(1) Riley velocity relative to the water after she jumps is 1.7 m/s.
(2) The velocity of the canoe relative to the water is 5.02 m/s.
The given parameters;
mass of Riley, m₁ = 62 kgmass of canoe, m₂ = 21 kg velocity of the Riley after jumping, v₁ = 1.7 m/s(1) Since the lake is still, her velocity relative to the water after she jumps is 1.7 m/s.
(2) Apply the principle of conservation of linear momentum;
m₁v₁ = m₂v₂
62 x 1.7 = 21v₂
105.4 = 21v₂
[tex]v_2 = \frac{105.4}{21} \\\\v_2 = 5.02 \ m/s[/tex]
Thus, after her leap, the velocity of the canoe relative to the water is 5.02 m/s.
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During a certain period of time, the speedometer of a car reads a constant
60 km/h. Does this indicate a constant speed? A constant velocity?
If a material were being designed to demonstrate no thermal expansions, how would the energy plot look like?
The characteristics of thermal expansion allow finding that the response for a material without thermal expansion is
The length variation is zero In the graph the line is horizontal so there is no change in length with temperature
Thermal expansion is the macroscopic sum of the changes in the length of the bonds when the energy (temperature) changes, it can be written
ΔL = α L₀ ΔT
Where ΔL is the change in length, α the coefficient of linear expansion, L₀ the initial length and ΔT the change in body temperature
In this case, a material is being designed that the thermal expansion is very small, for this the material must be made up of several compounds where some of them present a contraction with temperature, some examples: water at low temperature, liquefied gases , ceramic tile, quartz, etc.
The thermal expansion measurement processes control the body temperature and measure the change in length, in this case the change in length must be zero, in the attachment we can see a graph of a composite material with these characteristics, an example of this type of material is Invar an alloy of nickel and iron α = 3.7 10⁻⁶ ºC⁻¹
In conclusion, using the characteristics of thermal expansion we can find that the response of material without thermal expansion is
The length variation is zero In the graph the line is horizontal so there is no change in length with temperature
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Which of the following is the best hypothesis
Answer:
Melting and frezzing are physical changes
In two paragraph of lines each, describe how you
would simplify, for your
grade 10 learners the
following topics
1.1 Electricity and magnetism.
The question above wants to assess your ability to simplify complex matters. In that case, I can't answer this question for you, but I'll show you how to answer it.
First, you should research electricity and magnetism. This research will make you understand the subject and all its elements. You can do this research in textbooks and digital platforms aimed at children and teenagers since these media usually present subjects in a more simplified way.
After doing this research, you will be able to write a text about electricity and magnetism as follows:
Present the main focus of this subject.Present the elements that make up this subject.Present how this subject applies in the real world.Present the importance of this subject in human life and society.Remember that you must use simple language, without the use of technical terms, but with common terms.
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PLEASE HELP!!
What process is illustrated in the figure?
Answer: A
Explanation:
What four processes allow for the change of thermodynamics properties according to the first law
Answer:
The four types of thermodynamic process are isobaric, isochoric, isothermal and adiabatic.
Everytime a train passes Ms. Lindsey's house, one specific item on her dresser rattles. Use physics to explain why this occurs.
Answer: gravity
Explanation: the moving and sifting around in the train
What is the pulling force of this train, if its engine provides 4200 kW power and 90 km/h speed?
Answer:
yes by 30
Explanation:
uhnhuh
While you push a box you begin to decrease the force you are exerting on the box. When will the box reach equilibrium?
A. When the force you are exerting on the box is equal to 0.
B. When Fyou on box = -Fbox on you.
C. When the force of the box becomes Fyou on box < Fbox on you
D. The box will never reach equilibrium.
The application of a force on the box overcomes the friction and causes the box to accelerate
While the force is decreasing, the box will stabilize;
B. When [tex]\underline{F_{you \, on \, box} = -F_{box \, on \, you}}[/tex]Reason:
Newton's third Law of Motion states that action and reaction are equal in magnitude and opposite in direction
When the box is pushed with a force, [tex]F_{you \, on \, box}[/tex], the reaction of the box of mass, m, is as follows;
[tex]F_{you \, on \, box}[/tex] = [tex]F_{friction}[/tex] + m × accelerationWhere;
[tex]F_{friction}[/tex] = [tex]-F_{box}[/tex] for example
The negative sign is due to the direction of the friction force, or [tex]F_{box}[/tex] is opposite to the direction of the applied force
When the force is decreased to F₂ = [tex]F_{you \, on \, box}[/tex], such that we have;
[tex]F_{you \, on \, box}[/tex] = [tex]-F_{box \, on \, you}[/tex] , which is the condition for equilibrium, and the net
force is zero and according to Newton's first law of motion, the box moves
at constant speed no acceleration
Therefore the box will reach equilibrium when;
[tex]\mathbf{\underline{F_{you \, on \, box} = -F_{box \, on \, you}}}[/tex]Learn more about equilibrium here;
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Answer:
When the force you are exerting on the box is equal to 0
Explanation:
Once again expert verifiers are sabotaging people here is the actual answer.
What is the smallest part of a compound called?
element
O
molecule
O
atom
O
mixture
o
Answer:
Here is your answer,thanks for using brainly!
Explanation:
B:Molecule
Molecules usually consist of 2 atoms linked together,however some molecules consist of thousands of atoms!
Here is a list of smalles to largest with the answers provided
Molecules
Atoms
Elements
Mixtures
Hope this helped
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An 80-kilogram skier slides on waxed skis along a horizontal surface of snow at constant velocity while pushing with his poles.
What is the horizontal force pushing him forward?
Answer:
Special Relativity/Newtonian Physics
Explanation:
Well in Newtonian physics you could say your mass is pushing you down and the floor is pushing you up. But rather in Special relativity only to floor is pushing up on you.
In this theory the word inertial observer matters and proves several matters throughout science. So exploring is a huge important thing to do. A person cleaning the window falls, while doing so the person feel weightless while falling. Objects that fall down with the person would remain stationarily, relative to the person. Similar to a person in space. Far away from any large masses the person would be an inertial observer. With no acceleration the person is also not close to gravitational fields and all laws of physics in the person's reference frame. The man falling off the roof is an inertial observer too. Because of this both of the matters about the rocket man and the person falling off the roof are the same.But you would think that the person falling off the roof is accelerating. But the equivalence principle tells us wrong.
The equivalence principle has made it easy to prove both people in the situations are inertial observers. People watching would think that he is accelerating, but he is not. But he is accelerating? The equivalence principle tells us to focus on the experience of the observer and the person feels weightless so they are an inertial observer. If a person in Space comes across a planet, the person's rocket will start heading towards a planet. But the Space person would be oblivious. The person would not feel any acceleration. The spaceship would not sense any acceleration nor would it sense that it is turning. A person outside the spaceship may see the slight curving motion and the person inside would not notice until the instant it crashes into the planet. Explaining this is geodesics and spacetime it equally links and connects with this in an obvious and common way.
Spacetime is a model that makes 4D, it joins space and time, ‘Space-time’. Now people can say how it perfectly describes gravity with it’s queer way of curving.
But how does this happen without gravity? Space is 4D with width, breadth, height and time. There is a model called spacetime. Einstein along with many other people visualise it as woven along with time. Space- time. It curves by mass distribution. The person is still traveling in a straight line. Just straight through spacetime. It is traveling along the geodesics of spacetime. This is actually quite common, it is just an object travelling straight on a curved surface. Like an airplane travels straight to get quicker to a different place. But it appears curved because obviously the Earth is curved. So if you unfolded the earth the path would be curved, but the plane is still traveling in a straight line. Let’s also say you and your friend were standing on the equator. You are 1000 kilometers apart from your friend. As you move towards the north direction you would eventually meet with your friend. You are not being pushed by gravity but simple as that you are just traveling on the geodesics of Earth. Matter tells spacetime how to curve, Spacetime tells matter how to move-John Wheeler.
The man falling off the roof was accelerating so what happens if the rocket man accelerates?
Now once the rocket man accelerates the floor accelerates into rocket man. Objects remain stationary but the floor also accelerates into the objects. The situation is just like on earth except you are not an inertial observer because you do not feel weightless. The observer inside the rocket would feel a force pushing up on the feet. Same on earth. You are accelerating in order to remain stationary. However you can not see yourself accelerating. In Newton’s rule the force of Gravity would be pushing you down and the ground pushing you up. However in special relativity gravity does not exist so it’s just the force of the ground pushing up on you. Just like the rocket accelerating. You look like you are not accelerating up but only in your frame of reference. To measure your speed of acceleration you must get an inertial observer to measure your acceleration speed. Like the man falling off the roof. Let’s say you are in the building and the man falls off the roof. To him you would appear accelerating upwards. So you have to accelerate just to stand still. Why all objects fall at the same rate is a mystery to Newtonian Physics but it is not a mystery to Special relativity because the objects are not accelerating just the floor accelerating into it.
So I hope you understand now, I think you know what I'm getting at. Might of misunderstood your question.
Which stament describes Newton’s law of universal gravitation
Mass has little effect on gravity between objects
Gravity pushes objects away from earths center
Gravity does not act between earth and the moon
Every object in the universe attracts every other object
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help please this is due in an hour!!!
[tex]▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ { \huge \mathfrak{Answer}}▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ ▪ [/tex]
Charge on one electron :
[tex]1.602 \times 10 {}^{ - 19} \: \: coulombs[/tex]So, charge on ball having 97 electrons is equal to :
[tex]97 \times 1.602 \times 10 {}^{ - 19} [/tex][tex]155.394 \times 10 {}^{ - 19} [/tex][tex]1.554 \times 10 {}^{ - 17} \: \: coulombs[/tex]What is the magnitude of the momentum of a 1000 kg car traveling
at 5 m/s?
Answer:
5000 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question
mass = 1000 kg
velocity = 5 m/s
We have
momentum = 1000 × 5 = 5000
We have the final answer as
5000 kg.m/sHope this helps you
A train travels meters in the first second of travel, 6 meters again during the second second of travel, and 6 meters again during the third second. Its
acceleration is
O 0 m/s
6 m/s
O 12 m/s/s
18 m/s
O None of the above
Answer:
0 m/sExplanation:
there is no acceleration, it's velocity is always 6m/s
so your answer is 0m/s
A rocket traveling through space with a constant velocity of 10 m/s fires up a booster. The booster accelerates the rocket at a rate of 5 m/s. What distance in meters has the rocket traveled within 12 seconds after the booster is turned on?
The distance traveled by the rocket after the given time period is 480 m.
The given parameters;
velocity of the rocket, v = 10 m/sacceleration of the rocket, a = 5 m/s²time of motion of the rocket, t = 12 sThe distance traveled by the rocket after the given time period is calculated from the second kinematic equation of as shown below;
s = ut + ¹/₂at²
s = (10 x 12) + (0.5 x 5 x 12²)
s = 120 + 360
s = 480 m
Thus, the distance traveled by the rocket after the given time period is 480 m.
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When the propeller were turning at 25 rad/s , what is the period (in seconds) of this propeller?
Answer:
Explanation:
T = (2π rad / rev) / (25 rad/s) = 0.251327... = 0.25 s
The propeller was turning at 25 rad/s then the period of the propeller will be equal to 0.25 seconds.
What is Velocity?In terms of physics, velocity is a vector assessment of the motion's direction and speed. The rate of change in an object's position relative to a reference frame and time is the more precise definition of velocity. Simply put, the concept of velocity informs us of the rate at which an object is travelling in a given direction.
It indicates the rate of motion of objects. Take two moving things like our illustration. If both items are travelling in the same vague direction, it is simple to determine which is moving more quickly.
From the given data in the question,
T = 2π (rad/rev) / 25 (rad/s)
T = 0.25 seconds.
Therefore, the period of this propeller is 0.25 seconds.
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Michael stands upright and allows his right arm to swing back and forth, naturally and without forcing, like a pendulum. He measures the time for 21 oscillations (complete cycles) to be 28.1 s. Assume his arm (length L) behaves as a simple pendulum, with an effective length of 2/3 L. Find the length of his arm, L.
Answer:
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The length of his arm, L = 0.67 m.
What is time period?
A basic pendulum consists of a point mass hung by a tightly supported, weightless, and inextensible string.
T = 2π√ L/g, where L is the pendulum's length and g is the acceleration brought on by gravity, is the formula for a pendulum's period.
Given in the question the time for 21 oscillations (complete cycles) to be 28.1 s. Assume his arm (length L) behaves as a simple pendulum, with an effective length of 2/3 L.
T = 2π√ L/g
T = 2π√2l/3g
T = 28.1/21
T = 1.33
2π√2l/3g = 1.33
l = .67 m
The length of his arm, L = 0.67 m.
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PLEASEEEEEE HELPPPPPPP MEEEEEEEE!!!!!!!!!!!!!
Answer:
[tex]2 \\ because \\ 2 - 2 = 0 \\ 5 - 5 = 0[/tex]
A block of mass 2.52 kg is kept at rest
as it compresses a horizontal massless spring
(k 116 N/m) by 9.73 cm. As the block
is released, it travels 0.537 m on a rough
horizontal surface before stopping.
The acceleration of gravity is 9.8 m/s.
Calculate the coefficient of kinetic friction
between surface and block.
By Newton's second law, the net vertical force on the block is
∑ F = N - mg = 0
so that the normal force exerted by the surface has magnitude
N = mg = (2.52 kg) (9.80 m/s²) = 24.7 N
Then as the block slides over the surface, it feels a frictional force of
f = µ (24.7 N)
where µ is the coefficient of kinetic friction.
As the block is pushed by the spring to its equilibrium position, friction performs
µ (-24.7 N) (0.0973 m) = -2.40µ J
of work (which is negative because it opposes the block's motion).
In compressing the spring by 9.73 cm = 0.0973 m, we store
1/2 (116 N/m) (0.0973 m)² = 0.549 J
of energy. This energy is released and partially converted to kinetic energy, while the rest is lost to friction.
By the work-energy theorem, the total work performed on the block as the spring pushes it towards the equilibrium position is equal to the change in its kinetic energy:
W = ∆K
0.549 J - 2.40µ J = 1/2 (2.52 kg) v ² - 0
where v is the speed of the block at the equilibrium position. Solving for v, we get
v = 0.891 √(0.549 - 2.40µ) m/s
After the block is released, the only force acting on it as it slides freely is friction. It comes to a stop after 0.537 m, so that friction performs
µ (-24.7 N) (0.537 m) = -13.3µ J
of work.
Using the work-energy theorem again, we have
W = ∆K
-13.3µ J = 0 - 1/2 (2.52 kg) v ²
Substitute the velocity we found in terms of µ, and solve for µ :
-13.3µ J = -1/2 (2.52 kg) (0.891 √(0.549 - 2.40µ) m/s)²
===> µ = 0.0350
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the atmosphere of mercury and mars are very thin.what effects does the thin atmosphere on the temperature on the surface of this planet?
Answer:
The effects of the thin atmosphere are that the surface of the planet is going to be much hotter and not only that but also more radioactive than a planet with a thicker atmosphere. The thick atmosphere on other planets prevents a lot of radiation from going straight to the surface of the planet.
Explanation:
What force prevents a machine from having 100% efficiency? A. Magnetic B. Electric O C. Friction O D. Gravity
Answer:
I believe it would be C ? my apologies if I'm wrong.
For question 51, do you use a=d/t
No. That won't help. It's not even true.
plz help owo
What characteristic is shared by sunspots, solar flares, and coronal mass ejections? Select the two correct responses.
They are caused by outward fluctuations of the sun's magnetic field.
They appear as dark spots on the sun's surface.
They tend to occur during active periods of the solar cycle.
They appear as bright spots on the sun's surface.
Answer:
They are caused by outward fluctuations of the sun's magnetic field.
They tend to occur during active periods of the solar cycle.
Explanation:
While sun spots will appear darker than the surrounding surface, flares will tend to appear brighter. CME's are associated with massive flares.
The two correct responses are as follows:
They are caused by outward fluctuations of the sun's magnetic field.They tend to occur during active periods of the solar cycle.The following information should be considered:
At the time when sunspots should appear darker as compared to the surrounding surface, so flares should be appear brighter. CME's are along with massive flares.Due to this, the above answers are considered.Learn more: brainly.com/question/16911495
A dog is running at an initial speed of 10 m/s. He covers 50 m in 4 seconds. What is the acceleration of the dog?
a.
1.25 m/s2
b.
1.04 m/s2
c.
5 m/s2
d.
3.2 m/s2
A rock is held steady over a cliff and dropped. 1 seconds later, another rock is thrown straight down at a speed of 11.3 m/s, and hits the first rock. How far have the rocks dropped before they collide? How long is the first rock in the air before it gets hit by the second rock?
What is the displacement of the rocks when they collide? __________ (Hint: be careful of sign -- the rocks drop.)
The first rock is in the air for __________ before it is hit.
Answer:
4.27s
Explanation:
If "t" represents the time traveled from the time rock 2 is dropped until the collision, then the time traveled for rock 1 = t + 1. And, since rock #1 is dropped making its initial velocity = 0, then:
The distance rock 1 travels is
x = (0)(t + 1) + 1/2(-9.8)(t + 1)2 = -4.9(t2 + 2t + 1) = -4.9t2 - 9.8t - 4.9
The distance rock 2 travels
x = -11.3t + 1/2(-9.8)t2 = -11.3t - 4.9t2
For the distances must be equal when the rocks collide:
-4.9t2 - 9.8t - 4.9 = -11.3t - 4.9t2
-9.8t - 4.9 = -11.3t
-4.9 = -1.5t
t = 3.267 s
Now, the distance they traveled can be found by plugging the 3.267 s back into either equation:
x = -11.3(3.267) - 4.9(3.267)2 = -89.2 m or 89.2 m below where they began
The time the first rock was in the air is t + 1 = 3.267 + 1 = 4.267 s = 4.27 s
Let
First rocks time be x
Second rocks time be x+1
initial velocity=u=11.3m/s
Distance of both rocks be s1 and s2
[tex]\\ \sf\longmapsto s=ut+\dfrac{1}{2}at^2[/tex]
Now
[tex]\\ \sf\longmapsto s1=11.3x+5x^2[/tex]
[tex]\\ \sf\longmapsto s2=11.3(x+1)+5(x+1)^2[/tex]
As both collide then
[tex]\\ \sf\longmapsto s1=s2[/tex]
[tex]\\ \sf\longmapsto 11.3x+5x^2=11.3x+11.3+5(x+1)^2[/tex]
[tex]\\ \sf\longmapsto 5x^2=11.3+5x^2+10x+1[/tex]
[tex]\\ \sf\longmapsto 10x+12.3=0[/tex]
[tex]\\ \sf\longmapsto x=1.23s[/tex]
Displacement
[tex]\\ \sf\longmapsto 11.3(1.23)=13.8m[/tex]
Done
When a car's acceleration is negative, what is happening to the car's motion?
the car slows down
the car speeds up
the car travels at a constant speed
the car remains at rest
Answer:
the car slows down
Explanation:
You are driving to grandma's house, and you are traveling at an average of 70 mph. How long will it take you to travel 70 miles?
O 1 hour
O 1 second
70 hours
O 70 seconds
Answer: 1 hour
Explanation: Focus on the units; 70 miles per hour means that each hour, you will travel 70 miles
or you can use the equation time = distance/speed. You have 70miles/ 70mph = 1hour
Helppppppppppppppp please and explain!