For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law
so, 20 N force stretch 4 cm.
What is the Hooke's law ?Hooke's law is a law of elasticity discovered by the English scientist Robert Hooke in 1660 that states that the displacement or size of a deformation is directly proportional to the deforming force or load for relatively small deformations of an object.It is the fundamental principle underlying the manometer, spring scale, and clock balance wheel. Hooke's law is the underlying principle of seismology, acoustics, and molecular mechanics.Hooke's spring law usually applies to any elastic object of any complexity, as long as the deformation and stress can be expressed by a single number that can be both positive and negative.For the same spring, the value of spring constant must be same. The relation between the force and the spring constant is given by Hooke's law as :
F=kx
where
F = Force
k = is spring
constant
x = stretches
here
10/ 2 = 20/ x
x -= 4 cm .
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Two electromagnetic waves are traveling through a material. Wave 1 has a maximum electric field strength that is three times the maximum field strength of wave 2. How do the average intensities of the waves compare?.
The average intensities of the waves compare I1 = 9 x I2.
The electric field of an electromagnetic wave points in the positive y direction. At the same time, the magnetic field of this wave points in the positive z direction. In the electromagnetic field, electric and magnetic fields exist in the form of waves in horizontal and vertical patterns. To exist in this pattern requires maximum amplitude. Charged particles create electric fields.
This electric field exerts forces on other charged particles. A positive charge accelerates in the direction of the electric field, and a negative charge accelerates in the direction of the electric field. Magnetic fields are generated when charged particles move. In electromagnetic waves, the electric and magnetic fields are perpendicular to each other and both are also perpendicular to the direction of wave propagation.
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an 1800-w toaster, a 1400-w electric frying pan, and a 75-w lamp are plugged into the same outlet in a 15-a, 120-v circuit. (the three devices are in parallel when plugged into the same socket.) what current is drawn by the electric frying pan?
The current drawn by the electric frying pan is 27.295 A.
Power of toaster, P1 = 1800 W
Power of electric frying pan, P2 = 1400 W
Power of lamp, P3 = 75 W
Three devices are in parallel combination. So their Voltage difference is the same.
∆V = 120 Volt
Current is drawn by frying pan, I1 = P1/∆V = 1800/120 = 15 A
Current drawn by an electric frying pan, I2= 1400/120 = 11.67 A
Current drawn by frying pan, I3 = P3/120 = 75/120 = 0.625 A
Total current frying pan= (15 + 11.67 + 0.625) = 27.295 A
Electric current refers to the float of electricity in an electronic circuit, and to the amount of strength flowing via a circuit. it is measured in amperes (A). the bigger the price in amperes, the greater electricity is flowing inside the circuit.
The current is the charge of glide of price across a cross-segment every day to the direction of the float of the current. The S.I. unit of modern is coulomb consistent with 2d which is called ampere and denoted by means of A.
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what is the tension in a tow rope that is used to accelerate a 1700-kg car at 0.5 m/s2? (ignore the effects of friction.) a) assuming the tow rope is completely horizontal? b) assuming the tow rope is 400 above the horizontal?
The tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
F = m a
F = Net force
m = Mass
a = Acceleration
m = 1700 kg
a = 0.5 m / s²
∑ [tex]F_{x}[/tex] = m a
T = m a
T = 1700 * 0.5
T = 850 N
b ) Assuming the tow rope is 40° above the horizontal,
θ = 40°
Resolving the tension force into its horizontal component,
Tx = T cos θ
∑ [tex]F_{x}[/tex] = m [tex]a_{x}[/tex]
Tx = 1700 * 0.5
T cos 40° = 850
T = 1103.9 N
Therefore, the tension in a tow rope,
a ) If it is completely horizontal = 850 N
b ) If it is 40° above the horizontal = 1103.9 N
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air is moving at a velocity of 8 m/s through a hoop with cross sectional area of 100.0 m2. if the density of the air is 1.2 kg/m3, what mass flow rate of air is moving through the hoop (in kg/s)?
In consideration of Henry's law the molar mass of organic compound is 0.24 grams.
What is molar mass?
The mass of a sample of a chemical compound divided by the quantity, or number of moles in the sample, measured in moles, is known as the molar mass of that compound. What is the mass of water in grammes and how much Equis paper with a 12.5% sodium chloride content weighs at 55 degrees Celsius, according to Sol-One of three? His issue informs us that pure water has a specific gravity of 118 torr at 55 degrees Celsius. Therefore, the first task at hand is to determine the mole fraction of, I suppose, the thermal fractions of both water and sodium chloride.
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Air is approximately 21% o2 and 78% n2 by mass. Calculate the root-mean-square speed of each gas at 273 k.
The root square method of the gas at 273 K is given as 493.15 for N2 and 461.3 for O2
How to solve for the root mean square methodWe have to know that the root square method is dependent on the direct proportionality to the square root of absolute temperature as well as inverse of molar mass.
We have 1 j = 1 kgm²/s²
Vrms = √3rt/Mm
R = gas constant
T = temperature = 273
Mm is the molar mass
The molar mass of N₂ is = 0.02800 kg / mol
The mo;lar mass of o₂ = 0.03200 kg / mol
We have to solve first for N₂
= √3 (8.32447 * 273 / 0.028000
= √243,198.247
= 493.15
For 02
Vrms = √3 * 8.31447 * 273 / 0.03200
= √212798.466
= 461.3
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a person threw a small bundle toward their friend on a balcony 10 meters above them. how fast did they throw it up?
The speed with which they threw the bundle is 14 m/s.
What is the speed of the bundle?We know that the speed of the bundle can be obtained from the use of the equations of kinematics. Now we can use the equation of the upward motion under gravity here.
Using;
v^2 = u^2 - 2gh
v = final velocity
u = initial velocity
g = acceleration due to gravity
h = height
Now;
v = 0 m/s at the maximum height
u^2 = 2gh
We now have;
u = √2gh
u = √ 2 * 9.8 * 10
u = 14 m/s
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a lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline and its light makes four revolutions per minute. how fast (in km/min) is the beam of light moving along the shoreline when it is 1 km from p?
A lighthouse is located on a small island 3 km away from the nearest point p on a straight shoreline is the beam of light moving along the shoreline when it is 1 km from p is 83.78 km/min
3*10/9*8pi = dx/dt
80pi/3 = dx/dt
dx/dt = 83.78 km/min
Thus, the beam of light is sweeping along the shore at the rate of 83.78 km/min when the beam is 1 km from the point P and light makes four revolutions per minute.
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A baseball has a mass of 2.5 kilograms. If the acceleration due to gravity is 9.8 m/s2 , what is the weight of the baseball in newtons?
A. 20.0 N
B. 3.9 N
C. 10.5 N
D. 24.5 N
Answer: D. 24.5 N
Explanation:
Fgrav = mg
Fgrav = 2.5(9.8)
Fgrav = 24.5 N
an object is launched from ground level with an initial speed of 24.6 meters/second at an upward angle of 0.595 radians above the horizontal (90 degrees is about 1.57 radians). how far will it travel horizontally before hitting the ground?
The object will travel 55.67 meters horizontally before hitting the ground.
The object is launched with speed 24.6 meters/second.
The angle at which the object is launched is 0.595 radians.
We know,
90° = 1.57 radians
1 radian = 90°/1.57
So,
0.595 radians = 90°(0.595)/1.57
0.595 radians = 34°
The horizontally distance R travelled by the projectile can be given by,
R = U²sin2A/g
Where, U is the initial speed,
A is the angle at which object is launched,
g is acceleration due to gravity,
Putting all the values,
R = (24.6)²sin(68°)/10
R = 55.67 meters.
The horizontal range is 55.67 meters.
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a football player runs from a location 5m from the left sideline and 5m from his/her goal line to a location 35m from the left sideline and 60m from the goal-line. displacement is 63m. the player did not run in a straight line. at the start there is 1-minute left on the clock; at the end there is 50 seconds left on the clock. knowing only this information, what kinematic variables can we calculate?
Knowing only this information, the kinematic variable we can calculate is Vavg = 6.3 m/s. Option B - average velocity
velocity is the directional velocity of an object in movement as an illustration of its rate of trade in function as found from a selected body of reference and as measured by means of a specific standard of time.
The average velocity is defined because of the alternate in function or displacement (∆x) divided by the point durations (∆t) in which the displacement takes place. The common pace may be tremendous or negative relying upon the sign of the displacement.
As it is given that the player is not moving in a straight line then distance and Displacement will not same.
We know average velocity is the ratio of total displacement to the time and if both are known then it can find easily.
Hence average speed can't be found
Vavg = 63/(60-50) m/s
Vavg = 6.3 m/s
Instantaneous velocity is the velocity at a certain point of time that can't be found because there is only given initial & final locations
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Which statement best describes the process of alpha decay? (1 point)
O An unstable nucleus rearranges its particles and releases energy.
O An unstable nucleus releases a single positively charged particle.
O An unstable nucleus releases an electron.
O An unstable nucleus releases a particle containing two protons and two neutrons.
Two protons and two neutrons are both present in the particle that an unstable nucleus releases.
What does alpha decay mean?The nuclear process known as "alpha decay" results in the parent nucleus emitting an alpha particle. The alpha particle, represented by the Greek letter and physically similar to the helium atom's nucleus, is made up of two protons and two neutrons.
Which statement about alpha decay is accurate?What statement about deterioration is true? It brings down the atomic number of the nuclide by 2. The daughter nuclide, which frequently doesn't undergo further decay since the parent nuclide is unstable, is created during radioactive decay.
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Free-body diagrams for four situations are shown below. For each situation, determine the net force acting upon the object. Your answer must include both the magnitude and the direction of the net force vector. You should have four (4) total responses to this question (labeled A, B, C, and D).
The magnitude and direction of the net force are:
A: the net force is 3N in the downward direction,
B: the net force is zero,
C: The net force is 5N in the downward direction,
D: The net force is 4N in the right direction.
What is the net force?The net force of an object can be described as the vector sum of all the forces acting on an object. The net force is a single force that shows the same effect as the original forces on the particle's motion.
The net force becomes the resultant force. The net force has the same effect on the rotational motion as all original forces together by the object.
The mathematical expression can be written for the net force as:
[tex]\vec F_{net} = \vec F_{x} + \vec F_{y}[/tex]
For figure (A), the net force is equal to :
F = (2N - 2N) + (2N - 5N) = - 3N
So the magnitude of the force is 3N in the downward direction.
For figure (B), the net force is equal to :
F = (2N - 2N) + (5N - 5N) = 0
So the magnitude of the net force is equal to zero.
For figure (C), the net force is equal to :
F = (5N - 5N) + (5 N) = 5 N
So the magnitude of the net force is 5N in the downward direction.
For figure (D), the net force is equal to :
F = (2N - 2N) + (7N - 3N) = 4N
So the magnitude of the net force is 4N towards the right direction.
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It doesn't need arto lift off
4. What forces are acting on a book sitting on a table? Are action-reaction forces involved
in this situation?
5. If two people each standing on a scooter board push off of each other what happens
(relate to Newton's Third Law)?
6. In # 5 how would the distance moved by the scooter boards compare if one person had a
lot more mass than the other person?
7. If a person standing on a scooter board pushes off of a wall, what happens? Can this
situation be explained in terms of Newton's Third Law (action-reaction)?
8. How is shooting a shotgun related to Newton's Third Law?
9. Why does a rifle have less "kick" than a shotgun?
They will go off in opposite directions with the same force.
What is Newton's third law?
Newton's third law states that if object A exerts a force on object B, then object B must apply a force to object A that is equal in magnitude and directed in the opposite direction. This law illustrates a symmetry in nature whereby forces always occur in pairs and whereby no body can exert a force without also being subjected to one.
Newton's Third Law states that for every action, there is an equal but opposite reaction. If two people are standing on a scooter and push off each other (following the Law), it should come to the conclusion that they could go off in opposite with the same force.
Person is exiting for (describe in Newton's third law) against the wall that then has an effect on the person pushing them bac
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If a person standing on a scooter board pushes off of a wall, what happens? Can this
situation be explained in terms of Newton's Third Law (action-reaction)?
A 33-N force is applied to a 7-kg object to move it with a constant velocity of 6.3 m/s across a level surface. The coefficient of friction between the object and the surface is approximately ____. Round your answer to the hundredths place.(Use the approximation g ≈ 10 m/s2.)
Given:
The applied force is,
[tex]F=33\text{ N}[/tex]The mass of the object is,
[tex]m=7\text{ kg}[/tex]The constant velocity of the object is,
[tex]v=6.3\text{ m/s}[/tex]To find:
The coefficient of friction between the object and the surface
Explanation:
The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.
If the coefficient of friction between the object and the surface is
[tex]\mu[/tex]we can write the frictional force as,
[tex]f=\mu mg[/tex]For equilibrium condition,
[tex]\begin{gathered} \mu mg=F \\ \mu=\frac{F}{mg} \\ \mu=\frac{33}{7\times10} \\ \mu=0.47 \end{gathered}[/tex]Hence, the coefficient of friction between the object and the surface is 0.47.
a satellite is in a circular orbit around an unknown planet. the satellite has a speed of 1.31 x 104 m/s, and the radius of the orbit is 3.88 x 106 m. a second satellite also has a circular orbit around this same planet. the orbit of this second satellite has a radius of 9.96 x 106 m. what is the orbital speed of the second satellite?
The orbital speed of the second satellite with same centripetal force is 2.1 x 10⁴ m/s.
We need to know about centripetal force to solve this problem. The centripetal force is a force caused by moving objects in a circular motion. The magnitude of the centripetal force depends on tangential speed, mass and radius. It can be written as
Fc = m . v² / r
where Fc is the centripetal force, m is mass, v is tangential speed and r is the radius.
From the question above, we know that
Fc 1 = Fc 2 = Fc
m1 = m2 = m
v1 = 1.31 x 10⁴ m/s
r1 = 3.88 x 10⁶ m
r2 = 9.96 x 10⁶ m
Hence, the ratio of centripetal force is
Fc2 / Fc1 = (m2 . v2² / r2) / (m1 . v1² / r1)
v1² / r1 = v2² / r2
(1.31 x 10⁴)² / 3.88 x 10⁶ = v2² / 9.96 x 10⁶
v2² = 4.41 x 10⁸
v2 = 2.1 x 10⁴ m/s
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a strechy material with a spring constant of 68.7 n/m is stretched 2.71 cm from its equilibrium length. what is the magnitude of the resulting spring force?
The magnitude of the resulting spring force when the material is stretched from its equilibrium position is -0.02522 N.
The spring force is a spring or a stretchy material is given by the formula,
F = -1/2Kx²
Where z
F is the spring force,
K is the spring constant,
x is the compression or extension in the material,
The negative sign represent that the force is restoring in nature.
We know, in our case,
The extension in the material is 2.71cm.
1 cm = 1/100m
So,
2.71 cm = 2.71/100m
The spring constant is 68.7N/m.
Now, putting all the values,
F = 1/2Kx²
F = -1/2(68.6)(2.71/100)²
F = -0.02522N.
So, the spring force is 0.02522N.
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a cat slides down a slippery slanted roof at an acceleration of 2.2 m/s2 (it won't get hurt because it has nine lives). if it started at the top with zero initial speed, how far will the cat have slipped after 3 seconds? answer in meters and include two digits after the decimal point.
The cat will have slipped till the distance of 9.90 seconds in 3 seconds.
The acceleration of the cat is 2.2m/s², the initial velocity of the cat is 0m/s and the time take the cat takes to come down is 3 seconds.
Now, using equation of motion,
S = Ut + 1/2at²
Where,
U is initial velocity of the body,
t is the time period of the body,
S is the displacement of the body,
a is the acceleration of the body.
Putting all the values,
S = 1/2at²
S = 1/2(2.2)(3)²
S = 9.90 meters.
The distance to which the cat will fall is 9.90 meters.
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a ball is thrown upward with initial velocity of 20 m/s. (a) how long is the ball in the air? (b) what is the greatest height reached by the ball? (c) when is the ball 15 m above the ground?
a) t = 4.08 s
b) Response = 20.39m
c) t = 0.991 and 3.087 seconds.
Initially, the vertical speed was 20 m/s.
(a) how long is the ball in the air?
The ball is tossed upward, rises to its highest point, and then hits the ground again.
Consequently, the end height will be equal to the starting height.
h = h o = Om
Use the equation s= ut + -at.
2764 – An = 14
Put a negative sign for g because the ball is being thrown upwards and g is acting downwards.
Om = t - 0.5 * 9.81 m/s * 20 m/s
0 = 20 *t - 0.5 * 9.81 *t
20 *t=0.5*9.81 *t
20 = 0.5 * 9.81 *t
20 0.5*9.81
Answer (a): t = 4.08 s
(b) what is the greatest height reached by the ball?
Vertical velocity for the ball decreases to zero when it reaches its highest point.
Use the equation 2-u=295
-2ghmas for - u
(20m/s - (Om/s)2) = -2 * 9.81 m/s2 *
02 – 20= -2*9.81 *
-20% = -2 *9.81 *
202 = 2 * 9.81 *
b) RESPONSE: H = 20.39m
(c) when is the ball 15 m above the ground?
The ball will be 15 meters above the earth on two separate occasions.
1. When climbing
2. When descending
Use the equation s= ut + -at.
2,264 – fn = 4
0.5 * 9.81 m/s * 15m = 20 m/s*t
15 = 20 *t - 0.5 * 9.81 *t
15 = 20t – 4.9057
4.905 – 20t + 15 = 0
Calculator-based quadratic equation solution
(c) t = 0.991 and 3.087 seconds.
Hence the answers are,
a) t = 4.08 s
b) RESPONSE: Hmar = 20.39m
c) t = 0.991 and 3.087 seconds.
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A 6 kg object experiences a 5 m/s² acceleration? Find the force that
caused this acceleration.
Answer:
F=ma
F=6kg×5m/s^2
F=30kgm/s^2
F=30newton
does increasing the magnitude of a uniform magnetic field through which a charge is traveling necessarily mean increasing the magnetic force on the charge? does changing the direction of the field necessarily mean a change in the force on the charge?
Since the magnetic force and velocity are orthogonal, the velocity only changes in direction but not in magnitude . Circular motion is the end consequence. The force is in the opposite direction from the right-hand rule and has a negative charge.
Uniform In circular motion, an object moves in two dimensions with a constant speed in a fixed circular direction; however, because the object's direction changes at every point, the velocity also changes, and the direction at each point is always the tangent.
In physics, magnetic force is referred to as an object's maximal size and direction. Both vector and scalar values use magnetic force as a common factor. We understand that by definition
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Answer: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal.
Explanation: The velocity simply changes in direction, not magnitude, as the magnetic force and velocity are orthogonal. The resultant motion is circular. The force has a negative charge and is directed in the opposite direction from the right-hand rule.
Uniform In a circular motion, an item moves in two dimensions with a constant speed in a fixed circular direction; yet, because the object's direction varies at each point, the velocity also alters, and the direction at each point is consistently the tangent.
As an object's maximum size and direction, the magnetic force is referred to in physics. Magnetic force is a factor that is present in both scalar and vector values. We comprehend that by nature.
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1. A bike takes 9.0 seconds to decelerate to a stop over a distance of 30 meters. How fast was the bike traveling before the biker started to decelerate?
Answer:
Starting speed Vo = 6.7 m/s
Explanation:
Given:
t = 9.0 s
S = 30 m
___________
V₀ - ?
The path is numerically equal to the area of the figure lying under the velocity graph:
S = V₀* t / 2
Starting speed:
V₀ = 2*S / t = 2*30 / 9 ≈ 6.7 m/s
In an arena football game, the quarterback throws a pass so that it reaches the top of the stadium at the peak of its flight. If he threw the ball at an angle of 64 degrees and the stadium is 34 meters high, calculate the velocity with which he threw the ball and the distance the ball traveled.
Formulas for projectile motion:
Maximum height of projectile, h = [tex](u sin(\alpha )^{2}[/tex] / 2g
Horizontal range of projectile, R = [tex]u^{2}[/tex] sin(2α) / g
where u is the initial velocity, α is the angle of projection, and g is the acceleration due to gravity.
Given:
Angle of projection, α = 64°
Maximum height of projectile, h = 34 m.
To find: Initial velocity (u), and horizontal distance travelled (R).
Rearrange 'h' equation for 'u',
u sin(α) = [tex]\sqrt{2gh}[/tex]
⇒ u = [tex]\frac{\sqrt{2gh} }{sin(\alpha )}[/tex]
Substitute given values.
⇒ u = [tex]\sqrt{2*(9.8m/s^{2}*34m }[/tex] / sin(64°)
⇒ u = 25.81 / 0.899 m/s
∴ u = 28.71 m/s
This is the velocity with which the ball was thrown.
The distance travelled by the ball can be calculated by using the equation,
R = [tex]u^{2}[/tex] sin(2α) / g
Substitute the given values.
⇒ R = ([tex]28.71^{2}[/tex]× sin (2×64°)) / 9.8
⇒ R = 649.53 / 9.8
∴ R = 66.27 m.
This is the distance travelled by the ball.
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An elevator uses 100 000J of electrical energy to raise a load of 800 N through a height of 40m in a time of 20s. What is the rate of conversion of the electrical energy to other forms?
Therefore:
[tex]P_{out}:P_{in}=\frac{P_{out}}{P_{in}}=\frac{1600W}{5000W}=0.32[/tex]Answer:
1600W
A crate is at rest on an inclined plane. As the slope increases the crate remains at rest until the incline reaches an angle of 32.7° from the horizontal. At this angle the crate begins to slidedown the ramp.Draw a free body diagram of the crate just before it slides
The free body diagram of the crate can be shown as,
Here, N is the normal force acting on crate, mg is the weight of crate, f is the frictional force and theta is the angle of inclination of plane.
jim leaves his house and begins walking to his car in a straight line. he goes 2.0 m then returns to his house to get his keys. next, he leaves his house and travels 6.0 m to his car. what is jim's displacement?
Jim's displacement if Jim leaves his house and begins walking to his car in a straight line and he goes 2.0 m then returns to his house to get his keys, next, he leaves his house and travels 6.0 m to his car is 6 m
Δx = x2 - x1
Δx = Displacement
x2 = Final position
x1 = Initial position
Considering the house as origin,
Final position = 6 m
Initial position = 0
Δx = 6 - 0
Δx = 6 m
Displacement is the vector quantity that describes position change in a motion. Its scalar quantity distance describes the overall distance travelled during the entire motion.
Therefore, Jim's displacement is 6 m
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a winter storm that blows cold wind at least 56 km/hr and has falling or blowing snow that reduces visibility to less than 400 m for at least three hours is classified as a(n) blank . multiple choice question.
Wind speeds of above 56 kilometers per hour (35 miles per hour) are common during blizzards. These winds reduce visibility by causing a lot of snow to blow around in the air and close to the ground.
What is Blizzards?A blizzard is a severe snowstorm that lasts for a long time—typically at least three or four hours—and is marked by strong sustained winds and low visibility. When snow is not falling but rather loose snow on the ground is lifted and blasted by strong winds, the weather is called a "ground blizzard." A blizzard, according to the National Weather Service, is a storm with heavy snowfall or snow that is blowing, winds that are greater than 35 mph (56 kph), and visibility that is less than 14 mile (0.4 km) for at least three hours. There is no snow falling during some blizzards, known as ground blizzards.To learn more about Blizzards refer to:
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Please help meee I really need help on this one. 30 points! And brainliest
a. the amount of work done is __________(equal to, greater than, less than) the amount of energy used
b. power is the rate of __________ (energy use, work done, force)
c. the greater the work done. the _________(equal, greater, smaller) power needed
d. The two factors that affect the amount of work done are _________ and ______________(mass, force, power, length, with, displacement)
choose the correct answer from the parentheses for each sentence
a) The amount of work done is equal to the amount of energy used.
b) Power is the rate of energy use/work done .
c) The greater the work done. The greater the power needed.
d) The two factors that affect the amount of work done are force and displacement .
Energy is the ability to perform work. Work and energy are related in that an increase in work results in an increase in energy, and vice versa. Power is defined as the rate at which work is completed or the amount of work completed per unit of time. Power is also defined as the rate at which energy is supplied to the system.
Power depends mainly on the amount of work done as well as the time taken by the body to perform the work.
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145-g baseball is dropped from a tree 12.0 m above the ground. (a) with what speed would it hit the ground if air resistance could be ignored? (b) if it actually hits the ground with a speed of what is the average force of air resistance exerted on it?
The required speed is 15.35 m/s, if air resistance is ignored.
The magnitude of average force of air resistance is 1.0341N.
a) V = √2gh
The required speed is
V = √2(9.8)(12)
V = 15.35m/s
b) W = 1/2m([tex]v^{2}[/tex]-[tex]u^{2}[/tex])
W = (mg - f)h
( (0.145)(9.8) - f)12 = 1/2(0.145)(([tex]8^{2}[/tex]))
(1.421 - f)12 = 4.64
Force of an air resistance = 1.0341N
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Physics Trajectory question.
I need help finding the answers on Vy.
The vertical component of the velocity after the given interval of time will be:
B: -9.8 m/s
D: -19.6 m/s
F: -29.4 m/s
H: -39.2 m/s
What is a projectile?A projectile can be described as any object upon which the only force is gravity. The projectile travels with a parabolic trajectory because of the influence of gravity. No horizontal forces are acting upon projectiles so there is no horizontal acceleration.
The horizontal velocity of a projectile is constant and the vertical acceleration is caused by gravity. The vertical component of the velocity of a projectile changes by 9.8 m/s each second while the horizontal motion of a projectile is independent of its vertical motion.
Given, the initial horizontal velocity, vₓ = 18 m/s
The initial vertical velocity, Vy = 0 m/s
The time interval = 1 sec
The vertical component of the velocity is calculated as;
[tex]V_y = V_{0y} -gt[/tex]
[tex]V_y = 0- (9.8) (1)\\V_y = -9.8 m/s[/tex]
The vertical component when t = 2 sec and horizontal velocity, Vx = 18 m/s
[tex]V_y = 0- (9.8) (2)\\V_y = -19.6 m/s[/tex]
The vertical component of velocity when t = 3sec:
[tex]V_y = 0- (9.8) (3)\\V_y = -29.4 m/s[/tex]
The vertical component of velocity when t = 4sec:
[tex]V_y = 0- (9.8) (4)\\V_y = -39.2 m/s[/tex]
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Fiber optic cable is available in 12 km lengths. How long will it take for a signal to travel that distance assuming that the speed of light in the cable is the same as in a vacuum?.
The Time it takes a signal to travel the length of the cable of 12 km if the speed of light in the cable and the vacuum are the same is 4×10⁻⁵ s.
What is time?
Time is the measured or measurable period during which an action, process, or condition exists or continues.
To calculate how long it will take a signal to travel a distance the same as the lenght of the cable, we use the formula below.
Formula:
t = d/v.......... Equation 1Where:
t = Time it takes a signal to travel the length of the cabled = Length of the cablev = Speed of the signal/ speed of electromagnetic wave.From the question,
Given:
d = 12 km = 12000 mv = 3×10⁸ m/sSubstitute these values into equation 1
t = 12000/(3×10⁸ m/s)t = 4×10⁻⁵ sHence, the time its takes a signal to travel the length of the cable is 4×10⁻⁵ s.
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