8. 00 g of ethane gas, c2h6, is burned in oxygen. What volume of carbon dioxide gas is produced at 1. 00 atm and 25. 0°c?.

Answer:

freezing points hope it helps u

Distillation is a process used to separate a mixture of liquids based on different freezing points. Therefore, option C is correct.

Distillation is the process of turning a liquid into a vapor, which is then condensed back into a liquid state. The simplest illustration of it is when steam from a kettle condenses into drops of distilled water that are left on a cold surface.

In general, distillation is the process of vaporizing a liquid to its boiling point, then condensing it back into a liquid to separate it from impurities or other solutes.

Among the many industrial uses of distillation are the production of alcoholic drinks, water purification, and oil refining. Distillation is a physical procedure that removes desired pure compounds from an initial source using heat and other techniques.

Thus, option C is correct.

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An example of disruptive selection because both extremes are favored to survive is a Selection for the homozygous dominant (AA).

The CCRS-delta 32 gene provided immunity to a deadly disease of bacterial origin, bubonic plague. People who are homozygous for the CCR5-della 32 gene variant are completely immune, while heterozygotes only have partial immunity and homozygous recessive have none is a Selection against the heterozygote and one homozygote.

Sickle cell disease - homozygous dominant contract malaria, homozygous recessive die young from sickle cell, heterozygotes immune to malaria is Selection for the heterozygote.

This type of selection will result in the extinction of the species as all genotypes are at a selective disadvantage is a Selection against all genotypes.

Huntington's disease is a single-gene disorder caused by a malfunctioning gene on chromosome 4. It is an autosomal dominant disease, which means that only one copy of the gene needs to be defective is a Selection against the heterozygote.

Homozygotes are organisms that have the same copy of alleles for a given trait. For example, if the allele for height is H and h where H is the allele for tallness while h is for short.

The genotype of the homozygotes will be HH or hh

Heterozygotes are organisms that have different copies of alleles for a given trait. For example, if the allele for height is H and h where H is the allele for tallness while h is for short.

The genotype of the heterozygotes will be Hh.

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        The difference between a kelvin (K), which is a division of the kelvin scale, and a degree on the Celsius scale is where zero is. The zero point on the Kelvin scale is at absolute zero, whereas the zero point on the Celsius scale is the freezing point of water. As a result, 0oK equals -273.15oC and 0oC equals 273.15 kelvins.

Answer : C.933.45K

         At 0 degrees Celsius, or 273 Kelvin, water freezes. Also, -273 degrees Celsius are the same as 0 Kelvin. Therefore, multiply the Celsius degree by 273 to convert it to Kelvin. And to convert from Kelvin to Celsius, just take 273 out.

Celsius to Kelvin conversion: Kelvin = Celsius + 273 1.5. The figure of 273 is also used instead of 273.15

Solution :

K = ° C + 273.15

K = 660.3 + 273.15

K = 933.45

Answer :660.3°C = 933.45k

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Answer: Physical - Color, density, boiling/melting point, magnetism, texture, and odor

Chemical - reactivity, combustibility, color change, and temperature change

Explanation:

Physical properties are changes to a substance that can be reversed and refer to its state at the time. Chemical properties are properties that are observable during or after a chemical reaction and cannot be reversed since the reaction has changed the state of the substance.

Balanced chemical equation :

A balanced equation is a chemical reaction equation in which the total charge and the number of atoms for each element in the reaction are the same for both the reactants and the products.

Given Equation :

[tex]2NaOH_{}[/tex]  + [tex]CO_{2}[/tex] = [tex]Na_{2}CO_{3}[/tex]  + [tex]H_{2}O[/tex]

Here, we have 2 sodium (Na) atoms, 4 Oxygen (O) atoms, 2 Hydrogen (H) atoms and 1 Carbon (C) atom on the left hand side of the equation (reactants).

Also we have 2 sodium (Na) atoms, 4 Oxygen (O) atoms, 2 Hydrogen (H) atoms and 1 Carbon (C) atom on the right hand side of the equation (products).

Hence , the given equation, [tex]2NaOH_{}[/tex]  + [tex]CO_{2}[/tex] = [tex]Na_{2}CO_{3}[/tex]  + [tex]H_{2}O[/tex] is a balanced chemical equation.

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Experimental pH indicates the pH obtained by directly measuring a specific sample with a pH meter.

The main difference between calculated and experimental pH is that calculated pH gives the pH obtained by solving the pH equation whereas experimental pH is measured directly with a pH meter. It is to indicate the value of a particular sample obtained.

Because microorganisms such as bacteria are sensitive to the concentration of hydrogen ions present in the environment, pH results will change over the course of an experiment. pH is affected by larger proteins, including enzymes. pH is a quantitative measure of the acidity or basicity of a solution while acidity is a qualitative measure of the acidic properties of a solution.

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If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

To calculated the average atomic mass, we have to multiply the isotopes mass of each to the % abundance  then  add .

the formula for the calculation of average atomic mass :

Average atomic mass = ∑ ( isotope mass  × % of abundance )

Thus, If you assumed 100 total atoms in a sample, you could relate the % values shown in the sim into a number you could use for your calculation of average atomic mass is

Average atomic mass = ∑ ( isotope mass  × % of abundance )

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The second element in group 2 has an atomic number of 12.

We can describe atomic number as the number of protons that are present in the nucleus of an atom. The number of protons is equal to the number of electrons, hence the atomic number is the number of protons or the number of electrons in an atom.

Beryllium has an atomic number of 4 because the element Beryllium has 4 protons.

In the periodic table, you will find that the second element in group 2 is Magenium. The atomic number of Magnesium is 12 because Magnesium has 12 protons in the nucleus of its atom.

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By using the balanced reaction equation of ethane combustion, we can calculate that 12.8 L of carbon dioxide will be produced.

To calculate the answer to this, we need to write the balanced reaction equation:

2C₂H₆ + 7O₂ → 4CO₂ + 6H₂O

Based on this, we can see that 2 moles of ethane produce 4 moles of carbon dioxide. Now, we need to calculate the number of moles (n) of ethane using its mass (m = 8.00 g) and its molar mass (M = 30.07 g/mol):

n = m/M

n = 8.00 g / 30.07 g/mol

n = 0.266 mol

Based on this, we can conclude that 2 * 0.266 mol = 0.532 mol of carbon dioxide was produced. Assuming that carbon dioxide acts as an ideal gas, we can use the ideal gas equation to calculate its volume:

PV = nRT ⇒ V = nRT/P

V - the volume of the gas

n - number of moles of gas (0.523 mol)

R - universal gas constant (0.08206 L*atm/K*mol)

T - temperature in Kelvins (25 °C = 298.15 K)

P - pressure (1.00 atm)

Now we plug all the known values into the equation:

V = 0.523 mol * 0.08206 L*atm/K*mol * 298.15 K / 1.00 atm

V = 12.8 L

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Answer:

see the explanation

Explanation:

1. IV

2. VI

3. II

4. IV

5. II

6. VI

7. IV

8. III

9. II

10. I

11. I

12. V

13. VII

14. III

15. I

16. III

17. V

18. IV

19. V

20. III

21. IV

22. III

23. IV

24. VII

25. II

26. II

27. III

In first place, the balanced reaction is:

Fe₂O₃ + 3 CO → 2 Fe + 3 CO₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The limiting reagent is one that is consumed first in its entirety, determining the amount of product in the reaction.

To determine the limiting reagent, it is possible to use a simple rule of three as follows: if by stoichiometry 84 grams of CO reacts with 159.7 grams of Fe₂O₃, 13.4 grams of CO reacts with how much mass of Fe₂O₃?

mass of Fe₂O₃= (13.4 grams of CO× 159.7 grams of Fe₂O₃)÷ 84 grams of CO

mass of Fe₂O₃= 25.476 grams

But 25.476 grams of Fe₂O₃ are not available, 11.7 grams are available. Since you have less mass than you need to react with 13.4 grams of CO, Fe₂O₃ will be the limiting reagent.

The theoretical yield is the maximum amount of product that could be formed from the given amounts of reagents.

Considering the limiting reagent, the following rule of three can be applied: if by reaction stoichiometry 159.7 grams of Fe₂O₃ form 111.7 grams of Fe, 11.7 grams of Fe₂O₃ form how much mass of Fe?

mass of Fe= (11.7 grams of Fe₂O₃×111.7 grams of Fe) ÷159.7 grams of Fe₂O₃

mass of Fe= 8.183 grams

Then, the theoretical yield of Fe is 8.183 grams.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

percent yield= (actual yield÷ theoretical yield)×100%

In this case, you know:

Replacing in the definition of percent yield:

percent yield= (7 grams÷ 8.183 grams)×100%

Solving:

percent yield= 85.54%

Finally, the percent yield is 85.54%.

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Answer: protons: 92

electrons: 92

1. neutrons: 234-92 = 142

2. Neutrons- 233-92 = 141

3. Neutrons 232-92= 140

Explanation:

The atomic number of rubidium is 37, it means that its electron configuration is as follows:

Rubidium is an alkali metal. Its ion is formed when it loses an electron. It means that the rubidium ion has 36 electrons instead of 37, and its configuration is as follows:

The classification of the given processes as either physical changes (PC), chemical changes (CC), physical properties (PP), and chemical properties (CP): is as follows:

Physical changes are changes that occur in a substance that are easily reversible and only affect the physical properties of that substance.

In physical changes, no new substances are formed.

Some physical properties that may change in physical changes are color, taste, volume, mass, physical state, etc.

Chemical changes are changes that occur in a substance that are not easily reversible and which affect the chemical properties of that substance.

In chemical changes, new substances are formed.

Some chemical properties that may change in physical changes are oxidation state, combustibility, etc.

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The correct answer is that a) covalent bonds need to form between molecules. The process of polymerization to polybutene doesn't require any of the other given transformations.

The polymerization process of 1-butene to polybutene includes the homolytic cleavage of the double bond and the formation of new covalent bonds between the radical formed and another molecule of 1-butene. This means that there is no need for oxidation (option b), formation of additional double bonds (option c, although the resulting molecule could also undergo polymerization, but it would not result in the formation of polybutene), or exchange of hydrogen atoms between the molecules (option d).

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Answer: A. Covalent bonds would need to form between the molecules.

Explanation: Got 100 on edmentum

First, let's write the balanced chemical reaction:

2 H2O2 ---MnO2--> 2 H2O + O2

This reaction is a b. Decomposition Reaction of hydrogen peroxide.

Step 1. Let's transform 2.11 mg of H2O2 into moles using the following equation mole = mass / molar mass

Step 2. We are going to use the equation proportion to calculate the quantity in moles of each compound.

Step 3. We are going to transform moles into grams of each compound using the following equation: mass = mole x molar mass

Step 1.

We need to transform 2.11 mg to g. We just need to divide by 1000,

So: 2.11 x 10^-3 g of H2O

mole = 2.11 x 10^-3/34.02

mole = 6.20 x 10^-5 moles

Step 2.

2 moles of H2O2 ---- 2 moles of H2O

6.20 x 10^-5 moles ---- x moles of H2O

x = 6.20 x 10^-5 moles of H2O

2 moles of H2O2 ---- 1 moles of O2

6.20 x 10^-5 moles ---- x moles of O2

x = 3.10 x 10^-5 moles of O2

Step 3.

molar mass of O2 : 32 g/mol

molar mass of H2O: 18 g/mol

mass of H2O = 6.20 x 10^-5 x 18 = 1.12 x 10^-3 g

mass of O2 = 3.10 x 10^-5 x 32 = 9.92 x 10^-4 g

Answer

%Yield = 87.2%

Explanation

Given:

mass of NH3 reacted = 73 g

mass of H2O produced = 101 g

We know:

molar mass of NH3 = 17,031 g/mol

molar mass of water = 18.01528 g/mol

Required: % Yield

Solution:

The formula used to calculate the percentage yield is:

%Yield = (actual yield/theoretical yield) x 100

The actual yield of H2O produced = 101 g

Now lets calculate the theoretical yield first.

First find the number of moles of NH3, and use stoichiometry to find the theoretical mass of water.

n = m/M n is the moles, m is the mass and M is the molar mass.

n = 73/17,031 g/mol

n = 4.29 mol

Using the stoichiometry, there molar ratio between NH3 and H2O is 4:6

Therefore the moles of H2O = 4.29 x (6/4)

n of H2O = 6.43 mol

The theoretical mass can then be calculated:

m = n x M

m = 6.43 mol x 18.01528 g/mol

m = 115.83 g

%Yield = (101 g/115.83)*100

%Yield = 87.2%

Answer:

2.068

Explanation:

D = M/V

3.04 /1.47

= 2.068

Answer:

c) It describes the affinity an atom has for an electron.

Explanation:

C quite literally describes what electronegativity is, you can rule out most others by looking at periodic trends as attached below.

The type of adaptation shown by the dart frog is physiological adaptation while the one shown by the Hosta plant is structural adaptation.

Adaptation generally refers to the process by which living organisms adjust in order to continue to survive in an environment.

There are 3 main types of adaptations:

In behavioral adaptation, organisms change their behavior for their continued survival in their environments. Without these modifications, they may find it to survive and reproduce in the environment.

Physiological adaptation refers to changes that are encoded into the system of organisms. Changes that are not behavioral nor structural but ensure the continued survival of organisms in their environment.

Structural adaptation refers to the modification of physical structures for continued survival. These modifications become necessary because the environment keeps changing.

Thus, bright coloration as a warning to predators by the dart frog is a physiological adaptation while the development of big leaves that ensures that as much sunlight as possible is received by the Hosta plant is a structural adaptation.

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The Ka value of a protonated base is the acid ionization constant. Which can be calculated from the concentration of H+ ion and the conjugate base. The ka value of protonated urea of the given pH is 7.92 ×10⁻¹⁵.

pH of a solution is the measure of its H+ ion concentration. It is says how much acidic or basic the solution is. If the pH value is 7, then the solution is neutral and if it is less than 7 the solution is acidic. pH value greater than 7 indicates that the solution is basic.

pH of a solution mathematically is the negative logarithm of H+ ion concentration. Given that the pH of urea solution is 7.050. Thus its H+ ion concentration is calculated as follows;

-7.050 = log [H+]

[H+] = antilog (-7.050)

       = 8.9 × 10⁻⁸

Now when the protonated urea say it as HA is dissociated into its ions H+ and A-, then the ka value is written as;

[tex]Ka = \frac{[H+][A-]}{[HA]}[/tex]

Here, the [H+] and A- ion concentrations are equal and concentration of the solution HA is given 1 M.

Thus, Ka value of protonated urea can be calculated as follows:

Ka =  (8.9 × 10⁻⁸)² / (1-[ 8.9 × 10⁻⁸])

    = 7.92 ×10⁻¹⁵

Therefore, the acid ionization constant Ka of 1 M protonated urea with a pH of 7.050 is 7.92 ×10⁻¹⁵.

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The number of moles added to increase the volume of the gas from 8.51 L to 15.5 L is 8.67 moles.

The initial volume of the gas is 8.15 L and final volume of gas is 15.5 L and the initial moles are 9.51 moles.

As per the Ideal gas equation,

PV = nRT

where,

P is pressure,

V is volume of gas,

n is the number of moles of gas,

R is the gas constant,

T is the temperature of the gas.

Rearranging the equation,

V/n = RT/P

The left side is constant, so, it is valid to see,

V₁/n₁ = V₂/n₂

V₁ is initial volume,

n₁ is the initial moles,

V₂ is the final volume,

n₂ is the final moles.

So, we can write this by putting the values,

8.51/(9.5) = 15.5/n₂

n₂ = 18.17

The number of moles added = n₁ - n₂

Added moles = 8.67 moles

The moles added are 8.67 moles.

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The molarity of the chemical X is 11.65 M.

To calculate the molarity (c) of the solution, we need the number of moles (n) of substance X and the volume (V) of the solution. We can assume that we have 100 mL = 0.1 L of the solution. Now we have the volume, and we can use it to calculate the mass (m) of the solution using its density (d = 1.18 g/mL):

d = m/V ⇒ m = d * V

m = 1.18 g/mL * 100 mL

m(solution) = 118 g

From this, we can obtain the mass of substance X using the mass percentage (%w = 36% = 0.36):

m(X) = %w * m(solution)

m(X) = 0.36 * 118 g

m(X) = 42.48 g

Now that we have the mass of X, we divide it by its molar mass (M = 36.46 g/mol) to obtain the number of moles:

n = m/M

n = 42.48 g / 36.46 g/mol = 1.165 mol

Finally, we calculate the molarity of the solution:

c = n/V

c = 1.165 mol / 0.1 L = 11.65 M

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Answer:

physical

Explanation:

HAVE GREAT DAY!

The heat released by metal and added to water is the same which is 1039.83 joule.

The equilibrium condition of the system depends on the heat released from both gold and water. The total heat received by the system will equal to total heat released by objects. It should follow

Q released = Q received

The heat can be defined by

Q = m . c . ΔT

where Q is heat, m is mass, c is the specific heat constant and ΔT is the change in temperature.

The given parameters are

m = 17.27 g = 0.01727 kf

T1 = 92 ⁰C

T2 = 25.1 ⁰C

c = 900 J/kg⁰C

By substituting the given parameters, we can calculate the heat

Q = m . c . ΔT

Q = 0.01727 . 900 . (92 - 25.1)

Q = 1039.83 joule

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Ideal gas law is valid only for ideal gas not for vanderwaal gas. Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.

Ideal gas equation is the mathematical expression that relates pressure volume and temperature. There is no force of attraction between the particles.

Mathematically the relation between Pressure and temperature can be given as

P₁M₁=DRT₁

P₂M₂=DRT₂

Rearranging the two equation we get

P₁M₁÷T₁=P₂M₂÷T₂

where,

P = pressure

M= Molarity

D=density

T =temperature

R = Gas constant = 0.0821 L.atm/K.mol

Substituting all the given values, we get

(P₁×M₁)÷T₁=(P₂×M₂)÷T₂

(P₁×20)÷303=(1.0 ×28)÷293

P₁=1.44atm

Therefore, the pressure that will be required for neon at 30°C to have the same density as nitrogen at 20°C and 1.0 atm is 1.44atm.

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Once chewed and swallowed, the food will be digested and absorbed nutrients, while the rest of the food will be excreted through the body's feces. This digestion process can take about 24-72 hours.

The process of digestion of food in humans can be divided into two types, namely mechanical digestion and chemical (enzymatic) digestion. Mechanical digestion is the process of changing food from a large or coarse form to a smaller or finer form. The process takes place in the mouth with the help of teeth and tongue. The mechanical digestion process also occurs in the stomach with the help of peristaltic motion of the stomach wall, so that food is like being stirred. While the chemical digestion process is the process of converting food substances from complex forms into simpler forms with the help of digestive enzymes.

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The molecular formula of diazomethane is CH₂N₂, and the main reason for its instability is precisely the fact that it can very easily evolve nitrogen, as nitrogen's triple bond is one of the strongest covalent bonds in nature, and the energy released in its formation is more than enough to compensate the energy lost in the breaking of C-N bonds. The Lewis structure of diazomethane with the formal charges is attached below.

To obtain the molecular formula of diazomethane, we can imagine that we have 100 g of it. Now we can calculate the number of moles (n) for each of the elements, using their respective masses (m) and molar masses (M = 12 g/mol for carbon, 1 g/mol for hydrogen, and 14 g/mol for nitrogen):

n = m/M

n(C) = 28.57 g / 12 g/mol

n(C) = 2.38 mol

n(H) = 4.80 g / 1 g/mol

n(H) = 4.80 mol

n(N) = 66.64 g / 14 g/mol

n(N) = 4.76 mol

We now divide each of these numbers with the smallest of them (2.38) to calculate the molar ratio of the elements:

carbon: 2.38 / 2.38 = 1

hydrogen: 4.80 / 2.38 = 2

nitrogen: 4.76 / 2.38 = 2

Now we use these numbers to get the empirical formula of diazomethane: CH₂N₂.

The molar mass of the empirical formula is:

12 g/mol + 2 * 1 g/mol + 2 * 14 g/mol = 42 g/mol

Since this value is equal to the molar mass given to us, that means that CH₂N₂ is also the molecular formula of diazomethane.

The incorrect statement is, "reaction rate is the speed at which the reaction proceeds towards equilibrium".

The rate of the reaction is defined as the rate at which the reaction is taking place.

It is true that the rate of reaction is governed by the energy barrier between the reactant and the products.

Enzymes are special compounds which can accelerate the rate of reaction.

The rate of reaction is independent of the rate of temperature of the system. The rate of reaction depends on the concentration of the reactants.

Rate of the reaction is directly proportional to the increase in concentration of products.

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The partial pressure of Oxygen in the mixture is 280 mmHg.

The Sum of the partial pressure of elements in a solution equals the total pressure of the mixture as stated by Dalton's Law.

Total pressure = Partial pressure of Nitrogen + Partial pressure of Oxygen

P' = P₁ + P₂

The partial pressure is the pressure that each gas would exert if it alone occupied the volume of the mixture at the same temperature.

The system responds to changes in pressure, temperature, and chemical composition, phases may be created, eliminated, or altered in composition.

∴ 490 = 210 + P ₂

P₂ = 280 mm of Hg

Hence, the partial pressure of oxygen gas is 280 mm Hg.

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