A -13.68 gram of sample of iron is heated in the presence of excess fluorine. A metal Fluoride is formed with a mass of 27.64g. Determine the empirical formula of the metal fluoride.

Answers

Answer 1

Explanation:

A 13.68 g sample of iron is reacted in presence of excess fluorine and an iron fluoride with a mass of 27.64 g is formed.

We have to find the empirical formula of our compound. This compound has two elements: Fe and F. We can express it like:

metal fluoride = FeₐFₓ

Where a is the subscript of Fe and x is the subscript for F.

First we have to find the mass of F present in the compound. We know that our compound has a total mass of 27.64 g and the mass of Fe present is 13.68 g. Since it only has two elements we can find the mass of F.

mass of sample = mass of Fe + mass of F

mass of F = mass of sample - mass of Fe

mass of F = 27.64 g - 13.68 g

mass of F = 13.96 g

So we found that our sample has 13.96 g of F and 13.68 g of Fe. Now we can determine the number of moles of each element that are present in the sample by using their molar masses.

molar mass of Fe = 55.85 g/mol

molar mass of F = 19.00 g/mol

moles of Fe = 13.68 g * 1 mol/(55.85 g)

moles of Fe = 0.245 moles

moles of F = 13.96 g * 1 mol/(19 g/mol)

moles of F = 0.735 moles

By definition the empirical formula is "simplest whole number ratio of atoms present in a compound". So if we want to find the ratio between them we have to divide both of them by the smallest number.

a = subscript of Fe = 0.245/0.245 = 1

x = subscript of F = 0.735/0.245 = 3

So the empirical formula of our compound is:

empirical formula = FeₐFₓ

empirical formula = FeF₃

Answer: empirical formula = FeF₃


Related Questions

If you start with 29.0 grams of Ca(OH)2 and 12.5 grams of HCI how many moles of water can be formed?

Answers

Answer

The moles of water that will be produced = 0.343 mol

Explanation

Given:

Mass of Ca(OH)2 = 29.0 g

Mass of HCl = 12.5 g

We know the reaction : Ca(OH)2 + 2HCI —> CaCI2 + 2H2O

Molar mass of Ca(OH)2 = 74.093 g/mol

Molar mass of HCl = 36.458 g/mol

Molar mass of H2O = 18.015 g/mol

Required: Moles of water that will be formed

Solution:

Use the stoichiometry to find the moles of water using both the reactants.

For Ca(OH)2:

[tex]\begin{gathered} 29.0\text{ g Ca\lparen OH\rparen}_2\text{ x }\frac{1\text{ mole Ca\lparen OH\rparen}_2}{74.093\text{ g Ca\lparen OH\rparen}_2}\text{ x }\frac{2\text{ mol H}_2O}{1\text{ mol Ca\lparen OH\rparen}_2} \\ \\ =\text{ 0.783 mol H}_2O \end{gathered}[/tex]

For HCl

[tex]\begin{gathered} 12.5\text{ g HCl x }\frac{1\text{ mol HCl}}{36.458\text{ g}}\text{ x }\frac{2\text{ mol H}_2O}{2\text{ mol HCl}} \\ \\ =\text{ 0.343 mol H}_2O \end{gathered}[/tex]

HCl will produce less moles of H2O, thus HCl is the limiting reactant/reagent and the moles of water that will be produced = 0.343 mol

What is the concentration in molarity of a solution which is 2.91 %m/v benzene (C₆H₆, MM =78.11 g/mol ) in CCl₄ (MM = 153.81 g/mol)?

Answers

According to molar concentration,concentration in molarity  of the solution is 3.77×10[tex]^-7[/tex] M.

What is molar concentration?

Molar concentration is defined as a measure by which concentration of chemical substances present in a solution are determined. It is defined in particular reference to solute concentration in a solution . Most commonly used unit for molar concentration is moles/liter.

The molar concentration depends on change in volume of the solution which is mainly due to thermal expansion. Molar concentration is calculated by the formula, molar concentration=mass/ molar mass ×1/volume of solution in liters.

In terms of moles, it's formula is given as molar concentration= number of moles /volume of solution in liters.

In the given problem,mass of benzene =2.91 g  and molar mass of benzene=78.11 g/mole and volume=100-2.91=97.09 ml or 97.09×10[tex]^-3[/tex] L.

Substituting in the formula,molarity=2.91/78.11×1/97.09×10[tex]^-3[/tex]=3.77×10[tex]^-7[/tex] M.

Hence, the molarity of solution is 3.77×10[tex]^-7[/tex] M.

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what is the volume (in liters) of a 4.2 gram sample of O2 at STP

Answers

to solve this we need to use the ideal gas law:

[tex]PV=nRT[/tex]

we need to calculate the number of mols of O2

[tex]n=\frac{m}{Mm}=\frac{4.2g}{32\text{ g/mol}}=0.131mol[/tex]

Now we just have to solve for volume and use the number of mols just calculated and the standard pressure (1 atm) and temperature 273.15K:

[tex]V=\frac{nRT}{P}=\frac{0.131mol\cdot0.082\text{ }\frac{atm\cdot l}{K\cdot mol}273.15K}{1atm}=2.94l[/tex]

This type of bond is between two metals described as a "Sea of Electrons'?

Answers

Answer:

In the early 1900's, Paul Drüde came up with the "sea of electrons" metallic bonding

The correct answer would be Metallic Bond

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Usually scientists will a large isotope such as Uranium-235 with a ____.
The collision results in several more nuclear fissions, also known as a _____. This results in a HUGE release in energy!

Answers

Usually, scientists will collide a large isotope such as Uranium-235 with a neutron. The collision results in several more nuclear fissions, also known as a chain reaction. This results in a HUGE release of energy!

What is nuclear fission?

Nuclear fission is a type of nuclear reaction in which a large isotope such as uranium-235b is split into two or more smaller isotopes with the release of large quantities of energy and radiation.

The process of nuclear fission in large isotopes can be initiated by colliding or bombarding these large isotopes with fast-moving neutrons which splits the nucleus of the atom, releasing energy ad more neutrons that will split more atoms of the large isotope, resulting in a chain reaction.

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Planets A, B, and C revolve around stars like the sun in orbits like that of Earth. Could planet A possibly support human life?

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The planet, known as Proxima b, may be warm enough for liquid water to exist on its surface and hence be suitable for life because it is located within the star's "habitable zone."

The first and second laws of Kepler were what?

Applying Kepler's laws: The sun is at the centre of elliptical planetary orbits, according to the first law. Second Law: The radius vector from the sun to a planet covers the same area in exactly the same amount of time. Third Law: For every planet, there is a constant relationship between the cube of the elliptical semimajor axis and the square of the period of revolution.

Since the angular momentum is changing at a rate of zero, the angular momentum must be constant, which implies that the rate of change of the swept-out area for the celestial body's orbit must also be constant. This leads to Kepler's Second Law, which states that celestial objects in orbit cover equal regions in similar amounts of time.

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One day in lab, while adding a gnarled root to a dark liquid bubbling in an iron cauldron, your friend Leila (an expert chemist) says this:
"Group 1A metal hydrides react with water to produce hydroxides and hydrogen gas."
Using Leila's statement, and what you already know about chemistry, predict the products of the following reaction.

Be sure your chemical equation is balanced!

KH(s)+ H2O(l)=

Answers

The balanced equation of the reaction of the metal hydride, KH, and water is given below:

KH (s) + H₂O(l) ---> KOH + H₂ (g)

What are metal hydrides?

Metal hydrides are compounds that are composed of a reactive metal chemically combined with hydrogen.

The hydrogen atom is less electropositive than the metal and will accept electrons from the metal to form the negative hydride ion.

For example, Group 1A metal hydrides react with water to produce hydroxides and hydrogen gas.

Considering the above property, the given reaction will be:

KH (s) + H₂O(l) ---> KOH + H₂ (g)

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Which of the following is the ground-state electron configuration of a calcium atom?
O a. [Ne]3s²
O b. [Ne]3s²3p6
OC. [Ar]3d²
O d. [Ar]4s²
O e. [Ar]4s¹3d1

Answers

The arrangement of electrons in orbitals around an atomic nucleus is known as electronic configuration. It is also known as electronic structure or electron configuration. It follows Aufbau's principle, Hund's rule and Pauli's exclusion principle, to fill the electrons in various orbitals according to the energy of the orbitals.

Calcium has 20 electrons, that is, the atomic number of Ca = 20

Hence its electronic configuration will be, 1[tex]s^{2}[/tex] 2[tex]s^{2}[/tex] 2[tex]p^{6}[/tex] 3[tex]s^{2}[/tex] 3[tex]p^{6}[/tex] 4[tex]s^{2}[/tex]

Now, since Argon has 18 electrons, that is, the atomic number of Ar = 18, its electronic configuration will be,

                             Ar =   1[tex]s^{2}[/tex] 2[tex]s^{2}[/tex] 2[tex]p^{6}[/tex] 3[tex]s^{2}[/tex] 3[tex]p^{6}[/tex]

Thus , the simplified electronic configuration of Calcium is,

                                 Ca = [Ar]4[tex]s^{2}[/tex]

Thus, option d)  [Ar]4[tex]s^{2}[/tex] is the correct answer.

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What is the transfer of thermal energy between objects?A. HeatB. HotC. TemperatureD. Cold

Answers

Thermal energy is transferred from a hot body (higher temperature) to a colder body (lower temperature). In these energy exchanges, two types of changes are observed: temperature or physical state. These variations occur both with energy intake and loss. What is being transferred between the two bodies is heat.

Answer: A. Heat.

I need to understand how to do problem number 5

Answers

Answer:

[tex]\begin{gathered} \text{ - molecule of H}_2SO_4=2.408\times10^{24} \\ -4\text{ atoms of Oxygen} \end{gathered}[/tex]

Explanations:

Given the following parameters

Moles of sulfuric acid = 14 moles

According to the Avogadro's constant;

[tex]1\text{mole}=6.02\times10^{23}molecules[/tex]

The number of molecules of 14 moles of sulfuric acid is calculated as:

[tex]\begin{gathered} \text{ molecule of H}_2SO_4=14\times6.02\times10^{23} \\ \text{ molecule of H}_2SO_4=24.08\times10^{23} \\ \text{ molecule of H}_2SO_4=2.408\times10^{24} \end{gathered}[/tex]

Hence the molecule of sulfuric acid that is contained in 14moles if sulfuric acid is 2.408 * 10^24 molecules

Since the chemical formula of sulfuric acid is expressed as H₂SO₄. This shows that the compound has 2 atoms of Hydrogen, 1 atom of sulfur, and 4 atoms of oxygen.

Hence the number of atoms of oxygen contained in this sample is 4 atoms

when a bunsen burner is properly adjusted, what should the flame look like?

Answers

when a bunsen burner is properly adjusted, the flame looks Blue with no gap between the burner and the flame.

A Bunsen burner is a particular kind of gas burner that is frequently utilized as a heat source in lab investigations. The barrel or chimney of the burner is made up of a straight tube that extends vertically from a flat base. At the bottom of the chimney, liquid petroleum gas, such as propane or butane, or natural gas, primarily methane, is delivered.

The base of the chimney on Bunsen burners typically has a hose barb installed so that rubber tubing may supply the gas from a gas nozzle on the lab bench.

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Which of the following does NOT happen during a chemical reaction?A. Bonds are brokenB. Bonds are formedC. Energy is createdD. Mass is conserved

Answers

ANSWER

Energy is created ------ (option C)

EXPLANATION

During the chemical reaction process, reactants need to be converted to form products. To balance such chemical reaction equation, we need to apply the law of conservation of mass

Law of conservation of mass states that matter can neither be created nor destroyed but can be transformed from one form to another.

In the process ofa chemical reaction, bonds are broken are the reactants side, bonds are formed on the products side and mass is conserved

Therefore, the correct answer is Energy is created

List two components of rocket fuel?

Answers

A component that many space agencies use is liquid hydrogen, which can be abbreviated as LH2.

And another fuel very used in rockets is kerosene which is a hydrocarbons mixture of other compounds that fuel.

Answer:

Most liquid chemical rockets use two separate propellants: a fuel and an oxidizer. Typical fuels include kerosene, alcohol, hydrazine and its derivatives, and liquid hydrogen. Many others have been tested and used. Oxidizers include nitric acid, nitrogen tetroxide, liquid oxygen, and liquid fluorine.

Explanation:

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Calculate the total energy of 9.4 * 10^16 photons of visible light with a wavelength of 4.3 * 10^7 m.

Answers

According to the Planck's equation which is E= hc/λ the total energy  of 9.4×10¹⁶ photons is 43.446×10[tex]^-17[/tex] J.

What is Planck's equation?

Max Planck  discovered the theory which stated that energy is transferred in the form of discrete packs which are called quanta  and thus proposed an equation called the Planck's equation which relates energy and frequency of a photon and is given as, E=hcυ or in terms of wavelength it is ,E=hc/λ.

The equation makes use of a constant which is called the Planck's constant and it's value is 6.626×10[tex]^-34[/tex] Js.

Substituting the given value of wavelength of  one photon  in the above formula containing wavelength,E=6.626×10[tex]^-34[/tex]×3×10⁸/4.3×10⁷=4.622×10[tex]^-33[/tex] J.

Now, for energy of 9.4×10¹⁶ photons =4.622×10[tex]^-33[/tex]×9.4×10¹⁶=43.446×10[tex]^-17[/tex] J.

Thus, the energy of 9.4×10¹⁶ photons is 43.446×10[tex]-17[/tex] J.

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Please help with Chemistry I'm confused at the elements reactivity:

Question:
Which of the following combination of elements is the most reactive?

Answer options:
A: Potassium and Iodine
B: Caesium and Iodine
C: Sodium and Bromine
D: Caesium and Bromine

Answers

The combination of elements that is the most reactive would be caesium and bromine.

Reactivity of metals and non-metals

The reactivity series of elements is a table that shows how reactive elements are, usually in descending order.

Elements are classified as metals, non-metals, and metalloids. Metals or non-metals that are at the top of the reactivity series are highly reactive and cannot be displaced in solution by metals below them.

Highly reactive non-metals are also usually at the top of the reactivity series of non-metals. They are able to form compounds with a wide variety of elements.

A typical reactivity series of metals include caesium, rubidium, potassium, sodium, lithium, etc. A reactivity series of non-metals include fluorine, chlorine, oxygen, bromine, iodine, etc.

Thus, bromine is more reactive than iodine and caesium is more reactive than potassium and sodium.

The combination of elements that are the most reactive among the options is, therefore, Caesium and Bromine.

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Write formulas or names as appropriate for each of the following ionic compounds. 1. Magnesium nitride 6. SrI2 2. Lithium oxide 7. Ba3(PO4)2 3. Aluminum sulfite 8. (NH4)2O 4. Copper(II) bicarbonate 9. Fe(ClO)3 5. Sodium nitrate 10. ZnCrO4

Answers

We have the following formulas for the given compounds:

1. Magnesium nitride ---> Mg3N2

2. Lithium oxide ---> Li2O

3. Aluminum sulfite ---> Al2(SO4)3

4. Copper (II) bicarbonate ---> Cu(HCO3)2

5. Sodium nitrate ---> NaNO3

For the given formulas we have the following names:

6. SrI2 ---> Strontium iodide

7. Ba3(PO4)2 --->Barium phosphate

8. (NH4)2O ---> Ammonium oxide

9. Fe(ClO)3 ---> Iron(III) hypochlorite

10. ZnCrO4 ---> zinc chromate

How many atoms of O are there in 7.00 g FeSO4 ?

Answers

Answer:

1.11 x 10²³ atoms O

Explanation:

To find the number of oxygen atoms in FeSO₄, you need to (1) convert FeSO₄ from grams to moles (using the molar mass), then (2) convert moles FeSO₄ to moles O (using the mole-to-mole ratio of FeSO₄), and then (3) convert moles O to atoms O (using Avogadro's Number). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs like the given number (7.00 = 3 sig figs).

Atomic Mass (Fe): 55.845 g/mol

Atomic Mass (S): 32.065 g/mol

Atomic Mass (O): 15.999 g/mol

Molar Mass (FeSO₄): 55.845 g/mol + 32.065 g/mol + 4(15.999 g/mol)

Molar Mass (FeSO₄): 151.906 g/mol

1 mole FeSO₄: 1 mole Fe, 2 mole S, 4 moles O

Avogadro's Number:

6.022 x 10²³ atoms = 1 mole

 7.00 g FeSO₄             1 mole                 4 moles O            6.022 x 10²³ atoms
-----------------------  x  -------------------  x  -----------------------  x  ----------------------------
                                   151.906 g           1 mole FeSO₄                  1 mole

=  1.11 x 10²³ atoms O

a) A solution of sodium thiosulfate, Na2S2O3, is 0.1047 M. 18.59 mL of this solution reacts with 38.62 mL of I2 solution. What is the molarity of the I2 solution?

2(Na2S2O3) + I2↔Na2S4O6 + 2(NaI)

b) 26.64 mL of the I2 solution from above is required to titrate a sample containing As2O3. Calculate the mass of As2O3 (197.8 g/mol) in the sample.

As2O3 + 5(H2O) + 2I2 → 2(H3AsO4) + 4HI

Answers

From the calculations, the molarity of the iodine solution is 0.025 M and the mass of the arsenic oxide solution is 0.066 g.

What is the molarity?

Let us recall that the molarity is defined as the ratio of the number of moles to the volume of the solution. It is a measure of the amount of substance present. Ley us now try to use what we know to obtain the molarity of the solution in each of the cases of the questions.

a) Using;

CAVA/CBVB = NA/NB

CA = Amount of thiosuphate

CB = Amount of iodine

VA = volume of thiosuphate

VB = volume of iodine

NA = number of moles of thisulphate

NB = Number of moles of iodine

Hence;

0.1047 M * 18.59 mL/CB * 38.62 mL = 2/1

0.1047 M * 18.59 mL * 1 = CB * 38.62 mL * 2

CB = 0.1047 M * 18.59 mL * 1 /38.62 mL * 2

CB = 1.946/77.2

CB = 0.025 M

b) Using the formula;

Number of moles = concentration * volume

Number of moles = 0.025 M * 26.64 /1000 L

= 6.66 * 10^-4 moles

Again;

1 mole of the arsenic oxide reacts with 2 moles of iodine solution

x moles of the arsenic oxide reacts with 6.66 * 10^-4 moles of iodine

x = 1 mole *  6.66 * 10^-4 moles/ 2 moles

x = 3.33  * 10^-4 moles

Mass of the arsenic oxide = 3.33  * 10^-4 moles * 197.8 g/mol

= 0.066 g

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What is the balanced chemical equation for the reaction of sodium and oxygen?Na + O to NaO2Na + O2 to 2 NaO4Na + O2 to 2Na2ONa + O2 to NaO2

Answers

Answer

4Na + O₂ → 2Na₂O

Explanation

Sodium reacts with oxygen to form sodium oxide and has the following balanced chemical equation:

4Na + O₂ → 2Na₂O.

Hence, the balanced chemical equation for the reaction of sodium and oxygen is:

4Na + O2 to 2Na2O

Can someone draw this for me?
Btw you don't need real gumdrops or toothpicks you just need to draw it.
I'll mark the brainliest.

Answers

Both calcium oxide and carbon dioxide are inorganic compounds where calcium oxide is an ionic compound with a positive end at calcium and negative end at oxygen and carbon dioxide is a covalent compound formed by two double bonds between carbon and each oxygen.

What is calcium oxide?

Calcium oxide is also called soda lime which is an inorganic compound formed by the ionic bonding of oxygen and calcium. Calcium is a metal and it is electron rich with 2 valence electrons.

Oxygen is electronegative gas, having 6 valence electrons and require two electrons to be stable. Thus calcium donates its two electrons to oxygen making calcium a positive ions and oxygen a negative ion.

In carbon dioxide, carbon have a valency of four thus, it forms 4 bonds with two oxygens. Double bonds are formed with each oxygen as shown in the image. These bonds are formed by electron sharing and is called covalent.

Calcium carbonate is formed by passing carbon dioxide through lime (CaO) in which Ca exists as Ca²⁺ ion and carbonate as an anion with three negative charges residing on 2  oxygens in CO₃.

Therefore, the structure of each of these compounds depends on the type of bonds between the atoms and it is depicted in the uploaded image.

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If an acid dissosciates, what is happening?A. It is combining with a base in a neutralization reactionB. it is involved in a chemical reactionC. the concentration is decreasingD. it is being pulled apart by solvent molecules

Answers

In a solution, when we have an acid being dissociated, what is actually happening is that the acid is being pulled apart by solvent molecules, becoming two ions, the proton H+ and the conjugated base, this is what causes the solution to be acidic, and this is also how the strength of the acid is measured. Therefore the best answer is letter D

Place the following gases in order of decreasing average molecular speed at 300K: He, SF6, SO2, Ar

Answers

Temperature is a way to measure the kinetic energy of the molecules of gases. The kinetic energy is a kind of energy that a moving body has. it is related to the mass of the body and the speed they are moving. The kinetic energy can be calculated as:

[tex]E_k=\frac{1}{2}mv^2[/tex]

Where Ek is the kinetic energy, m is mass of the molecules and v is the speed of the molecule

Knowing that gasses with the same temperature have same kinetic energy, then gasses with larger mass will move slower and viceversa.

Since the molar mass of those gases are:

He: 4.00 g/mol

SF6: 146.06 g/mol

SO2: 64.066 g/mol and

Ar: 39.948 g/mol

the ligther gasses move faster and the hevier slower, so we just have to order them by increasing mass:

He, Ar, SO2 and SF6

Lithium nitride is an ionic compound. Draw a diagram which shows its formula, the charges on the ions and the arrangement of the valency (outer shell) electrons around the negative ion. Use x for an electron from a lithium atom and o for an electron from a nitrogen atom. ​

Answers

Lithium nitride is an ionic compound and the chemical formula of lithium nitride is Li₃N and the charges on the ions is Li⁺¹N³⁻ 3 valence electron in lithium and 5 valence electron in nitrogen

Ionic compound is the ion compound these ions are atom that gain or lose electron resulting in a net positive and negative charges and lithium nitride is an ionic compound and in that Li⁺¹N³⁻ is the ion and the arrangement of the valency (outer shell) electrons are 3 valence electron in lithium and 5 valence electron in nitrogen

X = 3 electron

O = 7 electron

And that's why lithium nitride has 10 electron

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PLEASE HELP, WILL MARK BRANLIEST!!
The half-life of cobalt-60 is 10.47 min. How many grams of cobalt-60 remain after 104.7 min if you start with 1024g?

Answers

Answer: 1 gram

Explanation:

- the equation is 1024(.5)^10

• so 1024g is your initial amount and it’s the amount that is being decayed

• since it’s half-life, the decay factor is 0.5

• the half life is 10.47 minutes, so 10.47 minutes would be considered one round of half life.

-basically, if you were finding the half life after 10.47 minutes you would use the equation 1024(.5)^1.

-as said, it’s raised to the 1st power because 10.47 minutes is one round.

• since you’re looking for the amount after 104.7 minutes, the equation is raised to the 10th power because 104.7 / 10 = 10.47. so 104.7 is 10 rounds of half-life.

- so 1024(.5)^10 = 1

so the half-life of 1024g of Cobalt-60 after 104.7 minutes is 1

hope this helps :)

Write a balanced equation for the decomposition reaction that occurred in Experiment 2. Include physical states.

Answers

The answer will be in the picture

Which type of element is shown in green boxes

Answers

Please upload what graphic you are referencing in this question.

How many grams of CO2 are produced if 12 liters of H2O are produced?

Answers

Answer

[tex]14653.7181\text{ g }CO_2\text{ }[/tex]

Procedure

Considering the following balanced equation.

2CH₃OH + 3O₂ ---> 2CO₂ + 4H₂O

To determine the grams of CO₂ that will be produced, you will first need to get the grams of water produced, then convert the grams of water into moles of water and use the molar proportios to get the moles of CO₂. Lastly, convert the moles of CO₂ into grams.

Additional data:

Dnsity of water = 1 g H₂O=/ of H₂O

CO₂ molar mass = 44.01 g/mol

H₂O molar mass = 18.02 g/mol

Calculations

Convert to mass

[tex]12L\text{ }H₂O\text{ }\frac{1kg\text{ }H_2O}{1L\text{ }H_2O}=12kg\text{ }H_2O[/tex]

Convert to moles

[tex]12kg\text{ }H₂O\text{ }\frac{1000g\text{ }H_2O\text{ }}{1kg\text{ }H_2O}\frac{\text{ }1\text{ }mole\text{ }H_2O}{18.02g\text{ }H_2O}=665.9267\text{ }mole\text{ }H_2O[/tex]

Convert to moles of CO₂ using the relationship

[tex]665.9267\text{ }mole\text{ }H_2O\frac{2moleCO_2}{4mole\text{ }H_2O}=332.9634\text{ }mole\text{ }CO_2[/tex]

Convert to grams of CO₂

[tex]332.9634\text{ }mole\text{ }CO_2\text{ }\frac{44.01g\text{ }CO_2}{1\text{ }mole\text{ }CO_2}=14653.7181\text{ g }CO_2\text{ }[/tex]

an equimolar mixture of n2(g)n2(g) and ar(g)ar(g) is kept inside a rigid container at a constant temperature of 300 kk. the initial partial pressure of arar in the mixture is 0.75atm0.75atm. an additional amount of arar was added to the container, enough to double the number of moles of arar gas in the mixture. assuming ideal behavior, what is the final pressure of the gas mixture after the addition of the arar gas? responses 0.75atm0.75atm, because increasing the partial pressure of arar decreases the partial pressure of n2n2. 0.75 atmosphere , because increasing the partial pressure of a r decreases the partial pressure of n 2 . 1.13atm1.13atm, because 333% of the moles of gas are n2n2. 1.13 atmospheres , because 33 percent of the moles of gas are n 2 . 1.50atm1.50atm, because the number of moles of n2n2 did not change. 1.50 atmospheres , because the number of moles of n 2 did not change. 2.25atm2.25atm, because doubling the number of moles of arar doubles its partial pressure.

Answers

To solve such type of question we must be knowing the concept behind the ideal gas equation. The final pressure of the gas mixture after the addition of the Ar gas is 2.25 atm

What is ideal gas equation?

Ideal gas equation is the mathematical expression that relates pressure volume, temperature and number of moles of gas

Mathematically,

PV=nRT

according to question T and V is constant

P ∝ n

P₁/n₁= P₂/n₂

Where

P₁ = initial pressure= 0.75atm

P₂ = Final pressure=?

n₁= number of moles of gas initially present=n

n₂ = Final moles of gas present=2n

Substituting into the given equation

P₂= P₁n₂/n₁

P₂ = 0.75atm ×2n/n

P₂ = 1.5 atm

The total pressure of the gas=partial pressure of N2 +  partial pressure after addition of Ar = 0.75 atm + 1.5 atm = 2.25 atm

The final pressure of the gas mixture after the addition of the Ar gas is 2.25 atm

To learn more about ideal gas equation, here:

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Calculate the imperial formula of the compound. Express your answer as a chemical formula.

Answers

The empirical formula corresponds to the simplest form of expressing a compound, it indicates the proportion of atoms in the molecule.

We have two elements S and F and they give us the mass resulting from the decomposition of the molecule. We can find the moles of each element using the atomic weight of each element as follows:

[tex]\begin{gathered} \text{Moles S= Given g of S}\times\frac{1\text{ mol S}}{AtomicWeight,\text{ g S}} \\ \text{Moles S= 0.905 g of S}\times\frac{1\text{ mol S}}{32.065\text{ g S}}=0.028\text{mol S} \end{gathered}[/tex][tex]\begin{gathered} \text{Moles F= Given g of F}\times\frac{1\text{ mol F}}{AtomicWeight,\text{ g F}} \\ \text{Moles F=3.221 g of F}\times\frac{1\text{ mol F}}{18.998\text{g F}}=0.170\text{mol F} \end{gathered}[/tex]

To find the ratio between the elements we divide the moles of each element by the smallest number of moles found, that is by 0.028 moles.

[tex]\begin{gathered} S\rightarrow\frac{0.028}{0.028}=1 \\ F\rightarrow\frac{0.170}{0.028}=6 \end{gathered}[/tex]

Therefore the empirical formula of the compound will be:

[tex]SF_6[/tex]


A silver ring is composed of 1.81×1023 atoms. Calculate the mass of the ring in grams.

Answers

Solving with Moles

Mole equation: [tex]n=\dfrac{m}{MM}[/tex]

n = number of moles (mol)m = mass (g)MM = molar mass (g/mol)

To find mass given number of atoms:

Divide number of atoms by the number of atoms in the chemical formula ⇒ find number of moleculesDivide number of molecules by Avogadro's number ([tex]6.02*10^{23}[/tex]) ⇒ find number of moles (n)Solve for m using moles equation

Solving the Question

We're given:

Ag (silver)Atoms = [tex]1.81*10^{23}[/tex] atomsm = ?

In the chemical formula, which is Ag, there is only 1 atom.

Divide [tex]1.81*10^{23}[/tex] atoms by 1 atom to get the number of molecules in the silver ring:

[tex]1.81*10^{23}\div 1\\=1.81*10^{23}[/tex]

Therefore, there are [tex]1.81*10^{23}[/tex] molecules in the silver ring.

Now, divide [tex]1.81*10^{23}[/tex] molecules by Avogadro's number to find n:

[tex]\dfrac{1.81*10^{23}}{6.02*10^{23}}\\\\=\dfrac{1.81}{6.02}\\\\=\dfrac{1.81}{6.02}\\\\= 0.30066[/tex]

Therefore, the sample has 0.30066 mol.

Finally, solve for the mass using the moles equation:

[tex]n=\dfrac{m}{MM}[/tex]

⇒ Rearrange the equation:

[tex]m=n*MM[/tex]

⇒ MM of Ag = 107.87 g/mol

⇒ Plug in given information:

[tex]m=0.30066* 107.87\\m=32.4[/tex]

Therefore, the mass of the ring is 32.4 g.

Answer

32.4 g

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