The concentration of the 25ml of original HNO₃ solution that was neutralized with 31.4 mL of 0.250 M Ba(OH)₂ is 0.628 M HNO3
The neutralization reaction involved with HNO₃ and Ba(OH)2 is
Ba(OH)₂ + 2HNO₃---> Ba(NO₃) + 2H₂O.
From the balanced equation of the reaction, we can say that to neutralize barium hydroxide (Ba(OH)₂) we would require 2 moles of Nitric acid (HNO₃)
By multiplying concentration of barium hydroxide by volume its volume, and then multiplying by 2 as twice is required we would get the moles of HNO3 that is equivalent to 2 moles based on the values
Moles of HNO₃ = 2 (0.0314 * 0.250) = 0.0157 moles
Concentration of the original HNO₃ solution = 0.0157 moles / 0.025 L = 0.628 M HNO₃
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A patient turns in a sample of urine for specific gravity test. The lab results record a value of1.024. What is the density of this patient's urine?
Specific gravity is the same concept for relative density. This measure indicates the density with respect to the density of water at standard temperature. The formula is:
[tex]\text{Specific gravity = }\frac{density\text{ of substance}}{density\text{ of water}},[/tex]If we are comparing pure water, the density of this would be 1.00 g/mL, so clearing the formula and replacing, we're going to have:
[tex]\begin{gathered} \text{density of substance (urine) = specific gravity }\cdot\text{ density of water,} \\ \text{density of urine = 1.024 }\cdot\text{ 1.00}\frac{g}{mL}, \\ \text{density of urine = 1.024 }\frac{g}{mL}. \end{gathered}[/tex]The density of the patient's urine is 1.024 g/mL if the specific gravity is 1.024.
Explain what you are observing in the containers. When referencing charts(Graphs) indicate which parameters would be the control, the dependent and or the independent variable. how does this experiment relate to our planet. What is being released from the baking soda.
The gas bubbles you see exists made of carbon dioxide, which exists released when baking soda and vinegar react to balance each other out.
What does baking soda do in experiments?Alkaline baking soda combines with acids like vinegar to produce water and carbon dioxide (a gas). The resulting fizz is fantastic entertainment for kids to watch, especially if you combine it with dish soap to create even more bubbles or if you add some food coloring, ice, or a theme.
The gas bubbles you see are made of carbon dioxide, which exists released when baking soda and vinegar react to balance each other out (vinegar exists an acid and baking soda is an alkali).
The project's objective is to demonstrate the potency of the gas created when vinegar and baking soda are combined. The goal is for the balloon to be blown up by the gas created.
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How many moles are in 95 grams of aluminum (AI)?
ANSWER
3.52 moles are in 95 grams of aluminum
STEP-BY-STEP EXPLANATION:
As you can see from the question provided, you are asked to find the moles of aluminum
Given data
Mass of aluminum = 95 grams
To find the moles of aluminum, we will need to apply the below formula
[tex]\text{ Mole }=\text{ }\frac{\text{ reacting mass}}{\text{molar mass}}[/tex]From the question provided, you can see that the molar mass of aluminum was given
From your periodic table, you will see that the molar mass of aluminum is 27 g/mol
Molar mass of aluminum = 27g/mol
The next thing is to substitute the data given in the above formula
[tex]\begin{gathered} \text{ Mole = }\frac{95}{27} \\ \text{mole = }3.52\text{ g/mol} \end{gathered}[/tex]Therefore, we have 3.52 moles are in 95 grams of aluminum
9. Which of the following shows whose model?a. Bohrb. Daltonc. Rutherfordd. Thomson
Answer
d. Thomson
Explanation
The given model shown above is Thomson's model of an atom.
In 1898, J. J. Thomson proposed that an atom is shaped like a sphere with a radius of approximately 10⁻¹⁰m, where the positive charge is uniformly distributed as shown in the model given. The electrons are embedded in this sphere so as to give the most stable electrostatic arrangement.
Thus, Thomson's model of an atom is also referred to as the watermelon model, the plum pudding model or the raisin pudding model.
An important aspect of Thomson's model of an atom is that it assumes that the mass of the atom is uniformly distributed over the atom. The model was successful in explaining the overall neutrality of the atom.
What is the mass in grams of aluminum metal (26.98 g/mol) that reacts to form 2.80 g of iron (55.85 g/mol)?
3 FeO (l) + 2 Al (l) → 3 Fe (l) + 1 Al2O3
Starting with 0.450 g of potassium chlorate (molar mass 122.55 g/mol), a student determined that the reaction released 0.156 g of oxygen gas. Calculate the percent yield for O2.
2 KCIO3 (s) → 2KCl (s) + 3 O2
The mass of aluminum metal that reacts to form 2.80 g of iron according to the reaction would be 0.9017 g.
The percent yield of the reaction if 0.450 g of potassium chlorate reacts according to the equation would be 87.05%.
Yield of reactionsConsider the first reaction:
[tex]3 FeO (l) + 2 Al (l) -- > 3 Fe (l) + 1 Al_2O_3[/tex]
The mole ratio of Al and Fe is 2:3.
2.80 g of Fe = 2.8/55.85
= 0.0501 moles
Equivalent mole of Al = 2/3 x 0.0501
= 0.0334 moles
Mass of 0.0334 moles Al = 0.0334 x 26.98
= 0.9017 g
Consider the second reaction:
[tex]2 KCIO_3 (s) -- > 2KCl (s) + 3 O_2[/tex]
The mole ratio of potassium chlorate to oxygen is 2:3.
Mole of 0.450 g potassium chlorate = 0.450/122.55
= 0.0037 moles
Equivalent moles of oxygen = 3/2 x 0.0037
= 0.0056 moles
Mass of 0.0056 moles oxygen = 0.0056 x 32
= 0.1792 g
Percent yield = 0.156/0.1792 x 100
= 87.05%
In other words, the mass of aluminum metal that reacts in the first reaction would be 0.9017 g while the percent yield of the second reaction is 87.05%.
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The soft drinks sold at county fairs are often dispensed from large pressurized containers that contain carbon dioxide gas above the liquid at a partial pressure of about 4 atm, compared to carbon dioxide’s normal partial pressure of 0.00035 atm in the air at sea level. a. Describe the reversible change that takes place inside one of these soft drink containers when the pressure of CO2 above the liquid is first brought from 0.00035 atm to 4 atm. Explain why this system comes to a dynamic equilibrium in which there is no net change in the amount of gas above the liquid or the amount of gas dissolved in the liquid.
CO2 particles move faster through the solution. Gas solubility increases as liquid CO2 partial pressure rises.
Dynamic equilibrium occurs when the solution rate matches the escape rate, and neither the gas above the liquid nor the gas dissolved in it changes.
This is further explained below.
What is dynamic equilibrium?Generally, The idea of partial pressure is connected to the changes that occur in soft drink containers. Since there are no gas particles in the liquid when we add CO2 at a typical partial pressure of 0.00035, the CO2 gas begins to move into the solution at a faster pace than it can leave.
But when the concentration of CO2 gas rises, it begins to diffuse into the liquid, and eventually, a dynamic equilibrium is attained when the rate of the solution equals the rate of escape.
However, as we continue to add CO2 to this dynamic equilibrium, its partial pressure will rise until it reaches 4 atm, and this rise in partial pressure accelerates the rate of solution. Thus, raising the partial pressure of CO2 causes this reversible transformation to occur.
When the rate of the solution equals the rate of escape, this is known as dynamic equilibrium, and neither the quantity of gas above the liquid nor the amount of gas dissolved in it changes in any significant way.
Now here comes what role is played by partial pressure. When the rate of solution and the rate of escape reach a dynamic equilibrium and we begin to introduce additional CO2 gas to this dynamic equilibrium stage.
The CO2 gas particle's partial pressure and concentration both rise. Because of the increased rate of collision between the surface of CO2 gas and the surface of the liquid particles due to the increasing concentration, the rate of solution also rises. The pace of solution has now surpassed the rate of escape.
As a result, the rate at which CO2 gas particles travel through the solution increases. This is how a rise in CO2 partial pressure over liquid causes a rise in gas solubility.
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Determine which of the following electron configurations are not valid:
1.) 1s²2s²2p 3s 3p 4s²4d¹04p5
2.) 1s²2s²2p 3s³3d5
3.) [Ra] 7s²5f8
4.) [Kr] 5s24d105p5
The electron configurations that are not valid among the options are 1s²2s²2p 3s 3p 4s²4d¹04p5 and 1s²2s²2p 3s³3d5. Options 1 and 2.
Electron configurationsThe electron configuration of atoms using the various orbital levels follows the order: 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p, 6s, 4f, 5d, 6p, 7s, 5f, 6d, 7p.
Also, according to Afbau principle, orbitals with low energy levels are filled with electrons before orbitals with higher energy levels.
Using the above, 1s²2s²2p 3s 3p 4s²4d¹04p5 is incorrect for some reasons:
4d, a higher energy level orbital, comes before 4p. 3s and 3p, lower energy level orbitals have no electrons in them while higher energy level orbitals have electrons in them.1s²2s²2p 3s³3d5 is incorrect because:
a lower energy level orbital, 2p is not filled before a higher energy orbital, 3s.3p and 4s orbitals should come before 3d orbital.The remaining electron configurations are correct with correctly placed electrons in the various orbitals.
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Add 43.8lbs and 56.8923lbs. What is the answer in the correct significant figures?
The answer in correct significant figures of the addition of the two numbers mentioned is 100.70.
What are significant figures?Significant figures are used for establishment of a number which is presented in the form of digits. These digits give a meaningful representation to the numbers.
The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:
1)All non-zero digits are significant .
2)All zeroes which occur between non-zero digits are significant.
3)All zeroes to the left and right of a non-zero digit are not significant.
4) All zeroes on right of decimal are significant if a non-zero number follows them.
5)All zeroes on right side of non-zero digit are significant.
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i need help with chemistry
Answer:
2.04×10^25
Explanation:
multiply with 10^9
Experiment 2: Copper(II) carbonate hydroxide produces one mole of water (=18.015 g/mol) for every two moles of solid product (=79.545 g/mol) produced. If 3.597 g of solid product were produced during the reaction, how many grams of water were realeased as water vapor?
Calculate the shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine if the bond energy, or bond dissociation energy, is 243 kJ/mol .
The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine is 493 nanometer.
The formula to calculate Energy is given as follows :
E = BE / Na
E = energy
BE = bond energy = 243 KJ / mol
Na = Avogadro number = 6.02 × 10²³
substituting the values in the formula:
E = 243 × 10³ / 6.02 × 10²³
E = 4.03 × 10⁻¹⁹ J
By using Einstein equation for photon , we can calculate the shortest wavelength :
E = (h c) / λ
E = energy
h = Planck constant = 6.626 × 10⁻³⁴ J.s
c = speed of light = 3 × 10⁸ m/s
λ = wavelength
therefore,
λ = (hc )/ E
λ =( 6.626 × 10⁻³⁴ J.s × 3 × 10⁸ m/s ) / 4.03 × 10⁻¹⁹ J
λ = 4.93 × 10⁻⁷ m
λ = 493 × 10 ⁻⁹ m
1 nm = 1 × 10 ⁻⁹ m
Shortest wavelength = 493 nanometer.
Thus, The shortest wavelength of light capable of dissociating the Cl–Cl bond in one molecule of chlorine if the bond energy, or bond dissociation energy, is 243 kJ/mol is 493 nanometer.
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The mass number of an atom containing 37 protons, 50 neutrons,and 37 electrons is:A)13B)50C)37D)87
The question requires us to determine the mass number of an atom with 37 protons, 50 neutrons and 37 electrons.
The atomic number of an atom is determined by its number of protons, while the mass number of an atom is defined as the sum of number of protons and number of neutrons.
Therefore, we can calculate for the atom given by the question:
[tex]\begin{gathered} \text{mass number = number of protons + number of neutrons} \\ \text{mass number = 37 + 50} \\ \text{mass number = 87} \end{gathered}[/tex]Therefore, the mass number of this atom is 87 and the best option to answer the question is letter D.
Samantha is testing a hair sample that is four centimeters long and lacks a root or follicular tissue. What is likely to be TRUE about this sample?
A.
There will be mitochondrial DNA present.
B.
There will be nuclear DNA present.
C.
There will be several medullas present.
D.
There will be no form of DNA evidence present.
The likely to be TRUE about a hair sample that is four centimeters long and lacks a root or follicular tissue is there will be mitochondrial DNA present (Option A).
What is mitochondrial DNA?Mitochondrial DNA is a type of genetic material that is independent of nuclear DNA and is contained in an organelle known as mitochondrion. These organelles (mitochondria) are the energy factors of the cell because they generate ATP through the process of cellular respiration.
Generally, the cells that contain cell nuclei also contain different organelles such as mitochondria, and this observation also includes the hair cell follicles that are differentiated specialized types of cells present in the hair.
Therefore, with this data, we can see that mitochondrial DNA is different from nuclear DNA and it is found in tissues that are subject to differentiation such as follicular tissues which need energy to differentiate.
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How many moles of ammonium nitrate (NH4NO3) are present in 0.085 L of a 0.23 M ammonium nitrate (NH4NO3) solution?
Answer:
No. of moles [tex]\approx[/tex] 0.020
Explanation:
To calculate the number of moles of a substance in a solution given its concentration and volume, we use the following formula:
[tex]\boxed{\mathrm{No. \ of \ moles = Concentration \times Volume}}[/tex],
where concentration is in mol/dm³ (or M) and volume is in L.
In the question, we are told that the volume of the solution is 0.085 L and that its concentration is 0.23 M. Substituting these values into the formula above, we get:
No. of moles = 0.23 × 0.085
= 0.01955
[tex]\approx[/tex] 0.020 mol (3 s.f.)
Therefore, there are 0.020 moles of NH₄NO₃ in the solution.
Could anyone please help me balance this equation?
K⁺(aq) + 2Al(s) +H⁺(aq) +SO₄²-(aq)+H2O(l)⭢KAl(SO4)2·12H2O(s)+3H2(g)
To see the total number of atoms we need to multiply coefficient which is written in foot of the molecule or element to the number that is written on the foot of that element
The balanced reaction is
2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)
What is Balanced equation?
Balanced equation is the one in which the total number of atoms of a species on reactant side is equal to the total number of atoms on product side
The unbalanced equation is
Al(s) + KOH(aq) + H₂SO₄(aq)→ KAl(SO₄)₂·12H₂O(s)
sulfur atoms on reactant side is 1 while on the product side it is 2 so multiply H₂SO₄ by 2
Al(s) + KOH(aq) + 2H₂SO₄(aq) → KAl(SO₄)₂·12H₂O(s)
Now add H₂O(l) and H₂(g) to balance oxygen and hydrogen. The balanced equation becomes
2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)
Thus the balanced equation is
2 Al(s) + 2 KOH(aq) + 4 H₂SO₄(aq) + 22 H₂O(l) → 2 KAl(SO₄)₂·12H₂O(s) + 3 H₂(g)
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CanvasX &Question 16Consider the reaction: 4Na(s) + O2(8) → 2Na2O(s)
ANSWER
The mass of Na2O in grams is 123.49 grams
EXPLANATION:
Given information
The mass of sodium is 91 grams
The mass of oxygen is 34.0 grams
To find the amount of Na2O produced, follow the steps below
Step 1: Write the balanced equation of the reaction
[tex]\text{ 4Na}_{(s)}\text{ + O}_{2(g)}\rightarrow\text{ 2Na}_2O_{(S)}[/tex]Step 2: Find the number of moles of sodium and oxygen using the formula below
[tex]\text{ Mole = }\frac{\text{ mass}}{molar\text{ mass}}[/tex]Recall, that the molar mass of Na is 22.989 g/mol, and the molar mass of oxygen atom is 32 g/mol
For Na
[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ Mole = }\frac{91.6}{22.989} \\ \text{ Mole = 3.985 moles} \end{gathered}[/tex]For O2
[tex]\begin{gathered} \text{ Mole = }\frac{mass}{molar\text{ mass}} \\ \text{ } \\ \text{ Mole = }\frac{34}{32} \\ \text{ Mole = 1.0625 moles} \end{gathered}[/tex]Step 3: Find the limiting reactant of the reaction
The limiting reactant is the reactant that has the least number of moles after dividing it by the coefficient of the reactant
From the reaction above, you will see that 4 moles of sodium react with one mole of oxygen to give 2 moles of sodium oxide.
For Na
[tex]\begin{gathered} \text{ Na = }\frac{\text{ number of moles}}{\text{ coefficient}} \\ \text{ Na = }\frac{3.985}{4} \\ \text{ Na = 0.99625 mole/wt} \\ \\ \text{ For O}_2 \\ \text{ O}_2\text{ = }\frac{1.0625}{1} \\ \text{ O}_2\text{ = 1.0625 moles/wt} \end{gathered}[/tex]From the above calculations, you will see that Na has the least number of moles, hence, Na is the limiting reactant
Step 4: Find the number of moles of Na2O
The Na2O can be determined using a stoichiometric ratio
Let x represents the number of moles
[tex]\begin{gathered} \text{ 4 moles of Na }\rightarrow\text{ 2 moles of Na}_2O \\ 3.985\text{ moles of Na }\rightarrow\text{ x moles of Na}_2O \\ \text{ cross multiply} \\ \text{ 4 moles of Na }\times\text{ x moles of Na}_2O\text{ = 2 moles of Na}_2O\times3.985\text{ moles of Na} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\cancel{moles\text{ of Na}_2}O\times3.985\cancel{moles\text{ of Na}}}{4\cancel{moles\text{ of Na}}} \\ \text{ x moles of Na}_2O\text{ = }\frac{2\times\text{ 3.985}}{4} \\ \text{ X moles of Na}_2O\text{ = 1.9925 moles} \end{gathered}[/tex]Hence, the number of moles of Na2O is 1.9925 moles
Step 5: Find the mass of Na2O
[tex]\begin{gathered} \text{ Mole = }\frac{\text{ mass}}{\text{ molar mass}} \\ \end{gathered}[/tex]Recall, that the molar mass of Na2O is 61.9789 g/mol
[tex]\begin{gathered} \text{ 1.9925 = }\frac{\text{ mass}}{61.978} \\ \text{ Cross multiply} \\ \text{ Mass = 1.9925}\times61.978 \\ \text{ Mass = 123.49 grams} \end{gathered}[/tex]Hence, the mass of Na2O in grams is 123.49 grams
What type of blood vessels can you find in most mammals?
A) tendons, ligaments, and capillaries
B) nerves and veins
C) aorta and ventricle
D) arteries, capillaries, veins
Answer:
Explanation:
the answer is D
Answer:
D
Explanation:
capillaries veins and arteries
Calculate the energy and wavelength of a photon with a frequency of 11.23 * 10^13 Hz
The wavelength and the energy would be2.67 × 10⁻⁴ meters and 7.02998 × 10 ⁻²⁰ Joules and respectively if the photon has a frequency of 11.23 × 10¹³ Hz.
What is Wavelength?It can be understood in terms of the distance between any two similar successive points across any wave.
C = λν
As given in the problem we have to calculate the energy and the wavelength of a photon with a frequency of 11.23 × 10¹³ Hz.
The wavelength of the photon = 3 × 10 ⁸ / 11.23 × 10¹³ Hz.
= 2.67 × 10⁻⁴ meter
The energy of the photon of light = h × ν
= 6.26 × 10⁻³⁴ × 11.23 × 10¹³ Hz.
= 7.02998 × 10 ⁻²⁰ Joules
Thus, the wavelength and the energy would be 2.67 × 10⁻⁴ meter and 7.02998 × 10 ⁻²⁰ Joules and respectively if the photon has a frequency of 1.1 × 10¹⁷ Hz.
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39.When the polyatomic ion (SO4)-2 combines with the iron (III) ion, Fe+3, the formula for the compound is...Select one:a. FeSO4b. Fe2SO4c. Fe2(SO4)3d. Fe3(SO4)2
Answer
c. Fe2(SO4)3
Explanation
The polyatomic ion (SO₄)⁻² has a net charge of -2 and iron (III) ion, Fe⁺³ has an oxidation number of +3. For a compound to be formed between them, two of Fe⁺³ will need three of the polyatomic ion, (SO₄)⁻² and the formula of the compound will be Fe2(SO4)3.
Which of the following formulas represent valid ionic compounds that can be made from these six elements: Al, Be, F, Li, N, and S? Select all that apply. A. AlN B. BeS C. AlLi D. LiF
The compound AlN, BeS, and LiF represents valid ionic compounds.
Ionic bonding:-
When all of the electrons are successfully transferred from one element to another, this sort of bonding is created. One element in this bonding is always a metal, whereas the other is invariably a non-metal.Thus, Al, Be, Li are metals and F, N, S are nonmetals which can form ionic bonding with each other. So, AlLi (Option C) rules out.Considering option A: - AlNThe valency of aluminum is 3 and nitrogen is of 3. The valency of the cations and the anions must be switched and subscripted in order to identify the ionic compound. Thus,Al N
3 3
Simplest ratio : - 1 1
AlN is an ionic compound and thus it is a valid ionic compound.The valency of beryllium is 2 and sulfur of 2. The valency of the cations and the anions are switched and put in subscripts to create the ionic compound. Thus,Be S
2 2
Simplest ratio : - 1 1
The ionic compound created is (b) BeS, making it a legitimate ionic compound.Fluorine and lithium both have valencies of 1. The valency of the cations and the anions are switched and put in subscripts to determine the ionic compound. Thus,Li F
1 1
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8.In the equation 2 NH3 + H2O + CO2 ---> (NH4)2CO3, which of the following is a product?Select one:a. CO2 b. H2O c. NH3 d. (NH4)2CO3
According to the explanation given in a previous session, the compounds that comes after the arrow are classified as product, and the compounds that comes before are classified as reactant, therefore in this reaction, (NH4)2CO3 is the product of the reaction, letter D
- 47 Celsius to kelvin
Answer
226 K
Explanation
To change from C to K, you add 273
Therefore -47 C + 273 = 226 K
T
Sn +Cl————SnCl4what is the limiting reactant when 15.7 g of tin reacts with 17.4 of chlorine? what mass of tin chloride can be formed?
Cl is the limiting reactant and the mass of tin chloride that can be formed is 31.9g.
- First, we need to balance the equation:
[tex]Sn\text{ + 4 Cl }\rightarrow SnCl_4[/tex]- Second, we need to know the molar weight of the compounds:
Sn: 118.7 g/mol
Cl: 35.5 g/mol
SnCl4: 260.7 g/mol
- Third, we need to know how much Sn can react with Cl according to the balanced equation:
[tex]\frac{15.7g\text{ . 142g}}{118.7g}=\text{ 18.8 g}[/tex]If 118.7g of Sn needs 142g of Cl to react according to the balanced equation, we found that the 15.7g of Sn will need 18.8g of Cl to complete the reaction.
As we have 17.4g of Cl available, we can see that we are going to need more Cl and therefore Cl is the limiting reactant.
- Now, to find the mass of tin chloride that can be formed, we use the limiting reactant amount for the calculation:
[tex]\frac{17.4g\text{ . 260.7g}}{142g}=31.9\text{ g}[/tex]According to the balanced equation we need 142g of Cl to produce 260.7g of tin chloride, so with 17.4g of chlorine we will obtain 260.7g of SnCl4.
So, the mass of tin chloride that can be formed is 31.9g.
Be sure to discuss the role of the force of gravity and/or fusion force in your explanation for why new stars form from a hydrogen and dust cloud. Don’t forget to include evidence to support your claim
The role of the force of gravity and/or fusion force in the formation of new stars form from a hydrogen and dust cloud is by providing the required force and conditions needed for the reaction.
What is a Star?This is referred to as an astronomical object which has a luminous spheroid of plasma which is held together by its gravity.
In the formation of stars, the fusion force helps in the initiation of the nucleosynthesis reaction which occurs. The outward pressure from heating of the gas must balance gravity for a new star to be formed thereby making it the correct choice.
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2. Oxygen gas is collected at a pressure of 123 kPa in a container which has a volumeof 10.0 L. What temperature must be maintained on 0.654 moles of this gas in order tomaintain this pressure? Express the temperature in Kelvin.
Answer
T = 226.21 K
Explanation
Given:
Pressure = 123 kPa
Volume = 10.0 L
number of moles = 0.654 moles
We know R = 8.314 L kPa/mol k.
Required: Temperature
Solution:
Pv = nRT
T = PV/nR
T = (123 kPa x 10.0 L)/(0.654 mol x 8.314 L kPa/mol k)
T = 226.21 K
Using the Mole: Empirical Formulas, Molecular Formulas, % Composition5. Potassium persulfate was used in photography to remove the last traces of hypo from photographic papers and plates, A 0,8162 g sample was found to contain 0,2361 g of potassium, 0.1936 g of sulfur, and the rest was oxygen. The formula weight of this compound was measured to be 270. What are the empirical and molecular formulas of this compound?
Answer:
Molecular formula = KSO4.
Empirical formula = K2S2O4.
Explanation:
What is given?
Mass of K (potassium) = 0.2361 g.
Mass of S (sulfur) = 0.1936 g.
Mass of O (oxygen) = 0.8162 g - 0.2361 g - 0.1936 g = 0.3865 g.
Molar mass of K = 39.1 g/mol.
Molar mass of S = 32 g/mol.
Molar mass of O = 16 g/mol.
Weight of compound = 270 g/mol.
Step-by-step solution:
Remember that empirical formulas show the simplest whole-number ratio of atoms in a compound, and molecular formulas show the number of each type of atom in a molecule. So first, let's see what would be the molecular formula:
Let's find the number of moles of each element using its molar mass:
[tex]\begin{gathered} 0.2361\text{ g K}\cdot\frac{1\text{ mol K}}{39.1\text{ g K}}=0.006038\text{ moles K,} \\ 0.1936\text{ g S}\cdot\frac{1\text{ mol S}}{32\text{g S}}=0.006050\text{ moles S,} \\ 0.3865\text{ g O}\cdot\frac{1\text{ mol O}}{16\text{ g O}}=0.02416\text{ moles O.} \end{gathered}[/tex]The next step is to divide each number of moles obtained by the least number of moles, in this case, the least number is 0.006038:
[tex]\begin{gathered} 0.006038\text{ moles K/0.006038=1 mol K,} \\ 0.006050\text{ moles S/0.006038 =}1.001\text{ moles S}\approx1\text{ mol S,} \\ 0.02416\text{ moles O/0.006038=4.001 moles O}\approx\text{4 moles O.} \end{gathered}[/tex]Our molecular formula would contain 1 mol of K, 1 mol of S, and 4 moles of O, so it would be KSO4.
But remember that we need to find the empirical formula too, based on the molecular weight. In the statement, they're telling us that the molecular weight is 270 g/mol, but the molecular weight of KSO4 is 135 g/mol (you can calculate it using the given molar masses and by doing an algebraic sum). So, to obtain the empirical formula with 270 g/mol as molecular weight, we have to multiply by two each number of moles of the compound (135 g/mol * 2 = 270 g/mol):
[tex]\begin{gathered} 1\text{ mol K}\cdot2=2\text{ moles K,} \\ 1\text{ mol S}\cdot2=2\text{ moles S,} \\ 4\text{ moles O }\cdot2=8\text{ moles O.} \end{gathered}[/tex]So, you can realize that K2S2O4 would be the empirical formula because its molecular weight would be 270 g/mol.
Molecular formula = KSO4.
Empirical formula = K2S2O4.
What could be the third quantum number for one of the electrons in the 4penergy sublevel of bromine?A. m = -1B. m = 5C. m = +D. m = 4
Assuming the third quantum number is the question is the magnetic quantum number, it is limited by the angular momentum quantum number. This is inditaced in the quastion: since the orbital is 4p, the "p" indicates that the angular momentum quantum number is 1.
The magnetic quantum number can only be -1, 0 or +1.
The only alternative with one os these is alternative A.
Chapter 6 Question 34 - AlgorithmicThe element that has a valence configuration of 3s2 3p6 is ________.- Choices:ArRnKrNeXe
We have to remember the rules to determine to which period and which group belongs an element, depending on its electronic configuration:
We always have to see the last level of energy, in this case is 3 (the highest number in the electronic configuration). It determines the period (the horizontal lines)
Now, we have to see the last letter which is with the 3, in this case the letter is p. It determines that the element is part of the A groups of the periodic table, also called the representative groups. In case of ending in d, it means that the element belongs to the transition metals. And trhe last possibility is ending in f, it means that the element belongs to the lanthanides and actinides.
The last thing, is to add up the valence electrons. Those are the ones in the last energy level, that as we mentioned before, it is 3 in this case. So, we have to add up, the exponents of the different letters that are in the last energy level. In this particular case, are the 2 and the 6, which is equal to 8.
So, we have to search in the periodic table, the element which is in the period 3, group VIII A. If we go, we will find it is the argon (Ar)
4. You have 500 grams of MgF2. If a 3 M solution is desired, how many Liters must be present?
They give us the grams of solute and the molarity of the solution. To find the liters we must take into account the definition of molarity. Molarity is defined as:
[tex]Molarity=\frac{MolesSolute}{Lsolution}[/tex]The definition of molarity asks us for the moles of solute, so we must pass the grams that give us to moles. For them, we divide the 500 grams by the molar mass of MgF2. The molar mass of MgF2 is 62.3018g/mol.
The moles of MgF2 will be:
[tex]\begin{gathered} molMgF_2=GivengMgF_2\times\frac{1molMgF_2}{MolarMass,gMgF_2} \\ molMgF_2=500gMgF_2\times\frac{1molMgF_2}{62.3018gMgF_2}=8.03molMgF_2 \end{gathered}[/tex]Now, we find the liters of solution:
[tex]\begin{gathered} Lsolution=\frac{MolesSolute}{Molarity} \\ Lsolution=\frac{8.03mol}{3M}=\frac{8.03mol}{3mol/L} \\ Lsolution=3L \end{gathered}[/tex]Answer: It must be present 3L of solution
explain third law of thermodynamics in brief
The third law of thermodynamics states that the entropy of a system approaches a constant value as the temperature approaches absolute zero.
Or:
The third law of thermodynamics states, regarding the properties of closed systems in thermodynamic equilibrium: The entropy of a system approaches a constant value when its temperature approaches absolute zero.