8CO + 17H2 → C8H18 + 8H2O

In this chemical reaction, how many grams of H2 will react completely with 6.50 moles of CO? Express your answer to three significant figures.

___ grams of H2 will react completely.

((27.6 IS NOT THE CORRECT ANSWER!!!!!)

The partial pressure of Oxygen in the mixture is 280 mmHg.

The Sum of the partial pressure of elements in a solution equals the total pressure of the mixture as stated by Dalton's Law.

Total pressure = Partial pressure of Nitrogen + Partial pressure of Oxygen

P' = P₁ + P₂

The partial pressure is the pressure that each gas would exert if it alone occupied the volume of the mixture at the same temperature.

The system responds to changes in pressure, temperature, and chemical composition, phases may be created, eliminated, or altered in composition.

∴ 490 = 210 + P ₂

P₂ = 280 mm of Hg

Hence, the partial pressure of oxygen gas is 280 mm Hg.

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In first place, the balanced reaction is:

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 84 grams of CO reacts with 159.7 grams of Fe₂O₃, 13.4 grams of CO reacts with how much mass of Fe₂O₃?

mass of Fe₂O₃= (13.4 grams of CO× 159.7 grams of Fe₂O₃)÷ 84 grams of CO

mass of Fe₂O₃= 25.476 grams

But 25.476 grams of Fe₂O₃ are not available, 11.7 grams are available. Since you have less mass than you need to react with 13.4 grams of CO, Fe₂O₃ will be the limiting reagent.

The theoretical yield is the maximum amount of product that could be formed from the given amounts of reagents.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 159.7 grams of Fe₂O₃ form 111.7 grams of Fe, 11.7 grams of Fe₂O₃ form how much mass of Fe?

mass of Fe= (11.7 grams of Fe₂O₃×111.7 grams of Fe) ÷159.7 grams of Fe₂O₃

mass of Fe= 8.183 grams

Then, the theoretical yield of Fe is 8.183 grams.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)×100%

In this case, you know:

Replacing in the definition of percent yield:

percent yield= (7 grams÷ 8.183 grams)×100%

Solving:

percent yield= 85.54%

Finally, the percent yield is 85.54%.

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Taking into account the reaction stoichiometry, a mass of 7.57 grams of MgBr₂ is formed when one grams of magnesium reacts with 5 g of bromine.

In first place, the balanced reaction is:

Mg  + Br₂ → MgBr₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction. When the limiting reagent is finished, the chemical reaction will stop.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 24.31 grams of Mg reacts with 159.8 grams of Br₂, 1 grams of Mg reacts with how much mass of Br₂?

mass of Br₂= (1 grams of Mg× 159.8 grams of Br₂) ÷24.31 grams of Mg

mass of Br₂= 6.57 grams

But 6.57 grams of Br₂ are not available, 5 grams are available. Since you have less mass than you need to react with 1 grams of Mg, Br₂ will be the limiting reagent.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 24.31 grams of Mg form 184.11 grams of MgBr₂, 1 grams of Mg form how much mass of MgBr₂?

mass of MgBr₂= (1 grams of Mg× 184.11 grams of MgBr₂)÷ 24.31 grams of Mg

mass of MgBr₂= 7.57 grams

Then, a mass of 7.57 grams of MgBr₂ can be produced.

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Answer: Physical - Color, density, boiling/melting point, magnetism, texture, and odor

Chemical - reactivity, combustibility, color change, and temperature change

Explanation:

Physical properties are changes to a substance that can be reversed and refer to its state at the time. Chemical properties are properties that are observable during or after a chemical reaction and cannot be reversed since the reaction has changed the state of the substance.

An example of disruptive selection because both extremes are favored to survive is a Selection for the homozygous dominant (AA).

The CCRS-delta 32 gene provided immunity to a deadly disease of bacterial origin, bubonic plague. People who are homozygous for the CCR5-della 32 gene variant are completely immune, while heterozygotes only have partial immunity and homozygous recessive have none is a Selection against the heterozygote and one homozygote.

Sickle cell disease - homozygous dominant contract malaria, homozygous recessive die young from sickle cell, heterozygotes immune to malaria is Selection for the heterozygote.

This type of selection will result in the extinction of the species as all genotypes are at a selective disadvantage is a Selection against all genotypes.

Huntington's disease is a single-gene disorder caused by a malfunctioning gene on chromosome 4. It is an autosomal dominant disease, which means that only one copy of the gene needs to be defective is a Selection against the heterozygote.

Homozygotes are organisms that have the same copy of alleles for a given trait. For example, if the allele for height is H and h where H is the allele for tallness while h is for short.

The genotype of the homozygotes will be HH or hh

Heterozygotes are organisms that have different copies of alleles for a given trait. For example, if the allele for height is H and h where H is the allele for tallness while h is for short.

The genotype of the heterozygotes will be Hh.

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Answer:

physical

Explanation:

HAVE GREAT DAY!

The type of adaptation shown by the dart frog is physiological adaptation while the one shown by the Hosta plant is structural adaptation.

Adaptation generally refers to the process by which living organisms adjust in order to continue to survive in an environment.

There are 3 main types of adaptations:

In behavioral adaptation, organisms change their behavior for their continued survival in their environments. Without these modifications, they may find it to survive and reproduce in the environment.

Physiological adaptation refers to changes that are encoded into the system of organisms. Changes that are not behavioral nor structural but ensure the continued survival of organisms in their environment.

Structural adaptation refers to the modification of physical structures for continued survival. These modifications become necessary because the environment keeps changing.

Thus, bright coloration as a warning to predators by the dart frog is a physiological adaptation while the development of big leaves that ensures that as much sunlight as possible is received by the Hosta plant is a structural adaptation.

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Answer:

2.068

Explanation:

D = M/V

3.04 /1.47

= 2.068

Answer:

c) It describes the affinity an atom has for an electron.

Explanation:

C quite literally describes what electronegativity is, you can rule out most others by looking at periodic trends as attached below.

        The difference between a kelvin (K), which is a division of the kelvin scale, and a degree on the Celsius scale is where zero is. The zero point on the Kelvin scale is at absolute zero, whereas the zero point on the Celsius scale is the freezing point of water. As a result, 0oK equals -273.15oC and 0oC equals 273.15 kelvins.

Answer : C.933.45K

         At 0 degrees Celsius, or 273 Kelvin, water freezes. Also, -273 degrees Celsius are the same as 0 Kelvin. Therefore, multiply the Celsius degree by 273 to convert it to Kelvin. And to convert from Kelvin to Celsius, just take 273 out.

Celsius to Kelvin conversion: Kelvin = Celsius + 273 1.5. The figure of 273 is also used instead of 273.15

Solution :

K = ° C + 273.15

K = 660.3 + 273.15

K = 933.45

Answer :660.3°C = 933.45k

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Answer: protons: 92

electrons: 92

1. neutrons: 234-92 = 142

2. Neutrons- 233-92 = 141

3. Neutrons 232-92= 140

Explanation:

If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

To calculated the average atomic mass, we have to multiply the isotopes mass of each to the % abundance  then  add .

the formula for the calculation of average atomic mass :

Average atomic mass = ∑ ( isotope mass  × % of abundance )

Thus, If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

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The atomic number of rubidium is 37, it means that its electron configuration is as follows:

Rubidium is an alkali metal. Its ion is formed when it loses an electron. It means that the rubidium ion has 36 electrons instead of 37, and its configuration is as follows:

Balanced chemical equation :

A balanced equation is a chemical reaction equation in which the total charge and the number of atoms for each element in the reaction are the same for both the reactants and the products.

Given Equation :

[tex]2NaOH_{}[/tex]  + [tex]CO_{2}[/tex] = [tex]Na_{2}CO_{3}[/tex]  + [tex]H_{2}O[/tex]

Here, we have 2 sodium (Na) atoms, 4 Oxygen (O) atoms, 2 Hydrogen (H) atoms and 1 Carbon (C) atom on the left hand side of the equation (reactants).

Also we have 2 sodium (Na) atoms, 4 Oxygen (O) atoms, 2 Hydrogen (H) atoms and 1 Carbon (C) atom on the right hand side of the equation (products).

Hence , the given equation, [tex]2NaOH_{}[/tex]  + [tex]CO_{2}[/tex] = [tex]Na_{2}CO_{3}[/tex]  + [tex]H_{2}O[/tex] is a balanced chemical equation.

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The incorrect statement is, "reaction rate is the speed at which the reaction proceeds towards equilibrium".

The rate of the reaction is defined as the rate at which the reaction is taking place.

It is true that the rate of reaction is governed by the energy barrier between the reactant and the products.

Enzymes are special compounds which can accelerate the rate of reaction.

The rate of reaction is independent of the rate of temperature of the system. The rate of reaction depends on the concentration of the reactants.

Rate of the reaction is directly proportional to the increase in concentration of products.

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Magnetic property of iron will help in seperating iron from rest of the materials.

Iron is a metal and have magnetic property. Magnetic property is property of metal in which metal has the attraction power to attract other metal. Iron is ferromagnetic but it requires certain temperature and certain conditions. It occurs below 770°C, which is curie temperature.

There are 5 magnetic properties

 types of magnetic materials

Diamagnetic Material,Paramagnetic Materials,Ferromagnetic Materials,Antiferromagnetic Materials,Ferrimagnetic Materials.

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First, let's write the balanced chemical reaction:

2 H2O2 ---MnO2--> 2 H2O + O2

This reaction is a b. Decomposition Reaction of hydrogen peroxide.

Step 1. Let's transform 2.11 mg of H2O2 into moles using the following equation mole = mass / molar mass

Step 2. We are going to use the equation proportion to calculate the quantity in moles of each compound.

Step 3. We are going to transform moles into grams of each compound using the following equation: mass = mole x molar mass

Step 1.

We need to transform 2.11 mg to g. We just need to divide by 1000,

So: 2.11 x 10^-3 g of H2O

mole = 2.11 x 10^-3/34.02

mole = 6.20 x 10^-5 moles

Step 2.

2 moles of H2O2 ---- 2 moles of H2O

6.20 x 10^-5 moles ---- x moles of H2O

x = 6.20 x 10^-5 moles of H2O

2 moles of H2O2 ---- 1 moles of O2

6.20 x 10^-5 moles ---- x moles of O2

x = 3.10 x 10^-5 moles of O2

Step 3.

molar mass of O2 : 32 g/mol

molar mass of H2O: 18 g/mol

mass of H2O = 6.20 x 10^-5 x 18 = 1.12 x 10^-3 g

mass of O2 = 3.10 x 10^-5 x 32 = 9.92 x 10^-4 g

It is better to use the analytical balance for smaller amounts of sodium hydroxide (up to a couple of grams).

The sensitivity of the analytical balance goes to a couple of tenths of a milligram, while the sensitivity of a top-loading balance goes to tens of milligrams at best. The amount of water absorbed by sodium hydroxide is significant, but not too great relative to the mass of the sample. With this in mind, it is far more recommendable to use the analytical balance over the top-loading balance in order to be able to register the change in mass at all.

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Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature. There is no force of attraction between the particles.

Mathematically the relation between Pressure and temperature can be given as

P₁M₁=DRT₁

P₂M₂=DRT₂

Rearranging the two equation we get

P₁M₁÷T₁=P₂M₂÷T₂

where,

P = pressure

M= Molarity

D=density

T =temperature

R = Gas constant = 0.0821 L.atm/K.mol

Substituting all the given values, we get

(P₁×M₁)÷T₁=(P₂×M₂)÷T₂

(P₁×20)÷303=(1.0 ×28)÷293

P₁=1.44atm

Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.

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Answer

%Yield = 87.2%

Explanation

Given:

mass of NH3 reacted = 73 g

mass of H2O produced = 101 g

We know:

molar mass of NH3 = 17,031 g/mol

molar mass of water = 18.01528 g/mol

Required: % Yield

Solution:

The formula used to calculate the percentage yield is:

%Yield = (actual yield/theoretical yield) x 100

The actual yield of H2O produced = 101 g

Now lets calculate the theoretical yield first.

First find the number of moles of NH3, and use stoichiometry to find the theoretical mass of water.

n = m/M n is the moles, m is the mass and M is the molar mass.

n = 73/17,031 g/mol

n = 4.29 mol

Using the stoichiometry, there molar ratio between NH3 and H2O is 4:6

Therefore the moles of H2O = 4.29 x (6/4)

n of H2O = 6.43 mol

The theoretical mass can then be calculated:

m = n x M

m = 6.43 mol x 18.01528 g/mol

m = 115.83 g

%Yield = (101 g/115.83)*100

%Yield = 87.2%

By using the balanced reaction equation of ethane combustion, we can calculate that 12.8 L of carbon dioxide will be produced.

To calculate the answer to this, we need to write the balanced reaction equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Based on this, we can see that 2 moles of ethane produce 4 moles of carbon dioxide. Now, we need to calculate the number of moles (n) of ethane using its mass (m = 8.00 g) and its molar mass (M = 30.07 g/mol):

n = m/M

n = 8.00 g / 30.07 g/mol

n = 0.266 mol

Based on this, we can conclude that 2 * 0.266 mol = 0.532 mol of carbon dioxide was produced. Assuming that carbon dioxide acts as an ideal gas, we can use the ideal gas equation to calculate its volume:

PV = nRT ⇒ V = nRT/P

V - the volume of the gas

n - number of moles of gas (0.523 mol)

R - universal gas constant (0.08206 L*atm/K*mol)

T - temperature in Kelvins (25 °C = 298.15 K)

P - pressure (1.00 atm)

Now we plug all the known values into the equation:

V = 0.523 mol * 0.08206 L*atm/K*mol * 298.15 K / 1.00 atm

V = 12.8 L

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Answer:

see the explanation

Explanation:

1. IV

2. VI

3. II

4. IV

5. II

6. VI

7. IV

8. III

9. II

10. I

11. I

12. V

13. VII

14. III

15. I

16. III

17. V

18. IV

19. V

20. III

21. IV

22. III

23. IV

24. VII

25. II

26. II

27. III

Answer:

freezing points hope it helps u

Distillation is a process used to separate a mixture of liquids based on different freezing points. Therefore, option C is correct.

Distillation is the process of turning a liquid into a vapor, which is then condensed back into a liquid state. The simplest illustration of it is when steam from a kettle condenses into drops of distilled water that are left on a cold surface.

In general, distillation is the process of vaporizing a liquid to its boiling point, then condensing it back into a liquid to separate it from impurities or other solutes.

Among the many industrial uses of distillation are the production of alcoholic drinks, water purification, and oil refining. Distillation is a physical procedure that removes desired pure compounds from an initial source using heat and other techniques.

Thus, option C is correct.

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The second element in group 2 has an atomic number of 12.

We can describe atomic number as the number of protons that are present in the nucleus of an atom. The number of protons is equal to the number of electrons, hence the atomic number is the number of protons or the number of electrons in an atom.

Beryllium has an atomic number of 4 because the element Beryllium has 4 protons.

In the periodic table, you will find that the second element in group 2 is Magenium. The atomic number of Magnesium is 12 because Magnesium has 12 protons in the nucleus of its atom.

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Answer: v = 0.70 ml

Explanation:

1. We can use the Density equation

(d = density (g/ml), m = mass (g), v = volume (ml))

D = m/v

2. Plug in what we have and solve for v.

2.7 = 1.9/v

v = 0.70 ml

The molecular formula of diazomethane is CH₂N₂, and the main reason for its instability is precisely the fact that it can very easily evolve nitrogen, as nitrogen's triple bond is one of the strongest covalent bonds in nature, and the energy released in its formation is more than enough to compensate the energy lost in the breaking of C-N bonds. The Lewis structure of diazomethane with the formal charges is attached below.

To obtain the molecular formula of diazomethane, we can imagine that we have 100 g of it. Now we can calculate the number of moles (n) for each of the elements, using their respective masses (m) and molar masses (M = 12 g/mol for carbon, 1 g/mol for hydrogen, and 14 g/mol for nitrogen):

n = m/M

n(C) = 28.57 g / 12 g/mol

n(C) = 2.38 mol

n(H) = 4.80 g / 1 g/mol

n(H) = 4.80 mol

n(N) = 66.64 g / 14 g/mol

n(N) = 4.76 mol

We now divide each of these numbers with the smallest of them (2.38) to calculate the molar ratio of the elements:

carbon: 2.38 / 2.38 = 1

hydrogen: 4.80 / 2.38 = 2

nitrogen: 4.76 / 2.38 = 2

Now we use these numbers to get the empirical formula of diazomethane: CH₂N₂.

The molar mass of the empirical formula is:

12 g/mol + 2 * 1 g/mol + 2 * 14 g/mol = 42 g/mol

Since this value is equal to the molar mass given to us, that means that CH₂N₂ is also the molecular formula of diazomethane.

The molarity of the chemical X is 11.65 M.

To calculate the molarity (c) of the solution, we need the number of moles (n) of substance X and the volume (V) of the solution. We can assume that we have 100 mL = 0.1 L of the solution. Now we have the volume, and we can use it to calculate the mass (m) of the solution using its density (d = 1.18 g/mL):

d = m/V ⇒ m = d * V

m = 1.18 g/mL * 100 mL

m(solution) = 118 g

From this, we can obtain the mass of substance X using the mass percentage (%w = 36% = 0.36):

m(X) = %w * m(solution)

m(X) = 0.36 * 118 g

m(X) = 42.48 g

Now that we have the mass of X, we divide it by its molar mass (M = 36.46 g/mol) to obtain the number of moles:

n = m/M

n = 42.48 g / 36.46 g/mol = 1.165 mol

Finally, we calculate the molarity of the solution:

c = n/V

c = 1.165 mol / 0.1 L = 11.65 M

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The number of moles added to increase the volume of the gas from 8.51 L to 15.5 L is 8.67 moles.

The initial volume of the gas is 8.15 L and final volume of gas is 15.5 L and the initial moles are 9.51 moles.

As per the Ideal gas equation,

PV = nRT

where,

P is pressure,

V is volume of gas,

n is the number of moles of gas,

R is the gas constant,

T is the temperature of the gas.

Rearranging the equation,

V/n = RT/P

The left side is constant, so, it is valid to see,

V₁/n₁ = V₂/n₂

V₁ is initial volume,

n₁ is the initial moles,

V₂ is the final volume,

n₂ is the final moles.

So, we can write this by putting the values,

8.51/(9.5) = 15.5/n₂

n₂ = 18.17

The number of moles added = n₁ - n₂

Added moles = 8.67 moles

The moles added are 8.67 moles.

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The heat released by metal and added to water is the same which is 1039.83 joule.

The equilibrium condition of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow

Q released = Q received

The heat can be defined by

Q = m . c . ΔT

where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.

The given parameters are

m = 17.27 g = 0.01727 kf

T1 = 92 ⁰C

T2 = 25.1 ⁰C

c = 900 J/kg⁰C

By substituting the given parameters, we can calculate the heat

Q = m . c . ΔT

Q = 0.01727 . 900 . (92 - 25.1)

Q = 1039.83 joule

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The classification of the given processes as either physical changes (PC), chemical changes (CC), physical properties (PP), and chemical properties (CP): is as follows:

Physical changes are changes that occur in a substance that are easily reversible and only affect the physical properties of that substance.

In physical changes, no new substances are formed.

Some physical properties that may change in physical changes are color, taste, volume, mass, physical state, etc.

Chemical changes are changes that occur in a substance that are not easily reversible and which affect the chemical properties of that substance.

In chemical changes, new substances are formed.

Some chemical properties that may change in physical changes are oxidation state, combustibility, etc.

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