The minimum distance at which an automatic braking system needs to activate to avoid hitting a stationary object is 2.5 meter. The correct answer is a.
To calculate this, we can use the equation:
distance = initial velocity² / (2 × deceleration).
In this case, the initial velocity is 10 m/s and the deceleration is 2 m/s². Plugging these values into the equation gives us:
distance = 10² / (2 × 2)
distance = 25 meter
Since the car's speed is slowing down at a rate of 2m/s², the car will need 25 meter distance to come to a complete stop. However, the question asked for the minimum distance at which the automatic braking system needs to activate, therefore the minimum distance at which the automatic braking system needs to activate is 10% of the stopping distance which is:
10/100 × 25 = 2.5 meter
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What is the acceleration of an object with 4 n and 0.2 kg
Answer:
I do not know this one sorry
Explain which movement Jamal should make (which car and which point), and why that movement will result in the largest increase in potential energy. Describe the magnetic force that will act on the vehicle he moves.
Because potential energy increases with separation distance, Jamal should move the toy car with the greatest separation distance.
What do you mean by potential energy ?The term potential energy is defined as stored energy that depends upon the relative position of various parts of a system. Potential energy is energy that cannot be transfer to kinetic energy. It has the capacity to do work but is not presently doing so.
Because magnetic force is inversely proportional to the separating distance between the cars, the magnetic force acting on the vehicles will decrease as he moves the cars away from each other.
Thus, potential energy increases with separation distance, Jamal should move the toy car with the greatest separation distance.
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a movable bin and its contents have a combined weight of 2.1 kn determine the shortest chain sling acb that can be used to lift the loaded bin if the tension in the chain is not to exceed 5 kn. the shortest chain sling acb that can be used is m.
The shortest chain sling ACB for a movable bin is 1.228 m.
The question is not complete. A similar question is in the attachment. Use the image in a similar question for this problem. Look at the picture. In the system works
Tension in the chain T₁ and T₂The weight of a movable bin = wTriangle ABC is an isosceles triangle. If ∠ CAB = ∠ CBA = θ.
T₁ = T₂ ≤ 5 kNAccording to Newton's first law, in the y-axis
∑ F = 0
w - T₁y - T₂y = 0
T₁y + T₂y = 2,100
T₁ sin θ + T₂ sin θ = 2,100
5,000 sin θ + 5,000 sin θ = 2,100
10,000 sin θ = 2,100
sin θ = 2,100 ÷ 10,000
sin θ = 0.21
θ = sin⁻¹ (0.21)
θ = 12.12°
Look at AOC
AO = OB = AB ÷ 2 = 1.2 ÷ 2 = 0.6 m cos θ = AO ÷ACLearn more about Newton's first law here: https://brainly.com/question/10454047
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What is the mechanical advantage of a pulley? 0.5 1.0 1.5 2.0
The mechanical advantage of a pulley is the ratio of the output force to the input force.
For example, if a pulley is used to lift a weight of 100 pounds, and the input force is 10 pounds, then the mechanical advantage is 10:1 (100/10).
This means that for every 10 pounds of input force, the pulley can lift 100 pounds of weight. The mechanical advantage of a pulley is determined by the number of strands of rope that are used in the pulley system. The more strands of rope, the higher the mechanical advantage will be.
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what is fetch? multiple choice question. the distance from wave trough to wave crest the distance over water that the wind blows in the same direction a standard measure used for water depth
Fetch: A region of an ocean or lake's surface where wind blows in a direction that is basically continuous, producing waves.
How physically act waves?An energetic disturbance called a wave moves from one place to another. The only thing that changes when a wave moves is energy, not matter. The substance in which a wave passes is known as the medium. Until it lands in the same place, that medium frequently swings back and forth.
What are the three fundamental qualities of waves?But amplitude, wavelength, energy, and speed are characteristics that all waves share. How much a wave's medium moves is described by its amplitude. Wavelength and frequency both refer to the size and frequency of waves. A wave's speed is its rate of movement.
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Which answer best describes the climate of an area?
A. Rain is falling from clouds
B. A hurricane cause several days of flooding
C. Snow is falling on a mountain
D. Most days are dry and Sunny
ball is thrown veritcally at this speed. how long until it reaches highest point? how long is in the air?
The ball takes 1.22s to reach the highest point. It remains in the air for 2.44 s when it is thrown vertically upwards.
Equations of motion define the behaviour of physical system in terms of the motion as a function of time.
At the topmost point, v = 0.
Gravitational acceleration is equal to a = -g = -9.8 m/s²
We know one of the equations of motion as, v = u + a t
where, v is final velocity
u is initial velocity
a is acceleration
t is time
Putting in the values in the above equation, we have,
0 = 12 -9.8 t
9.8 t = 12
t = 1.22 s
Thus, the ball reaches the highest point in 1.22 s.
To find out the time in which the ball remains in the air is can be calculated by, v² - u² = 2 a s
where, s is the distance
- 12² = 2 × (-9.8) s
19.6 s = 144
s = 7.34 m
The total time taken by the ball to reach the maximum height is 1.22 s and it takes another 1.22 s to reach the ground.
So, the ball remains in the air for 2.44 s.
The question is incomplete. The complete question is 'Ball is thrown vertically at this speed 12 m/s.'
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A batter hits a ball and it is caught 4 seconds later 100m from home plate. What is the initial velocity of the ball
The initial velocity vector of the ball is;= 25·i + 19.6·j.The falling ball's velocity as a function of time is v = -9.8 (m/s2) t j, and its location as a function of time is r = (4.9 m - 12 9.8 (m/s2) t2) j.
What is the initial velocity of the ball ?The parameters listed are;The ball's flight time was 4 seconds.The ball is caught 100 meters away from the plate in the horizontal direction.
Assuming that "u" stands for the initial velocity, we have;
100 m is equal to u cos(t) = u cos(4s)
u = cos() / 2 = 25 m/s (1)
∴tan() = 1.568/2 = 0.784 = arctan(0.784) 38.096°. 2usin() =
9.8 m/s2 4 s = 39.2 m/s
The ball's velocity vector's direction is 38.096°.
Equation (1) gives us u cos() = 25 m/s.
31.7672787629 m/s is equal to u = 25 m/s/cos()
= 25 m/s/cos(arctan(0.784))
The initial velocity vector's magnitude is u = 31.7672787629 m/s.
The initial velocity's vertical component is equal to u sin() = 31.7672787629 sin(arctan(0.784)).
Since the ball's starting velocity vector is approximately 31.767 m/s in a direction 38.096° above the horizontal, we can calculate the following:
u = ux(i,j) = 25(i,j) + 19.6(j)
= 25·i + 19.6·j
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what is the stopping sight distance for a road with a design speed of 65 mph, a 0.25 coefficient of friction and a 2% uphill grade? assume that the perception-reaction time is 2 seconds.
The stopping sight distance (SSD) for a road with a design speed of 65 mph, a 0.25 coefficient of friction, and a 2% uphill grade would be 2673.87 feet.
What is Stopping sight distance?Stopping sight distance (SSD) is a measure of the distance a vehicle needs to travel in order to come to a complete stop after the driver perceives a potential hazard on the road. It is calculated by taking into account the driver's perception-reaction time, the vehicle's speed, the road's gradient, and the road's surface friction. SSD helps ensure that drivers have enough time and distance to stop safely in case of an emergency. It is often used to determine the appropriate placement of signs, signals, and other traffic control devices on a road.
The stopping sight distance (SSD) for a road with a design speed of 65 mph, a 0.25 coefficient of friction, and a 2% uphill grade can be calculated using the formula: SSD = (Speed x Perception-Reaction Time) + (Speed² / (2 x G x Friction Coefficient))
Where, Speed = 65 mph = 65 x 1.46667 = 94.44 ft/s
Perception-Reaction Time = 2 seconds = 2 x 1.46667 = 2.933 ft/s
G = 32.17 ft/s² (acceleration due to gravity)
Friction Coefficient = 0.25
Therefore,
SSD = (94.44 x 2.933) + (94.44² / (2 x 32.17 x 0.25))
SSD = 277.33 + 2396.54
SSD = 2673.87 ft
So, the stopping sight distance is 2673.87 feet.
This means that a driver should be able to see an obstacle at least 2673.87 feet ahead of them in order to be able to stop safely in case of an emergency.
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a particle of mass m is located inside a uniform solid sphere of radius r and mass m, at a distance r from its center. (a) show that the gravitational potential energy of the system is (b) write an expression for the amount of work done by the gravitational force in bringing the particle from the surface of the sphere to its center.
The equation for the system's gravitational potential energy is U = − G * (m2 / R). and G * (m2 / R) is the amount of effort the gravitational force must do to move the particle from the sphere's surface to its centre.
(a) The formula U = - G * (Mm / r), where G is the gravitational constant, M is the mass of the sphere, and m is the mass of the particle, may be used to compute the gravitational potential energy of the system. Here, M = m U = - G * (m2 / R)
(b) The particle's initial potential energy when it is on the sphere's surface is Ui = - G * (m2 / R), and its final potential energy when it is in the sphere's centre is Uf = 0. Work completed equals Uf - Ui work completed equals 0 - (- G * (m2 / R)) work completed equals G * (m2 / R).
G * (m2 / R) represents the amount of effort the gravitational force must do to move a particle from the sphere's surface to its centre.
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if a w hairpin filament operating temperature is increased from 800c to 900 c what is the expected increase in the brightness
The brightness of a tungsten filament is determined by several factors, including its temperature, size, shape, and material properties, as well as the properties of the surrounding environment, such as the pressure and composition of the gas.
What do you mean by tungsten ?Tungsten is a chemical element with the symbol W and atomic number 74. It is a dense, silvery-white metal that is highly valued for its high melting point and its ability to withstand high temperatures. It is often used in the production of filaments for incandescent light bulbs, electrical contacts, and other electrical and electronic applications. Tungsten is also used in alloys, such as high-speed steel, to improve the hardness and strength of the materials.
It is not possible to determine the expected increase in brightness of a tungsten hairpin filament simply by knowing that its operating temperature has been increased from 800°C to 900°C. The brightness of a tungsten filament is determined by several factors, including its temperature, size, shape, and material properties, as well as the properties of the surrounding environment, such as the pressure and composition of the gas.
In general, increasing the temperature of a tungsten filament can increase its brightness, as higher temperatures can lead to increased rates of thermionic emission, which is the process by which electrons are emitted from a hot metal surface. However, increasing the temperature also has other effects on the filament, such as changes in its shape, which can also impact its brightness.
It is important to note that increasing the temperature of a tungsten filament beyond a certain point can result in rapid degradation of the filament and eventually cause it to fail. Therefore, it is important to carefully control the temperature of tungsten filaments and monitor their performance to ensure that they are operating within safe and reliable limits.
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what will be the magnitude of the electrostatic force between two charged balls 23.0 cm apart if the residual charge on the first ball is -31.0 micro c while the residual charge on the second ball is 12.0 micro c ?
Magnitude of electrostatic force between two charged balls is 63 Nm²/C²
What is electrostatic force?The electrostatic force is an attractive as well as repulsive force caused by the electric charge particles. It is also known as Coulomb's force. The Coulomb attraction would be named after Charles-Augustin de Coulomb, a French scientist. One of nature's four basic forces however is electrostatic force.
In this question we have ,
F = Q1 × q₂ ×K / R²
K = 9 × 10⁹
From above equation by solving his we get value of electrostatic force is 63 Nm²/C²
What is electric Field ?An electric field (sometimes E-field) is the physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them.It also refers to the physical field for a system of charged particles
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How does the current in a resistor change if the voltage across the resistor is
decreased by a factor of 4?
A. It decreases by a factor of 4.
B. It decreases by a factor of 2.
C. It increases by a factor of 4.
D. It increases by a factor of 2.
The current in a resistor change if the voltage across the resistor is
decreased by a factor of 4.
What is meant by resistor ?
A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device.A specified voltage can be supplied via resistors to an active device like a transistor.Modern resistors are often constructed from a carbon, metal, or metal-oxide layer.In these resistors, an insulating material is wrapped in a helix around a thin film of conductive (but still resistant) material.A passive electrical component called a resistor prevents the flow of electric current by introducing resistance.They are present in practically all electrical networks and electronic circuits. Ohms are used to measure resistance.Voltage, V = IR where I = current and R = resistance.
So,V₁ = I₁R. So, I₁ = V₁/R. Now the new current is I₂ = V₂/R
If V₂ = V₁/4, then I₂ = V₂/R = (V₁/4)/R = V₁/4R = I₁/4
I₂ = I₁/4
The current is reduced by 1/4
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How much force would you need to accelerate a 4 kg object from a standstill to 5 m/s^2
Answer:
Answer is in attached photo.
Explanation:
SolutionSolution is in attached photo, take note of the formula:
Force = Mass x Acceleration.
suppose a certain heat engine has an efficiency of 35% . a thermodynamic diagram showing a hot reservoir above, a cold reservoir below, and a closed system in between. a thick arrow indicates that heat flows into the system from the hot reservoir. thinner arrows indicate that the system does work and expels heat into the cold reservoir. in order for this heat engine to do 420 j of useful work, how much energy must be taken in as heat from the high-temperature reservoir?
Energy must be taken in as heat from the high-temperature reservoir is 1200 J.
What do you mean by thermodynamics?The science of thermodynamics examines how heat, work, temperature, and energy are related. The flow of energy from one location to another and from one form to another is broadly what thermodynamics is concerned with.
The efficiency of a heat engine is the ratio of the useful work done by the engine to the total heat energy taken in from the hot reservoir. In this case, the efficiency is 35%. Therefore, the useful work done by the engine is 35% of the total heat energy taken in from the hot reservoir.
If the heat engine does 420 J of useful work, we can use the efficiency formula to find the total heat energy taken in from the hot reservoir:
Total heat energy = (Useful work) / (Efficiency) = 420 J / 0.35 = 1200 J
So, in order for this heat engine to do 420 J of useful work, it must take in 1200 J of energy as heat from the high-temperature reservoir.
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An object whose mass is 3 kg is fired from a cannon, giving it a forward momentum
of 1050 kg-m/sec. What is its velocity?
The velocity of an object can be calculated using the equation:
velocity = momentum / mass
Given the mass of the object is 3 kg and the forward momentum is 1050 kg-m/sec, we can substitute these values into the equation:
velocity = 1050 kg-m/sec / 3 kg
velocity = 350 m/sec
Therefore, the velocity of the object is 350 m/sec.
How does the velocity of an object affect its momentum?The velocity of an object is directly proportional to its momentum. As the velocity of an object increases, so does its momentum. This relationship is described by the equation p = m * v, where p is the momentum, m is the mass of the object and v is its velocity. This equation shows that the momentum of an object is directly proportional to the velocity of the object. This means that if the velocity of an object is doubled, its momentum will also double. Conversely, if the velocity of an object is halved, its momentum will also be halved. Also, If the direction of motion of an object changes it also changes the direction of momentum but the magnitude of momentum will remain the same.
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An object whose mass is 3 kg is fired from a cannon, giving it a forward momentum has a velocity of 350 m/sec.
Evaluating :The velocity of an object can be calculated using the equation:
velocity = momentum / mass
Given the mass of the object is 3 kg and the forward momentum is 1050 kg-m/sec, we can substitute these values into the equation:
velocity = 1050 kg-m/sec / 3 kg
velocity = 350 m/sec
Therefore, the velocity of the object is 350 m/sec.
Momentum :The velocity of an object is directly proportional to its momentum. As the velocity of an object increases, so does its momentum. This relationship is described by the equation p = m * v, where p is the momentum, m is the mass of the object and v is its velocity. This equation shows that the momentum of an object is directly proportional to the velocity of the object. This means that if the velocity of an object is doubled, its momentum will also double.
Conversely, if the velocity of an object is halved, its momentum will also be halved. Also, If the direction of motion of an object changes it also changes the direction of momentum but the magnitude of momentum will remain the same.
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Four objects each with charge +2. 0×10−7C+2. 0×10−7C are located at the corners of a square whose sides are 2. 3 mm long.
Part A complete What quantities can be determined using this information?
The total electric potential energy of the system consisting of the four charged objects.
The electric force on a charged object placed at the center of the square.
The mass of each object.
Part B Find the electric force on a charged object placed at the center of the square.
Express your answer with the appropriate units
Negative electrons are more prevalent than positive protons or vice versa in charged things.
How can I determine the electric potential in a square's center? Negative electrons are more prevalent than positive protons or vice versa in charged things.Furthermore, the protons and electrons in neutral things are distributed equally, creating a balance of charge.Applied to things is the same idea that was previously stated for atoms.Electric force is the pressure exerted by charged objects on one another.Gravitational fields are similar to electric fields in that they are the area in which an object's gravitational pull is felt, such as the planet's orbit.The area around a charged object is similarly surrounded by an electric field.As a result, we have determined that the potential energy of the given system, which consists of four charges grouped as illustrated, is -0.021J.As a result, it is decided that Option E is the right response.To learn more about electric potential energy refer
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supply plane needs to drop a package of food to scientists working on a glacier in greenland. the plane flies 190 m m above the glacier at a speed of 160 m/s m / s . for help with math skills, you may want to review: mathematical expressions involving squares for general problem-solving tips and strategies for this topic, you may want to view a video tutor solution of dock jumping. part a how far short of the target should it drop the package? express your answer with the appropriate units.
The package should be dropped 25 m short of the target.
What is package?A package is a collection of related items, such as software components, that are combined into a single unit and distributed for installation or use. Packages can provide a wide range of functionality, from basic data types and libraries, to complete applications and services.
The package should be dropped 25 m short of the target.
To calculate this, we use the formula d = vt,
where d is the distance,
v is the velocity, and t is the time.
We know the velocity (160 m/s) and the time (0.15625 s).
We can determine the distance by plugging these values into the formula: d = 160 m/s × 0.15625 s = 25 m.
Therefore, the package should be dropped 25 m short of the target.
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(d) A 2.5 kg object is placed avocation X where it has 10 J of potential energy. A person bumps the shelf causing the object to fall to the ground, Describe the Law of Conservation of Energy and how it is demonstrated as the object falls to the ground.
The Law of Conservation of Energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.
As the object falls to the ground, its potential energy is converted into kinetic energy. The potential energy is determined by the object's mass and its height above the ground. As the object falls, its height decreases and its potential energy decreases, but this decrease in potential energy is compensated by an increase in kinetic energy. The kinetic energy is determined by the object's mass and its velocity. As the object's height decreases and its velocity increases, its kinetic energy increases.
As the object falls, the total amount of energy remains constant. The initial potential energy of 10 J is equal to the final kinetic energy of the object. This is an example of the Law of Conservation of Energy in action. The object's potential energy is transformed into kinetic energy, but the total amount of energy remains the same.
a point charge of 8.47 x 10-6 c and a mass of 5.49 x 10-6 kg is initially at rest within a constant electric field with a magnitude of 914 n/c. what is the magnitude of the acceleration of the point charge assuming that only the electric field force acts on it?
The magnitude of the acceleration of the point charge assuming that only the electric field force acts on it is 1.54×[tex]10^{7}[/tex].
The magnitude of the acceleration of the point charge can be calculated using the equation a = F/m, where F is the electric field force and m is the mass of the point charge. The electric field force is equal to the charge of the point charge times the magnitude of the electric field, or
F = (8.47 ×[tex]10^{-6}[/tex] C) x (914 N/C).
Therefore, the magnitude of the acceleration can be calculated as
a = (8.47×[tex]10^{-6}[/tex]C x 914 N/C)/(5.49 ×[tex]10^{-6}[/tex] kg) = 1.54 ×[tex]10^{7}[/tex] m/s2.
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You are pushing a 30 kg wooden crate across the floor. The force of sliding friction on the crate is 90 N. How much force must you exert on the crate to keep it moving with a constant velocity
Answer:
f=90N
Explanation:
What is the net work done on an object in free fall whose gravitational
potential energy decreases from 400J to 250J?
a. Wnet = 150J
b. Wnet = 250J
c. Wnet = -150J
d. Wnet = 400J
The net work that has been done by the object in free fall is -150 J.
What is the net work done?We have to note that when an object is said to fall down under the influence of gravity that the object would be acted upon by the acceleration due to gravity.
It should be noted that as the object is falling and the height of the object is decreasing, the value of the gravitational potential energy is also decreasing like wise as the object falls;
Net work done = Final value of energy - Initial value of energy
Net work done = 250J - 400 J
= -150 J
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This states that charge cannot be created or destroyed. However, a charge can be transferred from one object to other
The conservation of charge states that charge cannot be created or destroyed, but can be transferred between objects.
How does the conservation of charge affect the behavior of electric circuits?
The conservation of charge states that charge cannot be created or destroyed, it can only be transferred from one object to another. This principle affects the behavior of electric circuits by ensuring that the total charge in a closed circuit remains constant. This means that the charge flowing into a circuit must equal the charge flowing out of the circuit. If there is an imbalance, the circuit will not function properly.
The conservation of charge also helps to explain the behavior of electric charges in different types of circuits, such as series and parallel circuits.
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A 140.0 g sample of water at 20.0 °c is mixed with 100.0 g of a certain metal at 95.0 °c. after thermal equilibrium was established, the temperature of the mixture is 24.6 °c. what is the specific heat capacity of the metal?
The specific heat capacity of the metal can be calculated using the equation: q = mCΔT, where q is the heat transfer, m is the mass of the metal, C is the specific heat capacity, and ΔT is the change in temperature. The heat transfer from the metal to the water can be determined as q = mCΔT = 100 g * C * (24.6 - 95.0) °C. The heat transfer from the water to the metal can be determined as q = mCΔT = 140.0 g * 4.184 J/g°C * (24.6 - 20.0) °C. The specific heat capacity can then be calculated as C = q / (mΔT).
How does the temperature change of the water and metal determine the specific heat capacity of the metal?The temperature change of the water and steel is used to determine the unique warmth capacity of the steel by means of calculating the warmth switch between the two materials. The warmth switch between the water and metal may be calculated using the equation: q = mcΔT, where q is the heat transfer, m is the mass of the substance, c is the precise heat capability, and ΔT is the trade in temperature. By means of the usage of this equation for each the water and metal, the heat switch among the 2 materials may be calculated and the specific heat potential of the steel can be determined.
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The specific heat capacity of the metal is 140 J/kg°C.
What do you mean by Metal?A metal is a chemical element that is typically characterized by its high electrical conductivity, thermal conductivity, and luster. It is usually a dense, malleable, and ductile material that is a good conductor of heat and electricity. Examples of metals include copper, silver, gold, iron, and aluminum.
The specific heat capacity of the metal can be calculated using the formula:
ΔQ = mCΔT
where ΔQ is the heat transferred, m is the mass of the metal, C is the specific heat capacity, and ΔT is the change in temperature.
First, find the heat transferred:
ΔQ = mCΔT = (140.0 g + 100.0 g)(24.6 °C - 20.0 °C) = 240.0 g * 4.6 °C = 1101.6 J
Next, find the heat absorbed by the metal:
ΔQ = mCΔT = 100.0 g * (24.6 °C - 95.0 °C) = -9700 J
Finally, solve for the specific heat capacity:
C = ΔQ / mΔT = -9700 J / 100.0 g * (24.6 °C - 95.0 °C) = -9700 J / 100.0 g * -75.4 °C = 140 J/kg°C
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If john and sam each push on a boulder with a force of 30n, but in opposite directions, what will happen to the boulder?a. the boulder moves towards sam b. the boulder moves away from john and sam c. the boulder moves towards john d. the boulder will not move.
Answer: D
Explanation:
They are exerting the same amount of force on each side which means that there is no net movement.
Answer:D
Explanation:
they are pushing at the same strength so it will not move.
(c) A book with a mass of 0.21 kg is placed at location X. A magazine with a mass of 0.11 kg is placed at location Y. Potential energy of the book: Potential Energy of the magazine: Does the book or the magazine have more potential energy?
The book has more potential energy because it has a greater mass. Potential energy = mass x gravitational acceleration x height.
Does the book or the magazine have more potential energy?Since both objects are at the same height, the book has more potential energy due to its greater mass.The potential energy of an object is determined by the mass of the object and the height from which it is dropped. The higher the object is dropped from, the greater the potential energy. For the book and magazine in question, the potential energy of the book is 0.21 kg x height, while the potential energy of the magazine is 0.11 kg x height. So, if the book and magazine are dropped from the same height, the book will have more potential energy than the magazine. However, if the book is dropped from a higher height than the magazine, then the book will have more potential energy.The potential energy is also determined by the gravitational force acting on the object. The higher the gravitational force, the greater the potential energy. If the book and magazine are located in different locations, the gravitational force acting on the book and magazine will be different, which will also affect their potential energy. For example, if the book is located in a higher altitude than the magazine, the gravitational force acting on the book will be greater, resulting in more potential energy for the book.To learn more about The potential energy refer to:
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The speed of an object undergoing constant acceleration increases from 8.0 meters per second to 16.0 meter per second in 10 seconds. How far does the object travel during the 10 seconds?
The distance traveled by object is 120 m in given time 10 seconds.
What is kinematic equation?If other information is known, a set of four equations called the kinematic equations can be used to predict unknown information about an object's motion.
The equations can be applied to any motion that can be classified as either a constant velocity motion (with an acceleration of 0 m/s/s) or a constant acceleration motion. They are never permitted to be used over any time frame in which the acceleration is changing.
Four variables are present in each of the kinematic equations. The fquations offer a useful method of predicting details about an object's motion.
The kinematic equation for distance is,
[tex]\boxed{\mathrm{ d = (v +v_0) \dfrac{t}{2} }}[/tex]
Where,
[tex]\mathrm{V_0}[/tex] - initial speed = 8 m/s
V - final speed = 16 m/s
t - time = 10 s
Put the values in formula,
[tex]{\mathbf{ {d = (16+9) \dfrac{10}{2} }}[/tex]
[tex]\mathbf{d=120m}[/tex]
Thus, The distance traveled by object is 120 m in given time 10 seconds.
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In an adiabatic process, an ideal gas contracts to a volume that is 1/12
of its initial volume. The initial temperature is 340 K. What is the final temperature? Let y = 1. 67
In an adiabatic process,The initial temperature is 340 K then the final temperature: 95.2K
Adiabatic process :In an adiabatic process, an ideal gas follows the equation P[tex]V^{y}[/tex] = constant, where y is the ratio of the specific heat at constant pressure to the specific heat at constant volume.
Since the initial volume is V1 and the final volume is V2, we can write:
[tex]P_{1} V^{y}[/tex]₁ = P₁[tex]V^{y}[/tex]₂
As the process is adiabatic, no heat is exchanged with the environment, so the internal energy of the gas remains constant.
The internal energy of an ideal gas is , U = 3/2nRT where n is the number of moles, R is the gas constant and T is the temperature in kelvins.
So we can write:
3/2nRT₁ = 3/2nRT₂
As the process is adiabatic, the work done by the gas also remains constant. So the work done on the gas is equal to the work done by the gas.
P( V₂ - V₁) = - P( V₁ - V₂ )
So we can write:
P₁V₁ = P₂V₂
V₂ = V₁/ 12 P₁V₁ = P₂(V₁ /12) T₂
= 340 K × 1/12 ( 1.67 -1 )
= 340 K× ( 1/3.55)
= 95.2 K
Now, combining the above equations we can find the final temperature: 95.2K
What is an ideal gas?An ideal gas is a theoretical gas that is composed of a large number of atoms or molecules that are so small compared to the distance between them, that they do not interact with each other except during rare collisions. The properties of an ideal gas are defined by a set of assumptions that include: The gas is composed of a large number of identical particles (atoms or molecules) that have no volume and no interactions except for instantaneous, elastic collisions.
The gas is considered to be a perfect gas, meaning it follows the ideal gas law: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvins.
The gas is considered to be a diatomic gas, meaning it follows the adiabatic index , y = 1.67
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a 2kg ball is dropped from a height of 3m. what is the velocity of the ball when it hits the ground?
The required velocity of the ball when it hits the ground is calculated to be 7.75 m/s.
Mass of the ball = 2 kg
A ball is dropped from a height = 3 m
Velocity = ?
Initial potential energy of the ball Ep = m g h = (2)(10)(3) = 60 J
As the ball reaches the ground, its potential energy becomes zero as it is entirely converted into its kinetic energy Ek.
So, Ek = 60 J
The formula for Ek is said to be 1/2 m v².
Ek = 1/2 m v²
Making v as subject, we have,
v = √(2 Ek/m) = √(2×60/2) = 7.75 m/s
Thus, the velocity of the ball when it hits the ground is 7.75 m/s.
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suppose that the strength of the electric field about an isolated point charge has a certain value at a distance of 8 m. how will the electric field strength compare at a distance of 16 m from the point charge?
The electric field strength at 16m is weaker than the electric field strength at 8m.
What do you mean by electric field?A charged object creates an electric field, which acts as a force field on other charged things nearby. The size of the charge generating the field and its distance from the charge both affect how strong the electric field is. Lines of force can be used to illustrate electric fields, with the direction of the lines indicating the direction of the field. Many different physical phenomena, such as how electric charges behave and how electric circuits function, can be explained by electric fields.
The electric field strength around a point charge is inversely proportional to the square of the distance from the point charge. Specifically, the electric field strength at a distance of r from a point charge is given by the equation E = kq/r^2, where k is the Coulomb constant, q is the charge of the point, and r is the distance from the point charge.
Therefore, the electric field strength at 16m is (1/2)^2 = 1/4 times the electric field strength at 8m. So the electric field strength at 16m is weaker than the electric field strength at 8m.
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