Answer:
[tex]50\; {\rm m\cdot s^{-1}}[/tex], assuming that the force on the golf ball was constant.
Explanation:
Assume that the force the golf club exerted on the golf ball a constant force of magnitude [tex]F[/tex]. Let [tex]\Delta t[/tex] denote the duration the club was in contact with the golf ball. The impulse of this force would be:
[tex]J = F\, \Delta t[/tex].
Let [tex]\Delta p[/tex] denote the change in the momentum of this golf ball. By the impulse-momentum theorem, this [tex]\Delta p\![/tex] would be equal to the impulse on the golf ball.
[tex]\Delta p = J = F\, \Delta t[/tex].
The momentum [tex]p[/tex] of this golf ball is the scalar product between the mass [tex]m[/tex] of this golf ball and the velocity [tex]v[/tex] of this golf ball. The mass of this golf ball stays the same. Thus, when the momentum of this golf ball changes by [tex]\Delta p[/tex], the velocity of this golf ball would change by [tex](\Delta p) / (m)[/tex].
The change in the velocity of this golf ball would thus be:
[tex]\begin{aligned}\Delta v &= \frac{\Delta p}{m} & \genfrac{}{}{0em}{}{(\text{change in momentum})}{}\\ &= \frac{J}{m} & \genfrac{}{}{0em}{}{(\text{impulse on the golf ball})}{}\\ &= \frac{F\, \Delta t}{m} \\ &= \frac{500\; {\rm N} \times 0.01\; {\rm s}}{0.1\; {\rm kg}} \\ &\approx 50\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].
(Note that [tex]1\; {\rm N} = 1\; {\rm kg \cdot m^{2}\cdot s^{-2}}[/tex].)
what force much be applied to stop a 1400kg car that is initially traveling at 13 m/s over a 5 second time period
Answer:
As per Provided Information
Mass of car m is 1400KgInitial velocity u is 13m/sTime taken to stop t is 5 second .Final velocity v is 0m/swe have been asked to determine the force applied to stop the car. First we will calculate the acceleration of the car.
[tex] \boxed{\bf \: a \: = \dfrac{(v - u)}{t}}[/tex]
Substituting the value and let's solve it
[tex] \longrightarrow\sf \: a \: = \dfrac{0 - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = \cfrac{ - 13}{5} \\ \\ \\ \longrightarrow\sf \: a \: = - 2.6 \: {ms}^{ - 2} [/tex]
Now, let's calculate the force applied to stop the car .
[tex] \pink{\boxed{\bf \: F = ma}}[/tex]
Substituting the value we get
[tex] \longrightarrow \sf \: F = 1400 \times ( - 2.6) \\ \\ \\ \longrightarrow \sf \: F = - 3640 \: N[/tex]
Here , negative sign show that the " Force is acting in opposite direction of the motion"
Therefore,
3640 Newton force is required to stop the car .4. The work output is 500 joules for a machine that is 12.5 percent efficient. The work input is
joules. 0
(1 Point)
A.4000
B.1.000
C.2,000
D.12.500
Answer:
4000 J
Explanation:
x * .125 = 500
x = work input = 500 / .125 = 4000 J
If these cranes make the work being done ten times easier, what is the mechanical advantage?
A. cannot be determined
B. ten
What is the weight of a box with a mass of 150 kg on Earth?
N
Use g= 9.81 m/s2 and do not include units in your answer.
Answer:
W = M g = 150 kg * 9.81 m/s^2 = 1470 N
You were only given 3 significant figures in the question.
The weight of the box is 1471.5 N.
What is weight?In science and engineering, an object's weight is defined as the force of gravity acting on the thing. Weight is sometimes described as a vector quantity in common textbooks, denoting the gravitational force acting on the item.
Given parameters:
Mass of the box, m = 150 kg.
Acceleration due to gravity, g = 9.8 m/s².
Hence, weight of the box is, W = mg = 150 kg × 9.81 m/s² =1471.5 N.
SO, weight of the box with a mass of 150 kg on Earth is 1471.5 N.
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What resultant force is required to accelerate a 1600kg automobile uniformly from 8m/s to 30m/s in 10s?
Answer:
3520
Explanation: Force = Mass x Acceleration [∴ or F = ma]. Given values. mass, m = 1600 kg; initial velocity, u = 8 m/s; final velocity, v = 30 m/s; time taken, t = 10 s.
Help please I am stuck
Answer:
ADCACExplanation:
Explain Resistor in parallel and series.
[tex]\sf\huge\underline\blue{Resistor:-}[/tex]
[tex]\rightarrow[/tex]A resistor is a passive two-terminal electrical component that implements electrical resistance as a circuit element.
[tex]\rightarrow[/tex]Resistors reduce the current flow and lower voltage levels within circuits.
[tex]\sf\large\underline\purple{Resistors \:in\: Series:-}[/tex]
[tex]\rightarrow[/tex]A circuit is said to be connected in series when the same amount of current flows through the resistors. In such circuits, the voltage across each resistor is different.
[tex]\rightarrow[/tex]In a series connection, if any resistor is broken or a fault occurs, then the entire circuit is turned off. The construction of a series circuit is simpler compared to a parallel circuit.
[tex]\rightarrow[/tex]For the above circuit(attached image-1), the total resistance is given as:
[tex]\sf{R_{total}\: = \:R1 + R2 + ….. + Rn}[/tex]
The total resistance of the system is just the total of individual resistances.
[tex]\sf\large\underline\purple{Resistors \:in\: Parallel:-}[/tex]
[tex]\rightarrow[/tex]A circuit is said to be connected in parallel when the voltage is the same across the resistors. In such circuits, the current is branched out and recombines when branches meet at a common point.
[tex]\rightarrow[/tex]A resistor or any other component can be connected or disconnected easily without affecting other elements in a parallel circuit.
[tex]\rightarrow[/tex]The figure(attached image -2) above shows ‘n’ number of resistors connected in parallel. The following relation gives the total resistance here
[tex]\sf{\frac{1}{R_{total}}\: = \:\frac{1}{R1} + \frac{1}{R2} + ….. + \frac{1}{Rn}}[/tex]
[tex]\rightarrow[/tex]The sum of reciprocals of resistance of an individual resistor is the total reciprocal resistance of the system.
_______________________________
Hope it helps you:)
Answer:
In a series circuit, the output current of the first resistor flows into the input of the second resistor; therefore, the current is the same in each resistor. In a parallel circuit, all of the resistor leads on one side of the resistors are connected together and all the leads on the other side are connected together.
Sally and sam were building simple circuits in science class. they used d-cell batteries as an energy source. what kind of energy is found in batteries? question 1 options: potential light energy potential elastic energy potential chemical energy potential electrical energy
Answer:
option 3 potential chemical energy
The picture shows volcanoes and a trench that form where plates move toward each other.
1. This type of boundary is called_______
2. The area where one plate moves under another is called ______
1. This type of boundary is called convergent
2. The area where one plate moves under another is called the subduction zone.
Hope that helps!
A student makes a voltage divider from a 45-V battery, a 475-k
resistor, and a 235-k resistor. The output is measured across the
smaller resistor. What is the voltage?
Answer:
14.9 v
Explanation:
V = IR
The voltages across the resistors will be proprtional to the values of the resistors
45 * 235 / (235 + 475) =
A girl is travelling on her bike at a speed 2.54 m/s. If the girl and her bike have a kinetic energy of 193 J, what is the combined mass of the girl and her bike? Show all your work.
Answer:
About 59.83 kg
Explanation:
The formula for kinetic energy is [tex]KE = \frac{1}{2}mV^2[/tex], where KE = Kinetic Energy in Joules (J), m = mass in kilograms (kg), and V = Velocity in meters per second (m/s).
In this problem, we are given the Kinetic Energy amount as 193 Joules and the Velocity as 2.54 m/s. Let's plug it into our equation
[tex]193 = \frac{1}{2} * 2.54^2m[/tex]Now, let's solve this equation.
Step 1: Simplify both sides of the equation.
[tex]193 = 0.5 * 2.54 * 2.54 * m[/tex] [tex]193=3.2258m[/tex]Step 2: Divide both sides by 3.2258.
[tex]193/3.2258 = 3.2258m/3.2258[/tex] m ≈ 59.830 kilogramsRoughly how long does it take for the sun's light to reach Earth - 8 minutes, 8 hours or 8 days?
Answer:
8 minutes
Explanation:
Light travels at a speed of 299,792
kilometers per second; 186,287 miles
per second. It takes 499.0 second
for light to travel from the Sun to the
Earth, a distance celled 1 Astronomical
Unit.
four pieces of graph paper a ruler two pencils a helper Follow these steps: Choose which person will be the sender (satellite) and which will be the receiver (television). Each person then draws a 10" by 10" square on a piece of graph paper. Draw a grid within the square, so that each small square of the grid is about 1 inch square. This should give you an area with 100 squares in it. The size of the small squares will depend somewhat on the graph paper used - make sure you use some of the lines on the graph paper as guidelines. The sender now draws a simple picture within the 10" x 10" square without letting the receiver see what he or she is drawing. The sender should now “read” the picture to the receiver, using a digital code. If a square on the graph paper is blank, the sender says “Zero”; if the square is filled in or has any mark in it at all, the sender says, “One.” Using this code, the sender starts with the top row and reads from left to right, one square at a time. The receiver, upon hearing this code, transfers the information to his own graph paper. The receiver must mark the graph paper by starting with the top row of squares and going from left to right. If the sender says “zero,” no mark is made. If the sender says “one,” the receiver should fill in the square completely! At the end of the first row, the sender should say, “End row 1,” and repeat this at the end of each row. At the end of the last row, compare the two pictures. Check the results to see how accurate the transfer was. Now, get two more pieces of graph paper and draw 10” by 10” squares on them. This time, your grid size should be close to 1/4 inch rather than one inch. You will have many more squares than before! You can use the same drawing or switch people and the new sender can draw another picture. Follow the same procedure. Describe your results. Compare the accuracy of the two pictures drawn by the receiver. Which one is more precise
Answer:
is there a picture? so I can understand it more and it will be easier for me to answer. thank you
Answer:
The second one is more accurate because we were able to draw more precisely and accurately, the first picture was more of a general idea of the picture and the second picture was more of a detailed version.
Explanation:
I just did this assignment and this is what I turned in so yeah I hope this is good enough, if you need more of an explanation though ill try to lengthen it. =]
Think about the process of pulling down the spring and letting it go. For this event, list each form of energy associated with the spring and the weight. (Hint: Use the Energy Graph.)
Answer:
gravitational 2.force of gravityExplanation:
1.it ocours when an object is thrown into the sky. 2.iy ocurs when an object is falling or being pulled from the sky
A pool player makes a shot on a pool table. The 0.17 kg cue ball strikes the 0.15 kg #8-ball, but it is not sunken on the table. Instead, the 8-ball bounces off a rail, and collides into the cue ball a second time. When they collide in a perfectly elastic collision, the cue ball is travelling 1.2 m/s [N10°E) and the 8-ball is travelling 0.89 m/s [W20°N]. Determine the final velocities of each ball.
Answer:
cue ball final: 0.85 m/s at N65°W
8-ball final: 1.27 m/s at N12°E
Explanation:
In a perfectly elastic collision, both momentum and energy are conserved. The momentum is the sum of products of mass and velocity. The energy is half the product of mass and the square of velocity. The difference of "particle" velocities changes sign as a consequence of the collision.
__
equations for final velocityIf we let the masses be m1 and m2, the corresponding initial velocities be v1 and v2, and the final velocities be u1 and u2, we have ...
m1·u1 +m2·u2 = m1·v1 +m2·v2 . . . . . . . conservation of momentum
u1 -u2 = v2 -v1 . . . . . . . . . . . . . . . relative velocity sign changes
This pair of linear equations can be solved for u1 and u2 in any of the usual ways to give ...
u1 = v1(m1 -m2)/(m1 +m2) + v2(2·m2)/(m1 +m2)
u2 = v2(m2 -m1)/(m1 +m2) +v1(2·m1)/(m1 +m2)
__
application to this problemUsing angle measures as clockwise from north, we are given ...
cue ball: m1 = 0.17 kg, v1 = 1.2∠10° m/s
eight ball: m2 = 0.15 kg, v2 = 0.89∠-70° m/s
A suitable calculator can find the final velocities using the above equations.
The first attachment shows the calculations using a TI-84 work-alike calculator.
cue ball final: 0.85 m/s at N65°W
8-ball final: 1.27 m/s at N12°E
The second attachment shows a vector diagram of the velocities.
What is the energy of a single photon of visible light with a wavelength of 500.0 nm? 1 nm=10^−9 m
1. 3.97×10^−19 J
2. 84×10^14 J
2. 02×10^18 J
4. 95×10^−19 J
Answer:
3.97×10^−19 J
From the planks equation
E=hv
V= c/ wave length
V= 3×10^8/500×10^-9
=6×10^14
E= hv
6.63×10^-34×6×10^14
= 3.97×10^−19 J
Explanation:
why didn't the geologists include dates in the notes for the sedimentary rock layers?
Answer:
To establish the age of a rock or a fossil, researchers use some type of clock to determine the date it was formed. Geologists commonly use radiometric dating methods, based on the natural radioactive decay of certain elements such as potassium and carbon, as reliable clocks to date ancient events.
I'm doing a gravity project and need a catchy title. Any ideas?
Answer:
Drop zone :)
Have a great day!!
Please rate and mark brainliest!!
Answer:
if it was a love story you could call it ¨falling for you¨ hehe though since it's a project I'm guessing it's not a love story lol.
Explanation:
which is not one of the ways that codes of ethics can vary from each other?
a. authorship
b. level
c. principle
d. purpose
One of the ways in which code of ethics does not vary from each other is ; ( C ) Principle
What is code of ethics ?Code of ethics is a set of written principles that serves as a guideline to ethical behaviors expected from individuals under some form of authority usually at the place of work.
Code of ethics is different from code conduct because code of conduct is a set of rules that oultines the proper practices of individuals at the place of work. The code of ethics vary in autorship, level and purpose.
Hence we can conclude that One of the ways in which code of ethics does not vary from each other is ; ( C ) Principle
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Which purpose does a light bulb serve in a circuit?
Answer:
A light bulb is that component of circuit that lights up when electricity flows through it and vice versa. Its main function is to tell whether electricity is being supplied or not. Its function is also to light up dark places.
Explanation:
Answer:
A light bulb is that component of circuit that lights up when electricity flows
Explanation:
give any 2 evidence of the unsual expansion of water
Answer:
The anomalous expansion of water is an abnormal property of water whereby it expands instead of contracting when the temperature goes from 4o C to 0o C, and it becomes less dense.
Explanation:
The density is maximum at 4 degree centigrade and decreases below that temperature as shown in graph.
PLS HELP THIS IS DUE TOMORROW!!!
A real-life example of something that uses energy and all of the energy
Answer:
A ball rolling down a hill
Explanation:
Requires an input of gravitional potential energy
outputs rotational kinetic energy and translational kinetic energy
To clean the floor, David exerts a 40 N force on a broom handle to push it 2 m, what is the work done by David on the broom?
Answer:
80Nm
Explanation:
work done = force x distance
force= 40N, distance = 2m
work done= 40 x 2 = 80Nm
The mechanical energy of the diver is the same at every height. What is the mechanical energy of the diver
Which shows the correct order of processes leading up to the formation of a main sequence star?
The processes leading up to the formation of a main sequence star is that gases condense to form a nebula, gravity causes the nebula to collapse.
What is a nebula?It should be noted that nebula simply means a stellar nursery where the stars take birth. Also, gases condense to form nebula.
In this case, the processes leading up to the formation of a main sequence star is that gases condense to form a nebula, gravity causes the nebula to collapse and spin.
Lastly, a protostar forms and then nuclear fusion occurs.
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A 150- branch in a circuit must be reduced to 93 . A resistor will be added to this branch of the circuit to make this change. What value of resistance should be used and how must the resistor be connected
The value of resistance that should be used is 244.74 Ohms and the resistor must be connected in parallel.
Given the following data:
Initial resistance, R₁ = 150 Ohms.Final resistance, R₂ = 93 Ohms.What is a parallel circuit?A parallel circuit can be defined as an electrical circuit with the same potential difference (voltage) across its terminals.
In order to determine the magnitude of a resistor that should be added to this branch of the circuit, the electrical circuit would be connected as a parallel circuit.
Next, the total effective resistance of this electrical circuit is given by:
RT = (R₁ × R₂)/(R₁ - R₂)
RT = (150 × 93)/(150 - 93)
RT = 13950/57
RT = 244.74 Ohms.
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I need the answer of question (6) with explanation.
The gravitational pull of the sun is greatest in our solar system because it...
A. is the brightest
B. has the greatest mass
C. has the greatest magnetism
Answer:
B. has the greatest mass
Explanation:
mass & distance affect pull
grativy affects speed & shape of orbit of the planet
quiziz
The maximum distance particles of the medium move when a wave passes through them is wave:.
Answer:
Amplitude I believe.....
Explanation:
It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously
The sound intensity level of 100 physics professors talking simultaneously is equal to 72 decibel.
Given the following data:
Sound intensity = 52 dB.What is sound intensity?Sound intensity can be defined as a measure of the power of a sound wave per unit area. Thus, sound intensity is a quantity that can be used to measure the energy of sound and its unit of measurement is Watts per square meter.
How to calculate the sound intensity level.Mathematically, sound intensity level is given by this formula:
[tex]\beta = 10 log(\frac{I}{I_{ref}} )[/tex]
Note: The reference value of sound intensity is equal to [tex]1.0 \times 10^{-12}\;W/m^2[/tex]
Thus, the sound intensity for one (1) professor is given by:
[tex]I_1 = 1.0 \times 10^{-12} \times 10^{5.2}\\\\I_1=1.585 \times 10^{-7}\;W/m^2[/tex]
For 100 professors, the sound intensity is:
[tex]I_{100} = 1.585 \times 10^{-7} \times 100\\\\I_{100}=1.585 \times 10^{-5}\;W/m^2[/tex]
Substituting the parameters into the formula, we have;
[tex]\beta = 10 log(\frac{1.585 \times 10^{-5}}{1.0 \times 10^{-12}})\\\\\beta = 10 log(15.58 \times 10^{6})\\\\\beta = 10 \times 7.2\\\\\beta =72\;dB[/tex]
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Complete Question:
One physics professor talking produces a sound intensity level of 52 dB. It's a frightening idea, but what would be the sound intensity level of 100 physics professors talking simultaneously?
Answer:
72dB
Explanation:
The sound intensity level of one prof is given, that's your β1 (which is equal to 52dB).
Using the sound intensity level formula:
β1= 10log ([tex]\frac{I}{I_{o} }[/tex]) = 52 dB
*This will be useful later on [even if β1 is known]
Set up the formula for β2 (β2 is going to be the new sound intensity, the one for the 100 profs):
β2 = 10 log( [tex]\frac{ 100 I}{I_{o} }[/tex] )
*You need to multiply the intensity of one professor by 100 (because now there's more)
*do some algebra- pull out the 100
β2 = 10 log (100 [tex]\frac{I}{I_{o} }[/tex])
*use log laws
β2 = 10 ( log(100) + log ([tex]\frac{I}{I_{o} }[/tex]) )
*Now, isn't there a familiar part? Well, yes! The expression for β1!
β2 = 10log(100) + β1
β2 = 10log(100) + 52dB
*use your calculator
β2 = 73dB
^^^ that's your new sound intensity level