A baby cows growth. About how many pounds does the baby cow gain each week?

A Baby Cows Growth. About How Many Pounds Does The Baby Cow Gain Each Week?

Answers

Answer 1

Growth per week = 124 - 122 = 126 - 124 = 2

. = 2 pounds + 1 pound additional

. = 3

Then answer is

OPTION B) 3 pounds


Related Questions

The number of algae in a tub in a labratory increases by 10% each hour. The initial population, i.e. the population at t = 0, is 500 algae.(a) Determine a function f(t), which describes the number of algae at a given time t, t in hours.(b) What is the population at t = 2 hours?(c) What is the population at t = 4 hours?

Answers

a) Let's say initial population is po and p = p(t) is the function that describes that population at time t. If it increases 10% each hour then we can write:

t = 0

p = po

t = 1

p = po + 0.1 . po

p = (1.1)¹ . po

t = 2

p = 1.1 . (1.1 . po)

p = (1.1)² . po

t = 3

p = (1.1)³ . po

and so on

So it has an exponential growth and we can write the function as follows:

p(t) = po . (1.1)^t

p(t) = 500 . (1.1)^t

Answer: p(t) = 500 . (1.1)^t

b)

We want the population for t = 2 hours, then:

p(t) = 500 . (1.1)^t

p(2) = 500 . (1.1)^2

p(2) = 500 . (1.21)

p(2) = 605

Answer: the population at t = 2 hours is 605 algae.

c)

Let's plug t = 4 in our function again:

p(t) = 500 . (1.1)^t

p(4) = 500 . (1.1)^4

p(4) = 500 . (1.1)² . (1.1)²

p(4) = 500 . (1.21) . (1.21)

p(4) = 500 . (1.21)²

p(4) = 732.05

Answer: the population at t = 4 hours is 732 algae.

What is the length of the dotted line in the diagram below? Round to the
nearest tenth.

Answers

Answer:

12.1 units

Step-by-step explanation:

A) 14x + 7y > 21 B) 14x + 7y < 21 C) 14x + 7y 5 21 D) 14x + 7y 221match with graph

Answers

As all the options are the same equation

so, we need to know the type of the sign of the inequality

As shown in the graph

The line is shaded so, the sign is < or >

The shaded area which is the solution of the inequaity is below the line

So, the sign is <

So, the answer is option B) 14x + 7y < 21

The beginning mean weekly wage in a certain industry is $789.35. If the mean weekly wage grows by 5.125%, what is the new mean annual wage? (1 point)O $829.80O $1,659.60O $41,046.20$43,149.82

Answers

Given:

The initial mean weekly wage is $ 789.35.

The growth rate is 5.125 %.

Aim:

We need to find a new annual wage.

Explanation:

Consider the equation

[tex]A=PT(1+R)[/tex]

Let A be the new annual wage.

Here R is the growth rate and P is the initial mean weekly wage and T is the number of weeks in a year.

The number of weeks in a year = 52 weeks.

Substitute P=789.35 , R =5.125 % =0.05125 and T =52 in the equation.

[tex]A=789.35\times52(1+0.05125)[/tex]

[tex]A=43149.817[/tex]

[tex]A=43149.82[/tex]

The new mean annual wage is $ 43,149.82.

Final answer:

The new mean annual wage is $ 43,149.82.

Help me please Circle describe and correct each error -2=-3+x/4-2(4)-3+x/4•48=-3+x+3X=11

Answers

Answer

The error in the solution is circled (red) in the picture below.

The equation can be solved correctly as follows

[tex]\begin{gathered} -2=\frac{-3+x}{4} \\ \\ Multiply\text{ }both\text{ }sides\text{ }by\text{ }4 \\ \\ -2(4)=\frac{-3+x}{4}\cdot4 \\ \\ -8=-3+x \\ \\ Add\text{ }3\text{ }to\text{ }both\text{ }sides \\ \\ -8+3=-3+x+3 \\ \\ x=-5 \end{gathered}[/tex]

a group orders three large veggie pizzas each slice represents eighth of an entire Pizza the group eats 3/4 of a piece of how many slices of pizza are left

Answers

1 pizza contain 8 slices, so we can state a rule of three as:

[tex]\begin{gathered} 1\text{ Pizza ------ 8 slices} \\ \frac{3}{4}\text{ pizza ------ x} \end{gathered}[/tex]

then, x is given by

[tex]x=\frac{(\frac{3}{4})(8)}{1}\text{ slices}[/tex]

which gives

[tex]\begin{gathered} x=\frac{3}{4}\times8 \\ x=\frac{3\times8}{4} \\ x=3\times2 \\ x=6\text{ slices} \end{gathered}[/tex]

that is, 3/4 of pizza is equivalent to 6 slices. So, there are 8 - 6 = 2 slices left of one pizza.

However, they bought 3 large pizzas and ate almost one of them. So, there are 2x8 = 16slices plus 2 slices, that is, 18 slices are left.

Percents build on one another in strange ways. It would seem that if you increased a number by 5% and thenincreased its result by 5% more, the overall increase would be 10%.7. Let's do exactly this with the easiest number to handle in percents.(a) Increase 100 by 5%(b) Increase your result form (a) by 5%.(C) What was the overall percent increase of the number 100? Why is it not 10%?

Answers

Answer:

a) 105

b) 110.25

c) Increase of 10.25%. It is not 100% because the second increase of 5% is over the first increased value, not over the initial value.

Step-by-step explanation:

Increase and multipliers:

Suppose we have a value of a, and want a increse of x%. The multiplier of a increase of x% is given by 1 + (x/100). So the increased value is (1 + (x/100))a.

(a) Increase 100 by 5%

The multiplier is 1 + (5/100) = 1 + 0.05 = 1.05

1.05*100 = 105

(b) Increase your result form (a) by 5%.

1.05*105 = 110.25

(C) What was the overall percent increase of the number 100? Why is it not 10%?

110.25/100 = 1.1025

1.1025 - 1 = 0.1025

Increase of 10.25%. It is not 100% because the second increase of 5% is over the first increased value, not over the initial value.

А ВC D0 2 4 68 10 12Which point best represents V15?-0,1)A)point AB)point Bpoint CD)point D

Answers

We have to select a point that is the best representative of the square root of 15.

We can calculate the square root of 15 with a calculator, but we can aproximate with the following reasoning.

We know that 15 is the product of 3 and 5. If we average them, we have 4.

If we multiply 4 by 4, we get 16, that is a little higher than 15.

If we go to the previous number (3) and calculate 3 by 3 we get 9, that is far from 15 than 16.

So we can conclude that the square root of 15 is a number a little less than 4.

In the graph, the point B is the one that satisfy our conclusion, as it is a point in the scale that is between 3 and 4, and closer to 4.

The answer is Point B

The width of a rectangle measures (5v-w)(5v−w) centimeters, and its length measures (6v+8w)(6v+8w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?

Answers

The most appropriate choice for perimeter of rectangle will be given by -

Perimeter of rectangle = (22v + 14w) cm

What is perimeter of rectangle?

At first it is important to know about rectangle.

Rectangle is a parallelogram in which every angle of the parallelogram is 90°.

Perimeter of rectangle is the length of the boundary of the rectangle.

If l is the length of the rectangle and b is the breadth of the rectangle, then perimeter of the rectangle is given by

Perimeter of rectangle = [tex]2(l + b)[/tex]

Length of rectangle = (5v - w) cm

Breadth of rectangle = (6v + 8w) cm

Perimeter of rectangle = 2[(5v - w) + (6v + 8w)]

                                      = 2(11v + 7w)

                                      = (22v + 14w) cm

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Complete Question

The width of a rectangle measures (5v−w) centimeters, and its length measures(6v+8w) centimeters. Which expression represents the perimeter, in centimeters, of the rectangle?

triangle HXI can be mapped onto troangle PSL by a reflection If m angle H = 157 find m angle S

Answers

From the information provided, the triangle HXI can be mapped onto triangle PSL. This means the vertices of the reflected image would now have the following as same measure angles;

[tex]\begin{gathered} \angle H\cong\angle P \\ \angle X\cong\angle S \\ \angle I\cong\angle L \end{gathered}[/tex]

Measure of angle S cannot be determined from the information provided because there is insufficient information given to determine the measure of angle X, hence the angle congruent to it (angle S) likewise cannot be determined.

The half-life of radium is 1690 years. If 70 grams are present now, how much will be present in 570 years?

Answers

Solution

Given that

Half life is 1690 years.

Let A(t) = amount remaining in t years

[tex]\begin{gathered} A(t)=A_0e^{kt} \\ \\ \text{ where }A_{0\text{ }}\text{ is the initial amount} \\ \\ k\text{ is a constant to be determined.} \\ \end{gathered}[/tex]

SInce A(1690) = (1/2)A0 and A0 = 70

[tex]\begin{gathered} \Rightarrow35=70e^{1690k} \\ \\ \Rightarrow\frac{1}{2}=e^{1690k} \\ \\ \Rightarrow\ln(\frac{1}{2})=1690k \\ \\ \Rightarrow k=\frac{\ln(\frac{1}{2})}{1690} \\ \\ \Rightarrow k=-0.0004 \end{gathered}[/tex]

So,

[tex]A(t)=70e^{-0.0004t}[/tex][tex]\Rightarrow A(570)=70e^{-0.0004(570)}\approx55.407\text{ g}[/tex]

Therefore, the answer is 55.407 g

Point P is in the interior of

Answers

[tex]\because m\angle OZQ=125[/tex]

∵ m< OZQ = m[tex]\because m\angle OZP=62[/tex]Substitute the measures of the given angles in the equation above

[tex]\therefore125=62+m\angle PZQ[/tex]

Subtract 62 from both sides

[tex]\begin{gathered} \therefore125-62=62-62+m\angle PZQ \\ \therefore63=m\angle PZQ \end{gathered}[/tex]

The measure of angle PZQ is 63 degrees


Find the domain of the function f(x)=√100x²

Answers

The domain of the function √(100x²) will be (-∞,∞) as the definition of domain states that the set of inputs that a function will accept is known as the domain of the function in mathematics

What is domain?

The range of values that we are permitted to enter into our function is known as the domain of a function. The x values for a function like f make up this set (x). A function's range is the set of values it can take as input.

What is function?

A function in mathematics from a set X to a set Y assigns exactly one element of Y to each element of X. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.

Here,

The function is √(100x²).

The domain would be (-∞,∞).

The set of inputs that a function will accept is known as the domain of the function in mathematics, and the domain of the function √(100x²) will be (-∞,∞), according to the definition of domain.

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Use the distance formula to find the distance between the points given.(-9,3), (7, -6)

Answers

Given the points:

[tex](-9,3),(7,-6)[/tex]

You need to use the formula for calculating the distance between two points:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1^})^2[/tex]

Where the points are:

[tex]\begin{gathered} (x_1,y_1) \\ (x_2,y_2) \end{gathered}[/tex]

In this case, you can set up that:

[tex]\begin{gathered} x_2=7 \\ x_1=-9 \\ y_2=-6 \\ y_1=3 \end{gathered}[/tex]

Then, you can substitute values into the formula and evaluate:

[tex]d=\sqrt{(7-(-9))^2+(-6-3)^2}[/tex][tex]d=\sqrt{(7+9)^2+(-9)^2}[/tex][tex]d=\sqrt{(16)^2+(-9)^2}[/tex][tex]d=\sqrt{256+81}[/tex][tex]d=\sqrt{337}[/tex][tex]d\approx18.36[/tex]

Hence, the answer is:

[tex]d\approx18.36[/tex]

1. flight 1007 will hold 300 passengers the airline has booked 84% of the plane already. How many seats are open for the last-minute Travelers?2.Carly interviewed students to ask their favorite kind of television programs. 12 students claimed that they preferred comedies, 18 like drama 13 enjoy documentaries, and 7 voted for news programs what percentage of the students selected comedies?

Answers

The total passengers in the flight is P=300.

Determine the passenger who booked the seat in the flight.

[tex]\begin{gathered} Q=\frac{84}{100}\cdot300 \\ =252 \end{gathered}[/tex]

The number of seats booked by passenger is 252.

Determine the seats available for last-minutes travelers.

[tex]\begin{gathered} S=300-252 \\ =48 \end{gathered}[/tex]

So 48 seats available for the last minute travelers.

1 4/5 + (2 3/20 + 3/5) use mental math and properties to solve write your answer in simpleist form

Answers

Given data:

The given expression is 1 4/5 + (2 3/20 + 3/5).

The given expression can be written as,

[tex]\begin{gathered} 1\frac{4}{5}+(2\frac{3}{20}+\frac{3}{5}_{})=\frac{9}{5}+(\frac{43}{20}+\frac{3}{5}) \\ =\frac{9}{5}+\frac{43+12}{20} \\ =\frac{9}{5}+\frac{55}{20} \\ =\frac{36+55}{20} \\ =\frac{91}{20} \end{gathered}[/tex]

Thus, the value of the given expression is 91/20.

Identify the vertex of the function below.f(x) - 4= (x + 1)2-onSelect one:O a. (-4,1)O b.(1,-4)O c. (-1,-4)O d.(-1,4)

Answers

The standard equation of a vertex is given by:

[tex]f(x)=a(x-h)^2+k[/tex]

where (h,k) is the vertex.

Comparing with the given equation after re-arranging:

[tex]f(x)=(x+1)^2+4[/tex]

The vertex of the function is (-1, 4)

What is the solution set of x over 4 less than or equal to 9 over x?

Answers

we have

[tex]\frac{x}{4}\leq\text{ }\frac{9}{x}[/tex]

Multiply in cross

[tex]x^2\leq36[/tex]

square root both sides

[tex](\pm)x\leq6[/tex]

see the attached figure to better understand the problem

the solution is the interval {-6,6}

the solution in the number line is the shaded area at right of x=-6 (close circle) and the shaded area at left of x=6 (close circle)

factoring out: 25m + 10

Answers

Answer:

5(5m + 2)

Explanation:

To factor out the expression, we first need to find the greatest common factor between 25m and 10, so the factors if these terms are:

25m: 1, 5, m, 5m, 25m

10: 1, 2, 5, 10

Then, the common factors are 1 and 5. So, the greatest common factor is 5.

Now, we need to divide each term by the greatest common factor 5 as:

25m/5 = 5m

10/5 = 2

So, the factorization of the expression is:

25m + 10 = 5(5m + 2)

Which function has the greatest average rate of change on the interval [1,5]

Answers

Answer:

Explanation:

Given: interval [1,5]

Based on the given functions, we start by computing the function values at each endpoint of the interval.

For:

[tex]\begin{gathered} y=4x^2 \\ f(1)=4(1)^2 \\ =4 \\ f(5)=4(5)^2 \\ =100 \\ \end{gathered}[/tex]

Now we compute the average rate of change.

[tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{100-4}{5-1} \\ \text{Calculate} \\ =24 \end{gathered}[/tex]

For:

[tex]\begin{gathered} y=4x^3 \\ f(1)=4(1)^3 \\ =4 \\ f(5)=4(5)^3 \\ =500 \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{500-4}{5-1} \\ =124 \end{gathered}[/tex]

For:

[tex]\begin{gathered} y=4^x \\ f(1)=4^1 \\ =4 \\ f(5)=4^5 \\ =1024 \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{1024-4}{5-1} \\ =255 \end{gathered}[/tex]

For:

[tex]\begin{gathered} y=4\sqrt[]{x} \\ f(1)=4\sqrt[]{1} \\ =4 \\ f(5)\text{ = 4}\sqrt[]{5} \\ \end{gathered}[/tex][tex]\begin{gathered} \text{Average rate of change = }\frac{f(5)-f(1)}{5-1} \\ =\frac{(4\sqrt[]{5\text{ }})\text{ -4}}{5-1}\text{ } \\ =1.24 \end{gathered}[/tex]

Therefore, the function that has the greatest average rate is

[tex]y=4^x[/tex]

A line passes through the point (-2,-7) and has a slope of 4

Answers

Answer:

y= 4x +1

Step-by-step explanation:

The equation of a line, in slope-intercept form, is given by y= mx +c, where m is the slope and c is the y-intercept.

Given that the slope is 4, m= 4.

Substitute m= 4 into y= mx +c:

y= 4x +c

To find the value of c, substitute a pair of coordinates the line passes through.

When x= -2, y= -7,

-7= 4(-2) +c

-7= -8 +c

c= -7 +8

c= 1

Substitute the value of c into the equation:

Thus, the equation of the line is y= 4x +1.

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I'm attempting to solve and linear equation out of ordered pairs in slopes attached

Answers

Line equationInitial explanation

We know that the equation of a line is given by

y = mx + b,

where m and b are numbers: m is its slope (shows its inclination) and b is its y-intercept.

In order to find the equation we must find m and b.

In all cases, m is given, so we must find b.

We use the equation to find b:

y = mx + b,

↓ taking mx to the left side

y - mx = b

We use this equation to find b.

1

We have that the line passes through

(x, y) = (-10, 8)

and m = -1/2

Using this information we replace in the equation we found:

y - mx = b

↓ replacing x = -10, y = 8 and m = -1/2

[tex]\begin{gathered} 8-(-\frac{1}{2})\mleft(-10\mright)=b \\ \downarrow(-\frac{1}{2})(-10)=5 \\ 8-5=b \\ 3=b \end{gathered}[/tex]

Then, the equation of this line is:

y = mx + b,

y = -1/2x + 3

Equation 1: y = -1/2x + 3

2

Similarly as before, we have that the line passes through

(x, y) = (-1, -10)

and m = 0

we replace in the equation for b,

y - mx = b

↓ replacing x = -1, y = -10 and m = 0

-10 - 0 · (-1) = b

↓ 0 · (-1) = 0

-10 - 0 = b

-10 = b

Then, the equation of this line is:

y = mx + b,

y = 0x - 10

y = -10

Equation 2: y = -10

3

Similarly as before, we have that the line passes through

(x, y) = (-6, -9)

and m = 7/6

we replace in the equation for b,

y - mx = b

↓ replacing x = -6, y = -9 and m = 7/6

[tex]\begin{gathered} -9-\frac{7}{6}(-6)=b \\ \downarrow\frac{7}{6}(-6)=-7 \\ -9-(-7)=b \\ -9+7=b \\ -2=b \end{gathered}[/tex]

Then, the equation of this line is:

y = mx + b,

y = 7/6x - 2

Equation 3: y = 7/6x - 2

4

The line passes through

(x, y) = (6, -4)

and m = does not exist

When m does not exist it means that the line is vertical, and the equation looks like:

x = c

In this case

(x, y) = (6, -4)

then x = 6

Then

Equation 4: x = 6

5

The line passes through

(x, y) = (6, -6)

and m = 1/6

we replace in the equation for b,

y - mx = b

↓ replacing x = 6, y = -6 and m = 1/6

[tex]\begin{gathered} -6-\frac{1}{6}(6)=b \\ \downarrow\frac{1}{6}(6)=1 \\ -6-(1)=b \\ -7=b \end{gathered}[/tex]

Then, the equation of this line is:

y = mx + b,

y = 1/6x - 7

Equation 5: y = 1/6x - 7

12 + 24 =__(__+__)
Find the GCF. The first distributing number should be your GCF

Answers

A group of numbers' greatest common factor (GCF) is the biggest factor that all the numbers have in common. For instance, the numbers 12, 20, and 24 share the components 2 and 4.

Therefore, 12 and 24 have the most things in common. Figure 2: LCM = 24 and GCF = 12 for two numbers.

Find the other number if one is 12, then. What does 12 and 24's GCF stand for?

Example of an image for 12 + 24 = ( + ) Locate the GCF. You should distribute your GCF as the first number.

12 is the GCF of 12 and 24. We must factor each number individually in order to determine the highest common factor of 12 and 24 (factors of 12 = 1, 2, 3, 4, 6, 12; factors of 24 = 1, 2, 3,.

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4 Use the sequence below to complete each task. -6, 1, 8, 15, ... a. Identify the common difference (a). b. Write an equation to represent the sequence. C. Find the 12th term (a) our Wilson (All Things Algebral. 2011 Enter your answer(s) here

Answers

we have

-6, 1, 8, 15, ...

so

a1=-6

a2=1

a3=8

a4=15

a2-a1=1-(-6)=7

a3-a2=8-1=7

a4-a3=15-8=7

so

the common difference is

d=7

Part 2

write an equation

we have that

The equation of a general aritmetic sequence is equal to

an=a1+(n-1)d

we have

d=7

a1=-6

substitute

an=-6+(n-1)7

an=-6+7n-7

an=7n-13

Part 3

Find 12th term

we have

n=12

a12=-7(12)-13

a12=71

If b is a positive real number and m and n are positive integers, then.A.TrueB.False

Answers

we have that

[tex](\sqrt[n]{b})^m=(b^{\frac{1}{n}})^m=b^{\frac{m}{n}}[/tex]

therefore

If b is a positive real number

then

The answer is true

solve for x. then find the missing piece(s) of the parallelogram for #7

Answers

[tex]\begin{gathered} 2x+30+2x-10=180 \\ 2x+2x+30-10=180 \\ 4x+20=180 \\ 4x=160 \\ x=\frac{160}{4} \\ x=40^0 \end{gathered}[/tex]

Let us find the angles of the parallelogram below

[tex]\begin{gathered} 2x+30 \\ x=40 \\ 2(40)+30 \\ 80+30 \\ 110^0 \end{gathered}[/tex][tex]\begin{gathered} 2x-10 \\ 2(40)-10 \\ 80-10 \\ 70^0 \end{gathered}[/tex]

Theorem+: opposite angles of a parallelogram are the same

Hence the angles of the parallelogram are 110, 70, 110, and 70

what is 12 + 0.2 + 0.006 as a decimal and word form

Answers

[tex]12+0.2+0.006=12.206[/tex]

twelve and two hundred six thousandths

The sum of 19 and twice a number

Answers

Answer:

2x+19

Step-by-step explanation:

Let x be the number

2x+19

Add the rational expression as indicated be sure to express your answer in simplest form. By inspection, the least common denominator of the given factor is

Answers

Notice that the least common denominator is 9*2=18, therefore:

[tex]\begin{gathered} \frac{x-3}{9}+\frac{x+7}{2}=\frac{2(x-3)}{9\cdot2}+\frac{9(x+7)}{9\cdot2}, \\ \frac{x-3}{9}+\frac{x+7}{2}=\frac{2x-6}{18}+\frac{9x+63}{18}, \\ \frac{x-3}{9}+\frac{x+7}{2}=\frac{2x-6+9x+63}{18}, \\ \frac{x-3}{9}+\frac{x+7}{2}=\frac{11x+57}{18}\text{.} \end{gathered}[/tex]

Answer:

[tex]\frac{x-3}{9}+\frac{x+7}{2}=\frac{11x+57}{18}\text{.}[/tex]

2. Luis hizo una excursión de 20 km 75 hm 75 dam 250 m en tres etapas. En la primera recorrió 5 km 5 hm, y en la segunda 1 km 50 dam más que en la anterior. ¿Cuánto recorrió en la tercera etapa? Expresa el resultado de forma compleja

Answers

[tex]\begin{gathered} 5\text{ km 5 hm - first stage} \\ 6\text{ km 5 hm 50 dam - second stage} \\ \text{Subtract that from the total} \\ 14\text{ km 70 hm 25 dam 250 m - this would be third stage} \end{gathered}[/tex]

Other Questions
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