Answer:
Son's age (y) = 14 years
Step-by-step explanation:
According to the question,
Father's age = 42 years
Son's age = y years
Difference between father's & son's age is 28 years. i.e.
Father's age - son's age = 28
42 - y = 28
42 - 28 = y
y = 42 - 28
y = 14
What is the value of 10 1
10
10x1=10
Hope this helps
What interest will be earned if $11,000.00 is invested for 3 years at 11% compounded semi-annual?You would earn $ in interest. (Round to 2 decimal places.)
Answer:
$4,167.27
Explanation:
The amount, A(n) in an account for a Principal invested at compound interest is calculated using the formula:
[tex]\begin{gathered} A(n)=P(1+\frac{r}{k})^{nk}\text{ }where=\begin{cases}P=Prin\text{cipal} \\ r=\text{Annual Interest Rate} \\ k=\text{Compounding Period}\end{cases} \\ n=nu\text{mber of years} \end{gathered}[/tex]In the given problem:
• P = $11,000.00
,• r=11% = 0.11
,• n= 3 years
,• k=2 (semi-annual)
Substitute these into the formula:
[tex]\begin{gathered} A(n)=11,000(1+\frac{0.11}{2})^{2\times3} \\ =11,000(1+0.055)^6 \\ =11,000(1.055)^6 \\ =\$15,167.27 \end{gathered}[/tex]Next, we find the interest earned.
[tex]\begin{gathered} \text{Interest}=\text{Amount}-\text{Prncipal} \\ =15167.27-11000 \\ =\$4,167.27 \end{gathered}[/tex]You would earn $4,167.27 in interest (rounded to 2 decimal places).
Carolina wants to find out how many different ways can she arrange the apps on her Iphone on the first row. The first row has space for 4 apps, and she has 12 apps to choose from
ANSWER
495 ways
EXPLANATION
Carolina has 12 apps to choose from and she only has space for 4 apps.
To find out how many ways she can do it, we will need to use combination.
That is:
[tex]^{12}C_4[/tex]Note: we use combination because the order of the apps is not a factor
So, we have that:
[tex]\begin{gathered} ^{12}C_4\text{ = }\frac{12!}{(12\text{ - 4)! 4!}}\text{ = }\frac{12!}{8!\text{ 4!}} \\ =\text{ 495 ways} \end{gathered}[/tex]She can arrange them in 495 ways.
Question 2 (2 points)Find the value of x. If needed, round your answer to the nearest tenth.50°X5Not drawn to scaleX =
Solution
Find the value of x in the triangle shown below:
Calculate the value of x
Opposite = 5
adjacet = x
[tex]tan\theta=\frac{opp}{adj}[/tex][tex]\begin{gathered} tan50=\frac{5}{x} \\ x=\frac{5}{tan50} \\ x=\frac{5}{1.19175} \\ x=4.1955 \\ x=4.2\text{ \lparen nearest tenth\rparen} \end{gathered}[/tex]Therefore the correct value of x = 4.2
I have 4 questions I need help with This is first question number 2
We have the next function that models the Australian GDP since 1960 :
[tex]G(i)=1806x(1.037)^t[/tex]Where t is the number of years since 1960.
a)If we are in the year 1960, it means t=0
Therefore:
[tex]G(t)=1806x(1.037)^1[/tex][tex]G(0)=1806x(1.037)^0[/tex][tex]G(0)=1806[/tex]b)Now, we need to find the Australia capita in 1963.
This means t=3
Therefore:
[tex]G(t)=1806x(1.037)^t[/tex][tex]G(3)=1806x(1.037)^3[/tex][tex]G(3)=2013.974721[/tex]c) We need to find when the function is equal to 100,000.
Therefore we equal the function G(t)=100,000.
Then:
[tex]1806x(1.037)^t=1000000[/tex]Solve for t:
Divide both sides by 1806:
[tex]\frac{1806x(1.037)^t}{1806}=\frac{100000}{1806}[/tex][tex](1.037)^t=\frac{50000}{903}[/tex]Add Ln for each side:
[tex]\ln (1.037)^t=in(\frac{50000}{903})[/tex][tex]t\ln (1.037)=in(\frac{50000}{903})[/tex]Then:
[tex]t=\frac{in(\frac{50000}{903})}{\ln (1.037)}[/tex][tex]t=110.48286[/tex]Rounded to the nearest year:
[tex]t=110[/tex]Therefore: 1960 +110 = 2070
On 2070 the Austranlian GDP reaches 100,000 USD
Which of the following is NOT an equation?1. 5(2x+1)=10x+52. 4x-13. 5+3=104. x/2+1=7
By definition, an equation is a statement that two mathematical expressions are equal.
Equations always contain the equal sign "="
Out of the 4 expressions listed, number 2. does not contain the equal sign, which means that this expression is not an equation.
All other expressions contain the equal sign, they can be considered equations.
A sample has a sample proportion of 0.3. Which sample size will produce the widest 95% confidence interval when estimating the population parameter?A. 36B. 56C. 68D. 46
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
sample proportion = 0.3
widest 95% confidence interval
sample = ?
Step 02:
p = 0.3
1 - α = 0.95 =>> z α/2 = 1.96
We must check each value to find the solution.
A. sample = 36
[tex]\begin{gathered} 0.3-1.96\cdot\sqrt[]{\frac{0.3\cdot0.7}{36}}=0.3-0.1499 \\ 0.3+1.96\cdot\sqrt[]{\frac{0.3\cdot0.7}{36}}=0.3+0.1499 \end{gathered}[/tex]confidence interval (0.1501 , 0.4499)
difference = 0.2998
B. sample = 56
[tex]\begin{gathered} 0.3-1.96\cdot\sqrt[]{\frac{0.3\cdot0.7}{56}}=0.3\text{ - }0.120 \\ 0.3+1.96\cdot\sqrt[]{\frac{0.3\cdot0.7}{56}}=\text{ 0.3 + }0.120 \end{gathered}[/tex]confidence interval (0.18 , 0.42)
difference = 0.24
Analyzing these two values, we can conclude that the widest confidence interval will be for the smallest sample.
The answer is:
Sample = 36
Find the x-intercept and y-intercept of the line.
5x-9y=-12
The x and y intercepts of the line is found as (12/5, 0) and (0, -4/3) respectively.
What is termed as the x and y intercepts?An intercept is a y-axis point that the slope of a line passes. It is the y-coordinate of the a point on the y-axis where a straight line or even a curve intersects. This is represented by the equation for a straight line, y = mx+c, where m is the slope and c seems to be the y-intercept. There are two types of intercepts: x-intercept and y-intercept.For the given question,
The equation of the line is 5x-9y=-12.
For the x intercept, Put y = 0.
5x-9×0=-12.
x = 12/5
x intercept = (12/5, 0)
For y intercept, put x = 0.
5×0-9y=-12
y = -12/9
y = -4/3
y intercept = (0, -4/3)
Thus, the x and y intercepts of the line is found as (12/5, 0) and (0, -4/3) respectively.
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Newton's Second Law, F=m.a, describes the relationship between an object's mass, a force acting on it, and the resulting acceleration, where: F is force, in Newtons m is mass, in kilograms a is acceleration, in meters per second squared A young boy and his tricycle have a combined mass of 30 kilograms. If the boy's sister gives him a push with a force of 60 Newtons, what is his acceleration? 1 2 meter per second squared 2 meters per second squared 30 meters per second squared 90 meters per second squared
Newton's Second Law, F=m.a, describes the relationship between an object's mass, a force acting on it, and the resulting acceleration, where: F is force, in Newtons m is mass, in kilograms a is acceleration, in meters per second squared A young boy and his tricycle have a combined mass of 30 kilograms. If the boy's sister gives him a push with a force of 60 Newtons, what is his acceleration? 1 2 meter per second squared 2 meters per second squared 30 meters per second squared 90 meters per second squared
we have that
F=m*a
we have
m=30 kg
F=60 N
substitute in the formula
60=30*a
solve for a
a=60/30
a=2 m/s^2
therefore
the answer is 2 meters per second squaredWhich equation is set up for direct use of the zero-factor property? A. 3x2 - 19x - 14 = 0 C.X2 + x = 42 B. (7x + 9)2 = 3 D. (3x - 2)(- 2) = 0
Explanation:
The zero-factor property states that if ab=0, then either a = 0 or b = 0 (or both). A product of factors is zero if and only if one or more factors is zero.
From these options only B and D have factors, but B equals to 3. In D we have that (3x-2) = 0 or the other factor is zero (or both)
Answer:
The correct answer is option D
A $40,000 is placed in a scholarship fund that earns an annual interest rate of 4.25% compounded daily find the value in dollars of the account after 2 years assume years have 365 days round your answer to the nearest cent
SOLUTION
From the question, we want to find the value in dollars of the account after 2 years.
We will usethe formula
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ Where\text{ A = value of the account, amount in dollars = ?} \\ P=principal\text{ money invested = 40,000 dollars } \\ r=annual\text{ interest rate = 4.25\% = }\frac{4.25}{100}=0.0425 \\ n=number\text{ of times compounded = daily = 365} \\ t=time\text{ in years = 2 years } \end{gathered}[/tex]Applying this, we have
[tex]\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ A=40,000(1+\frac{0.0425}{365})^{365\times2} \\ A=40,000(1.000116438)^{730} \\ A=40,000\times1.0887116 \\ A=43,548.467179 \\ A=43,548.47\text{ dollars } \end{gathered}[/tex]Hence the answer is 43,548.47 to the nearest cent
Mr. Herman had $125, and Mr.Chandra had $80. After each of them had paid for a concert ticket, Mr. Herman had 6 times as much money as Mr. Chandra. how much money did Mr. Chandra have left?
We have
Let x = cost of the ticket
After paying for the tickets, Mr. Herman had 125 - x
and Mr Chandra had 80 - x
Then, the equation is:
[tex]125-x=6(80-x)[/tex]So, solve for x:
[tex]\begin{gathered} 125-x=480-6x \\ 125-x+6x=480-6x+6x \\ 125+5x=480 \\ 125+5x-125=480-125 \\ 5x=355 \\ \frac{5x}{5}=\frac{355}{5} \\ x=71 \end{gathered}[/tex]The concert ticket cost is $71
Therefore, Mr. Chandra have left:
[tex]80-71=9[/tex]Answer: $9
I don’t understand how to explain this question
The segments cannot be set equal since the constant terms 15 is greater than two. The variable x remains like a constant term in both sides of the point B. we say that 15x > 2x
What is inequality?In mathematics, the signs used inequality calculations are
greater thanless thangreater than or equal toless than or equal toUsing the picture as evidence the mark represented by B is not the midpoint hence the equality sign will not be used here. The sign to be used is the inequality sign.
In addition, the constants 15 and 2 shows that 15 is greater than 2. and there is no other addition to the variable x to help check the effect of the greatness of 15
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If the correlation coefficient r is equal to 0.755, find the coefficient of determination and the coefficient of nondetermination.Question 10 options: The coefficient of determination is 0.430 and the coefficient of nondetermination is 0.570 The coefficient of determination is 0.869 and the coefficient of nondetermination is 0.131 The coefficient of determination is 0.570 and the coefficient of nondetermination is 0.430 The coefficient of determination is 0.131 and the coefficient of nondetermination is 0.869
Given the word problem, we can deduce the following information:
The correlation coefficient r is equal to 0.755.
To determine the coefficient of determination and the coefficient of nondetermination, we use the formulas below:
[tex]Coefficient\text{ }of\text{ }Determination=r^2[/tex][tex]Coefficient\text{ }of\text{ N}ondetermination=1-r^2[/tex]Now, we first plug in r=0.755 to get the coefficient of determination:
[tex]Coeff\imaginaryI c\imaginaryI ent\text{ o}f\text{ D}eterm\imaginaryI nat\imaginaryI on=r^2=(0.755)^2=0.57[/tex]Next, we get the coefficient of nondetermination:
[tex]\begin{gathered} Coeff\imaginaryI c\imaginaryI ent\text{ o}f\text{ N}ondeterm\imaginaryI nat\imaginaryI on=1-r^2=1-0.57=0.43 \\ \end{gathered}[/tex]Therefore, the answer is:
The coefficient of determination is 0.570 and the coefficient of nondetermination is 0.430
25. Brett wants to sound proof his studio, which is in the shape of a box. He will cover all 4 walls, the floor and the ceiling with the sound proof padding material. If the floor's dimensions are 15ft x 20ft and the height of the room is 10ft tall, how much will Brett spend on padding that costs $2.50 per square foot?
We have that the floor's dimensions are 15ft x 20ft and the height of the room is 10ft tall. This is
if we extended it we would have:
We want to find how many square foot Brett needs to cover. We just find the area of each side of the studio.
We find it just by multiplying both of its sides (they all are rectangles):
Wall 1
area = 10ft x 15 ft
area = 150 ft²
Wall 2
area = 10ft x 20 ft
area = 200 ft²
Wall 3
area = 10ft x 15 ft
area = 150 ft²
Wall 4
area = 10ft x 20 ft
area = 200 ft²
Floor
area = 15ft x 20 ft
area = 300 ft²
Ceiling
area = 15ft x 20 ft
area = 300 ft²
A condensed way....
TOTAL AREA
Now, we add all the areas found, this will be the total area Brett must cover:
Wall 1 + wall 2 + Wall 3 + Wall 4 + ceiling + floor = total area
150 ft² + 200 ft² + 150 ft² + 200 ft² + 300 ft² + 300 ft² = 1300 ft²
COST
Since the padding costs $2.50 per square foot, and there are 1300 square foot to cover. Brett will spend
$2.50 x 1300 = $3250
Answer: Brett spend on padding $3250
Solve p3 = −512.
p = ±8
p = −8
p = ±23
p = −23
Answer:
B. p = −8
Step-by-step explanation:
Hope this helps you on whatever your doing. :))
if its incorrect, please let me know.
The solution is, the value is, p = −8.
What is multiplication?In mathematics, multiplication is a method of finding the product of two or more numbers. It is one of the basic arithmetic operations, that we use in everyday life.
here, we have,
given that,
p^3 = −512.
so, we know, p^3 = p*p*p
and, 512 = 8*8*8
now, we get,
p^3 = - 8*8*8
so, solving we get,
p = -8
Hence, The solution is, the value is, p = −8.
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The rate of growth of a particular population is given by dP/dt=50t^2-100t^3/2, where P is population size and t is fine and years. Assume the initial population is 25,000. a) determine the population function, P(t)b) estimate to the nearest year how long it will take for the population to reach 50,000
SOLUTION
Step1: write out the giving equation
[tex]\frac{dp}{dt}=50t^2-100t^{\frac{3}{2}}[/tex]Step2: Integrate both sides of the equation above
[tex]\int \frac{dp}{dt}=\int 50t^2dt-\int 100t^{\frac{3}{2}}dt[/tex]Then simplify by integrating both sides
[tex]p(t)=\frac{50t^{2+1}}{2+1}-\frac{100t^{\frac{3}{2}+1}}{\frac{3}{2}+1}+c[/tex][tex]p(t)=\frac{50}{3}t^3-40t^{\frac{5}{2}}+c[/tex]since the initial value is 25,000, then
the Population function is
[tex]\begin{gathered} p(t)=\frac{50}{3}t^3-40t^{\frac{5}{2}}+25000\ldots\ldots..\ldots\text{.. is the population function} \\ \text{where t=time in years} \end{gathered}[/tex]b). For the population to reach 50,000 the time will be
[tex]\begin{gathered} 50000=\frac{50}{3}t^3-40t^{\frac{5}{2}}+2500 \\ 50000-25000=\frac{50}{3}t^3-40t^{\frac{5}{2}} \\ 25000=\frac{50}{3}t^3-40t^{\frac{5}{2}} \\ \text{Then} \\ \frac{50}{3}t^3-40t^{\frac{5}{2}}-25000=0 \\ \end{gathered}[/tex]Multiply the equation by 3, we have
[tex]\begin{gathered} 50t^3-120t^{\frac{5}{2}}-75000=0 \\ \end{gathered}[/tex]To solve this we rewrite the function as
[tex]14400t^5=\mleft(-50t^3+75000\mright)^2[/tex]The value of t becomes
[tex]\begin{gathered} t\approx\: 15.628,\: t\approx\: 9.443 \\ t=15.625\text{ satisfy the equation above } \end{gathered}[/tex]Then it will take approximately
[tex]16\text{years}[/tex]
PLEASEEEE HELPPPPAdd. 3+(-7)=
The problem is asking as to perform an addition of signed numbers.
The firs one to add is 3 and the other one is -7.
We can understand the meaning of this type of addition by using the number line forst, and then have a very simple "short cut" every time we fce problems like this.
The number line approach:
locate yourself at the mark "3" on the number line, and then add the number "-7" whichmeans go to the left (as the negative indicates) 7 units. You will see that you move through zero, and then land on the number "-4".
Solve the quadratic equation using any algebraic method.
X²-11x+30=0
Answer:
5, 6
Step-by-step explanation:
using Vieta's formulas:
x₁ + x₂ = 11
x₁*x₂ = 30
x₁ = 5
x₂ = 6
I need help A. -3 B. 3 C. -2D. -10
The average rate of change can be calculated as the division of the output of the function on the interest interval by the size of the interval. To do that we have to find the value of "y" at the end of the interval and subtract it by the value of "y" at the beggining. This is shown as an expression below:
[tex]\text{average rate of change=}\frac{y_{\text{ final}}-y_{\text{ initial}}}{x_{\text{ final}}-x_{\text{ initial}}}[/tex]For this function the values of x are:
[tex]\begin{gathered} x_{\text{ initial}}=0 \\ x_{\text{ initial}}=3 \end{gathered}[/tex]The values for y are:
[tex]\begin{gathered} y_{\text{ initial}}=10 \\ y_{\text{ final}}=1 \end{gathered}[/tex]Using these values we can calculate the average rate of change:
[tex]\text{average rate of change=}\frac{1-10}{3-0}=\frac{-9}{3}=-3[/tex]The average rate of change for this function is approximately -3 for the given interval. The correct answer is A.
NO LINKS!! Please help me with this probability question
Answer: B) 46.67% approximately
=================================================
Work Shown:
A = it will be cloudy tomorrow
B = it will be rainy tomorrow
P(A) = 0.30
P(B) = 0.15
P(A and B) = 0.14
Apply the conditional probability formula.
P(B given A) = P(A and B)/P(A)
P(B given A) = 0.14/0.30
P(B given A) = 0.4667 approximately
P(B given A) = 46.67% approximately
Answer:
b) About 46.67%.
Step-by-step explanation:
Let event A = being cloudy.
Let even B = being rainy.
Given probabilities:
Probability of being cloudy = 30%.Probability of being rainy = 15%.Probability of being cloudy and rainy = 14%.Therefore:
P(A) = 0.3P(B) = 0.15P(A ∩ B) = 0.14Conditional Probability Formula
[tex]\sf P(B|A)=\dfrac{P(A \cap B)}{P(A)}[/tex]
The probability of being rainy given it is cloudy = P(B | A).
Substitute the given values into the formula:
[tex]\implies \sf P(B|A)=\dfrac{0.14}{0.3}=0.46666...=46.67\%\;(2\;d.p.)[/tex]
Therefore, the probability of it being rainy if you know it will be cloudy is about 46.67%.
Not sure how to approach this question whether to use the factor theorem or to use the synthetic division
EXPLANATION
If x+2 is a factor, we need to equal the factor to zero, isolate x and substitute the value into the function:
[tex]x+2=0\text{ --> x=-2}[/tex]Plugging in x=-2 into the function:
[tex]P(-2)=(-2)^4-2(-2)^2+3m(-2)+64[/tex]Computing the powers:
[tex]P(-2)=16-2*4-6m+64[/tex]Multiplying numbers:
[tex]P(-2)=16-8-6m+64[/tex]Adding numbers:
[tex]P(-2)=72-6m=0[/tex]Adding +6m to both sides:
[tex]72=6m[/tex]Dividing both sides by 6:
[tex]\frac{72}{6}=m[/tex]Simplifying:
[tex]12=m[/tex]In conclusion, the value of m is 12
I
Three relationships are described below:
I. The amount of time needed to mow a yard increases as the size of the yard increases.
II. The amount of timeneeded to drive from city A to city B decreases as the speed you are driving increases.
III. The income of a worker who gets paid an hourly wage increases as the number of hours worked increases and
increases as the salary rate increases.
What type of variation describes each relationship?
The type of variation that describes each relationship include the following:
Direct variation: the amount of time needed to mow a yard increases as the size of the yard increases.Indirect variation: the amount of time needed to drive from city A to city B decreases as the speed you are driving increases.Joint variation: the income of a worker who gets paid an hourly wage increases as the number of hours worked increases and increases as the salary rate increases.What is an indirect variation?An indirect variation simply refers to a type of proportional relationship in which a variable is inversely proportional to another variable. This ultimately implies that, an indirect variation represents two variables that are inversely proportional to each other, which means as one variable increases, the other variable decreases and vice-versa.
What is direct variation?Direct variation refers to a type of proportional relationship in which a variable is directly proportional to another variable. This ultimately implies that, a direct variation represents two variables that are directly proportional to each other, which means as one variable increases, the other variable also increases and vice-versa.
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STATEMENTREASON1. DBC - RST1. Given2. ZABC - ZDBC+ ABD2. Angle addition therom3.3. Ifa=b+cand c>0,thena > b4. ABC > RST4. SubstitutionWhich of the following statements would complete the proof in line 3?O ZABC> ZABDO LABC> DBCO ZDBC> ZABD
Answer
Option B is correct.
Angle ABC > Angle DBC
Explanation
Since it's been proven that
Angle ABC = Angle ABD + Angle DBC
Since Angle ABD > 0,
Angle ABC > Angle DBC is the part that completes the proof that
Angle ABC > Angle RST
Hope this Helps!!!
A dwarf seahorse swims 3/4 inch in a minute. How many minutes would take the seahorse to swim 1/3 inch?
A. 1/3 divided by 3/4= 4/9
B. 1/3 times 3/4= 1/4
C. 3/4 divided by 1/3= 9/4
D. 3/4 + 1/3= 13/12
Answer:
A
Step-by-step explanation:
we have 3/4 in / minute.
so, we divide this by 3/4 to get the time for 1 inch.
and then we multiply by 1/3 to get the time for 1/3 inch.
that combination, dividing by 3/4 and multiplying by 1/3, can be done in any sequence (commutative property of multiplication).
therefore, this can be expressed as 1/3 divided by 3/4. and A is the correct answer.
How do you solve this?
Answer: I thought you already asked this question.
Step-by-step explanation:
Look at this graph: у 10 9 8 7 6 5 3 2 1 0 1 2 3 4 5 6 7 8 9 10 What is the slope?
EXPLANATION
As we can see in the graph, we can calculate the slope with the following equation:
[tex]\text{Slope}=\frac{(y_2-y_1)}{(x_2-x_1)}[/tex]Let's consider any ordered pair, as (x1,y1)=(1,7) and (x2,y2)=(5,8), replacing this in the equation will give us:
[tex]\text{Slope}=\frac{(8-7)_{}}{(5-1)}=\frac{1}{4}[/tex]Answer: the slope is equal to 1/4.
The triangles formed by two ladders leaning against a wall are similar. How long is the shorter ladder?
To solve this problem we must use proportions
[tex]\begin{gathered} \text{ }\frac{x}{8}\text{ = }\frac{42}{24} \\ \text{ x = }\frac{8\text{ x 42}}{24} \\ \text{ x = }\frac{336}{24} \\ \text{ x = 14} \end{gathered}[/tex]The length of the shortest ladder is 14.
letter B is the correct answer.
Enter the correct answeach column.5. Bellatrix Lestrange keeps her money in GringottsWizarding Bank. She decided to take $100,000out of her vault and split it among three differentaccounts. She placed part in a savings accountpaying 3% per year, twice as much in Wizard bondspaying 5.5%, and the rest in a mutual fund thatreturned 4%. Her income from these investmentsafter one year was $4,480. How much did Bellatrixplace in each account?11223334.44HOW MUCH DID BELLATRIX PLACE IN THEMUTUAL FUND?556670N (0088
Assum,e that she put x in the account of 3%
So in wizard bonds, she put twice so it is 2x
The rest in the account of 4%
The rest is 100,000 - x - 2x = 100,000 - 3x
The rule of the investment is :
[tex]I=\text{prt}[/tex]I is the interest, P is the money she invested, r is the rate and t is the time
We will make equation for each account
[tex]\begin{gathered} I_1=x(\frac{3}{100})(1)=0.03x_{} \\ I_2=(2x)(\frac{5.5}{100})(1)=0.11x \end{gathered}[/tex][tex]I_3=(100,000-3x)(\frac{4}{100})(1)=4000-0.12x[/tex]The sum of the interest is 4,480, so add them and equate the sum by 4,480 to find the value of x
0.03x + 0.11x + 4000 - 0.12x = 4,480
Add like terms in the left side
0.02x + 4000 = 4,480
Subtract 4000 from both sides
0.02x + 4000 - 4000 = 4,480 - 4000
0.02x = 480
Divide both sides by 0.02
x = 24,000
The value in the mutual fund is 100,000 - 3x, so substitute s by 24,000
The mutual fund = 100,000 - 3(24,000) = 100,000 - 72,000 = 28,000
The mutual fund = $28,000
Find the length of the missing side of the triangle using the Pythagorean theorem. (Type an integer or decimal rounded to the nearest tenth as needed.)
Pythagorean theorem
[tex]\begin{gathered} a^2=b^2+c^2,\text{ where a is the hypotenuse} \\ a^2=(6.5)^2+(4.9)^2 \\ a^2=42.25+24.01 \\ a^2=66.26 \\ a=\sqrt[]{66.26}=8.1^{\prime} \end{gathered}[/tex](Type an integer or decimal rounded to the nearest tenth as needed.)
Integer = 8'
decimal rounded to the nearest tenth as needed = 8.1'