6th grade math plsss help​

Answer:

the order of operations tells us how to solve a problem.

first is P for parentheses. this means you solve all the expressions within the parentheses. this ensures a simplified expression before moving on.

second is E for exponents. this means you solve all the expressions with exponents. by doing this before MDAS, you do not raise the wrong values.

third and fourth is M/D for multiplication/division. the / is between these two because these steps are interchangeable. you can multiply or divide first. the results will be the same.

this also applies to the fifth and sixth, which are A/S for addition/subtraction.

Answer:

The answer is below

Step-by-step explanation:

Using binomial probability:

p = probability of a rural student getting admission = 1/2

q = probability of a rural student not getting admission = 1/2

n = number of students = 100

P(x) = [tex]C(n,x) p^xq^{(n-x)[/tex]

But [tex]p^xq^{n-x}=\frac{1}{2}^x\frac{1}{2}^{n-x}=\frac{1}{2}^{n}[/tex]

P(x > 50) = P(x = 51) + P(x = 52) + P(x = 53) + . . . + P(x = 100)

P(x > 50) = [tex]\frac{1}{2} ^{100}[C(100,51)+C(100,52)+C(100,53)+\ .\ .\ .+C(100,100)]\\[/tex]

[tex]P(x>50)=\frac{1}{2}^{100} (\frac{1}{2}( 2^{100}-C(100,50)))\\\\P(x>50)=(\frac{1}{2}^{100} *\frac{1}{2}*2^{100})- (\frac{1}{2}^{100} *\frac{1}{2}*C(100,50))\\\\P(x>50)=\frac{1}{2}[(2^{-100}*2^{100})-(\frac{1}{2}^{100} *C(100,50))]\\ \\P(x>50)=\frac{1}{2}[1-\frac{1}{2}^{100} *C(100,50)][/tex]

Answer:

a==3.3  a=-3 1/3  a=-10/3

all of those are different possible answers

Step-by-step explanation:

Answer:C

Step-by-step explanation:

(6 - 2) - 1 = 4 - 1 = 3

6 - (2 - 1) = 6 - 1 = 5

The associative rule doesn't work for subtraction because you get different results when you move the parentheses.

The absolute value of 3.4 = 3.4

The absolute value of something is always positive.

The answer is A

Answer: A. 3.4

Step-by-step explanation:

Concept:

Absolute value is the distance from a number to zero. Distance is always positive, so absolute value of any number is positive. Absolute value is often written as ( |x| ).

Solve:

Given :

The weight of an object on a particular scale is 125.2 lbs.

The actual weight by at most 0.4 lbs.

To Find :

The range of actual  weights of the object.

Solution :

It is given that uncertainty in weight is 0.4 lbs.

So, minimum weight can be( 125.2 -0.4 ) = 124.8 lbs.

Maximum weight is given by  ( 125.2 + 0.4 ) = 125.6 lbs.

Therefore, the range of actual  weights of the object is between :

124.8  x 125.6 .

Hence, this is the required solution.

Answer:

h=5

Step-by-step explanation:

Answer: D because it would mess with your feelings

I would put the answer as D.

Answer:

Horizontal compression

Step-by-step explanation:

Just took a test

Answer: horizontal compression

Step-by-step explanation:

Edge

Answer:

Step-by-step explanation:

i think yes

Answer: Covert the mixed number to an improper fraction for them to be too simple fractions and multiply them.

Step-by-step explanation:

By multiply fraction  by a mixed fraction you will have to rewrite the mixed number as an improper fraction.

For example ,

1  1/2  is a mixed fraction. If you convert it to improper fraction, you will get 3/2 then you multiply.

Answer:

its B, C and E

Step-by-step explanation:

on edge

Answer:

2a + 3p = 18

Step-by-step explanation:

The total has to equal 18 so then you have $2 and $3. Apples cost $2 so the 2 should have an a for Apples. The peppers cost $3 so the 3 should have a p for peppers. So the equation would be 2a + 3p = 18.

Answer:

2.6

Step-by-step explanation:

First you subtract and get 40 and then you add the 12 which gets 52 and then you divide it by 20 and get your 2.6

Answer:

Step-by-step explanation:

40.6 hope it helps

Answer:

we would need the answer choices to reply

33 in corresponds with the 11 in side

33 in / 11 in = 3

The scale factor is 3

24 in / 3 = 8 in

x = 8 in

Answer:

Step-by-step explanation:

In similar triangles, corresponding sides will be in same ratio.

[tex]\frac{33}{11}=\frac{24}{x}[/tex]

Cross multiply,

33*x = 24 * 11

[tex]x=\frac{24 *11}{33}\\\\x=\frac{24*1}{3}\\\\x = 8 in[/tex]

Answer:

What's the question???

Answer:

Cool can you give me brainliest

Step-by-step explanation:

Answer:

10 pages

Step-by-step explanation:

1 and 1/3 pages multiplies by 7.5 brings us to the answer of ten pages

20 minutes goes into 2 and 1/2 hours 7.5 times

10 pages i did this on edge

2020 hope this helps

your welcome =)

Answer:

For plato users, the answer would be letter C.

Step-by-step explanation:

A.

It represents neither a relation nor a function.

B.

It represents a relation only.

C.

It represents both a relation and a function.

D.

It represents a function only.

This equation represents both a relation and a function.

Took the test, hope this helps!

B. It represents both a relation and a function.

Note that both functions and relations are defined as sets of lists. In fact, every function is a relation. However, not every relationship is a function. In a function, there cannot be two lists that disagree on only the last element.

Given the graph of a relation, if you can draw a vertical line that crosses the graph in more than one place, then the relation is not a function. This is a function. Any vertical line will cross this graph at only one point.

Learn more about function here: https://brainly.com/question/6561461

#SPJ2

Answer: 144π or 452.389342117

Step-by-step explanation:

24= circumference

c=dπ

c=24π

24/2=12

12=radius

12^2π=area

144π=area

(4m - n)(3m - 2n)

12m^2 - 8mn - 3mn + 2n^2

Let's combine like terms

12m^2 - 11mn + 2n^2

Answer:

12m^2+2n^2-11mn

Step-by-step explanation:

(4m-n)(3m-2n)

=12m^2-8mn-3mn+2n^2

12m^2+2n^2-11mn

Answer:

7×2=14 (for the long side)5×2=10 (for the short sides) the you add up the two answers 14+10=24

Complete Question

Find a particular solution to [tex]ty''-(1+t)y'+y=t^2e^t , t > 0[/tex]  

[tex]y_1 = 1 + t , \ y_2 = e^t[/tex]

Answer:

The solution is    [tex]y_p = -e^{2t} + t + \frac{3t^2}{2} + \frac{t^3}{2}[/tex]

Step-by-step explanation:

  Now the given equation is [tex]ty''-(1+t)y'+y=t^2e^t , t > 0[/tex]

             dividing through by  t

       We have  

         [tex]y'' - \frac{1 + t }{t}y' + \frac{1}{t} y = te^t \\\\ let's\ call\ it \ g(t)[/tex]

Now for the given initial value we can generate our Wronskian as follows

        [tex]W(y_1 ,y_2) = | \left y_1} \atop {y_1'}} \right. \left y_2} \atop {y_2'}} \right | = | \left {(1 + t)} \atop {1}} \right. \left e^t} \atop {e^t}} \right | = (1 + t )e^t - e^t = te^t[/tex]

Now applying  method of variation of parameters to obtain the particular solution

So here we assume that

          [tex]y_p = v_1 y_1 + v_2 y_2[/tex]

So

       [tex]v_1 = - \int\limits {\frac{y_2 (t) g(t)}{W(t)} } \, dt = - \int\limits {\frac{e^t te^t}{te^t} } = - \int\limits { e^t} } = -e^t[/tex]

And

    [tex]v_2 = - \int\limits {\frac{y_1 (t) g(t)}{W(t)} } \, dt = - \int\limits {\frac{(1 + t) te^t}{te^t} } = - \int\limits (1 + t) = t + \frac{t^2}{2}[/tex]

So

     [tex]y_p = -e^t * e^t + t + \frac{t^2}{2} * 1 + t[/tex]

     [tex]y_p  =  -e^{2t}   +  t +   \frac{3t^2}{2} + \frac{t^3}{2}[/tex]

Hope you liked that.

Answer:

$8

Step-by-step explanation:

In debt at $20 (like an overdraft) = -20

To make a $10 purchase = -10 on the account

Total debt = -20 + (-10)

                 = -30

You deposit $38 (this is what you added to your account.) = +38

Balance of the checking = -30 + (+38)

                                         = $8

I really hope this helps. If I am right, please thank, rate 5 stars, and give brainliest. Thank you.

Answer:

272

Step-by-step explanation:

Do you need this?

Answer:

272

Step-by-step explanation: