During the collision an impulse is created which due to which is equal to change in momentum.
Mathematically,
[tex]\green{ \underline { \boxed{ \sf{Impulse, F\times t = m (v-u) }}}}[/tex]
where
F = forcet = time span m = massv= final speedu = initial speedNow,
[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times (0-30) \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F \times 0.4 = 850 \times -30 \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F = -\frac{25500}{0.4} \\\end{gathered} [/tex]
[tex]\begin{gathered}\\\implies\quad \sf F = -63750 N \\\end{gathered} [/tex]
[tex]\quad\quad\quad\quad\quad\quad[/tex](-ve sign denotes opposite direction)
Therefore, a force of 63750 Newton will act on the car in opposite direction.
A microwave has a period 0.000015 s has a wavelenth of ?
(Round your answer to the nearest hundreth. Add a zero to the begining of the number if necessary.)
Answer:
30 cm to 1 mm
Explanation:
30 cm to 1 mm
The electric field is measured for points at distances r from the center of a uniformly charged insulating sphere that has volume charge densi
For the electric field is measured for points at distances r,Electric field is mathematically given as
E=19.9*10^{-5}c/m^3
What is the Electric field?Generally, the equation for the electric field uniform charged is mathematically given as
[tex]E=\frac{lr}{3e0}[/tex]
Therefore
E=lr/3E0=3Ee0/r
Therefore
E=3*6*10^4*8.85*10^{-12}
E=19.9*10^{-5}c/m^3
In conclusion, E=19.9*10^{-5}c/m^3
E=19.9*10^{-5}c/m^3
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CQ
Complete question attached below
Franklin is loading a truck at work and his truck has a ramp that helps him move the boxes up. the incline of the ramp is 9 feet long and the top of the ramp is 3 feet off of the ground. what is the mechanical advantage of the incline franklin is using?
Answer:
Explanation:
Formula
MA = length of ramp / height
Givens
ramp length = 9 feet
height = 3 feet
Solution
MA = 9 / 3
MA = 3
Answer Mechanical advantage = 3
A car of mass 1200kg moving 90km/hr is brought to rest over a distance of 20m. calculate breaking force.
Answer:
-18,750N
Explanation:
90x1000
-------------
3600
u=25m/s
v=0m/s
v^2=u^2+2as
v=0
=625+(2×a×20)
625+40a
-625=40a
a= -15.625 m/s^2
F=ma
=(1200)(-15.625)
= -18,750N
A coin has a mass of 7.0g. It is made of a metal alloy of density 5.6g/cm3. Calculate the volume of the coin.
[tex]\text{Density,}\\\\~~~~~~~~\rho = \dfrac mV\\\\\\\implies V = \dfrac m{\rho}\\\\\\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{\tfrac{5.6 \times 10^{-3}~ \text{kg}}{ 10^{-6} ~\text{m}^3} }\\\\ \\\implies V = \dfrac{7 \times 10^{-3}~ \text{kg}}{5.6 \times 10^{-3} \times 10^6~~ \text{kg}~ \text{m}^{-3}}\\\\\\ \implies V = 1.25 \times 10^{-6}~ \text m^3\\\\\\\implies V =0.00000125~ \text m^3\\\\\text{Hence the volume of the coin is 0.00000125}~ \text m^3[/tex]
What is current of 12 ohm? help me pleasee
Answer:
Current for 12 ohms = 2.5
Explanation:
Ohm's Law:
Voltage = IR
Current = V/R
Resistance = V/I
Therefore, current = 30V/12 Ohms
30/12 = 2.5
So current for 12 ohms = 2.5
I hope this helps :>
hey guys can y’all help quickly?
how to induce a positive temporary charge on the right side of a metal ball
Answer:
Temporary? You have two options
If you have a positively charged object, bring it close to the LEFT side of the ball (not touching it!).
If you have a negatively charged object, bring it close to the RIGHT side of the ball (again, not in contact).
Either way, the electron cloud will migrate towards the right side of the of your sphere.
Another option is to have a capacitor large enough to house the sphere inside it, and polarize it by attaching it to a DC source making sure that the negative plate of it is to the right of the sphere.
Is distance a vector quantity
Explanation:
Nope, displacement is a vector quantity, whereas distance is the scalar (magnitude) of the total displacement.
Hope this clears things up :))
An iron sphere of radius 0.18m has mass 190 kg. Calculate the density of the iron
Volume:-
[tex]\\ \sf\rightarrowtail \dfrac{4}{3}\pi r^3[/tex]
[tex]\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.18)^3[/tex]
[tex]\\ \sf\rightarrowtail \dfrac{4}{3}\pi (0.005832)[/tex]
[tex]\\ \sf\rightarrowtail 0.024m^3[/tex]
Mass=190kgDensity:-
[tex]\\ \sf\rightarrowtail \dfrac{Mass}{Volume}[/tex]
[tex]\\ \sf\rightarrowtail \dfrac{190}{0.024}[/tex]
[tex]\\ \sf\rightarrowtail 7916.67kg/m^3[/tex]
What is the electric potential energy of a charge that experiences a force of 3. 6 × 10–4 N when it is 9. 8 × 10–5 m from the source of the electric field? 3. 5 × 10–8 J 4. 6 × 10–4 J 2. 7 × 10–1 J 3. 7 × 100 J.
The electric potential energy of the charge will be =3.5*10^8 J
What is Electric potential energy?Electric potential energy is the energy that is needed to move a charge against an electric field.
F=Force experienced by the charge = 3.6*10^-4 N
q1 = magnitude of charge producing the electric field
q2 = magnitude of charge experiencing the electric force
r1 = distance between the two charges
Electric force experienced by the charge is given using coulomb's law as
[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]
[tex]3.6\times 10^{-4}=\dfrac{9\times 10^9 q_1q_2}{(9.8\times 10^{-5})^2}[/tex]
[tex]q_1q_2=3.84\times 10^{-22}[/tex]
Electric potential energy of the charge can be given as
[tex]U=\dfrac{kq_1q_2}{r}[/tex]
[tex]U=\dfrac{(9\times 10^9)q_1q_2}{(9.8\times 10^{-5})^2}[/tex]
[tex]U=3.5\times 10^{-8}\ J[/tex]
Thus Electric potential energy of the charge can be given as [tex]U=3.5\times 10^{-8}\ J[/tex]
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a 600kg wrecking ball is swinging from a crane as shown. When the wrecking ball reached the bottom of the path, the wrecking ball is moving 10m/s
Answer:
Explanation:
The picture is cut off so the wrecking ball and its path are not shown. It would be better if the whole picture is available.
Based on the written info, at the bottom of the path, the wrecking ball is moving at 10m/s.
The centripetal acceleration = velocity^2 / radius
= 10^2 / 25
= 100 / 25
= 4m/s^2
The centripetal force = mass * centripetal acceleration
= 600*4
= 2400N
As the ball is moving horizontally at the bottom, net vertical force is zero.
So Tension force in cable = Wrecking ball weight + Centripetal force
= 600*g + 2400
= 6000 + 2400; assuming g is 10m/s^2
= 8400N
Ring of mass straight m and radius straight r is attached to the end of a thin rod of mass straight m and radius 2 straight r
The total moment of inertia about an axis is : [tex]L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}[/tex] for a ring of mass m and radius straight r attached to a thin rod.
Determine the Total moment of Inertia about an axisGiven data:
mass of ring --> m
radius of ring --> r
mass of rod --> M
Length of rod ---> L ( 2 * radius )
Total Moment of Inertia about an axis = Irod + Iring
where : Irod = moment of inertia of rod, Iring = moment of inertia of ring
Irod = ML² / 3
Iring = 2mr² / 5
moment of inertia around an axis by Iring = I
where ; I = 2mr² / 5 + ML² according to parallel axis theorem
Hence the Total moment of Inertia about an axis is :
Itotal = 2mr²/5 + ML² + ML² / 3
= [tex]L^{2} ( \frac{M}{3} + m ) + \frac{2mr^2}{5}[/tex]
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For a ring of mass m and radius straight r connected to a thin rod, the total moment of inertia about an axis is [tex]\rm I= L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex].
What is a moment of inertia?The sum of the products of the mass of each particle in the body with the square of its distance from the axis of rotation expresses a body's tendency to resist angular acceleration.
The given data in the problem is;
m is the ring's mass.
r is the radius of a ring.
L is the rod length = 2r
The total Moment of Inertia about an axis;
[tex]\rm I = I_{rod}+I_{ring} \\\\ \rm I =\frac{ML^2}{3} +\frac{2mr^2}{5}[/tex]
According to the parallel axis theorem,
[tex]\rm I = \frac{2mr^2}{5} + ML^2[/tex]
The total Moment of Inertia about an axis will be;
[tex]\rm I_{total} = \frac{ML^2}{3} +\frac{2mr^2}{5}+ML^2 \\\\ \rm I_{total} =L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex]
Hence for a ring of mass m and radius straight r connected to a thin rod, the total moment of inertia about an axis is [tex]\rm I= L^2 (\frac{M}{3} +m)+\frac{2mr^2}{5}[/tex].
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What are radio isotopes??
Give one example of a radio isotope State one use too..
Don't spam..
Answer:
An isotope is one of two or more species of atoms of a chemical element with the same atomic number and position in the periodic table and nearly identical chemical behavior but with different atomic masses and physical properties. In medicine, for example, cobalt-60 is extensively employed as a radiation source to arrest the development of cancer. Other radioactive isotopes are used as tracers for diagnostic purposes as well as in research on metabolic processes.
Hope this helps! Please let me know if you need more help, or if you think my answer is incorrect. Brainliest would be MUCH appreciated. Have a wonderful day!
Those isotopes which are unstable due to the presence of extra neutrons in their nuclei and emit various types of radiations are called radioactive isotopes. The radiations emitted are in the form of alpha particles, beta particles and gamma rays.
For eg :- carbon,hydrogen and chlorine.
Hope it helps you!!According to the inverse square law, the force due to gravity between two masses will _____________.
Answer:
The inverse square law proposed by Newton suggests that the force of gravity acting between any two objects is inversely proportional to the square of the separation distance between the object's centers.
Explanation:
When a 10-V battery is connected to a resistor, 2 A of current flow in the resistor. What is the resistor's value
Hi there!
We can use Ohm's law to solve:
[tex]V = IR[/tex]
V = Potential Difference (V)
I = Current (A)
R = Resistance (Ω)
We can rearrange the equation to solve for resistance:
[tex]R = \frac{V}{I}[/tex]
Plug in the given values to solve.
[tex]R = \frac{10}{2} = \boxed{5 \Omega}[/tex]
A body of mass 0.1 kg falling freely under gravity takes 10 s to reach the ground. Calculate the kinetic energy and potential energy of the body when it has travelled for first 6 s. Given, g = 9.8 m/ s²
Answer: KE = 172.872 J
PE = 307.328 J
Explanation:
For KE: acceleration = change in velocity / time → 9.8 = final velocity - 0 (because initial velocity is zero) / 6s → final velocity after 6s = 58.8 m/s.
Now, plug this into: KE = 1/2(m)(v^2) → KE = 1/2(.1)(58.8^2) = 172.872 J.
For PE: Find the velocity after 10 s: acceleration = change in velocity / time → 9.8 = final velocity - 0 (because initial velocity is zero) / 10s → final velocity after 10s = 98 m/s.
Now, find the total height: (v final)^2 = (v initial)^2 + 2*a*d → 98^2 = 0^2 + 2*9.8*d → d = total height = 490 m.
Now, find the change in height after 6 s: (v final)^2 = (v initial)^2 + 2*a*d → 58.8^2 = 0^2 + 2*9.8*d → d = change in height after 6 s → 176.4 m
Now, subtract the change in height from the total height to get its height after 6s: 490-176.4=313.6m
PE = m*g*h → Pe=.1*9.8*313.6 = 307.328 J :)
Planets A and B have the same mass, but planet A is half the size of planet B.
Which statement correctly explains the weight you would experience on each
planet?
A. You would weigh the same on both planets because the masses
of the planets are the same.
B. You would weigh less on planet A because the distance between
you and the planet's center of gravity would be smaller.
C. You would weigh the same on both planets because your mass
would be the same on both.
O D. You would weigh more on planet A because the distance between
you and the planet's center of gravity would be smaller.
Answer:
the correct one is A hope it helps
3 Select the correct answer.
Which of the following statements is TRUE? А. Children in the US are generally given the opportunity to play sports in school starting at a young age.
B. The US is one of the few countries to integrate sports into their school systems.
C. Most high schools and colleges in the US have various sport teams.
D. All of the above
Answer:
A,B,C
Explanation:
because that is true
A 1000 kg rocket carrying 25 kg of fuel and oxygen rises at a velocity of 305 m/s. If all the mass of fuel and oxygen is burned to form gases of combustion, what is the downward velocity of these gases?
If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.
Conservation of linear momentumThe principle of conservation of linear momentum states that, the total momentum of an isolated system is constant.
The downward velocity of thes gases is calculated as follows;
v1(m1 + m2) = v2(m2)
305(1000 + 25) = v2(25)
312,625 = 25v2
v2 = 312,625/25
v2 = 12,505 m/s
Thus, If all the mass of fuel and oxygen is burned to form gases of combustion, the downward velocity of these gases would be 12,505 m/s.
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Determine the slope of end a of the cantilevered beam. E = 200 gpa and i = 65. 0(106) mm4
For E = 200 gpa and i = 65. 0(106) mm4, the slope of end a of the cantilevered beam is mathematically given as
A=0.0048rads
What is the slope of end a of the cantilevered beam?Generally, the equation for the is mathematically given as
[tex]A=\frac{PL^2}{2EI}+\frac{ML}{EI}[/tex]
Therefore
A=\frac{10+10^2+3^2}{2*240*10^9*65*10^6}+\frac{10+10^3*3}{240*10^9*65*10^{-6}}
A=0.00288+0.00192=0.0048rads
A=0.0048rads
In conclusion, the slope is
A=0.0048rads
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The value of slope of end a of the cantilevered beam when E = 200 gpa and i = 65. 0(106) mm4 is 0.0048 rads.
How to find the slope at the end of the cantilevered beam?The formula used to find the slope at the end of the cantilevered beam is,
[tex]A=\dfrac{PL^2}{2EI}+\dfrac{ML}{EI}[/tex]
Here, (M) is the momentum, (EI) is flexural rigidity, (P) is concentrated load and (L) is the length of the beam.
Concentrated load is 10 KN and uniform load is 3 kN/m. E = 200 gpa and i = 65. 0(106) mm4.
[tex]A=\dfrac{10+10^2+3^2}{2\times240\times10^9\times65\times10^6}+\dfrac{10+10^3\times3}{240\times10^9\times65\times10^{-6}}\\A=0.00288+0.00192A=0.0048 \rm\; rads[/tex]
Thus, the value of slope of end a of the cantilevered beam when E = 200 gpa and i = 65. 0(106) mm4 is 0.0048 rads.
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A mass m on a frictionless plane, inclined at an angle θ with respect to the horizontal, is connected by a cord that runs parallel to the inclined plane and is wrapped around a flywheel of radius r and moment of inertia
[tex]i=\frac{3mr^{2}}{4}[/tex]
what is the acceleration of the mass down
the plane?
The acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).
Conservation of angular momentumThe acceleration of the mass down the plane is determined by applying the principle of conservation of angular momentum.
Fr = Iα
where;
F is weight of the object parallel to the planer is the radius of the flywheelI is moment of inertiaα is angular acceleration(mg sinθ)r = Iα
(mg sinθ)r = I(ar)
(mg sinθ) = I(a)
[tex]a = \frac{mg \times sin(\theta)}{I} \\\\a = \frac{mg \times sin(\theta)}{3mr^2/4} \\\\a = \frac{4mg \times sin(\theta)}{3mr^2}[/tex]
Thus, the acceleration of the mass down the plane is determined as (4mg sinθ)/(3mr²).
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according to this passage when making healthcare decisions, how should a person approach the decision making process
Answer:
What is your name?
Explanation:
no bro I don't know I am New of this app so I don't know
11. Which of the following gives the correct relation between the acceleration due to gravity and period of a pendulum?
g = 2πLT2
g = 4π2LT2
g = 2πLT
g = 2π2LT
Please show all of your algebra.
[tex]\\ \rm\rightarrowtail T=2\pi\sqrt{\dfrac{l}{g}}[/tex]
Derive g[tex]\\ \rm\rightarrowtail T^2=4\pi^2\dfrac{l}{g}[/tex]
[tex]\\ \rm\rightarrowtail g=\dfrac{4\pi ^2\ell}{T^2}[/tex]
[tex]\\ \rm\rightarrowtail g=\left(\dfrac{2\pi\sqrt{l}}{T}\right)^2[/tex]
9. Graph the following data on the graph, then use the graph to determine the half life of this
isotope.
The half life is the time taken for half the number of radioactive atoms originally present to remain. This is the time that corresponds to exactly half of the original number of radioactive isotopes remaining in the system.
What is half life?The half life is the time taken for half the number of radioactive atoms originally present to remain. We can plot the number of atoms against the time taken in a graph.
We can obtain the half life of the radioactive isotope from the graph by noting the time that corresponds to exactly half of the original number of radioactive isotopes remaining in the system.
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Hello~
Which of the following produces least friction?
(a) Sliding friction
(b) Rolling friction
(c) Composite friction
(d) Static friction
Answer:
Rolling friction
Explanation:
When a object rolls down the all sides of object comes contact to under surface for very low timeFor which the friction decreases .Option B is correct
A long thing bar of copper is heated evenly along it's length
Answer:
It becomes less heavy
Explanation:
Hopefully it helps!
The study of electrons as it relates to their use in electric devices
Answer:
An electron is a component of the broader term, electricity. Generally electricity refers to the control, manipulation, and use of the movement of electrons to perform some kind of work (motion/rotation, light, heat, etc…).
Explanation:
Or
put this
The study of electrons as it relates to their use in electric devices is electricity.
But I will go with the first one
How does the maximum value of the current depend on the frequency of the ac voltage source?.
The maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.
What is peak current of AC source?
The peak current of an ac source is the amplitude current flowing in the ac circuit.
The magnitude of the peak current is calculated as follows;
I₀ = i/(sin ωt)
I₀ = i/(sin 2πft)
where;
I₀ is the peak currenti is the ac currentω is angular speedf is the frequencyt is timemaximum value ac currenti = I₀ x sin 2πft
From the equation above, as the frequency of the of the ac voltage source increases, the value of the ac current (i) increases.
Thus, the maximum value of the current depend on the frequency of the ac voltage source because it increases as the frequency increases.
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According to Newton's second law for rotational motion, an object's angular
acceleration equals the
(A) net torque multiplied by the moment of inertia.
(B) net moment of inertia divided by the net torque.
(C) net torque divided by the moment of inertia.
(D) net torque added to the moment of inertia.
Answer:
C: Net Torque divided by Moment of Inertia
Explanation:
Torque = Moment of Inertia x Angular Acceleration.
According to Newton's second law for rotational motion, an object's angular acceleration equals the net torque multiplied by the moment of inertia, not divided by it. The correct answer is (A)
Mathematically, it can be expressed as:
Angular acceleration (α) = (Net torque (τ) / Moment of inertia (I))
Where:
α = angular acceleration (measured in rad/s²)
τ = net torque (measured in Nm or kgm²/s²)
I = moment of inertia (measured in kgm²)
This equation shows that the angular acceleration of an object is equal to the net torque applied to it divided by its moment of inertia. So, the correct answer is (A) net torque multiplied by the moment of inertia.
To summarize, Newton's second law for rotational motion states that the angular acceleration of an object is directly proportional to the net torque applied to it and inversely proportional to its moment of inertia. The moment of inertia represents an object's resistance to changes in its rotational motion, while the net torque represents the total rotational force acting on the object.
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1. Which of the following represents the distance (how much ground the particle covers) moved by a particle in a simple harmonic motion in one time period? (Here, A represents the amplitude of the oscillation.)
0 cm
A cm
2A cm
4A cm
Please show all of your work.
What's the relationship
[tex]\\ \rm\Rrightarrow T=2\pi \sqrt{\dfrac{l}{g}}[/tex]
[tex]\\ \rm\Rrightarrow T^2g=4\pi ^2\ell[/tex]
[tex]\\ \rm\Rrightarrow\ell=\dfrac{T^2g}{4\pi^2}[/tex]
4A can be correct
The correct option is: 2A cm
What is simple harmonic motion?In a simple harmonic motion, the particle moves back and forth around a mean position. The distance covered by the particle in one time period depends on the amplitude of the oscillation.
The time period (T) of a simple harmonic motion can be expressed in terms of the frequency (f) as:
T = 1/f
The frequency (f) of a simple harmonic motion can be related to the angular frequency (ω) as:
ω = 2πf
Therefore, the time period (T) can also be expressed in terms of the angular frequency (ω) as:
T = 2π/ω
The displacement of the particle at any time (t) during the simple harmonic motion can be expressed as:
x = A cos(ωt)
where x is the displacement, A is the amplitude, and cos(ωt) is the cosine function.
The particle moves from its initial position to its maximum displacement (+A), then back to its initial position, and finally to its maximum displacement in the opposite direction (-A), before returning to its initial position again. Therefore, the distance covered by the particle in one time period is twice the amplitude (2A).
Therefore, the correct option is:
2A cm
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