A container holds 3.5 ounces of tablets. How many grams does the container hold?
The container holds 99.223 grams of tablets.
How to convert ounces to grams?One-sixteenth of a pound is represented by the weight measurement called an ounce (oz). A slice of bread and a pencil are two items that weigh about one ounce. One fluid ounce is the same as one-eighth of a cup in terms of volume. A medication cup has a volume of roughly one liquid ounce.
To convert ounces to grams, we can use the conversion factor 1 oz = 28.3495 g.
So, the container holds:
[tex]$3.5\ \text{oz} \times 28.3495\ \frac{\text{g}}{\text{oz}} = 99.223\ \text{g}$[/tex]
Therefore, the container holds 99.223 grams of tablets.
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Which of the following is an irrational number?
Answer:
52/68
Step-by-step explanation:
idr why
Answer: π
Step-by-step explanation:
An irrational number is a number that cannot be shown as a fraction. Based on this, π is an irrational number, since it goes on forever, and can never be written as a perfect fraction.
someone please help me thank u
Answer:
C, E
Step-by-step explanation:
You want to identify the true statements about the end behavior, symmetry, domain, and range of g(x) = -5x² and f(x) = 5x-10.
End behaviorThe function g(x) is of even degree (the exponent is 2), and the function f(x) is of odd degree (the exponent is 1). An even-degree function cannot have the same end behavior as an odd-degree function.
RangeThe range of any odd-degree polynomial function is (-∞, +∞).
Any even-degree polynomial function will have a global maximum or minimum so cannot have the same range. The range of g(x) is (-∞, 0].
DomainThe domain of any polynomial function is "all real numbers." Both f and g have the same domain.
SymmetryAn even-degree function may have an axis of symmetry. An odd-degree function cannot be symmetrical about any line. The functions cannot have the same symmetry.
Points of intersectionTwo polynomial functions may have a number of points of intersection equal to the highest degree. That means a degree-1 and a degree-2 function may have up to 2 points of intersection. These two functions intersect twice, as the graph in the attachment shows.
the system2x-5y=1 -3x+7y=-3 is to be solved by elimination of x
the first equation is multiplied by 3
by which number should the second equation be multiplied
9 Is the value of x in linear equation.
What in mathematics is a linear equation?
An algebraic equation with simply a constant and a first-order (linear) term, such as y=mx+b, where m is the slope and b is the y-intercept, is known as a linear equation. The above is occasionally referred to as a "linear equation with two variables," where y and x are the variables.
2x-5y=1 ..............1
-3x+7y=-3 ..................2
Multiply by 3 in (1) and by 2 in (2)
6x - 15y = 3
-6x + 14y = -6
after substtuting
y = 3
put value of y in 1
2*x - 5*3 = 1
2x = 1 + 15
2x = 16
x = 8
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Can someone please help me if they cannnn :(
Step-by-step explanation:
Your debt ratio is the ratio of the credit limit you have spent.
Your debt ratio is the amount you have spent on the credit card/ the limit
You have spent $9000- $3200 = $5800
Debt ratio = 5800/9000
=58/90 = 29/45
2. Acceptable ratio is less than 43%
Is 29 out of 45 less than 43%
Convert 29/45 to percentage
29/45 /100/1 = 64.44%
You have exceeded acceptable ratio at 64.4%
Answer:
Your debt ratio is the percentage of your credit limit that you have spent.
spent $9000- $3200 = $5800
Debt to income ratio = 5800/9000 = 58/90 = 29/45
2. A satisfactory ratio is less than 43%.
Is 29 percent of 45 less than 43%?
29/45 converted to a percentage 29/45 /100/1 = 64.44%
Step-by-step explanation:
Brainliest pls
x/5+9=11 so I need to get it solved by using 2 Step Equation with Multiplication
Step 1: Isolate x/5 by subtracting 9 from both sides:
x/5 + 9 -9 = 11 -9
x/5 = 2
Step 2: Isolate x by multiplying both sides by 5:
5 · x/5 = 2 · 5
x = 10
The solution is 10.
The graph of an exponential function is shown in the figure below.
The horizontal asymptote is shown as a dashed line.
Find the range and the domain
Answer:
dghcŕhĝt5dfg9yd6grdy6cjbjbknygug4ximpohyvug5h7h6g6
the attendant at a parking lot compared the number of hybrid vehicles to the total number of vehicles in the lot over a weekend. the ratios for the three days were equivalent. complete the table. day hybrids total fri. sat. sun.
The table below shows the number of hybrid vehicles and the total number of vehicles in the parking lot for each day of the weekend:
Day Hybrids Total
Fri x y
Sat x y
Sun x y
Since the ratios for the three days were equivalent, this means that the fraction of hybrid vehicles to total vehicles was the same for each day. In other words:
x/y = x/y = x/y
Therefore, the values of x and y must be the same for each day. This means that the number of hybrid vehicles and the total number of vehicles in the parking lot were the same for each day of the weekend.
In conclusion, the table should be completed with the same values of x and y for each day, as shown below:
Day Hybrids Total
Fri x y
Sat x y
Sun x y
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In September 1998 the population of the country of West Goma in millions was modeled by f(x)=16.9e0.001x. At the same time the population of East Goma in millions was modeled by g(x)=13.8e0.019x. In both formulas x is the year, where x=0 corresponds to September 1998. Assuming these trends continue, estimate the year when the population of West Goma will equal the population of East Goma.A. 2009B. 1987C. 2008D. 11
In September 1998, the population of the country of West Goma in millions was modeled by f(x)=16.9e0.001x. The population of East Goma in millions was modeled by g(x)=13.8e0.019x. In both formulas, x is the year, where x=0 corresponds to September 1998.
To find the year when the population of West Goma will equal the population of East Goma, we will use the following method:
$$f(x)=g(x)$$
$$16.9e^{0.001x} = 13.8e^{0.019x}$$
Taking natural logarithms of both sides we have,
$$\ln(16.9) + 0.001x = \ln(13.8) + 0.019x$$
$$0.018x = \ln(16.9) - \ln(13.8)$$
$$x = \frac{1}{0.018}(\ln(16.9) - \ln(13.8))$$
$x \approx 41.06$, which corresponds to September 2039.
Therefore, the year when the population of West Goma will equal the population of East Goma is September 2039. Option E. 2039 is the correct answer.
Note: The growth rate of West Goma is smaller than that of East Goma, hence it will take a longer time to equalize.
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You borrow $2000 from a friend and promise to pay back $3000 in two years. What simple interest rate will you
pay?
Molly joined an after-school bowling club. The club members go bowling once a week throughout the school year. The bowling scores are recorded for each game so that they can be analyzed at the end of each week. Which of these is a statistical question that can be answered from the data?
Option C requires the examination of the data on bowling scores to find out what Molly's mean score is, and this constitutes a statistical inquiry that can be resolved with the information that has been gathered.
The statistical question that can be answered from the data is: C) What was Molly's average bowling score?
Option A is not a statistical question because it only concerns Molly's personal feeling towards one of her bowling scores.
Option B is a factual question that does not require statistical analysis.
Option D is also a factual question that does not require statistical analysis.
However, option C involves analyzing the bowling scores data to determine Molly's average score. This is a statistical question that can be answered using the collected data.
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Complete question:
Molly joined an after-school bowling club. The club members go bowling once a week throughout the school year. The bowling scores are recorded for each game so that they can be analyzed at the end of each week. Which of these is a statistical question that can be answered from the data?
A) Which bowling score made Molly the proudest?
B) How many times did the bowling club meet?
C) What was Molly's average bowling score?
D) On what day did the bowling club begin?
Which set of measurements would prove that Δ
ABC and Δ
DEF are similar?
Triangle A B C has side A B of length 9, side A C of length 12, and the angle between them 35 degrees. Triangle D E F has no measures given.
A. DE = 15, EF = 20 and m∠D = 35
B. DE = 16, DF = 21 and m∠D = 35
C. DE = 12, DF = 16 and m∠D = 35
D. DE = 18, EF = 24 and m∠D = 70
Therefore , the solution of the given problem of triangle comes out to be DE = 15, EF = 20, and m∠D = 35, so the solution is A.
What exactly is a triangle?A triangle is a polygon because it has two or more additional parts. It has the simple form of a rectangle. A triangle can only be distinguished from a conventional triangle by its three sides, A, B, but not C. So when borders are still not exactly collinear, Euclidean geometry results in a single area as opposed to a cube. Three edges and three angles are the characteristics of triangles.
Here,
We must demonstrate that the respective sides and angles of two triangles are proportional in order to establish their similarity.
We are aware of the lengths of two of the sides and one of the angles in the triangular ABC. The third side's length can be determined using the Law of Cosines:
=> BC² = AB² + AC² - 2ABACcos(35°)
=> 9² + 12² - 2912*cos(35°) = BC²
=> BC ≈ 8.455
The edges of triangle ABC are therefore AB = 9, AC = 12, and BC 8.455.
=> A. DE=15, EF=20, and m=35
The angle measurement is 35 degrees, which corresponds to the angle in the triangular ABC. If the ends are proportionate, we can verify this:
=> DE/AB = 15/9 = 1.67
=> EF/AC = 20/12 ≈ 1.67
This collection of measurements meets the requirements for the triangles to be similar because the ratios are equal.
=> DE = 15, EF = 20, and m∠D = 35, so the solution is A.
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Which ordered pair is the solution to tue system if equations below when using matrix tool 3x+y=17 2x-y=8
The solution of the system of equations is (4, 5).
How to solve the system of equations?Here we have the system of equations:
3x + y = 17
2x - y = 8
We would want tosolve this using matrices, then we need to solve:
[tex]\left[\begin{array}{ccc}3&1\\2&-1\end{array}\right] *\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}17\\8\end{array}\right][/tex]
If we add the first and second equations (or the rows of the first matrix) then we will get:
[tex]\left[\begin{array}{ccc}3&1\\5&0\end{array}\right] *\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}17\\25\end{array}\right][/tex]
Then we have:
5y = 25
y = 25/5
y = 5
And now that we know the value of y we can input it in any of the equations to find x.
3x + y = 17
3x + 5 = 17
3x = 17 - 5 = 12
x = 12/3 = 4
The solution is (4, 5).
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The late fee at the library is based on the number of days a book is late. Carter paid $1.08 for a book that was 9 days late. If his sister Sydney had a fee of $1.92 for a late book, how many days late was the book?
Answer:
16 days late
Step-by-step explanation:
[tex]1.08 \div 9 = .12[/tex]
So the overdue book charge is 12¢ per day. Letting d be the number of days, we have:
.12d = 1.92
d = 16
(x+42)
3x
please help
Given:-
A right angle is given to us.It is made up of two angles (x+42)° and 3x°.To find:-
The value of " x " .Solution:-
Here the sum of the two unknown angles will be 90° as they are the angles which make up 90° . So that;
[tex]\implies x^o + 42^o + 3x^o = 90^o \\[/tex]
[tex]\implies 4x^o = 90^o - 42^o \\[/tex]
[tex]\implies 4x^o = 48^o \\[/tex]
[tex]\implies x =\dfrac{48}{4} \\[/tex]
[tex]\implies \boxed{ x = 12} \\[/tex]
Hence the value of x is 12 .
and we are done!
What does constant time mean? Please hurry! :)
Answer:
When the ratio of the output to the input remains constant at every given point along the function, the rate of change is said to be constant. The slope is another name for the constant rate of change.
Step-by-step explanation:
The constant would be 2.
PLEASE I NEED THE AWNSER IN 2 MIN
Match the situation with the correct ratio. Don't forget that you can write a ratio three ways! Also remember the different ways to find equivalent ratios (simplify, rename, table, graph, tape diagram). Make sure you pay attention to the order!! Only enter CAPITAL letters with no spaces or numbers. (Your answer should look something like this WTYUSR)
*
1. 6:15 has a ratio of 2:5
2. 10:40 has a ratio of 1:4
3. 6:28 has a ratio of 3:14 but it would be 12:56 based on the answer choices
4. 15:25 has a ratio of 3:5 but it would be 15:25 based on the answer choices
The elongation α
of a planet is the angle formed by the planet, earth, and sun. It is known that the distance from the sun to Venus is 0. 723AU
(see Exercise 65 in Section 6. 2 ). At a certain time the elongation of Venus is found to be 39. 4∘.
Find the possible distances from the earth to Venus at that time in Astronomical Units (AU)
The possible distances from the Earth to Venus at the time of an elongation of 39.4 degrees are 0.709 AU and 1.333 AU.
The elongation of a planet is the angle formed when the planet, Earth, and Sun are in a straight line. At a certain time, the elongation of Venus was found to be 39.4 degrees. To find the possible distances from the earth to Venus at that time in Astronomical Units (AU), the Law of Cosines can be used.
The Law of Cosines states that for a triangle with sides a, b, and c and angles A, B, and C, c2 = a2 + b2 - 2abcosC.
In this case, a is the distance from the sun to Venus (0.723 AU), b is the distance from the Earth to Venus, and C is the elongation (39.4 degrees).
Therefore, b2 = 0.7232 + b2 - 2(0.723)(b)cos39.4.
Solving for b, we get b = 0.709 AU and b = 1.333 AU, so the possible distances from the Earth to Venus are 0.709 AU and 1.333 AU.
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anyone know this , i need help again lol
Check the picture below.
Let U= {q, r, s. t, u, v, w, x, y,z}
A= {q, s, u, w, y}
B= {q, s, u, w, y}
C= {v, w, x, y, z}
12. A∩B'
A.) {r, s, t, u, v, w, x, z}
B.) {t, v, x}
C.) {u, w}
D.) {q, s, t, u, v, w, x, y}
The intersection of A and B' is an empty set because there are no elements that are in both A and B'. The correct answer is (option E) the empty set.
What is a set ?
A set is a collection of distinct objects, called elements or members, that are well-defined and unordered.
We can start by finding the complement of set B, which consists of all the elements in U that are not in B:
B' = {r, t, v, x, z}
Then, A ∩ B' consists of all the elements that are in A and also in B':
A ∩ B' = {u, w, y} ∩ {r, t, v, x, z} = { }
Therefore, The intersection of A and B' is an empty set because there are no elements that are in both A and B', the correct answer is (option E) the empty set.
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What are the solutions to the system of equations below?
7x - 5y = 38
2x+10y = -12
Answer:
Step-by-step explanation:
To solve this system of equations, we can use either substitution or elimination method.
Let's use the elimination method to eliminate y.
Multiplying the first equation by 2 and the second equation by 5, we get:
14x - 10y = 76
10x + 50y = -60
Now, we can add the two equations to eliminate y:
(14x - 10y) + (10x + 50y) = 76 - 60
Simplifying the left side and right side, we get:
24x = 16
Dividing both sides by 24, we get:
x = 2/3
Now that we have the value of x, we can substitute it back into either of the original equations to find y.
Let's substitute it into the first equation:
7x - 5y = 38
7(2/3) - 5y = 38
Simplifying and solving for y, we get:
-5y = 38 - 14/3
-5y = 100/3
y = -20/3
Therefore, the solution to the system of equations is (x, y) = (2/3, -20/3).
Find the arc length of the shape
Answer:
The arc length of this quarter-circle is 7π/4.
Incorrect Your answer is incorrect. Find the midpoint M of the line segment joining the points C = (0, 8) and D = (-8, -8). D M-D = 00 X
The midpoint of the line segment joining the points C and D is M = (-4, 0).
How to calculate the midpoint MThe coordinates of the midpoint M of the line segment joining the points C = (0, 8) and D = (-8, -8) can be found using the midpoint formula:
M = ((x1 + x2)/2, (y1 + y2)/2)
So, for C = (0, 8) and D = (-8, -8), we have:
M = ((0 + (-8))/2, (8 + (-8))/2)
M = (-4, 0)
Therefore, the midpoint of the line segment joining the points C and D is M = (-4, 0).
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Patients arrive at a hospital emergency department according to a Poisson distribution with an average of 9 per hour. (a) What is the probability that exactly 7 patients will arrive during a 90 minutes period? (b) What is the probability that at least 30 minutes will pass until the next patient arrives? (c) If one hour has passed and no patient has arrived, what is the probability that the next patient arrives during the following 20 minutes? Problem 4: [9 points] Patients arrive at a hospital emergency department according to a Poisson distribution with an average of 9 per hour. (a) What is the probability that exactly 7 patients will arrive during a 90 minutes period? (b) What is the probability that at least 30 minutes will pass until the next patient arrives? (c) If one hour has passed and no patient has arrived, what is the probability that the next patient arrives during the following 20 minutes?
The probability that the next patient arrives during the following 20 minutes is approximately 0.776.
(a) The probability that exactly 7 patients will arrive during a 90-minute period can be found by using the Poisson distribution formula.Poisson distribution formula:P(X = x) = (e-λ * λx) / x!Where: λ is the average number of events per unit of time or space, x is the number of occurrences, e is the exponential constant equal to 2.71828.x! means x factorial that is x(x − 1)(x − 2)⋯(2)(1).Here, λ = 9/60 = 0.15 (since there are 9 arrivals in one hour, there would be 9/60 arrivals in 1 minute)We are to find the probability of exactly 7 patients arriving in 90 minutes.The time period is 90/60 = 1.5 hours. Hence, λ = 0.15 × 1.5 = 0.225P(X = 7) = (e-λ * λ7) / 7! = (e-0.225 * 0.2257) / 7! = 0.085 ≈ 0.09Therefore, the probability that exactly 7 patients will arrive during a 90 minutes period is approximately 0.09(b) We can calculate the probability of at least 30 minutes passing until the next patient arrives by using the cumulative distribution function (CDF) of the exponential distribution.Exponential distribution formula:f(x) = λe-λxwhere λ is the rate parameter, x is the time period, and e is the exponential constant equal to 2.71828.The mean waiting time between two successive arrivals is 60/9 = 6.67 minutes.Hence, λ = 1/6.67 = 0.15The probability of at least 30 minutes passing until the next patient arrives can be calculated as follows:P(X > 0.5) = 1 - P(X ≤ 0.5) = 1 - (1 - e-λx) = e-λx = e-0.15×0.5 ≈ 0.776Therefore, the probability that at least 30 minutes will pass until the next patient arrives is approximately 0.776.(c) The probability that the next patient arrives during the following 20 minutes can be calculated as follows:P(X > 1) = 1 - P(X ≤ 1) = 1 - (1 - e-λx) = e-λx = e-0.15×1/3 ≈ 0.776Therefore, the probability that the next patient arrives during the following 20 minutes is approximately 0.776.
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algebra 2 assignment three variable HELPPP 13 points
The team scored 2 field goals, 2 safeties, and 4 touchdowns.
Define the term equation?A statement proving the equality of two mathematical expressions is known as an equation. The goal is frequently to ascertain the values of the variables that make the equation true, and it may have one or more variables.
The football team scored 8 times and a total of 38 points.
Let T be the number of touchdowns, F be the number of field goals, and S be the number of safeties.
We know, T = F + S and F + S = 4
Substituting, T = F + S into the equation for total points,
we get, 7T + 3F + 2S = 38
Solving for F and S, we get F = 2 and S = 2.
Therefore, the team scored 2 field goals, 2 safeties, and 4 touchdowns.
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Solve for F and S then get F = 2 and S = 2.
The team scored 4 touchdowns, 2 field goals, and 2 safeties.
How to calculate DF score?The football group scored 8 times, totaling 38 points.
Let,
T is the no.of touchdowns,
F is the no.of field goals, and
S is the no.of safeties.
Touchdown: The ball is in possession of a runner who has moved from the field of play into the end zone and is on, above, or behind the plane of the opposing goal line (extended).
Field Goal: a three-point goal in football obtained by kicking the ball over the crossbar during normal play.
Safeties: NFL defences can score a safety, worth two points, by tackling the offensive player with the ball behind his own goal line or forcing him to run or throw the ball out of bounds behind his own goal line.
We know that,
T = F + S and
F + S = 4
For total points, put T = F + S into the equation.
We get,
7T + 3F + 2S = 38
Solve for F and S,
we get,
F = 2 and S = 2.
As a result, the team tallied 2 field goals, 2 safeties, and 4 touchdowns.
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Please help me desperately need help
Answer:
9) 15
10)22
11)25
Step-by-step explanation:
9)
[tex]area=\frac{bh}{2} \\30=\frac{(2x+1)4}{2} \\\\30=4x+2\\\\28=4x\\x=7\\[/tex]
substitute:
=2x+7
=2(7)+1
=15
10)
[tex]area=\frac{bh}{2} \\114=\frac{12(3x-2)}{2} \\114=18x-12\\126=18x\\7=x[/tex]
substitute:
=3x-2
=3(7)+1
=22
11)
[tex]area=h\frac{b1+b2}{2} \\\\69=\frac{4x-2}{2} \\\\69=\frac{24x-12}{2} \\\\69=12x-6\\75=12x\\x=6.25\\\\=4x\\=4(6.25)\\=25[/tex]
Offering brainliest to whoever gives explanation
Answer:
To find the volume of a rectangular prism, we need to know the length, width, and height of the prism. However, the height is not given in the problem, so we cannot calculate the volume.
We can use the surface area and given dimensions to set up an equation to solve for the height. The surface area of a rectangular prism is given by:
SA = 2lw + 2lh + 2wh
where l, w, and h are the length, width, and height of the prism, respectively. We are given that the surface area is 62 square feet, and the width and length are 2 and 5 feet, respectively. Substituting these values into the surface area equation, we get:
62 = 2(2)(5) + 2(5)h + 2(2)h
62 = 20 + 14h
42 = 14h
h = 3
Now that we have found the height of the rectangular prism, we can calculate its volume. The volume of a rectangular prism is given by:
V = lwh
Substituting the given dimensions and calculated height, we get:
V = (5)(2)(3)
V = 30
Therefore, the volume of the rectangular prism is 30 cubic feet.
Step-by-step explanation:
Answer:
[tex]30ft^3[/tex]
Step-by-step explanation:
Surface area of a rectangular prism is A = 2(wl +hl +hw)
Volume, height, and Width is given now we can solve for l, v
[tex]A = 2(wl + hl + hw)\\62ft^2 = 2(2ft * l + 5ft * l + 5ft * 2ft)\\62ft^2 = 2(2lft + 5lft + 10ft^2)\\62ft^2 = 2(7lft + 10ft^2)\\62ft^2 = 14lft + 20ft^2\\14lft = 42ft^2\\l = 3ft[/tex]
Now that we have the length, we can solve for the volume
Volume of a rectangular prism = Length x Width x Height
[tex]V = 3ft * 2ft * 5ft\\ = 30ft^3[/tex]
Hope this helps!
Brainliest is much appreciated!
Find the expected number of flips of a coin, which comes up
heads with probability 0.5,
that are necessary to obtain either h, h, h or t, t, t.
The expected value of X is given byE(X) = 1/p= 1/(1/4) = 4
To obtain either h, h, h or t, t, t, let's consider the sequence h, h, h, t, t, t. The probability of obtaining h, h, h or t, t, t is (1/2)^3 + (1/2)^3 = 1/4. Also, the probability of the first head or tail occurring on the nth flip is (1/2)^n-1. If X denotes the number of flips of a coin required to get h, h, h or t, t, t, then X has a geometric distribution with parameter p = 1/4. Hence, the expected value of X is given byE(X) = 1/p= 1/(1/4) = 4The expected number of flips of a coin, which comes up heads with probability 0.5, that are necessary to obtain either h, h, h or t, t, t is 4.
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major axis 12 units long and parallel to the y-axis, minor axis 8 units long, center at (-2,5)
center is located at (-2,5) is:(x+2)^2 / 36 + (y-5)^2 / 64 = 1
The dimensions of the given ellipse are major axis 12 units long and parallel to the y-axis, minor axis 8 units long, and the center is located at (-2,5).Let us find the standard form equation of the ellipse. The standard form equation of an ellipse is given by:(x-h)^2 / a^2 + (y-k)^2 / b^2 = 1Where (h, k) is the center of the ellipse, a is the distance from the center to either the x-axis or the y-axis, and b is the distance from the center to the other axis. Therefore, for the given ellipse, the equation of the ellipse in standard form is:(x+2)^2 / 36 + (y-5)^2 / 64 = 1Thus, the standard form equation of the ellipse whose major axis is 12 units long and parallel to the y-axis, minor axis 8 units long, and center is located at (-2,5) is:(x+2)^2 / 36 + (y-5)^2 / 64 = 1.
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Write a vertical motion model in the form ()=−++h of , open t close , equals negative 16 , t squared , plus , v sub 0 , t plus , h sub 0 for each situation presented. For each situation, determine how long, in seconds, it takes the thrown object to reach maximum height.
Initial velocity: 32 ft/s; initial height: 20 ft
Answer:
h(t)=−16t²+v
0 t+h 0
for each situation presented. For each situation, determine how long, in seconds, it takes the thrown object to reach maximum height. Initial velocity: 32 ft/s; initial height: 20 ft
Step-by-step explanation: