A​ company's stock began the day at ​$ 36.77per share. That price drops by ​$1.69 each hour. What is the price per share after 5 ​hours? What would it be after 23 hours if this rate​ continues? Use pencil and paper. Explain what the signs of the answers mean in this context.

Since the translation is 8 units right and 4 units down, we have to add 8 to the x coordinate and subtract 4 to the y coordinate.

R=(-2,1)

R' = (-2+8,1-4)= (6,-3)

R' = (6,-3)

Answer:

See below

Step-by-step explanation:

From 5 to 10 mugs is 5 mugs  

   These cost  110 - 67.50 = 42.50

        So each mug costs 42.50 / 5 = 8.50 each  

              With a 'base cost' of 25 dollars

   (Base cost might be artwork, design, order processing, shipping or whatever.....but this amount is added to each order)

(As a check    20 mugs would be   25 + 20 (8.50) = 195   <====yep

150 mugs will then be 25   +  150 ( 8.50) = 1300 dollars

Answer:

y=.25x+6

Step-by-step explanation:

Answer:

Mexico to the United States in 1947

Step-by-step explanation:

Answer: the radius of a cylinder is 4 cm

Step-by-step explanation:

[tex]S_{ts}=352\ cm\ \ \ \ H=10\ cm\ \ \ \ \ r=?[/tex]

The total surface area:

[tex]\displaystyle\\ S_{ts}= 2\pi r^2+2\pi rH\\\\S_{ts}=2\pi (r^2+rH)\\\\352=2\pi (r^2+10r)\\\\[/tex]

Divide both parts of the equation by 2π:

[tex]\displaystyle\\56=r^2+10r\\\\56-56=r^2+10r-56\\\\0=r^2+10r-56\\\\Thus,\\\\ r^2+10r-56=0\\\\D=(-10)^2-4(1)(-56)\\\\D=100+224\\\\D=324\\\\\sqrt{D}=\sqrt{324} \\\\\sqrt{D}=18\\\\ r=\frac{-10б18}{2(1)} \\\\r=-14\notin\ (r > 0)\\\\r=4\ cm[/tex]

Answer:

r ≈ 4 cm

Step-by-step explanation:

Total Surface Area of a cylinder

A = Base Area x 2 + Lateral Surface Area

A = 2(πr²) + 2πrh

where r = radius of base and h = height of cylinder

Solving for r we get

[tex]\displaystyle r = \dfrac{1}{2} \sqrt{h^2 + 2 \dfrac{A}{\pi} }-\dfrac{h}{2}\\\\[/tex]

Given h = 10 cm and A = 325 we get

[tex]\displaystyle r = \dfrac{1}{2} \sqrt{10^2 + 2 \dfrac{352}{\pi} }-\dfrac{10}{2}\\\\\\[/tex]

[tex]\sqrt{10^2 + 2 \dfrac{352}{\pi} } =\sqrt{100+\dfrac{704}{\pi }}\\\\= \sqrt{100 + 224.09}\\\\\\[/tex]

= [tex]\sqrt{324.09}[/tex]

= 18.0025

1/2 x 18.0025 ≈ 9

So r ≈  9 - 10/2 = 9 -5 = 4

r ≈ 4 cm

The absolute value expressions of the echo sounder are |r - w| and |w - r|

The statement in the question is represented as

The accuracy of an echo sounder is the positive difference between ...

To solve further, we use the following representations

Depth of water reading = r

Actual depth = w

So, the statement becomes

The accuracy of an echo sounder is the positive difference between r and w

The difference can be represented as

Difference = r - w or Difference = w - r

Represented as absolute value expressions

Difference = |r - w| or Difference = |w - r|

Hence, the expressions are |r - w| and |w - r|

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We are given that the length of a rectangle is 3 inches greater than the width.

Let us draw a rectangle and label the width and length.

Part A:

Let the width of the rectangle is x inches.

Then the length of the rectangle is (x + 3) inches.

Now recall that the area of a rectangle is given by

Where L is the length and W is the width of the rectangle.

Therefore, the above polynomial represents the area of the rectangle.

Part B:

We are given that the width is 4 inches.

Substitute the width (x = 4) into the equation of the area that we found in part A.

Therefore, the area of the rectangle is 28 square inches.

Using concept of Linear equation in two variables, we got 23 is  denomination count of 5$ bills and 21 is denomination count of 20$ bills.

Linear equations are used to solve equation in which two variables are connected with each other via some specific methods.

The linear equations in two variables are the equations in which each one of the two variables are of the highest exponent order of the 1 and have one, none, or may be infinitely many solutions. The standard form of a two-variable linear equation is given by ax + by + c = 0 where x and y are the two variables. The solutions can also be written in form of ordered pairs like (x, y).

It is given that 5$ bills are 2 more than 20$ bills,

so let suppose 20$ bills denomination count is x,

then 5$ bills denomination count=x+2;

It is also given that 535$ worth is summation of 5$ bills and 20$ bills

Therefore,[5×(x+2)+(20×x)]=535

On solving for x, we get x=21

Therfore,20$ bills denomination count is 21,and 5$ bills denomination count is 23.

Hence,5$ bills denomination count is 23 and 20$ bills denomination count is 21

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Answer:

1 hour

Step-by-step explanation:

Since the penguin supposedly walks a 1 mile per hour, it would take one hour to achieve 1 mile

The blue graph is represented by the equation g(x) = (x - 5)²

The possible graph that completes the question is added as an attachment

From the attached graph, we have the following parameters

Also from the graph, we have the equation of the function f(x) to be

f(x) = x²

Solving further, we can see that:

The only difference is that, f(x) is shifted to the right by 5 units

This means that

g(x) = f(x - 5)

So, we have

g(x) = (x - 5)²

Hence, the blue graph equation is g(x) = (x - 5)²

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Given:

The number sentence for 4 and n

Required:

We have to find the given sentence

Explanation:

4 and N, simply means you mixed them up, you sum them up

your result is 9, 4+N=9

Required solution :

4+N=9

The given triangle is a right angled triangle having the follwoing sides;

Hypotenuse = x (longest side)

Opposite = 14 (side facing the given acute angle)

Theta = 15 degrees

Using the SOH trigonometry identity;

sin 15 = opposite/hypotenuse

sin15 = 14/x

x = 14/sin15

x = 14/0.2588

x = 54.09

x is approximately equal to 54.1. Option B is coorect

If the liquid flows out of the tank at a rate of 40 cubic inches per minute, the height of the liquid will decrease at rate 0.0318 in./minute

Referring to the attached picture, the two triangles in a cone are similar. Hence,

r/h = 48/24

or

r = 2h.

The volume of the liquid is given by:

V = 1/3 . πr²h

Substitute r = 2h,

V = 1/3 . π(2h)²h = 4/3 . πh³

Take the derivative with respect to t

dV/dt = 4/3 .  3πh² . dh/dt

dV/dt = 4 .  πh² . dh/dt

Substitute dV/dt = -40 and h = 10

-40 = 4 .  π(10)² . dh/dt

dh/dt = - 0.0318 in./minute

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Answer:

x = 7 , ∠ A = 36°

Step-by-step explanation:

since ∠ ADB ≅ ∠ CBD ( alternate angles )

and ∠ ABD ≅ ∠ CDB ( alternate angles )

then ABCD is a parallelogram

the opposite angles of a parallelogram are congruent , so

∠ C = ∠ A , that is

8x - 20 = 3x + 15 ( subtract 3x from both sides )

5x - 20 = 15 ( add 20 to both sides )

5x = 35 ( divide both sides by 5 )

x = 7

Then

∠ A = 3x + 15 = 3(7) + 15 = 21 + 15 = 36°

Answer: x = 7 and m∠A = 36

Step-by-step explanation:

Here ∠ADB ≅ ∠CBD and ∠ABD ≅ ∠CDB

This configuration is found when a quadrilateral has two parallel sides which have a diagonal as their transversal. Thus the figure is of parallelogram. In a parallelogram, opposite angles are equal. Thus m∠A = m∠C

⇒3x +15 = 8x - 20

⇒3x + 15 - 3x = 8x - 3x -20

⇒5x = 20 + 15

⇒x = 7

Now m∠A = (3X7) +15 = 36

Answer:

brand A. The bag weights for brand A have less variability than the bag weights for brand B

Concept; Probability

Step1: The total number of tokens is

let the probability of blue be P(B) and the probability of red be P(R)

The probability that the first is Blue is

The probability the second is white without replacement is

Hence the combined probability of Blue and Red is

Therefore the probability that the first is blue and the second is white is 4/15

Answer:0.0008994

Step-by-step explanation:

Answer:

Brainliest Answer?

( 7 / 8 ) seconds

( 77 / 4 ) feet

Step-by-step explanation:

The question is a bit confusing but I will do it both ways. I will assume that you made a mistake copying over the function because the graph s( t ) is linear. Linear functions have a maximum value of infinity because it is an odd-degree polynomial.

Assume that s( t ) = - 16t² + 28t + 7;

The equation forms an upside-down parabola which means it has a maximum value.

Complete the square to get the axis of symmetry and the maximum value of the parabola or use my very cool formula. The variables h and k represent the axis and max respectively.

ax² + bx + c = a( x - h )² + k;

ax² + bx + c = a( x - ( - b / 2a ) )² + c - ( b² / 4a );

ax² + bx + c;

Take a as a factor.

a( x² + ( b / a )x + ( c / a ) );

Add and subtract the square of ( 1 / 2 ) of ( b / a ). This is called completing the square because it forms a perfect square trinomial.

a( x² + ( b / a )x + ( b / 2a )²  - ( b / 2a )² + ( c / a ) );

Factorise the trinomial.

a( ( x + ( b / 2a ) )² - ( b / 2a )² + ( c / a ) );

Use the distributive property of multiplication.

a( x + ( b / 2a )² + a( ( c / a ) - ( b / 2a )² );

a( x + ( b / 2a )² +  a( ( c / a ) - ( b² / 4a² ) );

Simplify the fractions.

a( x + ( b / 2a )² + c - ( b² / 4a );

Substitute the values.

- 16( t - ( - 28 / 2( - 16 ) )² + 7 - ( ( 28 )² / 4( - 16 ) );

Time is the x-axis so we need to solve for the axis of symmetry.

h = ( - 28 / 2( - 16 ) );

h = ( - 28 / - 32 );

Simplify the fraction.

h = ( 7 / 8 );

Maximum height is the parabola's y of the vertex.

k = 7 - ( ( 28 )² / 4( - 16 ) );

k = 7 - ( ( 28 )( 28 ) / - 64 );

k = 7 - ( 784 / - 64 );

k = 7 - ( - 49 / 4 );

k = ( 28 / 4 ) + ( 49 / 4 );

k =  77 / 4;

Number of kilometers the race was in all is [tex]1\frac{1}{3}[/tex] kilometers.

Given that, Kara ran 8/18 of a kilometer and cycled 16/18 of a kilometer.

To add two fractions, with different denominators, we need to rationalise the denominators by taking out the LCM and make the denominator same. Then add the numerators of the fractions, keeping the denominator common.

Now, total distance in race

8/18 + 16/18

= (8+16)/18

= 24/18

= 4/3

= [tex]1\frac{1}{3}[/tex] kilometers

Therefore, number of kilometers the race was in all is [tex]1\frac{1}{3}[/tex] kilometers.

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The function is given below

What is a function?

The value of a function f at an element x of its domain is indicated by f(x); the numerical value resulting from the function evaluation at a given input value is expressed by substituting x with this value; for example, the value of f at x = 4 is denoted by f(x) (4). When the function is not named and is represented by an expression E, the function's value at, say, x = 4 can be expressed by E|x=4. In science, engineering, and the bulk of the mathematical disciplines, functions are commonly used. Functions are claimed to be "the central objects of research" in most branches of mathematics.

The given function is

f(x) = x - 6/2

The function in gf is

g{f(x)} = √(x - 6/2) - 4

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The value of the required composite function is [tex]g(f(x))=\sqrt{x-\frac{6}{2} } -4[/tex].

What is a composite function?

When the result of one function is utilized as the input for another, a composite function is created.

Given that:

[tex]f(x)=x-\frac{6}{2}[/tex] and [tex]g(x)=\sqrt{x}-4[/tex]

To find the composite function [tex]g(f(x))[/tex], it is required to use the output of the first function as the input of the second function. It means that replace [tex]x[/tex] by  [tex]f(x)[/tex]  in the second function as:

[tex]g(x)=\sqrt{x}-4\\g(f(x))=\sqrt{f(x)}-4[/tex]

Now, substitute the value of  [tex]f(x)[/tex] on the right side of the above equation as:

[tex]g(f(x))=\sqrt{x-\frac{6}{2}}-4[/tex]

Hence, the required answer is:

[tex]g(f(x))=\sqrt{x-\frac{6}{2}}-4[/tex]

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The surface area of the barrel needs to be calculated in order to determine the amount of paint. The surface area of the barrel, including the lid, is 13 m²

Missing data from the problem:

radius of the barrel = 0.4 meters

height of the barrel = 1.2 meters

The shape of a barrel is cylinder. The surface area of the barrel, including the lid) is:

A = 2. πr² + 2. πr.h

Where:

r = radius

h = height

Plug the parameters into the formula:

A = 2. π(0.4)² + 2. π(0.4).(1.2)

A = 13 m²

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The mean and the standard deviation of the following numbers 20, 33, 44, 53, 69, 75, 89, 90 are 59.125 and 22.461 respectively

The mean is the average value in a collection and a standard deviation is the average amount of variability in a data.

mean= sum of data in the collection/ number of data

= (20+33+44+53+69+75+89+90)/8 = 473/8 = 59.125( nearest thousandth)

standard deviation= sum of √(x- mean)^2/ number of data while x is each number in the data

finding (x- mean)^2 for each value of x

(20-59.125)^2=848.266

(33-59.125)^2=682.516

(44-59.125)^2=228.766

(53-59.125)^2=37.516

(69-59.125)^2=102.516

(75-59.125)^2= 260.016

(89-59.125)^2= 907.516

(90-59.125)^2= 968.766

S.D= √(848.266+682.516+228.766+37.516+102.516+260.016+907.516+968.766)/8 =

√504.484

Therefore S.D =22.461 ( to the nearest thousandth)

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The number and type of roots of each quadratic function are:

The type of roots of a quadratic function is given by the value of the discriminant, which is the value under the square root of the quadratic formula.

The types of roots of a quadratic equation are;

The roots or solution to the quadratic equation, a·x² + b·x + c = 0, are given by the quadratic formula, [tex]x = \dfrac{-b\pm \sqrt{b^2 - 4\cdot a \cdot c} }{2\cdot a}[/tex]

Where:

b² - 4·a·c is known as the discriminant of the quadratic equation.

The type of root of a quadratic equation is given by the discriminant, b² - 4·a·c, as follows:

The given functions are:

Comparing the above equation to the, general form of a quadratic equation, f(x) = a·x² + b·x + c, we have;

a = 1, b = -9, and c = 21

The discriminant is therefore, (-9)² - 4 × 1 × 21 = -3 < 0

The quadratic equation therefore, has complex roots.

The quadratic equation, f(x) = x² + 16·x - 64 has a discriminant given as follows;

The discriminant is: 16² - 4 × 1 × (-64) = 512 > 0, therefore, the quadratic equation two real roots, given by the equation;

[tex]x = \dfrac{-16\pm \sqrt{16^2 - 4\times 1 \times 64} }{2\times 1}= \dfrac{-16\pm \sqrt{512} }{2}= \dfrac{-16\pm 16\cdot \sqrt{2} }{2}[/tex]

x = -8 + 8·√2 or x = -8 - 8·√2

The value of the discriminant is 10² - 4 × (-4) × 84 = 1444 > 0, therefore, the equation has two real and distinct roots, given by the equation;[tex]x = \dfrac{-10\pm \sqrt{1444} }{2\times (-4)}= \dfrac{-10\pm 38 }{-8}[/tex]

[tex]x = \dfrac{28 }{-8}= -3.5[/tex] and [tex]x = \dfrac{-48 }{-8}= 6[/tex]

The discriminant of the above quadratic equation is; 0² - 4 × 3 ×24 = -288 < 0

Therefore, the quadratic equation, f(x) = 3·x² + 24, has no real roots or complex roots

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In these linear expressions one is equivalent which is  3- 2( - 2.6x + 2.1) = 5.2x - 1.2 and one is not .

An algebraic expression known as a linear expression has terms that are either constants or variables raised to the first power.

Alternatively pluging; we will see that none of the exponents can be greater than 1.

2x - 3(1.3x - 2.5) = 5.9x + 7.5

2x -3.9x + 7.5 = 5.9 + 7.5

-1.9x + 7.5 ≠  5.9 + 7.5

thus linear expression is not equivalent.

3- 2( - 2.6x + 2.1) = 5.2x - 1.2

3 + 5.2x -  4.2 = 5.2x - 1.2

5.2x - 1.2 = 5.2x - 1.2

thus, linear expression is equivalent.

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The percentage of adult females with pulse rates between 49.0 bpm and 86.5 bpm - 81.86%

The percentage of adult females have pulse rates below 90 bpm - 89.97%

a)

X ~  N ( µ = 74 , σ = 12.5 )

P ( 49 < X < 86.5 )

Standardizing the  value

Z = ( X - µ ) / σ

Z = ( 49 - 74 ) / 12.5

Z = -2

Z = ( 86.5 - 74 ) / 12.5

Z = 1

P ( -2 < Z < 1 )

P ( 49 < X < 86.5 )  =  P ( Z < 1 ) - P ( Z < -2 )

P ( 49 < X < 86.5 )  = 0.8413 - 0.0228

P ( 49 < X < 86.5 )  = 0.8186  ≈  81.86%

b)

X ~ N ( µ = 74 , σ = 12.5 )

P ( X < 90 )

Standardizing the value

Z = ( X - µ  ) / σ

Z = ( 90 - 74 ) / 12.5

Z = 1.28

P (  ( X - µ ) / σ )  < ( 90 - 74 ) / 12.5 )

P ( X < 90 ) =  P ( Z < 1.28 )

P ( X < 90 ) = 0.8997  ≈  89.97%

The pulse rate, or the number of times the heart beats each minute, is gauged by the pulse rate. The arteries enlarge and constrict with the flow of blood as the heart pumps blood through them. An elevated heart rate, or tachycardia, can occur for any reason. Exercise-induced or stress-related heart rate increases are two possible causes (sinus tachycardia). Sinus tachycardia is not seen as an illness but rather a symptom. Another factor contributing to tachycardia is an unsteady heartbeat (arrhythmia).

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Answer:

15/8 for exact form

1.875 for decimal form

And

1 and 7/8 for mixed number form

hope this helps you!

(also already in the simplest form :)

Answer:

b= -1, -6

Step-by-step explanation:

divide by common factor

then use x=- b+- sqrt b^2-4ac/2a

separate the equations and solve them

Answer:

Step-by-step explanation:

Since the population quadruples each day, the population for the subsequent day would be 4*(population of the previous day).

Thus, the evolution of the population value takes the form of a geometric progression, with a common ratio, r = 4

The n-th term of a geometric progression is given by:

[tex]a_{n}[/tex] = [tex]ar^{n-1}[/tex]             (1)

Where a is the 1st term of the progression.

From (1), our population would generally take the form:

[tex]P_{d}[/tex] = [tex]P_0r^{d-1}[/tex]             (2)

In this case, the initial value (1st term) [tex]P_{0}[/tex] = 120.

So putting r and  [tex]P_{0}[/tex] into  (2):

P(d) = 120*([tex]4^{d-1}[/tex])

Noting that 4  = 2²:

P(d) = 120*([tex]2^{2(d-1)}[/tex])

FOR d = 8:

P(d) = 120*([tex]2^{2d-2}[/tex])

becomes:

P(8) = 120*([tex]2^{2(8)-2}[/tex])

P(8) = 120*([tex]2^{16-2}[/tex])

P(8) = 120*([tex]2^{14}[/tex])

P(8) = 120*(16,384)