9. The exchange rate of a certain foreign currency with the Indian rupee is Rs 62.50.How much of the foreign currency can be had for Rs3125 ?

Answers

Answer 1

Answer

Rs. 3125 is equivalent to 50 units of the foreign currency.

Step-by-step Explanation

The exchange rate of the foreign currency in Indian Rupee is Rs. 62.50

This means that

1 unit of that foreign currency = Rs. 62.50

Or better written as

Rs. 62.50 = 1 unit of the foreign currency

So, we are then told to find how much Rs. 3125 is in the foreign currency

Let Rs. 3125 be equal to x units of the foreign currency

Rs. 62.50 = 1 unit of the foreign currency

Rs. 3125 = x units of the foreign currency

A simple mathematics relation obtained by cross multiplying will give us the value of x

After cross multiplying

62.50 × x = 3125 × 1

62.50x = 3125

Divide both sides by 62.50

(62.50x/62.50) = (3125/62.50)

x = 50

Therefore, Rs. 3125 is equivalent to 50 units of the foreign currency.

Hope this Helps!!!


Related Questions

13) An airline weighed the carry-on luggage of all its 1,106 passengers in a single day. How many of these passengers had carry-on luggage that weighed less than 20 lb? *

Answers

we know that

4 lb or less ------> is less than 20 lb ------> 120

5-9 lb------------> is less than 20 lb -------> 222

10-14 lb -------> is less than 20 lb ------->378

15-19 lb ------> is less than 20 lb-------> 256

Adds the number of passenger

120+222+378+256=976

thereforethe answer is 976

hello and thank you for helping me and this is a trigonometry question bit for the question has give exact value and it won't accept decimals as an answer and thank you for your time.

Answers

1) In this question let's calculate the sin(θ) and cos(θ)

Given that

[tex]\begin{gathered} \text{If }\sin (\theta)=\frac{5\pi}{4} \\ \sin (\theta)\text{ }\Rightarrow\sin (\frac{5\pi}{4})\text{ }=-\frac{\sqrt[]{2}}{2} \\ \cos (\frac{5\pi}{4})=-\frac{\sqrt[]{2}}{2} \end{gathered}[/tex]

2) In this question, we're calculating the value of the sine and the cosine in radians.

We must remember that 5π/4 ⇒ to 225º, and that it's in the Quadrant III

If we subtract

225 -180 =45 So the sine of 5π/4 is -√2/2 and the cosine (5π/4 ) = -√2/2

2.3) The sign of the Quadrant

Since 225º is in Quadrant III both results are negative ones.

If licorice costs $6.59 a pound, how much would it cost to buy a quarter-pound of licorice?


If a 10-foot piece of electrical tape has 0.037 feet cut from it. What is the new length of tape?


A director replayed 231 of the 1000 scenes filmed for a movie. Write a decimal to represent the part of the movie the director replayed.


If you had half a dollar, three quarters, eight dimes, six nickels, and nine pennies, how much money would you have altogether?


What is the combined thickness of these shims: 0.008, 0.125, 0.15, 0.185, and 0.005 cm?


All the people of a neighborhood pooled together and won the lottery. They won $10,000,000 and each person got a 0.02 share. How much money did each person receive?

Answers

Answer:

1. 1.6475.

2. 9.963.

3. 0.231

4. $1.69

5.  0.473 cm.

6. x = $200,000

Step-by-step explanation:

1.$6.59 ÷ 4 = 1.6475.

2. 10-0.037 = 9.963

3. 231 divided by 1000.

4. $0.50 + $0.80 + $0.30 + $0.09 = $1.69

5. 0.008 + 0.125 + 0.15 + 0.185 + 0.005

6. x =$10,000,000(0.02) where x is the amount of money each person will receive.  x=$200,000 (multiply)

A wheel is rotating 600 times per minute. Through how many degrees does a point in the edge of the wheel move in 1/2 seconds.

Answers

The wheel is rotating 600 times per minute, find how many times rotate in 1 second:

1 minute = 60 seconds

[tex]600\frac{times}{\min}\cdot\frac{1\min}{60s}=10\frac{times}{s}[/tex]

Then, if in 1 second it rotates 10 times in 1/2 seconds it rotates:

[tex]\frac{10\frac{times}{s}}{2}=5\text{times}[/tex]

Multiply the number of times it rotates (5 times) by 360 (a wheel has 360º)

[tex]5\text{times}\cdot\frac{360º}{1\text{time}}=1800º[/tex]Then, a point moves 1800º in 1/2 seconds

Use log, 20.356, log, 3 0.503, and log, 5 0.835 to approximate the value of the given logarithm to 3 decimal places. Assume that b>0 and b + 1.
log, 625
X
A

Answers

Answer:

3.34

Step-by-step explanation:

625 is 5^4

Using the log rule [tex]log_b(x^a)=alog_b(x)[/tex],

log_b(5^4) = 4*log_b(5)

4*0.835 = 3.34

How does a graph of quadratic function (f(x) = ax2 + bx + c) vary when the a,b, c changes from -1 to +1?

Answers

When a, b, c changes from -1 to +1, the parabolas opens and widens.

Given,

The quadratic function, f(x) = ax² + bx + c

We have to find the change in graph when a, b, c changes from -1 to 1.

First lets consider:

a and b as constants and c is varying.

That is,

x² + x + c

Then,  the parabola will move up and down.

Now, lets consider:

a and c as constants and b is varying.

That is,

x² + bx + 1

Then, the vertex will move but  all parabolas passes through the points (0, c)

Now, we can move to the question.

What happens to graph when +1 changes to -1.

So,

b and c should keep constant and a is varying.

Then,

ax² + x + 1

Here, the parabolas opens and widens.

That is,

When a, b, c changes from -1 to +1, the parabolas opens and widens.

Learn more about parabolas here:

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I need help with question 12 please in a hurry I understand already

Answers

Trigonometric Ratios

The figure is a triangle with hypotenuse of h = 25 feet. The angle of elevation is 35°.

hey i need help giving 10 points

Answers

Answer:

B(2) = -1

Step-by-step explanation:

Assuming each division on the grid is 1 unit

Locate 2 on the x-axis. That is two divisions to the right of the origin. The y value corresponding to this is -1

Can you help me solve my homework question I will follow along the steps

Answers

Notice that both fractions have the same denominator, therefore, we can simply add the numerators:

[tex]\frac{-5a-3x-2a+9x}{6a}.[/tex]

Adding like terms, we get:

[tex]\frac{-7a+6x}{6a}.[/tex]Answer: [tex]\begin{gathered} \frac{-7a+6x}{6a},\text{ or equivalently} \\ -\frac{7}{6}+\frac{x}{a}. \end{gathered}[/tex]

Prove that every differentiable function is continuous

Answers

To prove :

every differentiable function is continuous.

thus, every differentiable function is continuous.

(4,0) and (0,2) write an equation in standard form for the line that passes through the given points

Answers

We have the following:

The first thing is to find the slope of the line, like this:

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

replacing:

[tex]m=\frac{2-0}{0-4}=\frac{2}{-4}=-\frac{1}{2}[/tex]

now, the equation has the following form:

[tex]y=mx+b[/tex]

for b,

m = -1/2

y = 2

x = 0

replacing:

[tex]\begin{gathered} 2=-\frac{1}{2}\cdot0+b \\ b=2 \end{gathered}[/tex]

Therefore, the equation in standard form is:

[tex]\begin{gathered} y=-\frac{1}{2}x+2 \\ y+\frac{1}{2}x=2 \\ 2y+x=4 \end{gathered}[/tex]

Let log, A = 3; log, C = 2; log, D=5 D? what is the value of

Answers

Evaluate the value of expression.

[tex]\begin{gathered} \log _b\frac{D^2}{C^3A}=\log _bD^2-\log _bC^3-\log _bA \\ =2\log _bD-3\log _bC-\log _bA \\ =2\cdot5-3\cdot2-3 \\ =10-6-3 \\ =1 \end{gathered}[/tex]

So answer is 1.

A hiker on the Appalachian Trail planned to increase the distance covered by 10% each day. After 7 days, the total distance traveled is 75.897 miles.

Answers

part A. We are given that a hiker will increase the distance covered by 10% each day. Let "S" be the distance, then on the first day the distance is:

[tex]S_1[/tex]

On the second day, we must add 10% of the first day, we get:

[tex]S_1=S_1+\frac{10}{100}S_1[/tex]

Simplifying we get:

[tex]S_2=S_1+0.1S_1=1.1S_1[/tex]

On the third day, we add 10% of the second day, we get:

[tex]S_3=S_2+0.1S_2=1.1S_2=(1.1)(1.1)S_1=(1.1)^2S_1[/tex]

On the fourth day, we add 10% of the third day, we get:

[tex]S_4=S_3+0.1S_3=1.1S_3=(1.1)^3S_1[/tex]

If we continue this pattern and we set "n" as the number of days, then a formula for the distance after "n" days is:

[tex]S_n=(1.1)^{n-1}S_1[/tex]

Now, we are given that for n = 7 the distance is 75897, therefore, we substitute n = 7 in the formula:

[tex]S_7=(1.1)^{7-1}S_1[/tex]

Substituting the value of the distance:

[tex]75897=(1.1)^{7-1}S_1[/tex]

Now we can solve for S1, we do that by dividing both sides by 1.1 together with its

exponent:

[tex]\frac{75897}{(1.1)^{7-1}}=S_1[/tex]

Now we solve the operations:

[tex]\frac{75897}{(1.1)^6}=S_1[/tex]

Solving the operations:

[tex]42842=S_1[/tex]

Therefore, the distance the first day was 42842 miles.

part B. The formula for Sn is the given previously but we replace the known value of S1:

[tex]S_n=42842(1.1)^{n-1}[/tex]

Part C. To determine the distance after 10 days, we substitute the value n = 10 in the formula, we get:

[tex]S_{10}=42842(1.1)^{10-1}[/tex]

Solving the operations we get:

[tex]S_{10}=101019.19[/tex]

Therefore, the distance after 10 days is 101019.19 miles.

Put the following equation of a line into slope-intercept form, simplifying all fractions.
3y-3x=15

Answers

Answer:

[tex]y=x+5[/tex]

Step-by-step explanation:

[tex]3y-3x=15 \\ \\ y-x=5 \\ \\ y=x+5[/tex]

Which number can be inserted into the parentheses to make a true statement?-10°C<( )A. -12° CB. -18° CC. -3°CD. -10° C

Answers

Answer:

[tex]-3\degree C[/tex]

Explanation:

Here, we want to get the number that could be inserted into the parentheses to make it true

From the logical operator given, we can see that we need a number greater than -10

From the options given, only -3 is greater than -10, which makes it the correct answer choice

8x - 3x + 4x = -36x = ?

Answers

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

8x - 3x + 4x = -36

x = ?

Step 02:

We must apply the algebraic rules to find the solution.

8x - 3x + 4x = -36

12x - 3x = - 36

9x = - 36

x = - 36 / 9

x = - 4

The answer is:

x = - 4

In triangle ABC, angle A is 44 degrees and angle B is 76 degrees. What is the measure of the third angle?

Answers

Answer:

60 degrees

Step-by-step explanation:

Total of angles of a triangle is 180

180-76-44= 60

Complete a two-column algebraic proof.Given: x – 4 = (8x+6) + 4xProve: x = -1

Answers

To perform a two column proof, we should give a statement and give a reason of it.

So we start with the initial statement.

1. Statement: x-4 =(1/2)(8x+6)+4x. Reason: Given

Next, we distribute the multiplication (1/2) with(8x+6). If we do so, we get the following statement.

2. Statement x-4 = (4x+3) + 4x. Reason: Distributive property of addition and multiplication.

Now, on the right we can add 4x with 4x, due to the associative property of additon, we get

3. Statement: x-4 = (4x+4x)+3 = 8x+3. Reason: Associative property of addition.

Now, we can subtract x on both sides, so we get

4. Statement: -4 = 7x+3. Reason: Subtraction property of equality.

By the same reason, we should subtract 3 on both sides. We get

5. Statement: -7 = 7x. Reason: Subtraction property of equality.

Finally, we divide by 7 on both sides, so we get

6. Statement: -1=x. Reason: Division property of equality.

7. Statement: x=-1. Reason: Symmetric property of equality.

Select the three expressions that are equivalent to 410

Answers

Answer:

A, C, E

Step-by-step explanation:

4^10 = 1048576

A: (4^5)^2 = 1048576

C: 4^20 / 4^10 = 1048576

E: (4^2 x 4^3)^2 = 1048576

Which quadrant has ordered pairs (-x,-y)?

Answers

ANSWER

Quadrant III

STEP-BY-STEP EXPLANATION:

Firstly, we need to draw the cardinal points and label each quadrant on it

Looking at the ordered pair (-x, -y), you will see that the x and y-values both fall on the negative side of the x-ais and y-axis

Hence, it falls on the quadrant III

i need immediate help.The exercise consists of finding the axis of symmetry for the equation below.

Answers

Explanation

Our equation

[tex]y=\frac{1}{3}(x+2)^2-1,[/tex]

is a quadratic equation. In simple words, it's a parabola, whose graph (red curve) is the following:

The axis of symmetry of a parabola is just the line dividing the parabola into its two arms. In the graph, the axis of symmetry is the blue vertical line. It's usually represented algebraically by

[tex]x=\text{ The first component of the vertex}[/tex]

Answer

The axis of symmetry of our quadratic equation is

[tex]x=-2[/tex]

In which graph does the height difference between Winter Hill and Frozen Field equal the height of BlizzardRun?Choose 1 answer:605040Height (in meters)30.©20100Blizzard RunSnow SlopeWinter HillFrozen FieldSledding hill

Answers

In graph A, you can see that:

• The height of Frozen Field is 50 meters

,

• The height of Winter Hill is 15 meters

,

• The height of Blizzard Run is 35 meters

Now, we can write the equation that describes the height difference between Winter Hill and Frozen Field.

[tex]\text{ Height of Frozen Field }-\text{ Height of Winter Hill }=50m-15m=35m_{}=\text{ Height of Blizzard Run }[/tex]

In graph B, you can see that:

• The height of Frozen Field is 45 meters

• The height of Winter Hill is 10 meters

• The height of Blizzard Run is 55 meters

Now, we can write the equation that describes the height difference between Winter Hill and Frozen Field.

[tex]\text{ Height of Frozen Field }-\text{ Height of Winter Hill }=45m-10m=35m\ne55m_{}=\text{ Height of Blizzard Run }[/tex]

Therefore, the graph where the height difference between Winter Hill and Frozen Field is equal to the height of Blizzard Run is graph A.

use matrices D, E, and F to find each sum or product

Answers

Problem

Solution

5. E-D

Procedure

-3-2 =-5

-4-1=-5

0-7=-7

1-5=-4

2-3=-1

6- (-4)=10

And the answer would be:

-5 -5

-7 -4

-1 10

6. 3F

Procedure

3* -2=-6

3 *5 = 15

3* 1= 3

3*3 = 9

3*14=12

3 * -6= -18

And the answer would be:

-6 15 3

9 12 -18

distribute and simply 5(3x+1)-6x

Answers

[tex]\begin{gathered} \Rightarrow5(3x+1)-6x \\ \Rightarrow15x+5-6x \\ \Rightarrow9x+5 \end{gathered}[/tex]

Solve this system of linear equations. Separatethe x- and y-values with a comma.6x + 20y = -623x - 9y = -12Enter the correct answerDONE

Answers

Given the following systems of linear equations,

6x + 20y = -62 (Equation 1)

3x - 9y = -12 (Equation 2)

Step 1 : Solve 6x+20y=−62 for x:

6x + 20y + (−20y) = −62 + (−20y) (Add -20y to both sides)

6x = −20y −62

6x/6 = (−20y −62)/6 (Divide both sides by 6)

x = (-10y/3) + (-31/3)

Substitute to Equation 2:

3x−9y=−12

3[(-10y/3) + (-31/3)] - 9y = -12

−19y−31=−12 (Simplify both sides of the equation)

−19y−31+31=−12+31 (Add 31 to both sides)

−19y=19

-19y/-19 = 19/-19 (Divide both sides by -19)

y= −1

Step 2: Substitute −1 for y in x =(-10y/3) + (-31/3)

x =(-10(-1)/3) + (-31/3)

x = -7

Answer:

x=−7 and y=−1

Write a quadratic function in intercept form whose graph passes through the points (-5,0)(-1,0) and (-7,-24)

Answers

EXPLANATION

The intercept-form of a quadratic function is as follows:

y = a(x - p)(x - q)

Now, as the roots are (-5,0)

Since the parabola passes through the point (−5,0), then 0=25a−5b+c

Since the parabola passes through the point (−1,0), then 0=a−b+c.

Since the parabola passes through the point (−7,−24), then −24=49a−7b+c.

Thus, we have obtained the following system:

Solving it we get that a=−2, b=−12, c=−10.

Thus, the equation of the parabola is y=(−2x−10)(x+1)

Sketch the graph of each line.

24)

y=3/5x-4

Answers

The graph of the given line is attached below.

We are given the line:-

y = (3/5)x - 4

We will find the x and y intercepts of the line to plot in the graph.

As the equation is already in the slope intercept form, we can write,

The y-intercept of the line is -4.

Hence, the coordinates of the point will be (0,-4).

To find the x - intercept of the line we will put y = 0 in the given line.

0 = (3/5)x - 4

4 = 3x/5

x = 20/3

The coordinates of the point will be (20/3,0).

We can plot these points to get the desired graph.

To learn more about slope intercept form, here:-

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How to put 7^3/4 in radical form

Answers

Given:

[tex]7^{\frac{3}{4}}[/tex]

Resolving it to its radical form can be gotten based on the general laws of indices.

We have:

[tex]A^{\frac{x}{y}}=\sqrt[y]{A^x}[/tex]

I.e. the number is raised to the power of the numerator and then we get the denominator's root of the number obtained.

Thus:

[tex]\begin{gathered} 7^{\frac{3}{4}}=\sqrt[4]{7^3}=\sqrt[4]{343} \\ \sqrt[4]{343}=343^{\frac{1}{4}}=343^{(\frac{1}{2}\times\frac{1}{2})} \\ =343^{(\frac{1}{2}\times\frac{1}{2})}=\sqrt[]{343^{\frac{1}{2}}} \end{gathered}[/tex]

Now, we have our value in the square root form as:

[tex]\sqrt[]{343^{\frac{1}{2}}}=\sqrt[]{7^{\frac{3}{2}}}[/tex]

Walnuts make up half of the nuts in this nut bread:
It has exactly 2 pecans

The number of walnuts is double the number of pecans.
Write an equation to show how many of each nut this nut bread contains.

Answers

The equation to show how many of each nut this nut bread contains is w = 2p and there are 4 walnuts.

What is an equation?

A mathematical equation is the statement that illustrates that the variables given. In this case, two or more components are taken into consideration to describe the scenario.

The number of walnuts is double the number of pecans. This can be illustrated as:

w = 2p

Therefore, the number of buts will be:

w = 2p

w = 2(2)

w = 4

Therefore, ther are 4 walnuts

Learn more about equations on:

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I need help please. I don’t know what to do.Number 6

Answers

By definition, a relation is a function if each input value (x-value) has one and only one output value (y-value).

In this case, you have the following relation:

[tex]\mleft(1,5\mright)\mleft(3,1\mright)\mleft(5,0\mright)\mleft(-2,6\mright)[/tex]

Notice that each ordered pair has this form:

[tex](x,y)[/tex]

Where "x" is the input value and "y" is the output value.

You can identify that each input value has one and only output value. Therefore, you can conclude that this relation is a function.

Hence, the answer is: It is a function.

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