A ball hits a wall going 10 m/s, and bounces off going 8 m/s. the coefficient of restitution is?

Container A has a higher temperature than container B according to the ideal gas approximation.

Multiple randomly moving point particles with no interparticle interactions make create an ideal gas in theory. The ideal gas notion is useful because it complies with the ideal gas law, has a condensed equation of state, and can be studied using statistical mechanics.

An ideal gas is a fictitious gas that, because of its tiny size and lack of interactions, perfectly complies with the gas laws. Ideal gas is a gas that abides by all gas laws at all pressures and temperatures.

Ideal gases' internal energy and enthalpy are solely dependent on temperature; neither volume nor pressure play a role.

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Answer:

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions

Newton’s Third Law: Action & Reaction

Whenever one object exerts a force on a second object, the second object exerts an equal and opposite force on the first.

His third law states that for every action (force) in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also exerts an equal and opposite force on object A. In other words, forces result from interactions.

Examples of action and reaction involving aerodynamics:

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HOPE THIS HELPS <3

Newton's Third law of motion states :

" Every action has an equal and opposite reaction "

i.e If a force is applied by an object A on another object B then that object B also exerts a foce on object A, that is of same magnitude and opposite direction to the force applied by object A.

Ex - A book on a table exerts gravitational force on the table and table exerts back a normal force on the book.

Answer:

Let x = A cos ω t      when ω t = 0, x = A = .1 m

x = .1 cos ω t

cos ω t = .06 / .1 = .6       when x = .06

ω t = 53.1 deg        at a displacement of .06

v = -ω A sin ω t      speed of particle

ω = (k / m)^1/2 = (800/2)^1/2 = 20

v = 20/s * .1 m sin 53.1 = 1.60 m/s

The distance covered by man is 7 km and displacement will be 5 km.

Distance is defined as the total path covered between two points. It is a scalar quantity.

Displacement is defined as the shortest path between two points. It is a vector quantity.

Distance is either always greater or equal to displacement. The distance can never be smaller than displacement.

According to the question, a person drives 6 km in the car, and he comes back 1 km to get some food means the distance traveled by him is 7 km.

However, the distance travelled will only be 5 kilometers if he travels straight to Burger King. Displacement is, after all, the shortest route between two places.

Hence, the distance will be 7 km and displacement will be 5 km respectively.

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Answer:

1) 00.5

2) 400

3) 0.0601

4) 10900

Explanation:

goggle it

Answer:

69.8 m  (nearest tenth)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]s=10.5 \quad u=0 \quad a=9.8[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2:\\\\10.5&=(0)t+\dfrac{1}{2}(9.8)t^2\\10.5&=4.9t^2\\t^2&=\dfrac{15}{7}\\t&=\sqrt{\dfrac{15}{7}}\end{aligned}[/tex]

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, using the value of t found previously:

[tex]u=47.7 \quad v=47.7 \quad a=0 \quad t=\sqrt{\dfrac{15}{7}}[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s&=ut+\dfrac{1}{2}at^2:\\\\s&=47.7\left(\sqrt{\dfrac{15}{7}}\right)+\dfrac{1}{2}(0)\left(\sqrt{\dfrac{15}{7}}\right)^2\\s&=47.7\left(\sqrt{\dfrac{15}{7}}\right)\\s&=69.82565022...\end{aligned}[/tex]

Therefore, the cannonball lands 69.8 m from the base of the wall.

The minimum power that is required for the fan is 75W.

It is given that:

ρ = 1.2 kg/m³, density of air

v = 5 m/s, flow velocity

Q = 5 m³/s, volumetric flow rate

So the minimum power required at 100% efficiency can be known by

P= 1/2 [tex]v^{2}[/tex][tex]\rho[/tex]Q

=1/2 x [tex]5^{2}[/tex] x 1.2 x 5

=75 W

The minimum power to be supplied is 75W

Power is defined as the amount of energy that is transferred or converted per unit time. Watt can be defined as the unit of Power which is one joule per second.

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The correct answer is Electrical charges in motion produce a magnetic field.

Given that an electrical current is made up of electrons travelling along a wire and that all electrons have a negative charge, all electrical currents produce magnetic fields. Due to their continual mobility, atoms' electrons also have magnetic fields. This indicates that electron mobility is what brought about the problem.

Every substance is composed of atoms, and each atom has an electron that is capable of carrying an electric charge.

The atoms are considered to be paramagnetic, which implies that they attract magnets, if these electrons are unpaired. The substance will therefore be referred to as magnetic.

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A. The acceleration of the train is –0.68 m/s²

B. The stopping distance is 660 m

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

a = (v – u) / t

a = (0 – 30) / 44

a = –0.68 m/s²

s = (v + u)t / 2

s = [(0 + 30) × 44]/ 2

s = (30 × 44) / 2

s = 1320 / 2

s = 660 m

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In the Cathode ray experiments, JJ Thomson observed that cathode rays were produced high voltage was applied to an anode and cathode in an evacuated tube.

Thomson surrounded the cathode ray with two electric plates that were charged in opposition to test the qualities of the particles. The negatively charged electric plate was avoided in favor of the positively charged plate, deflecting the cathode ray. This demonstrated the presence of negatively charged particles in the cathode ray.

JJ Thomson discovered during the cathode ray tests that cathode rays were generated when a high voltage was supplied to the anode and cathode inside of an evacuated tube. Cathode rays were deflected away from a negative charge and towards a positive charge, which allowed Thomson to conclude that they were negative particles. It was later determined that these particles were electrons, not cathode rays.

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the bus traveled from all the way back to  in 0.15 hrs then

is the bus's displacement-

Displacement of bus is 3 miles.

Given that

To find

So according the question

We have

                       u = 30 mile/hour.

                      t₁ = 0.1 hour.

                      t₂ = 0.15 hour.

Now, We have to find the total distance travelled by bus

We know that,

         [tex]velocity = \frac{distance}{time}[/tex]

So,

             [tex]u = \frac{distance}{t_1}[/tex]

              [tex]distance d = {u}\times {t_1}[/tex]

              d = 30 × 0.1

              d = 3 miles

The total distance from oprfhs to phs is 3 miles.

This bus firstly travels from oprfhs to phs and come back from phs to oprfhs so the distance travelled by bus will be same i.e 3 miles.

Now, we can say that when bus traveled from phs all the way back to oprfhs in 0.15 hrs then the displacement of the bus is 3 miles.

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The energy that is transferred in this time is E = 1.365 J.

To calculate Charge using formula,

Q = I x t

Q = 0.13A x 35 s

Q = 4.55 C

To calculate energy transferred,

E = Q x V

where,

Q is charge

V is potential difference

So by given values,

E = 4.55  x 0.30

E = 1.365 J

In order to perform work and to produce heat and light, energy must be transferred to a body or to a physical system. Energy is a quantitative property. Energy is a conserved resource; according to the law of conservation of energy, energy can only be transformed from one form to another and cannot be created or destroyed.

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The density of the liquid id 1.73g/ml

we know that density = mass/volume

so in this question mass = 34.719g and volume= 20 ml so density =1.73g/ml

A pure substance's mass concentration in numbers is equal to its density. Density varies greatly between different types of materials and may be significant in terms of packaging, purity, and buoyancy. Osmium and iridium are the known densest elements in conditions of normal temperature and pressure.

To make density comparisons between different systems of units easier, it is occasionally replaced by the dimensionless quantity "relative density" or "specific gravity," which is the ratio of the density of the material to that of a standard material, usually water.

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Answer:

yes

Explanation:

because you have to eat so that you can have strength of swimming again

Answer:

Classical physics predicted that the light given off by an object as its temperature increased is that the energy of the light would increase from visible light into the ultraviolet range

Explanation:

The phenomena are referred to as Black body radiation. When a substance heats up, its electrons become excited. An electron will occasionally descend to a lower state and produce a photon. The frequency of emitted light increases with increasing temperature.

This is also how incandescent light bulbs operate. The majority of the light we see from stars is caused by black body radiation, and we may deduce the temperature of a star based on its hue. Plank's Law is the equation that gives the energy emitted as a function of frequency and temperature.

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The speed of the car is 55.2 m/s.

We can define speed as the ratio of distance to time. We know that the question states the car is one lap behind the lead race car when the lead car has 52 laps to go in a race.

If 1 lap =  1.34km or 1340 m

Distance covered =   1340 m * 52 = 69680 m

Time = 69680 m/ 56.3 m/s

= 1237.7 s

Given that the second car is one lap behind;

51 *  1340 m = 68340 m

Speed =  68340 m/1237.7 s

= 55.2 m/s

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The tuning fork fallen 3.52m away, using doppler effect formula.

The Doppler effect, also known as the Doppler shift, is a term used to explain changes in frequency caused by moving sources of sound or light with regard to an observer. As the source gets closer to the observer, the waves it is emitting become compressed and have a greater frequency.

The mathematical notation of  doppler effect is as follows:

[tex]f_{0}= \frac{v+v_{0} }{v+v_{s} } f_{s}[/tex]

Plugging in the values we get:

[tex]\frac{400}{440} = \frac{345}{345+v_{fork} }[/tex]

400 (345+[tex]v_{fork}[/tex]) = 440(345)

[tex]v_{fork}[/tex] = 34.5m/[tex]s^{2}[/tex]

For distance,

[tex]\frac{v_{fork} *2}{19.6}[/tex] = [tex]\frac{34.5*2}{19.6}[/tex]

distance = 3.52meters.

Therefore, the tuning fork fallen 3.52m away.

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When the mirror produces the magnification of 3.81 when a person’s face is 18.0 cm away, The focal length of a mirror is 0.24 m

An optical system's focal length serves as a gauge for how strongly it diverges or converges light. It is the opposite of the system's optical power. A system is said to be somewhat divergent when the focal length is negative, slightly convergent when the focal length is positive.

Calculations:

Given:

Magnification, m = 3.81

distance between face and lens, d = 18 cm

We know that,

[tex]m=\frac{-d_{i} }{d_{o} }[/tex]

[tex]d_{i} = distance\;between\;object\;and\;lens[/tex]

[tex]d_{0} = distance\;between\;image\;and\;lens[/tex]

[tex]d_{i}=-m \times d_{o}[/tex]

Substitute the known values in the above reaction,

[tex]d_{i}=-3.81 \times 0.18[/tex]

[tex]d_{i}=-0.69\;m[/tex]

We know that, Focal length,

[tex]f=\frac{1}{\frac{1}{d_{0} } + \frac{1}{d_{i} } }[/tex]

Substitute the known values in the above equation,

[tex]f=\frac{1}{\frac{1}{0.18 } + \frac{1}{-0.69 } }[/tex]

By solving the above equation, We get,

[tex]f=0.24\;m[/tex]

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The type of line is used to indicate that a particular surface or surface area is Section lines. Section lines is used to indicate that a particular surface or surface area.

A solid object's surface area is a measurement of the total area that the surface of the object takes up. The definition of arc length for one-dimensional curves and the definition of surface area for polyhedral (i.e., objects with flat polygonal faces), where the surface area is the sum of the areas of its faces, are both much simpler mathematical concepts than the definition of surface area when there are curved surfaces. A smooth surface's surface area is determined using its representation as a parametric surface, such as a sphere. This definition of surface area uses partial derivatives and double integration and is based on techniques used in infinitesimal calculus.

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The position function s(t)m = 0.067t^3 + 2

Given that acceleration function a(t) = dv/dt = 0.4t

Then integrating both the side with respect to t, we get

v(t) = 0.2t^2 + C

Then we have that v(0) = 0 so, C = 0

Thus, velocity function v(t) = ds/dt = 0.2t^2

Again, integrating both sides with respect to t, we have

s(t) = 0.067t^3 +D

Given that s(0)= 2, we get D = 2

Thus, the required position function s(t)m = 0.067t^3 + 2

Based on arrival time variations as a function of source-receiver offset for a few reflection events in the gather, velocity functions are computed for selected CMP gathers.

These are the three equations:

v = u + at.

S = ut + 12at2

v2 = u2 + 2as.

The rate of change in position is known as velocity. The displacement of an object is the change in position, or the smallest distance between its initial location and its final position in a given direction.

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The gravitational acceleration close to the surface of a planet then a mass of 3m will be

Gravitational force is directly related to the mass of a body.

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The security guard make the trip of 120 m of distance in a time of 250 s with a speed of: 0.48 m/s

The formula and procedure we will use to solve this exercise is:

v = x /t

Where:

Information about the problem:

Applying the velocity formula we have that:

v = x /t

v = 120 m /250 s

v = 0.48 m/s

It is a physical quantity that indicates the displacement of a mobile per unit of time, it is expressed in units of distance per time, for example (miles/h, km/h).

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The length of the vector is proportional to the size of the force.

The wheelchair is not accelerating, so the forces on it are balanced.

In a free-body diagram of the wheelchair, force due to gravity points down,  normal force points up, force pushing the wheelchair points forward, friction resisting the motion points backward.

For the force diagram:

Forces are a push or pull agents that causes a change in the state of a body when they are applied to the body.

Unbalanced forces cause acceleration of a body.

In a free-body diagram, the mass (force) on an object is represented by a vector.

The length of the vector is proportional to the size of the force. Suppose you push a wheelchair forward at constant velocity. The wheelchair is not accelerating, so the forces on it are balanced. In a free-body diagram of the wheelchair, the vector for the force due to gravity points down, the vector for the normal force points up, the vector for your force pushing the wheelchair points forward, and the vector for the force of friction resisting the motion points backward.

Considering the picture visual representation of the forces between many interacting objects or the force diagram:

In picture 1: F gravity points down; F normal points up

In picture 2: F gravity points down; F tension points up

In picture 3: F gravity points down; F spring points up.

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μ1 = 0.97 and μ2 = 1.93 (viscosities of fluid below and above plate respectively.)

We have to find the viscosities above and below the plate

Let us take the viscosities above the plate = μ1 ,and below the plate =μ2

Now the force applied due to top layer of the fluid

Т1 = μ (Δu / Δv )

Here Δu and Δv are the velocity of plate and gap between the plate and upper surface respectively.

Where Δu= 0.3

          Δv = 0.03

So,

   T1 = μ( 0.3/0.03)

        =10μ

Now we have to find the force on plate due to bottom of the fluid

T2 = μ2 ×( Δu / Δv)

T2 = μ2 × (0.3/0.03)

T2= 10μ2

Total force per unit is = T1 + T2

i.e., the sum of two  viscous shear .

F/ A = T1 + T2

It is given that sum of two viscous sheer is 29N.

So

T1 + T2 = 29

10μ1 + 10 μ2 = 29

10(μ1 + μ2) = 29

μ1 + μ2 = 2.9  

μ2= 2μ1

Hence we get

μ1 + 2μ2 =2.9

3μ1=2.9

μ1 = 2.9/3

    0.9667≈ 0.967

 μ2 = 2μ1

       =  2 × 0.9667

       =1.9333 ≈1.93

Therefore the viscosities above and below the plate due to the top layer of the fluid are 0.967 and 1.93 respectively.

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By rectangular box formula,  the surface area is 8/h

We need to know about rectangular box volume to solve this problem. The volume of the rectangular box can be calculated by multiplying the base area by height. It can be written

V = SA . h

where V is volume, SA is base area and h is height

From the question above, we know that

SA = square

V = 8 m³

Hence, the surface area is

SA = x²

where x is side of the base length

Substitute to rectangular box volume equation

V = SA . h

8 = x².h

h = 8/x²

x = √(8/h) ...... (1)

Substitute (1) to find surface area function

SA = x²

SA = (√(8/h))²

SA = 8/h

Hence, the surface area is 8/h

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If you approach a light beacon while traveling at one half the speed of light (0.5c) you will measure the speed of light from the beacon to be 0.5 c.

Anti-collision lights, sometimes referred to as beacon lights or strobe lights, are a series of lights that must be installed on every aircraft in order to increase visibility to other aircraft and prevent collisions by alerting other pilots. Light-emitting diodes have lately replaced the incandescent bulbs that were previously used.

Beacon lights are most frequently made of red, amber or yellow, blue, green, and white. Red is used to convey stern warnings about hazards or danger and is most frequently seen on vehicles operated by law enforcement or fire departments.

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The statements are true that radio frequency signals are also called electromagnetic signals and optical signals are based upon photons and not electromagnetic waves, that's why optical signals are not part of the electromagnetic spectrum.

The complete spread of electromagnetic radiation by wavelength or frequency. Although all electromagnetic waves have a wide range of frequencies, wavelengths, and photon energies, they all move at the speed of light in a vacuum.

The range of all electromagnetic radiation is represented by the electromagnetic spectrum, which also includes numerous subranges, often known as parts, such as visible light and ultraviolet radiation. The various parts have different names depending on variations in the emission, transmission, and absorption of the associated waves as well as on the many practical uses for which they are put to use.

All radio waves (such as commercial radio and television, microwaves, and radar), infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays are all included in the entire electromagnetic spectrum, which ranges in frequency from the lowest to the highest (longest to shortest wavelength). Spectroscopy may make use of almost all electromagnetic radiation's frequencies and wavelengths.

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The minimum energy is released, and hence the minimum frequency photons are produced, when the proton and antiproton are at rest once they annihilate.

Energy = 2.27 × 10²³Hz

That is, E=E₀ and K=0. To conserve momentum, each photon must have the identical magnitude of momentum, and p = E/C, so each photon must take away one-half the energy

[tex]E_{min} = \frac{E_{0} }{2}[/tex] = E₀ = 938.3MeV = [tex]hf_{min}[/tex]

[tex]f_{min} =\frac{(938.3MeV) (1.602 * 10^{-13} J/MeV}{6.626 *10^{-34}Js } = 2.27 * 10^{23} Hz[/tex]

How much energy is required to produce a proton-antiproton pair?

The process of creating a particle-antiparticle pair is called pair production. to supply this pair, you would like a boson with sufficient energy. The Mass-Energy of both a proton and an anti-proton is about 938 Mev/c². Translated into Joules, this mean you would like about 27 MJ to do so

The amount of energy (E) produced by annihilation is equal to the mass (m) that disappears multiplied by the square of the speed of light in a vacuum (c)—i.e., E = mc²

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Answer:

The woman displaces a volume of air equivalent to her own volume; VV; V=\dfrac{m}{\rho_{\text{woman}}}=\dfrac{60}{980}=0.0612\mathrm{\ m^3}V= ρ woman m = 98060 =0.0612 m 3

Explanation:

Answer:

0.5=answer

us liquid quarts = millinery

1 ml is 0.00105669

Answer:

0.000439938

Explanation:

divide the 0.50 value by 1137