Answer:
2.282 atm
P1V1/T1 = P2V2/T2
2.70atm / (50+273) = X/ 273
make x subject of formula
:. X = 2.28 atm
or 2.28 * 1.01 *10⁵ N/m²
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A 0.210 g gas sample has a pressure of 432 torr in a 333 mL container at 23 C. What is the molar mass of the gas?
The molar mass of the gas is approximately 20.72 g/mol.
To determine the molar mass of the gas, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure (in atm)
V = volume (in liters)
n = number of moles
R = ideal gas constant (0.0821 L·atm/(mol·K))
T = temperature (in Kelvin)
First, let's convert the given values to the appropriate units:
Pressure = 432 torr = 432/760 atm
Volume = 333 mL = 333/1000 L
Temperature = 23°C = 23 + 273.15 K
Substituting the values into the ideal gas law equation:
(432/760) atm * (333/1000) L = n * 0.0821 L·atm/(mol·K) * (23 + 273.15) K
Simplifying the equation:
0.191 atm * 0.333 L = n * 0.0821 L·atm/(mol·K) * 296.15 K
Solving for the number of moles (n):
n = (0.191 atm * 0.333 L) / (0.0821 L·atm/(mol·K) * 296.15 K)
n ≈ 0.01012 moles
Finally, we can calculate the molar mass using the formula:
Molar mass = mass of the gas sample / moles of gas
Molar mass = 0.210 g / 0.01012 moles
Molar mass ≈ 20.72 g/mol
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The system at equilibrium below is heated.
How does the system adjust to reestablish
equilibrium?
2SO₂(g) + O₂(g) ⇒ 2SO3(g) + 198 kJ
When you touch a hot plate, the transfer of heat from the plate to your hand is called ______.
Answer:
Thermal Conduction
Explanation:
16. Who was the first modern chemist
someone help ASAP!!
What are possible components of ionic compounds? Check all that apply.
1: a metal and a nonmetal
2: 2 metals
3: a metal and a polyatomic anion
4: a polyatomic cation and a metal
What happens to ions during bonding to form an ionic compound?
Cations accept electrons and anions give away electrons.
Anions and cations share electrons.
Cations give away electrons and anions accept those electrons.
Answer:
Question 1:
1: a metal and a nonmetal
3: a metal and a polyatomic anion
4: a polyatomic cation and a metal
Question 2:
Cations give away electrons and anions accept those electrons
Calculate how many moles of FeSO4 • 7H2O were added to the Erlenmeyer flask in trial 2
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u don’t gotta answer all questions btw
The molarity of the 750 ml solution of BaI₂ was calculated to be 0.787 M.
413 grams of BaI₂corresponds to 1.05 moles and 750 ml of water corresponds to 0.75 liters of water. So the molarity of the solution is calculated as
1.05* 0.75= 0.787 moles.
24) Thus the molarity of the solution is 0.787 M.
25) P₂O₇ is a covalent compound. Both phosphorous and oxygen have similar electronegativity.
SnBr₂ is ionic as the electronegativity difference between the two is less.
Fe(OH)₂ is an ionic compound.
Cl₃O₈ is a covalent compound.
26) (NH₄)₂CO₃ is highly soluble in water while Fe(OH)₂ is insoluble in water. CaOH is poorly soluble in water while PbCl₂is only sparingly soluble in water.
27) In the given reaction FeS is formed as the precipitate and it is highly insoluble in water while the KCl is dissolved in the aqueous solution.
In the second reaction, ZnCl₂ is soluble as a part of the aqueous solution while strontium sulfate forms the precipitate.
28) In salt water salt is the solute and water is the solvent.
29) Air pressure is lower in a higher atmosphere. The pressure is 0.65 atm and the temperature is -15 degrees at the altitude where the balloon has risen. As the balloon rises, the external pressure decreases and the balloon volume increases. However, the internal pressure or ballon volume remains the same.
30) With an increase in the temperature of a substance, the kinetic energy of the substance increases too.
31) With an increase in the pressure, volume decreases while with a pressure decreases volume increases.
32) If the temperature of a gas increases the pressure also increases.
33) When the plunger is pushed in, the air pressure increases. This pushes the bubbles out and reduces the size of the marshmallow. When the plunger is pushed out, the air pressure decreases, causing the marshmallow to expand.
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Identify what kind of bonding takes place between sodium and chlorine? Explain this bonding. What is the name of the resulting compound? Explain what happens to the compound in water and why it acts this way.
The dissociation of sodium chloride in water allows it to act as an electrolyte, conducting electricity through the movement of ions.
The bonding between sodium and chlorine is classified as ionic bonding. In this type of bonding, electrons are transferred from one atom to another, resulting in the formation of ions. Sodium (Na) readily donates one electron from its outermost shell to achieve a stable electron configuration, while chlorine (Cl) accepts this electron to fill its outermost shell. As a result, sodium forms a positively charged ion (Na+), known as a cation, while chlorine forms a negatively charged ion (Cl-), known as an anion. The electrostatic attraction between these oppositely charged ions creates a strong bond between sodium and chlorine, forming sodium chloride (NaCl) as the resulting compound.
When sodium chloride is dissolved in water, the compound dissociates into separate sodium cations and chloride anions. Water molecules, which have a polar nature, surround the individual ions due to their attraction to opposite charges. This process is called hydration or solvation. The water molecules effectively separate the sodium and chloride ions, leading to the compound's dissolution. This is because water molecules have a higher affinity for the charged ions compared to the ionic bond holding the compound together.
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How many grams of BaSO4 can be produced from 200.0 g of Ba(NO3)2 and 100.0 g of Na2SO4? Which is limiting reactant? How much excess reactant remains?
The limiting reactant will be the one that produces fewer moles of BaSO4. The excess reactant will be the one that has moles left over after the reaction.
To determine the grams of BaSO4 produced and the limiting reactant, we need to compare the stoichiometry of the balanced chemical equation for the reaction between Ba(NO3)2 and Na2SO4, which is:
Ba(NO3)2 + Na2SO4 → BaSO4 + 2NaNO3
First, calculate the number of moles for each reactant:
Moles of Ba(NO3)2 = 200.0 g / molar mass of Ba(NO3)2
Moles of Na2SO4 = 100.0 g / molar mass of Na2SO4
Then, calculate the moles of BaSO4 formed by comparing the stoichiometric coefficients:
Moles of BaSO4 formed = Moles of Ba(NO3)2 (according to the stoichiometry ratio)
Next, calculate the grams of BaSO4 formed:
Grams of BaSO4 formed = Moles of BaSO4 formed × molar mass of BaSO4
To identify the limiting reactant, compare the moles of BaSO4 formed from each reactant. The reactant that produces fewer moles of BaSO4 is the limiting reactant.
To determine the excess reactant remaining, calculate the moles of excess reactant and then convert it to grams.
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Look at the graph that shows the progress made in reducing fuel cell system costs. Graph of progress in reducing Fuel Cell System has an x axis labeled Years from 2002 to 2010, and a y axis labeled cost in dollars per kilowatt hour from 0 to 300. Data is: 2002, 248 dollars. 2003, 198 dollars. 2004, 149 dollars. 2005, 99 dollars. 2007, 82 dollars. 2008, 60 dollars. 2009, 51 dollars. 2010, 43 dollars. 2015 goal is 30 dollars per kilowatt hour. Which conclusion is supported by the information in the graph? The cost of producing a kilowatt of power with a fuel cell will be less than $30 in 2015. Fuel cell cars are unlikely to be affordable in the near future. The rate of emissions is decreasing because of inexpensive fuel cell technology. The environment is unlikely to improve as a result of cheap fuel cell technology.
Describe two ways in which sodium chloride is different from sodium
Answer:
Sodium (Na) is a highly reactive metal, while sodium chloride (NaCl) is a compound formed by the combination of sodium and chlorine (Cl). Sodium exists as a pure element, whereas sodium chloride is a stable, crystalline compound.
Sodium is a soft, silvery-white metal that is highly reactive and can easily react with water or air. In contrast, sodium chloride is a white crystalline solid that is highly stable and does not react readily with water or air. Sodium chloride is commonly known as table salt and is widely used as a seasoning and food preservative.
While preparing 2.00 L of iced tea, Dora adds 0.750 moles of sucrose. What is the molarity of the sucrose in the iced tea mixture?
The molarity of the sucrose in the iced tea mixture prepared by dissolving 0.750 moles of sucrose in the 2.00 L of iced tea is
How do i determine the molarity of the solution?The following data were obtained from the question:
Number of mole of sucrose = 0.750 moleVolume of solution = 2 LitersMolarity of solution = ?The molarity of the solution can be obtained as illustrated below:
Molarity of solution = mole / volume
Molarity of solution = 0.750 mole / 2 liters
Molarity of solution = 0.375 M
Thus, we can conclude from the above calculation that the molarity of the solution is 2.5 M
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A compound is found to contain 3.622 % carbon and 96.38 % bromine by weight.
The molecular weight for this compound is 331.61g/mole. What is the molecular formula for this compound?
If a compound is found to contain 3.622 % carbon and 96.38 % bromine by weight. The molecular formula for the compound is CBr4.
First, get the empirical formula in order to calculate the molecular formula of the chemical. The empirical formula shows the atoms of a compound in their most straightforward whole number ratio.
Suppose 100 grams of the substance. To determine the mass of carbon and bromine in the compound using the provided percentages.
Mass of C = 3.622% of 100g
= 3.622g
Mass of Br = 96.38% of 100g
= 96.38g
The next step is to determine the atomic masses of carbon and bromine in order to determine the number of moles for each.
Atomic mass of carbon = 12.01 g/mol
Atomic mass of bromine = 79.90 g/mol
Moles of C = (mass of carbon) / (atomic mass of carbon)
= 3.622g / 12.01 g/mol
= 0.3016 mol
Moles of Br = (mass of bromine) / (atomic mass of bromine)
= 96.38g / 79.90 g/mol
= 1.205 mol
Divide the moles of each element by the fewest number of moles obtained, in this case the moles of carbon, to arrive at the empirical formula.
Empirical formula ratio:
C: (0.3016 mol) / (0.3016 mol)
= 1
Br: (1.205 mol) / (0.3016 mol)
= 4
The empirical formula for the compound is C₁Br4.
To determine the molecular formula, it is required to know the molecular weight of the compound. The molecular weight is 331.61 g/mol.
To find the number of empirical formula units in the molecular formula, divide the molecular weight by the empirical formula weight.
Empirical formula weight:
C = 12.01 g/mol × 1
= 12.01 g/mol
Br= 79.90 g/mol × 4
= 319.60 g/mol
Empirical formula weight = 12.01 + 319.60
= 331.61 g/mol
Now find the number of empirical formula units in the molecular formula:
Number of empirical formula units
= (molecular weight) ÷ (empirical formula weight)
Number of empirical formula units
= 331.61 g/mol / 331.61 g/mol
= 1
The number of empirical formula units is 1, the empirical formula C₁Br4 is would be the molecular formula for this compound.
Thus, the molecular formula for the compound is CBr₄.
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A block of wood has a mass of 450. g. When dropped into a graduated cylinder, the water level rises from 4.50 mL to 16.22 mL. What is the density of the block in g/mL?
The density of the block of wood is approximately 38.40 g/mL.
To calculate the density of the block of wood, we need to use the formula:
Density = Mass / Volume
First, let's convert the mass of the block from grams (g) to milliliters (mL). Since the density is expressed in g/mL, the mass and volume need to have the same units.
Given:
Mass of the block = 450 g
Change in water level = 16.22 mL - 4.50 mL = 11.72 mL
Density = 450 g / 11.72 mL
Calculating the density:
Density ≈ 38.40 g/mL
Therefore, the density of the block of wood is approximately 38.40 g/mL.
The density of a substance represents its mass per unit volume. In this case, the mass of the block of wood is 450 g, and the volume is determined by the change in water level when the block is dropped into the graduated cylinder. By subtracting the initial water level (4.50 mL) from the final water level (16.22 mL), we find that the block occupies a volume of 11.72 mL. Dividing the mass by the volume gives us the density of the block, expressed in grams per milliliter.
It's important to note that the density of wood can vary depending on factors such as the type of wood and its moisture content. The value calculated here represents the density of the specific block used in the given scenario.
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To calculate the molarity of the solution, we need to know the number of moles of BaI2 and the volume of the solution in liters.
First, let's calculate the number of moles of BaI2. We can use the formula:
Number of moles = Mass (in grams) / Molar mass
The molar mass of BaI2 can be calculated as follows:
Ba: atomic mass = 137.33 g/mol
I: atomic mass = 126.90 g/mol
2 x I = 2 x 126.90 g/mol = 253.80 g/mol
Total molar mass of BaI2 = 137.33 g/mol + 253.80 g/mol = 391.13 g/mol
Number of moles of BaI2 = 413 g / 391.13 g/mol ≈ 1.056 moles
Next, we need to convert the volume of the solution from milliliters to liters:
Volume of solution = 750 ml / 1000 = 0.75 L
Finally, we can calculate the molarity using the formula:
Molarity = Number of moles / Volume of solution
Molarity = 1.056 moles / 0.75 L ≈ 1.408 M
Therefore, the molarity of the BaI2 solution is approximately 1.408 M.
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How many grams of AgNO3 are needed to prepare 750 ml of a 0.30 M solution?
We can use the following formula to determine how many grams of AgNO3 are needed to make a 0.30 M solution with a volume of 750 ml:
moles = volume (L) x concentration (M)
The volume provided must first be converted from milliliters to liters:
Volume = 750 ml ÷ 1000 ml/L = 0.75 L
Now we can find the molarity of AgNO3:
moles = 0.30 M × 0.75 L = 0.225 moles
To find the grams of AgNO3, we need to use the molar mass of AgNO3, which is calculated as follows:
Ag: 1 atom × 107.87 g/mol = 107.87 g/mol
N: 1 atom × 14.01 g/mol = 14.01 g/mol
O: 3 atoms × 16.00 g/mol = 48.00 g/mol
Total molar mass of AgNO3:
107.87 g/mol + 14.01 g/mol + 48.00 g/mol = 169.88 g/mol
Now, we can calculate the grams of AgNO3 needed:
grams = moles × molar mass
grams = 0.225 moles × 169.88 g/mol = 38.22 grams
Therefore, approximately 38.22 grams of AgNO3 are needed to prepare 750 ml of a 0.30 M solution.
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based on table g what is the mass of kcl that must be dissolved in 200 grams of H2O at 10 c to make a saturated solution
Based on Table G, the mass of KCl that must be dissolved in 200 grams of H₂O at 10 °C to make a saturated solution is 60 g.
What is the mass of KCl that must be dissolved?Based on Table G, the solubility of KCl at 10°C is given as 30 g/100 g water.
To calculate the mass of KCl that can be dissolved in 200 grams of water at 10°C, we can set up a proportion:
(30 g KCl / 100 g water) = (x g KCl / 200 g water)
Cross-multiplying and solving for x, we get:
x g KCl = (30 g KCl / 100 g water) * (200 g water)
x g KCl = 60 g KCl
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determine if the following compounds are soluble (s) or insoluble (i) in what we based on the solubility chart
a. (NH4)2CO3
b.Fe(OH)2
c.CaOH
d. PbCl2
The solubility chart provides information about the solubility of various compounds in water. Here are the solubilities of the given compounds:
a. (NH₄)₂CO₃: According to the solubility chart, most carbonate (CO₃²⁻) salts are insoluble, except for those of Group 1 metals (alkali metals) and ammonium (NH₄⁺). Therefore, (NH₄)₂CO₃ is soluble.
b. Fe(OH)₂: Hydroxide (OH⁻) salts of transition metals, including iron (Fe), are generally insoluble, except for those of Group 1 metals and ammonium. Therefore, Fe(OH)₂ is insoluble.
c. Ca(OH)₂: Calcium hydroxide (Ca(OH)₂) is soluble. However, the given compound "CaOH" appears to be missing the subscript ₂, indicating two hydroxide ions. If it should be Ca(OH)₂, then it is soluble.
d. PbCl₂: According to the solubility chart, chloride (Cl⁻) salts, including lead chloride (PbCl₂), are generally soluble, except for those of silver (Ag⁺), lead (Pb²⁺), and mercury (Hg₂²⁺). Therefore, PbCl₂ is insoluble.
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Predict the products in the chemical reaction, Na+AlN
Identify reactions types and balancing equations
Balance the following chemical equations:
1. N2 + 3 H2 → 2 NH3
Ex: Synthesis reaction
2. 2 KClO3 → 2 KCl + 3 O2
Single Replacement reaction
3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl
Decomposition reaction
4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2
Double Replacement reaction
5. 2 H2 + O2 → 2 H2O
Combustion reaction
6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2
Synthesis reaction
7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Decomposition reaction
8. C3H8 + 5 O2 → 3 CO2 + 4 H2O
Combustion reaction
9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O
Double Replacement reaction
10. 4 P + 5 O2 → 2 P2O5
Synthesis reaction
11. 2 Na + 2 H2O → 2 NaOH + H2
Single Replacement reaction
12. 2 Ag2O → 4 Ag + O2
Decomposition reaction
13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
Combustion reaction
14. 2 KBr + MgCl2 → 2 KCl + MgBr2
Double Replacement reaction
15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O
Double Replacement reaction
16. C5H12 + 8 O2 → 5 CO2 + 6 H2O
Combustion reaction
17. 4 Al + 3 O2 → 2 Al2O3
Synthesis reaction
18. Fe2O3 + 2 Al → 2 Fe + Al2O3
Single Replacement reaction
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MgCl2 + 2 NaOH → 2 NaCl + Mg(OH)2
If you want to produce 11.00 moles of MgCl2, how many grams of NaOH are needed for the reaction to take place ?
To produce 11.00 moles of MgCl2, you would need 858.00 grams of NaOH.
To determine the amount of NaOH needed to produce 11.00 moles of MgCl2, we need to use stoichiometry and the balanced chemical equation:
[tex]MgCl_2 + 2 NaOH[/tex] → [tex]2 NaCl + Mg(OH)_2[/tex]
From the balanced equation, we can see that the mole ratio between [tex]MgCl_2[/tex]and NaOH is 1:2.
Therefore, for every 1 mole of[tex]MgCl_2[/tex], we need 2 moles of NaOH.
Given: Moles of [tex]MgCl_2[/tex]= 11.00 moles
Using the mole ratio, we can calculate the moles of NaOH required:
moles of NaOH = 2 * moles of MgCl2
moles of NaOH = 2 * 11.00 moles
moles of NaOH = 22.00 moles
Now, we need to convert the moles of NaOH to grams using the molar mass of NaOH:
The molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 39.00 g/mol
grams of NaOH = moles of NaOH * molar mass of NaOH
grams of NaOH = 22.00 moles * 39.00 g/mol
grams of NaOH = 858.00 grams
Therefore, to produce 11.00 moles of [tex]MgCl_2[/tex], you would need 858.00 grams of NaOH.
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A teacher divides her class into groups and assigns each group the task of measuring the mass of the samer object three times the teacher already knoes that the mass of the object is 25 g
Dividing the class into groups and assigning them the task of measuring the mass of the same object multiple times promotes scientific inquiry, encourages critical thinking.
It also provides an opportunity to discuss the concepts of precision, accuracy, and the role of statistical analysis in scientific investigations.
When the teacher divides her class into groups and assigns each group the task of measuring the mass of the same object three times, it allows for multiple measurements to be taken in order to obtain more accurate and reliable results. This approach is a common practice in scientific experiments and data collection.
By having multiple groups perform the measurements, several factors come into play:
1. Precision: Each group's measurements may have some inherent variability due to factors such as the sensitivity of the measuring instrument, human error, or slight variations in the experimental conditions. Taking multiple measurements allows for better assessment of the precision of the measurements by evaluating the spread or range of values obtained.
2. Accuracy: While the teacher already knows the mass of the object is 25 g, the purpose of the exercise is to assess the accuracy of the measurements performed by the students. By comparing the measured values from each group to the known value, the teacher can evaluate the accuracy of the measurements and identify any systematic errors or biases.
3. Averaging: Taking multiple measurements allows for the calculation of an average value, which tends to be a more reliable representation of the true value. By averaging the measurements from all the groups, the teacher can obtain a more accurate estimate of the mass of the object.
4. Statistical Analysis: With multiple measurements, the teacher can perform statistical analysis on the data, such as calculating measures of central tendency (mean, median) and measures of dispersion (standard deviation), to further assess the quality and reliability of the measurements.
Overall, dividing the class into groups and assigning them the task of measuring the mass of the same object multiple times promotes scientific inquiry, encourages critical thinking, and helps students understand the importance of repeated measurements in obtaining accurate and reliable data. It also provides an opportunity to discuss the concepts of precision, accuracy, and the role of statistical analysis in scientific investigations.
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The Russian Mir space station used a chemical oxygen generator system to make oxygen for the crew. The system ignited a tube of solid lithium perchlorate (LiClO4) to make oxygen and lithium chloride (LiCl):
LiClO4 (s) 2O2 (g) + LiCl (s)
If you have 500 g of LiClO4, then how many liters of oxygen will the system make at the station’s standard operating conditions, a pressure of 101.5 kPa and a temperature of 21°C?
At the usual working conditions of 101.5 kPa and 21°C, the chemical oxygen generator system would generate roughly 220.84 litres of oxygen using 500 g of LiClO4.
We may use the ideal gas law and stoichiometry to calculate how many litres of oxygen are created by the chemical oxygen generator system employing 500 g of LiClO4.
We must first determine the moles of LiClO4. LiClO4 has a molar mass of approximately 106.39 g/mol. As a result, 4.704 mol of LiClO4 are produced from 500 g of LiClO4 using the formula: 500 g / 106.39 g/mol
We can see from the chemical equation that 1 mole of LiClO4 results in 2 moles of O2. 4.704 mol of LiClO4 will therefore result in:
2 mol O2 / 1 mol LiClO4 4.704 mol LiClO4 = 9.408 mol O2
The moles of O2 under the specified conditions must then be converted to volume. The ideal gas law, which goes as follows:
PV = nRT
Where:
P = pressure = 101.5 kPa
V = volume (in liters)
n = moles of gas = 9.408 mol
R = ideal gas constant = 8.314 J/(mol·K)
T = temperature = 21°C = 294 K (converted to Kelvin)
Rearranging the equation to solve for V:
V = (nRT) / P
V = (9.408 mol × 8.314 J/(mol·K) × 294 K) / (101.5 kPa × 1000 Pa/kPa)
Simplifying the units:
V = (9.408 × 8.314 × 294) / 101.5
V ≈ 220.84 liters
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Identify reactions types and balancing equations
The following chemical equations must be balanced:
1. N2 + 3 H2 → 2 NH3
Type: Synthesis
2. 2 KClO3 → 2 KCl + 3 O2
Type: Single Replacement
3. 2 NaF + ZnCl2 → ZnF2 + 2 NaCl
Type- Decomposition
4. 2 AlBr3 + 3 Ca(OH)2 → Al2(OH)6 + 6 CaBr2
Type- Double Replacement
5. 2 H2 + O2 → 2 H2O
Type: Combustion
6. 2 AgNO3 + MgCl2 → 2 AgCl + Mg(NO3)2
Type: Synthesis
7. 2 Al + 6 HCl → 2 AlCl3 + 3 H2
Type: Decomposition
8. C3H8 + 5 O2 → 3 CO2 + 4 H2O
Type: Combustion
9. 2 FeCl3 + 6 NaOH → Fe2O3 + 6 NaCl + 3 H2O
Type: Double Replacement
10. 4 P + 5 O2 → 2 P2O5
Type: Synthesis
11. 2 Na + 2 H2O → 2 NaOH + H2
Type: Single Replacement
12. 2 Ag2O → 4 Ag + O2
Type: Decomposition
13. C6H12O6 + 6 O2 → 6 CO2 + 6 H2O
Type: Combustion
14. 2 KBr + MgCl2 → 2 KCl + MgBr2
Type: Double Replacement
15. 2 HNO3 + Ba(OH)2 → Ba(NO3)2 + 2 H2O
Type: Double Replacement
16. C5H12 + 8 O2 → 5 CO2 + 6 H2O
Type: Combustion
17. 4 Al + 3 O2 → 2 Al2O3
Type: Synthesis
18. Fe2O3 + 2 Al → 2 Fe + Al2O3
Type: Single Replacement
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The volume of 6.00M HCL needed to make 0.32L of 3.0M HCL is
Answer:
Explanation: the answer is in the picture
Answer:
[tex]\huge\boxed{\sf V_1=0.16 \ L}[/tex]
Explanation:
Given Data:Initial Molarity =[tex]M_1[/tex] = 6.00 M
Final Volume = [tex]V_2[/tex] = 0.32 L
Final Molarity = [tex]M_2[/tex] = 3.0 M
Required:Initial Volume = [tex]V_1[/tex] = ?
Formula:[tex]M_1V_1=M_2V_2[/tex]
Solution:Put the given data in the above formula,
Finding initial volume.
[tex]6 \times V_1=0.32 \times 3\\\\6 \times V_1 = 0.96\\\\Divide \ both \ sides \ by \ 6\\\\V_1=0.96/6\\\\V_1=0.16 \ L\\\\\rule[225]{225}{2}[/tex]
__Fe+__Pb(No3)3+__Pb
If 30.0 g of iron react with 258 g lead (Il) nitrate and 67.8 grams of lead form, what is the percent yield?
When 30.0 g of iron reacts with 258 g lead (Il) nitrate and 67.8 grams of lead form, then the percentage yield is 40.62%.
Given information,
Mass of iron = 30g
Mass of Lead (III) nitrate = 258g
Mass of lead = 67.8g
The balanced equation for the reaction is:
2 Fe + 3 Pb(NO₃)₂ → 3 Pb + 2 Fe(NO₃)₃
The stoichiometric ratio between iron (Fe) and lead (Pb) is 2:3.
The moles of Fe:
Moles of Fe = mass of Fe / molar mass of Fe
Moles of Fe = 30.0/ 55.845
Moles of Pb = (3/2) × moles of Fe
The theoretical yield of Pb:
Mass of Pb (theoretical) = moles of Pb × molar mass of Pb
Mass of Pb (theoretical) = (3/2) × moles of Fe × molar mass of Pb
The percent yield:
Percent yield = (actual yield / theoretical yield) × 100
Actual yield = 67.8 g
Theoretical yield = (3/2) × (30/55.845) × 207.2 = 166.95
Percent yield = 67.8/166.9 × 100 = 40.62%
Thus, the percentage yield is 40.62%.
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In the Pilbara iron ore exists in mines that are both readily accessible and contain high grade ore, which is then shipped to China. Research how the iron is extracted by reduction of haematite. Explain why this process is known as reduction and how the ore is separated before being reduced in a blast furnace.
The extraction of iron from haematite ore involves a process called reduction. Reduction is the chemical reaction in which oxygen is removed from a compound, resulting in the formation of a new substance.
In the case of haematite, the reduction process involves removing the oxygen from the iron oxide (Fe2O3) to obtain elemental iron (Fe). This is typically achieved through a process called smelting, which is carried out in a blast furnace. Before the haematite ore is reduced in a blast furnace, it needs to undergo a series of steps to separate impurities and prepare it for the reduction process. The first step is crushing and grinding the ore into smaller particles. This is done to increase the surface area of the ore, allowing for better contact with the reducing agent. After crushing and grinding, the ore is then subjected to a process called beneficiation, where it is separated from gangue materials and other impurities.
Beneficiation techniques vary, but commonly involve processes such as gravity separation, magnetic separation, and flotation. These methods exploit the differences in physical and chemical properties between the haematite ore and the impurities, allowing for their separation. Once the ore is purified and separated, it is ready to be reduced in a blast furnace, where the smelting process takes place.
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Question 5 of 25
What is the name of the branched alkane shown below?
Answer:
3rf or 5d cd Yu been successful of a new future
The name of the branched alkane shown below is 2- methylheptane that is in option D as alkane is a type of hydrocarbon, which is a compound consisting of hydrogen and carbon atoms only.
Alkanes are characterized by having single bonds between carbon atoms and being saturated hydrocarbons, meaning they have the maximum number of hydrogen atoms bonded to each carbon atom. Alkanes are often referred to as "paraffins" and serve as the simplest and most basic form of hydrocarbons. They are relatively unreactive and are commonly found in petroleum and natural gas. The systematic names for alkanes are derived from the prefix "n-" or "normal-," followed by the Greek numerical prefix indicating the number of carbon atoms. For example, "n-pentane" refers to the straight-chain alkane with five carbon atoms.
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How are moles and particles related. How could you find the number of particles in 4 moles of substance
determine if the following are ionic or covalent compounds
a. P2O7
b. SnBr2
c.Fe(OH)2
d.Cl3O8
Answer:
a. P2O7 - This is a covalent compound. P and O have similar electronegativities and they form a covalent bond between them, rather than an ionic bond.
b. SnBr2 - This is a covalent compound. Sn and Br have different electronegativities, but they still form a covalent bond due to their relatively small difference in electronegativity.
c. Fe(OH)2 - This is an ionic compound. Fe has a higher electronegativity than O and H, so it tends to donate its electrons and become positively charged. This results in the formation of ionic bonds between Fe and OH.
d. Cl3O8 - This is a covalent compound. Cl and O have similar electronegativities, so they form covalent bonds rather than ionic bonds.