A certain copper ore contains 3.24% of Cu2S by mass. In 1991, a single open-air smelt furnace heated 30000 tons of this ore. Compute the mass of copper metal obtained by this process. Enter in tons.

Answers

Answer 1

The mass of the copper that is obtained is 97.2 tons.

What is combustion?

We can define the term combustion as the procedure by which a substance can be burnt in oxygen. We can also be able to refer to the process as roasting the object in the air. It is an oxidation reaction.

Having said all all of these, the reaction equation can be written as;

[tex]Cu_{2} S + O_{2} ------ > 2Cu + SO_{2}[/tex]

We know that the percent of the copper that it contains can now be used when we are trying to compute the mass of the copper that can be obtained from the process as we are going to have in the question that is at hand here to solve.

We are now going to proceed to see the mass of the copper that can be produced from the 300 tons of the copper I sulfide ore given.

Thus;

The mass of copper that can be obtained is;

3.24/100 * 3000 tons

= 97.2 tons

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Related Questions

Which process is not reversible?Dissolving sugar in water Burning butane in a candle lighterMelting waxExtracting iron metal from iron (III) oxide

Answers

Answer

The process that is NOT reversible is Burning butane in a candle lighter

Explanation

All other processes can be reversed

what is the molar mass of anhydrous solid, mol

Answers

what is the molar mass of anhydrous solid, mol?

Convert 8.75X10^-4 to regular number

Answers

To convert the given number to regular notation, we have to move the decimal dot as many times as indicated by the exponent of 10. In this case, that exponent is -4, so we have to move the decimal dot 4 times to the left:

It means that the answer is 0.000875.

10. What is the Arrhenious definition for acids and bases? Why do we use thisdefinition?

Answers

ANSWER

Definition of an acid; is a substance that produced hydrogen ions (H+) as the only positive ion when dissolved in water or in an aqueous solution. it increases the concentration of hydrogen ions in an aqueous solution.

Definition of the base; are hydroxide compounds that give hydroxide ion (OH-) on dissociation in water. it increases the concentration of hydroxide ions in an aqueous solution.

Why do we use the definition: it helps us to understand the acid-base properties of substances in an aqueous medium. neutralization, hydrolysis, and strength of acids and bases

EXPLANATION:

Arrhenius defined acid and base in the following way

According to Arrhenius, he defined an acid as a substance that produced hydrogen ions (H+) as the only positive ion when dissolved in water or in an aqueous solution. it increases the concentration of hydrogen ions in an aqueous solution.

[tex]\begin{gathered} \text{According to Arrhenius} \\ HA_{(aq)}\rightleftarrows H^{+_{}}_{(aq)}+A^-_{(aq)} \end{gathered}[/tex]

Bases are hydroxide compounds that give hydroxide ion (OH-) on dissociation in water. it increases the concentration of hydroxide ions in an aqueous solution.

[tex]\text{BOH}_{(aq)}\rightleftarrows B^+_{(aq)}+OH^-_{(aq)}[/tex]

Arrhenius's definition of acid and base is still in use because it helps us to understand the acid-base properties of substances in an aqueous medium. neutralization, hydrolysis, and strength of acids and bases

Which diagram shows the correct way to represent an ionic compound of magnesium oxide?

Answers

Answer:

C.

Explanation:

The correct way to write the diagram of an ionic compound is:

- Use brackets by writing inside them, the symbol of each element separately.

- Draw the symbol and the number o the charge of each one, negative (-) add positive +()., in this case it is +1 for Mg (because Mg lost an electron) and -1 for O (because O won an elec).

What is the balanced, net ionic equation for the reaction described below?Aqueous sodium phosphate and aqueous iron (III) chloride react to produce aqueous sodium chloride and solid iron (III) phosphate.

Answers

A net ionic equation is the one that only includes the ions that are involved in the formation of the solid.

According to the information the solid formed is iron (III) phosphate, and the ions involved are Fe3+ and PO43-.

It means that the net ionic equation is:

[tex]Fe_{(aq)}^{3+}+PO_{4(aq)}^{3-}\rightarrow FePO_{4(s)}[/tex]

The correct answer is the second choice.

This question is to the Brainly employees: Can you please make it to where it doesn't cover the answer because you have to pay for it. Please and thank you sir or mam.

Answers

Answer:

right

Explanation:

Why does an atom want to form an octet or duet?And yes I know these rules and I know that it “wants” a stable electronic configuration and a filled shell.

Answers

Answer

An atom wants to form an octet or duet because an atom always wants to be in the most stable form. For any atom, stability is achieved by following the octet rule or duet rule, which is to say all atoms (with a few exceptions) want 8 electrons (octet) or 2 electrons (duet) in their outermost electron shell just like noble gases.

April investigated a crime scene where a gunshot sent blood through the air and it splattered on the wall. How would a forensic scientist BEST categorize this blood stain?

A.
transfer

B.
impact

C.
circular

D.
passive

Answers

The forensic scientist best categorize this blood stain by impact. Thus option B is correct.

What is forensic science?

Forensic science is defined as the application of science to criminal and civil laws, with a focus on the criminal side during a criminal investigation as defined by the legal requirements of admissible evidence and criminal procedure.

There are various laws and principles of forensic science.

The laws of individuality and progressive change.Lockard's Exchange PrinciplePrinciple of Comparison: This law is crucial for laboratory investigations.Analytical Principle.The law of probabilityCircumstantial facts law

Thus, the forensic scientist best categorize this blood stain by impact. Thus option B is correct.

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Jade throws a horseshoe toward a stake from the same starting point three different times. She tries to throw the horseshoe with the same amount of force each time. Jade measures the distance each horseshoe lands from the stake. Which distances did Jade likely measure?
Responses

100 in., 200 in., 300 in.



5 in., 25 in., 50 in.





2 in., 100 in., 120 in.

11 in., 12 in., 13 in

Answers

Since Jade tried to throw the horseshoe with the same amount of force, the likely distances that Jade measured would be 11 in., 12 in., 13 in. The last option.

Force and distance

The distance that the horseshoe thrown by Jade travels is a measure of the amount of force that she applies. The more the force, the longer the distance.

However, Jade tried to ensure that the same amount of force is used the 3 times she threw the horseshoe. The consequence is that the distance of the horseshoe from the stake will not vary much in all the 3 throws.

If the distances vary significantly, it means the amount of force used by Jade also differs significantly.

Thus, the only distances that could be a reflection of the relatively constant force used by Jade to throw the horseshoe are 11 in., 12 in., 13 in.

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The half-life of phosphorus−33 is 25.0 days. How much of a 2.7−oz sample of phosphorus−33 will remain after 150 days?

Answers

If phosphorus-33 have an half-life of 25 days the amount of phosphorus-33 that will remain after 150 days is 0.042 oz.

What is half-life?

Half-life is the time taken for half the sample of a radioactive substance to decay.

To calculate the amount of phosphorus-33 that will remain after 150 days, we use the formula below.

Formula:

R' = R/[tex]2^{T/t}[/tex]........ Equation 1

Where:

R = Original amount of phosphorus-33R' = Amount of phosphorus-33 that will remain after 150  daysT = Total timet = half-life

From the question,

Given:

R = 2.7 ozT = 150 dayst = 25 days

Substitute these values into equation 1

R' = 2.7/([tex]2^{150/25[/tex])R' = 2.7/[tex]2^{6}[/tex]R' = 2.7/64R' = 0.042 oz

Hence the amount of phosphorus-33 that will remain after 150 days is 0.042 oz.

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strategies for controlling carbon monoxide are in conflict with strategies for controlling oxides of nitrogen .

Answers

Answer:

I do not know how to answer this question. Is it even a question?

Explanation:

Help I am not sure how to do this number 8

Answers

Answer: The temperature of the gas sample under the conditions given is 30.313 K

Explanation:

The question requires us to determine the temperature, in Kelvins, of a C2H6 gas sample with the following mass, volume and pressure:

mass of C2H6 = m = 561.51g

volume of gas = V = 47.048L

pressure of gas = P = 100.03 kPa

To solve this problem, we can apply the equation of ideal gases rearranged to calculate the temperature, as shown below:

[tex]PV=nRT\rightarrow T=\frac{PV}{nR}[/tex]

where T is the temperature we want to calculate, P corresponds to the pressure of the gas, V is its volume, n is its number of moles and R is the constant of gases (8.314 kPa.L/mol.K).

Note that the only valye that was not provided by the question was the number of moles. We can determine the number of moles n considering the mass of the sample given (561.51g) and the molar mass of the gas C2H6, which we can determine from the atomic masses of C and H.

The atomic masses of C and H are 12.011 and 1.0078 amu, thus we can calculate the molar mass of C2H6 as:

[tex]molar\text{ mass \lparen C}_2H_6)=2\times12.011+6\times1.0078=30.069g/mol[/tex]

Now that we know the mass of the gas sample (561.51 g) and the molar mas of the gas (30.069 g/mol), we can determine the number of moles of gas as it follows:

[tex]\begin{gathered} number\text{ of moles = }\frac{mass\text{ \lparen g\rparen}}{molar\text{ mass \lparen g/mol\rparen}}\rightarrow n=\frac{m}{M} \\ \\ n=\frac{561.51g}{30.069g/mol}=18.674mol \end{gathered}[/tex]

Therefore, the number of moles of C2H6 gas that we need to consider is 18.674 moles.

Next, we can apply the equation of ideal gases to calculate the temperature of the gas:

[tex]\begin{gathered} T=\frac{PV}{nR} \\ \\ T=\frac{(100.03kPa)\times(47.048L)}{(18.674mol)\times(8.314kPa.L/mol.K)}=30.313K \end{gathered}[/tex]

Therefore, the temperature of the gas sample under the conditions given is 30.313 K.

The phenolic indicator (ln-OH) has approximately the same pKa as a carboxylic acid. Which H is the most acidic proton in ln-OH? Circle or otherwise indicate the most acidic proton. Explain why that H is the most acidic proton in ln-OH (i.e. what makes its conjugate base well stabilized)?

Answers

The most acidic hydrogen atom is the hydrogen atom that have been bonded to the oxygen atom.

What is an acidic proton?

We say that a proton is an acidic proton if the proton is able to leave very easily from the rest of the compound. We know that there are several factors that could make a proton that is found in a molecule to become a labile or an acidic proton. The acidity of a proton largely stem from the fact that electron density between the hydrogen atom and the atom to which it is bonded is weak. As such, the bond is weakened by the lengthening of the bond and a consequent lability of the attached hydrogen atom as discussed here.

In the compounds as shown, the most acidic proton is the proton that is attached to the oxygen atom. This is because, the extensive conjugation in the molecule withdraws electrons from  the 0-H bond and this makes the hydrogen atom to become labile or acidic.

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What mass of oxygen can be obtained from heating 163.27G of potassium chlorate?

Answers

Step 1

The reaction involved:

2 KClO3 => 2 KCl + 3 O2 (completed and balanced)

------------

Step 2

Data provided:

Mass of KClO3 = 163.27 g

---

Data needed:

The molar mass of:

KClO3) 122.6 g/mol

O2) 32.00 g/mol

-------------

Step 3

Procedure:

By stoichiometry,

2 KClO3 => 2 KCl + 3 O2

2 x 122.6 g KClO3 ------ 3 x 32.00 g O2

163.27 g KClO3 ------ X

X = 163.27 g KClO3 x 3 x 32.00 g O2/2 x 122.6 g KClO3

X = 63.92 g

Answer: 63.95 g (the nearest value)

can someone please help me with 28 A!

Answers

Answer: The answer for 28 A is [tex][He]2s^2 2p^2[/tex]

28 B is [tex]1s^2 2s^2 2p^1[/tex]

2- The vapor pressure of water at 80°C is 355 torr, Calculate the vapor
pressure of an aqueous solution made by dissolving 50 gm of ethylene
glycol (C₂H5O₂) in 50 gm of water. What is the vapor pressure lowering of
water in this solution?

Answers

The vapor pressure lowering of water in this solution is 1165 torr.


What is vapor pressure?
The pressure that a vapour exerts on its condensed phases in a closed system at a specific temperature is known as the vapour pressure or equilibrium vapour pressure. An indicator of a liquid's evaporation rate is the equilibrium vapour pressure. It has to do with how easily liquid-borne particles tend to elude detection (or solid). Volatile is a term used to describe a chemical that, at room temperature, has a high vapour pressure. Vapor pressure is the force that a vapour cloud exerts over a liquid surface. The kinetic energy of a liquid's molecules increases along with the temperature. The number of molecules vaporising also rises as a function of the molecules' rising kinetic energy, which raises the vapour pressure.

the vapor pressure of water and the mixture is 355 torr and 760 torrs. Therefore, the value of vapor pressure of oxygen would be,

Ptotal=PO2+PH2O

760=PO2+355

760−355=PO2

405=PO2

So, at the temperature, the vapor pressure of  Ethylene is 405 torr.

When volume reduces to 50ml, the pressure of the oxygen would be,

P1V1=P2V2

where P1 and P2 are the pressure and V1 and V2 are the volumes.

P1V1=P2V2

P1V1/V2=P2

405×100 / 50=P2

810=P2

So, when the volume is 50ml the vapor pressure of the oxygen is 810 torr.

Now the total pressure of water-saturated oxygen at 50 ml volume is,

Ptotal=PO2+PH2O

Ptotal=810+355

Ptotal=1165


So, the total vapor pressure is 1165 torr.
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How much water needs to be added to a 8.6317 M NaCl solution to obtain a 1.0421 M solution, if you start with 4.7869 liters of solution?

Answers

The amount of water needed to be added to a 8.6317 M NaCl solution to obtain a 1.0421 M solution starting with 4.7869 liters of solution would be 34.8629 L.

Dilution

The problem here has to do with dilution. The dilution principle states that the number of moles of solute in a solution is constant before and after dilution.

In other words, the dilution principle can be mathematically expressed as:

[tex]m_1v_1[/tex] = [tex]m_2v_2[/tex].

Where [tex]m_1[/tex] and [tex]m_2[/tex] are molarities before and after dilution; [tex]v_1[/tex] and [tex]v_2[/tex] are volumes before and after dilution.

In this case:  [tex]m_1[/tex] = 8.6317 M,  [tex]m_2[/tex]= 1.0421 M,  [tex]v_1[/tex]= 4.7869 L. We are to determine v2.

[tex]v_2[/tex] = [tex]m_1v_1[/tex]/ [tex]m_2[/tex]

    = 8.6317x4.7869/1.0421

    = 39.6498 L

If the final volume of the solution is 39.6498 L and the starting volume is 4.7869, then the amount of water needed can be calculated as:

39.6498 - 4.7869 = 34.8629 L

Thus, the amount of water that will be added to the original solution in order to arrive at the diluted solution is 34.8629 L.

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Sulfur burns in oxygen to form sulfur dioxide. Write a skeleton equation for this chemical reaction.

Answers

A skeletal chemical equation is a representation of a chemical reaction using chemical formulae of reactants and products.

Sulfur = S

Oxygen = O

Sulfur dioxide = SO2

The skeleton equation is:

[tex]S+O_2\text{ }\Rightarrow SO_2[/tex]

Here the skeleton equation = balanced equation.

How many molecules of carbon dioxide, CO2, comprise 1.22 moles?

Answers

How many molecules of carbon dioxide, CO₂, comprise 1.22 moles?

According to Avogadro's Number we have 6.02 * 10^23 molecules in one mol of molecules. So:

1 mol of CO₂ = 6.02 * 10^23 molecules of CO₂

Then:

1.22 moles of CO₂ * 6.02 * 10^23 molecules of CO₂ / 1 mol of CO₂ = 7.34 * 10^23 molecules of CO₂

There are 7.34 * 10^23 molecules of CO₂ in 1.22 moles of it

What is 4.8829g + 121.3 g + 9.384 g . ensure your answer confiding to rules regarding significant figures

Answers

Answer:

[tex]135.6g[/tex]

Explanation:

Here, we want to sum the given values, then give an answer to the correct significant figures

The correct significant figure for addition operation is the significant figure of the number that has the lowest count of values after the decimal places

Looking at the values, the number with the lowest significant figure after the decimal value is 121.3

Thus, our answer will have a value with 1 significant figure after the decimal place

We have it that:

[tex]\begin{gathered} \text{ 4.8829 + 121.3 + 9.384 = 135.5669g} \\ which\text{ finally is:} \\ 135.6g \end{gathered}[/tex]

In a lab experiment, 7.97 g of phosphorus reacts with bromine to form 69.65 g of phosphorus tribromide. How much phosphorus tribromide would be formed if 12.05 g of phosphorus reacted with 61.68 g of bromine? answer:______gi put what i got in the image and it is wrong sorry

Answers

1) List the known and unknown quantities.

First experiment:

Reactants

Phosphorus: 7.97 g.

Bromine: excess.

Product

Phosphorus tribromide: 69.65 g.

Second experiment

Reactants

Phosphorus: 12.05 g.

Bromine: 61.68 g.

Product

Phosphorus tribromide: unknown.

2) Write and balance the chemical equation.

[tex]2P+3Br_2\rightarrow2PBr_3[/tex]

3) Convert the masses.

3.1-Convert the mass of P to moles of P.

The molar mass of P is 30.97 g/mol.

[tex]mol\text{ }P=12.05\text{ }g\text{ }P*\frac{1\text{ }mol\text{ }P}{30.97\text{ }g\text{ }P}=0.38909\text{ }mol\text{ }P[/tex]

3.2-Convert the mass of Br to moles of Br.

The molar mass of Br2 is 159.8080 g/mol.

[tex]mol\text{ }Br_2=61.68\text{ }g\text{ }Br_2*\frac{1\text{ }mol\text{ }Br_2}{159.8080\text{ }g\text{ }Br_2}=0.38596\text{ }mol\text{ }Br_2[/tex]

4) Which is the limiting reactant?

4.1-How many moles of Br2 do we need to use all of the P?

The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.

[tex]mol\text{ }Br_2=0.38909\text{ }mol\text{ }P*\frac{3\text{ }mol\text{ }Br_2}{2\text{ }mol\text{ }P}=0.583635\text{ }mol\text{ }Br_2[/tex]

We need 0.583635 mol Br2 and we have 0.38596 mol Br2. We do not have enough Br2. This is the limiting reactant.

4.2-How many moles of P do we need to use all of the Br2?

The molar ratio between Br2 and P is 3 mol Br2: 2 mol P.

[tex]mol\text{ }P=0.38596\text{ }mol\text{ }Br_2*\frac{2\text{ }mol\text{ }P}{3\text{ }mol\text{ }Br_2}=0.25731\text{ }mol\text{ }P[/tex]

We need 0.25731 mol P and we have 0.38909 mol P. We have enough P. This is the excess reactant.

5) Moles of phosphorus tribromide produced from the limiting reactant.

Limiting reactant: 0.38596 mol Br2.

The molar ratio between Br2 and PBr3 is 3 mol Br2: 2 mol PBr2.

[tex]mol\text{ }PBr_2=0.38596\text{ }mol\text{ }Br_2*\frac{2\text{ }mol\text{ }PBr_3}{3\text{ }mol\text{ }Br_2}=0.25731\text{ }mol\text{ }PBr_3[/tex]

6) Conver the moles of Pbr3 to mass of PBr3.

The molar mass of PBr3 is 270.6858 g/mol.

[tex]g\text{ }PBr_3=0.25731\text{ }PBr_3*\frac{270.6858\text{ }g\text{ }PBr_3}{1\text{ }mol\text{ }PBr_3}=69.6502\text{ }g\text{ }PBr_3[/tex]

The mass of PBr3 produced in the reaction is 69.65 g PBr3.

.

What is the theoretical yield when 1.1134 g of gold (III) oxide is reacted with 20.0 L of H2 at 1.000 atm and 800K.

Answers

The theoretical yield of the gold is 0985 g

What is the theoretical yield?

Recall that the yield is defined as the mass of the product that is obtained in the reaction. Let us recall that a chemical reaction must involve the interaction of the reactants so as to obtain in a given amount, the products of the particular reaction that is in question.

Now;

Number of moles of the gold (III) oxide  = 1.1134 g/442 g/mol = 2.5 * 10^-3 moles

We can get the number of moles of the hydrogen from the ideal gas equation;

PV = nRT

n = PV/RT

n = 1.000 atm  * 20.0 L/0.082 atm LK-1mol-1 *  800K

n = 0.3 moles

Given that the mole ratio of the reaction is 1 mole of the oxide to three moles of hydrogen;

1 mole of gold (III) oxide reacts with 3 moles of hydrogen

2.5 * 10^-3 moles of gold (III) oxide reacts with 2.5 * 10^-3 moles *  3 moles /1 mole

= 7.5 * 10^-3 mole of hydrogen

Hence the hydrogen is present in excess.

The theoretical yield =

1 mole of the oxide produced 2 moles of the gold

2.5 * 10^-3 moles of the oxide produced 2.5 * 10^-3 moles * 2 moles/1 mole

= 5 * 10^-3 moles of gold

Theoretical yield = 5 * 10^-3 moles of gold * 197 g/mol

= 0985 g

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What is TRUE about expert witnesses?

A.
They offer personal and professional knowledge.

B.
They are not allowed to practice their testimony.

C.
They are required to link all evidence to the crime.

D.
They have all written a book about their area of expertise.

Answers

The statement they offer personal and professional knowledge is TRUE about expert witnesses (Option A).

What is the role performed by witnesses?

The specific role performed by witnesses in a given case is to answer questions associated with a subject matter, which are associated with evidence to confirm or reject a given hypothesis.

Therefore, with this data, we can see that the work performed by witnesses is to provide answers in a given subject matter, which is information that may be used as empirical evidence to confirm or reject a given process.

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9) How many ATOMS of fluorine are there in 3.71 moles of nitrogen trifluoride (NF3)? (Hint: this requires two conversions)

Answers

The number of atoms of fluorine present in 3.71 moles of nitrogen trifluoride, NF₃ is 6.7×10²⁴ atoms

How to determine the number of atoms

We'll begin by obtaining the number of moles of fluorine in 3.71 moles of nitrogen trifluoride NF₃. This can be obtained as follow:

1 mole of nitrogen trifluoride, NF₃ contains 3 moles of F

Therefore,

3.71 moles of nitrogen trifluoride, NF₃ will contain = 3.71 × 3 = 11.13 moles of F

Finall, we shall determine the number of atoms of fluorine pressnt in the compound as follow:

From Avogadro's hypothesis,

1 mole of fluorine = 6.02×10²³ atoms

Therefore,

11.13 moles of fluorine = (11.13 moles × 6.02×10²³ atoms) / 1 mole

11.13 moles of fluorine = 6.7×10²⁴ atoms

Thus, from the calculations made above, we can conclude that the number of atoms of fluorine present is 6.7×10²⁴ atoms

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Consider the reaction: 2H2₂0 +
energy --> 2H2 + O₂
exothermic because absorbing
energy
endothermic because absorbing
energy
endothermic because releasing
energy
exothermic because releasing
energy

Answers

Explanation:

endothermic because absorbing

energy

H2O is absorbing heat to release hydrogen and oxygen gas. any reaction that requires energy from outside is endothermic.

Which of the following statements is true? *
The stronger the acid the easier the H+ ions dissociate in solution.
The weaker the acid the easier the H+ ions dissociate in solution.
The stronger the base the easier the H+ ions dissociate in solution.
O The weaker the base the easier the H+ ions dissociate in solution.
4 points

Answers

The stronger the acid the easier the H+ ions dissociate in solution of the following statements is true.

The correct option is A.

Does a stronger acid dissociate more?

Because it almost entirely dissociates, HCl is a powerful acid. A weak acid, such as acetic acid (CH₃COOH), on the other hand, does not dissociate easily in water because numerous H+ ions are still locked up inside the molecule. In conclusion, more free H+ ions are liberated into solution with stronger acids.

Why do more stronger acids than weak acids dissociate?

Strong acids (and bases) are completely dissociated into ions, which is the cause of this. In comparison to weak acids (and bases) of comparable concentrations, they therefore supply more ions for conductivity. An illustration is the complete ionization of a 0.1 M hydrochloric acid solution.

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The complete question is -

Which of the following statements is true?

A-The stronger the acid the easier the H+ ions dissociate in solution.

B-The weaker the acid the easier the H+ ions dissociate in solution.

C-The stronger the base the easier the H+ ions dissociate in solution.

D-The weaker the base the easier the H+ ions dissociate in solution.

Which hydrogen below will have the greatest partial positive charge?Group of answer choicesHIHClHBrHFcannot determine

Answers

The hydrogen bonded to the most electronegative element will have the greatest partial positive charge. This is because electronegativity corresponds to the ability of the nucleus of an atom to attract the electrons involved in a chemical bond.

So the more electronegative, the more partial negative charge the atom will have.

Linus Pauling created a scale of the most electronegative elements, which can be of help in determining the intensity of polarization of different bonds:

F > O > N > C > Br > I > S > C > P > H

In this case, F is the most electronegative element.

So hydrogen will have the greatest partial positive charge bonded to F.

Answer: HF

What is neutralization reaction? Use an example to describe the components of neutralization reaction

Answers

1) Neutralization reaction.

In this type of reaction an acid and a base react to form a salt and water. In the course of the reaction H+ and OH- are produced. Afterward, they combine to produce water.

2) Example.

Acid: HCl

Base: NaOH

Salt: NaCl

[tex]\text{HCl}+\text{NaOH}\rightarrow NaCl+H_2O[/tex]


What is the theoretical yield, in grams, of CO₂, if 29.9 g of C₂ H₂ completely reacts?

Answers

The theoretical yield, in grams, of CO₂ is 93.97g having molar mass 44g

What is molar mass ?

The "counting unit" used by chemists to describe the quantity of atoms, ions, molecules, or formula units in a specific chemical sample is called a mole. The mole is comparable to other counting units you have employed in the past, such as pair (2), dozen (12), and gross (144). Avogadro's number (6.022 x 1023) of molecules (or formula units) make up one mole of a substance (ionic compound). The mass of 1 mole of a chemical is indicated by its molar mass. It provides you with the amount of grammes per mole of a substance, to put it another way. Therefore, grams/mole are the units for molar mass.

2C2H2 + 5O2=====> 4CO2+2H2O

Molar Mass of C2H2 = 2*12+2*2 = 28g = 1 mol

2 mol of C2H2 = 28*2 = 56g

Molar Mass of  CO2 = 12+2*16 = 44g = 1 mol

4 mol of CO2 = 4*44 = 176g

56g of C2H2 gives 176g of CO2

29.9g of C2H2 gives 176*29.9/56g of CO2

                                   = 93.97g of CO2

The theoretical yield, in grams, of CO₂ is 93.97g having molar mass 44g

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