Answer:
c
Explanation:
What should you do with electrical cells and batteries that no longer work
Answer:
Yes, single-use batteries are now made of common metals deemed non-hazardous by the federal government and can be disposed of in your regular trash in all states except California, where it is illegal to throw away all types of batteries.
An object moving in a straight line has a velocity v in m/s that varies with time t in s according the following function. v= 8+2.5 12 to 11. The instantaneous acceleration of the object at t = 2 sis (A) 2 m/s (B) 4 m/s (0) 6 m/s2 D) 8 m/s2 (E) 10 m/s2 12. The displacement of the object between t = 0 and t = 6 s is (A) 120 m (B) 180 m (C) 228 m (D) 242 m (E) 260 m
The instant acceleration of the object is 10 m/s² and the displacement of the object is 228 m.
Instantaneous acceleration
The instant acceleration of the object is determined by taking the derivative of the velocity as follows;
v = 8 + 2.5t²
a = dv/dt
a = 5t
a(2) = 5(2)
a(2) = 10 m/s²
Displacement of objectThe displacement of the object is determined by taking the integral of velocity as follows;
v = 8 + 2.5t²
x = ∫v
x = 8t + 2.5t³/3
x(0) = 0
x(6) = 8(6) + 2.5(6)³/3
x(6) = 228 m
Thus, the displacement of the object is 228 m.
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explain the fleming left-hand rule with the diagram and what will the direction of the induced current in the figure if the magnet is going towards the coil.
the dimensions of a cuboidal block are 2.5 m * 2m * 1.2m its weight 900 n what is the minimum presseure exerted by the block on the surface of its support.?
Answer:
your answer is here 180
Explanation:
900/2.5 * 2 = 180
Answer:
The answer is 180 Pa.
Explanation:
Given;Here, weight = thrust = 900 N,
dimensions are 2.5 m × 2 m × 1.2 m
To Find;Pressure exerted by the block on the surface of its support.Formula;Pressure = Thrust ÷ AreaWe know that, Pressure is inversely proportional to area. For the minimum pressure the area must be more.
So, if the block is resting with 2.5 m × 2 m surface on the support, the pressure will be minimum.
Pressure = 900 N ÷ 2.5 × 2.0 m² = 180 Pa
Thus, The pressure exerted by the block on the support is 180 Pa.
A wave has a frequency of 5hz and a wave speed of 25m/s what is the wavelength?
25 m
5 m
25 m/s
125 m
1. Discuss the two ways by which volcanoes are formed.
2. Does the theory of plate tectonics answer the question on why volcanoes erupt? Support your answer.
3. What are mantle plumes and where are they usually found?
4. What are the gases released by volcanoes in smaller amounts?
5. Extinct volcanoes may be classified as inactive volcanoes but this doest not mean they will not erupt again. Explain this statement.
Answer:
1.Divergent boundaries (crust moves apart, magma fills in) Convergent boundaries (magma fills when one plate goes beneath another) Hot spots (a large magma plume rises from mantle)
2.Some mountains are made of solid rock, like the Rocky Mountains or the Swiss Alps. But, some mountains are actually volcanoes.
3.an area under the rocky outer layer of Earth, called the crust, where magma is hotter than surrounding magma.
4.hydrogen sulfide, carbon monoxide, hydrogen chloride, hydrogen fluoride, and other minor gas species.
5.Extinct volcanoes are not expected to erupt in the future. Inside an active volcano is a chamber in which molten rock, called magma, collects. Pressure builds up inside the magma chamber, causing the magma to move through channels in the rock and escape onto the planet's surface.
Explanation:
hope its help:)
A box weighing 8 newtons requires a force of 2 newtons to push it along the floor. The coefficient or friction Berween the box and the floor is_?
I believe the answer is 16.
Have a blessed day!
Calculate the speed of sound in a string that has a tension of 100 N and a linear mass density of 0.0001 kg/m
What is maxwell’s theory about atoms?
Answer:
it states that the atom will rest confortably in the ground state and will not collapse for lack of energy
Can someone help with this
Hi there!
A.
We can use the work-energy theorem to solve.
Initially, both blocks have gravitational potential energy, which is then converted to kinetic energy.
Recall:
[tex]U = mgh \\[/tex]
U = Potential Energy (J)
m = mass (kg)
g = acceleration due to gravity (m/s²)
h = height (m)
And at the end, block 2 has both kinetic and potential energy. Kinetic is defined as:
[tex]KE = \frac{1}{2}mv^2[/tex]
v = velocity (m/s)
We can do a summation of initial and final forces.
Initial:
[tex]E_i = m_2g\frac{h}{2} + m_1gh[/tex]
Final:
[tex]E_f = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2[/tex]
Set the two equal (no energy loss in this situation) and solve for velocity.
[tex]m_2g\frac{h}{2} + m_1gh = \frac{1}{2}m_2 v^2 + m_2g\frac{3h}{2} + \frac{1}{2}m_1 v^2\\\\m_2g\frac{h}{2} + m_1gh - m_2g\frac{3h}{2} = \frac{1}{2}m_2 v^2 + \frac{1}{2}m_1 v^2\\\\v^2 = \frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}\\\\v = \sqrt{\frac{gh(\frac{m_2}{2} + m_1 - \frac{3m_2}{2})}{\frac{1}{2}m_2 + \frac{1}{2}m_1}}\\\\v = \boxed{3.704 \frac{m}{s}}[/tex]
**This can be solved in a simpler way using a summation of forces.
B.
Now, we can do a summation of forces to solve. First, we must solve for the acceleration of the system now that we have found the velocity. Use the kinematic equation:
[tex]v_f^2 = v_i^2 + 2ad[/tex]
Initial velocity is 0 m/s, so:
[tex]v_f^2 = 2ad\\\\a = \frac{v_f^2}{2d} = \frac{(3.704^2)}{2(2.10)} = 3.267 \frac{m}{s^2}[/tex]
Now, we can use a summation of forces for any block. We can do block 1:
[tex]\Sigma F = m_1g - T[/tex]
Using Newton's Second Law:
[tex]m_1a = m_1g - T\\\\T = m_1g - m_1a \\T = m_1 (g - a) = 4.10(9.8 - 3.267) = \boxed{26.828 N}[/tex]
You are pushing a 30 crate along a rough surface by applying a horizontal force. The coefficients of
frictions between the surface and the crate are 0.3 and 0.6. Sketch the situation and create a Free Body diagram
from it, then Calculate:
a. The normal force on the crate by the floor.
b. The force required to get the crate to move.
c. Determine the kinetic friction force that the floor applies on the object.
d. Determine the acceleration of the crate.
Answer:
ill say math too!
Explanation:
A fish uses its tail fin to push against the water. The water is pushed backward, in the fish is pushed for it. Is it Newton's first law of motion, Newton's second law of motion, or Newton's third law of motion?
Answer:
it is Newton's third law of motion?
Hope This Helps
curd is made from milk... t or f
Explanation:
Curd is made from milk . ( True )
Curd is made by bacterial fermentation of milk.
Answer:
very true
curd is made from warm milk and a bacterial youghurt starter and it aslo has been used for many years
pleaseee pretty please put me as brainliest
In a circuit, we are using conducting wires made from Manganese.
(i) If we assume there are 3 free electrons per an atom of manganese, what is its
electron density?
(ii) How much current flows through a cylindrical manganese wire of volume 27 cm3,
length 3cm if the circuit is switched on for 5 seconds?
i. The electron density of maganese is 2.44 × 10²⁸ electrons/m³
ii. The current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA
To solve the question, we need to know what electron density is.
What is electron density?This is the number of free electrons per unit volume of material.
To find electron density, we need to find the atom density which is the number of atoms per unit volume, n.
Atom density of manganeseSo, the atom density of manganese is n = Nρ/A where
N = avogadro's number = 6.022 × 10²³ atoms/mol, ρ = density of manganese = 7430 kg/m³ and A = atomic mass of manganese = 0.0594 kg/molSo, n = Nρ/A
n = 6.022 × 10²³ atoms/mol × 7430 kg/m³/0.05494 kg/mol
n = 44743.46 × 10²³ atoms/mol × kg/m³/0.05494 kg/mol
n = 81440.59 × 10²³ atoms/m³
n = 8.144059 × 10²⁷ atoms/m³
n ≅ 8.14 × 10²⁷ atoms/m³
i. Electron density of manganese
The electron density of maganese is 2.44 × 10²⁸ electrons/m³
So, the electron density of manganese n' = n" × n where
n" = number of free electrons per atom = 3 and n = atom density = 8.14 × 10²⁷ atoms/m³So, n' = n" × n
= 3 electrons per atom × 8.14 × 10²⁷ atoms/m³
= 24.42 × 10²⁷ electrons/m³
= 2.442 × 10²⁸ electrons/m³
≅ 2.44 × 10²⁸ electrons/m³
So, the electron density of maganese is 2.44 × 10²⁸ electrons/m³
ii. How much current flows through the cylindrical maganese wire?
The current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA
The current flowing through the wire is given by i = n'eV/t where
n = electron density = 2.44 × 10²⁸ electrons/m³, e = electron charge = 1.602 × 10⁻¹⁹ C, V = volume of wire = 27 cm³ = 27 × 10⁻⁶ m³ and t = time current flows = 5 sSo, substituting the values of the variables into the equation, we have
i = n'eV/t
i = 2.44 × 10²⁸ electrons/m³ × 1.602 × 10⁻¹⁹ C × 27 × 10⁻⁶ m³/5 s
i = 105.54 × 10³ C/5 s
i = 21.11 × 10³ C/s
i = 21.11 × 10³ A
i = 21.11 kA
So, the current that flows through a cylindrical manganese wire of volume 27 cm3 is 21.11 kA
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What is electrical power and how is it measured?
Answer:
power is measured in watts and its the messure of work over time.
Explanation:
In a ______ wave, particles
the medium move perpendicular
to the direction of the wave.
Answer:
Transverse wave
Explanation:
I hope this helps you! :)
If a→=3i^-2j^-k^ and b→=i^+4j^+k^, find a unit vector n^ normal to the plane containing a→ and b→ such that a→, b→ and n^, in this order, form a right-handed system.
The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
Given data :
The unit vectors
a→=3i^-2j^-k^ and b→=i^+4j^+k^
Determine the unit vector normal to the planeThe unit vector normal to the plane is calculated as
n = [tex]\frac{a*b}{|b*b|}[/tex] ---- ( 1 )
where ; a→ * b→ = 2i - 4j + 14k and |b * b| = [tex]\sqrt{216}[/tex]
back to equation ( 1 )
n = ( 2i - 4j + 14k ) / [tex]\sqrt{216}[/tex]
= [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
Hence we can conclude that The unit vector normal to the plane is ; n = [tex]\frac{i}{\sqrt[3]{6} } - \frac{2j}{\sqrt[3]{6} } + \frac{7k}{\sqrt[3]{6} }[/tex]
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9- How many protons, electrons, and neutrons does an atom with atomic number
50 and mass number 125 contain? *
O A) 50 protons, 50 electrons, 75 neutrons
B) 75 electrons, 50 protons, 50 neutrons
C) 120 neutrons, 50 protons, 75 electrons
D) 70 neutrons, 75 protons, 50 electrons
Answer:
A
Explanation:
the atomic number means the number of protons so there are 50 protons
the number of positive charges (protons) should equal the number of negative charges (electrons) so there should be 50 electrons
the mass number = neutrons number + protons number
and we knew already that we have 50 protons so the number of neutrons is 125-50=75 neutrons
What is the gravitational potential energy of a 2100 kg car at the top of an 18 m parking garage?
[tex]\qquad\qquad\huge\underline{{\sf Answer}}♨[/tex]
Gravitational Potential of an object with mass m, and height of h metre is :
[tex]\qquad \sf \dashrightarrow \:mgh[/tex]
Now, if the mass of object is 2100 kg, height of 18 m is placed in there, then it's gravitational potential energy is ~
[tex]\qquad \sf \dashrightarrow \:2100 \times 10 \times 18[/tex]
[tex]\qquad \sf \dashrightarrow \:378000 \: \: joules[/tex]
[tex]\qquad \sf \dashrightarrow \:3.78 \times 10 {}^{5} \: \: joules[/tex]
7. A steel band exerts a horizontal force of 80.0 N on a tooth
at point B in Figure 7.3. What is the torque on the root of
the tooth about point A?
Gum
48.0°
A
F
1.20 cm
The torque experienced by the root of the tooth about point A when the steel band exerts the given force is 0.713 Nm.
Torque about point AThe torque experienced by the root of the tooth about point A is calculated as follows;
τ = rFsinθ
where;
F is applied forcer is the perpendicular distanceτ = (0.012) x (80) x (sin 48)
τ = 0.713 Nm
Thus, the torque experienced by the root of the tooth about point A when the steel band exerts the given force is 0.713 Nm.
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A car of mass 1200kg falls a vertical distance of 24m starting from rest what is the workdone by the force of gravity on the car?Use the work energy theorem to find the final velocity of the car just before it hits the water(Treat the as a point like object)
Answer:
PE (relative to water) = M g h
PE = 1200 kg * 9.8 m/s^2 * 24 m = 2.82E5 Joules
KE = PE when vehicle strikes water
1/2 M V^2 = 2.82E5
V = (2.82E5 * 2 / 1200)^1/2 = 21.7 m/s
Check:
M g h = 1/2 M V^2
V = (2 g h)^1/2 = (2 * 9.8 * 24)^1/2 = 21.7 m/s
By what percent is the torque of a motor decreased if its permanent magnets lose 6.5 % of their strength
1. A person walks 20 meters toward the east and then walks 30 meters toward the west. What is the total distance covered? What is the displacement? with explaination
2. What is the average speed of a car that travels 2000 meters in 5 minutes in meters/second? with explaination
Answer:
1.) 30 m is the total distance covered 10m is the displacement you
2.)24,000m/h (24km/h or 6.67m/s) Average speed is calculated by dividing the total distance that something has traveled by the total amount of time it took it to travel that distance
Explanation:
A heat engine exhausts 6000 J of heat while performing 2000 J of useful work.
Determine the efficiency of the engine
Answer:
Explanation:
The efficiency can be calculated by:
[tex]\eta = \frac{Q_{E}-Q_{W}}{Q_{E}}=\frac{6000-2000}{6000}=\frac{2}{3}[/tex]
or we can say it becomes approximately 66.7%
What is the kinetic energy of a 1375 kg car that travels at 8.5 m/s
Answer:
49671.875
Explanation:
KE = [tex]\frac{1}{2}m[/tex][tex]v^{2}[/tex]
KE = 0.5(1375)(8.5)
= 49671.875 J
A dragster's top acceleration is 60 m/s.
If it accelerates for 3 seconds from the
starting line, how fast will it be going?
Answer:
very fast
Explanation:
list three things that spectra can tell us about objects in space
Answer:
The temperature, the density, and the element of stars.
Explanation:
The spectral line also can tell us about any magnetic field of the star. The width of the line can tell us how fast the material is moving. We can learn about winds in stars from this.
Two blocks are connected to identical ideal springs and are oscillating on a horizontal frictionless surface. Block A has mass m, and its motion is represented by the graph of position as a function of time shown above on the left. Block B’s motion is represented above on the right. Which of the following statements comparing
block B to block A is correct?
(A) Because block B covers more distance per cycle than block A, block B takes more time to complete each
cycle.
(B) Because the spring attached to block B is initially stretched a greater distance, the spring constant is smaller
and therefore block B has a slower average speed than block A does.
(C) Because block B has more mass, it has a slower average speed than block A does.
(D) Because block B has more mass, its acceleration is smaller than that of block A at any given displacement
from the equilibrium position.
Hi there!
We can begin by identifying key characteristics of both graphs.
Graph A.
Looking at the graph, we can see that the maximum distance (amplitude) is 10 cm (0.1 m). Additionally, its period (T) is 2 seconds (one full cycle).
We also know that:
[tex]T = 2\pi \sqrt{\frac{m}{k}}[/tex]
We can use this equation to compare with the other graph. Notice how the period does NOT depend on how far the spring is stretched. We can eliminate choice A for this reason.
Graph B.
The amplitude is 20 cm (0.2 m), and each period is 4 seconds.
We can now eliminate choice B because the springs are identical, so their spring constants are equal. Distance stretched has no impact on the spring constant.
For the other choices, we must look at forces and work.
Recall that:
Spring potential energy = [tex]\frac{1}{2}kx^2[/tex]
Kinetic energy = [tex]\frac{1}{2}mv^2[/tex]
Using the work-energy theorem:
[tex]\frac{1}{2}kx^2 = \frac{1}{2}mv^2[/tex]
Even if the mass of Block B is greater, its displacement is larger than that of Block A. Since displacement is squared in this equation, it would have a greater effect on the speed. Thus, Choice C is incorrect.
Using Hooke's Law:
[tex]\Sigma F = -kx\\\\ma = -kx\\[/tex]
[tex]a = \frac{-kx}{m}[/tex]
If the mass is greater, the acceleration will be smaller. Choice D is correct.
4. The 50-kg crate shown in Fig. rests on a horizontal surface for which the coefficient of
kinetic friction is u - 0.3. If the crate is subjected to a 400-N towing force as shown,
determine the acceleration of the crate.
your
P = 400 N
490.5 N
400 N
too
30
30°
+
F-0.3 Nc
Nc
ΣΕ = max
Σ F, = may
A. a = 4. 185 m/s2
B. a = 5. 185 m/s2
C. a = 6. 185 m/s2
D. The entire above are false
Answer:
5.057 m/s^2
Explanation:
Force of kinetic friction = .3 = F /normal force
.3 = F /(50* 9.81) F of friction = 147.15
Net force = 400 - 147.5 = 252.85 N
F = m * a
252.85 = 50 * a a = 5.057 m/s^2
Striking a match stick on the matchbox involves the reaction of potassium chlorate and red phosphorus with the following equation: 10 KCIO3 (s) + 3P4 (s) → 3P4O10 (s) + 10 KCI (s) How much of each reactant will be needed to produce 105.8 g of tetraphosphorus decaoxide (P4O10)?
Answer:
m(P4) = 46.175 (grams)
m (KClO3) = 149 (grams)
Explanation:
1) n(P4) = n(P4O10);
m(P4)/M(P4) = m(P4O10)/M(P4O10);
m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)
2) Analogously, 10n(P4O10) = 3n(KClO3)
m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).
149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .
What do you mean by reactant?In a chemical equation, the substance or substances to the left of the arrow are referred to as reactants. A substance that is present when a chemical reaction first begins is known as a reactant.
Products refer to the material or substances to the right of the arrow. A substance that is present after a chemical reaction is complete is called a product.
Given Data:
m(P4) = 46.175 (grams)
m (KClO3) = 149 (grams)
Then it is given by:
1) n(P4) = n(P4O10);
m(P4)/M(P4) = m(P4O10)/M(P4O10);
The equation becomes :
m(P4) = M(P4)*m(P4O10)/M(P4O10)
= 123.90*105.8/283.89
= 46.175 (grams)
2) Analogously, 10n(P4O10) = 3n(KClO3)
m (KClO3) = 10M(KClO3)*m(P4O10)/3M(P4O10)
= 10*122.55*105.8/283.89/3
= 149 (grams).
Thus, 149 gm of each reactant is needed to produce 105.8 gm of tetra phosphorous decaoxide .
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