The final speed of the combined masses is 0.21 m/s
Applying the law of conservation of momentum:
Total momentum before collision = Total momentum after collision.
⇒ Formula:
MU+mu = V(M+m).................. Equation 1
⇒ Where:
M = mass of the first bodym = mass of the second bodyU = Initial speed of the first bodyu = Initial speed of the second bodyV = common final speed.From the question,
⇒ Given:
M = 0.24 kgU = 0.60 m/sm = 0.26 kgu = -0.20 m/s (traveling in opposite direction)⇒ Substitute these values into equation 1
0.24(0.6)+0.26(-0.20) = V(0.24+0.2)⇒ Solve for V
0.144-0.052 = 0.44V0.44V = 0.092V = 0.092/0.44V = 0.209V ≈ 0.21 m/sHence the final speed of the combined masses is 0.21 m/s
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What are the three different social perspectives on sport
Answer:
functionalist theory,feminist theory. discipline of sociology
2.
A swimmer swims 1 m/s due north against a current of 3 m/s due south. What is the resultant velocity of
the boat?
The resultant velocity of the boat is equal to 2 m/s due south.
Given the following data:
Swimmer's speed = 1 m/s due northOcean current speed = 3 m/s due south.To determine the resultant velocity of the boat:
Resultant velocity can be defined as the sum (addition) of each of the vector velocity acting on a physical or an object. Thus, it is simply a combination of two or more single vector velocity.
Note: When the velocities are acting in the same direction, you will add them up while you will subtract when the velocities are acting in opposite directions.
In this scenario, the velocities are acting in opposite directions. Thus, we would subtract as follows:
[tex]V = 3 - 1[/tex]
V = 2 m/s due south.
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according to newton, doubling the distance between two interacting objects:
Answer:
So as two objects are separated from each other, the force of gravitational attraction between them also decreases. If the separation distance between two objects is doubled (increased by a factor of 2), then the force of gravitational attraction is decreased by a factor of 4 (2 raised to the second power).
Explanation:
hope his helps
A 50 kg driver of a car is traveling at 35 m/s when she hits a large deer. She strikes the air bag/seatbelt combination that brings her body to a stop in 1.1s. What is the impulse imparted to the driver of the car?
Answer:1590 N
Explanation:
Impulse = change in momentum/time
change in momentum = 0 - 50 x 35 = -1750
-1750/1.1 = 1590 (3s.f.) N
How much energy has 4x 1010 m³ of water collected in a reservoir at a 2. 3. height of 100 m from the power house? What kind of energy is that? (Given, mass of 1 m³ of water = 1000 kg)
Explanation:
[tex] \rule{999pt}{66646pt}[/tex]
if A and B are non zero vectors, is it possible for vector A×vector B and vector A.vector B both to be zero? Justify your answer
Answer:
not able to understand the question
Liquid X of volume 0.5m3 and density 900kgm-3 was mixed with liquid Y of volume 0.4m3 and density 800kgm-3. What was the density of the mixture?
Answer:
Density of the mixture = 855.56kgm-3
Explanation:
Density = Mass / Volume
Volume of Liquid X = 0.5m³
Density of Liquid X = 900kgm-3
Mass of Liquid X = Density × Volume
= 900kgm-3 × 0.5m³ = 450kg
Volume of Liquid Y = 0.4m³
Density of Liquid Y = 800kgm-3
Mass of Liquid Y = Density × Volume
= 800kgm-3 × 0.4m³= 320kg
As X and Y are mixed, we add their masses and volumes together:
Mass = 770kg
Volume = 0.9m³
Now we can find the density of the mixture:
Density = 770kg / 0.9m³ = 855.56kgm-3 (rounded to the 2nd decimal)
Mike drops a rock from the top of a suspension bridge. If the rock falls for 4.88 seconds,
how high is the bridge?
This question involves the concepts of the equations of motion in vertical direction.
The height of the bridge is "116.8 m".
We will use the second equation of motion in vertical direction to find out the height of the bridge.
[tex]h=v_it+\frac{1}{2}gt^2\\\\[/tex]
where,
h = hieght = ?
vi = initial speed = 0 m/s
t = time taken = 4.88 s
g = acceleration due to gravity = 9.81 m/s²
Therefore,
[tex]h=(0\ m/s)(4.88\ s)+\frac{1}{2}(9.81\ m/s^2)(4.88\ s)^2[/tex]
h = 116.8 m
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A single covalent bond is stronger than a single hydrogen bond so why does a group of polar molecules tend to have a higher boiling point than a group of non polar molecules
Answer:
this question makes no sense
Explanation:
like how do you get this question
Answer:They require more energy to break intermolecular forces hence polar molecules have higher melting points and boiling points than non-polar molecules of similar size, shape and number of electrons.
Explanation:
The app claimed it has "Forbidden text"
The normal force of a parked car on a level surface is 15,000 Newtons. What is the force of the car?
Answer:
The force of the car is 15000N.
Explanation:
The unit of force is Newtons (N), so based on the question, the force is 15000 Newtons.
The gravitational force between two asteroids is 6.2 × 108 N. Asteroid Y has three times the mass of asteroid Z.
If the distance between the asteroids is 2100 kilometers, what is the mass of asteroid Y?
Answer:
1.1x10¹⁶ kg
Explanation:
Let m = mass of asteroid y.
Because asteroid y has three times the mass of asteroid z, the mass of asteroid z is m/3.
Given:
F = 6.2x10⁸ N
d = 2100 km = 2.1x10⁶ m
Note that
G = 6.67408x10⁻¹¹ m³/(kg-s²)
The gravitational force between the asteroids is
F = (G*m*(m/3))/d² = (Gm²)/(3d²)
or
m² = (3Fd²)/G
= [(3*(6.2x10⁸ N)*(2.1x10⁶ m)²]/(6.67408x10⁻¹¹ m³/(kg-s²))
= 1.229x10³² kg²
m = 1.1086x10¹⁶ kg = 1.1x10¹⁶ kg (approx)
Which electromagnetic wave has a lowest frequency?
Group of answer choices
A) x-rays
B) ultraviolet light
C) microwaves
D) infrared light
E) visible light
Answer:
E.visible lights
Explanation:
hope its attachments
Tim is pushing a heavy box across the floor. He is using 300N of force and can accelerate at 2m/s/s. What is the mass of the box?
-298 kg
-600 kg
-0.006 kg
-150 kg
Using Newton's second law
[tex]\\ \sf\Rrightarrow F=ma[/tex]
[tex]\\ \sf\Rrightarrow 300=2m[/tex]
[tex]\\ \sf\Rrightarrow m=150kg[/tex]
Hey there!
The formula of “mass” in physics is:
m = F/a
Whereas “f” is ‘force’, “a” is ‘acceleration’, & “m” is your ‘mass’ of course.
mass = 300 Net force/2 acceleration
300 Net force/2 acceleration = m
mass = 150
Therefore, your answer is: 150 kg
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
4 What type of circuit is described by each of the following statements?
Answer series or parallel
a All components are connected end-to-end.
b. The current in the circuit divides so that some flows through one component
and the rest through another component
Two lamps are connected side by side so that each lights brightly
d The current has the same valur everywhere in the circuit
C
8 million electrons per second through an ohmic gas
the compare software
hope it's help
Answer:
you ask or answer?
Explanation:
thanks for point
[tex] \huge{ \mathrm{question \hookleftarrow}}[/tex]
Calculate equivalent resistance of two resistors R1 and R2 in parallel where,
[tex] \sf R_ 1 = (6 \pm0.2 )\: \: ohms[/tex]
[tex] \sf R_ 2 = (3 \pm0.1 )\: \: ohms[/tex]
[tex]it \: was \: helpful \: to \: you[/tex]
# be careful#
A 0.15 kg baseball moving at 20 m/s is stopped by a player in 0.010 s. What is the average force of the ball?
Answer: 300N
Explanation:
Impulse= Mass * Velocity
F.T = M * V
F= MV/T
F= (0.15*20)/ 0.01
F= 300N
A 2.0 kg block rests on a level surface. The coefficient of static friction is, and the coefficient of kinetic friction is A horizontal force, X, is applied to the block. As X is increased, the block begins moving. Describe how the force of friction varies as X increases from the moment the block is at rest to when it begins moving. Indicate how you could determine the force of friction at each value of X―before the block starts moving, at the point it starts moving, and after it is moving. Show your work.
ps. I had to change F to X because of brainly.
By Newton's second law, the net force acting on the block in the vertical direction is
∑ F [ver] = n - mg = 0
where n = magnitude of normal force and mg = weight of the block. It follows that n = mg.
When the block is at rest, the applied force X will not be enough to move the box until it can overcome the maximum mag. of static friction. If µ[s] is the coefficient of static friction, then the maximum mag. of the frictional force is
f = µ[s] n = µ[s] mg
The net horizontal force would be
∑ F [hor] = X - µ[s] mg = 0
so a minimum force of X = µ[s] mg is required to get the block moving. Any mag. smaller than this and the block stays at rest/in equilibrium.
Once the mag. of X exceeds µ[s] mg, the block will begin to move. At that point, if the coefficient of kinetic friction is µ[k], then the net force on the block is
∑ F [hor] = X - µ[k] mg = 0
so a minimum force of X = µ[k] mg would be needed to keep the block moving at constant speed, or otherwise X = µ[k] mg + ma if the block is accelerating with mag. a.
The principles here are captured in the attached plot.
A certain satellite is in circular orbit about the earth at an altitude of 550km. If the satellite makes a revolution in 110minutes, calculate its orbital speed
Answer:
Approximately [tex]6.59\times 10^{3}\; \rm m\cdot s^{-1}[/tex].
Explanation:
Look up the radius of the earth: approximately [tex]6.371 \times 10^{3}\; \rm km[/tex].
The radius of the orbit of this satellite is the of the radius of the earth (at ground level) plus the height of the satellite relative to ground level:
[tex]\begin{aligned}r &\approx 6.371 \times 10^{3}\; {\rm km} + 550\; {\rm km} \\ &= 6.921 \times 10^{3}\; \rm km\end{aligned}[/tex].
Convert the units of both distance and time to standard units:
Orbital radius:
[tex]\begin{aligned}r &\approx 6.921 \times 10^{3}\; {\rm km} \\ &= 6.921 \times 10^{3}\; {\rm km} \times \frac{10^{3}\; \rm m}{1\; \rm km} \\ &= 6.921 \times 10^{6}\; \rm m\end{aligned}[/tex].
Orbital period:
[tex]\begin{aligned}t &= 110\; \text{minute} \\ &= 110\; \text{minute} \times \frac{60\; \text{second}}{1\; \text{minute}} \\ &= 6.6 \times 10^{3}\; \text{second}\end{aligned}[/tex].
Calculate the circumference of this orbit:
[tex]\begin{aligned}& 2\, \pi\, r \\ \approx\; & 2 \, \pi \times 6.921 \times 10^{6}\; {\rm m} \\ \approx\; & 4.35 \times 10^{7}\; \rm m\end{aligned}[/tex].
Calculate the orbital speed (tangential) of this satellite:
[tex]\begin{aligned}v &= \frac{2\, \pi\, r}{t} \\ &\approx \frac{4.35 \times 10^{7}\; \rm m}{6.6 \times 10^{3}\; \rm s} \\ &\approx 6.6 \times 10^{3}\; \rm m \cdot s^{-1}\end{aligned}[/tex].
John throws a ball with a velocity of 30 m/s at an angle of 60 degrees. What is the horizontal component of the velocity?
a 30 m/s
b 0 m/s
c 25.9 m/s
d 15 m/s
The horizontal component of the velocity is equal to: D. 15 m/s.
Given the following data:
Velocity = 30 m/sAngle = 60°To determine the horizontal component of the velocity:
The horizontal component of the velocity represents the influence of velocity in displacing an object or projectile in the horizontal direction.
Mathematically, the horizontal component of velocity is given by the formula:
[tex]V_x = Vcos(\theta)[/tex]
Substituting the given parameters into the formula, we have;
[tex]\\\\V_x = 30cos(60)\\\\V_x = 30 \times 0.5[/tex]
Horizontal component, Vx = 15 m/s
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the purpose of many scientific investigations is to test a {n}
Answer:
Scientific investigation is a quest to find the answer to a question using the scientific method.
Explanation:
the scientific method is a systematic process that involves using measurable observations to formulate, test or modify a hypothesis.
hi i need some help with this.....
Answer: D
Explanation: moogle helps lol.
What is the final temperature if it requires 5000 J of heat to warm 2.38892 x10-2 kg of water that starts at 5oC? Remember Cp for water is 4186 J/kgC
The final temperature of water is equal to 50.9999°C
Given the following data:
Mass = [tex]2.38892 \times 10^{-2}\;kg[/tex]Quantity of heat = 5000 J Specific heat capacity of water = 4186 J/kg°CTo determine the final temperature of water:
Mathematically, quantity of heat is given by the formula;
[tex]Q=mc\theta[/tex]
Where:
Q represents the quantity of heat.m represents the mass of an object.c represents the specific heat capacity.∅ represents the change in temperature.Substituting the given parameters into the formula, we have;
[tex]5000=2.38892 \times 10^{-2}\times 4186 \times \theta\\\\5000=100.0001912 \theta\\\\ \theta=\frac{5000}{100.0001912} \\\\ \theta=49.9999^{\circ}C[/tex]
For the final temperature:
[tex]\theta = T_2 - T_1\\\\T_2 = \theta+T_1\\\\T_2 = 49.9999 + 50[/tex]
Final temperature = 50.9999°C
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in what direction will the seesaw rotate and what will the sign of the angular acceleration be?
Answer:
It can rotate in any direction. The sign of the angular acceleration depends on how you set the reference system, it can be both negative or positive.
A point charge of 5. 0 Ă— 10â€""7 C moves to the right at 2. 6 Ă— 105 m/s in a magnetic field that is directed into the screen and has a field strength of 1. 8 Ă— 10â€""2 T. What is the magnitude of the magnetic force acting on the charge? 0 N 2. 3 Ă— 10â€""3 N 23 N 2. 3 Ă— 1011 N.
The magnitude of the magnetic force acting on the charge which moves to the right is 0 N.
Given to us,
the charge [tex]q[/tex] = [tex]5\times 10^{-7}[/tex] C,
the velocity [tex]v[/tex] = [tex]2.6\times 10^5[/tex] m/sec,
the magnetic field [tex]B[/tex] = [tex]10^{-2}[/tex] T,
angle between the direction of v and B [tex]\theta[/tex] = 0,
Magnetic force is as important as the electrostatic or Coulomb force. The magnitude of the magnetic force F on a charge q moving at a velocity of v in a magnetic field of strength B is given by
[tex]\begin{aligned}F&=qvB\ sin\Theta\\&= 5\times10^{-7}\times2.6\times10^5\times10^{-2} \times sin(0)\\&= 0\ N\\\end{aligned}[/tex]
Hence, the magnitude of the magnetic force acting on the charge which moves to the right is 0 N
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how to solve for time given distance and velocity
Answer:
Well, I think you're talking about kinematics, especially uniform rectilinear motion. We know that there is a specific equation for that:
S = Vt + S0
With S being the distance, V the velocity, t the time and S0 the initial distance (initial displacement).
From this you can calculate t, if that's what you want.
What is the mass of an object that has a weight of 110N ?
Answer:
The mass of the object is 11.2 Kg.
Hope you could get an idea from here.
Doubt clarification - use comment section.
The mass of an object that has a weight of 110 N is 11.2kg.
What is Weight?The weight of an object is defined as the force that acts on the object due to gravity. It is a vector quantity in some cases such as when the force of gravity acts on an object but it is also a scalar quantity where the force of gravity has a magnitude.
Weight is the gravitational force of attraction on an object due to the presence of another heavy object, such as the Earth or the Moon. It is expressed by multiplying the mass by the gravitational acceleration.
In above case,
Weight (W) = 110 N
Acceleration due to gravity (g) = 9.8 m/s^2
Let the mass of the object be m.
By using the formula,
W = mg,
[tex]110 N = 9.8 m/s^2 *m\\m = 110 N/ 9.8 m/s^2[/tex]
so, m = 11.2 Kg
Thus, the mass of an object that has a weight of 110 N is 11.2kg.
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how much force would be needed to push a box weighing 30 N up a ramp that ahas an ideal mechanical advantage of 3
Answer:
60n would be the needed force
The force needed to push a box weighing 30 N up a ramp that has an ideal mechanical advantage of 3 is equal to 10 N.
What is the mechanical advantage?The mechanical advantage can be described as the ratio of the input force to the output force. The mechanical advantage of any machine can be determined by the ratio of the forces involved to do the work.
The ratio of the resistance force to the effort is called the actual mechanical advantage which will be comparatively less. The efficiency of a machine is always determined by equating the ratio of its output to its input.
The efficiency of the machine is equal to the ratio of the actual mechanical advantage (M.A.) and theoretical mechanical advantage. Mechanical advantage can be defined as the force produced by a machine to the force applied to it.
Given the load = 30 N and the ideal mechanical advantage = 3
Mechanical advantage = Load/ Effort
Input force or effort = Load/ M.A.
Force = 30/3
Input Force = 10 N
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Plz help!
A person walks the path shown
below. The total trip consists of
four straight-line paths. At the end of the walk, what is the person's
resultant displacement measured from the starting point?
The analytical method for the sum of vectors allows to find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
The displacement is a vector quantity, therefore vector algebra must be used to perform the addition of vectors, in general there are two methods:
Graphic. In this case, the origin of a vector is placed at the tip of the previous one and the resulting vector goes from the origin of the first vector to the tip of the last, this method is not very precise. Analytical. In this method the vectors are decomposed into a coordinate system, the sum of the components is performed and the resulting vector is built, this method is very expensive.
Indicate in the graph a Cartesian coordinate system, let alone the West - East axis coincide with the x axis. Let's use trigonometry to decompose the vectors.
Vector A.
Aₓ = 100.0 m
Vector B.
B_y = -300.0 m
The negative sign indicates that it goes in the negative direction of the y-axis
Vector C.
We use trigonometry.
The angle measured from the positive side of the x-axis counterclockwise is
θ = 180 + 30 = 210
sin 210 = [tex]\frac{C_y}{C}[/tex]
cos 210 = [tex]\frac{C_x}{C}[/tex]
C_y = C sin 210
Cₓ = C cos 210
C_y = 150.0 sin 210 = -75.0 m
Cₓ = 150.0 cos 210 = -129.9 m
Vector D.
The angle from the positive side of the x-axis counterclockwise.
θ = 180-60 = 120º
sin 120 = [tex]\frac{D_y}{D}[/tex]
cos 120 = [tex]\frac{D_x}{D}[/tex]
D_y = D sin 120
Dₓ = D cos 120
D_y = 200.0 sin 120 = 173.2 m
Dₓ = 200.0 cos 120 = -100.0 m
we add the component with algebraic sum.
x = Aₓ + Cₓ + Dₓ
y = B_y + C_y + D_y
x = 100 - 129.9 -100 = -129.9 m
y = -300 - 75.0 + 173.2 = -201.8 m
We construct the resulting vector.
We use the Pythagorean theorem for the Modulus.
[tex]R+ \sqrt{x^2 +y^2}[/tex]
R = [tex]\sqrt{129.9^2 + 201.8^2 }[/tex]
R = 239.99 m
We use trigonometry for the angle.
tan θ = [tex]\frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{y}{x}[/tex]
θ = [tex]tan^{-1} \frac{201.8}{129.9}[/tex]tan-1 (201.8 / 129.9)
θ = 57.2º
Since the two coordinates are negative, this angle is in the third quadrant; to measure it from the positive side of the x-axis.
θ = 270 - θ'
θ = 270 - 57.2
θ = 212.8º
In conclusion using the analytical method for the sum of vectors we can find the result for the sum of the vectors is:
The resulting vector has a modulus of R = 239.99 m and an angle of θ= 212.8º
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