A ball is thrown from a height of 44 meters with an initial downward velocity of 6 m/s . The ball's height h (in meters) after t seconds is given by the following.
h= 44 - 6t - 5t squared 2
How long after the ball is thrown does it hit the ground?
Round your answer(s) to the nearest hundredth.
(If there is more than one answer, use the "or" button.)

Answer:

The 8th term is [tex]\frac{1}{729}[/tex].

Step-by-step explanation:

Let's begin with the formula for a geometric sequence. We know this is geometric because we are working with a common ratio, or the number we multiply to find each term.

[tex]a_n=a_0(r)^{n-1}[/tex]

In this formula, [tex]a_0[/tex] is the first term, [tex]r[/tex] is the common ratio, and [tex]n[/tex] is the desired term. We know the values of [tex]r[/tex], [tex]a_0[/tex], and [tex]n[/tex] from the given information:

[tex]a_0=3\\r=\frac{1}{3}\\n=8[/tex]

Substituting those values we get:

[tex]a_8=3(\frac{1}{3})^{8-1}[/tex]

[tex]a_8=3(\frac{1}{3})^7\\a_8=3(\frac{1}{2187})\\a_8=\frac{3}{2187}\\a_8=\frac{1}{729}[/tex]

The period of the given function is T = 2π

The period T of a function f(x) is such that:

f(x + T) = f(x).

In this case, our function is:

f(θ) = e^{iθ}

Remember that this can be written as:

f(θ) = cos(θ) + i*sin(θ)

So yes, this is in did a periodic function.

Then the period of the function f(θ) is the same as the period of the cosine and sine functions, which we know is T = 2π.

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The period of the considered function f(θ) = e^{iθ} is found to be P = 2π (assuming 'i' refers to 'iota' and 'e' refers to the base of the natural logarithm)

For any real value θ, we have:

[tex]e^{i\theta} = \cos(\theta) + i\sin(\theta)[/tex]

where 'e' is the base of the natural logarithm, and 'i' is iota, the imaginary unit.

Functions which repeats their values after a fixed interval, are called periodic function.

For a function [tex]y = f(x)[/tex], it is called periodic with period 'T' if we have:

[tex]y = f(x) = f(x + T) \: \forall x \in D(f)[/tex]

where D(F) is the domain of the function f.

Suppose that, the period of the function [tex]f(\theta) = e^{i \theta}[/tex] be P, then we get:
[tex]f(\theta + P) = f(\theta)\\\\e^{i(\theta)} = e^{i(\theta + P)}\\\\\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex]

When two complex numbers are equal, then their real parts are equal and their imaginary parts are equal.

That means,

[tex]\cos(\theta) + i\sin(\theta) = \cos(\theta + P) + i\sin(\theta + P)[/tex] implies that:

[tex]\cos(\theta) = \cos(\theta + P)\\\sin(\theta) = \sin(\theta + P)[/tex]

Also, we know that the period of sine and cosine function is [tex]2\pi[/tex]

Thus, we get:

[tex]P = 2\pi[/tex]

Thus, the period of the function [tex]f(\theta) = e^{i \theta}[/tex]  is P = 2π

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The equation will be:

[tex]m\angle 1=\dfrac{1}{2}(arc\ a-arc\ b)[/tex]

The arc of the circle is the curved line on the circle formed by the angle and the radius of the circle.

In the attached picture of the question, we can see that

The measure of the interior angle is the semi-sum of the arches that comprise it and its opposite.

So the equation will be

[tex]m\angle 1=\dfrac{1}{2}(arc\ a-arc\ b)[/tex]

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Answer: a

Step-by-step explanation:

Answer:

(2,0) is not a point on the graph of the function y=x+2

Step-by-step explanation:

Go to the TI-84 plus calculator and go to the y= button and then type in x+2 and then press the 2nd button and then the graph button and then you should get your answer.

A ratio shows the relation between two numbers. The amount of more material that is needed by Jake is 42.5 cm³.

A ratio shows us the number of times a number contains another number.

Given that the volume of the first prism is 14.5cm³, while the scale factor is 4. Since the scale factor is applicable to dimension, and volume is always the cube of three-dimension.

Therefore, the volume of the scaled prism will be the cube the of the volume of the first prism, which can be written as,

[tex]\rm \text{Volume of the Scaled prism}= (Scale\ factor)^3 \times \text{Volume of the first prism}[/tex]

Substitute the values,

[tex]\rm \text{Volume of the Scaled prism}= 4^3 \times 14.5 = 928\ cm^3[/tex]

Since, the volume of material with Jake is 900 cm³, while the material he has already used is 14.5 cm³, thus the volume of the material that is left with Jake is 885.5 cm³(900cm³-14.5cm³).

Now, since the material needed to make the scaled prism is 928 cm³, the amount of material that is with Jake is 885.5 cm³, therefore, the amount of the material that is needed by Jake to complete the scaled prism can be written as,

The Amount of more material Needed by Jake = Amount of material needed to make the scaled prism - Amount of material left with Jake

The Amount of more material Needed by Jake = 928 cm³ - 885.5 cm³

                                                                               = 42.5 cm³

Hence, the amount of more material that is needed by Jake is 42.5 cm³.

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Answer:

Step-by-step explanation:

A = 1/2 bh = 1/2 (12)(17) = 204 square inches

[tex]\qquad \textit{perfect square trinomial} \\\\ (a\pm b)^2\implies a^2\pm \stackrel{\stackrel{\text{\small 2}\cdot \sqrt{\textit{\small a}^2}\cdot \sqrt{\textit{\small b}^2}}{\downarrow }}{2ab} + b^2 \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ x^2 \pm \stackrel{\stackrel{2\sqrt{x^2}\sqrt{c^2}}{\downarrow }}{6x} +c^2~\hspace{10em}6x=2\sqrt{x^2}\sqrt{c^2}\implies 6x=2xc \\\\\\ \cfrac{6x}{2x}=c\implies 3=c\implies 9=c^2~\hfill \boxed{(x\pm 3)^2}[/tex]

c=9 makes the given expression a perfect square trinomial.

The given expression is:

[tex]x^{2} +6x+c[/tex]

We can rewrite it as:

[tex]x^{2} +2*x*3 + c[/tex].....(1)

The expansion of [tex](a+b)^2[/tex] is [tex]a^{2} +2ab+b^{2}[/tex]

Comparing (1) with [tex]a^{2} +2ab+b^{2}[/tex]

We get

a=x

b=3

c=b²

So, c=3² =9.

So, c=9 makes the given expression a perfect square trinomial.

Hence,  c=9 makes the given expression a perfect square trinomial.

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Answer:

See below.

Step-by-step explanation:

Let x = amount of money you have in your account.

The money in your account plus the $125 extra that you need equals the total cost of the computer.

The equation is:

x + 125 = 2250

Now we solve the equation by subtracting 125 from both sides.

x = 2125

Answer: You have now $2125 in your account

Answer:

Step-by-step explanation:

Answer:

342

Step-by-step explanation:

9x38=342, so the answer is 342 crayons

Answer:

342 crayons

Step-by-step explanation:

Each child has 9 crayons. This means each one of the children has 9 crayons for himself or herself. So if there are 38 children,it means each one of the 38 children has 9 crayons.

The total number of crayons is therefore gotten by multiplyiong the number of crayons of each child(9) by the total number of children(38).

∴38×9=342.

Answer:

No, 20 ≠ -10

Step-by-step explanation:

20 = (-10) = (-20)+10

20≠-10=-20+10

20≠-10=-10

Answer:

Step-by-step explanation:

Compare the decimals using >, <, or =

Name two equivalent fractions for each fraction listed below.

If there are 16 cups in one gallon, how many cups are in 3 gallons?

16 cups = 1 gal.

? cups = 3 gals.

3 * 16 = 48 cups

How many cups are in 5 gallons?

5 * 16 = 80 cups

Compare and contrast squares are rectangles

Squares: have four sides and four equal sides

Rectangles: have four sides and have 2 parallel sides, meaning that they have 2 opposite sides that are equal.

Hope this helps!

Step-by-step explanation:

x^2 + (4+3)X + 12

x^2 + 4x + 3X + 12

X (X + 4) + 3 ( X + 4)

( X + 3) (X +4)

Solving steps:

[tex]\sf \rightarrow x^2\:+\:7x\:+\:12[/tex]

breakdown the following

[tex]\sf \rightarrow x^2\:+\:3x + 4x\:+\:12[/tex]

break the expressions into groups

[tex]\sf \rightarrow \left(x^2+3x\right)+\left(4x+12\right)[/tex]

factor the following

[tex]\rightarrow \sf x\left(x+3\right)+4\left(x+3\right)[/tex]

factor the common term: (x+3)

[tex]\rightarrow \sf \left(x+3\right)\left(x+4\right)[/tex]

Using the Central Limit Theorem, it is found that the standard deviation is of 0.0971.

In this problem, for each sample, the standard error is given by:

[tex]s_I = \sqrt{\frac{0.25(0.75)}{50}} = 0.0612[/tex]

[tex]s_{II} = \sqrt{\frac{0.35(0.65)}{40}} = 0.0754[/tex]

Hence, for the distribution of differences, it is given by:

[tex]s = \sqrt{s_I^2 + s_{II}^2} = \sqrt{0.0612^2 + 0.0754^2} = 0.0971[/tex]

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Answer:

A parallelogram by definition has 2 pairs of parallel sides.

A parallelogram could be:

____________

|                        |

|___________|

A rectangle in euclidean geometry has 4 right angles.

For example:

________________

|                                 |

|_______________|

However, a parallelogram may have 2 pairs parallel sides but not 4 right angles.

For example:

______________

\                              \        

 \______________\

Therefore, A parallelogram is not always a rectangle.

Hope this helps!!!

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Answer:

pq - 12r

step by step explanation:

as far as I can read that, well, the company has a revenue income of 8250000 and their expenditure on purchases is 49% of that amount, how much is that?

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{49\% of 8250000}}{\left( \cfrac{49}{100} \right)8250000}\implies 4042500[/tex]

so on saving 2.05% of purchasing expenses or namely 2.05% of 4042500

[tex]\begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{2.05\% of 4042500}}{\left( \cfrac{2.05}{100} \right)4042500}\implies 82871.25[/tex]

so sales must be increased by that much in order to match the 2.05% of 4042500.

Using separation of variables, it is found that the solution to the initial value problem is of y(x) = x² + 2.

In separation of variables, we place all the factors of y on one side of the equation with dy, all the factors of x on the other side with dx, and integrate both sides.

In this problem, the differential equation is given by:

[tex]\frac{dy}{dx} = 2x[/tex]

Then, applying separation of variables:

[tex]dy = 2x dx[/tex]

[tex]\int dy = \int 2x dx[/tex]

[tex]y = x^2 + K[/tex]

Since y(0) = 2, we have that the constant of integration is K = 2, and the solution is:

y(x) = x² + 2.

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The differential equation is y(x) = x² + 2.

Differential Equations In Mathematics, a differential equation is an equation that contains one or more functions with their derivatives.

The given equation is;

[tex]\rm \dfrac{dy}{dx}=2x[/tex]

Applying the variable separation method;

[tex]\rm \dfrac{dy}{dx}=2x\\\\\int\limits \, dy=\int\limits\, 2x. dx\\\\y = 2 \times \dfrac{x^{1+1}}{1+1} +c\\\\y = 2 \times \dfrac{x^{2}}{2} +c\\\\y = x^2+c[/tex]

The value of c when y( 0 ) = 2 is c =2.

Hence, the required differential equation is y(x) = x² + 2.

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Answer: -20/21

Step-by-step explanation:

Using the Pythagorean identity, we can get that the sine of angle theta is [tex]\pm 20/29[/tex].

But since theta terminates in Quadrant II, the sine of angle theta is positive, meaning that it has a value of 20/29.

Now, since tan = sin/cos, tan theta = (20/29)/(-21/29) = -20/21

Answer:

[tex] \frac{1}{ \sqrt{2} } [/tex]

Step-by-step explanation:

Given

[tex]theta = 22 \frac{1}{2} = \frac{45}{2} [/tex]

[tex]2 \times theta = \frac{45}{2} \times 2 = 45[/tex]

Sin2theta=sin45⁰=1/√2

[tex] \frac{1}{ \sqrt{2} } [/tex]

is your answer

Answer:

[tex]\sf \dfrac{\sqrt{2}}{2}[/tex]

Step-by-step explanation:

[tex]\sf If\:\theta=\left(22\dfrac12\right)^{\circ}[/tex]

[tex]\sf \implies2\theta=2\cdot\left(22\dfrac12\right)^{\circ}=45^{\circ}[/tex]

[tex]\sf Therefore\:\sin2\theta=\sin(45)^{\circ}=\dfrac{\sqrt{2}}{2}[/tex]

Proof

If a right triangle has an interior angle of 45°, then the third interior angle will also be 45° (since the sum of the interior angles of a triangle is 180°).

This means that the two legs of the right triangle are equal in length.

Using Pythagoras' Theorem, we can state that the hypotenuse of a right triangle with two legs of equal length will be √2 times the length of a leg.

Let a = b = 1

⇒ 1² + 1² = c²

⇒ c = √2

The sine trig ratio is:

[tex]\mathsf{\sin(\theta)=\dfrac{O}{H}}[/tex]

where:

[tex]\implies \sf \sin(45^{\circ})=\dfrac{1}{\sqrt{2} }[/tex]

[tex]\implies \sf \dfrac{1}{\sqrt{2}}\times \dfrac{\sqrt{2}}{\sqrt{2}}=\dfrac{\sqrt{2}}{2}[/tex]

[tex]\implies \sf \sin(45^{\circ})=\dfrac{\sqrt{2}}{2}[/tex]

The triangles PQR and PMN are similar triangles

The ratio MN/ QR is 2/3

The question is incomplete, as the figure of the triangles are not given.

So, I will give a general explanation

The given parameters are:

PM= 2MQ

PN = 2NR

Rewrite PM= 2MQ  as:

PM/MQ = 2/1

The equation becomes

PM/(PM + MQ) = 2/(2 + 1)

PM/(PM + MQ) = 2/3

Add PM and MQ

PM/PQ = 2/3

The above means that:

PM/PQ = MN/ QR = 2/3

Hence, the ratio MN/ QR is 2/3

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Answer:

C, Almost fifty percent

Step-by-step explanation: I just got it right.

The equation of the line in slope-intercept form and standard form that passes through the line are  y = -5 / 6x - 43 / 6 and  5x + 6y = -43 respectively.

The Slope intercept equation is use to represent a linear table or graph. Therefore, the formula is represented as follows

y = mx + b

where

m = slope

b = y-intercept

Hence,

(-5, -3)(1, -8)

m = -8 + 3 / 1 + 5 = - 5 / 6

Using (1, -8) let's find b

-8 = -5 / 6 (1) + b

-8 + 5 / 6 = b

-48 + 5/6 = b

b = -43 / 6

Therefore, the slope intercept equation is y = -5 / 6x - 43 / 6

The equation in standard form is represented as Ax + By = C. Therefore,

y + 5 / 6 x = - 43/6

5x + 6y = -43

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The molar solubility of Ba₃(PO₄)₂ is its concentration of pure substance

The correct equation for the ksp is Ksp = 6x⁵

Start by writing the reaction for the solution of Barium phosphate

Ba₃(PO₄)₂  ⇌3Ba²⁺ +2PO₄³⁻

Next, we make an ICE chart

Let "x" be the molar solubility of Barium phosphate

          Ba₃(PO₄)₂(s)  ⇌3Ba²⁺ +2PO₄³⁻

I                                 0                  0

C                              +3x               +2x

E                                3x³                 2x²

Lastly, we write the expression for the solubility product constant (Ksp)

This is represented as:

Ksp = [3Ba²⁺] × [2PO₄³⁻]²

Ksp = 3x³ × 2x²

Evaluate the product

Ksp = 6x⁵

Hence, the correct equation for the ksp is Ksp = 6x⁵

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The molar solubility of Ba₃(PO₄)₂ is its concentration of a pure substance.

The correct equation for the ksp is Ksp = 6x⁵.

The solubility product constant is the equilibrium constant for the dissolution of a solid substance into an aqueous solution. It is denoted by the symbol Ksp.

Start by writing the reaction for the solution of Barium phosphate.

Ba₃(PO₄)₂  ⇌3Ba²⁺ +2PO₄³⁻

Let "x" be the molar solubility of Barium phosphate

         Ba₃(PO₄)₂(s)  ⇌3Ba²⁺ +2PO₄³⁻

I                                 0                  0

C                              +3x               +2x

E                                3x³                 2x²

Lastly, we write the expression for the solubility product constant (Ksp),

This is represented as:

Ksp = [3Ba²⁺] × [2PO₄³⁻]²

Ksp = 3x³ × 2x²

Evaluate the product

Ksp = 6x⁵

Hence, the correct equation for the ksp is Ksp = 6x⁵

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Answer:

60 days.

Step-by-step explanation:

Let the actual time be x, then:

x - 0.25x = 45

0.75x = 45

x = 45/0.75

= 60 days.

Answer:

  1

Step-by-step explanation:

The square of the value in the empty space is the constant in the expanded expression. That is ...

  [ ]² = 1

The value in the space is ...

  [ ] = √1 = 1

The filled-in equation is ...

  (3x -1)² = 9x² -6x +1

_____

The expansion of the square of a binomial is ...

  (ax -b)² = a²x² -2abx +b²

Above, we used the constant term to find 'b', but we could also have used the linear term:

  -6x = -2(3)bx . . . . . a=3 in this problem

  1 = b . . . . . . . divide by -6x

Answer:

side length = 4

Step-by-step explanation:

Let x = the side length

Area is x•x, which is x^2.

Perimeter is x+x+x+x, which is 4x.

x^2 = 4x

x^2 - 4x = 0

Factor.

x(x-4) = 0

x = 0 or x = 4

Discard 0 as an answer as it is not useful.

x = 4.

Area = 4^2 = 16

Perimeter = 4(4)= 16

The side length is 4.

The rigid transformation of figure JKLM would not change the side length and angle measure

The features of the figure JKLM that would remain the same are its side lengths and angles

A rigid transformation is any of the following

All of the above transformation do not change the side length and the angle measure of the shape they transform

Hence, the features of the figure JKLM that would remain the same are its side lengths and angles

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Answer:

Undefined Slope

Step-by-step explanation:

The points (2,6) and (2,7) are on the same vertical line of 2, which results in an undefined slope.

Answer:

m=undefined

Step-by-step explanation:

The formula to find the slope isn't very complicated. The formula is:

    y₂-y₁

m= --------

      x₂-x₁

You have the points (2,7) and (2,-6). In (2,7) 2 is your x and 7 is your y. Since (2,7) is your first coordinate set, we put 2 as our x₁ . We put 7 as our y₁ .

In (2,-6) 2 is your x and -6 is your y. Since (2,-6) is your second coordinate set, we put 2 as our x₂ . We put -6 as our y₂ .

Let's substitute all of these numbers in:

    -6-7       -13

m= -------  = -------

     2-2         0

So we have -13/0 .You would think that any number divided by                0 is 0, right?

                No. Any number divided by 0 is undefined.

Therefore, you slope, m, would be:

m=undefined .

Answer:

x = 62°

Step-by-step explanation:

Concepts:

Solving

Step 1: Combine like terms.

Step 2: Subtract 118 from both sides.

Step 3: Check if solution is correct.

Therefore, the answer is x = 62°.