A car starts from point A, goes 100 km to point B, immediately turns around, and returns to point A. The round trip takes 4 hours.
What is the average speed of the car?

Answers

Answer 1

Answer:

50 km/h

Explanation:

200 km = 4 hours

200/4=50

50km/h


Related Questions

a hiker walks westward 2 meters and then eastward 7 meters. for this motion the distance moved is?​

Answers

Answer:

d = 9 [m]

Explanation:

This is a problem where we must be clear about the concept of distance, which tells us that it is a measure of the space traveled on a trajectory.

Therefore:

d = 2 + 7

d = 9 [m]

The directions are not taken into account, as it is the sum of the displacements traveled, regardless of their directions.

According to Steinberg, which of the following statements is true about creative people


They appreciate art and music.
They always take popular stands.
They accept ideas at fàce value.
They accept their limitations,

Answers

They appreciate art and music

In simple harmonic motion, the acceleration is proportional to In simple harmonic motion, the acceleration is proportional to:_________.
a. the amplitude.
b. the velocity.
c. the frequency.
d. the displacement.
e. all of the above

Answers

Answer:

e. all of the above

Explanation:

In simple harmonic motion, the acceleration is given as;

a = -ω²x = -(2πf)²x

[tex]a_{max} = -\omega ^2A[/tex]

where;

ω is the angular velocity

f is the frequency

x is the displacement

A is the amplitude

Thus, In simple harmonic motion, the acceleration is proportional to the amplitude, velocity, frequency, and displacement.

The correct option is E.

"all of the above"


Through what angle in degrees does a 33 rpm record turn in 0.32 s?
63°
35°
46°
74°

Answers

Answer:

1 rev = 2(pi) rad  pi(rad) = 180 degrees

so 33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s = 63.36 degrees

Explanation:

63.36 estimated to 63 so 63

The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.

Calculation of the angle:Since we know that

1 rev = 2(pi) rad

So here  pi(rad) = 180 degrees

Now for 33 rpm it should be like

=  33 rev/min * 1 min/60s * (2*pi)rad/1 rev *180 deg/ pi rad * .32 s

= 63.36 degrees

= 63 degrees

hence, The angle in degrees where 33 rpm record turn in 0.32 s should be considered as the 63 degrees.

Learn more about an angle here: https://brainly.com/question/3394547

A 1.2-kg object moving with a speed of 8.0 m/s collides perpendicularly with a wall and emerges with a speed of 6.0 m/s in the opposite direction. If the object is in contact with the wall for 2.0 ms, what is the magnitude of the average force on the object by the wall?
a. 9.8 kN.
b. 8.4 kN.
c. 7.7 kN.
d. 9.1 kN.
e. 1.2 kN.

Answers

Given that,

Mass of the object, m = 1.2 kg

Initial speed of the object, u = 8 m/s

Final speed of the object, v = -6 m/s (in opposite direction)

Time, t = 2 ms

To find,

The average force on the object by the wall.

Solution,

Let F be the force. Using Newton's second law of motion,

F = ma, a is acceleration

[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{1.2\times ((-6)-8)}{2\times 10^{-3}}\\\\=8400\ N[/tex]

or

F = 8.4 N

So, the magnitude of average force in the object by the wall is 8.4 N.

Help me please..

Velocity is defined as a
and a?

A) speed, direction

B) change, direction

C) speed, acceleration

D) change, acceleration

Answers

it’s A speed in a given direction

Answer:

Speed and direction.....

For a polymer that was maintained at constant strain, an initial stress of 2.76 MPa decreases to 1.72 MPa after 6 hr. Estimate the stress remaining after 30 hr.

Answers

Answer:

1.48 Mpa

Explanation:

Given that For a polymer that was maintained at constant strain, an initial stress of 2.76 MPa decreases to 1.72 MPa after 6 hr. To estimate the stress remaining after 30 hr, we must first find the decay constant by using the exponential equation.

Therefore, the estimate of the stress remaining after 30 hr, is 1.48Mpa.

Please find the attached file for the solution.

What is the condition required of the phase difference (in radians) between two waves with the same wavelength if these waves interfere constructively?
a. (2m +1)π where m= 0, +1, +2, etc.
b. mπ where m = 0, +1, +2, etc.
c. 2mπ where m = 0, +1, +2, etc.
d. (m+1)π where m = 0, +1, +2, etc.

Answers

Answer:

c.

Explanation:

In order to two waves with the same wavelength can interfere constructively, their crests and valleys must coincide in space, so the phase difference must be equal to an integer number of wavelengths, i.e. m *(2 π rad), where m= 0, +1, +2, etc.This is equal to the stated by the answer c) , so c) it's the right answer.

*
If a rock falls for 3 seconds off of a bridge, how far will the rock fall?
-30 m
-45m
-60m
-75m

Answers

It will fall for about 45m

Pure sodium metal explodes when it makes contact with water, and chlorine, in its natural state, is a deadly, poisonous gas. When these two chemicals combine, they form a harmless, white powder known as sodium chloride or table salt. Which of the following statements does this information support?

A.The properties of substances change during chemical reactions but then later go back to their original condition.

B.Heat must be added in order to change the chemical properties of substances.

C.When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.

D.When substances are chemically combined, the properties of the new substances that are formed are the same as the properties of the original substances.

Answers

Answer: When substances are chemically combined, the properties of the new substances that are formed are often different from the properties of the original substances.

Explanation:

Match the scienntist with their accomplishment / discoveries

Answers

Answer:

newton - motion, gravity

kepler - orbital paths

brahe - the sun goes around the earth

Explanation:

im not sure about brahe but its the only one that makes sense

A tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward.

Determine the magnitude of the distance the object traveled and the magnitude and direction of the displacement.

Answers

Answer:

The answer is 8m N

Explanation:

When a tennis ball moves 16 meters northward, then 22 meters southward, then 12 meters northward, and finally 32 meters southward. then the distance traveled by it is 82 m and the displacement covered by it is 26 m in a southward direction

What is displacement?

An object's position changes if it moves in relation to a reference frame, such as when a passenger moves to the back of an airplane or a professor moves to the right in relation to a whiteboard. Displacement describes this shift in location.

Displacement is a vector quantity. This indicates that it has both a direction and a magnitude and that it is visually represented as an arrow that points from the starting position to the ending position.

Thus, when a tennis ball travels 16 meters to the north, 22 meters to the south, 12 meters to the north, and 32 meters to the south. then it has a covered distance of  82 meters and has covered 26 meters of displacement in a southerly direction.

Learn more about displacement here

https://brainly.com/question/10919017

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what is mean by combination reaction ?​​

Answers

[tex] \underline{\purple{\large \sf Combination \: reaction :-}} [/tex]

Those reaction in which two or more substances combine to form a one new substance are called Combination reaction

In this reaction, We can add :

Two or more elements can combine to form a compound.Two or more compounds can combine to from a one new compound.An element and a compound can combine to form a new compound.

[tex] \underline{\green{\large \sf For\: example :}} [/tex]

[tex] \sf 2H_{2} + O_{2} \: \underrightarrow{Combination} \: 2H_{2}o[/tex]

In this, Hydrogen is an element and Oxygen is another element. Both are combined to form compound 'Hydrogen oxide'. Hydrogen oxide is commonly known as water.

20 pts.





Which of the following statements is true?
O Electromagnets use electrlcity and magnets.
O Magnetic fields are strongest around the poles of a magnet.
O The south pole of a magnet will repel the south pole of another magnet.
O all of the above

Answers

Answer:

all are true so d is right

Explanation:

Electromagnets use electrlcity and magnets is true.

Magnetic fields are strongest around the poles of a magnet is true.

The south pole of a magnet will repel the south pole of another magnet is true

and since all of them is true the answer is d all of the above

The speed of sound in air is 10 times faster than the speed of a wave on a certain string. The density of the string is 0.002kg/m. The tension in the string is __________.

Answers

Answer:

The tension on the string is 2.353 N.

Explanation:

Given;

the speed of sound in air, v₀ = 343 m/s

then, the speed of sound on the string, v = 343 / 10 = 34.3 m/s

mass per unit length, m/l = μ = 0.002 kg/m

The speed of sound on the string is given as;

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu} \\\\T = v^2 \mu[/tex]

where;

T is the tension on the string

T = (34.3)²(0.002)

T = 2.353 N

Therefore, the tension on the string is 2.353 N.

true or false The most extreme tides occur during a new
moon and full moon.

Answers

Answer:

true

Explanation:

An airplane flies eastward and always accelerates at a constant rate. At one position along its path, it has a velocity of 28.3 m/s. It then flies a further distance of 48900 m, and afterwards, its velocity is 45.5 m/s. Find the airplane's acceleration (m/s^2) and calculate how much time elapses (s) while the airplane covers those 40500 m.

Answers

Answer:

a==0.012979m/s^2

t=662.6s

Explanation:

.

Using the Newton equation below

Vf^2 = Vi^2 + 2as

Where Vf= final velocity

Vi= initial velocity

a= acceleration

Vf=45.5 m/s

Vi=28.3 m/s

Xf=48900 m,

Xi=0

a= (Vf^2 - Vi^2)/2s

If we substitute the values,

a=(45.5^2 -28.3^2)/(2×48900)

=(2070.25-800.88)/(2×48900)

=

a= 1269.36/97800

=0.012979m/s^2

Hence, the airplane's acceleration (m/s^2) is =0.012979m/s^2

Using the Newton equation we can calculate the time

a=(vf - vi) /t

Making "t" subject of the formula, we have

t=(vf - vi) /a

a=0.012979m/s^2

If we substitute the values, where

, we have

t= (45.5-28.3)/(2×=0.012979)

=17.2/0.025958

=662.6s

Hence, time elapses (s) while the airplane covers those 40500 m. Is =662.6s

Suppose a uniform solid sphere of mass M and radius R rolls without slipping down an inclined plane starting from rest. The linear velocity of the sphere at the bottom of the incline depends on?

Answers

Answer:

None of the mass or the radius of the sphere

Explanation:

When a uniform solid sphere of any given mass, say M and any given radius, say R, rolls without slipping downwards an inclined plane that starts from rest. The linear velocity of the sphere at about the bottom of the inclined happens not to depend on either of its mass or that of the radius of its sphere.

PHYSICS! HELP ME PLEASE ASAP!

1.) If an ambulance passes you while you're walking your dog, a change in pitch is ____?
A.) not perceived by either the pedestrian or you
B.) perceived by the you
C.) perceived by the driver

2.) In the star wars movies, the soundtrack is very important. musicians and sound technicians spend weeks perfecting the noise of the light sabers, lasers, tie fighters and explosions. in real life, there would be no sound at all in space. Why?
A.) mechanical waves require a medium to travel
B.) sound is an electromagnetic wave
C.) mechanical waves do not require a medium to travel
D.) sound is a product of vibration

3.) what is a compression?
A.) region of zero pressure in a medium caused by a wave passing
B.)region of a high altitude in a medium caused by a passing wave
C.) region of a high pressure in a medium cause by a passing wave
D.) region of low pressure in a medium caused by a passing wave

Answers

Answer:

1B, 2B and 3C hope this helps

Explanation:



A popular ride at an amusment park lifts
customers up to a height of 50 m and then
drops them threw a displacement of 50 m
before slowing them to a stop. How fast
are the customers going at the 50 m
mark?

Answers

Answer:

[tex]31.32\ m/s[/tex]

Explanation:

[tex]We\ are\ given\ that:\\Height\ to\ which\ there're\ lifted=50m\\Displacement\ during\ the\ descent=50m\\Now,\\In\ order\ to\ find\ the\ velocity\ of\ the\ customers\ at\ 50\ m,\\We\ can\ use\ the\ Third\ Equation\ Of\ Motion,\ which is:\\2as=v^2-u^2\\As\ we\ know\ that,\\Acceleration\ due\ to\ gravity=9.81\ m/s^2\ or\ roughly\ 10\ m/s^2\\Displacement=50\ m\\Initial\ velocity=0\ m/s^2\\ [As\ they\ stop\ when\ they\ reach\ the\ maximum\ height\ of\ 50\ m\\ and\ begin\ their\ descent][/tex]

[tex]By\ reconstructing\ the\ Third\ Equation\ Of\ Motion,\ we\ have:\\2gs=v^2\\Hence,\\v^2=2*9.81*50 \\v^2=981\ m^2/s^2 \\v=\sqrt{981\ m^2/s^2} \\v=31.32\ m/s[/tex]

What electromagnetic wave is a is a TV remtoe

Answers

Answer:

infared radiation

Explanation:

Two motorcycles are traveling due east with different velocities. However, 3.63 seconds later, they have the same velocity. During this 3.63-second interval, motorcycle A has an average acceleration of 4.55 m/s2 due east, while motorcycle B has an average acceleration of 18.9 m/s2 due east. (a) By how much did the speeds differ at the beginning of the 3.63-second interval, and (b) which motorcycle was moving faster

Answers

Answer:

52.095 m/s

Motorcycle a was moving faster

Explanation:

We start by using one of the equations of motion

V = u + at

If the first motorcycle starts with an initial speed of u(a) and accelerates at a value of a(a) = 4.55 m/s², then the final speed after a time of 3.63 seconds is V(a). We then represent it as

V(a) = u(a) + a(a).t

If the second motorcycle starts with an initial speed of u(b) and accelerates at a value of a(b) = 18.9 m/s², then the final speed after a time of 3.63 seconds is V(b). We then represent it as

V(b) = u(b) + a(b).t

Assuming that the final speeds v(a) = v(b), and then subtract the equation of the second motorcycle from that of the first, we have

0 = u(a) - u(b) + a(a).t - a(b).t

-u(a) + u(b) = a(a).t - a(b).t, on rearranging, we have

u(b) - u(a) = [a(a) - a(b)]t

Since we have the values for acceleration and the time, we substitute so that

u(b) - u(a) = (4.55 - 18.9)3.63

u(b) - u(a) = -14.35 * 3.63

u(b) - u(a) = -52.095, or we rearrange to get

u(a) - u(b) = 52.095 m/s

An airplane wing is designed so that the speed of the air across the top of the wing is 297 m/s when the speed of the air below the wing is 209 m/s. The density of the air is 1.29 kg/m3. What is the lifting force on a wing of area 26.0 m2?

Answers

Answer:

The value is   [tex]F_L = 759200 \ N[/tex]

Explanation:

From the question we are told that

   The speed of air across the top of its wings is  [tex]v = 297 \ m/s[/tex]

   The speed of air below  its wings is [tex]u = 209 \ m/s[/tex]

    The density of air is [tex]\rho = 1.29 \ kg/m^3[/tex]

     The area of the wing is  [tex]A = 26.0 \ m^2[/tex]

Generally the lifting force is mathematically represented as

             [tex]F_L = \Delta P * A[/tex]

Here  [tex]\Delta P[/tex] is the difference in kinetic energy density between the top and the bottom  

   [tex]\Delta P = \frac{1}{2} * \rho * [v^2 - u^2 ][/tex]              

=>     [tex]\Delta P = \frac{1}{2} * 1.29 * [297^2 - 209^2 ][/tex]

=>     [tex]\Delta P = 2.92 *10^{4} \ Pa[/tex]

So  

      [tex]F_L = 2.92 *10^{4} * 26.0[/tex]

=>   [tex]F_L = 759200 \ N[/tex]

Find the current if 55 C of charge pass a particular point in a circuit in 5 seconds.

Answers

Answer:

The current is 11 Amperes

Explanation:

Electric Current

The electric current is defined as a stream of charged particles that move through a conductive path.

The current intensity can be calculated as:

[tex]\displaystyle I=\frac{Q}{t}[/tex]

Where:

Q = Electric charge

t   = Time taken by the charge to move through the conductor

The current intensity is often measured in Amperes.

The charge passing through a point in a circuit is Q= 55 c during t=5 seconds, thus the current intensity is:

[tex]\displaystyle I=\frac{55}{5}[/tex]

I = 11 Amp

The current is 11 Amperes

Define conductor and insulator, including how the resistance is different in the two, and give at least one example of each.

Answers

Answer:

Those substances which can conduct electricity are called conductors, while those substances which don't conduct electricity are called insulators.

Resistance is the obstruction provided by the material through which the current passes,so since conductors conduct electricity and insulators don't,so the obstruction i.e resistance provided by the conductor must be less,while insulators being unable to conduct electricity,has very high resistance.

Example of conductor is copper

Example of insulator is plastic

WILL MARK BRAINLIEST JUST PLEASE HELP

Answers

Answer:

40N in either direction is the answer

The Third choice 40n in either direction will be your answer. Hope this helped. Have a great day!

A force of 64 N gives an object an acceleration of 23.53 m/s^2. What is the mass of the object?
A-2.00 kg
B-1505 kg
C-2.72 kg
D-736 kg

Answers

D is the right answer for this I think

A carousel at the local carnival rotates once every 45 seconds.
(a) What is the linear speed of an outer horse on the carousel, which is 2.75 m from the axis of rotation?
(b) What is the linear speed of an inner horse that is 1.75 m from the axis of rotation?

Answers

Answer:

We know that the carousel does a complete rotation in 45 seconds.

Then the frequency of this carousel will be f =  1/45 seconds.

And the angular frequency will be 2*pi times the frequency, then we have:

angular frequency = w = 2*3.14*(1/45s) = 0.1396 s^-1

Now, the linear speed of an object that rotates with a radius R, and an angular frequency W is:

S = R*W

then:

a) in this case the radius is 2.75m, then the linear speed is:

S = 2.75m*0.1396 s^-1 = 0.3839 m/s

b) in this case the radius is 1.75m, then the linear speed here is:

S = 1.75m*0.1396 s^-1 = 0.2443 m/s

(a) The linear speed of an outer horse on the carousel is 0.384 m/s.

(b) The linear speed of an inner horse on the carousel is 0.244 m/s.

Given data:

The time interval for the rotation of carousel is, t = 45 s.

The distance of the outer horse from the axis of rotation is, r = 2.75 m.

The distance of an inner horse from the axis of rotation is, r' = 1.75 m.

(a)

The linear speed in this problem can be obtained from the concept of rotational mechanic, in which the ratio of the circumference and the time gives required linear speed. So,

v = 2 π r/t

Solving as,

v = 2 π (2.75) / 45

v = 0.384 m/s

Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.384 m/s.

(b)

Now similarly the linear speed of an inner horse is calculated as,

v' = 2 π r' / t

Solving as,

v' = 2 π (1.75) / 45

v' = 0.244 m/s

Thus, we can conclude that the linear speed of an outer horse on the carousel is 0.244 m/s.

Learn more about the rotational mechanics here:

https://brainly.com/question/18303026

The average speed of a car that drives 140 kilometers in 2 hours

Answers

Answer:

240 kilometer

Explanation:

ur just mutipling the number by 2

Your average speed was 70.0 Kilometers per hour (km/h)

Help me please,

A ball is thrown straight up in the air. What is the velocity and acceleration at the top of the path?

A) v 0m/s, = 0m/s/s

B) v = 0m/s, a 10m/s/s

C) v = 10m/s, a 10m/s/s

D) v = 10m/s, a = 0m/s/s

E) None of the above

Answers

Option B

Explanation:

no distance was given only the acceleration due to the fact that it went up (10m/s/s)

s0 it is

0 m/s and 10m/s/s (option B)

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