A car drives down the road at 6m/s. The tires on the car have a diameter of .7m. How long does it take the car’s tires to complete one full rotation?

Answer:

That's Rontgen

Explanation:

Wilhem Rontgen

(a) The wavelength of the wave for the fundamental mode is 2.4 m.

(b) The fundamental frequency of the wave is 2,708.33 Hz.

The wavelength of the wave for the fundamental mode is calculated as follows;

Node to Node, N → N = λ/2

L = λ/2

λ = 2L

λ = 2 x 1.2

λ = 2.4 m

The fundamental frequency of the wave is calculated as follows;

f = v/λ

f₀ = v/2L

f₀ = (6500)/(2 x 1.2)

f₀ = 2,708.33 Hz

The diagram of the wave for the fundamental mode is in the image uploaded.

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Answer:

D

Explanation:

The speed is increasing and he was stationary which means the acceleration is not 0

If the earth rotated on an axis that was not tilted with respect to earth's orbit Under this condition time periods of daylight and darkness be equal everywhere on earth all year.

The Earth orbits the Sun in a counterclockwise pattern above the northern hemisphere at an average distance of 149.60 million km.

The Earth revolves around its axis once every 24 hours and orbits the sun once every 365 days. The Earth's rotation on its axis, not its orbit around the sun, causes day and night.

The term 'one day' refers to the time it takes the Earth to rotate once on its axis, which includes both day and night.

Hence the earth rotated on an axis that was not tilted with respect to the earth's orbit Under this condition time periods of daylight and darkness be equal everywhere on earth all year.

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Based on the first law of thermodynamics, the energy gained by a system is equal to the energy lost by the surroundings.

The laws of thermodynamics can be summarised as follow

From the laws given above precisely the first law, we can conclude that the energy gained by a system is equal to the energy lost by the surroundings

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Answer:

distance of compression: 0.07071 m

Explanation:

[tex]\sf energy = \dfrac{1}{2} kx^2[/tex]

[tex]\rightarrow \sf 0.5= \dfrac{1}{2} (200)x^2[/tex]

[tex]\rightarrow \sf 0.5= (100)x^2[/tex]

[tex]\rightarrow \sf 5\ *\ 10^{-3}= x^2[/tex]

[tex]\rightarrow \sf x = \sqrt{5\ *\ 10^{-3}}[/tex]

[tex]\rightarrow \sf x =0.07071 \ m[/tex]

Hi there!

We can use the equation for the charge of a charging capacitor:
[tex]q(t) = C\epsilon( 1 - e^{-\frac{t}{RC}})[/tex]

Using Capacitor equations:
[tex]C = \frac{Q}{V}}\\\\Q = CV[/tex]

Therefore, Cε equals the steady-state charge of the capacitor (the function approaches this value as t ⇒ ∞.

We can plug in the givens and solve.
[tex]\epsilon = 5 V\\\\C = 100\mu F = 0.0001 F[/tex]

[tex]Q = C \epsilon = (0.0001)(5) = \boxed{0.0005 C}[/tex]

The charge on the capacitor when the circuit has reached a steady-state is 0.0005C.

The capacitance of a conductor is defined as the ratio of the quantity of electric charge stored on it to the difference in electric potential.

Given that the resistance of the resistor is 20 kω, while the capacitance of the capacitor is 100 μf, and the voltage of the battery is 5V.

Now, the charge on the capacitor when the circuit has reached a steady-state can be written as,

[tex]Q=CV\\\\Q = 100\mu F \times 5V\\\\Q = \dfrac{100}{1,000,000}F \times 5V\\\\Q = 0.0005C[/tex]

Hence, the charge on the capacitor when the circuit has reached a steady state is 0.0005C.

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Centripetal acceleration

#1

#2

Direction of force also towards centre

Answer:

3 m/s

Explanation:

Initial = Final

Mass * Velocity = Mass *Velocity

8000kg * 12m/s = (8000kg+ 24000kg) * (Final Velocity)

(96000 kgm/s) / (32000kg) = (Final Velocity)

Final Velocity = 3 m/s

The speed of the coal car afterward is 3 m/s if an empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin.

The momentum of the body before the contact is always equal to the momentum of the body after the collision, according to the law of conservation of momentum.

According to the law of conservation of momentum;

Momentum before collision =Momentum after collision

We have:

Mass of the empty coal car of train M(e) = 8000 kg

Speed V(e) = 12 m/s

Mass of the coal M(c)  = 24000 kg

Let's suppose the speed of the coal car afterward V(c)

M(e) ×V(e) = (M(c)+M(e))× V(c)

8000×12 = (24000+8000)×V(c)

V(c) = 3 m/s

Thus, the speed of the coal car afterward is 3 m/s if an empty coal car of a train of mass 8000 kg is moving at 12 m/s along rails. 24000 kg of coal is dumped into the car from a motionless bin.

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Question :-

Answer :-

Explanation :-

As per the provided information in the given question, we have been given that the Frequency of the Radio is 220 Hertz . Wavelenght is given as 4.2 meter . And, we have been asked to calculate the Speed of the Wave .

For calculating the Speed , we will use the Formula :-

[tex] \bigstar \: \: \: \boxed{ \sf{ \: Speed \: = \: Wavelength \: \times \: Frequency \: }} [/tex]

Therefore , by Substituting the given values in the above Formula :-

[tex] \dag \: \: \: \sf{Speed \: = \: Wavelength \: \times \: Frequency} [/tex]

[tex] \longmapsto \: \: \: \sf{Speed \: = \: 4.2 \: \times \: 220} [/tex]

[tex] \longmapsto \: \: \: \textbf {\textsf {Speed \: = \: 924 }} [/tex]

Hence :-

[tex] \underline {\rule {180pt} {4pt}} [/tex]

Answer:

A Radio has a Frequency of 220 Hertz . The Sound produced by the Wavelength is 4.2 meter . Identify the Speed of the Wave .

11 m/s

0.01 m/s

52.3 m/s

924 m/s

Answer :-

Speed of the Wave is 924 m/s .

Explanation :-

As per the provided information in the given question, we have been given that the Frequency of the Radio is 220 Hertz . Wavelenght is given as 4.2 meter . And, we have been asked to calculate the Speed of the Wave .

For calculating the Speed , we will use the Formula :-

\bigstar \: \: \: \boxed{ \sf{ \: Speed \: = \: Wavelength \: \times \: Frequency \: }}★

Speed=Wavelength×Frequency

Therefore , by Substituting the given values in the above Formula :-

\dag \: \: \: \sf{Speed \: = \: Wavelength \: \times \: Frequency}†Speed=Wavelength×Frequency

\longmapsto \: \: \: \sf{Speed \: = \: 4.2 \: \times \: 220}⟼Speed=4.2×220

\longmapsto \: \: \: \textbf {\textsf {Speed \: = \: 924 }}⟼Speed = 924

Hence :-

Fourth Option is Correct Answer .

Answer:

Alloys are just mixtures of metal and metalloids are metallic substances with properties of metal.

Answer:

metalloids are chemical elements that form substances that have properties of metals and non metals while alloys is a mixture of metals