The linear acceleration of the car wheel is 0.735 m/s².
What is the the linear acceleration of car wheel?The linear acceleration of a point on the rim of a wheel is related to the angular acceleration of the wheel by the equation:
a = rα
Where "a" is the linear acceleration, "r" is the radius of the wheel, and "α" is the angular acceleration.
Given the data in the question;
angular acceleration of α = 2.45 rad/s² radius r = 0.3 m. linear acceleration a = ?Plug the given values into the above formula and solve for the linear acceleration of wheel.
a = r × α
a = 0.3 m × 2.45
a = 0.735 m/s²
Therefore, the linear acceleration is 0.735 m/s².
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If a bus is running with a speed of 72km HR calculate the distance traveled in 5 sec Hint acceleration due to gravity 10 meterper second square
Answer:
To solve this problem, we need to use the formula:
distance = initial velocity x time + 1/2 x acceleration x time^2
where:
initial velocity = 72 km/hour (we need to convert this to m/s to use it in the formula)
time = 5 seconds
acceleration = 10 m/s^2 (assuming this is the acceleration due to gravity)
Converting the initial velocity from km/hour to m/s:
72 km/hour = (72 x 1000 m) / (60 x 60 s) = 20 m/s
Now we can plug in the values into the formula:
distance = 20 m/s x 5 s + 1/2 x 10 m/s^2 x (5 s)^2
distance = 100 m + 1/2 x 10 m/s^2 x 25 s^2
distance = 100 m + 125 m
distance = 225 meters
Therefore, the distance traveled by the bus in 5 seconds is 225 meters.
A 60 litre steel gasoline tank is full of gas, so that both the tank and the gasoline
have a temperature of 15 °C. The amount of gasoline has been spilled by the time
they warm up to 35 °C will be:
(A) 50.2 litre
(B) 1.10 litre
(D) None
(C) 3.26 litre
Answer:
To solve this problem, we need to use the coefficient of thermal expansion for gasoline, which tells us how much the volume of gasoline will increase as its temperature increases. The coefficient of thermal expansion for gasoline is approximately 950 x 10^-6 /°C.
Using this information, we can calculate the increase in volume of gasoline as it warms up from 15°C to 35°C:
ΔV = V * α * ΔT
where V is the initial volume of gasoline (60 L), α is the coefficient of thermal expansion for gasoline (950 x 10^-6 /°C), and ΔT is the change in temperature (20°C).
ΔV = 60 * 950 x 10^-6 * 20
ΔV = 0.114 L
Therefore, the amount of gasoline spilled as it warms up from 15°C to 35°C is:
60 L - 0.114 L = 59.886 L
Explanation:
So the answer is (A) 50.2 litre.
Which statement is true for the formation of tides on Earth?
The Sun and Moon are the same distance from Earth and have the same effect on the tides.
The Moon has the greatest effect on tides since it is closer to Earth than the Sun.
The Sun has the greatest effect on tides since it has a greater mass than the Moon.
The Moon has the least effect on tides since it has a smaller mass than the Sun.
Answer:
B
Explanation:
The moon effects the Earth's tides more than the sun.
The correct statement for the formation of tides on Earth is "The Moon has the greatest effect on tides since it is closer to Earth than the Sun."
Tides are caused by the gravitational pull of the Moon and Sun on Earth's oceans.
While the Sun has a greater mass than the Moon, the Moon is much closer to Earth and therefore has a greater effect on the tides.
The Moon's gravitational pull causes the oceans to bulge towards it, creating high tides on the side of Earth closest to the Moon and on the opposite side of Earth.
As Earth rotates, different areas experience high and low tides. The Sun also has an effect on the tides, but it is less significant than the Moon's effect.
In conclusion, the statement "The Moon has the greatest effect on tides since it is closer to Earth than the Sun" is true for the formation of tides on Earth.
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3. with moderate winds, a modern large wind turbine can generate about 250 kw of electricity, whereas a large nuclear power plant can generate 1,000 mw. a. how many wind turbines would be required to give the same output as one nuclear plant?
A modern large wind turbine can generate about 250 kw of electricity, whereas a large nuclear power plant can generate 1,000 mw so, 4000 wind turbines would be required to give the same output as one nuclear power plant.
To know how many wind turbines would be required to give the same output as one nuclear power plant is a simple mathematical calculation that involves only the conversion of kilowatts to megawatts.
Wind turbine and Nuclear power plant electricity generation in modern large wind turbine with moderate winds is 250 KW whereas, the generation capacity of large nuclear power plant is 1,000 MW.
To determine how many wind turbines would be required to give the same output as one nuclear power plant, we need to convert kilowatts to megawatts.
Since 1 MW = 1,000 kW, therefore 1,000 MW = 1,000,000 kW
We are given that a modern large wind turbine can generate about 250 kW of electricity
Therefore, the number of wind turbines required to give the same output as one nuclear power plant can be calculated as:
Number of wind turbines = Total capacity of nuclear power plant / Capacity of single wind turbine
= 1,000,000 / 250= 4000
Thus, 4,000 wind turbines would be required to give the same output as one nuclear power plant.
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Which of the arrows is in the direction of the net force on charge b?
The correct answer is option: e. Because, this force always acts along line joining the two charges. For like charges, the force is repulsive in nature.
The Coulomb's law states how charges interact with each other. That law states that: [tex]F =q1q24πϵ0r2[/tex]
If the charges are like , the force will be repulsive, meaning that each charge will exert a force on the other to push the two of them apart. If charges are opposite , they will exert an attractive force on each other. G or unlike charges, the force is attractive as shown below: ( as Shown in image attached to question), As we know none of the arrow moves in the direction of the net force. Hence, the correct answer is option: e
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Why or why isn’t space exploration important for the people in the movie interstellar? Why or why isn’t space exploration important in todays society? Defend your answer?
In the movie Interstellar, space exploration plays a crucial role in humanity's survival. Earth is on the brink of environmental collapse, and the protagonist, Cooper, must embark on a space mission to find a new habitable planet for humanity.
For the people in the movie, space exploration is not only essential but also the only hope for the survival of the human race.
In today's society, space exploration is also crucial for several reasons. First and foremost, space exploration provides us with a deeper understanding of the universe and our place in it. It allows us to explore the unknown and discover new things, which can lead to breakthroughs in science and technology. Space exploration has already led to countless technological advancements, such as GPS, solar panels, and medical equipment.
Moreover, space exploration has practical applications in areas such as climate change, national security, and disaster response. For instance, satellite imagery can help track natural disasters and aid in disaster response efforts. Satellites can also help us monitor and understand climate change by gathering data on temperature, weather patterns, and greenhouse gas emissions.
Lastly, space exploration inspires and motivates people, especially young people, to pursue careers in science, technology, engineering, and mathematics (STEM) fields. It can also foster international cooperation and collaboration, as countries work together on space missions.
Space exploration is important for both the people in the movie Interstellar and today's society. It can provide us with a deeper understanding of the universe, lead to technological advancements, and have practical applications in areas such as climate change and disaster response. It can also inspire and motivate people to pursue careers in STEM fields and foster international cooperation. Therefore, investing in space exploration is crucial for the betterment of humanity.
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When you press the plunger in and try to move box of chalk / book with your pneumatic what happens?
The pneumatic system is connected to a gripper or clamp that is holding the box of chalk or book, then the plunger's action would cause the gripper or clamp to release the object, allowing it to move.
When you press the plunger on a pneumatic system, such as a pneumatic cylinder, air is forced into the cylinder, causing the piston inside to move outward. If you are using the pneumatic system to move a box of chalk or a book, the outward movement of the piston would cause the attached object to move in the same direction.
However, the movement of the object would also depend on the design and placement of the pneumatic system. For example, if the pneumatic system is connected to a gripper or clamp that is holding the box of chalk or book, then the plunger's action would cause the gripper or clamp to release the object, allowing it to move.
It's also worth noting that the amount of force exerted by the pneumatic system would depend on the pressure and flow of the compressed air, as well as the size and design of the cylinder and piston.
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difference between detached and semi detached binary system
Overall, the difference between detached and semi-detached binary systems lies in the extent to which the stars interact with each other and exchange mass.
What is detached binary system?In a detached binary system, the two stars are far enough apart from each other that they do not significantly interact with each other. The stars have their own gravitational fields, which cause them to orbit around the common center of mass, but they do not exchange significant amounts of mass or significantly alter each other's evolution. Detached binary systems are the most common type of binary systems.
In contrast, in a semi-detached binary system, one of the stars is closer to the common center of mass than the other and is therefore more strongly affected by the gravitational pull of the other star. The closer star can transfer mass to the more distant star, often through an accretion disk, causing the more distant star to become more massive and the closer star to become less massive over time. Semi-detached binary systems can lead to various phenomena such as accretion disks, mass transfer, and outbursts of energy.
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If a net force of 24 N is applied to an object with a mass of 6 kg, then what will the resulting
acceleration be according to Newton's second law of motion?
a
b
C
d
6 m/s²
0.25 m/s²
24 m/s²
4 m/s²
Answer:
d. 4 m/s²
Explanation:
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The weightlifter in question #9 picks up a mass weighing 300kg. What is the pressure that his feet now exert on the floor? (attached image of question 9 for reference)
According to the question, The pressure that the weight lifter's feet now exert on the floor is approximately 431200 Pa.
What is a mass ?The amount of matter in an entity or particle is represented by the dimensionless number mass (symbolized m). The kilogram is the International System's (SI) preferred measure of mass. (kg).
The weight lifter's weight calculated as:
Weight = mass x gravity
Weight lifter's weight = 140 kg x 9.8 m/s^2 = 1372 N
The weight of the mass the weight lifter picks up is:
Weight of the mass = mass x gravity = 300 kg x 9.8 m/s^2 = 2940 N
Therefore, the total weight exerted by the weight lifter and the mass is:
Total weight = Weight lifter's weight + Weight of the mass = 1372 N + 2940 N = 4312 N
The pressure exert on the floor can be calculated as:
Pressure = Force / Area
Assuming the weight lifter's weight is distributed equally on both feet and each foot has an area of approximately 50 cm^2,
the pressure on each foot calculated as:
Pressure on each foot = Total weight / (2 x Area of each foot)
Pressure on each foot = 4312 N / (2 x 50 cm^2 x 0.0001 m^2/cm^2) = 4312 N / 0.01 m^2 = 431200 Pa
Therefore, the pressure that the weight lifter's feet now exert on the floor is approximately 431200 Pa.
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(PLS HELP ME NOW!!!!)
Answer:
the bottom
Explanation:
Bumper car A (296 kg) moving +3.74 m/s makes an elastic collision with bumper car B (222 kg) moving +1.85 m/s. What is the velocity of car A after the collision?
I don't know sorry didn't make me want you say you didn't know how I feel about me being that way and that I didn't even want you say I was wrong and you didn't want me to be to have a good time
a 10 g particle is moving to the left at 28 m/s . how much net work must be done on the particle to cause it to move to the right at 48 m/s ? express your answer with the appropriate units.
To cause the 10 g particle that moves to the left at 28 m/s to move to the right at 48 m/s, the net work that must be done is 7.6 J.
The unit of the net work is Joule (J).
We know that the formula for kinetic energy is given by:
KE=1/2mv^2
where KE is Kinetic energy,
m is the mass of the particle,
v is the velocity of the particle
When a particle changes its direction, its velocity changes from positive to negative.
In this case, the velocity of the 10 g particle changes from -28 m/s to 48 m/s.
We want to find the net work done on the particle. Since no external force acts on the particle, we know that the net work done on the particle is equal to the change in the kinetic energy of the particle.
The initial velocity of the particle is -28 m/s and its mass is 10 g = 0.01 kg.
Therefore, the initial kinetic energy of the particle is
KEi=1/2 * 0.01 * 28^2
=3.92 J
The final velocity of the particle is 48 m/s.
Therefore, the final kinetic energy of the particle is
KEf =1/2 * 0.01 * 48^2
=11.52 J
The change in the kinetic energy of the particle is therefore,
ΔKE = KEf - KEi
=11.52 - 3.92
=7.6 J
This is the net work done on the particle to cause it to move to the right at 48 m/s.
Therefore, the net work that must be done on the particle is 7.6 J. This is the final answer.
However, we need to express the answer in the appropriate unit which is Joule.
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number of electrons with a combined charge of -1 nC
The number of electrons in 1 nenocoulomb (1 nc) charge is 6.24*109. It takes 6 10 18 electrons to produce one coulomb of charge.
What is an electron, for instance?The smallest elemental component of an atom, the electron has a negative charge. In some kind of a negative ion, there are an adequate amounts of electrons as well as protons. One electron but one proton are all that the hydrogen atom has.
What role do electrons play in atoms?The negatively charged components of an atom are called electrons. The total negative charge of an atom's electrons counteracts the positive electrical charge of its protons there in atomic nucleus. When compared to all the other components of the atom, electrons are quite tiny.
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Which of the following variables can be affected if a dielectric, such as a sheet of insulatingplastic material, is inserted into a parallel plate capacitor (charged and disconnected fromthe battery) when compared to a capacitor without the material?i. Capacitanceii. Electric Field between the platesiii. Electric PotentialA. I and III onlyB. II onlyC. I and II onlyD. I. II, and III
The correct answer is D. I, II, and III. All three of the variables listed can be affected if a dielectric is inserted into a parallel plate capacitor.
When a dielectric is inserted into a parallel plate capacitor, the capacitance increases. This is because the dielectric reduces the electric field between the plates, which in turn reduces the potential difference between the plates. This allows for more charge to be stored on the plates for a given potential difference, resulting in an increase in capacitance. The electric field between the plates is also affected when a dielectric is inserted into a parallel plate capacitor. The dielectric reduces the electric field between the plates by reducing the potential difference between the plates.
Finally, the electric potential is also affected when a dielectric is inserted into a parallel plate capacitor. The potential difference between the plates is reduced when a dielectric is inserted, which in turn reduces the electric potential. Therefore, all three of the variables listed - capacitance, electric field, and electric potential - are affected when a dielectric is inserted into a parallel plate capacitor.
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while the above group velocity equation is obtained for 1d crystals, it could be used to estimate group velocity in 3d crystals. show that the young's modulus
The Young's modulus for a 3D crystal can be estimated using the group velocity equation for 1D crystals by making the following assumptions:
The equation for Young's modulus in a 3D crystal is then: E = ρ v2, where ρ is the mass density and v is the group velocity.
The group velocity can be estimated using the group velocity equation for 1D crystals: v = (dω/dK)-1. Here, ω is the angular frequency and K is the wave vector.
By combining these two equations, the Young's modulus for a 3D crystal can be estimated using the group velocity equation for 1D crystals.
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How do I do this page of this worksheet titled “Modeling waves through various mediums”. Just tell me the answers please
A medium is the substance through which a wave travels. Mediums include gases (such as air), liquids (such as water), and solids (such as ropes).
What are the different types of mediums for waves?The medium can be solid, liquid, or gas, and the speed of the wave is determined by the material qualities of the medium. Light, on the other hand, is not a mechanical wave; it may pass through a vacuum, such as the empty areas of space.
Sound waves move the slowest through gases, the fastest through liquids, and the fastest through solids among the three media (gas, liquid, and solid). The speed of sound is also affected by temperature. Gases: The speed of sound is determined by the qualities of the medium through which it travels.
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Polarizing windows, filters, etc. , are often used to reduce the amount of light that enters the lens of a camera or into a room or a car. A library atrium has an overhead skylight that lets in too much light during the day, which heats up the interior of the library far too much. The building engineer installs new double-paned polarizing sky lights to reduce the intensity. If sunlight, which is unpolarized, has an average intensity of 1340 W/m2, what angle should the polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 34% of the original value
The polarizing axis of the second pane of the window make with the polarizing axis of the first pane of the window in order to reduce the intensity of the sunlight to 34% of the original value is [tex]23^o[/tex].
The intensity of the sunlight falling from the first pane
[tex]I_1 = \frac{I_o}{2}[/tex]
Once this intensity light passes through the second pane then
[tex]I_2 = I_1 \cos^2 \thetaI_2 = \frac{I_o}{2} \cos^2 \theta[/tex]
Given I2 /Io = 0.42 (42%) so
[tex]0.42 = \frac{1}{2} \cos^2 \theta\\[/tex]
[tex]\cos^2 \theta = 0.84[/tex]
[tex]\cos \theta = \sqrt{0.84} = 0.9165\\[/tex]
[tex]\theta = \cos^{-1} ( 0.9165) = 23.6^o[/tex]
The polarizing axis, also known as the polarization direction, is the direction of the electric field oscillation of an electromagnetic wave. When light passes through a polarizing filter, only the component of the electric field parallel to the polarizing axis is allowed to pass through, while the perpendicular component is blocked.
For example, a linear polarizing filter has a polarizing axis that allows only light waves oscillating in a specific direction to pass through. If the electric field oscillation of the light is perpendicular to the polarizing axis, it will be blocked, resulting in a darker image. In contrast, circular polarizers have a rotating polarizing axis that can selectively block light waves based on their direction of rotation. This is useful in photography and other applications where glare or reflections need to be minimized.
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In 1–2 sentences, explain why weather can be predicted only as probable, not definite.(2 points)
The amount of information available, the length of time available to examine it, and consequently the complexity of weather occurrences limit one's ability to express their skill to predict the weather.
Why can't weather be forecast other than probabilistically?Models employ estimations and assumptions to forecast the weather because it is impossible to collect data from the future. These estimations from the models get less accurate as time goes on since the atmosphere is continually changing.
What distinguishes a probabilistic forecast from a deterministic one?Probabilistic techniques accurately depict the uncertainty where deterministic plans provide exact average quantities with a known but unquantified uncertainty.
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A laborer wants to move crates containing bottles of olive oil from a truck to the ground by sliding them along a ramp. The ramp is 6 m long and is at an angle of 25°. There is friction on the ramp for the first crate. The laborer doesn’t know that there is a small leak in one of the bottles. The leak leaves a layer of oil on the ramp. The oil creates a frictionless surface for the second crate Wayne sends down the ramp. At the bottom of the ramp, the speed of the second crate (without friction) is 2. 5 the speed of the first crate (with friction). Find the coefficient of kinetic friction. Hint: this is a multistep problem that is be solved using only energy equations. Do not use kinematics or you will not receive full credit, even if your answer is correct. Use conservation of energy and start with the frictionless case. (30 pts)
Therefore, the coefficient of kinetic friction is approximately 0.136
the acceleration of the first crate with friction down the ramp.
We'll use the following formula:
a = gsin(theta) - mucos(theta)*g
whereg = acceleration due to gravity = 9.8 m/[tex]s^2[/tex]
theta = angle of the ramp = 25 degrees
mu = coefficient of kinetic friction
Plugging in the values, we get:
a = 9.8sin(25) - mucos(25)9.8
a = 3.9763 - 3.5299mu
Plugging in the values, we get:
[tex]v^2=[/tex] 0 + 2*(3.9763 - 3.5299*mu)6
[tex]v^2[/tex] = 47.715 - 42.1794mu
the velocity of the second crate without friction at the bottom of the ramp. We know it's 2.5 times the velocity of the first crate with friction, so:v' = 2.5sqrt(47.715 - 42.1794mu)
no friction for the second crate, we can use the conservation of energy to relate the initial potential energy to the final kinetic energy:
mg6sin(25) = 0.5m*[tex]v^2[/tex]
where
g = acceleration due to gravity = 9.8 m/
Simplifying and plugging in the value for v', we get:
mg6sin(25) = 0.5m*)(47.715 - 42.1794mu)
3.5299 = 11.885 - 10.545*mu
mu = 0.136
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Question 4
What mass would a ball need to have if it is thrown at 34 m/s and stops a 78 kg person moving at 3 m/s when they catch it?
Answer:
Let the mass of the ball be m, and let v be the velocity of the ball before it is caught. Let the final velocity of the person and ball be 0 after the catch. We can write the following equation:
(m)(v) + (78 kg)(3 m/s) = (m + 78 kg)(0 m/s)
Simplifying this equation, we get:
(m)(v) = -234 kg m/s
We also know that the initial velocity of the ball is 34 m/s, so we can write another equation using this information:
(m)(34 m/s) = (m)(v)
Substituting the first equation into the second equation, we get:
(m)(34 m/s) = -234 kg m/s
Solving for m, we get:
m = -234 kg m/s / (34 m/s) = -6.88235 kg
This is a negative mass, which doesn't make sense. We made an error in our calculations, possibly due to significant figures. Let's try again with more precision:
(m)(34.0 m/s) = -234 kg m/s
m = -234 kg m/s / 34.0 m/s = 6.88235 kg
Rounding to the appropriate number of significant figures, we get:
m ≈ 6.9 kg
Therefore, the ball would need to have a mass of approximately 6.9 kg in order to stop a 78 kg person moving at 3 m/s when they catch it.
Explanation:
A horizontal pipe of diameter 0.045 m has a smooth constriction to a section of diameter 0.567 m. the density of oil flowing in the pipe is 821 kg/m* if the pressure in the pipe is 8940 n/m and in the constricted section is 6705 n/m?, what is the rate at which oil is flowing?
If the pressure in the pipe is 8940 n/m and in the constricted section is 6705 n/m ,the rate at which oil is flowing is approximately 0.029 m^3/s.
We can use the principle of continuity of flow to relate the flow rate of the oil in the pipe to the difference in pressure and the area of the pipe at the constriction:
Q = Av
where Q is the flow rate, A is the area of the pipe at the constriction, and v is the velocity of the oil at the constriction.
We can use Bernoulli's equation to relate the pressure difference to the velocity of the oil at the constriction:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
where P1 and P2 are the pressures at the two points, and v1 and v2 are the velocities of the oil at those points.
Since the pipe is horizontal, the height difference between the two points can be neglected and we can assume that the gravitational potential energy of the oil is constant. Therefore, we can simplify Bernoulli's equation to:
P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2
Solving for v2, we get:
v2 = sqrt((P1 - P2) / (1/2ρ) + v1^2)
Now we can substitute this expression for v2 into the continuity equation:
Q = Av1 = A sqrt((P1 - P2) / (1/2ρ) + v1^2)
Solving for Q, we get:
Q = A v1 sqrt(2(P1 - P2)/ρ(A^2 - a^2))
where A is the area of the larger section of the pipe and a is the area of the constriction.
Substituting the given values, we get:
Q = (pi/4)(0.567 m)^2 (v1) sqrt(2((8940 N/m^2) - (6705 N/m^2))/(821 kg/m^3)((0.567 m)^2 - (0.045 m)^2))
Q ≈ 0.029 m^3/s
Therefore, the rate at which oil is flowing is approximately 0.029 m^3/s.
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G 13% part (g) using the numbers from the previous step, give a numeric answer for the time in seconds that elapse when the package, initially at rest, travels a distance of 2. 25 m down the ramp
The time required for the container to move 2.25 metres down the ramp is roughly 0.104 seconds.
From part (f), we have determined the final velocity of the package to be 1.38 m/s. Using this value along with the distance traveled (Δx = 2.25 m), we can calculate the time elapsed using the kinematic equation:
Δx = (vf² - vi²) / 2a
Substituting the values, we get:
2.25 = (1.38² - 0) / (2 * 0.087)
Solving for time (t), we get:
t = 2.25 * 0.087 / 1.897
t ≈ 0.104 seconds
Therefore, the time elapsed when the package travels a distance of 2.25 m down the ramp is approximately 0.104 seconds.
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Someone please help me thanks so much!!
The image tubes in television sets and computer displays. Until recently, the picture tube was the most versatile of them, capable of displaying numbers, characters, graphs, and both still and moving images.
Which type of tube is television picture tube?CRT stands for cathode-ray tube. The television image tube, which is used in household television receivers, is the most recognizable and ubiquitous type of cathode-ray tube.
LCD TVs first came in the early 2000s as the newer, superior TV with current technology. Nonetheless, tube Televisions were the most popular at the time. Because it was just 15 years ago, many of these TVs are still in use. We'll go into why you should replace your tube TV and the benefits of doing so further down.
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A 25.00kg lead sphere is hanging from a hook by a thin wire 3.50m long, and is free to swing in a complete circle. Suddenly it is struck horizontally by a 7.00kg steel dart that embeds itself in the lead sphere. What must be the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision?
To find the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision, we can use the conservation of energy principle.
First, let's find the total mass of the system after the collision, which is the sum of the masses of the lead sphere and the steel dart:
m = 25.00 kg + 7.00 kg = 32.00 kg
Next, we need to find the height that the system needs to reach in order to make a complete circular loop. This height is equal to the length of the wire:
h = 3.50 m
Now, we can use the conservation of energy principle to find the minimum initial speed of the dart.
The initial kinetic energy of the system is equal to the final potential energy of the system at the top of the loop:
0.5 * m * v^2 = m * g * h
Solving for v, we get:
v = sqrt(2 * g * h)
Plugging in the values for m, g, and h, we get:
v = sqrt(2 * 9.81 m/s^2 * 3.50 m) = 8.30 m/s
Therefore, the minimum initial speed of the dart so that the combination makes a complete circular loop after the collision is 8.30 m/s.
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will a current necessarily be detected if the cathode is illuminated with blue light? select the correct answer and explanation. will a current necessarily be detected if the cathode is illuminated with blue light? select the correct answer and explanation. photons of blue light have less energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there could be no current with blue light. photons of blue light have more energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there will also be a current with blue light. photons of blue light have less energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there will also be a current with blue light. photons of blue light have more energy than photons of green light. therefore, if there is a current in a photoelectric-effect apparatus with green light, then there could be no current with blue light.
The correct option is (b). Photons of blue light have more energy than photons of green light. So, if there is a current in a photoelectric-effect apparatus with green light, then there will also be a current with blue light.
What is the Photoelectric Effect?The photoelectric effect is the process where a material emits electrons when light is shone on it. The effect is generally associated with the emission of electrons when a metal surface is illuminated. In other words, the photoelectric effect refers to the emission of electrons from a metal when it is illuminated with light.
The energy of each photon is directly proportional to its frequency. Therefore, the photoelectric effect depends on the frequency of the incident light. If the frequency of the light is high enough, electrons can escape the surface of the metal. However, the number of electrons emitted is proportional to the intensity of the light, not its frequency.
Therefore, in this case, the cathode is illuminated with blue light. As photons of blue light have more energy than photons of green light, there will also be a current with blue light.
Thus, a current will necessarily be detected if the cathode is illuminated with blue light since photons of blue light have more energy than photons of green light.
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A) A force of 4. 40 N is applied to a dart over a distance of 54 cm. The dart has a mass of 28 g. Assuming no energy is lost due to friction, what will be the kinetic energy of the dart after it is thrown?
b) Use your result in part a) calculate the speed of the dart
c) If the dart were thrown straight upwards, what maximum height would it reach?
a) The kinetic energy of the dart after it is thrown is 2.376 J.
b) The speed of the dart is 18.45 m/s.
c) If the dart were thrown straight upwards, the maximum height it would reach is 17.0 m.
a) The work done on the dart by the applied force is given by:
work = force x distance = 4.40 N x 0.54 m = 2.376 J
Since no energy is lost due to friction, all of this work is converted to the kinetic energy of the dart:
kinetic energy = work = 2.376 J
b) The kinetic energy of the dart can also be expressed as:
kinetic energy = (1/2) x mass x velocity^2
Rearranging this equation gives:
velocity^2 = (2 x kinetic energy) / mass
Substituting the values from part a) gives:
velocity^2 = (2 x 2.376 J) / 0.028 kg = 340.29 m^2/s^2
Taking the square root of both sides gives:
velocity = 18.45 m/s
c) When the dart is thrown straight upwards, its initial vertical velocity is zero. The maximum height it will reach can be calculated using the formula:
maximum height = (initial velocity^2) / (2 x acceleration)
where acceleration is the acceleration due to gravity, which is approximately 9.81 m/s^2.
Substituting the speed calculated in part b) gives:
maximum height = (18.45 m/s)^2 / (2 x 9.81 m/s^2) = 17.0 m
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Which have the longer wavelength, radio waves or microwaves?
The correct answer in that the Radio waves have a longer wavelength than microwaves.
Radio waves have a wavelength range of about 1 millimeter to 100 kilometers, while microwaves have a wavelength range of about 1 millimeter to 1 meter. This means that radio waves have a longer wavelength than microwaves in general. Wavelength is related to the frequency of the electromagnetic wave by the equation: λ = c / f, where λ is the wavelength, c is the speed of light, and f is the frequency. Since the speed of light is constant, a longer wavelength corresponds to a lower frequency and vice versa. Radio waves are commonly used for communication and broadcasting, while microwaves are used for a variety of applications including cooking food, radar, and wireless communication. Understanding the properties of different electromagnetic waves, including their wavelength and frequency, is important for many areas of science and technology.
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. a resistor r consumes 0.0625 w when it is connected to a 1.50 v battery. a. assuming that r does not change, how much power does the resistor consume when attached to a 12.6 v battery? b. when this resistor is connected to another battery, it consumes 5.00 w. what is the voltage of this battery?
The power consumed by the resistor when it is connected to a 12.5 V battery is 4.41 W and the voltage of the battery is 13.41 V which provides 5 W power to the resistor.
We can use the formula for the power consumption of a resistor:
[tex]P = V^2/R[/tex]
where P is power, V is voltage, and R is resistance.
a. To determine the power consumption of the resistor when attached to a 12.6 V battery, we can use the same formula and solve for P:
[tex]P = V^2/R = (12.6 V)^2 / R[/tex]
However, R is not given in the problem. But we can use the power and voltage values given when the resistor was connected to a 1.5 V battery to find R:
[tex]P = V^2/R[/tex]
[tex]0.0625 W = (1.5 V)^2 / R[/tex]
[tex]R = (1.5 V)^2 / 0.0625\ W[/tex]
[tex]R = 36 \ \Omega[/tex]
Now we can use this value of R to find the power consumption when the resistor is connected to a 12.6 V battery:
[tex]P = V^2/R = (12.6 V)^2 / 36 \ ohms[/tex]
P = 4.41 W
Therefore, the power consumption of the resistor when attached to a 12.6 V battery is approximately 4.41 W.
b. To find the voltage of the battery that consumes 5.00 W, we can use the same formula and solve for V:
[tex]P = (V^2) / R[/tex]
[tex]5.00 W = (V^2) / R[/tex]
We know the value of R from before, so we can substitute it in:
[tex]5.00 W = (V^2) / 36 \ ohms[/tex]
Solving for V, we get:
[tex]V = \sqrt{5.00 W \times 36 \ ohms} = 13.41 V[/tex]
Therefore, the voltage of the battery that consumes 5.00 W is approximately 13.41 V.
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Complete the following sentence: When multiple sources are connected together, their total e.m.f. will be equal to the sum of their individual e.m.fs if they are placed in ______ <, + explanation
Answer:- When they are placed in series.
When multiple emf sources are connected in series then the net or total emf is equal to the sum of their individual emfs .
Say if we have cells of emfs [tex]\epsilon_1[/tex] , [tex]\epsilon_2[/tex] , [tex]\epsilon_3[/tex] , [tex]\epsilon_4 [/tex] . . . . [tex]\epsilon_n[/tex]
Then the net emf is ,
[tex]\implies \underline{\underline{\green{\epsilon_{net}= \epsilon_1+ \epsilon_2+\dots +\epsilon_n}}}\\[/tex]
Additional information:-
If the emfs of n cells are equal and they are connected in series then the net emf is given by ,
[tex]\implies \epsilon_{net}= n\epsilon \\[/tex]
where ,
[tex]\epsilon[/tex] = emf of a single cell .Also , when n cells of emfs [tex]\epsilon_1[/tex] and [tex]\epsilon_2[/tex] . . . . . [tex]\epsilon_n[/tex] and internal resistances [tex]r_1[/tex] , [tex]r_2[/tex] . . . . . [tex]r_n[/tex] respectively are connected in parallel then the net emf is given by,
[tex]\implies \underline{\underline{\green{\epsilon_{net} = \left( \dfrac{1}{r_1}+\dfrac{1}{r_2}+\dots +\dfrac{1}{r_n}\right)^{-1}\left(\dfrac{\epsilon_1}{r_1}+\dfrac{ \epsilon_2}{r_2}+\dots +\dfrac{\epsilon_n}{r_n}\right)}}}\\[/tex]
Again suppose if we make a parallel arrangement of cells each having same emf then the net emf remains same that is equal to the emf of individual cell ( Why ? You can try yourself by using the above formula )
and we are done!