that the bus’s
the fall of a body on the earth's surface cannot be a complete free fall why ?
Explanation:
because the boy has larger surface area due to which he offers the larger air resistance which decreases the acceleration so, he will fall towards the earth's surface approximately with constant velocity.
pls help me with this
Answer:
A screw
Explanation:
A ball has a mass of 0.1 kg and an initial velocity of 20 m/s. The ball is given an acceleration of 30 m/s2 for 5 s. What is the net force on the ball during acceleration?
Answer:
acceleration = v-u /t
30- 20/5
= 10/5 = 2m/sec²
Force = mass * acceleration
Force = 0.1 * 2
Force = 0.2 Newton
Answer:
I hope the above pic will help you
I will always help you understanding your assingments
have a great day #Captainpower:)
a small balloon containing baking soda has a mass of 4 grams. A student adds 10 ml. of vinegar
to a 100 gram glass bottle. The student stretches the opening of the balloon over the mouth of
the bottle, mixing the baking soda and vinegar inside the bottle. Once the balloon is inflated, the
student finds the mass of the balloon, bottle, and their contents to be 116 grams. What was the
mass of the vinegar originally in the bottle
F.10g G.12g J.16g
Answer:
10 grams
Explanation:
I took a test with this question earlier.
what is the uses of space weather data?
Answer:
Space Weather Data
They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.
Explanation:
Calculate the displacement of the following components:
1 units North
2 units South
2 units North
2 units North
3 unit South
Answer:
zero displacement
its returnin to the starting point.
5 north 5 south
A steel rod has a diameter of 3.75cm.Express it's diameter in millimeters and meter
Answer:
3.75cm into millimetres
= 3.75 * 10
37.5 millimetres
3.75 cm into metres
3.75/100
= 0.0375m
What does this same experiment( the picture) tell you about light waves? Explain.
1. A race starts out at rest and accelerates to 30m/s over a period of 10s. What is the acceleration of the car?
O 3.0 m/s
O 3.0 m.s2
O 2.0 m/s2
O 5.0 m/s2
Answer:3.0m/s
Explanation:
A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.
Answer:
Explanation:
It is still using F = m*a -- just in a disguised form.
Givens
F = 900 N
vf = 360 m/s
vi = 0
t = 40 second
Formulas
a = (vf - vi)//t
F = m * a
Solution
a = (360 - 0)/ 40
a = 9
F = m * a
900 = m * 9
m = 900/9
m - 100 kg. Doesn't seem high enough.
Answer:
a= V- u/t
a= 360 - 0 /40 = 9 m/sec2
F = MA
900 = M * 9
M = 900/9
M= 100 kg
a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3
Answer:2.47
Explanation:
So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!
a 5.00 kg plane is speeding up on the ground with an applied force of 706 N. If the net force is 450 N, what would be the force due to air resistance
Answer:
The force due to air resistance is 256 N.
Explanation:
Given;
mass of the plane, m = 5 kg
applied force on the plane, Fa = 706 N
the net force on the plane, ∑F= 450 N
Let the force due to air resistance = Fr
The net force on the plane is given as;
Net force = applied force - force due to air resistance
∑F = Fa - Fr
Fr = Fa - ∑F
Fr = 706 - 450
Fr = 256 N.
Therefore, the force due to air resistance is 256 N.
at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C
Answer:
The volume of the gas becomes three times the initial volume.
Explanation:
Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.
So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.
The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.
As the pressure is constant, so [tex]P_1=P_2[/tex].
Let V_1 and V_2 be the initial and final volume respectively.
Assuming that the given gas is ideal gas.
So, applying the ideal gas equation
PV=nRT
where n is the number of moles of the gas and R is the universal gas constant.
For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]
and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]
Dividing the equation (i) by (ii), we have
[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]
As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then
[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]
As the pressure is not changing, so [tex]P_1=P_2[/tex], then
[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]
[tex]V_2=3V_1[/tex]
So, the volume of the gas becomes three times the initial volume.
PLZ HELP MEEEEEEE,;-;
Answer:
thxs for the points
Explanation:
because just started
If you launch an object in space, it
will continue to move forward
until an external force stops it.
This is a characteristic of which
law?
Answer:
I believe this represents Newton's first law of motion. Any object in motion will continue to move until a force stops it, be it friction or a physical object.
Voltage has been described as similar to the water in the water pipes in your home. What other analogy can you think of that is similar to voltage?
1. A book is at rest on a tabletop. Diagram the forces acting on the book.
The free-body diagram of the forces acting on a book resting on a table is shown in the figure.
When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.
So, the forces acting on a book resting on a tabletop are:
1. Weight of the book, W(downward)
2. Normal force (N) perpendicular to the surface in contact.
Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.
To know more about forces, click here:
https://brainly.com/question/13191643
#SPJ6
A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable
Answer:
500N
Explanation:
50kgx10N/kg
= 500N
A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface
Answer:
[tex]x =\frac{-R}{2}[/tex]
Explanation:
From the question we are told that mass
Thin layer radius [tex]= 2R[/tex]
Generally the expression for ths solution is given as
Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2
the center of mass will not move at initial state
Considering the center of mass of both bodies
[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]
[tex]x =\frac{-R}{2}[/tex]
Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]
The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
Given-
Radius of the ball is [tex]R[/tex].
the mass of the ball is [tex]m[/tex].
The mass of the thin shell is [tex]m[/tex].
The radius of the thin shell is [tex]2 R[/tex].
For the two bodies with mass [tex]m[/tex], the center of mass can be given as,
[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]
In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,
[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]
[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]
[tex]x_{cm} =x[/tex]
Distance for center of mass can also be given as,
[tex]x_{cm} =m\times o[/tex]
[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]
[tex]x_{cm} =\dfrac{-R}{2}[/tex]
Comparing both the values of the distance of center of mass we get,
[tex]x =\dfrac{-R}{2}[/tex]
Hence, The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
For more about the center of mass follow the link below,
https://brainly.com/question/8662931
I need help with the questions when it says what is the topic and rest