A bus accelerates forward. If an apple were on the floor of the bus it would move forward.
A: True
B: False

Answers

Answer 1

Answer:

False

Explanation:

Since it is on the bus, it would not move forward because the outside acceleration cannot be considered.


Related Questions


When the net force on an object is zero, what do we know about the motion of that object

Answers

Answer:

The objects speed or motion does not change if the net force is 0.

Explanation: There basically doesn't have anything acting on it so it stays put.

Directions: Summarize the main ideas of this lesson by answering the question below.
How might a person acquire a fear of or aversion to something even though it has no negative effect
on him or her?

Answers

Answer:

Explanation:

Trypophobia is a fear or disgust of closely-packed holes. People who have it feel queasy when looking at surfaces that have small holes gathered close together.A person may start by imagining what they fear, then looking at pictures of the fear object, and then finally being near or even touching the source of their anxiety. In the case of trypophobia, a person with symptoms may start by simply closing his eyes and imagining something such as a honeycomb or seed poThey can help you find the root of the fear and manage your symptoms. Last medically reviewed on July 20, 2017 Medically reviewed by Timothy J. Legg, Ph.D., CRNP — Written by Annamarya Scaccia ...

A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?

Answers

Answer:

[tex]2.33\ m/s^2[/tex]

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn = m.a

Where a is the acceleration of the object.  The net force is the sum of the individual vector forces applied to the object.

The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.

The net force is Fn = 5000 N - 1500 N = 3500 N

To find the acceleration, we solve the equation for a:

[tex]\displaystyle a=\frac{Fn}{m}[/tex]

[tex]\displaystyle a=\frac{3500}{1500}[/tex]

[tex]\boxed{a = 2.33\ m/s^2}[/tex]

The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]

URGENT! 40 POINTS! For each situation below, find the work done on the box using both energy and forces.

1. A 2 kg box initially at rest slides down a frictionless ramp (at 15ᵒ from the ground) for
1 second.

2. A 2 kg box is thrown upward with an initial speed of 3.5 m/s. Consider the box from
the time it was thrown until it reaches its maximum height.

3. A 2 kg box is dropped from an initial height of 10 m.


I have some physics, I just don't know what formulas to use or where to start. Help is much appreciated.

Answers

Answer:

i’m not sure one second let me try to figure it out

Explanation:

Which of the following is NOT one of the essential components of an exercise program?

Answers

Answer:

i dont know dude but ask someone who is in your grade lol

Explanation:

what are the harmful effects of drugs in the body?​

Answers

Explanation:

causes hallucinations

causes lung cancer eg cigarettes

causes bad breath

damages the nervous system eg cocaine

Explanation:

Drug use can lead to an addiction. Effects of

drugs on the body can slowly destroy vital

systems and functions. Drug dependence can quickly begin to affect your psychological and physical health, and can also affect your work and social life.

hope it helps!

A car traveled 885mi from El Paso, TX to Dallas, TX in 12.5 hours. What was the car's average speed?

Answers

Answer:

The car's average speed is 70.8 mph

Explanation:

The given parameters are;

The total distance traveled = 885 miles

The time of travel = 12.5 hours

The average speed is given by the following equation;

[tex]Average \ speed = \dfrac{Total \ Distance \ traveled}{Total \ time \ taken \ to \ travel \ the \ distance}[/tex]

Therefore, we have;

[tex]Average \ speed = \dfrac{885 \ miles}{12.5 \ hours} = 70.8 \ miles \ per \ hour[/tex]

Therefore, the car's average speed = 70.8 mph.

Answer:

The car's average speed is 70.8 mph

Explanation:

A child pushes a 100 kg refrigerator with a force of 50 N, but the refrigerator does not move. Suppose the coefficient of static friction between the floor and the refrigerator is 0.4. What is the force due to friction in this scenario

Answers

Answer:

50 N

Explanation:

Since the refrigerator doesn’t move, that means the force of friction equals the amount of force the child exerts on the fridge. If the friction force were greater than the force by the child, the fridge would start accelerating towards the child. If it were less than the force the child exerted, the fridge would start accelerating away from the child. Therefore, the net force must be 0, in this case, the friction force is equal to the force the child exerted, for it to stay at rest (as Newton’s First Law stated).

I hope this helps! :)

How long will it take an object traveling at 7 m/s to reach a distance of 26 meters

Answers

Answer:

3 hours 71 minutes

Explanation:

As because Speed= distance/time taken

so time taken= 3.71

An object has a force of 29.43 N acting on it. Its acceleration is 3.5 m/s2. What is the mass of this object?

Answers

Answer:

The mass of the object is 8.41 Kg.

Explanation:

Mechanical Force

The second Newton's law states that the net force exerted by an external agent on an object of mass m is:

F = m.a

Where a is the acceleration of the object. The SI unit for the force is the Newton: [tex]1\ Nw = 1~Kg.m/s^2[/tex]

We are given the net force of F=29.43 N acting on an object and producing an acceleration of a=3.5~m/s^2.

To calculate the mass of the object, we solve the above equation for m:

[tex]\displaystyle m=\frac{F}{a}[/tex]

[tex]\displaystyle m=\frac{29.43}{3.5}[/tex]

Calculating:

m = 8.41 Kg

The mass of the object is 8.41 Kg.

Which of the following does not illustrate a complete circuit?

Answers

Answer:

I think A

Explanation:

because it dosn't have enough tools

what is one standard kilogramun si system




Answers

Answer:

The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.

The kilogram (kg) is defined by taking the fixed numerical value of the Planck constant h to be 6.62607015 ×10−34 when expressed in the unit J s, which is equal to kg m2 s−1, where the meter and the second are defined in terms of c and ∆νCs.

the acceleration due to gravity of the moon is 1.67

Answers

Answer:

I think it's 1.625 m/s2

the speed of water at the tap of lower storey is more than that in the upper storey​

Answers

Answer:

Pressure of liquid in container is given by, P= height × density × acceleration of gravity.

At the lower storey, the height of the liquid from the open end is great, since height is directly proportional to pressure, the pressure exerted by liquid is maximum hence increase in velocity of flow.

Unlike the upper storey where the height of water is less hence the pressure exerted by the liquid is minimum which decreases the velocity / speed of liquid flow

The speed of water in the upper story will be lower than the lower storey because the kinetic energy of water in the upper storey will be less than that in lower storey.

What is kinetic energy?

Kinetic energy of an object is generated by virtue of the motion of the object. Whereas potential energy of the object is formed by virtue of the position of the object.

Kinetic energy depends on the mass of velocity of the object by the equation:

KE = 1/2 Mv²

Potential energy of a body p = Mgh

where, m is mass, g is acceleration due to gravity and h be the height of the object from the surface.

Water at the tap of upper storey is at more height from the surface and thus, having greater potential energy than that in lower storey. Hence, the flow of water will be reduced since it possess more potential energy than kinetic energy.

To find more on potential energy, refer here;

https://brainly.com/question/24284560

#SPJ2

Asha walks 15 m west, then 20 m north, then 15 m east. Calculate the distance
covered by Asha.(a) (Numbering problem)_​

Answers

Distance walked to the west= 15m

" " " " north= 20m

" " " " east = 15m

Total Distance= (15+ 20+ 15) m

= 50m

Asha covered 50m distance in total.

I need help
What should be done when the National Weather Service issues a severe weather watch?

Evacuate immediately.

Seek shelter immediately.

Take immediate action.

Begin to prepare.

Answers

I think in this situation, it depends on where you are. However, you should always be prepared in advance. But I think you should take immediate action and seek shelter. I hope this helps!
It depends but I think evacuate

Which one of the following is not a member of the solar family: (a) Morning Star (b) Evening Star (c) Pole Star (d) Tailed Star plzzz answer this...

Answers

Answer:

Tailed star

Explanation:

Tailed star

Two skaters A and B. having masses 50 kg and
70 kg respectively, stand facing each other 6 m
apart on a horizontal smooth surface. They pull
on a rope stretched between them. How far does
each move before they meet?
(A) both move 3 m
(B) A moves 2.5 m and B moves 3.5 m
(C) A moves 3.5 m and B moves 2.5 m
(D) both move 4 m
(E) none of the above

Answers

Answer:

Explanation:

Hell im good dude

why watchman does no work but gets tired ?​

Answers

Answer: the body is trained to wake up when the sun rises and get the energy from the sun and sleep and it is night on when the sun is not there. So when a watchman works at night there is no sun first of all to give him any kind of energy and secondly the body clock resists him waking up thus making him tired.

Explanation:

A loudspeaker produces a sound wave of frequency 50hz.
The amplitude of sound wave is increased.
What is heard?
A) a louder sound of higher pitch.
B) a louder sound of the same pitch.
C) a sound of higher pitch but the same loudness.
D) a sound of the same pitch and loudness as before

Answers

Answer:

B) a louder sound of the same pitch.

Explanation:

Given that the loudspeaker produces a sound wave of frequency 50hz and the amplitude of the sound wave is increased.

As loudness of the sound depends on the amplitude of the sound while pitch depends on the frequency of the sound.

On increasing the amplitude of the sound there is no effect on the frequency of the sound, so, the loudness of the sound will increase while the pitch remains unchanged.

Therefore, on increasing the amplitude of the soundwave a louder sound of the same pitch is heard.

Hence, option (B) is correct.

Calculate the kinetic energy of a 50 kg cart moving at a speed of 7.1 m/s.

ill give u 100 points if you give me the right answer.

Answers

══════════XXX═════════════

[tex]\huge\boxed{\fcolorbox{black}{yellow}{HOPE\: IT \: HELPS}}[/tex]

HOPE IT HELPS

[tex]\begin{gathered}\begin{gathered}\\\huge\underline{ \mathbb\blue{Please}\:\mathbb\green{Mark}\:\mathbb\orange{As}}\:\end{gathered}\end{gathered}[/tex]

Please Mark As

[tex]\huge\underline{ \mathbb\red{Brilliant}\:\mathbb\purple{Answers}}[/tex]

Brilliant Answers

Un automóvil se mueve a velocidad constante v = 60 [km/h]. Si el tiempo de reacción del conductor al ver la luz roja de una intersección es de 0.5 [s], y ´este desacelera a razón de 40 [m/s2 ] ¿Qué distancia recorre el automóvil desde el instante en que el conductor nota la se˜nal hasta detenerse por completo? Entiéndase por tiempo de reacción, el intervalo de tiempo transcurrido entre el instante en que se percibe la señal y el instante en que se lleva a cabo la acción (instante en que el conductor activa el sistema de frenado).

Answers

Answer:

El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.

Explanation:

De acuerdo con el enunciado, el conductor nota la luz roja, empieza a decelerar 0.5 segundos después y decelera hasta detenerse. La distancia total recorrida por el automóvil desde el instante en que el conductor nota la luz roja ([tex]\Delta s_{T}[/tex]), medida en metros:

[tex]\Delta s_{T} = \Delta s_{1}+\Delta s_{2}[/tex] (1)

Donde:

[tex]\Delta s_{1}[/tex] - Distancia recorrida a velocidad constante, medida en metros.

[tex]\Delta s_{2}[/tex] - Distancia recorrida hasta alcanzar el reposo, medida en metros.

Si suponemos que la segunda etapa describe un movimiento uniformemente acelerado, entonces la distancia recorrida total que representada por la siguiente fórmula:

[tex]\Delta s_{T} = v_{o}\cdot \Delta t_{o} + \frac{v_{f}^{2}-v_{o}^{2}}{2\cdot a}[/tex] (2)

Donde:

[tex]v_{o}[/tex] - Velocidad inicial del automóvil, medida en metros por segundo.

[tex]v_{f}[/tex] - Velocidad final del automóvil, medida en metros por segundo.

[tex]\Delta t_{o}[/tex] - Tiempo de reacción del conductor, medido en segundo.

[tex]a[/tex] - Aceleración, medida en metros por segundo al cuadrado.

Si conocemos que [tex]v_{o} = 16.667\,\frac{m}{s}[/tex], [tex]v_{f} = 0\,\frac{m}{s}[/tex], [tex]\Delta t_{o} = 0.5\,s[/tex] y [tex]a = -40\,\frac{m}{s^{2}}[/tex], entonces la distancia recorrida total es:

[tex]\Delta s_{T} = \left(16.667\,\frac{m}{s} \right)\cdot (0.5\,s)+\frac{\left(0\,\frac{m}{s} \right)^{2}-\left(16.667\,\frac{m}{s}\right)^{2}}{2\cdot \left(-40\,\frac{m}{s^{2}} \right)}[/tex]

[tex]\Delta s_{T} = 11.806\,m[/tex]

El automóvil recorre una distancia de 11.806 metros antes de deternerse por completo.

What would the mechanical advantage of a ramp be if the length is 25 feet and the height is 5 feet?
10
125
5
30

Answers

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Answer:

5.

Explanation:

From the question given above, the following data were obtained:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =?

Mechanical advantage of an inclined plane is simply defined as the ratio of the length of the ramp to the height of the ramp. Mathematically, it is expressed as:

Mechanical advantage = length /height

MA = L/H

With the above formula, we can simply calculate the mechanical advantage of the ramp as follow:

Length (L) of ramp = 25 feet

Height (H) of ramp = 5 feet

Mechanical advantage (MA) of ramp =.?

MA = 25 / 5

MA = 5

The, the mechanical advantage of the ramp is 5.

Why do women typically tend to have slightly greater stability than men?
A.
Women are shorter than men, and shorter people are more stable.
B.
Men have more muscle mass in their lower bodies that makes them stiff and less stable.
C.
Women have lower centers of gravity, and lower centers of gravity provide more stability.
D.
The increased muscle mass in their upper bodies makes their centers of gravity difficult to find.



Please select the best answer from the choices provided.


A
B
C
D

Answers

Answer:

C

Explanation:

I figured it sounded more accurate

An object is falling from a height of d and reaches a final velocity of vf. Calculate velocity when the object has fallen a distance d/2.

Answers

Answer:

The final velocity, [tex]v_{f}[/tex], is gd.

Explanation:

The condition here is a free falling object. Thus from the third equation of motion under free fall, we have;

[tex]v_{f}[/tex] = [tex]v_{i}[/tex] + 2gs

where [tex]v_{f}[/tex] is the final velocity of the object, [tex]v_{i}[/tex] is the initial velocity of the object, g is the gravitational force and s is the height.

Since the object falls from a height of d, then [tex]v_{i}[/tex] = 0 m/s, and s = d.

So that;

[tex]v_{f}[/tex] = 0 + 2gd

   = 2gd

[tex]v_{f}[/tex] = 2gd

When the distance is [tex]\frac{d}{2}[/tex], [tex]v_{i}[/tex] = 0 m/s.

Then;

[tex]v_{f}[/tex] = 2g[tex]\frac{d}{2}[/tex]

[tex]v_{f}[/tex] = g x d

When the object falls through the height [tex]\frac{d}{2}[/tex], then the final velocity is gd.

Calculate the kinetic energy of a 50 kg cart moving at a speed of 18.6 m/s.

Answers

Answer:

8649 J

Explanation:

KE = 1/2mv^2

1/2(50)(18.6)^2

1/2(50)(345.96) = 8649 J


Ek = ½mv^2
This is for calculate the kinetic energy

The force of attraction between two oppositely charged pith is 5mx 10 to the -6th power newtons. If the charge on the two is 6.7 x 10 to the -9th power coulombs what is the distance between the two charges

Answers

Answer:

0.28 m

Explanation:

The following data were obtained from the question:

Force (F) = 5×10¯⁶ N

Charge 1 (q₁) = 6.7×10¯⁹ C

Charge 2 (q₂) = 6.7×10¯⁹ C

Electrical constant (K) = 9×10⁹ Nm²C¯²

Distance apart (r) =?

Thus, the distance between the two charges can be obtained as follow:

F = Kq₁q₂/r²

5×10¯⁶ = 9×10⁹ × 6.7×10¯⁹ × 6.7×10¯⁹/r²

5×10¯⁶ = 4.0401×10¯⁷ / r²

Cross multiply

5×10¯⁶ × r² = 4.0401×10¯⁷

Divide both side by 5×10¯⁶

r² = 4.0401×10¯⁷ / 5×10¯⁶

Take the square root of both side

r = √(4.0401×10¯⁷ / 5×10¯⁶)

r = 0.28 m

Therefore, the distance between the two charges is 0.28 m

What is the height of a shelf that has 15 kg objects with 450 J of gravitational potential energy

Answers

PE=mgh
450J=15kg•9.8m/s2squared
450=147h
—— ——
147 147

h=3.0612m

Bolt starts the race not moving, but then increased his speed until he reaches a top speed. Once Bolt reaches his top speed he maintains that speed for a few seconds to:
a) move at a constant velocity
b) accelerating by moving faster
c) accelerating by moving slower
Is it a, b, or c?

Answers

Answer:

a) move at a constant velocity

Explanation:

A train travels with a speed of 115km/hr. How much time does it take to cover a distance of 470km.​

Answers

It would take approximately 4 hours for the train to cover a distance of 470km.

4 hours 5 minutes 13.04 seconds

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