(4 to the 3rd power * 4 to the 6 power)to the 5th power

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Answer 1

hello

if i'm right, what you're trying to ask is


Related Questions

I have a question about how to solve graphing a system of inequalities and about how to do the (0,0)

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The given system of inequality is

[tex]\begin{gathered} 2x-3y>-12 \\ x+y\ge-2 \end{gathered}[/tex]

At first, we must draw the lines to represent these inequalities

[tex]2x-3y=-12[/tex]

Let x = 0, then find y

[tex]\begin{gathered} 2(0)-3(y)=-12 \\ 0-3y=-12 \\ -3y=-12 \\ \frac{-3y}{-3}=\frac{-12}{-3} \\ y=4 \end{gathered}[/tex]

The first point is (0, 4)

Let y = 0

[tex]\begin{gathered} 2x-3(0)=-12 \\ 2x-0=-12 \\ 2x=-12 \\ \frac{2x}{2}=\frac{-12}{2} \\ x=-6 \end{gathered}[/tex]

The second point is (-6, 0)

We will do the same with the second line

Let x = 0

[tex]\begin{gathered} 0+y=-2 \\ y=-2 \end{gathered}[/tex]

The first point is (0, -2)

Let y = 0

[tex]\begin{gathered} x+0=-2 \\ x=-2 \end{gathered}[/tex]

The second point is (-2, 0)

Since the sign of the first inequality is >, then the line will be dashed

Since the sign of the second inequality is >=, then the line will be solid

Let us substitute x, y by the origin point (0,0) in both inequalities to find the shaded part of each one

[tex]\begin{gathered} 2(0)-3(0)>-12 \\ 0-0>-12 \\ 0>-12 \end{gathered}[/tex]

Since the inequality is true then the point (0, 0) lies on the shaded area

[tex]\begin{gathered} 0+0\ge-2 \\ 0\ge-2 \end{gathered}[/tex]

Since the inequality is true, then point (0, 0) lies in the shaded area

Let us draw the graph

The red line represents the first inequality

The blue line represents the second inequality

The area of two colors is the area of the solution

Point (0, 0) lies in this area, then it is a solution for the given system of inequalities

Will give brainliest thank you..!

Answers

Answer:

4

Step-by-step explanation:

4

4

4

4

Is y = 8 a solution to the inequality below?

Answers

Answer:

Yes

Step-by-step explanation:

136/8 = 17

17 +3 = 20

20 is less than or equal to 123 so 8 does work as a solution

Margie uses 36 inches of lace to make one pillow. She makes 24 pillows for the school fair. How many total inches of lace does Margie use on the pillows?

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Margie used a total of 264 inches of lace for the 24 pillows

How to calculate the total inches of lace used ?

Margie used 36 inches of lace for one pillow

She needs to make 24 pillows

The total inches of lace that was used for the 24 pillows can be calculated as follows

= 36 × 24

= 864

Hence Margie used 864 inches of lace for 24 pillows

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Please someone can help me please #1

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Complete the  following Division

Quotient of 96, 55, 84 and 63 is 12, 11, 14 and 21 respectively

What is Division?

One of the four fundamental arithmetic operations, or how numbers are combined to create new numbers, is division. The other operations are multiplication, addition, and subtraction.

1) 96

Divisor = 8

96 / 8

= 12

Quotient = 12

2) 55

Divisor = 5

55 / 5

= 11

Quotient = 11

3) 84

Divisor = 6

84 / 6

= 14

Quotient = 14

4) 63

Divisor = 3

63 / 3

= 21

Quotient = 21

Hence , Quotient of 96, 55, 84 and 63 is 12, 11, 14 and 21 respectively

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Amanda y Pedro realizaron queques iguales, Lurdes se comió 2/4 partes, Amanda 2/3 y Pedro 3/4, quien comió menos?

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A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96 m long and 64 m wide. Find the area of the training field. Use the value 3.14 for n, and do not round your answer. Be sure to include the correct unit in your answer.

Answers

To find:

The area of the training field.

Solution:

The training field is made of two semicircles and a rectangle.

The length and width of the rectangle is 96 m and 64 m. So, the area of the rectangle is:

[tex]\begin{gathered} A=l\times w \\ =96\times64 \\ =6144\text{ m}^2 \end{gathered}[/tex]

The diameter of the semicircle is 64 m. SO, the radius of the semicircle is 32 m.

The area of two semicircles is:

[tex]\begin{gathered} A=2\times\frac{1}{2}\pi r^2 \\ =3.14\times(32)^2 \\ =3.14\times1024 \\ =3215.36 \end{gathered}[/tex]

So, the area of the training field is:

[tex]\begin{gathered} A=6144+3215.36 \\ =9359.36 \end{gathered}[/tex]

Thus, the area of the training field is 9359.36 m^2.

reduce to lowest term.5p+5q/4p+4q

Answers

[tex]\frac{5}{4}[/tex]

Explanation

[tex]\frac{5p+5q}{4p+4q}[/tex]

Step 1

factorize

[tex]\begin{gathered} 5p+5q\rightarrow5\text{ is a common factor, so}\rightarrow5(p+q) \\ 4p+4q\rightarrow4\text{ is a common factor, so}\rightarrow4(p+q) \end{gathered}[/tex]

hence, the expression would be

[tex]\begin{gathered} \frac{5p+5q}{4p+4q}=\frac{5(p+q)}{4(p+q)} \\ \frac{5(p+q)}{4(p+q)} \end{gathered}[/tex]

Step 2

now, we can see there is the same factor in numerator and denominator (p+q), so it can be eliminated.

[tex]\begin{gathered} \frac{5(p+q)}{4(p+q)}=\frac{5}{4} \\ \frac{5}{4} \end{gathered}[/tex]

therefore, the answer is

[tex]\frac{5}{4}[/tex]

I hope this helps you

Solve the equation 7-(5t-13)=-25-15b+21+5b=-19

Answers

Let's solve the following expressions:

a.) 7 - (5t - 13) = -25

[tex]\text{ 7 - (5t - 13) = -25}[/tex][tex]\text{ 7 - 5t + 13 = -25}[/tex][tex]\text{ 20 - 5t = -25}[/tex][tex]\text{-5t = -25 - 20}[/tex][tex]\text{-5t = -4}5[/tex][tex]\frac{\text{-5t}}{-5}\text{ = }\frac{\text{-4}5}{-5}[/tex][tex]\text{ t = 9}[/tex]

Therefore, t = 9

b.) -15b + 21 + 5b = -19

[tex]-15b+21+5b=-19[/tex][tex]-10b+21=-19[/tex][tex]-10b=-19\text{ - 21}[/tex][tex]-10b=-40[/tex][tex]\frac{-10b}{-10}=\frac{-40}{-10}[/tex][tex]\text{ b = 4}[/tex]

Therefore, b = 4

Can someone help me with this geometry question?A.Triangular prismB.Hexagonal prismC.Triangular pyramidD.Hexagonal pyramid

Answers

B. Hexagonal Prism

1) One prism is defined, in terms of naming it by the base.

2) Counting the edges of the base in this net surface, we can tell that this is a Hexagonal Prism for the base is a hexagon.

in chess, the knight (the piece shaped like a horse) moves in an L pattern.

Answers

yes, that is correct.

Answer:

That is true but still remember that playing the knight at the start can be very useful.

P(A) = 1/4 P(A n B) = 1/12 P(AUB) = 13/24 Find P(B) c 21/24 5/24 O O O 3/8 11/24

Answers

Okay, here we have this:

Considering that P(AUB)=P(A)+P(B)-P(AintersectionB), we obtain that:

P(B)=P(AUB)-P(A)+P(AnB)

P(B)=(13/24)-(1/4)+(1/12)

P(B)=3/8

Finally we obtain that P(B) is equal to 3/8.

What Is the inverse of.. (ignore pencil writing) -matrices- (there may be more than one answer

Answers

[tex]A^{-1}\text{ =}\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}\text{ (option B)}[/tex]

Explanation:[tex]\begin{bmatrix}{3} & {5} & {} \\ {1} & {2} & {} \\ {} & {} & {}\end{bmatrix}[/tex]

To find the inverse of the matrix, first let's find the determinant:

[tex]\begin{gathered} |A|\text{ = 3(2) - 5(1)} \\ |A|\text{ = 6 - 5} \\ |A|\text{ = 1} \end{gathered}[/tex]

Then, we'll find the Adjunct of the matrix:

[tex]\begin{gathered} \begin{bmatrix}{3} & {5} & {} \\ {1} & {2} & {} \\ {} & {} & {}\end{bmatrix}\text{ : interchange }3\text{ and 2. negate 1 and 5} \\ \text{Adjunct = }\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix} \end{gathered}[/tex][tex]\begin{gathered} In\text{verse of the matrix = }\frac{1}{|A|}\times\text{ adjunct} \\ A^{-1}\text{ = }\frac{1}{1}(\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}) \\ A^{-1}\text{ =}\begin{bmatrix}{2} & {-5} & {} \\ {-1} & {3} & {} \\ {} & {} & {}\end{bmatrix}\text{ (option B)} \\ \end{gathered}[/tex]

Tiffany works at a lawnmower store.Part AA portion of Tiffany's monthly salary is based on commission. She earns 21% of everything she sells. This month she sold $27,000 worth of lawnmowers. Howmuch was her sales commission this month?Part BThe store purchased one riding lawn mower for $1,500 and sold it for $2025. What percentage was the markup for the mower?PartTiffany earns $15 per hour. The store offers her a raise-a 2% increase per hour. After the raise, how much will Tiffany make per hour?

Answers

1) Gathering the data

Part A

Tiffany's Commission: 21%

Sales Revenue: 27,000

2) In this case, we can figure out how much has she earned by doing this:

[tex]27,000\text{ }\times0.21=5,670[/tex]

Part B)

$1,500

$ 2,025

We can solve it in 2 steps. Firstly let's find the equivalence of 2025 in percentage.

1500-------100%

2025- ----x

1500x = 202500

x=202500/1500

x =135%

Now we need to subtract from 100%. 135%-100%= 35%

So the percentage (markup) was 35%. That lawnmower was sold 35% above the price.

Part C)

$15 per hour

2% per hour (0.02)

In this, case we need a simple calculation multiplying that 15 by (1 +0.02)

15 x ( 1 +0.02)

15 x (1.02)

15.3

After the raise, Tiffany earns $15.30 per hour

Use the Distributive Property to solve the equation 2/3 (9a + 6) = 23.8

Answers

Distributive property tell us how to solve expressions in the form a(b+c), it says:

a(b+c)=ab+ac

Then,

[tex]\begin{gathered} \frac{2}{3}(9a+6)=23.8 \\ \frac{18a}{3}+\frac{12}{3}=23.8 \\ 6a+4=23.8 \\ 6a=23.8-4 \\ a=\frac{19.8}{6}=3.3 \end{gathered}[/tex]

use the angle shown to determine if the line are parallel

Answers

If the lines were parallel then

angle H would be corresponding to angle L and then

[tex]\measuredangle H\cong\measuredangle Z.[/tex]

Since angles H and Z are a linear pair then if the lines were parallel angle H, Z and L would have to be right angles. Since the problem never states that those angles are right angles, then the lines are not necessarily parallel.

Answer: No.

Need help asap please and thank you

Answers

Answer:

y=[tex]\frac{1}{2}[/tex]x+1

Step-by-step explanation:

y=mx+b

m is the slope of the line, which you find by counting the rise over run between two points. In this case its up one, and right two, or [tex]\frac{1}{2}[/tex].

b is the y intercept, or where the line crosses the y axis

karen recorded her walking pace in the table below. what equation best represents this relationship

Answers

Given Data:

The table given here shows time taken in the first column and the distance travelled in the second column.

First check the ration of distance /time to verify if the speed of the man is constant or not.

[tex]\begin{gathered} \frac{8.75\text{ m}}{2.5\text{ h}}=3.5\text{ m/h} \\ \frac{14\text{ m}}{4\text{ h}}=3.5\text{ m/h} \end{gathered}[/tex]

As both ratios are same it means the speed of the man is constant and the distance travelled is directly proportional to the time taken and varies linealy with the time.

Now to determine the relationship between m and h we will use the same ratio of m and h which comes in the previous step.

[tex]\begin{gathered} \frac{m}{h}=3.5 \\ m=3.5h \end{gathered}[/tex]

Thus, option (D) is the required solution.

Three times a number decreased by 1 is 10 Three times the difference of a number is 1 is 10One less than three times a number is 10The quotient of a number and 3 is 10

Answers

Three times a number decreased by 1 is 10:

X is the number.

3x = three times a number.

3x - 1 = 10 (Three times a number decreased by 1 is 10)

3x = 10 + 1

3x = 11

x = 11/3

A straight line is 180 degrees. Find the value of X.

Answers

Given a straight line angle = 180

So, the angles (9x-100) and (40-x) are supplementary angles

So,

[tex](9x-100)+(40-x)=180[/tex]

Solve for x:

[tex]\begin{gathered} (9x-x)+(40-100)=180 \\ 8x-60=180 \\ 8x=180+60 \\ 8x=240 \\ x=\frac{240}{8}=30 \end{gathered}[/tex]

So, the answer will be x = 30

Harry fills up his Jeep with gasoline and notes that the odometer reading is 23,529.6 miles. The next time he fills up his Jeep, he pays for 10 gallons of gasoline he notes his odometer reading is 23,640.6 miles. How many miles per gallon did he get? (Round the answer to the nearest 10th if necessary.)

Answers

Answer:

11.1 miles per gallon

Explanation:

Given;

Odometer reading when the jeep is filled up with gasoline = 23,529.6 miles

Odometer reading when the jeep is filled up with 10 gallons of gasoline =23,640.6 miles

We can now go ahead and determine how many miles per gallon Harry got as seen below;

[tex]\begin{gathered} \frac{(Reading\text{ when j}eep\text{ is filled with 10 gallons }-Reading\text{ when j}eep\text{ is filled up)}}{\text{Gallo of gasoline}} \\ =\frac{23640.6-23529.6}{10}=\frac{111}{10}=11.1\text{miles per gallon} \end{gathered}[/tex]

So Harry got 11.1 miles per gallon

1 4 a) Is the above sequence arithmetic? Justify your answer. b) Write the explicit formula for the above sequence. c) Find the 18th term.

Answers

THe length of each cube is inreasing by 1. This means that the increment is in arithmetic sequence.

The formula for determining the nth term of an aritmetic sequence is expressed as

Tn = a + (n - 1)d

Where

a represents the first tem of the sequence

Common difference, d represents the difference between consecutive terms

Given that a = 3, d = 1

Tn = 2 + (n - 1)1

Tn = 2 + n - 1

Tn = 1 + n

For the 18th term, n = 18

T18 = 1 + 18 = 19

The number of boxes in the square for the 19th term is

19 * 19 = 361

Can you help me solve the domain of this math word problem?

Answers

the domain refers to all possible values of x in the function.

since a negative time does not make sense, the smallest value of the domain is zero

on the other hand, the problem indicates that the model is considered accurate up to 100,000 years, therefore that would be the largest value of t

in conclusion, the domain of the function A(t) is

[tex]\lbrack0,100000\rbrack[/tex]

[ 0 , 100,000 ]

The length of time (T) in seconds it takes the pendulum of a clock to swing through one compete cycle is givenby the formulaT= 2T✔️L/32 Where L is the length, in feet, of the pendulum, and is pie approximately 22/7. How long must the pendulum be of one complete cycle takes 2 seconds? Answer as a fraction or round to at least 2 decimal places.The pendulum must be__ feet.

Answers

we have the formula

[tex]T=2\pi\sqrt{\frac{L}{32}}[/tex]

For T=2 seconds

substitute in the given formula

[tex]\begin{gathered} 2=2\pi\sqrt{\frac{L}{32}} \\ \\ 1=\frac{22}{7}\sqrt{\frac{L}{32}} \\ \\ squared\text{ both sides} \\ \\ (\frac{7}{22})^2=\frac{L}{32} \\ \\ L=\frac{7^2*32}{22^2} \\ \\ L=3.24\text{ ft} \end{gathered}[/tex]

What two variables can you define to write an equation to match this scenario?x = number of minutes for fruit cans and y = number of minutes for vegetable cansx = total number of minutes and y = total number of cansx = number of minutes for fruit and y = total number of cansx = total number of minutes and y = number of minutes for vegetables

Answers

An equation to correctly match this scenario would have to include both separate products. The current order which is 384 cans of food, includes both fruits and vegetables, and therefore any expression that does not include them both would give a wrong answer and the order would not be properly met.

The correct scenario is;

[tex]\begin{gathered} x=Number\text{ of minutes for fruit cans} \\ y=\text{Number of minutes for vegetable cans} \end{gathered}[/tex]

This way you can produce both at a maximum without overproducing one and underproducing the other.

Find the x-intercepts and y-intercept of the following
function.
f(x) = (x+7) (x + 1)(x − 2)
Write your answer in coordinate pairs of the form (x, y).
Provide your answer below:
x-intercept: ().(
]).() and
y-intercept:

Answers

Step-by-step explanation:

there are 3 x-intercepts (the x- values when y = 0). because y is only 0, when one of the 3 factors is 0.

and that is the case for

x = -7

x = -1

x = 2

so, formally, the x- intercepts are

(-7, 0), (-1, 0), (2, 0)

the y intercept is the y- value when x = 0.

(0 + 7)(0 + 1)(0 - 2) = 7×1×-2 = -14

the y-intercept is formally

(0, -14)

Using the GCF you found in Part B, rewrite 72 + 81 as two factors. One factor is the GCF and the other is the sum of two numbers that do not have a common factor. Show your work.

Answers

The factors of 72 and 81 are

[tex]\begin{gathered} 72=2^3\cdot3^2 \\ 81=3^4 \end{gathered}[/tex]

Therefore, their GCF is equal to 3^2=9

Then,

[tex]72+81=9\cdot8+9\cdot9=9(8+9)[/tex]

The answer is 9(8+9).

The factors of 8 and 9 are

[tex]\begin{gathered} 8\to2,4,8 \\ 9\to3,9 \end{gathered}[/tex]

solve the equation for x. x/16=10

Answers

[tex]\frac{x}{16}=\text{ }\frac{10}{1}[/tex]

To solve further cross multiply both sides

so that

[tex]x\text{ }\times1\text{ = 16 }\times10[/tex]

x = 160

Factor the expression using the GCF. 11. 24 - 9 12. 14x + 63

Answers

Recall that the GCF of two ( or more numbers) is the highest number that divides exactly the two numbers.

11.- Notice that:

[tex]\begin{gathered} 24=3\cdot8, \\ 9=3\cdot3. \end{gathered}[/tex]

Therefore:

[tex]9-24=3(8-3)\text{.}[/tex]

12.- Notice that.

[tex]\begin{gathered} 14x=7\cdot2x, \\ 63=7\cdot9. \end{gathered}[/tex]

Therefore:

[tex]14x+63=7(2x+9)\text{.}[/tex]

Answer:

11.-

[tex]3(8-3)\text{.}[/tex]

12.-

[tex]7(2x+9)\text{.}[/tex]

Which of the following statements follows from (x - 3)2 = 7? ox2 +9=7 Ox-3=1 / OX-3 = +49 NEXT QUESTION O ASK FOR HELP

Answers

So, given the equation:

We could take the square root to both sides of the equation to obtain that:

So the correct option is B.

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