A direct current of 3.0 A flows through a circuit consisting of a battery and a 6.0 A resistor. Calculate the potential difference across the resistor. a​

Answers

Answer 1

Question :-

A Direct Current of 3.0 A flows through a Circuit consisting of a Battery and a 6.0 Ohm's Resistor. Calculate the Potential Difference across the Resistor .

Answer :-

Potential Difference is 18 Volt's .

Explanation :-

As per the provided information in the given question, we have been given that the Current of the Device is 3.0 Ampere . The Resistance is given as 6.0 Ohm's . And, we have been asked to calculate the Potential Difference .

As we know ,

V = I R

Where ,

V denotes to Potential DifferenceI denotes to CurrentR denotes to Resistance

Therefore , by Substituting the given values in the above Formula :-

[tex] \sf {\dag \: \: \: Potential \: Difference \: = \: Current \: \times \: Resistance} [/tex]

[tex] \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3.0 \: \times \: 6.0} [/tex]

[tex] \sf {\Longrightarrow \: \: \: \sf Potential \: Difference \: = \: 3 \: \times \: 6} [/tex]

[tex] \bf {\Longrightarrow \: \: \: \bf {Potential \: Difference \: = \: 18 \: }} [/tex]

Hence :-

Potential Difference = 18 Volt's .

[tex] \underline {\rule {210pt}{4pt}} [/tex]

Additional Information :-

[tex] \Longrightarrow \: \: \: \sf {Voltage \: = \: Current \: \times \: Resistance} [/tex]

[tex]\Longrightarrow \: \: \: \sf {Current \: = \: \dfrac {Voltage}{Resistance} } [/tex]

[tex]\Longrightarrow \: \: \: \sf {Resistance \: = \: \dfrac {Voltage}{Current} } [/tex]

[tex] \underline {\rule {210pt}{4pt}} [/tex]

Note :-

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Related Questions

Using the model above, which letter represents the position of the earth when the northern hemisphere is experiencing the shortest hours of daylight
A

B

C

D

Answers

Answer:

At position "B" the northern hemisphere is tilted the most from the earth-sun direction and will experience the shortest hours of daylight, (and also the most indirect sun rays).

The main environmental effects of ozone depletion could include all of the following except

Answers

The main environmental effects of ozone depletion could include the following:

higher risk of skin cancersunburnsquick ageingweakend immune system

What is ozone depletion?

Ozone depletion is the gradual thinning of the ozone layer in the upper atmosphere as a result of the relelase of chemical compounds or gases.

Ozone layer helps prevent the Earth surface against incoming ultraviolet radiations that could cause damage to our environment.

Therefore, the main environmental effects of ozone depletion could include the following:

higher risk of skin cancersunburnsquick ageingweakend immune system

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The following are some of the primary environmental implications of ozone depletion and increased risk of skin cancer, sunburns, rapid aging, and the immune system being weakened.

What is ozone depletion, and how does it happen?

The progressive weakening of the ozone layer in the upper atmosphere as a result of the release of chemical compounds or gases is known as ozone depletion.

The ozone layer protects the Earth's surface from harmful UV rays that may harm our environment. As a result, the primary environmental effects of ozone depletion could include:

1. An increased risk of skin cancer

2. Sunburns

3. Rapid aging

4. The immune system is weakened.

Hence increased risk of skin cancer is the main environmental effect of ozone depletion.

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Cars enter a car wash at a mean rate of 33 cars per half an hour. What is the probability that, in any hour, exactly 22 cars will enter the car wash? round your answer to four decimal places

Answers

Answer:Cars enter a car wash at a mean rate of 4 cars per half an hour. 

Explanation:

The probability that, in any hour, exactly 22 cars will enter the car wash will be 0.0920.

What is probability?

Probability means possibility. It deals with the occurrence of a random event. The value of probability can only be from 0 to 1.

Its basic meaning is something is likely to happen. It is the ratio of the favorable event to the total number of events.

The  mean rate of car is,[tex]\rm \lambda = 66 \ car/hour[/tex]

[tex]P(x=K) = \frac{8^k e^{-8}}{k\!}\\\\P(x=22) = \frac{66^{22} e^{-22}}{22\!}\\\\ P(x=22)=\frac{0.000000000000691\times 1.07\times 10^{40}}{22} \\\\\ P(x=22)=0[/tex]

Hence the probability that, in any hour, exactly 22 cars will enter the car wash will be 0

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10. A ball is attached to a string of length 4 m to make a pendulum. The pendulum is placed at a location that is away from the Earth’s surface by twice the radius of the Earth. What is the acceleration due to gravity at that height and what is the period of the oscillations?

Please show all of your work.

Answers

Let's see

Radius of earth=6371mTwice of it=6371(2)=12742m

[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi \sqrt{\dfrac{4}{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=2\pi\dfrac{2}{\sqrt{g}}[/tex]

[tex]\\ \rm\rightarrowtail T=\dfrac{4\pi}{\sqrt{g}}[/tex]

So

[tex]\\ \rm\rightarrowtail g=\dfrac{16\pi ^2}{T^2}[/tex]

Answer:

g' = 1.09 m/s²

T = 12 s

Explanation:

Gravity due to acceleration

Distance from center of Earth = r + 2r = 3rgravity due to acceleration on surface, g = GM/r²Substitute 3r in the denominatorg' = GM/(3r)² = GM/9r²⇒ g' = g/9 = 9.8/9 = 1.09 m/s²

Time period

T = 2π√L/g'T = 2π√4/1.09T ≅ 12 s

The presence of which magnetic feature best explains why a magnet can act at a distance on other magnets or on objects containing certain metals? fields dipoles domains forces

Answers

The orientation with the largest magnetic torque on the dipole is Orientation B (See attached image).

What is Magnetic Torque?

The torque on the dipole is defined as:

τ = µ×B,

where B is the external magnetic field.

The magnitude of this torque is µB sinθ, where θ is the angle between B and µ

Magnetic Torque is highest when;

→     →

µ ⊥ β

That is when θ  = 90°. Hence B is the correct answer. Please see attached image.

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Answer:

b

Explanation:

A 23. 6 g ball of clay is thrown horizontally to the right at 40. 4 m/s toward a 1. 70 kg block sitting at rest on a frictionless surface. The clay hits and sticks to the block.


What is the speed of the block and clay right after the collision?


Answer in m/s to three significant figures

Answers

Answer:

0.142 m/s

Explanation:

You solve it by conservation of momentum.

Before the impact the total momentum is, considering right the positive direction,

[tex]m_1v_1+m_2v_2 =6\cdot10^-^3\times 40.4\ kg\cdot m/s + 1.7\times 0 \ kg\cdot m/s =242.4\cdot 10^-^3\ kg\cdot m/s[/tex]

After the impact, we have a single body of mass [tex]m_1+m_2[/tex] and thus a single value of speed, V.

[tex](m_1+m_2)V =1.703 kg \cdot V[/tex]

Since no external forces are applied, the two quantities are equal after the impact. That allows us to solve for V

[tex]V= (242.4\cdot10^-^3 \ kg\cdot m/s )\div (1.703\ kg)=142.337\cdot10^-^3 m/s = 0.142 m/s[/tex]

Gwen runs back and forth along a straight track. During the time interval 0≤t≤45 seconds, gwen’s velocity, in feet per second, is modeled by the function v given by v(t)=250sin(t2120)t 6

Answers

Gwen's position is a function of his velocity and time

Gwen's position at 45 seconds is 63.9 feet

How to determine Gwen's position at 45 seconds?

The function is given as:

v(t) = 250sin(t^2/120)/(t + 6)

When t = 45, we  have:

v(45) = 250sin(45^2/120)/(45 + 6)

Evaluate the sum, the exponent and the quotient

v(45) = 250sin(16.875)/(51)

Evaluate the sine ratio

v(45) = 250 * 0.2903/51

Evaluate the product and quotient

v(45) = 1.42

The position is then calculated as:

S(45) = v(45) * 45

This gives

S(45) = 1.42 * 45

Evaluate the product

S(45) = 63.9

Hence, Gwen's position at 45 seconds is 63.9 feet

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The displacement is the shortest between any two given points. The displacement of Gwen at the time period of 45 seconds is 63.9 feet.

What is displacement?

The displacement is the shortest between any two given points. It is the product of velocity and time.

Given that the function of the velocity is [tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]. Therefore, substitute the value of t as 45, to know the velocity of Gwen at 45 seconds,

[tex]v(t)=\dfrac{250\sin\left(\frac{t^{2}}{120}\right)}{\left(t+6\right)}[/tex]

[tex]v(45)=\dfrac{250\sin\left(\frac{45^{2}}{120}\right)}{\left(45+6\right)}\\\\v(45) = 1.42[/tex]

Since displacement is the product of velocity and time, therefore, the displacement is equal to,

[tex]s = v \times t\\\\s = 1.42 \times 45\\\\s = 63.9\rm \ feet[/tex]

Hence, the displacement of Gwen at the time period of 45 seconds is 63.9 feet.

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Explain why electromagnetic forces are essential to forming compounds.

Answers

Explanation:

formation of compounds because the electric forces compel the atoms to attract each other and formed bonds which leads to the formation of chemical compounds. The attractive or repulsive interaction between any two charged bodies is known as an electric force so the attraction between two opposite charged atoms causes the formation of compounds so we can conclude that electric forces are important for the formation of compounds.

1 point
8. A magnetic field of 30 T is directed perpendicular to the force of a coil
with an area of 0.36 m^2. Calculate the magnetic flux in the coil.

A)0.27 Wb
B)9.3 Wb
C)10.8 Wb
D)83.3 Wb

Answers

Answer:

the answer is. C.

Explanation:

[tex] 0.36 \times 30 = 10.8[/tex]

the solution

A photon with wavelength 11. 0 nm is absorbed when an electron in a three-dimensional cubical box makes a transition from the ground state to the second excited state

Answers

For a photon with wavelength 11. 0 nm,  the side length LL of the box is mathematically given as

L=1.414*10^{-27}m

What is the side length LL of the box?

Generally, the equation for the change in energy is mathematically given as

[tex]dE=\frac{hc}{\lambda}[/tex]

Therefore

[tex]\frac{hc}{\lambda}=\frac{6h^2}{8ml}\\\\L=\sqrt{6h\lambda}{8mc}\\\\L=\sqrt{\frac{6(6.626*10^{-34})*11.0*10^{-9}}{8(9.11*10^31)(3*10^8)}}[/tex]

L=1.414*10^{-27}m

In conclusion,  the side length LL of the box is

L=1.414*10^{-27}m

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The side length of the box for a photon of wavelength 11. 0 nm will be [tex]\rm L = 1.414 \times 10^{-27}[/tex] m.

What is wavelength?

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The change in the energy of the photon is found as;

[tex]\rm dE = \frac{hc}{\lambda} \\\\ \frac{hc}{\lambda} =\frac{6h^2}{8ml} \\\\ L= \sqrt{\frac{6h\lambda}{8mc} } \\\\ L = \sqrt{\frac{6 \times 6.626 \times 10^{-34}\times 11 \times 10^{-9}}{8 \times 9.11 \times 10^{31} \times 3 \times10^8} } \\\\ L= 1.414 \times 10^{-27} \ m[/tex]

Hence  the side length of the box for a photon of wavelength 11. 0 nm will be [tex]\rm L = 1.414 \times 10^{-27}[/tex] m.

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Calculate the volume of 500 kilograms
to 2 decimal places
flead if the density of lead is 11400 kg/m². Give your answer
Enter your answer to 2 decimal places

Answers

Answer:

d (density) = M / V

V = M / d = 500 kg / (11400 kg / m^2 = .044 m^3

My Noacid performs a physics lab to determine the speed of sound inside a tube. She blocks off one end of the 120. 0 cm tube with a book and places a microphone at the other end. When she snaps her finger she determines the time for the sound to get back to the microphone is. 00695 s. What was the speed of sound that day

Answers

The speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.

Speed of the sound

The speed of the sound wave can be determined by applying echo formula as shown below;

v = 2d/t

where;

d is the distance traveled by the sound wave = 120 cm = 1.2 mt is the time when the sound wave was heard = 0.00695 s

Substitute the given parameters and solve for speed.

v = (2 x 1.2)/(0.00695

v = 345.32 m/s

Thus, the speed of sound inside a tube when she snapped her finger is determined as 345.32 m/s.

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define one meter lendth​

Answers

Explanation:

The metre is currently defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second.

Hope it helps

Have a great day

TC

:DD

I have an answer but I'm not it sure about it. I just need someone to help confirm it. Thanks​

Answers

Answer:

0.40s. He's dead, Jim.

Explanation:

The block accelerates at a rate of [tex]9.81 ms^-^2[/tex]. The moment it's 14 meters from the ground, it has traveled 39 meters, in about [tex]39=\frac12(9.81)t^2 \rightarrow 2.82 s[/tex].

For the man to dodge, the time left is the distance the block takes to go down to 2 meters from ground, or 51 meters from its starting point. Which translates in [tex]51=\frac12(9.81)t^2\rightarrow 3.22s[/tex]

He has thus less than half a second ([tex]0.40s[/tex] to be exact) to dodge.

A student states, "The wave model is better than the particle model for electromagnetic radiation because it is easier to understand." Is the student's statement a scientific claim?(1 point)

Yes, it is because simpler scientific models are better.

No, it isn't because the particle model is better than the wave model.

No, it isn't because the statement is an opinion.

Yes, it is because there is ample proof that wave models are easier.

Answers

The student's claim did not follow the scientific method of discovery, hence, it is an opinion not a scientific claim.

What is the scientific method?

The scientific method is a procedure employed by scientific towards understanding the world around them as well giving explanation for phenomena in the natural world.

The scientific method involves:

observations asking questions putting forward a hypothesis testing the hypothesis through experiments analyzing results of the experiments and drawing conclusions establishing a theory.

Since the student in question just put forward an opinion without testing it out using the scientific method, the statement is not a scientific claim.

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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0. Consider the moment when the current is 2. 50 a

Answers

For a  flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω, the rate of energy being delivered is mathematically given as

P= 53 W

What rate is energy being delivered by the battery?

Generally, the equation for the Battery power  is mathematically given as

P = I (dt)V

Therefore

P= 2.50 A * 21.2V

P= 53 W

In conclusion, rate of energy being delivered

P= 53 W

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A flat coil of wire has an inductance of 40. 0 mh and a resistance of 6. 00 ω. It is connected to a 21. 2-v battery at the instant t = 0.The power developed will be 53 Watt.

What is electric power?

Electric power is the product of the voltage and current. Its unit is the watt. It is the rate of the electric work done.

The given data in the problem is;

V is the voltage = 21.2 volt (V)

I is the electric current = 2.50 ampere (A)

The formula for the power is given as;

[tex]\rm P= V I \\\\\ P= 2.50 \times 21.2 \\\\ P=53 \ watt[/tex]

Hence electric power developed will be 53 Watts.

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Emma wants to drive forward in her car. What does she need to do other than place her vehicle's gear in Drive and accelerate

Answers

She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate

How we drive a car?

We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.

So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.

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write comparison between Electrical Circuit and Magnetic Circuit.

[tex] \\ \\ \\ \\ \\ \\ \\ [/tex]


Thanks¡!¡:)​

Answers

Magnetic circuit, closed path to which a magnetic field, represented as lines of magnetic flux, is confined.

In contrast to an electric circuit through which electric charge flows, nothing actually flows in a magnetic circuit.

Explanation:

Hope it helps you (`▿▿▿▿´ƪ)

A 120 N accelerates an object 1. 2 m/s? What is the mass of the object?

Answers

Answer:

m = 100 kg

Explanation:

F = ma

120 = m × 1.2

m = 120 ÷ 1.2

m = 100 kg

Photoelectrons are emitted from the surface of a metal when light shines on it. If the wavelength of the light is decreased

Answers

Answer:

what are your answer choices if you have any?

Explanation:

(my ask question thingy isnt working)

why is the freezing compartment kept at top in a refrigerator?

Answers

Answer:

Because Geography says the higher one goes the colder it gets

Answer:

The nature of convection.

Explanation:

Warm air rises; cold air falls, so the freezer at the top provides cold air for the other compartments at the bottom.

Calculate the mass (in g) of 346 cm³ of polythene. The density of polythene is 0.95 g/cm³. Give your answer to 2 decimal places.

Answers

Answer:

M = 328.70g

Explanation:

From the given values:

V = 346 cm³

M of 1 cm³ of Polythene = 0.95g or 95/100g

Solve:

M = (95×346)

10

= 32870

100

M = 328.70g

Which Tesla would win in a drag race?

(A) 2009 Tesla Roadster

(B) 2016 Tesla Model X

Answers

B 2016 tesla model x

Answer:B

Explanation:  

A has about 248 hp  but B has about 683 hp. 2016 is younger too. good day

Question 1(Multiple Choice Worth 2 points)
(04.05 LC)
The number of protons plus the number of neutrons in an atom is equal to its
O atomic number
O mass number
O nuclear model
O energy level
Question 2 Multiple Choice Worth 2 points)

Answers

Answer: Mass Number

Explanation:

Atomic number is the number of just protons;

Nuclear Model is a theoretical description of what an atom looks like;

Energy levels are the energy states that electrons are in;

However, mass number is by definition the number of protons + number of neutrons. :)

The rotational inertia of a sphere of mass m and radius r about a diameter is 25mr2. The rotational inertia about an axis tangent to the sphere is

Answers

The rotational inertia about an axis tangent to the sphere of the given mass and radius is ⁷/₅MR².

Parallel axis theorem

According to parallel axis theorem, the moment of inertia of a body about any axis is equal to the sum of the product of its mass and the square of the distance between the two parallel axis and the moment of inertia of the body about a parallel axis passing through its centre of mass.

The moment of inertia of the sphere about its parallel axis passing through its centre of mass = ²/₅MR²

The product of its mass and the square of the distance between the two parallel axis = MR²

Rotational inertia about an axis tangent to the sphere

Moment of inertia about an axis tangent to the sphere = MR² + ²/₅MR²

                                                                                           = ⁷/₅MR²

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The rotational inertia of a sphere of given mass and radius along a tangent axis is [tex]\rm \frac{7}{5} MR^2[/tex].

What is a moment of inertia?

The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.

The given data in the problem is;

M is the sphere's mass.

R is the radius of a sphere

According to the parallel axis theorem,The rotational inertia of a sphere of given mass and radius along a tangent axis is found as;

[tex]\rm I=MR^2+\frac{2}{5} MR^2 \\\\ I=\frac{7}{5} MR^2[/tex]

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At what constant velocity must a spacecraft travel from earth if it is to reach the star in 3. 7 years, as measured by travelers on the spacecraft?

Answers

The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

Given data :

Distance of star from earth = 4.3 light years

Observers time = 3.7 years

Determine the constant velocity the spacecraft must travel

Observers time = 3.7 * 365 * 24 * 60 * 60

Distance of star from earth = 4.3 * 9.46 * 10¹⁵

The velocity the spacecraft must travel will be calculated using the equation

V = distance / time

   = ( 4.3 * 9.46 * 10¹⁵ ) / ( 3.7 * 365 * 24 * 60 * 60 )

   = 3.49 * 10⁸ m/s

Hence we can conclude that The constant velocity that the spacecraft must travel is : 3.49 * 10⁸ m/s

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Attached below is the missing detail related to the question

The constant velocity must the spacecraft travels from the earth will be 3.49×10⁸ m/sec.

What is velocity?

The change of distance with respect to time is defined as speed. Speed is a scalar quantity. It is a time-based component. Its unit is m/sec.

The given data in the problem is

Distance of earth from stars = 4.3 light year

The given time = 3.7 year

One year converted into the second as;

[tex]\rm 1 \ year = 3.7 \times 365 \ days \ \times 24 \ hour \times 60 \ minute \times 60 \ sec \\\\ 1 year = 116 \times 10^6 \ sec[/tex]

1 light-year into a kilometer as;

[tex]\rm 4.3 \ light year = 4.3 \times 9.46 \times 10^{15 metre} \\\\[/tex]

At what constant velocity must a spacecraft travel from the earth if it is to reach the star in 3. 7 years,

The velocity of the spacecraft's travel from the earth will be;

[tex]\rm V = \frac{d}{t} \\\\ V= \frac{4.3 \times 9.46 \times 10^{15}}{3.7 \times 365 \times 24 \times 60 \times 60 } \\\\\ V= 3.49 \times 10^8 \ m/sec[/tex]

Hence the constant velocity must the spacecraft travels from the earth will be  3.49×10⁸ m/sec.

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A wave oscillates 4.0 times a second and has a wavelength of 3.0 m.
What are the (a) frequency, (b) period, and (c) speed of this wave?

Answers

a) The frequency of the wave is 4.0 Hz

b) The period T of the wave is 0.25s

c) The speed of the wave is 12m/s

Given the data in the question;

Number of oscillation per seconds = 4.0Wavelength; [tex]\lambda = 3.0m[/tex]Frequency; [tex]f = \ ?[/tex]Period; [tex]T = \ ?[/tex]Speed of the wave; [tex]v = \ ?[/tex]

Frequency, Period and speed.

Frequency is simply the number of occurrences of a repeating phenomenon per unit time.

Period is the time needed for a complete cycle of vibration to pass a given point.

It is expressed as;

[tex]T = \frac{1}{f}[/tex]

Where f is the frequency

Speed is simply the distance traveled in a given interval of time or time ratio.

It is expressed as;

[tex]v = \lambda * f[/tex]

Where [tex]\lambda[/tex] is wavelength and f is frequency

a) Frequency

We said frequency is the number of occurrences of a repeating phenomenon per unit time.

Since the wave oscillates 4.0 times a second

Hence, the frequency of the wave is 4.0 Hz

b) Period

[tex]Period\ T = \frac{1}{f} \\\\Period\ T = \frac{1}{4.0Hz}\\\\Period\ T = \frac{1}{4.0s^{-1}}\\\\Period\ T = 0.25s[/tex]

Therefore, the period T of the wave is 0.25s

c) Speed

[tex]v = \lambda * f\\\\v = 3.0m * 4.0Hz\\\\v = 3.0m * 4.0s^{-1}\\\\v = 12ms^{-1}\\\\v = 12m/s[/tex]

Therefore the speed of the wave is 12m/s.

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To predict whether a star will ultimately become a black hole, what is the key property of the star we should look at?.

Answers

A star will ultimately become a black hole when it collapses due to end of fuel.

Which star becomes a black hole?

When a star burns through the last of its fuel, the object may collapse, or fall into itself. For smaller stars which are about three times the sun's mass, the new core will become a white dwarf but when a larger star collapses, it turns into a black hole.

So we can can conclude that a star will ultimately become a black hole when it collapses due to end of fuel.

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A particular lightbulb is designed to consume 40 W when operating on a car's 12-V DC electric power. If you supply that bulb with 12-V AC power from a transformer, how much power will it consume

Answers

40V because it will provide the same amount of power.

The wavelengths of visible light vary from about 300 nm to 700 nm. what is the range of frequencies of visible light in a vacuum?

a) 90 hz to 210 hz
b) 9*10^10 hz to 2.1*10 hz
c) 4.28*10^5 hz to 1*10^6 hz
d) 4.29*10^14 hz to 1*10^15 hz

Answers

The range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.

Frequency of the visible light

The frequency of the visible light is determined  by using the following formulas relating speed of light and frequency of light.

c = fλ

where;

c is speed of lightf is frequency of lightλ is the wavelength

Frequency of light at 300 nm wavelength

f = c/λ

f = (3 x 10⁸) / (300 x 10⁻⁹)

f = 1 x 10¹⁵ Hz

Frequency of light at 700 nm wavelength

f = c/λ

f = (3 x 10⁸) / (700 x 10⁻⁹)

f = 4.29 x 10¹⁴ Hz

Thus, the range of frequencies of visible light in a vacuum with wavelength between 300 nm to 700 nm is determined as 4.29 x 10¹⁴ Hz to 1 x 10¹⁵ Hz.

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