7) What is the volume of the liquid in graduated cylinder A before the rockwas added?AYour answer8060BE10080★8 points

7) What Is The Volume Of The Liquid In Graduated Cylinder A Before The Rockwas Added?AYour Answer8060BE100808

Answers

Answer 1

To read the measuring cylinder we first count the number of smaller divisions between the marked interval. In this case it is 10 intervals. The marked intervals are 60 and 80, therefore between these values we have 20. We will now divide the 20 by the 10 intervalswhich is equal to 2. Now each interval has a numerical value of 2. We read from the bottom of the meniscus. The meniscus is ttouching the 5th line and so we say 5 x 2=10, we add this to 60.

Answer: 60+10= 70,


Related Questions

Describe global influences on local
weather.

Answers

Some global influences that effect local weather would be global warming. Due to amount of human activity including burning fossil fuel, more of the ice in Greenland, Antartica, and the Arctic are melting. The effect of the melting ice is sea levels to rise, and mountain glaciers to shrink. Locally it has been shifting the season and making hotter summers and colder winters.

How many moles of chromium metal, Cr, are in a 260 gram piece of chromium?

Answers

In order to answer this question we will use the molar mass of Chromium, which is 52 g/mol, that means that in every 1 mol of Cr, we will have 52 grams of it:

52 g = 1 mol

260 g = x moles

52x = 260

x = 5 moles of Chromium

Ascorbic acid (vitamin C) is important in many metabolic reactions in the body, including the synthesis of collagen and prevention of scurvy. Given that themass percent composition of ascorbic acid is 40.9% C, 4.58% H, and 54.5% O, determine the empirical formula of ascorbic acid. Show all your work

Answers

Empirical formula:

Step 1

Information already provided

The mass percent composition:

40.9 % C

4.58 % H

54.5 % O

Information needed: from the periodic table

For C) 1 mol = 12.01 g

For H) 1 mol = 1.008 g

For O) 1 mol = 15.99 g

---------------------------

Step 2

A sample of 100 g is assumed, so:

40.9 % C => 40.9 g C

4.58 % H => 4.58 g H

54.5 % O => 54.5 g O

--------------------------

Step 3

Convert mass into moles:

40.9 g C x (1 mol/12.01 g) = 3.40 moles C

4.58 g H x (1 mol/1.008 g) = 4.54 moles H

54.5 g O x (1 mol/15.99 g) = 3.40 moles O

------------------------

Step 4

All moles calculated in step 3 need to be divided by the smallest one.

3.40 moles C/3.40 moles = 1

4.54 moles H/3.40 moles = 1.33

3.40 moles O/3.40 moles = 1

-----------------------

Step 5

Integer numbers are needed, so let's multiply by 3 all of them in step 4

Therefore,

For C) 3

For H) 3.99 = 4 approx.

For O) 3

All these numbers calculated will be the subindexes in ascorbic acid

Answer:

Empirical formula: C3H4O3

How many grams of H2 are required to completely convert 80g of Fe2O3?

Answers

Answer

3.0 grams H₂ is required.

Explanation

Given:

Mass of Fe2O3 = 80 g

Equation:

What to find:

The grams of H2 required to completely convert 80g of Fe2O3.

Step-by-step solution:

From the equation of reaction;

3 moles of H2 completely react with 1 mole of Fe2O3

Note: Molar mass of H2 is 2.016 grams per mole and Molar mass of Fe2O3 is 159.69 g/mol

This implies; (3 x 2.016 g) = 6.048 grams H2 completely react with 159.69 grams Fe2O3.

Therefore, x grams H2 will completely convert 80 grams Fe2O3.

Cross multiply and divide both sides by 159.69 grams Fe2O3.

x grams H2 is now equal to

[tex]x=\frac{80\text{ }g\text{ }Fe_2O_3}{159.69\text{ }g\text{ }Fe_2O_3}\times6.048\text{ }g\text{ }H_2=3.0298\approx3.0\text{ }grams\text{ }H_2[/tex]

Therefore the grams of H2 required to completely convert 80g of Fe2O3 is 3.0 grams

Sugar forms when carbon, oxygen, and hydrogen combine in a specific ratio. From what you know about elements and the periodic table, what is true about the bonding in sugar?

Answers

Answer

B. The bonds in the compound are covalent

Explanation

The carbon, oxygen, and hydrogen that combine in a specific ratio to form the sugar are nonmetals. From what was learned about elements and the periodic table, nonmetals form covalent bonds among themselves to form compounds.

So what is true about the bonding in sugar is:

B. The bonds in the compound are covalent.

a.
__K (s) + __Cl2 (g) —> __ KCl (aq)

Balance, and Type of reaction?

Answers

[tex]2K_(s) + Cl_2_(g)[/tex] ⇒ [tex]2KCl_(aq)[/tex]

Type of Reaction: Synthesis

What is a synthesis reaction?

When 2 or more substances react to form a single compound.

Starting with a gas of N2 in a balloon of temperature 148.5°C and volume 241.8mL, what is its final volume if you cool it to -96.4°C?

Answers

Answer

101.3 mL

Explanation

Given:

The initial temperature, T₁ = 148.5 °C = (148.5°C + 273) = 421.5 K

The initial volume, V₁ = 241.8 mL

Final temperature, T₂ = -96.4 °C = (-96.4°C + 273) = 176.6 K

What to find:

The final volume of the gas.

Step-by-step solution:

The final volume, V₂ of the gas can be calculated using Charle's law formula.

[tex]\begin{gathered} \frac{V_1}{T_1}=\frac{V_2}{T_2} \\ \\ \Rightarrow V_2=\frac{V_1\times T_2}{T_1}=\frac{241.8mL\times176.6K}{421.5K}=\frac{42701.88\text{ }mL}{421.5} \\ \\ V_2=101.3\text{ }mL \end{gathered}[/tex]

The final volume of the gas is 101.3 mL

A reaction experimentally yields 15.68 g of a product. What is the percent yield if the theoretical yield is 18.81 g?

Answers

Answer

The percent yield = 83.36%

Explanation

Given:

Experimental yield = actual yield = 15.68 g

Theoretical yield = 18.81 g

What to find:

The percent yield for the reaction.

Step-by-step solution:

The percent yield for the reaction can be calculated using the formula below:

[tex]\begin{gathered} Percent\text{ }yield=\frac{Actual\text{ }yield}{Theoretical\text{ }yield}\times100\% \\ \\ Percent\text{ }yield=\frac{15.68\text{ }g}{18.81\text{ }g}\times100\% \\ \\ Percent\text{ }yield=83.36\% \end{gathered}[/tex]

Hence, the percent yield for the reaction is 83.36%

A 1.6700 g sample of pure compound was analyzed and found to contain 0.1870 ghydrogen, 0.8899 g carbon with the remainder being oxygen. What is the molecularformula of the unknown compound if its molar mass is 90.14 g/mol.?

Answers

Answer: C4H10O2

Explanation:

At first find the percentage composition, in 1.67 g compound what percentage of Carbon, Hydrogen and Oxygen are there. Then from those percentages through unitary method find out how much Carbon, Hydrogen and Oxygen would be there in 90.1 g of compound. From those amounts finds their mole number, as in divide the obtained amount by their gram equivalent mass. The numbers you obtain are the corresponding number of Carbon Hydrogen and Oxygen in one molecule of the compound. Hope this helps

Classify CH3CH2NH2 as astrong base or a weak base.Strong BaseWeak Base

Answers

Answer:

CH3CH2NH2 is a weak base.

Explanation:

CH3CH2NH2 is a weak base since its Kb is small, and thus it partially dissociates.

The following lists consists of ionic compounds EXCEPT

barium hydroxide, zinc carbonate, ammonium sulfate
calcium chloride, carbon disulfide, magnesium nitrate
sodium sulfate, copper(II) oxide, potassium nitride
aluminium sulfide, sodium sulfite, calcium fluoride

Answers

The following lists consists of ionic compounds except carbon disulfide (CS₂).

Barium hydroxide , Ba(OH)₂ is an ionic compound.

zinc carbonate, ZnCO₃ is an ionic compound.

ammonium sulfate , (NH₄)₂SO₄  is an ionic compound.

calcium chloride, CaCl₂  is an ionic compound.

carbon disulfide, CS₂ is not an ionic compound. In carbon disulfide both the elements are non metallic elements. The bond formed between atoms are by sharing of electron known as covalent bond due to very little difference in electronegativity.

magnesium nitrate, Mg(NO₃)₂  is an ionic compound.

sodium sulfate, Na₂SO₄  is an ionic compound.

copper(II) oxide, CuO  is an ionic compound.

potassium nitride KNO₃  is an ionic compound.

aluminium sulfide, Al₂S₃  is an ionic compound.

sodium sulfite, Na₂S  is an ionic compound.

calcium fluoride, CaF₂  is an ionic compound.

Thus, The following lists consists of ionic compounds except carbon disulfide (CS₂).

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How many molecules of ethane gas, C2H6 are in 15 grams of the compound?

Answers

Answer:

3.01×10²³molecules.

Explanations:

The formula for the number of molecules of a compound given the number of moles is expressed as:

[tex]nu\text{mber of molecules=moles}\times6.02\times10^{23}[/tex]

Get the moles of ethane gas using the formula:

[tex]\begin{gathered} \text{moles of ethane=}\frac{Mass\text{ of ethane}}{Molar\text{ mass of ethane}} \\ \text{Moles of ethane=}\frac{15}{2(12)+1(6)} \\ \text{Moles of ethane}=\frac{15}{30}\text{moles} \\ \text{Moles of ethane}=0.5\text{moles} \end{gathered}[/tex]

Determine the required number of molecules of ethane

[tex]\begin{gathered} nu\text{mber of mol}ecules=0.5\times6.02\times10^{23} \\ nu\text{mber of mol}ecules=3.01\times10^{23} \end{gathered}[/tex]

Hence the molecule of ethane gas that is in 15 grams of the compound is 3.01×10²³molecules.

A solution with a total volume of 1000.0 mL contains 37.1 g Mg(NO3)2. If you remove 20.0 mL of this solution and then dilute this 20.0 mL sample with water until the new volume equals 500.0 mL, what is the concentration of Mg+2 ion in the 500.0 mL of solution? What is the concentration of nitrate ion?

Answers

1. The concentation of the magnesium ion, Mg²⁺ in the solution is 0.01 M

2. The concentation of the nitrate ion, NO₃⁻ in the solution is 0.02 M

We'll begin by obtaining the concentration of the stock solution. This can be obtained as follow:

Mass of Mg(NO₃)₂ = 37.1 gMolar mass of Mg(NO₃)₂ = 148 g/moleMole of Mg(NO₃)₂ = 37.1 / 148 = 0.25 moleVolume = 1000 mL = 1000 / 1000 = 1 LConcentration =?

Concentration = mole / volume

Concentration = 0.25 / 1

Concentration = 0.25 M

Next, we shall determine the concentration of the diluted solution

Volume of stock solution (V₁) = 20 mLConcentration of stock solution (C₁) = 0.25 MVolume of diluted solution (V₂) = 500 mL Concentration of diluted solution (C₂) =?

C₁V₁ = C₂V₂

0.25 × 20 = M₂ × 500

5 = M₂ × 500

Divide both side by 500

C₂ = 5 / 500

C₂ = 0.01 M

1. How to determine the concentration of magnesium ion, Mg²⁺

Mg(NO₃)₂(aq) <=> Mg²⁺(aq) + 2NO₃⁻(aq)

From the balanced equation above,

1 mole of Mg(NO₃)₂ contains 1 mole of Mg²⁺

Therefore,

0.01 M Mg(NO₃)₂ will also contains 0.01 M Mg²⁺

Thus, the concentration of Mg²⁺ is 0.01 M

2. How to determine the concentration of nitrate ion, NO₃⁻

Mg(NO₃)₂(aq) <=> Mg²⁺(aq) + 2NO₃⁻(aq)

From the balanced equation above,

1 mole of Mg(NO₃)₂ contains 2 mole of NO₃⁻

Therefore,

0.01 M Mg(NO₃)₂ will contain = 0.01 × 2 = 0.02 M NO₃⁻

Thus, the concentration of NO₃⁻ is 0.02 M

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Which two elements would have the same number of energy levels

Answers

The elements with the same number of energy levels are the ones that belong to the same period of the periodic table.

Copper and Zinc both belong to the 4th period of the periodic table.

Nickel belongs to the 4th period and palladium to the 5th period.

Lithium belongs to the 2nd period and Magnesium to the 3rd period.

It means that the correct answer is Copper and Zinc, they belong to the same period,

Methane(CH4) gas and oxygen (O2) gas react to form carbon dioxide (CO2) gas and water vapor(H2O). Suppose you have 5.0 mol of CH4 and 1.0 mol of O2 in a reactor.
What would be the limiting reactant? Enter its chemical formula below

Answers

The limiting reactant, given that 5.0 moles of CH₄ and 1.0 mole of O₂ are in the reactor is O₂

How do I determine the limiting reactant

We'll begin by obtainig the balanced equation for the reaction. This is given below:

CH₄ + 2O₂ —> CO₂ + 2H₂O

The limiting reactant for the reaciont can be obtained as illustrated below:

From the balanced equation above,

1 mole of CH₄ reacted with 2 moles of O₂

Therefore,

5 moles of CH₄ will react with = 5 × 2 = 10 moles of O₂

From the above illustration, we can see that a higher amount of O₂ is needed to react completely with 5 moles of CH₄.

Thus, we can conclude that O₂ is the limiting reactant.

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How to find oxidation number of ReO4^-?

Answers

The oxidation number of O is usually -2 and in this case it is.

Our ion is ReO₄⁻. It has a total charge of -1. The charge of the four atoms of O is -8. With this information we can write an equation. X will represent the oxidation state of Re.

Total charge = Oxidation state of Re + 4 * Oxidation state of O

- 1 = x + 4 * (-2)

- 1 = x - 8

-1 + 8 = x

x = +7

So the oxidation state of Re is +7.

If you wanted to dilute the 3M NaOH solution to 500mL of 1M NaOH solution, how much L of the 3M NaOH solution would you need?

Answers

Answer:

0.167L

Explanation:

In order to know how much L of the 3M NaOH solution would you need, we will simply set up an equal proportion solution expressed as;

[tex]C_1V_1=C_2V_2[/tex]

C1 and C2 are the concentration of the solutions

V1 and V2 are the volumes of the solutions

Given the following parameters;

C1 = 1M

V1 = 500mL

C2 = 3M

V2 = ?

Substitute the given parameters into the formula above to get the required litre of solution needed.

[tex]\begin{gathered} 1\times500=3\times V_2_{} \\ 500=3V_2 \\ \text{Swap} \\ 3V_2=500 \end{gathered}[/tex]

Divide both sides by 3:

[tex]\begin{gathered} \frac{3V_2}{3}=\frac{500}{3}_{} \\ V_2=166.67mL \end{gathered}[/tex]

Converting to litres

Since 1mL = 0.001L

166.67mL = x

Cross multiply

[tex]\begin{gathered} 1\times x=166.67\times0.001 \\ x=0.167L \end{gathered}[/tex]

Hence the amount of L of the 3M NaOH solution would you need is 0.167L

How many moles are in 53.99 mg chromium?

Answers

There are 0.001038 moles in 53.99 mg of Chromium.

What a balanced chemical equation for the single displacement reaction you observed in Experiment 3. Include physical states.

Answers

2HCl(aq)+Zn(s)=ZnCl2(aq)+H2(g)

I’m not sure and I’m kind of confused can anyone help?

Answers

Answer: C3H8

We will reconstruct the model in the following manner :

From the above diagram we can see that :

• number of Carbon atom = 3

• number of hydrogen atom = 8

• rewrite this in an alphabetical order, you get :

[tex]\begin{gathered} C_3H_8\text{ } \\ \Rightarrow Propane\text{ } \end{gathered}[/tex]the molecule has a chemical formula = C3H8

The quantatum mechanical model of an atom uses atomic orbitals to describe what

Answers

The quantum mechanical model of atoms describes the three-dimensional position of the electron in a probabilistic manner according to a mathematical function called a wavefunction, often denoted as ψ. Atomic wavefunctions are also called orbitals.

What is the density of hydrogen sulfide (H2S) at 0.2 atm and 311 K?Answer in units of g/L

Answers

Answer

Density = 0.267 g/L

Explanation

Given:

Pressure of H2S = 0.2 atm

Temperature = 311 K

We know:

The molar mass of H2S = 34,1 g/mol

R constant = 0.08206 L.atm/K.mol

Solution:

From the ideal gas law:

PV = nRT

We know that:

density = m/V

n = m/M

Therefore we can use the following equation to solve for density of H2S

[tex]\begin{gathered} density\text{ = }\frac{PM}{RT} \\ density\text{ = }\frac{(0.2\text{ atm x 34,1 g/mol\rparen}}{(0.08206\text{ }L.atm/K.mol\text{ x 311 K\rparen}} \\ \\ density\text{ = 0.267 g/L} \end{gathered}[/tex]

What is the largest possible electronegativity difference for a bond to be covalent?A.0.5B.1.7C.0.0D.1.0

Answers

Answer

B. 1.7

Explanation

As a rule, an electronegativity difference of 2 or more on the Pauling scale between atoms leads to the formation of an ionic bond. A difference of less than 2 between atoms leads to covalent bond formation.

Therefore, the largest possible electronegativity difference for a bond to be covalent is 1.7

A sample of glass that has a mass of 9.3 g gives off 87 J of heat. If the temperature of the sample changes by 12.7°C during this change, what is the specific heat of the glass? NEED ASAP

Answers

Answer

The specific heat of the glass = 0.7366 J/g°C

Explanation

Given:

Mass of the glass sample, m = 9.3 g

Quantity of heat given off, Q = 87 J

Change in temperature, ΔT = 12.7 °C

What to find:

The specific heat, c of the glass.

Step-by-step solution:

The specific heat, c of the glass can be calculated using the given formula below.

[tex]\begin{gathered} Q=mc\Delta T \\ \\ \Rightarrow c=\frac{Q}{m\Delta T} \end{gathered}[/tex]

Putting the values of the given parameters into the formula, we have;

[tex]c=\frac{87J}{9.3g\times12.7°C}=\frac{87\text{ }J}{118.11\text{ }g°C}=0.7366\text{ }J\text{/}g°C[/tex]

Therefore, the specific heat of the glass is 0.7366 J/g°C

Density of gasses lawA sample of gas with a density of 0.066 g/l at 32 C and a pressure of 0.95 atm. Find the density of the gas at STP

Answers

Answer:

[tex]0.078\text{ g/l}[/tex]

Explanation:

Here, we want to calculate the density of the gas at STP

We use a modification of the general gas law as follows

Mathematically:

[tex]\frac{P_1}{D_1\times T_1}\text{ = }\frac{P_2}{D_2\times T_2}[/tex]

where:

P1 is the initial pressure which is 0.95 atm

D1 is the initial density which is 0.066 g/l

T1 is the initial temperature in Kelvin (we add the temperature in Celsius with 273 K : 32 + 273 = 305 K)

P2 is the pressure at STP which is 1 atm

D2 is the density that we want to calculate

T2 is the temperature at STP which is 273 K

Substituting the values, we have it that:

[tex]\begin{gathered} \frac{0.95}{0.066\times305}\text{ = }\frac{1}{D_2\times273} \\ \\ D_2\text{ = }\frac{0.066\times305}{0.95\times273}\text{ = 0.078 g/l} \end{gathered}[/tex]

Can someone help me to answer this?As you reflect on how to interpret a balanced chemical reaction.Ammonium nitrate is a common fertilizer, but under the wrong conditions it can be hazardous. In 2002, Philippines has banned imports of ammonium nitrate that used in bombs that killed 12 people in Mindanao area.The explosion resulted from this reaction:2NH4NO3(s)→2N2(g)+4H2O(g)+O2(g)Construct a table showing how to interpret the information in the equation in terms of:1. individual molecules and ions.2. moles of reactants and products.3. grams of reactants and products given 2 mol of ammonium nitrate.4. numbers of molecules or formula units of reactants and products given 2 mol of ammonium nitrate.

Answers

(1)

The molecule NH4NO3 is ammonium nitrate, which makes a redox reaction.

It produces N2, O2, and H2O, which are nitrogen, oxygen, and water.

The ions are 2NH4+ and 2NO3-.

2 molecules of N2, 4 molecules of H2O, and 1 molecule of O2.

(2)

There are 2 moles of NH4NO3, 2 moles of N2, 4 moles of H2O, and 1 mole of O2.

(3)

The molar mass of NH4NO3 is 80.043 grams per mole, but there are 2 moles of it, so there are 160.09 grams of NH4NO3.

There are 56.03 grams of N2 because there are 2 moles of it. (1 mole N2 = 28.0134 g/mol).

There are 72.06 grams of H2O because there are 4 moles of it (1 mole H2O = 18.02 g/mol).

There are 31.998 grams of O2 because there's just 1 mole of it.

(4)

The formula units of NH4NO3 is 1.204x10^24, which is equivalent to 2 moles.

Nitrogen has the same formula units because there are 2 moles of it, so it's 1.204x10^24.

Water has 2.409x10^24 because there are moles of it.

Oxygen has 6.022x10^23 because there's just 1 mole, inis Avogadro's Number.

What functional group is found in amino acids?A) aminesB) alkanesB) cyclic hydrocarbon ringsC) alcohols

Answers

Answer:

[tex]A)\text{ Amines}[/tex]

Explanation:

Here, we want to get the functional group is found in amino acids

In the amino acids, we can get amines, carboxylic acid groups, and the carbon chain

Looking at the options, we can see that the amine group is the right option here as the other two are not available

Substance Density (grams/cm3)Chloroform - 1.5Ebony wood - 1.2Mahogany wood - 0.85Oil - 0.9Water - 1.025.Since volume = mass/density, a 1,700 gram beam of mahogany wood has a volume of...Volume = Mass / DensitySelect one:a. 500 cm3b. 1,445 cm3c. 1,785 cm3d. 2,000 cm3

Answers

As the question gave us the formula in which we have to use to calculate the volume of this type of wood:

V = m/d

We have:

m = 1700 grams

d = 0.85

Now we add these values into the formula:

V = 1700/0.85

V = 2000 cm3, letter D

8. Based on the Law of Conservation of Matter: At the start of the reaction 20g of
one material and some amount of another material were reacted and produced
30g of solid and 70g of a gas. What is the other amount of reactant used?
a. 20
b. 60g
c. 80g
d. 100g

Answers

Answer:

80g

Explanation:

The law of conservation of matter states that matter cannot be created nor destroyed. Basically, whatever mass you have at the beginning of a reaction, should be the same as at the end of the reaction on the product side.

Since here it lets you know that a total of 100g (30g + 70g) were produced on the product side, that means that we started off with 100g in our reactant side.

We have given that one material is 20g on our reactant side but we need the mass of the other. To find the mass of the other material, simply subtract 20g from the total mass created on the product side.

100g - 20g = 80g

The 80g would be the missing amount from the reactant side that isn't stated.

54000 mL isO 54 m3O 5400 cm3O 0.054m3O 540 m3

Answers

mL and cm³ have a 1 to 1 conversion, so we have:

[tex]54000mL=54000cm^{3}[/tex]

But we don't have this option, so we will need to find another.

The other are in m³, so we can use the conversion from cm to m to get this:

[tex]\begin{gathered} 1m=100cm \\ (1m)^{3}=(100cm)^{3} \\ 1m^{3}=1000000cm^{3} \\ 1cm^{3}=\frac{1}{1000000}m^{3} \end{gathered}[/tex]

So, we can apply this to what we have:

[tex]54000cm^3=54000\cdot\frac{1}{1000000}m^3=0.054m^{3}[/tex]

We have an option with 0.054m³, so the correc alternative is 0.054 m³.

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