7: 8: 9 = .... : 12 : ....
plz help

Answer:

6 dogs are there who ate the biscuits

Answer:

Hi, the answer would be $11.21 after rounding.

Step-by-step explanation:

I see what you mean about the 49, but remember that when writing a price you only have two spots after the decimal. Yes, your decimal placing is correct!

So, after rounding and multiplying correctly you would get about $11.21

Hope this helps!!

Answer:

He poured 2.5 liters into each container

Step-by-step explanation:

Add 2.75, 1.25, and 3.5 together to get 7.5. Divide 7.5 by 3 and you get 2.5 liters per container.

Answer:

x or AB = 9

Step-by-step explanation:

Use Pythagorean Theorem to solve for missing side.

Pythagorean Theorem: a² + b² = c²

Plug our sides in to get AB² + BC² = AC²

We are solving for AB so we arrange the equation to get:

AB² = AC² - BC²

Solve for AB:

AB² = (√117)² - (6)²

AB² = 81

AB = 9

x or AB = 9

Answer:

Step-by-step explanation:

You should add 9 fl. oz. of oil to your 3.75 gallons of gas.

Puch Maxi Moped from the mid-Eighties now since this moped doesn't run on straight gasoline, you need to create a special fuel mixture. This involves combining oil and gas in a specific ratio. The magic ratio here is 2.4 fl. oz. (fluid ounces) of oil for every gallon of gasoline.

You mentioned you've got 3.75 gallons of gas. To figure out how much oil you need, we can use some math. First, let's find out how much oil is required for one gallon of gas:

2.4 fl. oz. of oil/gallon x 1 gallon = 2.4 fl. oz. of oil.

So, for 3.75 gallons of gas, you'll need:

2.4 fl. oz. of oil/gallon x 3.75 gallons = 9 fl. oz. of oil.

You should add 9 fluid ounces of oil to your 3.75 gallons of gas to create the proper fuel mixture for your Puch Maxi Moped.

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The sequence of the number of girl attendees at each Barangay is nonzero, given by multiplying the number of attendees in the previous Barangay by 2

The required values are;

a. The completed table is presented as follows;

[tex]\underline{\begin{array}{|l|c|c|c|c|c|c|c|}\mathbf{Barangay}&1&2&3&4&5&6&7\\\mathbf{Number \ of \ attandees}&4&8&16&32&64&128&256\end{array}}[/tex]

b. The sequence of the number of girls attendees aₙ = 4×2⁽ⁿ⁻¹⁾

c. The sum of beneficiaries of the lecture from the twelve Barangay is 16,384 girls

Reason:

Known parameters are;

Number of girls that attended the lecture at Barangay 1 = 4 girls

Number of girls that attended from Barangay 2 = 8 girls

Number that attended from Barangay 3 = 16 girls

a. The required table with the assumption that the number of girls that attended at each Barangay from Barangay 1 to Barangay 7 doubles, is presented as follows;

b. The sequence of the number of girls who attended the lecture from Barangay 1 to Barangay 7 is presented as follows;

The sequence is a geometric progression having the form, aₙ = a·r⁽ⁿ⁻¹⁾

The first term of the sequence, a = 4

The common ratio, r = 2 (each term is twice the previous term)

n = The number of terms

The sequence is therefore;

c. The total number of girls in the geometric progression, (G. P.) is given by the sum of a G. P. as follows

[tex]S_n = \dfrac{a \cdot (r^n - 1 )}{r - 1}[/tex]

Where;

n = The number of terms = 7 + 5 = 12

Which gives;

The total number of girls who will benefit from the lectures, S₁₂ = 16,384 girls

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Answer: 5h+9

Step-by-step explanation:

10h + (-5h)

5h+(6(+3))

Answer:

C) Chris and Dylan

Step-by-step explanation:

Answer:

62.5 units squared.

Step-by-step explanation:

Answer:

r = 0.35 is Moderate and positive

Step-by-step explanation:

A correlation of r = 0.35 represents a moderate and positive relationship between two variables.

Answer:

x=[tex]\frac{60}{121}[/tex],z=[tex]\frac{535}{121}[/tex],y=-10

Step-by-step explanation:

Answer:

[tex]1) \: \: 12x + 6y + 7z = - 35 \\ 6y = - 35 - 12x + 7z \\ y = \frac{ - 35 - 12x + 7z}{6} \\ \\ 2) \: \: 7x - 5y - 6z = 200 \\ - 5y = 200 - 7x + 6z \\ y = \frac{200 - 7x + 6z}{ - 5} \\ \\ 3) \: \: x + y = - 10 \\ y = - 10 - x \\ [/tex]

Answer:

N+5

Step-by-step explanation:

4,9,14,19

4+5=9+5=14+5=19….

Answer:

Assuming "x2" is x squared:

5x(x2-4x+2)

(5x(x2)+5x(-4x)+5x(2))

5x^3-20x+10x

For these polynomial multiplication problems, just distribute the number outside the parentheses.

Answer:

[tex]5x^3-20x^2+10x[/tex]

Answer: x = 10 and y = 3

Step-by-step explanation:

Due to the x rule, (5x - 17) = (3x + 3)

If we add 17 to both sides:

5x = 3x + 20

Take away 3x from both sides

2x = 20

Divide by 2:

X = 10

This means that (5x - 17) = (3x + 3) = 33

Since all angles must add to 360, the top angle = (360- (33*2)) /2

(360-66) /2

294 /2

147

This shows that 9x - 19y = 147

90 - 19y = 147

Minus 90 both sides

19y = 57

Y = 3

So, x = 10 and y = 3

Answer:

Right Triangle.

Step-by-step explanation:

A right triangle always has a 90 degree angle.

Answer:Right angle

Step-by-step explanation:the box down there signals its a 90 degree angle

Answer:

165/11= 15

Step-by-step explanation:

I used a calculator

Answer:

Step-by-step explanation:

This is a typical probability question where there is a large number of possible outcomes to be considered.

That suggests an approach where we look at the probability of it not occurring.

For that to happen, we have to have 5 coins all landing heads up. The probability of that happening is (1/2)5=1/32.

From this,  we can deduce the probability of that not happening (i.e. there being at least one tail) is  1−1/32=31/32.

Answer:

2700 more eggs were ordered

Answer:

The points would be: (-3, 3) (-4, -1) (2, -1) (1, 3)

Step-by-step explanation:

Because when you move 4 units left, all of the x values in the points will go down by 4, and when you move 2 units down, the y values will go down by 2 units. So when applied to the points shown, you get the answer I put.

I believe this is correct? Hope it helps!

(1)

(a) Use the fact that [tex]\sqrt{x^2} = |x|[/tex] for all [tex]x[/tex]. Since [tex]x\to+\infty[/tex], we have [tex]x>0[/tex] and [tex]|x| = x[/tex].

[tex]\displaystyle \lim_{x\to\infty} \frac{\sqrt{9x^2 - 2}}{x + 4} = \lim_{x\to\infty} \frac{\sqrt{x^2} \sqrt{9 - \frac2{x^2}}}{x + 4} \\\\= \lim_{x\to\infty} \frac{ x \sqrt{9 - \frac2{x^2}}}{x+4} \\\\= \lim_{x\to\infty} \frac{\sqrt{9 - \frac2{x^2}}}{1 + \frac4x} \\\\= \frac{\sqrt9}1 = \boxed{3}[/tex]

(b) This time [tex]x\to-\infty[/tex], so [tex]x < 0[/tex] and [tex]|x| = -x[/tex].

[tex]\displaystyle \lim_{x\to\infty} \frac{\sqrt{9x^2 - 2}}{x + 4} = \lim_{x\to\infty} \frac{\sqrt{x^2} \sqrt{9 - \frac2{x^2}}}{x + 4} \\\\= \lim_{x\to\infty} \frac{ \boxed{-x} \sqrt{9 - \frac2{x^2}}}{x+4} \\\\= (-1) \times \lim_{x\to\infty} \frac{\sqrt{9 - \frac2{x^2}}}{1 + \frac4x} \\\\= -\frac{\sqrt9}1 = \boxed{-3}[/tex]

(c) We immediately have

[tex]\displaystyle \lim_{x\to\infty} (x - \sqrt x) = \boxed{\infty}[/tex]

since [tex]x > \sqrt x[/tex] for all [tex]x > 1[/tex].

(d) Introduce a difference of squares by factoring in the limand's conjugate. The rest mirrors what we did in (a)/(b).

[tex]\displaystyle \lim_{x\to\infty} \left(\sqrt{x^2 + 12x} - x\right) = \lim_{x\to\infty} \frac{\left(\sqrt{x^2+12x} - x\right) \left(\sqrt{x^2+12x} + x\right)}{\sqrt{x^2 + 12x} + x} \\\\ = \lim_{x\to\infty} \frac{\left(\sqrt{x^2+12x}\right)^2 - x^2}{\sqrt{x^2+12x}+x} \\\\ = \lim_{x\to\infty} \frac{12x}{\sqrt{x^2+12x}+x} \\\\ = \lim_{x\to\infty} \frac{12}{\sqrt{1 + \frac{12}x} + 1} = \frac{12}{\sqrt1 + 1} = \boxed{6}[/tex]

(e) Divide through by the highest-degree exponential term.

[tex]\displaystyle \lim_{x\to\infty} \frac{12e^{2x} - 3e^{3x}}{2e^{2x} + 4e^{3x}} = \lim_{x\to\infty} \frac{12e^{-x} - 3}{2e^{-x} + 4} = \frac{0 - 3}{0 + 4} = \boxed{-\frac34}[/tex]

(2) By definition of the derivative, we have

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{f(x+h) - f(x)}h[/tex]

For [tex]f(x) = \sqrt{x^2+1}[/tex], the limit becomes

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\sqrt{(x+h)^2+1} - \sqrt{x^2+1}}h[/tex]

Factor in the conjugate.

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\left(\sqrt{(x+h)^2+1} - \sqrt{x^2+1}\right) \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\left(\sqrt{(x+h)^2+1}\right)^2 - \left(\sqrt{x^2+1}\right)^2}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{\bigg((x+h)^2+1\bigg) - (x^2+1)}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{2xh + h^2}{h \left(\sqrt{(x+h)^2+1} + \sqrt{x^2+1}\right)}[/tex]

[tex]f'(x) = \displaystyle \lim_{h\to0} \frac{2x + h}{\sqrt{(x+h)^2+1} + \sqrt{x^2+1}}[/tex]

[tex]\implies \boxed{f'(x) = \displaystyle \lim_{h\to0} \frac{x}{\sqrt{x^2+1}}}[/tex]

(3) The tangent line to

[tex]y = \frac1{x^2+1}[/tex]

at the point (2, 1/5) has slope equal to the derivative [tex]\frac{dy}{dx}[/tex] when [tex]x = 2[/tex]. Compute the derivative; since [tex]y = \frac1{f(x)^2}[/tex] where [tex]f(x)[/tex] is the function from the previous problem, using the chain rule gives

[tex]y = \dfrac1{f(x)^2} \implies \dfrac{dy}{dx} = -\dfrac{2f'(x)}{f(x)^3} = -\dfrac{2 \times \frac{x}{\sqrt{x^2+1}}}{\left(\sqrt{x^2+1}\right)^3} \\\\ \implies \dfrac{dy}{dx} = -\dfrac{2x}{(x^2+1)^2}[/tex]

The tangent line at (2, 1/5) then has slope

[tex]\dfrac{dy}{dx}\bigg|_{x=2} = -\dfrac{2\times2}{(2^2+1)^2} = -\dfrac4{25}[/tex]

Using the point-slope formula, the equation of the tangent line is

[tex]y - \dfrac15 = -\dfrac4{25} (x - 2) \implies \boxed{y = -\dfrac{4x - 13}{25}}[/tex]

Answer:

y= 80/9

Step-by-step explanation:

Given

" y varies directly as x" and "as the square of z" so y = x* z²* some number

if y =25/9 when x= 5, z= 1 and y = x*z²* some number

then 25/9  = 5 * 1² * some number

      5*(5/9) = 5 * some number

therefore y = x* z²* (5/9)

y= ? when x=1 , z= 4

y = x * z² * (5/9)

y = 1 * 4² * (5/9)

y = 16*5 / 9

y = 80/9

Answer:

∆K = 98°

∆M = 82°

∆G = 118°

∆H = 62°

Step-by-step explanation:

∆K & ∆G is by corresponding angle

and

∆M & ∆H is by linear pairs

Answer:

13l4 3/5%

Step-by-step explanation:

ithink that is the answer

Answer:

I think its A

Step-by-step explanation:

Answer:

-2 is the only answer

Step-by-step explanation:

You know the answer can't be a positive number because a positive multiplied by a positive is a positive number. It is not 0 because 0 X anything is 0. -16 x 16 is way to high. But, -2 x 2 = -4

There are no real solutions

Option F is correct.

An imaginary number is a number that, when squared, has a negative result. Essentially, an imaginary number is the square root of a negative number and does not have a tangible value.

Given equation

[tex]x^{2} =-4[/tex]

Apply square root on both sides of the equation

[tex]\sqrt{x^{2} } =\sqrt{-4}[/tex]

[tex]x=2i[/tex]

2i is imaginary number.

There are no real solutions

Hence, Option F is correct.

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Answer:

25h

I hope this helps :)