Coco, this is the solution to the inequality:
5 - 3x/2 ≥ 1/3
Subtracting 5 at both sides:
5 - 3x/2 - 5 ≥ 1/3 - 5
-3x/2 ≥ 1/3 - 15/3
-3x/2 ≥ -14/3
LCD (Least Common Denominator) between 2 and 3 : 6
-9x/6 ≥ -28/6
Dividing by -9/6 at both sides:
-9x/6 / -9/6 ≥ -28/6 / -9/6
x ≥ 28/9
In consequence, the correct answer is C. x ≥ 28/9
A rectangular prism has a legth of 5 1/4 m, a width of 4m, and a height of 12 m.How many unit cubes with edge lengths of 1/4 m will it take to fill the prism? what is the volume of the prism?
Volume of a cube with edge lengths of 1/4m:
[tex]\begin{gathered} V_{cube}=l^3 \\ \\ V_{cube}=(\frac{1}{4}m)^3=\frac{1^3}{4^3}m^3=\frac{1}{64}m^3 \end{gathered}[/tex]Volume of the rectangular prism:
[tex]\begin{gathered} V=l\cdot w\cdot h \\ \\ V=5\frac{1}{4}m\cdot4m\cdot12m \\ \\ V=\frac{21}{4}m\cdot4m\cdot12m \\ \\ V=252m^3 \end{gathered}[/tex]Divide the volume of the prism into the volume of the cubes:
[tex]\frac{252m^3}{\frac{1}{64}m^3}=252\cdot64=16128[/tex]Then, to fill the prism it will take 16,128 cubes with edge length of 1/4 mBased on the experimental probability, predict the number of times that you will roll a 5 if you roll the number cube 300 timesExperiment result on previews question: The number 5 was rolled 9 times out of 20 on a previous question
Explanation: To understand this problem we need to know that there are two different types of probability. The experimental probability and the theoretical probability.
- The experimental probability occurs once you conduct the experiment and after the experiment, you calculate the probability using the result of the experiment.
- The theoretical probability occurs before the experiment. Once you have information about the situation so you calculate the probability the get a specific result before trying.
Step 1: For this question, once we have a number cube with faces 1,2,3,4,5 and 6 and we want to know the experimental probability to get a 5 once you roll the cube 300 times you would need to get in real life a number cube and to roll it 300 times. After this experiment we would get all the results of each time we roll it and we would know how many times (from 300 times) we got a number 5. After that, we would use the following formula
[tex]Experimental_{probability}=\frac{number\text{ of times we got a number 5}}{300}[/tex]Once the get this result we finish the question.
Find the expression for the possible width of the rectangle.
Given the area of the rectangle is given by the following expression:
[tex]A=x^2+5x+6[/tex]The area of the rectangle is the product of the length by the width
So, we will factor the given expression
To factor the expression, we need two numbers the product of them = 6
and the sum of them = 5
So, we will factor the number 6 to find the suitable numbers
6 = 1 x 6 ⇒ 1 + 6 = 7
6 = 2 x 3 ⇒ 2 + 3 = 5
So, the numbers are 2 and 3
The factorization will be as follows:
[tex]A=(x+3)(x+2)[/tex]So, the answer will be the possible dimensions are:
[tex]\begin{gathered} \text{Length}=x+3 \\ \text{Width}=x+2 \end{gathered}[/tex]Question
Mrs. Hanson has a potato salad recipe that calls for 238 pounds of potatoes, but she wants to make 112 times as much as the recipe calls for.
The diagram represents the number of pounds of potatoes that Mrs. Hanson needs.
How many pounds of potatoes does Mrs. Hanson need?
Answer:
3 9/16 lbs
Step-by-step explanation:
Explain when you can cancel a number that is in both the numerator and denominator and when you cannot cancel out numbers that appear in both the numerator and the denominator.
Let me write here an example of a common number/term in both numerator and denominator that we can cancel.
[tex]\frac{4xy}{4}=xy[/tex]In the above example, we are able to cancel out the common number 4 because they are stand alone numbers. We can divide 4 by 4 and that is 1. Hence, the answer is just xy.
Another example:
[tex]\frac{(x+2)(x-1)}{(x+2)(2x-1)}=\frac{(x-1)}{(2x-1)}[/tex]In the above example, we are able to cancel out (x + 2) because this term is a common factor to both numerator and denominator.
In the example, we can also see that -1 is a common number however, we cannot cancel it out because the number -1 is not a standalone factor. It is paired with other number/variable. (x - 1) and (2x - 1) are both factors but are not the same, that is why, we are not able to cancel that.
Another example:
[tex]\frac{(x+2)+(x-1)}{(x+2)+(2x-1)}=\frac{(x+2)+(x-1)}{(x+2)+(2x-1)}[/tex]As we can see above, (x + 2) is a common term however, we cannot cancel it. We can only cancel common terms if they are common factors of both numerator and denominator. (Notice the plus sign in the middle. )
The term (x + 2) above is not a factor of the numerator and denominator, hence, we cannot cancel it.
The table below shows possible outcomes when two spinners that are divided into equal sections are spun. The first spinner is labeled with five colors, and the second spinner is labeled with numbers 1 through 5. Green Blue Pink Yellow Red 1 Gi B1 P1 Y1 R1 1 2 . G2 B2 P2 Y2 R2 3 G3 B3 P3 Y3 R3 4 G4 B4 P4 Y4 R4 5 G5 B5 P5 Y5 R5 According to the table, what is the probability of the first spinner landing on the color pink and the second spinner landing on the number 5?
Answer:
P = 0.04
Explanation:
The probability is equal to the number of options where the first spinner is landing on the color pink and the second spinner is landing on the number 5 divided by the total number of options.
Since there is only one option that satisfies the condition P5 and there are 25 possible outcomes, the probability is:
[tex]P=\frac{1}{25}=0.04[/tex]So, the answer is P = 0.04
Can someone do it for me please
Step-by-step explanation:
13.
a/7 + 5/7 = 2/7
a/7 = 2/7 - 5/7 = -3/7
a = -3
14.
6v - 5/8 = 7/8
6v = 7/8 + 5/8 = 12/8
v = 12/8 / 6 = 2/8 = 1/4
15.
j/6 - 9 = 5/6
j - 54 = 5
j = 5 + 54 = 59
16.
0.52y + 2.5 = 5.1
0.52y = 5.1 - 2.5 = 2.6
y = 2.6/0.52 = 5
17.
4n + 0.24 = 15.76
4n = 15.76 - 0.24 = 15.52
n = 15.52/4 = 3.88
18.
2.45 - 3.1t = 21.05
-3.1t = 21.05 - 2.45 = 18.6
t = 18.6/-3.1 = -6
The ratio of the volume of two spheres is 8:27. What is the ratio of their radii?
We have that the volume of the spheres have a ratio of 8:27.
[tex]undefined[/tex]This means that the relation between linear measures, like the radii, will be the cubic root of that ratio
3. The data in the table gives the number of barbeque sauce bottles (y) that are sold with orders of chicken wings (x) for each hour on a given day at Vonn's Grill. Use technology to write an equation for the line of best fit from the data in the table below. Round all values to two decimal places.
1) Let's visualize the points
2) To find the equation for the line of best fit we'll need to follow some steps.
2.1 Let's find the mean of the x values and the mean of the Y values
2.2 Now It's time to find the slope, with the summation of the difference between each value and the mean of x times each value minus the mean over the square of the difference of the mean of x and x.
To make it simpler, let's use this table:
The slope then is the summation of the 5th column over the 6th column, we're using the least square method
[tex]m=\frac{939.625}{1270.875}=0.7393\cong0.74[/tex]The Linear coefficient
[tex]\begin{gathered} b=Y\text{ -m}X \\ b=14.625-0.73(19.875) \\ b=0.11625\cong0.12 \end{gathered}[/tex]3) Finally the equation of the line that best fit is
[tex]y=0.73x+0.12[/tex]Julia found the equation of the line perpendicular toy = -2x + 2 that passes through (5.-1).Analyze Julia's work. Is she correct? If not, what washer mistake?1 y25= 1/2 (-2) + 6Yes, she is correct,No, she did not use the opposite reciprocal for theslope of the perpendicular line.No, she did not substitute the correct x and yvaluesNo she did not apply inverse operations to solve forthe y-intercept.3+5b=555y=x5.5
The given line is
[tex]y=-2x+2[/tex]The line passes through (5, -1),
Perpendicular lines have opposite slopes, so we use the following equation to find the new slope knowing that the slope of the given line is -2.
[tex]\begin{gathered} m\cdot m_1=-1 \\ m\cdot(-2)=-1 \\ m=\frac{-1}{-2} \\ m=\frac{1}{2} \end{gathered}[/tex]Now, we use the slope, the point, and the point-slope formula to find the equation.
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-(-1)=\frac{1}{2}(x-5) \\ y+1=\frac{1}{2}x-\frac{5}{2} \\ y=\frac{1}{2}x-\frac{5}{2}-1 \\ y=\frac{1}{2}x+\frac{-5-2}{2} \\ y=\frac{1}{2}x-\frac{7}{2} \end{gathered}[/tex]Therefore, the equation of the new perpendicular line is[tex]y=\frac{1}{2}x-\frac{7}{2}[/tex]So, she's not correct, she didn't substitute the correct x and y values.
The right answer is C.Consider the following functions round your answer to two decimal places if necessary
Solution
Step 1:
[tex]\begin{gathered} f(x)\text{ = }\sqrt{x\text{ + 2}} \\ \\ g(x)\text{ = }\frac{x-2}{2} \end{gathered}[/tex]Step 2
[tex]\begin{gathered} (\text{ f . g\rparen\lparen x\rparen = }\sqrt{\frac{x-2}{2}+2} \\ \\ (\text{ f . g\rparen\lparen x\rparen }=\text{ }\sqrt{\frac{x\text{ +2}}{2}} \end{gathered}[/tex]Step 3
Domain definition
[tex]\begin{gathered} The\:domain\:of\:a\:function\:is\:the\:set\:of\:input\:or\:argument\:values \\ \:for\:which\:the\:function\:is\:real\:and\:defined. \\ \mathrm{The\:function\:domain} \\ x\ge \:-2 \\ \\ \:\mathrm{Interval\:Notation:}\text{ \lbrack-2, }\infty) \end{gathered}[/tex]Final answer
A committee of five members is to be randomly selectedfrom a group of nine freshman and seven sophomores.Which expression represents the number of different committeesof three freshman and two sophomores that can be chosen?
The answer would be the product of the number of 3 freshman groups by 2 sophomores groups.
The number of 3 freshman groups is given by
[tex]C^9_3=\frac{9\times8\times7}{3\times2\times1}=84[/tex]The number of 2 sophomore groups is given by
[tex]C^7_2=\frac{7\times6}{2\times1}=21[/tex]Now, doing their product
[tex]21\times84=1764[/tex]We have 1764 different committees of three freshman and two sophomores.
12/13+-1/13 equals what ?
Given:
[tex]\frac{12}{13}+(-\frac{1}{13})[/tex]Adding a negativen number is the same as subtracting that number, so:
[tex]\frac{12}{13}-\frac{1}{13}[/tex]Since both denominators (bottom number ) are equal we can subtract the numerators ( top numbers)
[tex]\frac{(12-1)}{13}=\frac{11}{13}[/tex]Answer:
[tex]\frac{11}{13}[/tex]13 nickels to 43 dimes in a reduced ratio form
The reduced ratio form of 13 nickels to 43 dimes is 13/86.
What is a ratio?
a ratio let us know that how many times one number contains another number.
We are given 13 nickels and 43 dimes.
We know that 1 dime equal to 2 nickels.
Hence 43 dimes equals 86 nickels.
Now we find the ratio of the 2.
Which will be [tex]\frac{13}{86}[/tex]
Hence the reduced ratio form is 13/86.
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Use the graph below to determine the equation of the circle in (a) center-radius form and (b) general form.10-(-3,6)(-6,3(0,3)-10(-3,0)1010
Question:
Solution:
An equation of the circle with center (h,k) and radius r is:
[tex](x-h)^2+(y-k)^2=r^2[/tex]This is called the center-radius form of the circle equation.
Now, in this case, notice that the center of the circle is (h,k) = (-3,3) and its radius is r = 3 so that the center-radius form of the circle would be:
[tex](x+3)^2+(y-3)^2=3^2[/tex]To obtain the general form, we must solve the squares of the previous equation:
[tex](x+3)^2+(y-3)^2-3^2\text{ = 0}[/tex]this is equivalent to:
[tex](x^2+6x+3^2)+(y^2-6y+3^2)\text{ - 9 = 0}[/tex]this is equivalent to
[tex]x^2+6x+9+y^2-6y\text{ = 0}[/tex]this is equivalent to:
[tex]x^2+y^2+6x-6y\text{ +9= 0}[/tex]so that, the general form equation of the circle would be:
[tex]x^2+y^2+6x-6y\text{ +9= 0}[/tex]thus, the correct answer is:
CENTER - RADIUS FORM:
[tex](x+3)^2+(y-3)^2=3^2[/tex]GENERAL FORM:
[tex]x^2+y^2+6x-6y\text{ +9= 0}[/tex]Jackson purchased a pack of game cards that was on sale for 22% off. The sales tax in his county is 6%. Let y represent the oeiginal price of the card.. Wrote an expression that can be used to determine the final cost of the cards.
Given:
Discount - 22% = 0.22
Sales Tax - 6% = 0.06
Required:
Expression for the final cost of the cards, x
Solution:
Let: y represent the original price of the card.
x represent the final cost of the cards
D represent the discounted cost of the cards
Assume that the the sales tax is applied to the price after the discount.
D= Original Price ( 1 - Discount) = y ( 1 - 0.22) = 0.78y
To compute for the final cost,
Final Cost = D + Tax
Tax = 0.06 D
x = D + 0.6(D)
x = 1.06D
x = 1.06 ( 0.78 y)
x = 0.827y
Answer:
The final cost of the card can be describe by the expression:
x = 0.827y
[tex] f(x) = 3x^{2} - 2x + 3[/tex]if (-3,n) is an element of the function what is the value of n?
SOLUTION
[tex]\begin{gathered} f(x)=3x^2\text{ - 2x + 3 } \\ \text{Here, (-3, n) can be written as (x, y), where x = -3 and y = n} \\ \text{Also y is also = f(x). } \\ \text{That is y = }3x^2\text{ - 2x + 3 } \end{gathered}[/tex]Now putting x = -3 into f(x) or y, we have that
[tex]\begin{gathered} y=3(-3)^2\text{ -2(-3) + 3} \\ y\text{ = 3(9) + 6 + 3} \\ y\text{ = 27 + 6 + 3} \\ y\text{ = 36. } \\ \text{Since y = n, therefore, n = 36. } \end{gathered}[/tex]The value of n is 36
call Scott's is collecting canned food for food drive is class collects 3 and 2/3 pounds on the first day in 4 and 1/4 lb on second day how many pounds of food has they collected so far
The food collected on first day,
[tex]\begin{gathered} 3\frac{2}{3} \\ =\frac{3\times3+2}{3} \\ =\frac{9+2}{3} \\ =\frac{11}{3} \end{gathered}[/tex]The food collected on second day,
[tex]\begin{gathered} 4\frac{1}{4} \\ =\frac{4\times4+1}{4} \\ =\frac{16+1}{4} \\ =\frac{17}{4} \end{gathered}[/tex]The total amount of food collected can be calculated as,
[tex]\begin{gathered} T=\frac{11}{3}+\frac{17}{4} \\ =\frac{11\times4+17\times3}{3\times4} \\ =\frac{44+51}{12} \\ =\frac{95}{12} \\ =7\frac{11}{12} \end{gathered}[/tex]Therefore, the total amount of food collected so far is 7 11/12 pounds.
Use the appropriate differenatal formula to find© the derivative of the given function6)3(16) 96) = (x²-1) ²(2x+115
1) We need to differentiate the following functions:
[tex]\begin{gathered} a)\:f(x)=x\sqrt[3]{1+x^2}\:\:\:\:Use\:the\:product\:rule \\ \\ \\ \frac{d}{dx}\left(x\right)\sqrt[3]{1+x^2}+\frac{d}{dx}\left(\sqrt[3]{1+x^2}\right)x \\ \\ \\ 1\cdot \sqrt[3]{1+x^2}+\frac{2x}{3\left(1+x^2\right)^{\frac{2}{3}}}x \\ \\ \sqrt[3]{1+x^2}+\frac{2x^2}{3\left(x^2+1\right)^{\frac{2}{3}}} \\ \\ f^{\prime}(x)=\sqrt[3]{1+x^2}+\frac{2x^2}{3\left(1+x^2\right)^{\frac{2}{3}}} \end{gathered}[/tex]Note that we had to use some properties like the Product Rule, and the Chain Rule.
b) We can start out by applying the Quotient Rule:
[tex]\begin{gathered} g(x)=\frac{(x^2-1)^3}{(2x+1)} \\ \\ f^{\prime}(x)=\frac{\frac{d}{dx}\left(\left(x^2-1\right)^3\right)\left(2x+1\right)-\frac{d}{dx}\left(2x+1\right)\left(x^2-1\right)^3}{\left(2x+1\right)^2} \\ \\ Differentiating\:each\:part\:of\:that\:quotient: \\ \\ ------- \\ \frac{d}{dx}\left(\left(x^2-1\right)^3\right)=3\left(x^2-1\right)^2\frac{d}{dx}\left(x^2-1\right)=6x\left(x^2-1\right)^2 \\ \\ \frac{d}{dx}\left(x^2-1\right)=\frac{d}{dx}\left(x^2\right)-\frac{d}{dx}\left(1\right)=2x \\ \\ \frac{d}{dx}\left(x^2\right)=2x \\ \\ \frac{d}{dx}\left(1\right)=0 \\ \\ \frac{d}{dx}\left(2x+1\right)=2 \\ \\ Writing\:all\:that\:together: \\ \\ f^{\prime}(x)=\frac{6x\left(x^2-1\right)^2\left(2x+1\right)-2\left(x^2-1\right)^3}{\left(2x+1\right)^2} \\ \end{gathered}[/tex]Thus, these are the answers.
If the two triangles shown below are similar based on the giveninformation, complete the similarity statement, otherwise choose the"Not Similar" button.А18 in9 inHB7 in14 inACAB-ANot Similar
1) Two triangles are similar if they have congruent angles and proportional sides (for each corresponding leg).
2) So let's check whether there are similar triangles by setting a proportion:
[tex]\begin{gathered} \frac{HC}{CA}=\frac{JH}{CB} \\ \frac{9}{18}=\frac{7}{14} \\ Simplify\text{ both:} \\ \frac{1}{2}=\frac{1}{2} \end{gathered}[/tex]3) So yes they are similar, i.e. ΔCAB ~ΔHGJ
ten B В 15 cm А 20 cm С C
Tangent segment, of a circle
Apply formulas
20^2 - 15^ 2 = AB^2
Also
15^2 = 20•( 20 - AB)
225 = 400 - 20AB
Then
20AB = 400-225= 175
AB = √ 175= 13 + 6/25 =13.24
Shaun deposits $3,000 into an account that has an rate of 2.9% compounded continuously. How much is in the account after 2 years and 9 months?
The formula for finding amount in an investment that involves compound interest is
[tex]A=Pe^{it}[/tex]Where
A is the future value
P is the present value
i is the interest rate
t is the time in years
e is a constant for natural value
From the question, it can be found that
[tex]\begin{gathered} P=\text{ \$3000} \\ i=2\frac{9}{12}years=2\frac{3}{4}years=2.75years \end{gathered}[/tex][tex]\begin{gathered} e=2.7183 \\ i=2.9\text{ \%=}\frac{2.9}{100}=0.029 \end{gathered}[/tex]Let us substitute all the given into the formula as below
[tex]A=3000\times e^{0.29\times2.75}[/tex][tex]\begin{gathered} A=3000\times2.21999586 \\ A=6659.987581 \end{gathered}[/tex]Hence, the amount in the account after 2 years and 9 months is $6659.99
Factor the quadratic expression2x²+x-62x+ +x-6= (Factor completely.)
2x² + x - 6
The coefficient of x² is 2 and the constant term is -6. The product of 2 and -6 is -12. The factors of -12 which sum 1 are -3 and 4 so:
2(2x - 3) + x(2x - 3)
Factor 2x - 3 from 2(2x - 3) + x(2x - 3):
(2x - 3)(x + 2)
help meeeeeeeeee pleaseee !!!!!
The simplified answer of the composite function is as follows:
(f + g)(x) = 2x + 3x²(f - g)(x) = 2x - 3x²(f. g)(x) = 6x³(f / g)(x) = 2 / 3xHow to solve composite function?Composite functions is a function that depends on another function. A composite function is created when one function is substituted into another function.
In other words, a composite function is generally a function that is written inside another function.
Therefore,
f(x) = 2x
g(x) = 3x²
Hence, the composite function can be simplified as follows:
(f + g)(x) = f(x) + g(x) = 2x + 3x²
(f - g)(x) = f(x) - g(x) = 2x - 3x²
(f. g)(x) = f(x) . g(x) = (2x)(3x²) = 6x³
(f / g)(x) = f(x) / g(x) = 2x / 3x² = 2 / 3x
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I need help on doing this finding the slope of a line
Given:
[tex](x_1,y_1)=(1,6)and(x_2,y_2)=(6,1)[/tex][tex]\text{Slope(m)=}\frac{y_2-y_1}{x_2-x_1}[/tex][tex]\text{Slope(m)=}\frac{1-6}{6-1}[/tex][tex]\text{Slope(m)}=-\frac{5}{5}[/tex][tex]\text{Slope (m)=-1}[/tex]he two-way frequency table given shows the results from a survey of students who attend the afterschool program.
Takes Art Class Doesn't Take Art Class Total
Plays a Sport 45 120
Doesn't Play a Sport 45
Total 225
Does the data show an association between taking an art class and playing a sport?
There is a strong, positive association.
There is a strong, negative association.
There is a weak, positive association.
There is a weak, negative association.
The association between the variables art class and playing a sport is classified as follows:
There is a strong, negative association.
What is the association between the two variables?The association between variables can be classified either as positive or as negative, as follows:
Positive: both variables behave similarly, either both increases or both decreasing.Negative: the variables behave in an inversely manner, with one increasing and the other decreasing, or vice-versa.In the context of this problem, it is found that of the students that take art class, the majority do not play a sport, while among those who do not take art class, the majority play a sport, hence there is a strong and negative association between the two variables.
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A local real estate company has 5 real estate agents. The number of houses that each agent sold last year is shown in the bar graph below. Use this bar graph to answer the questions.
Given:
Rachel sold 4 houses.
Heather sold 4 houses.
Kaitlin sold 12 houses.
Lena sold 11 houses.
Deshaun sold 3 houses.
Required:
a) We need to find which agent sold the most houses.
b) We need to find the number of houses Lna soldemore than Heather.
c) We need to find the number of agents who sold fewer than 4 houses.
Explanation:
a)
The greatest number of houses sold =12 houses.
Kaitlin sold 12 houses.
Answer:
The agent Kaitlin sold the most houses.
The agent sold 12 houses.
b)
Lena sold 11 houses.
Heather sold 4 houses.
The difference between 11 and 4 is 11-4 =7.
Answer:
Lena sold 7 housmore than Heather
8.[–/1 Points]DETAILSALEXGEOM7 9.2.012.MY NOTESASK YOUR TEACHERSuppose that the base of the hexagonal pyramid below has an area of 40.6 cm2 and that the altitude of the pyramid measures 3.7 cm. A hexagonal pyramid has base vertices labeled M, N, P, Q, R, and S. Vertex V is centered above the base.Find the volume (in cubic centimeters) of the hexagonal pyramid. (Round your answer to two decimal places.) cm3
Solution
- The base is a regular hexagon. This implies that it can be divided into equal triangles.
- These equal triangles can be depicted below:
- If each triangle subtends an angle α at the center of the hexagon, it means that we can find the value of α since all the α angles are subtended at the center of the hexagon using the sum of angles at a point which is 360 degrees.
- That is,
[tex]\begin{gathered} α=\frac{360}{6} \\ \\ α=60\degree \end{gathered}[/tex]- We also know that regular hexagon is made up of 6 equilateral triangles.
- Thus, the formula for finding the area of an equilateral triangle is:
[tex]\begin{gathered} A=\frac{\sqrt{3}}{4}x^2 \\ where, \\ x=\text{ the length of 1 side.} \end{gathered}[/tex]- Thus, the area of the hexagon is:
[tex]A=6\times\frac{\sqrt{3}}{4}x^2[/tex]- With the above formula we can find the length of the regular hexagon as follows:
[tex]\begin{gathered} 40.6=6\times\frac{\sqrt{3}}{4}x^2 \\ \\ \therefore x=15.626947286066 \end{gathered}[/tex]- The formula for the volume of a hexagonal pyramid is:
[tex]\begin{gathered} V=\frac{\sqrt{3}}{2}b^2\times h \\ where, \\ b=\text{ the base} \\ h=\text{ the height.} \end{gathered}[/tex]- Thus, the volume of the pyramid is
[tex]\begin{gathered} V=\frac{\sqrt{3}}{2}\times15.626947286066^2\times3.7 \\ \\ V=782.49cm^3 \end{gathered}[/tex]I’m confused on this question. I just have to choose which one
SOLUTION:
Case: Circle theorems
Method:
From the given circle
Theorem: The angle at the center of the circle is twice the angle at the circumference formed by the same segment.
The implication to the circle in the question is:
[tex]\begin{gathered} \hat{mST}=2m\angle2 \\ OR \\ m\angle2=\frac{1}{2}(\hat{mST}) \end{gathered}[/tex]Final answer
[tex]m\operatorname{\angle}2=\frac{1}{2}(\hat{mST})[/tex]I need help with this question can you please help me
Given the following question:
[tex]\begin{gathered} x^2+3x-5=0 \\ \text{ Convert using the quadratic formula:} \\ x^2+3x-5=0=x_{1,\:2}=\frac{-3\pm\sqrt{3^2-4\cdot\:1\cdot\left(-5\right)}}{2\cdot\:1} \\ x_{1,\:2}=\frac{-3\pm \sqrt{3^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1} \\ \text{ Solve} \\ 3^{2}-4\times1(-5) \\ 1\times-5=-5 \\ 3^2-4\times-5 \\ 3^2=3\times3=9 \\ =29 \\ =\sqrt{29} \\ x_{1,\:2}=\frac{-3\pm \sqrt{29}}{2\cdot \:1} \\ \text{ Seperate the solutions:} \\ x_1=\frac{-3+\sqrt{29}}{2\cdot \:1} \\ x_2=\frac{-3-\sqrt{29}}{2\cdot\:1} \\ \text{ Simplify} \\ 2\times1=2 \\ x=\frac{-3+\sqrt{29}}{2} \\ x=\frac{-3-\sqrt{29}}{2} \end{gathered}[/tex]Your answers are the first and second options.