Answer:
91.79 yardsExplanation:
Let the direction of the south be -y
Let the direction of the east be +x
The displacement is gotten by using the pythagoras theorem as shown;
Let d be the displacement;
d² = x² + y²
Given
x = 45 yards
y = -80 yards
Substitute the given values into the expression;
d² = x² + y²
d² = 45² + (-80)²
d² = 2025 + 6400
d² = 8425
d = √8425
d = 91.79 yards
Hence the total displacement of the player is 91.79 yards
a motorbike can travel 1000 meters in 10 minutes calculate how car it can travel in 1 sec.
Answer:
1.67meter
Explanation:
if it can travel 1000 meters in 10 minutes, 10 minutes are 600 secs (10×60), 1000÷600 is 1.67
Answer:
HI
Explanation:
A substance will take on the shape of an open container if it is a
liquid.
plasma.
gas.
solid.
Answer:
liquid
Explanation:
A stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy
Answer:
A
Explanation:
Given that a stone dropped from the top of a 80m high building strikes the ground at 40 m/s after falling for 4 seconds. The stone's potential energy with respect to the ground is equal to its kinetic energy. (use 9 - 10 m/s)
O at the moment of impact
2 seconds after the stone is released after the stone has fallen 40 m
when the stone is moving at 20 m/s
At the top of the hill, the P.E = mgh
P.E = 10 × 80 × m
P.E = 800m
At the moment of impact, K.E = 1/2mv^2
K.E = 1/2 × 40^2 × m
K.E = 1/2 × 1600 × m
K.E = 800m
Since both P.E and K.E are the same, we can therefore conclude that the stone's potential energy with respect to the ground is equal to its kinetic energy at the moment of impact.
The correct answer is option A.
Nore ordered an ice cream cone.
Answer:
okay
Explanation:
okay
Answer:
Cool
Explanation:
What connects the colon to the anus?AColon B Anus C Rectum D Biceps
The answer is C. Rectum.
Answer:
You have a severe case.
Explanation:
My anus smells foul, like poop or diarrhea. Why? Like your anus might be tired of making the same old sensational brown. No fear needed! Anus Maker is here! With this app, you can post poop photos for help if you need! No more foul sensational browns! Start your free Anus Maker trial today!
A girl pushes a wagon at constant velocity. If the
momentum of the wagon is 50 kg*m/s at a
velocity of 2 m/s, the mass of the wagon is what
Bob can run the 100 meter dash in 25 seconds. What is his speed?
Answer:
4 meters a second
Explanation:
100/25
plzz mark brainiest
When momentum is conserved it is called _____. (multiple choice)
A.) Conservation of Momentum
B.) The Law of Momentum
C.) The Physics of Momentum
D.) The Rules of Momentum
Answer:
Based off the word "conserved" I would say
A. Conservation of Momentum.
Explanation:
Answer:
A.) Conservation of Momentum
What two things does force depend on
it takes 5100 N of force to accelerate a ford mustang 3 m/s2 what is the mass of the car
Answer:
1700 kg
Explanation:
The mass of the ford mustang car be 1700 kg.
What is mass?In physics, mass is a quantitative measurement of inertia, a basic characteristic of all matter. It essentially refers to a body of matter's resistance to changing its speed or location in response to the application of a force.
The change caused by an applied force is smaller the more mass a body has. The kilograms serves as the unit of mass in the International System of Units (SI).
Given parameters:
Force applied on the ford mustang car: F = 5100 N.
Acceleration of the ford mustang car: a = 3 m/s^2.
So, The mass of the ford mustang car be = force/acceleration
= 5100/3 kg.
= 1700 kg.
Hence, the mass of the ford mustang car be 1700 kg.
Learn more about mass here:
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#SPJ2
HIII DROPPING COINS YALL
Answer:
tysm
Explanation:
Answer:
OMG THANK U SO MUCH I NEEDED THEMMMMM
Consider an elevator carrying Kermit the frog weighing 4000.0 N is held 5.00 m above a spring with a force constant of 8000.0 N/m. The elevator falls onto the spring while subject to a frictional force (brake) of 1000.0 N. Determine the maximum compression distance, x, of the spring.
Answer:
Maximum compression distance (x) = 2.236 m (Approx)
Explanation:
Given:
Weight of frog = 4,000 N
Height = 5 m
Constant force = 8,000 N/m
Frictional force = 1,000 N
Find:
Maximum compression distance (x)
Computation:
Using Law of conservation;
mgh = 1/2(k)(x)²
4,000(5) = 1/2(8,000)(x)²
Maximum compression distance (x) = 2.236 m (Approx)
What distance does a biker travel if he rides at a constant speed or 22 m/s for 45 seconds?
Answer:
it would be 990 m.
Explanation:
22 m/s x 45 seconds.
I need a little help with this
Answer:
truck 1 has the most velocity
Explanation:
Because it weights less which means it faster and yea
A rose plant inherited two alleles for white flower petals.
Which conclusion is best supported by the given information?
Answer:
a
Explanation:
Answer:
A or each parent had at least one allele for white pedals
Explanation:
What wavelength would a ripple in water have if the frequency is 1.8 Hz and a
wave speed of 825 m/s?
Explanation:
825m/s / 1.8Hz = 458.33m
λ=v/f
λ-wavelength
v-speed
f-frequency
λ=825/1.8=458.33m
A book that weighs 5 N sits on a table. What force does the table apply to the book?
Answer:
E =F.d =[1/2]mv^2
mad = [1/2]mv^2
d= v^2/2a ,v=u+at , v^2 = [at]^2 since u=0
So d = at^2/2
F = ma= 20a= 50 , a=5/2 and t=2
so d = [5/2][2^2]/2=5
Explanation:
Every action has an equal and opposite reaction. It is an action-reaction principle. Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
What is Newton's third law of motion?Newton's third law of motion state that every action has an equal and opposite reaction. It is an action-reaction principle. It stated that the force always exists in a pair.
Therefore the table exerts a force of 5 N on the book in order to be in stable condition.
The given data in the problem is ;
W is the weight of the book sits on table = 5N
N is the normal force on the book
From the equilibrium equation ;
Weight -Normal force on the book =0
Weight =Normal force on the book
The normal force on the book =5N
Hence the table exerts a force of 5 N on the book in order to be in stable condition.
To learn more about Newton's third law of motion refer to the link;
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what is the KE of a 1.00 kg hammer swinging at 20.0 m/s? 200 Joules
I know the answer I just need help understanding it.
Answer:
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 1250 kg
Velocity (v) = 20.0 m/s.
Kinetic energy (K.E) =?
Kinetic energy is simply defined as energy possed by a body in motion. Mathematically, it is expressed as:
K.E = ½mv²
Where:
K.E is the kinetic energy
m is the mass of the object
v is the velocity of the object.
Thus, we can obtain the kinetic energy of the automobile by using the above formula as illustrated below:
Mass (m) = 1250 kg
Velocity (v) = 20.0 m/s.
Kinetic energy (K.E) =?
K.E = ½mv²
K.E = ½ × 1250 × 20²
K.E = 625 × 400
K.E = 250000 J
Therefore, the kinetic energy of the automobile is 250000 J
Circular motion requires the application of a constant force in which direction?
Outward from the circle
Toward the center of the circle
Toward the object in motion
Away from an object
the velocity of a body of mass 60kg reaches 15m/s from 0m/s in 12 second. calculate the kinetic energy and power of the body.
Answer:
KE=1/2m v^2
1/2*60*15*15
30*15*15
6750 joules
power=work/time
Engine 1 produces twice the power of engine 2.
If it takes engine 1 the time T to do the work W, how long does it take engine 2 to do the same work?
Express your answer in terms of some of all of the variables T and W.
T2=________________
Answer:
[tex]T_2=\frac{T}{2}[/tex]
Explanation:
Given that engine 1 produces twice the power of engine 2.
Let [tex]P_1[/tex] and [tex]P_2[/tex] be the power of engine 1 and engine2.
So, the power of the engine 2,
[tex]P_2 = 2P_1\cdots(i)[/tex]
As, Work = Power x time,
So, the work, W, done by an engine 1:
[tex]W=P_1\timesT\cdots(ii)[/tex]
The work, W, done by an engine 2:
[tex]W_2=P_2\times T_2\cdots(iii)[/tex]
If the work done by both the engines are the same, then
[tex]W_2=W[/tex]
[tex]\Rightarrow P_2\times T_2=P_1\timesT[/tex] [from (ii) nd (iii)]
[tex]\Rightarrow 2P_1\times T_2=P_1\timesT[/tex] [by using (i)]
[tex]\Rightarrow 2 T_2=T \\\\\Rightarrow T_2=\frac{T}{2}[/tex]
Hence, [tex]T_2=\frac{T}{2}.[/tex]
The time taken for engine 2 to do the same amount of work is given by:
T₂ = 2TLet the power of the 1st engine be P₁
Let the power of the 2nd engine be P₂
Power = Work / timeFrom the question given above,
Engine 1 produces twice the power of engine 2.
Thus,
P₁ = 2P₂
P₂ = ½P₁
Next, we shall determine the power used by engine 1 to do the work in time T.Work = W
Time (T₁) = T
Power (P₁) =?Power = Work / time
[tex]P_{1} = \frac{W}{T}\\\\[/tex]Finally, we shall determine the time taken for engine 2 to do the same work.Work = W
Power of engine 1 (P₁) = [tex]\frac{W}{T}\\\\[/tex]
Power of engine 2 (P₂) = ½P₁
Power of engine 2 (P₂) = [tex]\frac{1}{2} (\frac{W}{T}) = \frac{W}{2T}[/tex]
Time (T₂) =?[tex]Power = \frac{Work}{time} \\\\ P_{2} = \frac{W}{T_{2}} \\\\\frac{W}{2T} = \frac{W}{T_{2}} \\\\\frac{1}{2T} = \frac{1}{T_{2}}\\\\[/tex]
Invert
T₂ = 2TTherefore, the time taken for engine 2 to do the same amount of work is: T₂ = 2T
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Charles, the 75 kg trampoline artist, lands on a trampoline with a speed of 9.0 m/s.
If the trampoline behaves like a spring with a spring constant of 52,000 N/m, what maximum distance will Charles push down the trampoline before bouncing back up? (Hint: at maximum compression, Charles is not moving.)
Answer:
The maximum distance Charles will push down the trampoline ≈ 0.342 m
Explanation:
The given parameters are;
The mass of the trampoline artist, m = 75 kg
The speed with which the trampoline artist lands, v = 9.0 m/s
The value of the spring constant of the trampoline, k = 52,000 N/m
Let x represents the maximum distance Charles will push down the trampoline
Therefore, we have;
Kinetic energy = 1/2·m·v²
The kinetic energy with which the trampoline artist lands = 1/2 × 75 × 9.0² = 3037.5
The kinetic energy with which the trampoline artist lands = 3037.5 J
The potential energy stored in a spring = 1/2·k·x² = The kinetic energy with which the trampoline artist lands
∴ 1/2 × 52,000 × x² = 3037.5
∴ x = √(3037.5/(1/2 × 52,000)) ≈ 0.342
The maximum distance Charles will push down the trampoline = x ≈ 0.342 m
A car travels 14 km due west, then does a
U-turn, and travels 43 km due west.
I. What total distance has the car
traveled?
II.
What is the total displacement of the
car?
III. If the entire trip took 3.20 hours.
determine the average speed of the
car. Give
your answer in both
km hour, and m s. (show
conversion)
IV. If the entire trip took 2.50 hours.
determine the average velocity of
the car. Give your answer in both
km h, and mph (show conversion)
Explanation:
It is given that,
A car travels 14 km due west, then does a U-turn and travels 43 km due east (when it takes U-turn, it will change direction from west to east)
i. Total distance = total path covered
= 14 km + 43 km
= 57 km
ii. Let east is positive and west is negative.
Displacement = final position-initial position
= 43-14
= 29 km
iii. If time taken in the entire trip = 3.2 hours
Average speed = distance/time
[tex]s=\dfrac{57\ km}{3.2\ h}\\\\=17.81\ km/h[/tex]
1 km/h = 0.2777 m/s
17.81 km/h = 4.94 m/s
iv. If time taken in the entire trip = 2.5 hours
Average velocity = displacement/time
[tex]v=\dfrac{29\ km}{2.5\ h}\\\\=11.6\ km/h[/tex]
1 km/h = 0.621 mph
11.6 km/h = 7.2 mph
Henc, this is the required solution.
deducing the acceleration = deduce the gradient of velocity-time graphs
true or false?
Answer:
True
Explanation:
Understanding the relationship between change in velocity with time will explain to you how the object is accelerating or decelerating. This means acceleration is a ratio calculated from the change in velocity of an object and change in time. In a velocity time graph, the y-axis represents the velocity and the x-axis represents the time.
The slope of the graph m = Δ y-axis values/Δ x-axis values
m= Δvelocity / Δ time
m= Δ v / Δ t ------this the definition of acceleration so;
a= Δ v / Δ t
Conclusion : The slope/gradient of a velocity -time graph is acceleration.
An example of a poor coping mechanism is ?
Answer: A bad, maladaptive, unhealthy or destructive coping mechanism is one where the behavior does not resolve the problem in the long-term and may actually increase the harm. Unhealthy coping strategies may feel like they are having the desired effect in the short term.
Explanation: Yes, it was from google...
What is the work energy transfer equation?
Answer:
The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)
Answer:
The equation used to calculate the work done is: work done = force × distance. W = F × d. This is when: work done (W) is measured in joules (J)
Explanation:
The net work done on a particle equals the change in the particle's kinetic energy:
HELP ASAP Which statement is true about magnetic field lines?
A. There is no consistent pattern in the lines, B. The lines form a loop from the north pole back to the north pole and from the south pole to the south pole. C. The lines point away from the south pole of a magnet and toward the north pole. D. The lines point away from the north pole of a magnet and toward the south pole.
Answer:
i think it's c
Explanation:
but I'm not sure
Answer:
The answer is D
Explanation:
5. Describe the relationship between the buoyant force and the weight of an object if the object:
a) is floating
b) is sinking
c) is rising up through the water.
A) the state of deep mental and physical therapy or relaxation
B) falling or moving to a lower level
C) up to owns kness
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10s. If the airplane is putting out an average force of 5.8810x10^4 N during this time, what is the average friction force exerted on the airplane by the air?
Given :
A 2450 kg stunt airplane accelerates from 120 m/s to 162 m/s in 2.10 s.
If the airplane is putting out an average force of [tex]5.8810\times 10^4 \ N[/tex].
To Find :
The average friction force exerted on the airplane by the air.
Solution :
Acceleration is given by :
[tex]a = \dfrac{162-120}{2.10}\ m/s^2\\\\a = 20 \ m/s^2[/tex]
Now, force equation is given by :
[tex]F - F_{friction} = ma\\\\F_{friction} = F-ma\\\\F_{friction} = 58810 - (2450\times 20 )\\\\F_{friction} = 9810\ N[/tex]
Therefore, frictional force exerted in the airplane by the air is 9810 N.
Please help! Will mark brainliest!
Answer:
im pretty sure its d
Explanation: