Answer:
the answer is 9.321 miles
It takes Evelyn, traveling at 36 mph, 20 minutes longer to go a certain distance than it takes Sarah traveling at 60 mph. Find the distance
traveled.
The distance travelled by both Evelyn and Sarah is 30 miles.
Given,
The speed travelled by Evelyn = 30 mph
Time taken by Evelyn to cover a distance = 20 minutes
Speed travelled by Sarah = 60 mph
We have to find the distance travelled by both of them.
Speed = distance / time
Then,
Distance = speed x time
Lets take x as the distance.
Then,
36 × (x + 20) = 60x
36x + 720 = 60x
60x - 36x = 720
24x = 720
x = 720/24
x = 30
That is,
The distance travelled by both Evelyn and Sarah is 30 miles.
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Question 5 of 40Roxanne likes to fish. She estimates that 30% of the fish shecatches are trout, 20% are bass, and 10% are perch. Shedesigns a simulation.
30% are trout, 20% are bass, 10% are perch
what is the chance that one of the next 4 is a bass
20% are bass
100 - 20 = 80
0.8^4 = 0.4096
1 - 0.4096 = 0.5904
of the 20 simulation results, 12 had bass
12/20 = 0.6
B) 60% estimate
59.04% actual
The ratio of 1.2 to 32 is equal to the ratio of 3.6 to____.
Answer:
96
Step-by-step explanation:
let the number be x then
1.2x=32
x=80/3
again
3.6x
3.6×80/3
96
a package of 8 count AA batteries costs 6.40 a package of 20 count AA batteries costs 15.80 which statement about the unit price is true?the 20 count pack of AA batreries has a lower unit price of 0.80 per batterythe 8 count pack of AA batteries has a lower unit price 0.79 per batterythe 8 count pack of AA batteries has a low unit price of .80 per batterythe 20 count pack of AA batteries has a lower unit price of .79 per battery
Notice that for the $6.40 package each battery costs:
[tex]\frac{6.40}{8}=0.80.[/tex]For the $15.80 package each battery costs:
[tex]\frac{15.80}{20}=0.79.[/tex]Therefore, the 20 count pack of AA batteries has a lower unit price of $0.79 per battery.
Answer: Last option.
the area of a triangular wedge is 90 square inches the height is 18in what is the base
it is given that,
the height of the wedge is h = 18 in
the area of the wedge is A = 90 square in.
we know that the area of a triangle is
A = 1/2 x base x height
put values,
90 = 1/2 x base x 18
90/18 = 1/2 x base
5 = 1/2 x base
base = 5 x 2
base = 10 inches,
thus, the base of the wedge is 10 inches,
Suppose the population of a certain city is 5700 thousand. It is expected to decrease to 4823 thousand in 50 years. Find the percent decrease.Around to the nearest tenth
We can calculate a percent change by calculating the difference between the actual state and the previous state and then dividing this difference by the previuos state.
Finally, multypling by 100% gives the percentage change.
Here we have the last state as the future population (4823 thousand people). The actual state (in this case the state to which wew want to compare the variation ir change) is 5700 thousand people.
The difference is 4823 - 5700 = -877.
Then, we can divide it by the actual population and we will have:
[tex]\frac{4823-5700}{5700}=\frac{-877}{5700}\approx0.1538[/tex]This is equivalent to:
[tex]01538\cdot100\%=15.38\%[/tex]If we have to round to nearest tenth, the percent change is 15.4%.
Review The measure of m
in the given image
m it is given that m
120 = 3x - 5 + 2x
120 = 5x - 5
5x = 120 + 5
x = 125/5
x = 25
so the value of x is 25
So, mm
m = 3 (25) - 5
= 75 - 5
mso, m
the, sum of the angles
so,
120 + mmm
24. A rocket is launched into the air. Its height in feet, after x seconds, is given by the equation The starting height of the rocket is h(x)=-16x’ +300x + 20 The maximum height is The rocket hits the ground after seconds.
Well we just need to do the analise of the function h, so for the first question we need to know what is the value of h when x=0, so if we evaluate we see that
[tex]h(0)=-16(0)^2+300(0)^{}+20^{}=20^{}[/tex]So the first answer is that the start heigth of the rocket is 20.
Now for the second we need to do the derivate and see the critical ponit to know the maximum, we are going to calculate first the derivate, so
[tex]h^{\prime}(x)=-32x^{}+300[/tex]now we need to find the critical ponits so for this, we are going to see when h'(x) = 0, this meand when the derivate is equal to zero, so h'(x) = 0 when
[tex]\begin{gathered} -32x\text{ + 300 =0} \\ 300\text{ = 32x} \\ \frac{300}{32}=x \end{gathered}[/tex]to see if this critical poni is a maximum we need to calculate the secon derivate and see that the second derivate valued in 300/32 is smaller than 0, so
[tex]h^{\doubleprime}(x)\text{ = -32}[/tex]now when x= 300/32 we have that h''(x) is -32 because the second derivate is constant, in this case h''(300/32) < 0, because of this the answer is that 300/32 is the maximum, bur 300/32 = 75/8.
Now for the third question, we need to see the roots of h, so we need to see when h is zero, so for wich values of x we have that h(x) = 0, then
[tex]-16x^2+300x+20=0^{}[/tex]we can solve this with the quadratic equation to solve this kind of equations. This equation is
so we have that
[tex]\begin{gathered} x\text{ = }\frac{-300\text{ }\pm\sqrt[]{300^2\text{ -4(-16)20}}}{2(-16)} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{90000\text{ + 1280}}}{-32} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{91280}}{-32} \end{gathered}[/tex]the answer is x = (-300 - v/ 91280)/(-32) or x = (-300 + v/ 91280)/(-32) and this is equal to x = (300 + v/ 91280)/(32) or x = (300 - v/ 91280)/(32) if you prefer. We can also write the answer in a simpler way: x = (75 + v/ 5705)/(8) or x = (75 - v/ 5705)/(8), this is
[tex]x\text{ = }\frac{75\text{ }\pm\sqrt[]{5705}}{8}[/tex]Well we just need to do the analise of the function h, so for the first question we need to know what is the value of h when x=0, so if we evaluate we see that
[tex]h(0)=-16(0)^2+300(0)^{}+20^{}=20^{}[/tex]So the first answer is that the start heigth of the rocket is 20.
Now for the second we need to do the derivate and see the critical ponit to know the maximum, we are going to calculate first the derivate, so
[tex]h^{\prime}(x)=-32x^{}+300[/tex]now we need to find the critical ponits so for this, we are going to see when h'(x) = 0, this meand when the derivate is equal to zero, so h'(x) = 0 when
[tex]\begin{gathered} -32x\text{ + 300 =0} \\ 300\text{ = 32x} \\ \frac{300}{32}=x \end{gathered}[/tex]to see if this critical poni is a maximum we need to calculate the secon derivate and see that the second derivate valued in 300/32 is smaller than 0, so
[tex]h^{\doubleprime}(x)\text{ = -32}[/tex]now when x= 300/32 we have that h''(x) is -32 because the second derivate is constant, in this case h''(300/32) < 0, because of this the answer is that 300/32 is the maximum, bur 300/32 = 75/8.
Now for the third question, we need to see the roots of h, so we need to see when h is zero, so for wich values of x we have that h(x) = 0, then
[tex]-16x^2+300x+20=0^{}[/tex]we can solve this with the quadratic equation to solve this kind of equations. This equation is
so we have that
[tex]\begin{gathered} x\text{ = }\frac{-300\text{ }\pm\sqrt[]{300^2\text{ -4(-16)20}}}{2(-16)} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{90000\text{ + 1280}}}{-32} \\ x\text{ = }\frac{-300\text{ }\pm\sqrt[]{91280}}{-32} \end{gathered}[/tex]the answer is x = (-300 - v/ 91280)/(-32) or x = (-300 + v/ 91280)/(-32) and this is equal to x = (300 + v/ 91280)/(32) or x = (300 - v/ 91280)/(32) if you prefer. We can also write the answer in a simpler way: x = (75 + v/ 5705)/(8) or x = (75 - v/ 5705)/(8), this is
[tex]x\text{ = }\frac{75\text{ }\pm\sqrt[]{5705}}{8}[/tex]The denominator of a fraction is five more than twice the numerator if both the numerator and the denominator are decreased by three the simplified result is 1/4 find the original fraction
Answer:
7/19
Step-by-step explanation: we could get two equations from the question if we set the denominator as x and the numerator as y:
1: x=2y+5
2:(y-3)/(x-3)=1/4
cross multiply
4(y-3)=1(x-3)
4y-12=x-3
x=4y-9
3: Then we can choose one of them and minus by another one
x-x=4y-2y-(9+5)
0=2y-14
2y=14
y=7
Then we only have to plug in
x=2*7+5
x=14+5
x=19
Which value of w makes 6W + 7 = 12 true
6W + 7 = 12
to solve this, just isolate W
[tex]\begin{gathered} 6W+7=12 \\ \text{substract 7 in both sides} \\ 6W+7-7=12-7 \\ 6W=5 \\ divide\text{ each side by 6} \\ \frac{6W}{6}=\frac{5}{6} \\ W=\frac{5}{6} \end{gathered}[/tex]so, the answer is w=5/6
A cubic function has turning points at (-1,2) and (1,-2). Which could be its graph?
ANSWER
Graph D is the correct option
EXPLANATION
The turning points of a function are the points where its derivative changes sign - therefore the slope of the function changes sign. In other words, the turning points are the local maximums and local minimums of the function.
From these options, the one that has a local maximum/minimum at point (-1, 2) and another at point (1, -2) is option D.
tristan asked his coworkers about how much time they spent commuting each morning Find the median
SOLUTION
In a box and whisker plot, the firt dot on the box is Q1
The second dot on the box is Q2
The third dot on the box is Q3
Q2 is the median
From what we see,
[tex]Q2=25[/tex]Hence the answer is 25, option D
1. Input, X 9753 1 Output, y 1 2 2 3 4 Function - Yes or no
before we can dtermone whether it is a function, there must be a relationship between X and y i.e they must have a constannt of proportionality as shown:
From the table:
when x = 9, y = 1
when x = 7, y = 2
when x = 5, y = 2
when x = 3, y = 3
when x = 1, y = 4
let us determine the constant of proportionality from the given values as shown:
k = y2-y1/x2-x1
when x = 9, y = 1
when x = 7, y = 2
k = 2-1/7-9
k = 1/-2
k = -1/2
Also
when x = 5, y = 2
when x = 3, y = 3
k = 3-2/3-5
k = 1/-2
k = -1/2
Also;
when x = 5, y = 2
when x = 3, y = 3
k = 3-2/3-5
k = 1/-2
k = -1/2
Since all the constant of proportionality are the same;
Hence y = kx
y = -1/2 x
This shows that the tabke is a function and X is directly proportional to y. hence the answer is YES, it is function
Sarah took the advertising department from her company on a round trip to meet with a potential client. Including Sarah a total of 10 people took the trip. She was able to purchase coach tickets for $240 and first class tickets for $1040. She used her total budget for airfare for the trip, which was $4000
. How many first class tickets did she buy? How many coach tickets did she buy?
Sarah bought 8 first class tickets and she buy 2 coach ticket .
In the question ,
it is given that
total number of people including Sarah = 10 people .
let the number of first class ticket = f
let the number of coach tickets = c
So , the equation is f + c = 10
f = 10 - c
the cost for first class tickets = $240
the cost for "f" first class tickets = 240f
the cost for coach tickets = $1040
the cost for "c" coach tickets = 1040c
total budget is $4000 .
So , the equation is 240f + 1040c = 4000
On substituting f = 10 - c , we get
240(10 - c) + 1040c = 4000
2400 - 240c + 1040c = 4000
1040c - 240c = 4000 - 2400
800c = 1600
c = 1600/800
c = 2
and f = 10 - 2 = 8 .
Therefore , Sarah but 8 first class tickets and she buy 2 coach ticket .
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Write the first 4 terms of the sequence defined by the given rule. f(n)=n^3-1
copy and complete each problem
/20 = 11/55
Answer:
[tex]\frac{4}{20}[/tex] = [tex]\frac{11}{55}[/tex]
Step-by-step explanation:
[tex]\frac{x}{20}[/tex] = [tex]\frac{11}{55}[/tex] cross multiply and solve for x
55x = 11(22)
55x = 220 Divide both sides by 55
x = 4
Gary has read 30 pages of his book. Each day he wants to read 15 pages until he finishes the book which has a total of 180 pages. Write an equation to represent the situation
ANSWER
30 + 15x = 180
EXPLANATION
We have that Gary has read 30 pages of his book.
He wants to read 15 pages every day till he finishes the 180 pages.
Let the number of days it will take him be x.
This means that after reading 15 pages for x days, he will have read:
15 * x = 15x
Therefore, the total number of pages he will have read (180) will be:
30 + 15x = 180
That is the equation that represents the situation.
Which situation represents a proportional relationship?
O Renting a movie for $2 per day
O Renting a movie for $2 per day with a coupon for $0.50 off for the first day
O Renting a movie for $2 per day along with paying a $5 membership fee
O Renting a movie for $2 for the first day and $1 for each day after the first day
The option D that is "Renting a movie for $2 for the first day and $1 for each day after the first day" shows a proportional relationship as they are in proper ratio.
What is proportional relationship?Relationships between two variables that are proportional occur when their ratios are equal. Another way to consider them is that in a proportional relationship, one variable is consistently equal to the other's constant value. The "constant of proportionality" is the name of this constant.
What is ratio?A ratio in mathematics demonstrates how many times one number is present in another. For instance, if a bowl of fruit contains eight oranges and six lemons, the ratio of oranges to lemons is eight to six. The ratio of oranges to the total amount of fruit is 8:14, and the ratio of lemons to oranges is 6:8.
As they are in the right ratio, option D, "Renting a movie for $2 for the first day and $1 for each day after the first day," demonstrates a proportional relationship.
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There are two points (-7,6) and (7,2) the upper part is a shaded circle the ordered pairs that are solutions to the inequality on the graph.This is the line -- - - - - - - -- - -- - - - - - - -- - - - - - --- - - - - - -You can use DESMOS(6,3)(-6,6)(5,0)(2,4)
SOLUTION
Incomplete question
the output is 9 less than 5 times the input"
Let the output is y and the input is x, then
output is means y =
9 less than 5 times input means 9 less than 5x
Then
y = 5x - 9
What is the equation for this? I don't understand which piece of information is irrelevant.
It is given that she produce print of her photos at a cost of 4 dollar per print and a setup cost of 45 dollar per run.
Let the number of photos produced be x.
Then the equation formed is
[tex]C(x)=4x+45[/tex]The sellling cost given is the unnecessary data given in the question.
The total cost is determined by only the setup cost and cost produce per prints.
The graph formed for the total cost and number of photos produced is
X-axis represent the number of photos produced and Y-axis represent the total cost.
Johnny is going to use ASA to prove that VWX=YZX.Which of these is a necessary step in Johnny's proof? A. Prove that WX= XZby CPCTC.B. Prove that VW=YZ by CPCTC.C. Prove that VWX=YZX by alternate interior angles.D. Prove that VXW = YXZ by vertical angles.
In order to prove that two triangles are congruent using the ASA theorem, it is necessary to show two pairs of congruent angles and one pair of congruent sides of the triangles.
In the given diagram, there is already a pair of congruent triangles and a pair of congruent sides shown.
Then, in order to use the ASA theorem, we need to prove that there is another pair of congruent angles, one from each triangle.
Since the side VX must be adjacent to both angles involved in the procedure, then we need to show that the angle VXW is congruent to the angle YXZ, which is adjacent to the side YX.
This can be proven using the fact that VXW and YXZ are vertical angles.
Therefore, the necessary step in Johnny's proof is shown in option D)
[tex]\text{Prove that }\angle VXW\cong\angle YXZ\text{ by vertical angles}[/tex]Solve F(x) for the given domain. Include all of your work in your final answer. Submit your solution.
F(x) = x2 + 3x - 2
F(a) =
For a given function f(x) = x² + 3x - 2, f(a) is a² + 3a - 2 and f(x - 1) = x² + x - 4
Given,
The function f(x) = x² + 3x - 2
We have to find f(a) and domain f(x - 1)
Here,
f(x) = x² + 3x - 2
Then,
f(a) = a² + 3a - 2
Now,
f(x - 1) = (x - 1)² + 3(x - 1) - 2
f(x - 1) = x² - 2x + 1 + 3x - 3 - 2
f(x - 1) = x² + x - 4
That is,
For a given function f(x) = x² + 3x - 2, f(a) is a² + 3a - 2 and f(x - 1) = x² + x - 4
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The parent function y = |x| is reflected across the x-axis to obtain ________________.y = -|x|y = -|x + 1|y = |-x|y = -|x + 5|
The given function is:
[tex]y=|x|[/tex]It is reflected across the x-axis to obtain a new function. This transformation follows the rule:
[tex]g(x)=-f(x)\rightarrow reflection\text{ }across\text{ }x-axis[/tex]If we apply this rule, we obtain:
[tex]y=-|x|[/tex]The answer is y=-|x|
you’re making desert, but your recipe needs adjustment. your oatmeal cookie recipe makes 2 dozen cookies, but you need 3 cookies. If the recipe requires 1 and 1/3 cups of sugar, 3/4 teaspoon of salt, and 1 and 1/4 cups of raisins, how much of each of these ingredients are for 3 dozen cookies? simply your answer
we know that
For 2 dozen cookies
we need
1 1/3 cups of sugar
3/4 teaspoon of salt
1 1/4 cups of raisins
To convert 2 dozens to 3 dozens------> multiply by 3/2
but first convert mixed number to improper fractions
1 1/3=1+1/3=4/3 ----> multiply by 3/2
(4/3)*(3/2)=2 cups of sugar
3/4*(3/2)=9/8 ----> convert to mixed number
9/8=8/8+1/8=1 1/8 teaspoon of salt
1 1/4=1+1/4=5/4
5/4*(3/2)=15/8
15/8=8/8+7/8=1 7/8 cups of raisins
Which compound inequality does the number line represent
The compound ineqality which the number line represents will be 5x ≥ -15 or 5x ≤ 10 so option (B) must be correct.
What is inequality?
A difference between two values reveals whether one is greater, smaller, or fundamentally different from the other.If the sides are not equal, an expression in mathematics is said to be unequal. The result of comparing any two values is a determination of whether one is smaller, bigger, or equal to the value on the opposite side of the equation.In option (B) given that
5x ≥ -15
⇒ x ≥ -15/5
⇒ x ≥ -3
And
5x ≤ 10
⇒ x ≤ 10/5
⇒ x ≤ 2
By looking at the number line it is clear that the blue line is greater than -3 and less than 2 hence it will be correct.
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Hello, I need some assistance with this homework question please for precalculusHW Q11
A polynomial has the following form:
[tex]P(x)=a_nx^n+a_{n-1}x^{n-1}+...+a_2x^2+a_1x+a_0[/tex]Therefore, the function is a polynomial
Answer:
It is a polynomial of degree 3.
The standard form of a 3rd degree polynomial is given by:
[tex]P(x)=ax^3+bx^2+cx+d[/tex]So:
The polynomial in standard form is:
[tex]f(x)=x^3+3x[/tex]With the leading term x³ and the constant 0.
what is the area of the regular 15-gon with radius 12mm?
The regular pentagon can divide into 5 congruent isosceles triangles
The equal sides of each triangle have length r and vertex angle of measure 72 degrees
Then we will use the sine rule of the area to find the area of each triangle, then multiply it by 5 to get the area of the pentagon
Since the radius is 7mm, then
r = 7
[tex]A=5\times\frac{1}{2}\times r\times r\times sin72[/tex]Substitute r by 7
[tex]\begin{gathered} A=5\times\frac{1}{2}\times7\times7\times sin72 \\ \\ A=116.5044232\text{ mm}^2 \end{gathered}[/tex]Round it to the nearest whole number
A = 117 mm^2
The area of the pentagon is 117 mm^2
Find a given that the line through M(-2, a) and N(0, -2) has gradient -4
a=6
1) Given that we have M (-2, a), N(0, -2), and the gradient -4. Let's start by applying the formula for the gradient.
G = (y_2 - y_1 ) / (x_2- x_1)
2) So "a", the second coordinate of point M is equal to 6, and as the gradient is a negative number indicates a "downhill" a decreasing direction of that line.
Hello, can you please help me solve this question ASAP!!!
SOLUTION:
Step 1:
In this question, we have that:
Step 2:
Part A:
We are meant to show that the equation:
[tex]5sinx=1+2cos^2x[/tex]can be written in the form
[tex]2sin^2\text{x + 5 sin x - 3=0}[/tex]Proof:
[tex]\begin{gathered} \text{5 sin x = 1 + 2 cos }^2x\text{ } \\ \text{But cos}^2x+sin^2x\text{ = 1} \\ \text{Then,} \\ \cos ^2x=1-sin^2x\text{ } \\ \text{Hence,} \\ 5sinx=1+2(1-sin^2x_{}) \\ 5sinx=1+2-2sin^2x \\ 5sinx=3-2sin^2x \end{gathered}[/tex]Re-arranging, we have that:
[tex]2sin^2x\text{ + 5 sin x - 3 = 0 }[/tex]Part B:
b) Hence, solve for x in the interval:
[tex]0\text{ }\leq\text{ x }\leq\text{ 2}\pi[/tex]