Answer: Fn
Explanation: Because Fn is applying force upward
1. A race starts out at rest and accelerates to 30m/s over a period of 10s. What is the acceleration of the car?
O 3.0 m/s
O 3.0 m.s2
O 2.0 m/s2
O 5.0 m/s2
Answer:3.0m/s
Explanation:
Indica en cada caso si estas fuerzas producen un efecto deformador o dinámico: a) Empujar un carro de la compra c) Atraer mediante un imán un clavo que estaba en reposo b) Modelar una figura de arcilla d) Lanzar una pelota de tenis
Answer:
Dynamic a, b and d
Deformer c and d
Explanation:
When a force is applied to an object, the acceleration may or may not change, which is analyzed from Newton's second law, this effect is a dynamic effect on the system; The environment can change the shape of the object, in this case the force creates a deformation in it.
With these clarifications let's analyze the different situations.
a) Dynamic. When pushing a car initially an acceleration is created in it, shortly after this decreases to zero and continues with constant speed.
b) Dynamic. When the nail moves it does not change the shape of the body that contains it, nor the shape itself, therefore the system can be analyzed with Newton's second law and the force is of the Dynamic type
c) Deformer. In this case the body (clay) has no net movement, but it does change its shape, so the effect of the force translates into a deformation of the system
d) Deformar and Dynamic. The launch of tennis balls has an initial deformation stage during the acceleration process, in this part the force is of the DEFORMING type, but during the trajectory the deformation disappears and the ball has (gravity) a DYNAMIC action
PLZ HELP MEEEEEEE,;-;
Answer:
thxs for the points
Explanation:
because just started
The law of __________________________ says that people think of similar objects as belonging together.
Answer:
Explanation:is the law means that the police are the law
what is gravity???☺️
Answer:
Gravity
Explanation:
its an invisible force that pulls objects
toward each other.
hope it helps
Solid solutions containing two or more metal are commonly called alloys. True or false
Answer:
True
Explanation:
An alloy is a combination of metals or metals combined with one or more other elements. For example, combining the metallic elements gold and copper produces red gold, gold and silver becomes white gold, and silver combined with copper produces sterling silver.
Answer:
this is true
Explanation:
yes yes true
A ball of radius R and mass m is magically put inside a thin shell of the same mass and radius 2R. The system is at rest on a horizontal frictionless surface initially. When the ball is, again magically, released inside the shell, it sloshes around in the shell and eventually stops at the bottom of the shell. How far does the shell move from its initial contact point with the surface
Answer:
[tex]x =\frac{-R}{2}[/tex]
Explanation:
From the question we are told that mass
Thin layer radius [tex]= 2R[/tex]
Generally the expression for ths solution is given as
Xcm =(m*0 =m(-2R))/2m =-mR/(2m)=-R/2
the center of mass will not move at initial state
Considering the center of mass of both bodies
[tex]xcm=\frac{m*x+m*x)}{2m} =x[/tex]
[tex]x =\frac{-R}{2}[/tex]
Therefore the enclosing layer moves [tex]x =\frac{-R}{2}[/tex]
The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
Given-
Radius of the ball is [tex]R[/tex].
the mass of the ball is [tex]m[/tex].
The mass of the thin shell is [tex]m[/tex].
The radius of the thin shell is [tex]2 R[/tex].
For the two bodies with mass [tex]m[/tex], the center of mass can be given as,
[tex]x_{cm}=\dfrac{m_{1} x_{1}+m_{2} x_{2} }{m_{1} +m_{2}}[/tex]
In the given question, the mass of both the bodies are equal and the given distance of center of mass for both bodies are also equal. Therefore,
[tex]x_{cm}=\dfrac{m x_+mx }{m +m}[/tex]
[tex]x_{cm}=\dfrac{2mx }{2m}[/tex]
[tex]x_{cm} =x[/tex]
Distance for center of mass can also be given as,
[tex]x_{cm} =m\times o[/tex]
[tex]x_{cm} =m\times \dfrac{-R}{2m}[/tex]
[tex]x_{cm} =\dfrac{-R}{2}[/tex]
Comparing both the values of the distance of center of mass we get,
[tex]x =\dfrac{-R}{2}[/tex]
Hence, The shell move from its initial contact point with the surface is,
[tex]x =\dfrac{-R}{2}[/tex]
For more about the center of mass follow the link below,
https://brainly.com/question/8662931
An airplane cruising at a constant velocity and altitude. Which of the following diagrams best represents the four forces of the airplane?
Answer:
You need to put the diagrams. repost and include the diagrams
If y is inversely proportional to x and y = 4 and x=10, find y when x = 20
Answer:
Y=8
Explanation:
Y=4
X=10
if x is 20 it means it is doubled frm the previous therefore it means even y has to be doubled
first. now
x=10. x=20
y=4. y=8
a ball bounce on the ground. at what position (A,B,C)does the ball have the greatest potential energy? kinetic energy? explain your answer.
Answer:
What is the meaning of the kinetic I think the answer is both the ball has both Kinetic and potential energy so I think is the answer is true
How do the summer monsoons of India affect the hydrosphere, geosphere, and biosphere?
Answer:
Explanation:
The monsoon rains are the main source of water for 55 percent of the country’s arable land. This means the rains are crucial — not only for India’s farmers, but for its economy as a whole. Now, that’s a good thing when the monsoon arrives on time and brings the right amount of rain. But when it’s late or weak, it leads to drought.
1. A book is at rest on a tabletop. Diagram the forces acting on the book.
The free-body diagram of the forces acting on a book resting on a table is shown in the figure.
When a body is at rest, the net force on the body is zero. So, no acceleration is produced in it. If a body is in contact with another body or surface, a normal contact force acts on it perpendicular to the surface in contact.
So, the forces acting on a book resting on a tabletop are:
1. Weight of the book, W(downward)
2. Normal force (N) perpendicular to the surface in contact.
Therefore, the free-body diagram of the forces acting on a book resting on a table is shown in the figure.
To know more about forces, click here:
https://brainly.com/question/13191643
#SPJ6
‼️can someone help me‼️
• What are the other two ways that you can rewrite the
formula F=ma?
• If I push a wheelbarrow, with a force of 240 N, with an
acceleration of 4 m/s2, how much mass does the
wheelbarrow have? (Solve using formula F=ma)
Answer:
Part A:
The other two ways we can rewrite F = m·a are;
1) F = dp/dt
2) F = m × d(v)/dt
Part B:
The mass of the wheelbarrow is 60 kg
Explanation:
Part A:
The other two ways of rewriting the equation are;
1) Force as the rate of change of momentum, F = dp/dt = d(m·v)/dt and
2) From the above equation, where, m is constant, we have;
F = d(m·v)/dt = m × d(v)/dt
∴ F = m × d(v)/dt
Part B:
The force with which we push the wheelbarrow = 240 N
The acceleration, a, given to the wheelbarrow (by the applied force) = 4 m/s²
From F = m × a
Where;
m = The mass of the wheelbarrow
m = F/a = 240 N/(4 m/s²) = 60 kg
The mass of the wheelbarrow = m = 60 kg.
at constant pressure by what fraction of its volume will aquantity of gas change if the temperature changes from -173degree C to 27degree C
Answer:
The volume of the gas becomes three times the initial volume.
Explanation:
Given that the pressure is constant, and temperature changes from -173degree C to 27degree C.
So, the initial temperature, [tex]T_1[/tex] = -173 degree C = -173+273 = 100 K.
The final temperature, [tex]T_2[/tex]= 27 degree C = 27+273=300 K.
As the pressure is constant, so [tex]P_1=P_2[/tex].
Let V_1 and V_2 be the initial and final volume respectively.
Assuming that the given gas is ideal gas.
So, applying the ideal gas equation
PV=nRT
where n is the number of moles of the gas and R is the universal gas constant.
For the initial state, [tex]P_1V_1=n_1RT_1\cdots(i)[/tex]
and for the final state, [tex]P_2V_2=n_2RT_2 \cdots(ii)[/tex]
Dividing the equation (i) by (ii), we have
[tex]\frac {P_1V_1}{P_2V_2}=\frac {n_1RT_1}{n_2RT_2} \\\\\frac {P_1V_1}{P_2V_2}=\frac {n_1T_1}{n_2T_2}[/tex]
As the mass of the gas is not changing, so [tex]n_1=n_2[/tex], then
[tex]\frac {P_1V_1}{P_2V_2}=\frac {T_1}{T_2}[/tex]
As the pressure is not changing, so [tex]P_1=P_2[/tex], then
[tex]\frac {V_1}{V_2}=\frac {100}{300}[/tex]
[tex]V_2=3V_1[/tex]
So, the volume of the gas becomes three times the initial volume.
What is the net force of the diagram?
A force of 900N acts on
a stationary body
for 40sec and the body acquires the velocity of360 m/s calculate mass a body.
Answer:
Explanation:
It is still using F = m*a -- just in a disguised form.
Givens
F = 900 N
vf = 360 m/s
vi = 0
t = 40 second
Formulas
a = (vf - vi)//t
F = m * a
Solution
a = (360 - 0)/ 40
a = 9
F = m * a
900 = m * 9
m = 900/9
m - 100 kg. Doesn't seem high enough.
Answer:
a= V- u/t
a= 360 - 0 /40 = 9 m/sec2
F = MA
900 = M * 9
M = 900/9
M= 100 kg
How much energy is required to raise the temperature of 5.0 g of silver from 298 K to
334 K?
Answer:
43.2J
Explanation:
Q = m × c × ∆T
Where:
Q = amount of energy
m = mass (grams)
c = specific heat capacity
∆T = change in temperature
Mass = 5.0g
Specific heat capacity of Silver (Ag) = 0.240 J/g°C
We need to convert the temperature from Kelvin (K) to °C
Initial temperature = 298 - 273 = 25°C
Final temperature = 334 - 273 = 61°C
Q = 5 × 0.240 × (61°C - 25°C)
Q = 1.2 × 36
Q = 43.2J
A sign is attached to the side of a building as seen below. The sign is attached to a steel rod. A wire connects to the end of the rod for support. The mass of the sign is 50 kg. Determine the supporting force exerted by the cable
Answer:
500N
Explanation:
50kgx10N/kg
= 500N
Mr. D's dog Gromit jumped out of a second story window (through the screen) and fell to the ground below. The window is 15 feet high, the acceleration of gravity is 9 m/s', and there are 3.28 feet in each meter. What was the final velocity of this crazed dog? (True story, don't worry he's fine and now he knows about gravity)
Answer:
Vf = 9.46 m/s
Explanation:
In order to find the final velocity of the dog we can use third equation of motion:
2gh = Vf² - Vi²
where,
g = acceleration due to gravity = 9.8 m/s²
h = height of window = (15 ft)(1 m/3.28 ft) = 4.57 m
Vf = Final Velocity of Dog = ?
Vi = Initial Velocity of Dog = 0 m/s
Therefore,
(2)(9.8 m/s²)(4.57 m) = Vf² - (0 m/s)²
Vf = √(89.572 m²/s²)
Vf = 9.46 m/s
a beaker weighs 0.4N when empty and1.4N when filled with water what does ot weigh when filled with brine of density 1.2 g/cm3
Answer:2.47
Explanation:
So, the beaker weighs 1.40N when filled with water, brine of density weighs about 1.7N, you add the density + water. Have a good day!
what is the uses of space weather data?
Answer:
Space Weather Data
They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.
Explanation:
Why is a teacher's feedback valuable?
Answer:
Because they could help you move on better with your strategy and ultimately get you better scores on tests
Answer:
Through feedback, teachers can provide the students with suggestions for development, learning strategies and corrections for errors. The importance of constructive feedback allows for many positive opportunities. This component also enhances a student's self-efficacy and provides an avenue for motivation.
What movement allows us to move our side to side?
Answer:
Ball-and-socket joints
Explanation:
A car weighing 19600N is moving with a speed of 30 m/sec on a level road. If it is brought to rest in a distance of 100 m. Find the average distance friction force acting on it
Answer:
F = -8820 N
Explanation:
Given that,
The weight of a car, W = 19600 N
Initial speed of the car, u = 30 m/s
It is brought to rest, final velocity, v = 0
Distance, d = 100 m
We need to find the average friction force acting on it.
Firstly we find the acceleration of the car using third equation of motion. Let it is a.
[tex]v^2-u^2=2as\\\\a=\dfrac{v^2-u^2}{2d}\\\\a=\dfrac{(0)^2-(30)^2}{2\times 100}\\\\=-4.5\ m/s^2[/tex]
Average frictional force,
F = ma
m is mass, [tex]m=\dfrac{W}{g}=\dfrac{19600\ N}{10\ m/s^2}=1960\ kg[/tex]
F = 1960 kg × -4.5 m/s²
= -8820 N
So, the average friction force acting on it is 8820 N.
Calculate the aceleration of a vehicle of 100 kg when applicates 400 N
Answer:
For this we applicate 2nd law of Newton:
F = ma
Replacing:
400 N = 100 kg * a
a = 400 N / 100 kg
a = 4 m/s²
The aceleration is 4 meters per second squared.
Answer:
....................
Explanation:
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HELP ASAP!! WILL TRY TO GIVE BRAINLIESTT!!
Please define the prefixes hyper-, hypo-, & iso- AND describe a solution that is hypertonic, hypotonic, & isotonic as well as compare how a living cell reacts when placed in a solution of each of the 3 types.
If a cell is placed in a hypertonic solution, water will leave the cell, and the cell will shrink. In an isotonic environment, there is no net water movement, so there is no change in the size of the cell. When a cell is placed in a hypotonic environment, water will enter the cell, and the cell will swell.
pls help me with this
Answer:
A screw
Explanation:
what is the function of brushes in D.C motor
Answer:
to transfer the voltage
Explanation:
The brushes make physical contact with the commutator. When a DC voltage is applied to the brushes, that voltage is transferred into the commutator which, in turn, powers the windings. This electrical input generates a magnetic field around the armature.
MUSIC
Progressions can start on any number of chords but usually end on the I.
true or false
Answer:
true
Explanation:
Answer:
false
Explanation:
A single celled organism is found in a sample of water. It contains a nucleus as well as other membrane bound organelles and possesses collagen for movement. This organism most likely belongs to which kingdom?
Answer:
Explanation:
The cell is the smallest living organism that contains all the features of life, and most all life on the planet begins as a single-cell organism. Two types of single-celled organisms currently exist: prokaryotes and eukaryotes, those without a separately defined nucleus and those with a nucleus protected by a celluA single-celled organism is found living in a deep sea vent at the bottom of the ocean in extremely hot water. If it is examined further, which of the following is most likely to be found within it? It will have DNA that is not contained in a nucleus since it is likely a member of the domain Archaea.lar membrane.