9,11,10 need those answers

When 1 mol of liquid diethyl ether at its standard boiling point is given an enthalpy of vaporization of 26.52 kJ/mol, the temperature of the liquid will remain the same, but the physical state of the diethyl ether will change from liquid to vapor.

The enthalpy of vaporization is the energy required to convert one mole of a liquid into a vapor and is also known as the heat of vaporization. When the enthalpy of vaporization is applied to liquid diethyl ether, it causes the liquid to become a vapor.

In order to understand this concept, it is helpful to look at the thermodynamic process of vaporization, or boiling. Vaporization involves the conversion of liquid to a gas at the standard boiling point by the absorption of energy, which is provided in the form of heat.

During vaporization, the liquid molecules move quickly and gain enough energy to escape the surface of the liquid and form a gas. This process is also reversible, so as the vaporized molecules lose energy, they can condense back into the liquid state.

Therefore, the temperature remains the same, but the liquid is converted to a vapor. This vapor can eventually condense back into liquid form, depending on the temperature and pressure of the system.

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Answer:

Explanation: Te3Cl2

Se2 S6

Just make the number small like subscripts

71.86 grams of Fe2O3 can form from 21.6 grams of O2.

To determine the amount of Fe2O3 that can form from 21.6 g of O2, we need to use the balanced chemical equation and the stoichiometry of the reaction.

According to the balanced chemical equation:

4 Fe(s) + 3 O2(g) → 2 Fe2O3(s)

The stoichiometric ratio of O2 to Fe2O3 is 3:2. This means that for every 3 moles of O2, 2 moles of Fe2O3 are produced.

To calculate the amount of Fe2O3 formed, we need to first convert the mass of O2 given to moles:

n(O2) = m(O2) / M(O2)

where:

Next, we can use the stoichiometric ratio to calculate the number of moles of Fe2O3 formed:

n(Fe2O3) = 2/3 x n(O2)

n(Fe2O3) = 2/3 x 0.675 mol = 0.450 mol

Finally, we can convert the number of moles of Fe2O3 to grams using its molar mass:

m(Fe2O3) = n(Fe2O3) x M(Fe2O3)

where:

Therefore, 71.86 grams of Fe2O3 can form from 21.6 grams of O2.

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How many grams of [tex]Fe_2O3[/tex] can form from 21.6g of [tex]O_2[/tex]

[tex]4Fe(s) + 3O_2(g) -------- > 2Fe_2O_3(s)[/tex]

Answer:

The correct answer is C. The mass remains constant.

Explanation:

The Law of Conservation of Mass states that the total mass of a closed system remains constant during a chemical reaction. This means that the mass of the reactants before the reaction is equal to the mass of the products after the reaction.

In the given chemical reaction, silver nitrate (AgNO3) reacts with sodium chloride (NaCl) to produce silver chloride (AgCl) and sodium nitrate (NaNO3). Since the reaction involves only the rearrangement of atoms and not the creation or destruction of atoms, the total mass of the reactants must be equal to the total mass of the products.

The correct answer is C. The mass remains constant.

Answer:

Actual yield and theoretical yield

Answer:

The molar mass of CuO is 63.55 g/mol for copper and 15.9994 g/mol for oxygen, giving a total molar mass of 79.55 g/mol.

To calculate the number of moles in 4.0 g of CuO, we can use the formula:

moles = mass / molar mass

moles of CuO = 4.0 g / 79.55 g/mol

moles of CuO = 0.0502 mol

Therefore, there are 0.0502 moles in 4.0 g of CuO.

The death rate in Star City is 0.452 deaths per 1000 people.

The death rate is the number of deaths per unit of population. It is calculated by dividing the number of deaths by the total population and multiplying the result by 1000 to express it per 1000 people.

The formula for death rate is:

Death rate = (Number of deaths / Total population) x 1000

Substituting the given values:

Death rate = (1.9 x 10³ / 4.2 x 10⁶) x 1000

Simplifying the expression:

Death rate = 0.000452 x 1000

Death rate = 0.452 deaths per 1000 people

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Explanation:

The pH range between 3.2 and 9.4 will precipitate aluminum hydroxide but not lead (II) hydroxide. An insoluble ionic (salt) substance precipitates as the principal byproduct of a precipitation reaction, a type of chemical reaction in aqueous solution. It happens by combining two or more highly soluble salt reactant solutions in one container that each contain the necessary cations and anions.

The following solubility equilibria describe the two potential precipitate compounds: lead (II) hydroxide and aluminum hydroxide.

[tex]Pb(OH)_{2} (s) =Pb{2} + (aq) + OH{-} (aq)\\k_{spl} = 1.43(10)^{-20} =[Pb^{2+} ][OH^{-2} \\Al(OH)_{3} = Alx^{3} +(aq)+3OH^{-} (aq)[/tex]

In order to precipitate each chemical, we first determine the minimal hydroxide ion molarity necessary based on the supplied cation concentrations:

[tex]1.43(10){} ^{-10} =(0.27)(OH}^{-} )^{2} _{1}[/tex]

[tex]OH^{-} _{1} =2.39(10)^{-5} M\\1.90(10)^{-33} =(0.50M)(OH^{-} )^{3} _{2} \\[/tex]

[tex](OH^{-} )_{2} =1.56(10)^{-11} M[/tex]

[tex]1.43(10)^{-10} =(0.27)(OH)^{2} _{1} \\(OH^{-}) _{1} =2.39(10)^{-5} M= 2.4(10)^{-5} \\(OH^{-} )_{2} =1.56(10^{-11} )M=1.6(10)^{-11}[/tex]

These hydroxide ion molarity numbers line up with specific pH numbers.

[tex]pOH_{1} = -log(OH^{-} )_{1} =4.61\\pH_{1} = 14- pOH_{1} =9.4[/tex]

[tex]pOH_{2} = -log(OH^{-} )_{2} = 10.8\\pH_{2} =14-pOH_{2}=3.2[/tex]

As a result, the pH range between 3.2 and 9.4 will precipitate aluminum hydroxide but not lead (II) hydroxide.

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0.459 moles of H₂O can be formed from 1.84 x 10²³ molecules of NH₃.

From the balanced equation, we can see that 4 moles of NH₃ will react with 6 moles of O₂ to produce 6 moles of H₂O.

So, the ratio of moles of NH₃ to moles of H₂O is 4:6, or 2:3

Using the coefficients in the balanced chemical equation, you can calculate the moles of H₂O that can be formed from 1.84 x 10²³ molecules of NH₃.
Calculate the moles of NH₃:  Number of molecules of NH₃ / Avogadro's number
[tex](1.84 * 10^{23} / 6.022 * 10^{23} ) = 0.306 \ moles\ NH3[/tex]
Calculate the moles of H₂O formed:
0.306 moles NH₃ x (6 moles H₂O/4 moles NH₃) = 0.459 moles H₂O

[tex]0.306 * (6/4) \ = 0.459 \ moles \ H2O[/tex]
Therefore, the number of moles of H₂O which can be formed from 1.84 x 10²³ molecules of NH₃ is 0.459

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The volumes 447.0 mL and 353.0 mL of equimolar aqueous solutions of K2HPO4 and KH2PO4 must she combine to make 250. 0 mL of the pH 7. 00 buffer solution.

A buffer solution is defined as a solution when an acid or a base is in equilibrium with its conjugate base or acid and because of that, when other acid or base is added to the solution, the pH remains almost unaltered. It is a water solvent based solution which consists of a mixture containing a weak acid and the conjugate base of the weak acid or a weak base and the conjugate acid of the weak base. Buffer resist a change in pH upon dilution or upon the addition of small amounts of acid or alkali to them.

The pH of a buffer can be calculated by the expression of Henderson–Hassel Balch equation,

pH = pKa + log[A-]/[HA]

Here, pKa is the equilibrium constant of the acid and A- is the conjugate base and [HA] is the acid.

(n1/V1)/(n2/V2) = 0.79

(n1/V1)*(V2/n2) = 0.79

Because n1 = n2,

V2/V1 = 0.79

V2 = 0.79V1

The total volume must be 800.0 mL, so

V1 + V2 = 800.0

V1 + 0.79V1 = 800.0

1.79V1 = 800.0

V1 = 447.0 mL

V2 = 353.0 mL

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Depending on where a force, fulcrum, and load are, the three classes differ from one another. The centre of gravity of a first-class lever is situated here, halfway between both the input force or the output force.

Depending upon where the power supply, fulcrum, or load are located, there are three different kinds of levers. The fulcrum of a class 1 lever is situated between both the input force or the load. The load is situated between both the fulcrum and the input force of a class 2 lever. Levers with the input force located between the fulcrum as well as the load are classified as class 3 levers.

These are the types of levers where the weight is on one end, the fulcrum is in the middle, as well as the force is applied. The arrangement is shown as a weight-force-fulcrum. In this situation, we need to exert greater force in order to move the weight.

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We will need 12.817 grams of naphthalene to react stoichiometrically with 0.1 moles of 2-bromo-2-methylpropane. As mentioned in the question, a mass within 0.040 g of the calculated stoichiometric quantity will be sufficient for the experiment. So, a mass of naphthalene between 12.777 g and 12.857 g will be appropriate.

2-bromo-2-methylpropane + naphthalene → product(s)

To calculate the mass of naphthalene required for the reaction, we need to know the mole ratio of 2-bromo-2-methylpropane to naphthalene in the balanced equation.

From the balanced equation, we can see that the mole ratio is 1:1.

This means that one mole of 2-bromo-2-methylpropane will react with one mole of naphthalene.

First, we need to determine the number of moles of 2-bromo-2-methylpropane that we have in the flask.

Let's assume we have 0.1 moles of 2-bromo-2-methylpropane.

To react stoichiometrically, we will need 0.1 moles of naphthalene.

The molar mass of naphthalene is 128.17 g/mol.

To calculate the mass of naphthalene required, we can use the following equation:

mass = moles x molar mass

mass = 0.1 moles x 128.17 g/mol

mass = 12.817 g

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CORRECT QUESTION WOULD BE

Calculate the mass of naphthalene required to react stoichiometrically with the moles of 2-bromo-2-methylpropane that you have placed in the flask. Dispense that quantity of naphthalene into the weighing dish. There is some imprecision in delivering the powder onto the weigh boat, but a mass within 0. 040 g of the calculated stoichiometric quantity will be sufficient for this experiment. Note that you can use a combination of the 1 g and the 0. 1 g buttons to add the required mass. If you overshoot the goal, you can displace some of the powder back into the bottle with a spatula.

Answer:

1. Gasoline is not a homogeneous mixture; it is a complex mixture of different hydrocarbons and additives.

2.  If a mixture is cloudy or displays the Tyndall effect, then it is either a colloid or a suspension.

Which of the following organisms typically have more than one form of east of each gene from can mask the appearance another form that form is considered  dominant  the other form,

Each gene in each of us has two alleles, or variations. If you inherit two identical copies of a gene, you are said to be homozygous for that gene. In contrast, a genotype with distinct alleles is called a heterozygous genotype. Individuals with recessive characteristics, such as red hair or blue eyes, are always homozygous for that gene.

if a trait has two equally expressed alleles and none can prevent the expression of the other allele This is an illustration of codominance, a genetic phenomena in which the expression of two alleles (differing variants of the same gene) within an organism is equal. The features linked to each allele are therefore displayed concurrently.

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Each atom on both sides of a balanced chemical equation has the same number and type. A balanced equation's coefficients must have the simplest whole number ratio. In chemical processes, mass is always preserved.

Consider the following reaction: 2Mg(s)+O2(g)2MgO(g), Two atoms of magnesium and oxygen are present on both the reactant and product sides of this reaction. As a result of obeying the rule of conservation of mass, the chemical reaction is a balanced chemical equation.

A balanced chemical equation is one in which the number of each type of atom on both sides of the equation is equal. Subscripts are elements in the chemical formulae of reactants and products that denote the number of atoms of the previous element.

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Answer:

Solutions - smaller than 1 nm

Colloids - 1 nm to 1000 nm

Suspensions - larger than 1000 nm

Answer:

Explanation:

moles of what?

if P4= 0.078 moles P4

if F2=0.47 MOLES F2

The crust, mantle, and core of the earth are its three layers. Both the heat and the light from the Sun come from the a nuclear fusion inside the Sun's core. Proton fusion is the part of fusion takes place inside Sun.

These are, starting from the outside: the heated, outermost layer of the atmosphere is called the corona. between the photosphere and the corona is a transparent layer known as the chromosphere. This visible "surface" of a Sun is called the photosphere.

The 3 major layers that make the environment are the convective zone, the radiative zone, and the core. They make up the Sun's interior. The region of the Sun that is closest to it's own centre is called the core, which is where that hydrogen fuses with helium to form helium.

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KI: This is an ionic compound made of the nonmetal iodine and the metal potassium (K) (I). Phosphorus (P) and oxygen (O) combine to generate the chemical compound P2O5 (O).

White, microcrystalline, light-weight phosphorus pentoxide is created when elemental phosphorus burns in an atmosphere with too much oxygen. The anhydride of orthophosphoric acid, H3PO4, is phosphorus pentoxide.

A molecular molecule typically consists of two or more nonmetal parts. Molecular compounds are termed using the stem of the first element's name plus the suffix -ide, followed by the second element. The number of atoms in a molecule is specified using numerical prefixes.

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Answer:

boys have faster reaction than girls

Explanation:

that because the Y chromosome do not have the greater ability to resist reaction while the X does

Molar mass of carbon dioxide is 44.01 g/mol. Thus, 9.2 moles of carbon dioxide will have a mass of 408.19 g.

Carbon dioxide (CO2) is a colorless, odorless gas that is naturally found in the Earth's atmosphere. It is one of the most important greenhouse gases and is the primary driver of global warming. Carbon dioxide is produced naturally by the respiration of living organisms, such as humans and animals, and by the decomposition of organic matter. It is also produced by burning fossil fuels and other industrial processes. Carbon dioxide is used in photosynthesis by plants, which convert it into oxygen and carbohydrates, providing the oxygen humans and animals need to breathe.

Molar mass of methane is 16.04 g/mol. Therefore, 408.19 g of carbon dioxide is equivalent to 25.5 moles of methane. This means that 25.5 moles of methane will have a mass of 408.19 g. Therefore, the answer is 408 g.

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False.

We use the ideal gas law to describe the behavior of gases under specific conditions, such as constant temperature, pressure, and volume. It is a mathematical formula that relates the pressure, volume, amount, and temperature of a gas.

What is Ideal Gas Law?

The ideal gas law is a mathematical equation that describes the behavior of an ideal gas under specific conditions. It relates the pressure (P), volume (V), temperature (T), and amount of substance (n) of an ideal gas, using the following equation:

PV = nRT

where R is the universal gas constant, which has a value of 8.31 J/(mol·K) in SI units.

The ideal gas law assumes that the gas molecules are point masses that do not interact with each other except through perfectly elastic collisions, and that the gas occupies a large volume compared to the size of the molecules. In reality, most gases do not behave exactly like ideal gases, especially at high pressures or low temperatures.

However, when a gas changes, we may need to use different laws or equations to describe the behavior of the gas, depending on the conditions and factors involved. For example, if the volume of a gas changes at a constant temperature and pressure, we would use Boyle's Law, which describes the relationship between volume and pressure.

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Answer:

Ca(NO3) + Pb

Explanation:

that,s the proper  equation

The grams of CO2 that could have been produced according to the reaction is 21.2 grams.

We apply the stoichiometric principles to calculate the potential yield of a particular mixture of chemicals. To determine the mole to mole correlations between the chemical species in stoichiometry, we apply the balanced chemical equation. The theoretical yield is the highest yield that can be estimated from the starting reagent quantities. The amount collected is known as the actual yield, and frequently we discover that the theoretical yield is not achieved.

The balanced chemical equation is:

2CO + O₂ → 2CO₂

Molar Mass CO = 28.0 grams per mole

Molar Mass O2 = 32.0 grams per mole

Molar Mass CO2 = 44.0 grams per mole

We determine the maximum quantity of carbon dioxide that may be produced from each reagent based on their initial concentrations. This assumes that there is an excess of the other reagent.

13.5 g CO x 1 mol CO / 28 g CO x 2 mol CO₂ / 2 mol CO x 44 g CO₂

= 21.2 g CO₂

Therefore, grams of CO2 could be produced is 21.2 g.

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Complete question:

A reaction vessel contains 6. 300 g of CO and 6. 300 g of O2. How many grams of CO2 could be produced according to the following reaction?

2CO + O₂ ----> 2CO₂

Answer:

Explanation:

Based on the information given in the graphic, we can determine that the atom has 12 protons and 12 neutrons, which would give it an atomic mass of 24. However, the graphic does not provide information about the number of electrons, which would be necessary to determine the element's location on the modern periodic table.

Therefore, none of the answer choices provided can be determined from the information given. We cannot identify the group or period of the element on the modern periodic table based solely on the number of protons and neutrons in the atom.

This polysaccharide has the molecular formula C₆₀H₁₀₂O.

When ten glucose molecules are linked together by dehydration reactions, a polymer is formed called a polysaccharide. The molecular formula of this polysaccharide can be derived by adding the molecular formula of ten glucose molecules and subtracting the number of water molecules released during the polymerization process.

The molecular formula of one glucose molecule is C₆H₁₂O₆. When ten glucose molecules are linked together, ten water molecules are released, one for each bond formed. Therefore, the molecular formula for the polymer made by linking ten glucose molecules together by dehydration reactions would be:

(C₆H₁₂O₆)10 - (H₂O)10 = C₆₀H₁₀₂O₅₁

So the molecular formula for this polysaccharide is C₆₀H₁₀₂O₅₁. This type of polysaccharide is commonly found in nature, including starch in plants and glycogen in animals.

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Many common things you use regularly are colloids except alloy.

An alloy is a solid solution composed of two or more metals or a metal and a non-metal element. In contrast, colloids are mixtures where one substance is dispersed throughout another substance in the form of small particles that do not settle out.

Colloids are mixtures composed of particles that are intermediate in size between those of a solution and a suspension. These particles are typically between 1 and 1000 nanometers in diameter, which is too small to be seen with the eye, but large enough to scatter light, giving the mixture a cloudy or opaque appearance.

Milk, hair, spray, and paint are all examples of colloids.

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The mass of gas B is 32 grams .

The answer is next to the question. Do you mean gas A?

Answer:

Explanation:

The moles of water produced by the combustion of butane requires 3 steps.  The first is the primary challenge of this question:

1)  Balance the Reaction

 Write the reaction using just chemical formulas.  We know that a combustion reaction produces carbon dioxide and water, so let's start there:

  C4H10 + O2 = CO2 + H2O  

This looks correct - there are no elements that are just on one side (unaccounted for).  Now we need to balance the reaction.  Use pencil and paper for this step.  We can see that although butane consists of only two elements, carbon and oxygen, there are a lot of them.  It is often a good idea to find the most complex molecule and assign it a coefficient of 1 (in pencil), just to get started.

 a)  1C4H10 + O2 = CO2 + H2O  

Now distribute the atoms from butane to the products by assigning them coefficients:

  b)  1C4H10 + O2 = 4CO2 + H2O

The 4 carbons require that we add a coefficient of 4 to CO2, since it is the only possible destination for the carbons.  

The 10 hydrogens must all go to the H2O, so add a 5 to the H2O:

  c)  1C4H10 + O2 = 4CO2 + 5H2O

Now that the carbons and hydrogens are accounted for, work on the oxygens.  As written in c, there are 2 O atoms from the reactants, and (8+5) = 13 O atoms from the products.  This is an annoying outcome:  There will always be an even number of O atoms coming from the O2.  so there is no whole number we can add as the O2 coefficient that will produce an odd number of O atoms.  But an easy resolution is, temporarily, use a fraction for the number of O2 molecules.  If we use a coefficient of 6.5 for the O2, the equation will balance.

 d)  1C4H10 + 6.5O2 = 4CO2 + 5H2O

But we can't have 1/2 of a molecule, so let's multiply all coefficents by 2, so that they are all whole numbers:

 e)  2C4H10 + 13O2 = 8CO2 + 10H2O

That's why we use a pencil.

2.  Determine the molar ratio of the water to the butane

The important thing to note is that the balanced equation tells us that we should expect 10 moles of H2O for every 2 moles of C4H10, a molar ratio of 5/1 moles water/mole butane.  This is a conversion factor:  (5 moles H2O)/(1 mole C4H10)

3.  Find the moles of water produced

It took a while to get to this point, "but the end is near."  We are given 2.49x10^-2 moles of butane.  Simply multiply that times the molar ratio we derived above:

A lot of work for 2.24 grams of water.  I suggest finding a water fountain instead.