#1
Clockwise 90° rotation rule (x,y)—»(y,-x)
X'=(4,-2)Y'=(-3,-5)Z'=(1,7)#2
Dilation of scale factor 2
X''=(4×2,-2×2)=(8,-4)Y''=2(-3,-5)=(-6,-10)Z''=2(1,7)=(2,14)#3
reflection across x axis rule (x,y)—»(x,-y)
X'''=(8,4)Y'''=(-6,10)Z"'=(2,-14)#4
Rule for given translation (x-5,y+2)
X""=(8-5,4+2)=(3,6)Y""=(-6-5,10+2)=(-11,12)Z""=(2-5,-14+2)=(-3,-12)Answer:
Given points:
X = (2, 4)Y = (5, -3)Z = (-7, 1)Part (a)
Rotate 90° clockwise (about the origin): (x, y) → (y, -x)
X' = (4, -2)Y' = (-3, -5)Z' = (1, 7)Part (b)
Dilation by a scale factor → multiply the points by the scale factor
scale factor = 2
X'' = (8, -4)Y'' = (-6, -10)Z'' = (2, 14)Part (c)
Reflect across the x-axis: (x, y) → (x, -y)
X''' = (8, 4)Y''' = (-6, 10)Z''' = (2, -14)Part (d)
Translate 2 up and 5 to the left: (x, y) → (x - 5, y + 2)
X'''' = (3, 6)Y'''' = (-11, 12)Z'''' = (-3, -12)Give the dimensions of 2 solids with equal surface area and different volume
Two solids with the same surface and different volumes are a cube of side length of 1 unit, and a sphere of radius of 0.69 units.
How to find the two solids?
First, let's define a cube of a side length of 1 unit. The surface of this cube is equal to 6 times the area of one of the faces, or:
S = 6*(1 unit square) = 6 units square.
And the volume is equal to the side length cubed, so we have:
V = (1 unit)^3 = 1 unit cubed.
Now, let's find a sphere with the same surface than our cube. For a sphere of radius R, the surface is:
S = 4*3.14*R^2
Then we must have:
4*3.14*R^2 = 6 units square
R = √(6/(4*3.14)) units = 0.69 units.
And the volume of this sphere is:
V = (4/3)*3.14*R^3 = (4/3)*3.14*(0.69 units)^3 = 1.38 cubic units.
So the sphere has the same surface and more volume.
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Factor the equation 4x^2-20x+25
Answer:
[tex](2x - 5)^2[/tex]
Step-by-step explanation:
[tex]y = 4x^2 -20x + 25\\\rightarrow (2x - 5)(2x - 5)\\\rightarrow (2x - 5)^2\\\\\text{checking...}\\(2x - 5)^2 = (2x - 5)(2x - 5) = 4x^2 - 10x - 10x + 25 = 4x^2 - 20x + 25[/tex]
please help me please pleasr please
Answer:
which one's anwer you want
2. length= 65 ft width=24 m area=135 in2
Tori made a scale drawing of an Italian
restaurant. The restaurant's kitchen is 2
millimeters long in the drawing. The actual
kitchen is 16 meters long. What scale did Tori
use for the drawing?
1 millimeter :
meters
Step-by-step explanation:
2mm : 16m
so to get 1mm you need to divide 16 by 2
16/2 is 8 therefore
1mm : 8m
1 millimeter represents 8 meters in real life
hope that helps :)
Solve for x. Round to the tenths place. Can somebody help
Answer:
12.12
Step-by-step explanation:
7^2+x^2=14^2, as by the Pythagorean theorem.
49+x^2=196,
x^2=147,
square root of 147;
it's close to 144,
thus, 12.12
Let a represent a non zero rational number and let b represent an irrational number. Which expression could represent a rational number?
The operation between a rational and a irrational number that results in a rational number is a multiplication, hence the expression ab could represent a rational number.
What are rational and irrational numbers?If a number can be represented by a fraction, it is rational, otherwise, it is irrational.
The addition/subtraction of a rational and an irrational numbers is irrational, while the multiplication is rational, hence the expression ab could represent a rational number.
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The first term of an A.P is 3 and the fifth term is 9.Find the number of terms in the progression if the sum of the progression is 81.
Answer:
its A becauss i tryed b and th en i tried A so its a
please help and please leave a legit answer
Answer:
y= -12/x + 3
Step-by-step explanation:
Here's my answer
is this correct?
A.yes
B. No
C. Maybe
D. I DUNNO???!!!
Answer:
its yes
Step-by-step explanation:
because it's x 2 I hope this helps
Two containers designed to hold water are side by side, both in the shape of a cylinder. Container A has a diameter of 6 feet and a height of 18 feet. Container B has a diameter of 8 feet and a height of 17 feet. Container A is full of water and the water is pumped into Container B until Container A is empty. To the nearest tenth, what is the percent of Container B that is empty after the pumping is complete?
The percent of container B that is left after pumping the water of Container A full in it is 40 per cent .
Step by step explanation :
Given -
Two containers ( Container A & Container B ) in shape of cylinders.Diameter of Container A = 6 feetHeight of Container A = 18 feet Diameter of container B = 8 feet Height of Container B = 17 feetTo find -
The percent of container B that is left after pumping the water of Container A full in it.
Solution -
Firstly, we have to find how much water each container can hold i.e. volume of containers .
We know that -
[tex] \boxed{ \mathfrak \purple{volume \: of \:cylinder = \pi {r}^{2} h} }[/tex]where, r is the radius of the cylinder & h is the height of the cylinder.
Now,
For Container A
Given, diameter = 6 feet
.•. Radius = [tex] \frac{6}{2} [/tex]
[tex] = 3 \: \mathfrak{feet}[/tex]
Height = 18 feet
•.• Volume of Container A = [tex] \frac{22}{7} \times {3}^{2} \times 18[/tex]
[tex] = \frac{22}{7} \times 3 \times 3 \times 18[/tex]
[tex] = \frac{3564}{7} [/tex]
[tex] = 509.142857 \:{ft.}^{3} \mathfrak{(approximately)}[/tex]
Rounding off to the nearest tenth . ..
[tex] => 510 \: \mathfrak{ {feet}^{3} }[/tex]
For Container B
Given, Diameter = 8 feet
.•. Radius = [tex] \frac{8}{2} [/tex]
[tex] = 4 \: \mathfrak{feet}[/tex]
Height = 17 feet
•.• Volume of Container B = [tex] \frac{22}{7} \times {4}^{2} \times 17[/tex]
[tex] = \frac{22}{7} \times 4 \times 4 \times 17[/tex]
[tex] = \frac{5984}{7} [/tex]
[tex] = 854.857143 \: {ft.}^{3} \mathfrak{(approximately)}[/tex]
Rounding off to the nearest tenth. ..
[tex] => 850 \: \mathfrak{ {feet}^{3} }[/tex]
Now,
Volume container B that is left after pumping the water of Container A in it = Volume of Container B - Volume of Container A
= ( 850 - 510 ) ft^3
= 340 ft^3
Now ,
The percent of container B that is left after pumping the water of Container A in it = Volume container B that is left after pumping the water of Container A /Total volume of Container B × 100
[tex] = \frac{340}{850} \times 100[/tex]
[tex] = \boxed{ 40 \: \%}[/tex]A pool measuring 10 meters by 26 meters is surrounded by a path of uniform width, as shown in the figure. If the area of the pool and the path combined is 1380 square meters, what is the width of the path?
Answer:
112m
Step-by-step explanation:
A = lw
A = 10(26)
A = 260
1380 - 260 = 1120
1120 = 10(w)
1120 / 10 = 112
Help picture below problem 11
Answer:
Missing Angle = 26⁰ ( corresponding angles )
PLEASE HELP PLEASE PLEASE HELP
Answer:
I believe it is Dissolve.
am I right? please only answer if you are positive that you’re correct. thank you!
Answer:
yes you are correct :)))
50% of the population are within one standard deviation.
O True
O False ???
Answer: False
Step-by-step explanation:
68%
Key Takeaways. The Empirical Rule states that 99.7% of data observed following a normal distribution lies within 3 standard deviations of the mean. Under this rule, 68% of the data falls within one standard deviation, 95% percent within two standard deviations, and 99.7% within three standard deviations from the mean.
I need help please give explanation and thank you
how do i solve this?
Answer:
33
Step-by-step explanation:
For 4 triangles area 4*(1/2)*4*3=24
base square area 3*3=9
all together 24+9= 33
7(5/14a-5/21)-1/12(3a+6)
[tex]\sf \dfrac{9a}{4}-\dfrac{13}{6}[/tex] or [tex]\sf \dfrac{54a-52}{24}[/tex]
======================================
[tex]\sf \rightarrow 7\left(\dfrac{5}{14}a-\dfrac{5}{21}\right)-\dfrac{1}{12}\left(3a+6\right)[/tex]
use distributive method
[tex]\sf \rightarrow \dfrac{5a}{2}-\dfrac{5}{3}-\dfrac{a}{4}-\dfrac{1}{2}[/tex]
group terms
[tex]\rightarrow \sf \rigtharrow \dfrac{5a}{2}-\dfrac{a}{4}-\dfrac{5}{3}-\dfrac{1}{2}[/tex]
make the denominators same
[tex]\rightarrow \sf \rigtharrow \dfrac{2(5a)}{4}-\dfrac{a}{4}-\dfrac{2(5)}{6}-\dfrac{3(1)}{6}[/tex]
simplify
[tex]\rightarrow \sf \rigtharrow \dfrac{10a-a}{4}-\dfrac{10+3}{6}[/tex]
answer in separate constants
[tex]\rightarrow \sf \dfrac{9a}{4}-\dfrac{13}{6}[/tex]
make the denominators same
[tex]\rightarrow \sf \dfrac{6(9a)}{24}-\dfrac{4(13)}{24}[/tex]
simplify
[tex]\rightarrow \sf \dfrac{54a}{24}-\dfrac{52}{24}[/tex]
join both fractions
[tex]\rightarrow \sf \dfrac{54a-52}{24}[/tex]
Answer:
[tex]\boxed{\dfrac{9a}{4} - \dfrac{7}{6}}[/tex]
Step-by-step explanation:
[tex]7(\dfrac{5a}{14} - \dfrac{5}{21} ) - \dfrac{(3a + 6)}{12}[/tex]
Step-1: Simplify the distributive property
⇒ [tex]\dfrac{35a}{14} - \dfrac{35}{21} - \dfrac{(3a + 6)}{12}[/tex]
Step-2: Make common denominators
⇒ [tex]\dfrac{35a \times 3}{14 \times 3} - \dfrac{35 \times 2}{21 \times 2} - \dfrac{7 \times (3a + 6)}{12 \times 7}[/tex]
⇒ [tex]\dfrac{210a}{84} - \dfrac{140}{84} - \dfrac{7 \times (3a + 6)}{84}[/tex]
Step-3: Simplify the distributive property
⇒ [tex]\dfrac{210a}{84} - \dfrac{140}{84} - \dfrac{21a + 42}{84}[/tex]
Step-4: Rewrite (21a + 42)/84 in a different way
⇒ [tex]\dfrac{210a}{84} - \dfrac{140}{84} - \dfrac{21a}{84} + \dfrac{42}{84}[/tex]
Step-5: Add/Subtract if necessary
⇒ [tex]{\dfrac{189a}{84} - \dfrac{98}{84}}[/tex]
Step-6: Simplify the fractions
⇒ [tex]{\dfrac{189a}{84} - \dfrac{98}{84}} = {\dfrac{9a}{4} - \dfrac{49}{42}} = \boxed{\dfrac{9a}{4} - \dfrac{7}{6}}[/tex]
I don’t know what is the least common factor of 18 and 12.
Answer:
the common factors for both are 1,2,3,6
Number 1. Don’t worry about the other stuff well you can the other stuff if you want I don’t know them either
Applying the appropriate circle theorems involving angles formed by chords and tangents, we have:
1. x = 75°; y = 85°, z = 210°
2. x = 38°
3. x = 143°
What is the Angles of Intersecting Tangents Theorem?The angle formed outside a circle when two tangents intersect equals half of the positive difference of the intercepted arcs, based on the angles of intersecting tangents theorem.
What is the Angles of the Intersecting Chords Theorem?The angles of intersecting chords theorem states that, half the sum of the intercepted arcs equals the vertical angle formed by two chords in a circle.
What is the Inscribed Angle Theorem?According to the inscribed angle theorem, the measure of an inscribed angle in a circle = 1/2(measure of intercepted arc)
1. x = 180 - 105 (opposite angles in a cyclic quadrilateral are supplementary)
x = 75°
y = 180 - 95 = 85°
z = measure of intercepted arc HEF = 2(105) [inscribed angle theorem]
m(HEF) = 210°
2. x = 1/2(218 - 142) [angles of intersecting tangents theorem]
x = 1/2(76)
x = 38°
3. x = 1/2(146 + 140) [angles of intersecting chords theorem]
x = 1/2(286)
x = 143°
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can someone please help me with this question???? its an exam study guide and i dont understand it
Josef owns four par value $1,000 bonds from Dowc Beverage Co. Each bond has a market value of 104.561 and gives 9.2% interest. Josef also owns 170 shares of stock in Dowc Beverage Co. Stock in Dowc Beverage Co. has a share price of 26.25 and pays a dividend of $2.38. If the broker Josef employed to purchase these stocks and bonds charges a commission of $72 for each ten shares of stock bought or sold and a commission of 4% of the market value of each bond bought or sold, which aspect of Josef’s investment in Dowc Beverage Co. has a greater percent yield, and how much greater is it?
a.
The stocks have a yield 2.15 percentage points higher than that of the bonds.
b.
The stocks have a yield 0.27 percentage points higher than that of the bonds.
c.
The bonds have a yield 1.35 percentage points higher than that of the stocks.
d.
The bonds have a yield 2.08 percentage points higher than that of the stocks.
Answer:
If the broker Josef employed to purchase these stocks and bonds charges a commission of $72 for each ten shares of stock bought or sold and a commission of 4% of the market value of each bond bought or sold, then the bonds have a yield 1.35 percentage points higher than that of the stocks.
Step-by-step explanation:
Two gears are connected and rotating at the same time. The smaller gear completes 2 1/2 rotations every time the larger gear completes 1/4 of a rotation.
How many rotations does the smaller gear complete when the larger gear completes 1 rotation?
A.1/10
B. 5/8
C. 5
D. 10
The small does 2 1/2 for 1/4 of the large. Multiply by 4 to get a full rotation of the large one:
2 1/2 x 4 = 10
answer: D. 10
Lela bought 3.3 pounds of nuts they cost $1.79 a pound. How much money did she spend
Answer:
5.907
Step-by-step explanation:
I believe if you multiply 3 times 1.79 you get 5.37 then if you multiply 0.3 times 1.79 you get 0.537. If you combine the 2 you get 5.907. I think this is correct not sure though D:
Find the 18th term in the arithmetic sequence.
2, 8, 14, 20, 26, ...
87
110
104
102
Answer:
104
Step-by-step explanation:
1st term + or - common difference (term -1)
common difference is +6
2 + 6 (18-1)
2 + 6 (17)
2 + 102
104
Determine the perimeter of the figure below:
6 cm
5 1/2
helpppp
Answer:
•SEE BELOW••WHAT IS PERIMETER?
>> PERIMETER MEANS THE SUM OF ALL SIDES OF FIGURE
NOW,LET'S SEE YOUR GIVEN QUESTION.
THE FIGURES 2 SIDES DATA IS GIVEN
•6CM
•5.5CM
THEREFORE : 6 + 5.5
: 11.5 CM
THE PERIMETER OF FIGURE IS 11.5 CM
Why 10^33/2=5*10^32? Explain, pls. :(
Answer:
see below
Step-by-step explanation:
10^33/2
Rewriting the numerator as 10 * 10 ^ 32
10 * 10 ^32
--------------------
2
10/2 = 5
5 * 10 ^32
Therefore
10^33/2=5*10^32
A vet is preparing a diet for a group of dogs. Each serving should be no larger than 8
ounces and must contain at least 29 units of Nutrient I and at least 20 units of Nutrient II.
The diet will be prepared from a combination of 2 brands, brand A and brand B. Each ounce
of brand A contains 3 units of Nutrient I and 4 units of Nutrient II. Each ounce of brand B
contains 5 units of Nutrient I and 2 units of Nutrient II. Brand A costs 3 cents/ounce and B
costs 4 cents/ounce. Determine how many ounces of each brand of dog food should be used
per serving in order to meet the given requirements at a minimum cost.
Question Number 16 You are the head seamstress at a boutique that specializes in making prom dresses. You are supervising the construction of a new style of dress that will take 180 hours of work to complete. Twenty percent of this time is for beading. Thirty-five percent of this time is for adding ruffles. The remaining time is divided equally between embroidery and sewing. When pricing this style, hourly labor and material costs are $40 for beading, $35 for ruffles, $20 for embroidery, and $18 for sewing. The dress is then sold in the showroom for 25% more than the cost of labor and materials. How much will this dress sell for in the boutique?
This dress will be sold in the boutique for $6,716.25.
Price calculationGiven that a new style of dress will take 180 hours of work to complete, and twenty percent of this time is for beading, thirty-five percent of this time is for adding ruffles, and the remaining time is divided equally between embroidery and sewing, and when pricing this style, hourly labor and material costs are $40 for beading, $35 for ruffles, $20 for embroidery, and $18 for sewing, and the dress is then sold in the showroom for 25% more than the cost of labor and materials, To determine how much this dress will sell for in the boutique, the following calculation must be made:
(((180 x 0.25) x 40) + ((180 x 0.35) x 35) + ((180 x 0.20) x 20) + ((180 x 0.20) x 18)) x 1.25 = X((45 x 40) + (63 x 35) + (36 x 20) + (36 x 18)) x 1.25 = X(1800 + 2205 + 720 + 648) x 1.25 = X5373 x 1.25 = X6,716.25 = XTherefore, this dress will be sold in the boutique for $6,716.25.
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Answer:
This dress will be sold in the boutique for $6,716.25.
Step-by-step explanation:
BRAINLIEST GIVEN)The figure is the net for a rectangular prism.
What is the surface area of the rectangular prism represented by the net?
Enter your answer in the box.
Answer:
238
Step-by-step explanation:
You have to find the area for each box and then you add all of them together
Answer:
238 mm²
Surface area of rectangular prsim = 2(lw + lh + wh)
Here,
length = 11 mm
width = 4 mm
height = 5 mm
area:
2*(4*11+5*11+5*4)238 mm²Find the domain and range of the function graphed below.
Domain:
Range:
The domain of the function is [-2, 2) while the range is [4, 2) (along the y -axis).
How to find the domain and range of a functionThe domain of a function is the input value for which the function exists while the range is the output value for which the function exists.
For the graph, the domain lie across the x-axis. The domain of the function is [-2, 2) while the range is [4, 2) (along the y -axis).
Note that point where the circles are shaded shows a closed interval
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