a company that manufactures mufflers for cars offers a lifetime warranty on its products, provided that ownership of the car does not change. suppose that only 20% of its mufflers are replaced under this warranty. a button hyperlink to the salt program that reads: use salt. (a) in a random sample of 400 purchases, what is the approximate probability that between 70 and 90 (inclusive) mufflers are replaced under warranty? (round your answer to four decimal places.)

Answers

Answer 1

The approximate probability that between 70 and 90 is 0.728.

Using normal distribution,

Mean = xbar = np = 400 × 0.2 = 80

Standard deviation = √[np(1-p)] = √(80 × 0.8) = 8

To ensure that the distribution is normal,

np ≥ 10

80 ≥ 10

And,

np(1-p) ≥ 10

80(0.8) = 320 ≥ 10

Hence, we use the z-tables for this

a) Convert 75 and 100 into standardized scores.

A value's standardized score is equal to the value minus the mean divided by the standard deviation.

z = (x - xbar) ÷ σ

For 75

z = (75 - 80) ÷ 8 = - 0.625

For 100

z = (100 - 80) ÷ 8 = 2.5

To calculate the approximate likelihood that between 75 and 100 (inclusive) mufflers will be replaced under warranty.

P(75 ≤ x ≤ 100) = P(-0.625 ≤ z ≤ 2.5)

For these probabilities, use data from the normal probability table.

P(75 ≤ x ≤ 100)

= P(-0.625 ≤ z ≤ 2.5)

= P(z ≤ 2.5) - P(z ≤ -0.625)

= 0.994 - 0.266

= 0.728

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Related Questions

3/4 - (-1/2) as a fraction

Answers

Answer:1/4

Step-by-step explanation:

enter 2 Expressions that represent the retail price of the clothes you see for your variable and exclusive clothing boutiques quadruples the price of the items it purchases for resale.

Answers

Explanation

Step 1

Let

c represent the original price

if the boutiques quadruples the price of the items it purchases for resale.​then

[tex]\begin{gathered} \text{new price=4}\cdot c \\ percentage \\ 4=4\cdot\frac{100}{100} \\ 4=\frac{400}{100} \\ 4=400\text{ per cent} \end{gathered}[/tex]

400 percent

Step 2

expressions

[tex]\begin{gathered} \text{new price=4}\cdot c \\ \text{new price= 400 percent of C} \end{gathered}[/tex]

4c and 400%c

I hope this helps you

If the mean weight of 3 outfielders on the baseball team is 192 lb and the mean weight of the 6 other players is 228 ​lb, what is the mean weight of the 9​-person​ team?

Answers

Answer:

Step-by-step explanation:

If the mean weight of 3 outfielders on the baseball team is 194 lb and the mean weight of the 6 other players is 229 ​lb, what is the mean weight of the 9

ickets to the zoo cost $15 for adults and $10 for children. The school has a budget of $300 for the field
trip. An equation representing the budget for the trip is 15x+10y = 300.
a. With a budget of $300, determine if 21 students and 6 adults can go to the zoo. Explain how you
know.
b. If there are four adults who need tickets, what is the maximum number of students who can go to
the zoo while staying within the school budget? Show or explain your reasoning.
c. Solve the equation15x+10y = 300 for y.

Answers

Answers: lol sorry very long answer

part a answer: Yes, because if we substitute the variables, the equation will be 15(6) + 10(21) = 300. Simplifying this will be 90 + 210 = 300. And since 90 + 210 does equal 300, 21 students and 6 adults can go to the zoo

part b answer: 24 students. Using the equation 15x + 10y = 300, we can find out the maximum number of students who can go to the zoo. First we can substitute x for 4 because that's how many adults who need the tickets. The equation will now be 15(4) + 10y = 300. Simplifying this will be 60 + 10y = 300. Now we can subtract 60 on both sides to isolate the y term. The equation will be 10y = 240. Divide each side by 10 to find out what y is and we get y = 24. So if 4 adults go the zoo, up to 24 students can go.

part c answer: y = 30 - 1.5x. To solve 15x + 10y =300, we first need to move 15x to one side of the equation. To do this we will subtract it on both sides. The equation is now 10y = 300 -15x. Then you will divide 10 on both sides to find out what y is. y = 30 - 1.5x.

A hen was given $10, a spider was given $40, a bee was given $30. How much would be given to a dog?

Answers

Answer:

Umm 20 dollars?

Step-by-step explanation:

explain how you got it please

Answers

The simplest form of the expression as we have it is; (-4x^4z^2)(2xy^3z^2)

What does it mean to simplify?

When we are asked to simplify, what we are asked to do is to write the expression that we have in a form that is simplest. That is, we should put the expression in a form that there would not be any simpler presentation of the expression.

We have;

(-2x^2z)^2(2xy^3z^2)

Then we now have to deal with the exponent outside the bracket;

(-4x^4z^2)(2xy^3z^2)

Thus, we now have the expression in the simplest form that it can take and it can not be further broken down.

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Write an integer that lies between-7.73 & -6.41, what is the answer?

Answers

-7.07

As
(-7.73 + -6.41)/2 = -14.14/2 = -7.07
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what is the type of angle are <1 and <14??????????

Answers

1° and 14° are acute angles.  

An acute angle is one that is less than 90°, or one that is between 0° and 90°.  

The opposite of an acute angle is an obtuse angle. In other terms, an obtuse angle is one that is larger than 90° and less than 180°. It is the angle that is between 90° and 180°.

90° is the standard for a right angle. Any angle that is less than 90° is called acute, and any angle that is larger than 90° is called obtuse.

∠1 and ∠14 are less than 90° therefore, they are acute angles.

Correct question :

What type of angle are 1° and 14°?

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please dont use any big words & give an essay explanation

Answers

We want to create a real-life reasonable problem in which we can apply the laws of exponents.

Using a compound interest example;

Word Problem:

Calculate the final value of a $2,000 investment in an account with a 5% interest compounded Quarterly for 5 years.

Solving the word problem;

We have the following parameters;

[tex]\begin{gathered} \text{ Principal P = \$2,000} \\ \text{Rate r = 5\%} \\ \text{Time t = 5 years} \\ \text{ Number of times compounded n = 4} \end{gathered}[/tex]

Recall that the formula for compound interest is;

[tex]F=P(1+\frac{r}{n})^{nt}[/tex]

Substituting the given values;

[tex]\begin{gathered} F=2000(1+\frac{0.05}{4})^{4(5)} \\ F=2000(1+0.0125)^{20} \\ F=2000(1.0125)^{20} \\ F=2000\times(1.0125)^{20} \\ F=\text{ \$2,564.07} \end{gathered}[/tex]

Therefore, the solution to the problem is;

The final

which of the following best describes XWO A. Angle bisectorB. MedianC. AltitudeD. Perpendicular bisector15W15Z

Answers

INFORMATION:

We have the next triangle

And we must select the answer that best describes XW segment

STEP BY STEP EXPLANATION:

We can see that XW segment divides the YZ side into two equal parts, which measure 15 units. And we can also see that the XW segment starts in one of the vertex of the triangles and goes to the opposite side.

Then, we can analyze the definition for the median of a triangle

Finally, if we compare, we can see that the definition of median describes the XW segment.

ANSWER:

B. Median.

Which sequence shows the numbers in order from least to greatest?
A. |-8.23| < 8 1/5 < 8.3
B. 8 1/5 > 8.3 > |-8.23|
C. 8 1/5 < |-8.23| < 8.3
D. 8.3 < |-8.23| < 8 1/5

Answers

The sequence that shows the numbers in order from least to greatest is A. |-8.23| < 8 1/5 < 8.3

How to illustrate the information?

It's important to note that arranging numbers from the least to the greatest simply means ascending order.

In this case, it's vital to note that the negative value is the smallest. Then 8 1/5 is 8.2. This conea after. The greatest number is 8.3 since it's the biggest.

In conclusion, the correct option is A.

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The perimeter of a rectangular garden is 72 meters. The length is 6 meters longer than
twice the width. Find the dimensions of the garden.

Answers

P = 2L + 2W

P = 72

L = 12W (that's an odd way to put it -- 6x 2x)

P = 2(12W) + 2W

P = 24W + 2W

72 = 26W

W = 2.769

Xavier has a bag of 20 marbles. 8 are blue, 7 are red, and 5 are green. Xavier pulls out a marble, records what color it is, and puts it back. He then selects another marble and records its color What is the probability of pulling out a blue marble and then a green marble?

Answers

Answer:

0.1

Step-by-step explanation:

chance of pulling out a blue marble can be described as 8 equally probable outcomes (blue marbles) out of 20 equally probable outcomes (all marbles).

Similarly, the chance of pulling out a green marble is 5 out of 20.

In total, we have 8*5 (combinations of blue then green) outcomes out of 20*20 (any two marbles):

8*5 / (20*20) = 40 / 400 = 1/10 = 0.1

t - 2 < 21 solve the inequality for t simplify your answer as much as possible

Answers

Answer:

t < 23

Step-by-step explanation:

t - 2 < 21

Step 1 : Add 2 on both sides.

t - 2 + 2 < 21 + 2

t < 23

question allistair throws a biased six-sided dice. the probability of getting a 6 with this dice is 0.4. the other numbers are equally probable. if he throws the dice 3 times, what is the probability that he gets 5, 3, and 2 in this order?

Answers

The probability that he gets 5, 3, and 2 in this order is 0.92, 0.52, and 0.32 respectively.

The possibility of rolling a 6 with these dice is 0.4, according to the question. The possibility of rolling a 1 through 5 on the dice is also the probability of not obtaining a 6.

a) Chance of receiving 5:

P(6) + Q(6) = 5

Q(6) = 5 - P(6)

Q(6) = 5 - 0.4

Q(6) = 4.6

The probability of obtaining 5 to 5 is 4.6 overall.

The probability of receiving one is,

P(1) + P(2) + P(3) + P(4) + P(5) = 4.6

The first five numbers have an equally likely probability.

P(1) = 4.6 ÷ 5

P(1) = 0.92

b) Probability of getting 3:

P(6) + Q(6) = 3

Q(6) = 3 - P(6)

Q(6) = 3 - 0.4

Q(6) = 2.6

The probability of obtaining 3 to 5 is 2.6 overall.

The probability of receiving one is,

P(1) + P(2) + P(3) + P(4) + P(5) = 2.6

The first five numbers have an equally likely probability.

P(1) = 2.6 ÷ 5

P(1) = 0.52

c) Probability of getting 2:

P(6) + Q(6) = 2

Q(6) = 2 - P(6)

Q(6) = 2 - 0.4

Q(6) = 1.6

The probability of obtaining 2 to 5 is 1.6 overall.

The probability of receiving one is,

P(1) + P(2) + P(3) + P(4) + P(5) = 1.6

The first five numbers have an equally likely probability.

P(1) = 1.6 ÷ 5

P(1) = 0.32

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Perimeter and area polynomials

Answers

The combined perimeter of

2b (14y - 12)

2c (18y + 4)

2d (14y - 16), is

[tex]P=14y-12+18y+4+14y-16[/tex]

Add the like terms

[tex]\begin{gathered} P=(14y+18y+14y)+(-12+4-16) \\ \\ P=46y+(-24) \\ \\ P=46y-24 \end{gathered}[/tex]

The combined perimeter is (46y - 24)

The combined area of

1b (10y^2 - 27y +5)

1c (20y^2 + 11y - 3)

1d (12y^2 -24y), is

[tex]A=10y^2-27y+5+20y^2+11y-3+12y^2-24y[/tex]

Add the like terms

[tex]\begin{gathered} A=(10y^2+20y^2+12y^2)+(-27y+11y-24y)+(5-3) \\ \\ A=42y^2+(-40y)+2 \\ \\ A=42y^2-40y+2 \end{gathered}[/tex]

The combined area is (42y^2 - 40y + 2)

Robert finds some nickels and pennies in his change purse. How many
coins does he have if he has 110 nickels and 130 pennies? How many
coins does he have if he has n nickels and p pennies?

Total coins, 110 nickels and 130
pennies:

Total coins, n nickels and p pennies:

Pls answer fast

Answers

Answer:

Step-by-step explanation:

If coins 110 plus 130 will give you 240 coins

If actual money 110 times 5 will give you 550 plus 130 will give you 680 or 6 dollars and 80 cents.

N times 5 plus p will be your equation

You begin with $25 in a saving account and $50 in a checking account. Each week you deposit $5 into saving and $10 into checking. After how many weeks is the amount in checking twice the amount in saving?

Answers

Answer:

1 week

Step-by-step explanation:

After 1 week

Saving account: $25 + $5 = $30

Checking amount: $50 + $10 = $60

30 x 2 = 60

So it's 1 week

Determine the intercepts

Y - 3 = 5(x-2)

Answers

Answer: x-intercept(s): (7/5, 0)

Y intercept(s): (0,−7)

Please help!

4|x+7| < 8
3

Answers

so this is a

You also will not know precisely how many sentences will appear in the random paragraph. But some piano roll artists made a name with pieces that could not possibly be played by an precise individual. Most of his research deal with difficult meters and polyrhythms. Many include distinct voices enjoying the identical line at different tempos, usually in odd ratios. On top of this, most of the traces themselves tend to be highly dissonant and exhausting to actually play. Someday we might come nose to nose with pure house, that could presumably be a nothingness waiting to be filled.

Triangle EFG is dilated by a scale factor of 2 centered at (0, 2) to create triangle E′F′G′. Which statement is true about the dilation?

Answers

Answer:Triangle EFG is dilated by a scale factor of 2 centered at (0, 2) to create triangle E'F'G'. Which statement is true about the dilation? segment EG ≅ segment E prime G prime. The slope of segment EF is the same as the slope of segment E prime H prime.

Step-by-step explanation:

[x-6] +4 =10 solve for X

Answers

Answer:

x=12

Step-by-step explanation:

(x-6)=6

x=12

You would first want to simplify so it would be x-2=10
Than you group all the constants on the right side of the equation so you add 2 to both sides (x-2)+2=10+2 than you simplify it you get x=10+2 than you simplify again and you get x=12
So x=12 hope this helps you.

PLEASE HELP ME ASAP.

Answers

18,0 goes in x axis because there is only a
y value

0,12 goes in the y axis because there is only a y value

4.5, 10.6 goes in quadrant I because all the values in quadrant I must be positive.

3,-7 goes in quadrant IV because values in that quadrant will have a negative y value

-15, 12 goes in quadrant II because in that quadrant all the x values are negative.

- 3/4, -4 1/9 goes in quadrant III because in that quadrant both the x and y values are negative.

I recommend you draw a graph like this in your notes just in case you get another question like this, you could also print one out.

Also I apologize if anything is wrong.



I just want the answer :)

Answers

The diagonals of a rectangle are congruent, so RT = SU, that is

3x + 8 = 6x - 4 (subtract 4x from both sides)

3x + 8 = 6x - 4

Subtract 8 from both sides 3x + 8 - 8 = 6x - 4 - 8

Simplifying the above equation, we get

3x = 6x-12

Subtract 6x from both sides 3x - 6x = 6x - 12 - 6x

Simplifying the above equation, we get

-3x = -12

Divide both sides by -3

[tex]$\frac{-3 x}{-3}=\frac{-12}{-3}[/tex]

x = 4

Then, R T= 3x + 8 = 3(4) + 8 = 20

The diagonals bisect each other, then

RV = 0.5 × 20 = 10

∠ RVU = ∠ SVT = 54° ( vertical angles)

RV = UV ( diagonals are congruent and bisect each other)

Then Δ RVU is isosceles with base angles congruent, then

∠ VUR =[tex]$\frac{180-48}{2}[/tex] = 66°.

In the rectangle, RV = 3x+8, SV = 6x-4, and ∠ VRS = 54° then the value of x is 4 and ∠ VUR is 66°.

How to estimate the value of x?

The diagonals of a rectangle are congruent, so RT = SU, that is

3x + 8 = 6x - 4 (subtract 4x from both sides)

3x + 8 = 6x - 4

Subtract 8 from both sides 3x + 8 - 8 = 6x - 4 - 8

Simplifying the above equation, we get

3x = 6x-12

Subtract 6x from both sides 3x - 6x = 6x - 12 - 6x

Simplifying the above equation, we get

-3x = -12

Divide both sides by -3

[tex]$\frac{-3 x}{-3}=\frac{-12}{-3}[/tex]

x = 4

Then, R T= 3x + 8 = 3(4) + 8 = 20

The diagonals bisect each other, then

RV = 0.5 × 20 = 10

∠ RVU = ∠ SVT = 54° ( vertical angles)

RV = UV ( diagonals are congruent and bisect each other)

Then Δ RVU is isosceles with base angles congruent, then

∠ VUR =[tex]$\frac{180-48}{2}[/tex] = 66°.

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The quotient of 2 and a number.

Answers

Answer:

it should be the variable divided by 1. For example, x/2.

Linear ApplicationThe function V(x) = 20.6 +2.2x gives the value (in thousands of dollars) of an investmentafter a months.Interpret the Slope in this situation.The value of this investment is decreasing✓at a rate ofdollars per year V

Answers

SOLUTION:

Case: Interpreting slopes from linear equations

Method:

V(x) = 20.6 + 2.2x

Compared to

y = mx + b

Where m is the slope and it is being interpreted as the rise for every single run on the line graph.

As it applies,

V(x) = 20.6 + 2.2x

m = 2.2 thousand ie. 2200

It is interpreted as the amount the value increases by each month.

Final answer:

The value of this investment is increasing at a rate of $2200 each month

An engineer is designing the parking lot shown below for a local grocery store. The parking spaces are marked with lines where XD←→∥TZ←→∥YF←→∥LP←→ and WC←→− is a transversal. m∠CNL=(6x−17.6)°, m∠FBH=(12y−22)°, and m∠THR=(3x+29.2)°

Answers

Answer:

Step-by-step explanation:

35. If 7-√5 / 7+√5= a +b√5, then find the value of a and b.​

Answers

Answer:a = (27 - 7 √5)/(22) - b √5b = [(22a - 27 + 7√5) √5]/110For finding a = Solve for a by simplifying both sides of the equation, then isolating the variable.b = Solve for b by isolating the variable by dividing each side by factors that don't contain the variable.
Therefore a=27/22 and b=-5/22

Karen made costumes for the annual school play. She used a total length of928.8 in of blue fabric. The fabric came in 2 rolls that each had the samelength. How much fabric was in each roll? Write your answer in yards.Use the table of conversion facts as necessary, and do not round your answer.=Conversion facts for length12 inches (in) = 1 foot (ft)3 feet (ft) = 1 yard (yd)36 inches (in) = 1 yard (yd)5280 feet (ft) = 1 mile (mi)1760 yards (yd) = 1 mile (mi)ydX 5 ?

Answers

[tex]\begin{gathered} \text{total}=928.8\text{ in} \\ total\text{ yd = 928.8 in}\cdot\frac{1yd}{36\text{ in}} \\ total\text{ yd =2}5.8\text{ yd} \\ \text{There were 2 rolls,} \\ \text{roll}=\frac{25.8yd}{2} \\ \text{roll =}12.9\text{ yd} \\ \text{ hence each roll has 12.9 yd} \end{gathered}[/tex]

Which compound inequality is equivalent to the absolute value inequality lbl >6?
hand

Answers

Answer:

b > 6, b < -6

Step-by-step explanation:

Hello!

Using absolute value rules:

|b| > 6; b > 6, b < -6

The compound inequality is as follows: b > 6, b < -6

This makes sense because all values turn positive in the asbolute value. So a number that is negative and less than -6 (say -7), would turn positive to be 7, which is greater than 6.

And any number already greater than 6 will always be greater than 6.

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