98*68-67+87
this is for my lady

Answer:

x = 11/c

Step-by-step explanation:

cx - 4 = 7

Add 4 to each side

cx - 4+4 = 7+4

cx = 11

Divide each side by c

cx/c = 11/c

x = 11/c

Answer: C

Step-by-step explanation: I could tell just by looking at the first two, they’re negative

Answer:

three shirts an hour

Step-by-step explanation:

Answer:

sorry I don't mean to be rude but where is the question what you've written is a statement

D. 1,925 km

Multiply 55 with 35 --> 1,925 km/35hrs

Answer:

D

Step-by-step explanation:

55*35=1925

Answer:

m∠A = 39°

Step-by-step explanation:

From the figure attached,

BE ≅ BC

m∠C = 32°

m∠BFD = 103°

In ΔBCE,

m∠E = m∠C = 32°  [Since, BE ≅ BC]

m∠E + ∠C + m∠EBC = 180°

32° + 32° + m∠EBC = 180°

m∠EBC = 116°

m∠EBC + m∠EBA = 180° [Linear pair of angles]

116° + m∠EBA = 180°

m∠EBA = 64°

Similarly, m∠AFB + m∠DFB = 180° [Linear pair of angles]

m∠AFB + 103° = 180°

m∠AFB = 77°

Now in ΔAFB,

m∠A + m∠AFB + m∠FBA = 180° [Sum of internal angles of a triangle = 180°]

m∠A + 77° + 64° = 180°

m∠A = 39°

Answer:

6

Step-by-step explanation:

2(x+3)=18

2x+6=18

2x=12

x=6

Answer:

x = 6

Step-by-step explanation:

2(x + 3) = 18

 2x + 6 = 18

       2x = 12

         x = 6

Answer:

12

Step-by-step explanation:

12 / 2 = 6

19 - 6 = 13

Answer:

12

Step-by-step explanation:

19-13 is 6

Half of 12 is 6

Answer: x= 200

Step-by-step explanation: Any value greater than 103 will be equal to x. So... in this case, x= >103. (200>103).

Answer:

Jamal has the the better record

Answer:

This is the sample response from Edge

Step-by-step explanation:

Jamal has the better record because his record is 0.7 and Brian’s record is 0.625. Jamal made more free throws.

Answer:

So the volume expands as kinetic energy is gained and the more mass there is the more kinetic energy there will be. Hopefully this helps you and if it doesn't I will add on to it, just lmk.

The scale factor from triangle ABC to triangle PQR is 2/3 or 3/2, depending on the direction of comparison.

To find the scale factor from triangle ABC to triangle PQR, we need to compare the corresponding side lengths of the two triangles.

Side AB corresponds to side PQ, which has a length of 6 units.

Side BC corresponds to side QR, which has a length of 9 units.

Side AC corresponds to side PR, which has a length of 12 units.

So, the scale factor from triangle ABC to triangle PQR can be found by comparing the ratio of corresponding side lengths:

AB/PQ = BC/QR = AC/PR

Using the values we found above, we can write:

|AB/PQ| = 2/3

|BC/QR| = 3/4

|AC/PR| = 4/5

Since all three ratios are equal in magnitude, we can take any one of them to be the scale factor. Therefore, the scale factor from triangle ABC to triangle PQR is 2/3 or 3/2, depending on the direction of comparison.

To learn more about scale factor please click on below link.

https://brainly.com/question/30215044

#SPJ1

Answer:

then it would 50 no? i first divided 100 from x and game me 100x and then since i knew that 2 plus 3 is 5 and if i add a 0 then it would make 50

Step-by-step explanation:

Answer:

9 :/

Step-by-step explanation:

Answer:9

Step-by-step explanation:

3x9=27

27 divided by 3=9

Answer:

the answer is 62

Step-by-step explanation:

you take  180 and subtract 118

Answer:

The answer should be 62, but i'm not positive so correct me if i'm wrong!

Explanation:

What I did is i added 118 and 118 then subtracted 360 by the sum. After that I divided the result by two which gave me 62, and I am almost sure that is the answer, but like I said i'm not positive. :)

Answer:

2/3

Step-by-step explanation:

I checked on desmos.

Answer:

whats the question.

Step-by-step explanation:

let me know

Answer:

C.

Step-by-step explanation:

Answer:

[tex]3d - 9[/tex]

Step-by-step explanation:

[tex](-7d - 3)+(10d - 6)\\-7d - 3 + 10d - 6\\-7d + 10d -3 - 6\\3d - 9[/tex]

Answer:

No they are not equivalent because 3/4 would be equivalent to 6/8, 9/12, 12/16/ 15/20. 16/20 would be the greatest fraction because in its simplest form it would be 4/5.

Answer:

im not sure but here u go 85x+60

Distance = rate * time

Let r = rate

Distance is the same for both runs,  so:

.5r = D =  3/4(r - 2)

Distribute (and convert .5):

2/4r = 3/4r - 3/2

Subtract 3/4 r from both sides:

-1/4r = -3/2

Multiply both sides by -4 to get a solitary r:

r = -3 * -4 / 2

r = 3 * 2

r = 6 miles per hour

.5 hours * 6 mi/hr = 3 miles

check:

6 - 2 = 4

3/4 hours * 4 mi/hr = 3 miles

Answer:

60°

140°

Step-by-step explanation:

From the given figures,

 a. we use the concept of alternate angles.

   Two parallel lines cut by a transversal will have equal alternate angles;

  So;

       6x + 12 = 7x + 4

    collect like terms and solve for x;

     6x - 7x = 4 - 12

         -x = -8

         x = 8

Now, 6x + 12 = 6(8) + 12

                     = 48 + 12

                     = 60°

b. Here we use alternate angles and angles on a line;

     4x is an alternate angle to that angle to the left of 13x + 10

And sum of angles on a line = 180

    4x + 13x + 10 = 180

        17x = 170

          x = 10

Now,  13x + 10 = 13(10) + 10 = 140°

Answer:

-5/3

Step-by-step explanation:

-2 to 1 =3   x=3

4 to -1=5   y=-5

y/x      slope=-5/3 or -1  2/3

Answer:

Step-by-step explanation:

Answer:

[tex]y=2x-6[/tex]

Step-by-step explanation:

A locus can be defined as a curve or figure formed by all the points satisfying a particular equation of the relation between coordinates.

The condition stated in the question is such that a generic (x,y) point of the curve is equidistant from the points A(2,3) and B(6,1).

The distance d1 from (x,y) to (2,3) is:

[tex]d_1=\sqrt{(x-2)^2+(y-3)^2}[/tex]

The distance d2 from (x,y) to (6,1) is:

[tex]d_2=\sqrt{(x-6)^2+(y-1)^2}[/tex]

Since d1=d2:

[tex]\sqrt{(x-2)^2+(y-3)^2}=\sqrt{(x-6)^2+(y-1)^2}[/tex]

Squaring both sides:

[tex](x-2)^2+(y-3)^2=(x-6)^2+(y-1)^2[/tex]

Operating:

[tex]x^2-4x+4+y^2-6y+9=x^2-12x+36+y^2-2y+1[/tex]

Simplifying all the squares:

[tex]-4x+4x+4-6y+9=-12x+36-2y+1[/tex]

Moving the variables to the left side and the numbers to the right side:

[tex]-4x+12x-6y+2y=36+1-4-9[/tex]

Simplifying:

[tex]8x-4y=24[/tex]

Dividing by 4:

[tex]2x-y=6[/tex]

Or, equivalently:

[tex]\boxed{y=2x-6}[/tex]