Answer:
8 J and 2 J
Explanation:
Given that,
Mass of the rubber ball, m = 1 kg
Initial speed of the rubber ball, u = 4 m/s (in east)
Final speed of the rubber ball, v = -2 m/s (in west)
We need to find the kinetic energy of the ball before it hits the wall, the kinetic energy of the ball after it bounces off the wall.
Initial kinetic energy,
[tex]K_i=\dfrac{1}{2}mv^2\\\\K_i=\dfrac{1}{2}\times 1\times (4)^2\\\\K_i=8\ J[/tex]
Final kinetic energy,
[tex]K_f=\dfrac{1}{2}mv^2\\\\K_f=\dfrac{1}{2}\times 1\times (2)^2\\\\K_f=2\ J[/tex]
So, the initial kinetic energy is 8 J and the final kinetic energy is 2 J.
The kinetic energy of the ball after it bounces off the wall is 2.0 Joules.
The kinetic energy of an object is the energy that is in motion or performing work. It can be expressed by using the formula:
[tex]\mathbf{K.E = \dfrac{1}{2}mv^2}[/tex]
The mass of the object(rubber ball) = 1.0 kgThe initial speed of the rubber ball before the collision = 4.0 m/sThe final speed of the rubber ball after the collision = - 2.0 m/sThe Kinetic energy of the ball after the collision and when it bounces off the wall is computed as:
[tex]\mathbf{K.E = \dfrac{1}{2} \times 1 \times 2.0^2}[/tex]
K.E = 2.0 Joules
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IS IT B!! if not pls helpp!
Answer:
I believe you are correct but we just started this unit
Explanation:
which wave carries the highest energy?
Answer:
Gamma rays
Explanation:
How many centimeters are there in 9.3 meters
Answer:
930 centimeters
Explanation:
A piece of glass weights 25 g in air, 16.77g in water at 4C and 16.89g in water at 60C. Find the mean coefficient of cubical expansion of water between 4C anf 60C, taking the coefficient of linear expansion of glass as 8*10^6
sorry i think so i dont exactly know i am sorry
Explanation:
As a certain amount of water is cooled from room temperature until it reaches 4 °C, its volume drops. The density reduces as the volume increases below 4 °C. Therefore, water's greatest density occurs at 4 degrees Celsius.
What coefficient of cubical expansion of water?Water has an unusual trait called anomalous expansion, which causes it to enlarge rather than compress when the temperature drops from 4 °C to 0 °C, and it becomes less dense.
At temperatures not far below zero degrees Celsius, water ice is unique for having low coefficients of static and dynamic friction that range from 0.04-0.02, but as the temperature drops, these numbers rise.
Therefore, When a metal sheet's temperature rises by one degree, its coefficient of area expansion is calculated as the increase in surface area per unit of original surface area.
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A 5.00 kg crate is on a 21.0° hill.
Using X-Y axes tilted down the
plane, what is the y-component
of the weight?
(Unit = N)
Answer:
17.56 N
Explanation:
Given that,
Mass of a crate, m = 5 kg
It is on a 21.0° hill
We need to find the y component of the weight.
y component = mgsinθ
Put all the values,
y-component = 5×9.8×sin(21)
= 49×sin(21)
= 17.56 N
So, the y-component of the weight is 17.56 N.
Answer:
-45.745
Explanation:
it is negative because it is downwards.
The image shows landforms in Monument Valley, Utah.
Which correctly lists the three features shown in the photo?
folds, strike-slip faults, and anticlines
anticlines, synclines, and folds
synclines, normal faults, and strike-slip faults
normal faults, folds, and anticlines
The correctly lists the three features shown in the photo is folds, strike-slip faults, and anticlines.
What is the difference between folds and failures?Modern folds are those that emerged recently (on the scale of geological periods), that is, in the Tertiary Period (between 65 million and 2.5 million years ago). Faults are geological structures that originate from vertical (top-down) or inclined internal forces.
The transcurrent fault – also called horizontal fault – occurs when there is displacement in the horizontal plane between the two blocks, being more common in zones where two tectonic plates meet, when these also move horizontally.
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Answer: folds, strike-slip faults, and anticlines. (A)
Explanation: Got it right on my exam on Edge.
A vector
of magnitude 5 units and another vector ū of magnitude 3 units point in directions
differing by 60°. Find out (a) the scalar product of the two vectors and (b) the vector product of the two vectors
Answer:
7.5 units
13 units
Explanation:
[tex]|v|=5\ \text{units}[/tex]
[tex]|u|=3\ \text{units}[/tex]
[tex]\theta[/tex] = Angle between the vectors = [tex]60^{\circ}[/tex]
Scalar product is given by
[tex]u\cdot v=|u||v|\cos\theta\\ =3\cdot 5\cdot \cos60^{\circ}\\ =7.5\ \text{units}[/tex]
The scalar product of the vectors is 7.5 units.
Vector product is given by
[tex]u\times v=|u||v|\sin\theta\\ =3\times 5\sin60^{\circ}\\ =13\ \text{units}[/tex]
The vector product of the vectors is 13 units.
Margaret Mary, Doug , and Kako are at a local amusement park. They see an attraction called the Giant Slide, which is simply a very long and high inclined plane. Visitors at the amusement park climb a long flight of stairs to the top of the 27inclined plane and are given canvas sacks. They sit on the sacks and slide down the plane 70m long. At the time when the three friends walked past the slide, a 135-kg man and a 20-kg boy are each at the top preparing to slide down. "I wonder how much less time it will take the man to slide down than it will take the boy," said Margaret Mary. "I think the boy will take less time," said Doug. "You're both wrong,"said Kako. "They will reach the bottom at the same time."
The question is incomplete. The compete question is :
Margaret Mary, Doug , and Kako are at a local amusement park. They see an attraction called the Giant Slide, which is simply a very long and high inclined plane. Visitors at the amusement park climb a long flight of stairs to the top of the 27inclined plane and are given canvas sacks. They sit on the sacks and slide down the plane 70m long. At the time when the three friends walked past the slide, a 135-kg man and a 20-kg boy are each at the top preparing to slide down. "I wonder how much less time it will take the man to slide down than it will take the boy," said Margaret Mary. "I think the boy will take less time," said Doug. "You're both wrong,"said Kako. "They will reach the bottom at the same time."
If the man and the boy do not take the same amount of time to reach the bottom of the slide, calculate how many seconds of difference there will between the two times.
Solution :
From body sliding down an incline plane, the acceleration is given by, [tex]$a = g \sin \theta$[/tex]
Since the body slides from rest, the initial velocity is, u = 0
Now the equation of motion, we have
v= u + at
or v = 0 +at
or v = at
or [tex]$t=\frac{v}{a}$[/tex] ............(1)
again we have, [tex]$v^2 -u^2 =2as $[/tex]
or [tex]$v = \sqrt{2s g \sin \theta} $[/tex]
Then from equation (1), we have
[tex]$t=\frac{\sqrt{2sg \sin \theta}}{g \sin \theta}$[/tex]
Thus this means that the time of sliding down an inclined plane does not depend on the mass of the body that slides.
Therefore, Kako is correct.
Since the time taken to slide an inclined plane is same for both the man and the boy, there is no difference between their time of sliding.
Which of these would be the most efficient means to transmit light pulses over long distances?
Answer: It’s fiber optics so B
4) Which is the BEST description of a tectonic plate? *
O A. Tectonic plates consist of the lithosphere and part of the asthenosphere.
O B.Tectonic plates are large pieces of mesosphere that never move.
C. Tectonic plates are large pieces of lithosphere that move on tope of the
asthenosphere.
O D. None of these answers is correct.
Answer:
The answer is A
Explanation: i took k12
whats the result of rounding 52.8015 into five significant figures
Answer:
52.802
Explanation:
"Significant figures" in Mathematics refer to the digits that give accuracy to the value of a measurement. There are specific rules when it comes to determining the significant figures. For example, all non-zero digits are considered significant and zeroes located in-between non-zero numbers are significant. In the number given above, the digit "0" is located between "8" and "1," therefore, it is significant. All the digits above are significant.
The problem is only asking for "five" significant figures. We can do this by counting from the left to the right. By this means, we know that the number will be rounded off to the nearest thousandths, which is "1." The number after 1 is 5, which means that 1 digit will be added to number 1, thus, making the digit into "2." The last digit (5) will then be removed.
Explanation:
five significant of 52.8015=52.801 ..
In water, sound travels 1500 m/s. A whale sings at a frequency of 17 Hz. What will be the length of the sound wave?
Answer:
A 20 Hz sound wave is 75 m long in the water (1500/20 = 75) whereas a 20 Hz sound wave in air is only 17 m long (340/20 = 17) in air. As we descend below the surface of the sea, the speed of sound decreases with decreasing temperature.
2. A uniform rod of weight 5N and length 1m is pivoted at a point 20cm from one of its ends. A weight is hung from the other end so that the rod balances horizontally. What is the value of the weight?
Answer:
The weight is 7.5 N
Explanation:
Since the rod is uniform, its weight applies downwards at its middle (i.e 50 cm mark). The diagram attached to this answer shows the appropriate sketch.
Applying the principle of moment to the question, let the weight by represented by W.
Total clockwise moment = Total counterclockwise moment
[tex]F_{1}[/tex] x [tex]d_{1}[/tex] = [tex]F_{2}[/tex] x [tex]d_{2}[/tex]
5 x 0.3 = W x 0.2
1.5 = 0.2 W
W = [tex]\frac{1.5}{0.2}[/tex]
= 7.5 N
The value of the weight is 7.5 N.
[04.04] Which best describes the current atomic theory?
If a 1000 kg car is traveling at 3
meters per second, what is its
kinetic energy?
6. A hockey player skates ten meters to the goal.
What term is used to describe the hockey
player's process of changing position?
Answer:
Displacement
Explanation:
Displacement is a term used to represent change in position.
Which of the following statements is TRUE concerning forces?
A. Forces in the same direction are added together
B. Forces in the opposite direction are subtracted from one another
C. An overall net force must be present in order for movement to occur
D. All of the above
10 POINTS QUESTION: Why both are models for monomers, polymers, and cross-linked polymers
Answer:
Because both monomers and polymers and cross linked polymers are mers with physically properties which is good for applycations
Explanation:
because they are good for using and not using
also, this is a 5 point question, you are not fooling anyone. thx for 5 points tho
What does an electromaget do
Answer:
An electromagnet is a magnet that runs on electricity. Unlike a permanent magnet, the strength of an electromagnet can easily be changed by changing the amount of electric current that flows through it. The poles of an electromagnet can even be reversed by reversing the flow of electricity.
if a 2kg ball has and initial velocity of
4 m/s and is kicked and accelerated to
10 m/s in one second, what is the force that was applied to the ball? Rember that acceleration is the change in velocity/ change in time
please help me asap
Answer:
[tex]\boxed {\boxed {\sf 12 \ Newtons }}[/tex]
Explanation:
Force is equal to the product of mass and acceleration.
[tex]F=m*a[/tex]
We know the mass, but not the acceleration. Therefore, we must calculate it before we can calculate force.
1. Calculate Acceleration
Acceleration is the change in velocity over the change in time.
[tex]a=\frac{V_f-V_i}{t}[/tex]
The final velocity is 10 meters per second and the initial velocity is 4 meters per second. The time is 1 second.
[tex]V_f=10 \ m/s \\V_i= 4 \ m/s \\t= 1 \ s[/tex]
Substitute the values into the formula.
[tex]a=\frac{10 \ m/s-4 \ m/s }{1 \ s}[/tex]
Solve the numerator.
[tex]a=\frac{6 \ m/s}{1 \ s }[/tex]
Divide.
[tex]a= 6 \ m/s/s=6 \ m/s^2[/tex]
2. Calculate Force
Now we know the acceleration and the mass.
[tex]m= 2 \ kg \\a= 6 \ m/s^2[/tex]
Substitute the values into the fore formula.
[tex]F= 2 \ kg * 6 \ m/s^2[/tex]
Multiply.
[tex]F= 12 \ kg*m/s^2[/tex]
1 kilogram meter per square second is equal to 1 Newton. Our answer of 12 kg*m/s² is equal to 12 Newtons[tex]F= 12 \ N[/tex]
The force applies to the ball was 12 Newtons.
a cellphone weighing 80 g is flying to the air at 15 m/s what is it's kinetic energy
Answer:
9J
Explanation:
Given parameters:
Mass of cell phone = 80g
1000g = 1kg
80g is therefore 0.08kg
Velocity of the cellphone = 15m/s
Unknown:
Kinetic energy of the cellphone = ?
Solution:
The kinetic energy of a body is the energy due to its motion.
It is expressed as:
K.E = [tex]\frac{1}{2}[/tex] mv² = [tex]\frac{1}{2}[/tex] x 0.08 x 15² = 9J
A squirrel runs at a speed of 9.9 m, with 25 J of kinetic energy. What is the squirrel’s mass?
Answer:
The mass of the squirrel is 0.51kg
A squirrel runs at a speed of 9.9 m/s with 25 J of kinetic energy.
What is the squirrel’s mass?
Answer: 0.51 kg
Four velcro-lined air-hockey disks collide with each other in a perfectly
inelastic collision. The first disk has a mass of 50.0 g and a velocity of
0.80 m/s to the west, the second disk has a mass of 60.0 g and a velocity of
2.50 m/s to the north, the third disk has a mass of 100.0 g and a velocity of
0.20 m/s to the east, and the fourth disk has a mass of 40.0 g and a
velocity of 0.50 m/s to the south. What is the final velocity of the disks
after the collision?
Answer:
The magnitude of the final velocity is approximately 0.526 m/s in approximately the direction of 8.746° East of South
Explanation:
The given collision parameters are;
The kind of collision experienced by the four velcro-lined air-hockey disk = Inelastic collision
The mass of the first disk, m₁ = 50.0 g
The velocity of the first disk, v₁ = 0.80 m/s West = -0.8·i
The mass of the second disk, m₂ = 60.0 g
The velocity of the second disk, v₂ = 2.50 m/s North = 2.5·j
The mass of the third disk, m₃ = 100.0 g
The velocity of the third disk, v₃ = 0.20 m/s East = 0.20·i
The mass of the fourth disk, m₄ = 40.0 g
The velocity of the fourth disk, v₄ = 0.50 m/s South = -0.50·j
Therefore, the total initial momentum of the four velcro-lined air-hockey disk, [tex]\Sigma P_{initial}[/tex] is given as follows;
[tex]\Sigma P_{initial}[/tex] = m₁·v₁ + m₂·v₂ + m₃·v₃ + m₄·v₄ = 50.0×(-0.80·i) + 60.0×(2.50·j) + 100 × (0.20·i) + 40.0 × (-0.50·j)
∴ [tex]\Sigma P_{initial}[/tex] = -40·i + 150·j + 20·i - 20·j = -20·i + 130·j
∴ [tex]\Sigma P_{initial}[/tex] = -20·i + 130·j
By the law of conservation of linear momentum, we have;
[tex]\Sigma P_{initial} = \Sigma P _{final}[/tex] = -20·i + 130·j
Therefore, given that the collision is perfectly inelastic, the disks move as one after the collision and the four masses are added to form one mass, "m", m = m₁ + m₂ + m₃ + m₄ = 50.0 + 60.0 + 100.0 + 40.0 = 250.0
∴ m = 250.0 g
Let, "v" represent the final velocity of the four disks moving as one after the collision
We have;
[tex]\Sigma P _{final}[/tex] = m × v = 250.0 × v = -20·i + 130·j
∴ v = -20·i/250 + 130·j/250 = -0.08·i + 0.52·j
The final velocity of the four disks after collision, v = -0.08·i + 0.52·j
The magnitude of the final velocity, [tex]\left | v \right |[/tex] = √((-0.08)² + (0.52)²) ≈ 0.526
[tex]\left | v \right |[/tex] ≈ 0.526 m/s
The direction of the final velocity, θ = arctan(0.52/(-0.08)) ≈ -81.254°
The direction of the final velocity, θ ≈ -81.254° which is 8.746° East of South
Jackson throws a football 30 meters at a speed of 15 m/s. How long was the football in the air before Laurence caught it for touchdown
Answer:
2s
Explanation:
Given parameters:
Distance = 30m
Speed = 15m/s
Unknown:
Time before Laurence caught it = ?
Solution:
To solve this problem;
Speed = [tex]\frac{disance }{time}[/tex]
Time taken = [tex]\frac{distance }{speed }[/tex] = [tex]\frac{30}{15}[/tex] = 2s
The time it takes is 2s
Given:
30 metersSpeed of 15 m/sWe will solve:
Speed = [tex]\frac{distance}{time}[/tex]
Time taken = [tex]\frac{distance}{time}[/tex] = [tex]\frac{30m}{15m/s}[/tex] = 2s
The time it takes is 2s
A student is leaving the lesson and walking to Maths at a speed of 1m/s. He notices that he is late for the lesson and speeds up to 3 m/s. It takes him 4 seconds to speed up. Calculate his acceleration.
Answer:
Acceleration = 0.5 m/s²
Explanation:
Given the following data;
Initial velocity, u = 1m/s
Final velocity, v = 3m/s
Time, t = 4 seconds
To find acceleration;
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
[tex]a = \frac{v - u}{t}[/tex]
Substituting into the equation, we have;
Acceleration = (3 - 1)/4
Acceleration = 2/4
Acceleration = 0.5 m/s²
Which type of matter is likely to absorb the most sound waves? A. Metal door B. Loudspeaker C. Hot air O D. Foam wall
Answer:
its either A or D
Explanation:
They use foam walls in like asylums but in the movies all the bad guys say "They can't hear you the metal is too thick" so its either one of those, hope it helped
Sound absorbing foams are typically softer and more lightweight than their sound blocking counterparts. This open and flexible cell structure acts as a natural soundwave absorber and prevents noises from reverberating off hard surfaces like walls, floors and ceilings.
What are sound waves ?"A sound wave is the pattern of disturbance caused by the movement of energy traveling through a medium (such as air, water, or any other liquid or solid matter) as it propagates away from the source of the sound. The source is some object that causes a vibration, such as a ringing telephone, or a person's vocal chords."
What is sound ?"Sound is a vibration that propagates as an acoustic wave, through a transmission medium such as a gas, liquid or solid. In human physiology and psychology, sound is the reception of such waves and their perception by the brain."
What is noise ?Sound is defined as vibrations that travel through air or another medium that can be heard when they reach a person's or animal's ears. Noise is defined as unwanted sound. In engineering, noise has the additional connotation of signals varying over time without meaning, whereas sound connotes meaningful signals.
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Guidewords for the word “serpent” may be
a.
Serbia and service
c.
Seltzer and Saturday
b.
Seattle and section
d.
Solitude and second
THE CORRECT ONE IS A!!!!!!!!
Answer:
A. Serbia and service
Explanation:
A guide word is a word written on top of a page to indicate the first or last word entry on that page. For example in a dictionary, they indicate the alphabetical first and last words on the page.
In this example; the word ' serpent ' note the first three letters to guide you in the words that are on that page;
In this case : Serbia and Service.
A vertical spring with a force constant of 26 N/m has a relaxed length of 35 cm. A 200 g mass is then
attached to the end of the spring and is allowed to come to rest. (a) Find the length of the stretched spring.
(b) How much elastic potential energy is stored in the spring?
I just need the work please the answers is
(a) 45.2 J
(b) 0.0739
Answer:
(a) The length of the stretched string is approximately 42.53846 cm
(b) The elastic potential energy stored in the string is approximately 0.073877 Joules
Explanation:
(a) The given parameter are;
The force constant of the vertical spring, k = 26 N/m
The relaxed length of the spring, L = 35 cm = 0.35 m
The mass attached to the end of the spring, m = 200 g = 0.2 kg
By Hooke's law, we have;
F = k·x
Where;
F = The applied force on the sting = The weight of the attached mass, W
∴ F = W
The weight of the attached mass, W = m × g
Where;
g = The acceleration due to gravity ≈ 9.8 m/s²
Therefore, F = W = 0.2 kg × 9.8 m/s² = 1.96 N
From Hooke's law, we have;
x = F/k = 1.96 N/(26 N/m) ≈ 0.0753846 m
The extension of the stretched spring, x ≈ 0.0753846 m
The length of the stretched string, L[tex]_{stretched}[/tex] = L + x
∴ L[tex]_{stretched}[/tex] ≈ 0.35 m + 0.0753846 m ≈ 0.4253846 m
0.4253846 m = 42.53846 cm
The length of the stretched string ≈ 42.53846 cm
(b) The elastic potential energy stored in the string, U = 1/2·k·x²
By substituting the known values, we get;
U = 1/2 × 26 N/m × (0.0753849 m)² ≈ 0.073877 Joules
4. A toy car travels 60 m during 5.7 s at a constant speed. What is the speed of the toy car?
15.556
13.526
6.116
10.526
None of these is correct.
Answer: 10.526m/s
Explanation:
The speed of the toy car would be calculated as the distance travelled by the toy card divided by the time taken. This will be:
= Distance travelled / Time taken
= 60/5.7
= 10.526m/s
The speed of the toy car is 10.526 meters per second.
Body Systems Directly Involved (Give at Least 2)
Cartoon
13. Ouch! You step on a tack and jump away without even thinking. Then you decide to pick up the tack and place it back in a desk drawer.
I need the second one the nervous system and...
Answer:
Nervous system and immune system
Explanation:
The nervous system is involved because you immediately jumped away, that ur brain and nerves initiating the fight or flight response. The immune system is involved because the tack most likely pierced your skin, so your immune system needs to work to make sure the wound does not get infected.