A 50 kg circus worker stands on a merry go round platform. If the worker's acceleration is 2.5 m/s2, what is her centripetal force?

Answers

Answer 1

F = ma

= 50kg × 2.5 m/s²

= 125 N

Answer : 125N

Explanation :

F = Force (N)

m = mass (kg)

a = acceleration (m/s²)


Related Questions

the fall of a body on the earth's surface cannot be a complete free fall why ?​

Answers

Explanation:

because the boy has larger surface area due to which he offers the larger air resistance which decreases the acceleration so, he will fall towards the earth's surface approximately with constant velocity.

Ethics are deliberately learned from the family. Please select the best answer from the choices provided

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Answer:

what are the choices provided?

Explanation:

Answer:

True

Explanation:

On Edg

Yuna is writing an opinion piece about her Schools lunch menu which text structure would best Express her ideas check all that apply​

Answers

Answer:

Cause and effect, problem and solution, order of importance, comparison and contrast.

Explanation:

A pinball bangs against a bumper of a pinball machine with a speed of 0.46 m/s. If the ball has a mass of 0.058 kg, what is the ball's kinetic energy?

Answers

Answer:

either its 12 or 0.402

Explanation:

- During a certain period, the angular position of a rotating object is given by: = − + , where  is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.

Answers

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by [tex]$\theta =2t^2 +10t+5$[/tex], where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, [tex]$\theta =2t^2 +10t+5$[/tex]

∴ Angular speed is   [tex]$\omega = \frac{d \theta}{dt}$[/tex]

                                 ω = 10 + 4t

And angular acceleration is [tex]$\alpha = \frac{d \omega}{dt}$[/tex]

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(0)^2 +10(0)+5$[/tex]

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

b). At time, t = 3.00 seconds :

   Angular displacement is [tex]$\theta =2t^2 +10t+5$[/tex]

                                            [tex]$\theta =2(3)^2 +10(3)+5$[/tex]

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 [tex]$rad/s^2$[/tex]

                                   

                                           

Physical values in the real world have two components: magnitude and

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Answer:

Dimension.

Explanation:

Can u anser 5,6 on the picture

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Answer: Number 6 is Periods

Explanation:

Which of the following is NOT one of the essential components of an exercise program?

Answers

Answer:

i dont know dude but ask someone who is in your grade lol

Explanation:

PLZ HELP MEEEEEEE,;-;

Answers

Answer:

thxs for the points

Explanation:

because just started

If the velocity of an object changed from 30 m/s to 60 m/s over a period of 10 seconds what would the average acceleration be ?

Answers

3 meters per second squared (3 m/s2)

A racecar is driving around a circular track. The car is moving with a speed of 49.7 m/s, and the track has a radius of 114 m. What is the magnitude of the centripetal acceleration of the car?

Answers

Answer:

21.67 m/s²

Explanation:

From the question given above, the following data were obtained:

Velocity (v) = 49.7 m/s

Radius (r) = 114 m

Centripetal acceleration (a) =?

The centripetal acceleration can be obtained by using the following formula:

a = v²/r

a = 49.7² / 114

a = 2470.09 / 114

a = 21.67 m/s²

Therefore, the centripetal acceleration of the car is 21.67 m/s²

Shows a car travelling around a bend in the road. The car is travelling at a constant speed. There is a resultant force acting on the car. This resultant force is called the centripetal force. (i) In which direction, A, B, C or D, does the centripetal force act on the car? Tick ( ) one box. A B C D (1) (ii) State the name of the force that provides the centripetal force.

Answers

Answer:

This question is incomplete

Explanation:

This question is incomplete but the missing figure is in the attachment below.

When an object is travelling around a circular path, there is a force that tends to draw that object towards the center of the circular path and keep the object moving in the curved path, that force is called the centripetal force. From this description, it can be deduced that the direction of the centripetal force that acts on the car (in the attachment below) is D.

The name of the force that provides this centripetal force is frictional force. This is the force that prevents the car from slipping off the road; keeping it moving in the curved path.

how many teeth shows signs of decay?​

Answers

Answer:

what do you mean

Explanation:

A 1500 kg car has an applied forward force of 5000 N and experiences an air resistance of 1250 N. What is the car's acceleration?

Answers

Answer:

[tex]2.33\ m/s^2[/tex]

Explanation:

Net Force

According to the second Newton's law, the net force exerted by an external agent on an object of mass m is:

Fn = m.a

Where a is the acceleration of the object.  The net force is the sum of the individual vector forces applied to the object.

The m=1500 Kg car has two horizontal forces applied: the forward force of 5000 N that causes the movement and the air resistance force of 1250 N that opposes motion.

The net force is Fn = 5000 N - 1500 N = 3500 N

To find the acceleration, we solve the equation for a:

[tex]\displaystyle a=\frac{Fn}{m}[/tex]

[tex]\displaystyle a=\frac{3500}{1500}[/tex]

[tex]\boxed{a = 2.33\ m/s^2}[/tex]

The car's acceleration is [tex]a = 2.33\ m/s^2[/tex]

A molecule of water H2O and a molecule of methane CH4 have close to the same mass Which statement explains why water has much higher boiling point than methane?
A. There is hoydrogen bonding between water molecules?
B. There is ionic bonding between water molecules
C. There is hydrogen bonding between methane molecules
D. There is ionic bonding between methane molecules​

Answers

Answer:

A. There is hydrogen bonding between water molecules

Explanation:

Boiling point is a physical property of matter. It is typically conditioned by the intermolecular forces present between the molecules of a compound.

The nature of the intermolecular forces between the molecules of water is very different from those of methane. Water molecules have hydrogen bonds within their molecules. These intermolecular bonds are very strong compared to the london dispersion forces in methane. Hydrogen bond forms when the hydrogen of one molecule binds with the oxygen of another molecule.

Answer:

A)

Explanation:

There is hydrogen bonding between water molecules

what is the uses of space weather data?​

Answers

Answer:

Space Weather Data

They are used to produce forecasts, such as the monthly sunspot number forecast. Most notably, sunspot numbers represent one of the longest continuous climate records available. The data give scientists the means to make many forecasts and issue space weather advisories and alerts.

Explanation:

help plz The sum of all chemical reactions that take place within an organism is known as ______________. *

Answers

Answer:

Metabolism

Explanation:

metabolism is the sum of all chemical reactions that take place within an organism

Answer:

Metabolism

Explanation:

A train travels with a speed of 115km/hr. How much time does it take to cover a distance of 470km.​

Answers

It would take approximately 4 hours for the train to cover a distance of 470km.

4 hours 5 minutes 13.04 seconds

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