If the hiker moves at a constant 500 Watts per meter, it will take 2.4 hours to ascend the hill (1200 meters x 500 Watts).
Explain about the Motion.The way a body's orientation or position changes over time. Translation describes motion along a line or a curve. Rotation is a motion in which a body's orientation is altered.
An object moving or being moved is referred to as motion. It's said that motion follows a pattern when it repeats. Making predictions about future motion requires the observation of patterns of motion. Friction is the name for the force that prevents moving objects from moving.
The fundamental kinematics equation of motion, which states that the distance travelled divided by the object's speed equals the amount of time required to travel that distance.
Following are the steps to determine how long it took to climb the hill:
To start, figure out the hiker's power output.
500 Watts are being produced continuously by the hiker.
Step two is to compute the climbing time.
By dividing the distance travelled by the time it took to climb the slope.
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An aluminum rod is 20. 0 cm long at 20°C and has a mass of 350 g. If 10 000 J of energy is added to the rod by heat, what is the change in length of the rod?
Linear expansion refers to the increase in length of a material as its temperature increases. It is typically measured as the change in length per unit length per degree of temperature change. the answer change in length of the rod is approximately 0.014 cm.
This effect is caused by the thermal motion of the atoms or molecules in a material, which increases as the temperature increases. Linear expansion is typically a small effect, but can be significant in certain applications, such as in the construction of bridges or buildings.The change in length of the rod can be calculated using the equation for linear expansion:
ΔL = L0 * α * ΔT
Where:
L0 = initial length (20.0 cm)
α = coefficient of linear expansion for aluminum (about 2.5 x 10^-5 /°C)
ΔT = change in temperature (can be calculated by using the heat added, mass, and specific heat capacity of aluminum)
First we need to calculate ΔT, we know that c(Aluminum)= 0.90 J/g °C
ΔT= Q / (m * c)where:
Q = heat added (10000 J)
m = mass of the rod (350 g)
c = specific heat capacity of aluminum (0.90 J/g °C)
Substituting the values we have,
ΔT = 10000 J / (350 g * 0.90 J/g °C) = 28.57142857142857 °C
Now we can find the change in length,
ΔL = L0 * α * ΔT = 20.0 cm * 2.5 x 10^-5 /°C * 28.57142857142857 °C = 0.014 cm
So the change in length of the rod is approximately 0.014 cm.
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a horizontal clothesline is tied between 2 poles, 18 meters apart. when a mass of 2 kilograms is tied to the middle of the clothesline, it sags a distance of 5 meters. what is the magnitude of the tension on the ends of the clothesline?
The magnitude of the tension on the ends of the clothesline is 175N.
Tension is a mechanical term that describes the opposing resisting force that a rope or string experiences when it experiences a weight at the end of it. It can be measured in Newtons. It can be found all the way down a rope or thread.
we know that the combined vertical tension in the clothesline must equal the weight of the mass;
using g=9.8m/s/s, W=2kgx 9.8m/s/s = 19.6N
now, draw a diagram of the situation; if we call x the angle between the clothesline and the horizontal line that connects the poles, we have that
tan x = 1/9 => x =6.34 deg
now, we can use this angle to show that if T is the tension in the clothes line, the vertical component of tension is T sin x = T sin 6.34
since both sides of the line exert a tension up, we have that
2 T sin 6.34 = W = 19.6 N
or T= 175N.
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A mass on a string of unknown length oscillates as a pendulum with a period of 6. 6 s. Parts A to D are independent questions, each referring to the initial situation.
What is the period if the mass is doubled?
What is the period if the string length is doubled?
The time period is not depends on the mass. So even the mass is doubled its time period not changes. The period of a simple pendulum is given by the equation T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
A. In this equation, the mass does not appear, so doubling the mass of the pendulum does not affect the period. If the mass of the pendulum is doubled, the period of the pendulum will remain the same.
B. If the length of the pendulum's string is doubled, the period will also be doubled. The period of a simple pendulum is given by the equation T = 2π√(L/g),
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Doubling the length of the pendulum increases the length by a factor of 2, which increases the period by a factor of 2.
What is Pendulum?A pendulum is a weight suspended from a pivot so that it can swing freely. The weight, also known as a bob, is the object that oscillates (moves back and forth) under the influence of gravity. Pendulums can be used to measure time, as in the case of a grandfather clock, or as a simple device to demonstrate harmonic motion.
The force acting on the pendulum is gravity, which is pulling the bob downward. This force is opposed by the tension in the string or rod that is holding the bob. The bob has kinetic energy when it is moving, and potential energy when it is at the highest or lowest point of its swing. As the bob swings back and forth, its kinetic and potential energy are constantly changing.
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a 60 kg hiker wishes to climb 1200 meter high if he can generate a sustained average power of 500 watts, how long will the climb take
The time it will take do the hiker to climb the 1200m high wall is 1,411.2 seconds.
How to calculate time from power?Power refers to the measure of the rate of doing work or transferring energy.
Power = Work done/time
Since work = force × distance the body is moved
Power = (m × g × h) / t
Where;
m = the mass of the bodyg = the acceleration due to gravityh = the height the body has fallent = the time the body has fallenAccording to this question, a 60kg hiker wishes to climb 1200m high. If he can generate a sustained average power of 500 watts, the time it will take to climb is as follows;
500 = 60 × 9.81 × 1200/t
500t = 705,600
t = 1,411.2 seconds
Therefore, 1,411.2 seconds is the time it will take the hiker.
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a rifle with a weight of 30.0 n fires a 5.0-g bullet with a speed of 300 m/s. (a) find the recoil speed of the rifle. (b) if a 700-n man holds the rifle firmly against his shoulder, find the recoil speed of man and rifle.
The recoil speed of man and rifle are 0.05 m/s and 0.0021 m/s .
(a) The recoil speed of the rifle can be found using the law of conservation of momentum. The momentum of the bullet is equal to the momentum of the rifle and the man.
Momentum of the bullet = mv = (5.0 g)(300 m/s) = 1.5 kg·m/s
Momentum of the rifle = (30.0 n)(v)
Therefore, v = 1.5 kg·m/s ÷ 30.0 n = 0.05 m/s
The recoil speed of the rifle is 0.05 m/s.
(b) The total momentum of the man and the rifle is equal to the momentum of the bullet.
Momentum of the man and rifle = mv = (700 n)(v)
Therefore, v = 1.5 kg·m/s ÷ 700 n = 0.0021 m/s
The recoil speed of the man is 0.0021 m/s.
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a 20 kg box is attached to a compressed spring that has a spring constant of 300 n/m. the box is resting on a frictionless surface and the spring is compressed 30 cm. how fast will the box be moving after the spring releases the box?
The box will be moving at the speed of 1.16 m/s, when the spring is compressed by 30 cm, if the spring constant is 300 n/m and the mass of the box is 20 kg.
Potential energy stored in the spring during compression of x cm, U = 0.5 kx²
Kinetic Energy possessed by the object moving at a speed of v, = 0.5 mv²
0.5 × 20 × v² = 0.5 × 300 × 0.3²
v² = (0.5 × 300 × 0.3²)/(0.5 × 20)
v² = 1.35
v = √1.35
v = 1.16 m/s
So the box will be moving at a speed of 1.16 m/s.
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A 1.68 x 10-15 N oil drop is suspended between two oppositely-charged parallel plates. The plates are 4.0 cm apart and there is a potential difference of 140 V between them. The top plate is positive and the bottom plate is negative.
a) Sketch the electric field between the plates.
b) Calculate the magnitude of the electric field between the plates.
c) Determine the charge on the oil drop. Include the SIGN.
d) How many electrons is this charge composed of?
A magnetic field is created between these two charged parallel plates. The field indicates a direction from the positive plate to the negative plate.
What is a positively charged plate?Protons are in excess on a positively charged metal plate. From the electron's point of view, a positively charged aluminium.The force acting on a positively charged test particle is considered to constitute the definition of the field's direction. Positive charges always gravitate away from other positive charges and in the direction of negative charges.The separator, which is made of polyethylene, divides the positive and negative plates to allow for an effective flow of electrical current.The density of surface charges on a negatively charged plate is 2 x 10-6 C/m2. The least initial distance that an electron must travel if it is travelling toward a plate with 200 eV of energy but cannot strike the plate is: 1,77 mm, 3,51 mm, and 1,77 cm, 3,51 cm.To learn more about parallel refer to:
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Where are the carbon atoms before the chemical reaction starts?
Carbon atoms combine with carbon dioxide molecules to form ethanol. The area of the atom where a chemical reaction takes place is called the electron cloud.
What molecule are carbon atoms in before the chemical change?In ethanol, carbon atoms join molecules of carbon dioxide. The electron cloud is the region of the atom that is involved in a chemical process. The area of the atom surrounding the nucleus is called the electron cloud. The particle that caused the reaction to take place is an electron, which is found in the electron cloud.
A chemical reaction neither creates nor destroys atoms. Rearranging the atoms occurs. Due to this, new compounds are created that have properties that differ from the initial substances.
The materials that initiate a chemical reaction are known as reactants, while the materials created as a result of the reaction are known as products.
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consider steady one-dimensional heat conduction through a cylindrical or spherical layer. what can you say about the rate of heat transfer through the layer
The rate of heat transfer through the layers of the cylinder will be constant.
There is no heat flow from the sides of the object. The cross-sectional area of a body in the direction of heat flow is constant. This is called one-dimensional heat flow because the temperature of a body is a function of only one dimension (distance from each side of the body). Heat transfer from the hot combustion gases includes forced convection through the hot gas boundary layer, conduction through the cylinder wall, and forced convection (including boiling) into the coolant liquid in head, engine block, and piston.
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a proton is placed at point a. the proton is then removed and an electron is placed at point b. what is the direction of the electric force ? give angle relative to x with ccw as positive. what is the direction of the electric force ? what is true of the magnitude of the two forces?
When a proton is removed from point A and an electron is placed at point B, the direction of the electric force will be from point B towards point A. The angle of this force relative to the x-axis would be 180 degrees, with counterclockwise as positive.
As the electron and proton have equal and opposite charges, the magnitude of the force between them will be the same as the magnitude of the force between the proton and the electron.
The magnitude of the force between the proton and electron can be determined by Coulomb's law, which states that the force is proportional to the product of the charges and inversely proportional to the square of the distance between them.
In other words, the magnitude of the two forces is equal, but the direction of the two forces is opposite.
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A positively charged rod is brought near one end of an uncharged metal bar. The end of the metal bar farthest from the charged rod will be charged
positive.
negative.
neutral
The end of the metal bar farthest from the positively charged rod will be negatively charged.
What is the initial charge of the metal bar before the rod is brought near?
The initial price of the metal bar earlier than the rod is delivered near is uncharged. That is specific inside the trouble assertion, wherein it's far said that the steel bar is uncharged before the undoubtedly charged rod is brought close to. The steel bar is taken into consideration as a impartial item earlier than the creation of the charged rod. It method that the wide variety of protons and electrons inside the metallic bar are identical, so there's no internet rate. Therefore, the initial price of the steel bar earlier than the rod is brought close to is uncharged.
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19. A rock that is thrown vertically downward travels
10.0 m before hitting the ground. If it strikes the
ground at a velocity of 15.0 m/s, how long did it
take to reach the ground?
It took 2.04 seconds for the rock to reach the ground, after it was thrown vertically downward at a velocity of 15.0 m/s.
What is velocity?
Velocity is a vector quantity that describes the rate of change of an object's position in a specific direction. It is defined as the distance an object travels per unit of time. The standard unit of velocity is meters per second (m/s) in the International System of Units (SI).
To determine how long it took for the rock to reach the ground, we can use the equation:
d = v0t + (1/2)gt^2
Where d is the distance traveled, v0 is the initial velocity (which is zero for a rock that is thrown vertically downward), t is the time, and g is the acceleration due to gravity (approximately 9.8 m/s^2).
Since we know the distance traveled and the final velocity of the rock, we can rearrange the equation and solve for t:
t = (2d / g)^1/2
Plugging in the given values:
t = (2 * 10 m / 9.8 m/s^2)^1/2 = (2 * 10 / 9.8)^1/2 = 2.04 s
Therefore, it took 2.04 seconds for the rock to reach the ground, after it was thrown vertically downward at a velocity of 15.0 m/s.
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What is the electric flux through one side of a cube that has a single point charge of -3. 80 µC placed at its center? Hint: You do not need to integrate any equations to get the answer.
? N·m^2/C
The electric flux through one side of a cube is found as -7.1 x 10⁴ V.m.
Explain the term Gauss's Law?According to Gauss's law, the enclosed charge is the only factor affecting the electric flux across a closed surface. Furthermore, no matter how the closed surface is shaped, the electric flux for a point charge remains constant.The equation is given by
ФE = q(int) / ∈₀
ФE = electric flux passing any of the surface
q(int) = charge enclosed by surface = -3. 80 µC
∈₀ = 8.85 x 10⁻¹² F/m (permittivity of free space)
Put the given values.
ФE = -3. 80 x 10⁻⁶ /8.85 x 10⁻¹² / 6 (for one surface of the cube)
ФE = -7.1 x 10⁴ V.m
Thus, the electric flux through one side of cube is found as -7.1 x 10⁴ V.m.
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A rocket of mass 1000kg containing a propellant gas of 3000kg is to be launched vertically. If the fuel is consumed at a steady rate of 60kg/s, calculate the least velocity of the exhaust gases if the rocket and content will just lift off the launching pad immediately after firing?
A 1000 kg rocket with a 3000 kg propellant gas is intended for vertical launch. If the gasoline is used consistently at a rate of.
What initiates the launch of a rocket?When the upward force of thrust is higher than the downward force of gravity, a rocket is said to have launched. A rocket will speed upwards as a result of this imbalanced force. As long as the thrust of a rocket engine produces an upward force, a missile will continue to accelerate.
What forces are present when a rocket is launched?A rocket experiences four forces while in flight: weight, velocity, and the aerodynamics of lift and drag. The weight's size is determined by the.
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a hot rod of mass 1000 kg, starting from rest reaches a speed of 130 m/s in only 29 s. what is the average output power?
A 1000 kilogramme FRICTION is driving at a pace of 130 metres per second. To bring a car to a stop, the brakes are applied. Hence, 223 J is the average output power
What causes road friction?To prevent sliding vehicles or spinning wheels, friction or traction are essential. The act of rubbing one surface or object against another is known as friction. The maximum acceleration and shortest stopping distance are determined by the friction between the tyres of your car and the road.
Is the friction on tyre roads static?Because there is only frictional force acting on the car, friction is acting backwards. The amount of friction that can be applied to a vehicle's tyres to prevent road traction is as high as.
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. In a railroad yard, a train is being assembled. An empty boxcar, coasting at 3.0 m/s, strikes a
loaded car that is stationary, and the cars couple together. Each of the boxcars has a mass of 9000
kg when empty, and the loaded car contains 55,000 kg of lumber. what is
the final velocity
The final velocity of the two coupled cars is 1.2 m/s.
What is the final velocity of the two coupled cars?The final velocity of the two coupled cars when the empty boxcar strikes the loaded car is determined by the conservation of momentum.Momentum is defined as the product of mass and velocity and is conserved in an isolated system. Since the system of the two cars is considered isolated, the total momentum before the collision is equal to the total momentum after the collision.The total momentum before the collision is equal to the momentum of the empty boxcar. The momentum of the empty boxcar is equal to 9000 kg multiplied by 3.0 m/s, which is 27000 kg m/s.The total momentum after the collision is equal to the sum of the momentum of the loaded car, which is 55000 kg multiplied by 0 m/s, and the momentum of the two coupled cars.The final velocity of the two coupled cars is determined by solving for the velocity in the equation 27000 kg m/s = (9000 + 55000) kg multiplied by v, with v being the final velocity of the two coupled cars. The final velocity of the two coupled cars is equal to 2.4 m/s.To learn more about The final velocity refer to:
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Please help!!!!!!!!!!!!!!!
Answer:
1. The properties of ionic compounds are:
a. Ionic compounds usually exist in the form of crystalline solids at room temperature.
b. Ionic compounds are soluble in water.
c. Ionic compounds have high melting and boiling points
d. Ionic compounds don't conduct electricity in solid state.
e. The ions of ionic compound crystals are orderly arranged.
2. The properties of covalent compounds are:
a.Covalent compound generally exist in liquid and gaseous state.
b. They are poor conductor of elctricity.
c. Melting and boiling points of covalent compounds are lower than ionic compound.
d. They are generally soluble in non- polar solvents such as benzene.
e. They are made up of molecules held together by weak Vanderwaal's force of attraction.
3. Salt is a covalent compound.
4. Sugar is an ionic compound.
Rest of the assignment is practical. Do at a Lab.
A block is on a surface with
is = 0. 325. It takes 4. 11 N to
break it free from static friction.
How much normal force acts
on the block?
(Unit = N)
The normal force acting on the block is 4.11N/0.325 = 12.68N.
Can you explain the difference between static friction and kinetic friction?
Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.
On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.
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The normal force acting on the block is 12.68N when block is on a surface with is = 0. 325. It takes 4. 11 N to break it free from static friction.
Evaluating :Surface = 0.325
force = 4.11 N
Static friction = 4.11N/0.325
= 12.68N.
Static friction :Static friction is the force that opposes to the motion of an object when it is at rest. It acts between two surfaces that are in contact and are not moving relative to each other. The force of static friction is always less than or equal to the limiting friction, and it is needed to move an object to overcome the static friction and start moving.
Kinetic friction :On the other hand, kinetic friction is the force that opposes to the motion of an object when it is in motion. It acts between two surfaces that are in contact and are moving relative to each other. The force of kinetic friction is always less than the static friction and it is needed to maintain the motion of an object. In general, the coefficient of kinetic friction is lower than the coefficient of static friction.
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the volume of a gas is proportional to the temperature of a gas is known as
Charles's law means that the volume of a gas is directly proportional to its absolute temperature
Simple Gas Laws - Boyle's Law, Charles' LawBoyle's Law tells us that the volume of a gas increases as the pressure decreases. Charles's law tells us that the volume of a gas increases with increasing temperature
This is stated by Karl's law, also known as the law of volumes
For a dry gas sample, its volume and Kelvin temperature are directly proportional if the pressure is kept constant
Mathematical representation -
[tex]\begin{equation*} PV=nRT \end{equation*}[/tex] P : is a Pressure(Pa)
[tex]\begin{equation*} V=\frac{nRT}{P} \end{equation*}[/tex] V : is volume ([tex]m^{3}[/tex])
T : absolute temperature (K)
R : gas constant [tex]\begin{equation*} 8.314K^{-1}.mol^{-1} \end{equation*}[/tex]
n : amount of substance of the gas (mole)
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Which equation can you use to calculate the mechanical advantage of a simple machine?
MA = delta x1 / delta x0
MA = delta xi - delta x0
MA = delta xi * delta x0
MA = delta x0 / delta x1
The equation that can be used to calculate the mechanical advantage of a simple machine is as follows: MA = delta x0 / delta x1 (option D).
How to calculate mechanical advantage?Mechanical advantage is the ratio of the output force produced by a machine (especially a simple machine) to the applied input force.
The mechanical advantage (MA) is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = Fo/Fi
Where;
Fo = output forceFi = input forceAccording to this question, option D best describes the equation that can be used to calculate the mechanical advantage of a simple machine.
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You are pushing a book across a desk with a constant velocity. What are the forces acting on the book and in what direction? Are the y-forces equal in magnitude, why or why not? Are the x-forces equal in magnitude, why or why not? Explain using Newton’s Second Law. If you push on the book, according to Newton’s Third Law of Motion, what is the equal and reactive force?
When you are pushing a book across a desk with a constant velocity, there are two forces acting on the book: friction and the force of your push.
The force of friction acts in the opposite direction to the motion of the book and opposes the motion of the book. The force of friction is caused by the interaction between the bottom surface of the book and the surface of the desk.
The force of your push acts in the same direction as the motion of the book and causes the book to move.
The y-forces on the book are not equal in magnitude, as there is only one force acting in the y-direction, which is the force of friction. The x-forces are also not equal in magnitude, as there is one force acting in the x-direction, which is the force of your push.
According to Newton's Second Law, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In this case, since the book is moving with a constant velocity, the forces acting on the book are balanced, and the net force on the book is zero.
According to Newton's Third Law of Motion, for every action, there is an equal and opposite reaction. So, when you push on the book, the equal and opposite force is the force exerted by the book on your hand.
Answer:
The book is being pushed from the side meaning there are horizontal forces at work. The first is an applied force, the second is a force of friction against the motion. Since the book is moving at a constant velocity, the book is not accelerating. This means that the forces must be balanced.
Have a Nice Day : ) .
a tennis ball is struck horizontally from a height of 1 m. with this information alone, can we find how long the ball stayed airborne?
We cannot find how long the tennis ball that is struck horizontally from a height of 1 meter will stay airborne with the information given.
To determine the time of flight, we would need additional information such as the initial velocity of the ball, the angle at which it was struck, and the drag coefficient of the ball.
The horizontal component of velocity does not change under the influence of gravity alone, so we can't use it to determine how long the ball stays in the air. Also, we need to know the angle of launch and the drag coefficient of the ball to calculate the time of flight.
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The distance (miles) a rider travels on a mountain trail is given by s(t) = 3t^3 + 2t^2 + 4. What is the rider's acceleration after two minutes?
A.
36 miles/min2
B.
38 miles/min2
C.
40 miles/min2
D.
44 miles/min2
Answer:
To determine the rider's acceleration after two minutes, we need to find the second derivative of the distance function s(t) = 3t^3 + 2t^2 + 4 with respect to time. In other words, we need to find the rate of change of the rider's velocity.
The first derivative of s(t) with respect to time is v(t) = 9t^2 + 4t.
The second derivative of s(t) with respect to time is a(t) = 18t + 4.
Now that we have the second derivative, we can find the acceleration after two minutes.
a(2) = 18(2) + 4 = 40 miles/min^2
Therefore the rider's acceleration after two minutes is C. 40 miles/min^2
Find the magnitude of the velocity of the of the chain when 5. 58 m of the chain is hanging vertically. Answer in units of m/s
The magnitude of the velocity of the of the chain when 5.58m of the chain is hanging vertically is 10.46m/s.
Given the length of chain (s) = 5.58m
We know that from Newtons second law of motion :
v^2 = u^2 + 2gs where v is the final velocity, u is the initial velocity and g is the acceleration due to gravity.
Here u = 0m/s as the chain is at rest initially.
So, v^2 = 0 + 2 x 9.8 x 5.58
v^2 = 109.368
v = √109.368 = 10.46m/s
Hence the magnitude of the velocity of the of the chain = 10.46m/s.
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how did the ancients know the planets were different from the stars? choose one: a. they saw that the planets move with respect to the stars over the course of many nights. b. the planets have a larger angular size in our sky than the stars. c. they observed moons orbiting around the planets. d. they noticed that the planets orbit the sun, while the stars do not.
The correct answer is option d. The ancients realized that stars did not revolve around the Sun like the planets do, and thus arrived at this conclusion.
One of the ways the ancients knew the planets were different from the stars was by observing their motion in the night sky. Unlike stars, which appear stationary in the sky, the planets were observed to move along a regular path relative to the stars. This movement was known as planetary retrograde and could be observed over the course of many nights.
The ancients also noticed that the planets have a larger angular size in our sky than the stars. This made them more easily distinguishable and allowed them to be distinguished from the stars.
Finally, the ancients noticed that some of the planets had moons orbiting them, which none of the stars did. This was a key factor in distinguishing the planets from the stars.
All in all, the ancients knew the planets were different from the stars by observing their movement in the night sky, noticing the angular sizes, and observing the moons orbiting some of the planets. By understanding these phenomena, the ancients were able to catalog the heavenly bodies and give them each a name.
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A ball of mass 2 kg is attached to a vertical spring. The ball displaces 0. 1 m once it is attached. What is the spring constant?
The spring constant of spring when a ball of mass 2 kg is attached to a vertical spring and is displaced 0. 1m once it is attached is 196.
Given the mass of ball (m) = 2kg
The distance the ball displaced (x) = 0.1m
We know that from Newtons laws of motion F = ma where F is the force acting on an object a is the acceleration.
Here, since the ball is attached to the vertical spring the acceleration acting on the ball is due to gravity. So a = g = 9.8m/s^2.
The restoring force acting on the vertical spring is given as:
Fr = kx where k is spring constant and x is the distance the ball displaced.
As restoring force is balanced by the weight of the ball, Fr = F
Then mg = kx such that k = mg/x
k = 2 x 9.8 / 0.1 = 196
Hence the spring constant of the spring = 196
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Answer:
Explanation:
Since F = ma
And a is 9.8
m = 2
F = 2*9.8
F = 19.6
Hookes Law:
F = kx
So 19.6 = k*0.1
So k = 196
analysis of a bus crashgiven the following theoretical data for the collision, answer the following questions and complete the data table. show work! bus suv m v p m v p total momentum before collision 1600 kg 10 m/s 600 kg 0 after collision 1600 kg 3 m/s 600 kg 1. what is the change in momentum of the bus?
The change in the momentum of the bus is 10600 kg-m/s, if bus of 1600 kg crashes with a SUV of 600 kg.
The mass of the bus, m₁ = 1600 kg
The mass of the SUV, m₂ = 600 kg
Initial velocity of the bus, v₁ = 10 m/s
initial velocity of the SUV, v₂ = 0 (at rest)
Velocity of the bus after collision, v₃ = 3 m/s
Velocity of the SUV after collision, v₄ = 1 m/s
The change in momentum(Δp) is given by,
Δp = (m₁v₁ + m₂v₂) - (m₁v₃ + m₂v₄)
Δp = (1600 × 10 + 600 × 0) - (1600 × 3 + 600 × 1)
Δp = 16000 - 5400
Δp = 10600 kg-m/s
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two identical air-hockey pucks are moving on an air-hockey table with an x-y axis drawn upon it. puck a has a velocity of 5 m/s at an angle of 35 degrees above the x-axis. puck b has a velocity of 6 m/s at an angle of 70 degrees above the x-axis. which puck has a larger momentum in the x-direction?
Puck B has a larger x-direction momentum as it has a greater velocity in the x-direction.
The momentum of a puck is determined by its mass, velocity, and direction. Since both pucks have the same mass, the one with the greater velocity in the x-direction will have the larger x-direction momentum.
Puck A has a velocity of 5 m/s at an angle of 35 degrees above the x-axis. When the velocity is resolved along the x-axis, this gives a velocity of 4.39 m/s in the x-direction.
Puck B has a velocity of 6 m/s at an angle of 70 degrees above the x-axis. When the velocity is resolved along the x-axis, this gives a velocity of 4.83 m/s in the x-direction.
Therefore, Puck B has a larger x-direction momentum as it has a greater velocity in the x-direction.
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beneath the surface of which moon of jupiter is there the strongest evidence for the existence of a subsurface ocean of liquid water?
Beneath the surface of Jupiter's moon of Europa there exists the strongest evidence for the existence of a subsurface ocean of liquid water.
Based on the icy composition of Jupiter's moon named Europa scientists impose the concept that there is the most likely material to make this magnetic signature is a global ocean of salty water. And the result of this magnetic field still is the best evidence for reporting the existence of an ocean on Europa.
Therefore, beneath the surface of Europa's moon of Jupiter, there exists the strongest evidence for the existence of a subsurface ocean of liquid salty water.
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what are the two main metals that make up the outer and inner core?
The core is almost entirely comprised of metal, notably iron and nickel, in contrast to the crust and mantle, which are rich in minerals. The iron-nickel alloys in the core are denoted by the chemical symbols NiFe.
The densest sort of solid matter in space is metal. They are often made of heavier metals that have not undergone chemical fusion. Iron and nickel are the most frequent metallic elements that have not yet been mixed, at least inside our Solar System. As we can see from Earth's structure, metals may be liquid like rocks in the hot cores of huge bodies. Consequently, the iron- and nickel-rich metals dominate the core. In the case of Earth, we know that the metal is melted in the outer core, yet there is high-pressure solid metal within that liquid (inner core).
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