Given the number pattern:
20; 18: 14; 8;
a) Determine the nth term of this number pattern.
b) Determine the value of T12 in this number pattern.
c) Which term in this number pattern will have a value of - 36?
A quadratic number pattern has a second term equal to 1, a third term equal to -6 and a fifth term equal to - 14.
a) Calculate the second difference of this quadratic number pattern.
b) Hence, or otherwise, calculate the first term of this number pattern.
Answer:
[tex]\textsf{a)} \quad T_n=-n^2+n+20[/tex]
[tex]\textsf{b)} \quad T_{12}=-112[/tex]
[tex]\textsf{c)} \quad \sf 8th\;term[/tex]
a) Second difference is 2.
b) First term is 10.
Step-by-step explanation:
The given number pattern is:
20, 18, 14, 8, ...To determine the type of sequence, begin by calculating the first differences between consecutive terms:
[tex]20 \underset{-2}{\longrightarrow} 18 \underset{-4}{\longrightarrow} 14 \underset{-6}{\longrightarrow}8[/tex]
As the first differences are not the same, we need to calculate the second differences (the differences between the first differences):
[tex]-2 \underset{-2}{\longrightarrow} -4 \underset{-2}{\longrightarrow} -6[/tex]
As the second differences are the same, the sequence is quadratic and will contain an n² term.
The coefficient of the n² term is half of the second difference.
As the second difference is -2, the coefficient of the n² term is -1.
Now we need to compare -n² with the given sequence (where n is the position of the term in the sequence).
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5}n&1&2&3&4\\\cline{1-5}-n^2&-1&-4&-9&-16\\\cline{1-5}\sf operation&+21&+22&+23&+24\\\cline{1-5}\sf sequence&20&18&14&8\\\cline{1-5}\end{array}[/tex]
We can see that the algebraic operation that takes -n² to the terms of the sequence is to add (n + 20).
[tex]\begin{array}{|c|c|c|c|c|}\cline{1-5}n&1&2&3&4\\\cline{1-5}-n^2&-1&-4&-9&-16\\\cline{1-5}+n&0&-2&-6&-12\\\cline{1-5}+20&20&18&14&8\\\cline{1-5}\sf sequence&20&18&14&8\\\cline{1-5}\end{array}[/tex]
Therefore, the expression to find the the nth term of the given quadratic sequence is:
[tex]\boxed{T_n=-n^2+n+20}[/tex]
To find the value of T₁₂, substitute n = 12 into the nth term equation:
[tex]\begin{aligned}T_{12}&=-(12)^2+(12)+20\\&=-144+12+20\\&=-132+20\\&=-112\end{aligned}[/tex]
Therefore, the 12th term of the number pattern is -112.
To find the position of the term that has a value of -36, substitute Tₙ = -36 into the nth term equation and solve for n:
[tex]\begin{aligned}T_n&=-36\\-n^2+n+20&=-36\\-n^2+n+56&=0\\n^2-n-56&=0\\n^2-8n+7n-56&=0\\n(n-8)+7(n-8)&=0\\(n+7)(n-8)&=0\\\\\implies n&=-7\\\implies n&=8\end{aligned}[/tex]
As the position of the term cannot be negative, the term that has a value of -36 is the 8th term.
[tex]\hrulefill[/tex]
Given terms of a quadratic number pattern:
T₂ = 1T₃ = -6T₅ = -14We know the first differences are negative, since the difference between the second and third terms is -7. Label the unknown differences as -a, -b and -c:
[tex]T_1 \underset{-a}{\longrightarrow} 1 \underset{-7}{\longrightarrow} -6 \underset{-b}{\longrightarrow}T_4 \underset{-c}{\longrightarrow} -14[/tex]
From this we can create three equations:
[tex]T_1-a=1[/tex]
[tex]-6-b=T_4[/tex]
[tex]T_4-c=-14[/tex]
The second differences are the same in a quadratic sequence. Let the second difference be x. (As we don't know the sign of the second difference, keep it as positive for now).
[tex]-a \underset{+x}{\longrightarrow} -7\underset{+x}{\longrightarrow} -b \underset{+x}{\longrightarrow}-c[/tex]
From this we can create three equations:
[tex]-a+x=-7[/tex]
[tex]-7+x=-b[/tex]
[tex]-b+x=-c[/tex]
Substitute the equation for -b into the equation for -c to create an equation for -c in terms of x:
[tex]-c=(-7+x)+x[/tex]
[tex]-c=2x-7[/tex]
Substitute the equations for -b and -c (in terms of x) into the second two equations created from the first differences to create two equations for T₄ in terms of x:
[tex]\begin{aligned}-6-b&=T_4\\-6-7+x&=T_4\\T_4&=x-13\end{aligned}[/tex]
[tex]\begin{aligned}T_4-c&=-14\\T_4+2x-7&=-14\\T_4&=-2x-7\\\end{aligned}[/tex]
Solve for x by equating the two equations for T₄:
[tex]\begin{aligned}T_4&=T_4\\x-13&=-2x-7\\3x&=6\\x&=2\end{aligned}[/tex]
Therefore, the second difference is 2.
Substitute the found value of x into the equations for -a, -b and -c to find the first differences:
[tex]-a+2=-7 \implies -a=-9[/tex]
[tex]-7+2=-b \implies -b=-5[/tex]
[tex]-5+2=-c \implies -c=-3[/tex]
Therefore, the first differences are:
[tex]T_1 \underset{-9}{\longrightarrow} 1 \underset{-7}{\longrightarrow} -6 \underset{-5}{\longrightarrow}T_4 \underset{-3}{\longrightarrow} -14[/tex]
Finally, calculate the first term:
[tex]\begin{aligned}T_1-9&=1\\T_1&=1+9\\T_1&=10\end{aligned}[/tex]
Therefore, the first term in the number pattern is 10.
[tex]10 \underset{-9}{\longrightarrow} 1 \underset{-7}{\longrightarrow} -6 \underset{-5}{\longrightarrow}-11 \underset{-3}{\longrightarrow} -14[/tex]
Note: The equation for the nth term is:
[tex]\boxed{T_n=n^2-12n+21}[/tex]
Describe the transformations of each equation
The required answer are :
6. The transformation from the graph of f to the graph of r in equation (6) involves compressing the graph horizontally by a factor of 5/2.
7. The transformation from the graph of f to the graph of r in equation (7) involves stretching the graph vertically by a factor of 6.
8. The transformation from the graph of f to the graph of r in equation (8) involves shifting the graph horizontally to the right by 3 units.
9. The transformation from the graph of f to the graph of r in equation (9) involves compressing the graph horizontally by a factor of 4/3.
10. The transformation from the graph of f to the graph of r in equation (10) involves shrinking the graph vertically by a factor of 1/2.
11. The transformation from the graph of f to the graph of r in equation (11) involves shifting the graph vertically upward by 3 units.
In formula form: r(x) = f(2/5x)
This transformation causes the graph of r to become narrower compared to the graph of f, as it is compressed horizontally. The rate at which x-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is narrower and more compact.
Therefore, the transformation from the graph of f to the graph of r in equation (6) involves compressing the graph horizontally by a factor of 5/2. This means that every x-coordinate in the graph of f is multiplied by 2/5 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.
In formula form: r(x) = 6f(x)
This transformation causes the graph of r to become taller compared to the graph of f, as it is stretched vertically. The rate at which y-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is taller and more elongated.
Therefore, the transformation from the graph of f to the graph of r in equation (7) involves stretching the graph vertically by a factor of 6. This means that every y-coordinate in the graph of f is multiplied by 6 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.
In formula form: g(x) = f(x - 3)
This transformation causes the entire graph of f to shift to the right by 3 units. Every point on the graph of f moves horizontally to the right, maintaining the same vertical position. The overall shape and slope of the graph remain the same, but it is shifted to the right.
Therefore, the transformation from the graph of f to the graph of r in equation (8) involves shifting the graph horizontally to the right by 3 units. This means that each x-coordinate in the graph of f is increased by 3 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.
In formula form: g(x) = f(4/3x)
This transformation causes the graph of r to become narrower compared to the graph of f, as it is compressed horizontally. The rate at which x-values change is increased, resulting in a steeper slope. The overall shape and direction of the graph remain the same, but it is narrower and more compact.
Therefore, the transformation from the graph of f to the graph of r in equation (9) involves compressing the graph horizontally by a factor of 4/3. This means that every x-coordinate in the graph of f is multiplied by 4/3 to obtain the corresponding x-coordinate in the graph of r. The vertical positioning of the graph remains unchanged.
In formula form: g(x) = 1/2 f(x)
This transformation causes the graph of r to become shorter compared to the graph of f, as it is vertically shrunk. The rate at which y-values change is decreased, resulting in a flatter slope. The overall shape and direction of the graph remain the same, but it is shorter and more compact.
The transformation from the graph of f to the graph of r in equation (10) involves shrinking the graph vertically by a factor of 1/2. This means that every y-coordinate in the graph of f is multiplied by 1/2 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.
In formula form: g(x) = f(x) + 3
This transformation causes the entire graph of f to shift upward by 3 units. Every point on the graph of f moves vertically upward, maintaining the same horizontal position. The overall shape and slope of the graph remain the same, but it is shifted upward.
The transformation from the graph of f to the graph of r in equation (11) involves shifting the graph vertically upward by 3 units. This means that every y-coordinate in the graph of f is increased by 3 to obtain the corresponding y-coordinate in the graph of r. The horizontal positioning of the graph remains unchanged.
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Solve following modular equation, using reverse Euclidean algorithm:
[tex](5 * x) mod 91 = 32[/tex]
The required reverse Euclidean algorithm is the solution to the modular equation (5x) mod 91 is
x = 6(mod 91).
Given that (5*x) mod 91 =32.
To solve the modular equation (5*x) mod 91 =32 using reverse Euclidean algorithm is to find the modular inverse of 5 modulo 91.
Consider (5*x) mod 91 =32.
5x = 32(mod 91)
Apply the Euclidean algorithm to find GCD of 5 and 91 is
91 = 18 * 5 + 1.
Rewrite it in congruence form,
1 = 91 - 18 *5
On simplifying the equation,
1 = 91 (mod 5)
The modular inverse of 5 modulo 91 is 18.
Multiply equation by 18 on both sides,
90x = 576 (mod91)
To obtain the smallest positive solution,
91:576 = 6 (mod 91)
Divide both sides by the coefficient of x:
x = 6 * 90^(-1).
Apply the Euclidean algorithm,
91 = 1*90 + 1.
Simplify the equation,
1 + 1 mod (90)
The modular inverse of 90 modulo 91 is 1.
Substitute the modular inverse in the given question gives,
x = 6*1(mod 91)
x= 6 (mod91)
Therefore, the solution to the modular equation (5x) mod 91 is
x = 6(mod 91).
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Tariq has $640 to spend at a bicycle store for some new gear and biking outfits. Assume all prices listed include tax.
He buys a new bicycle for $291.24.
He buys 4 bicycle reflectors for $19.56 each and a pair of bike gloves for $16.52.
He plans to spend some or all of the money he has left to buy new biking outfits for $50.80 each.
Write and solve an inequality which can be used to determine
x, the number of outfits Tariq can purchase while staying within his budget.
Let's solve the inequality to determine the number of outfits Tariq can purchase while staying within his budget.
Given:
Amount Tariq has to spend: $640
Cost of a new bicycle: $291.24
Cost of 4 bicycle reflectors: $19.56 each
Cost of bike gloves: $16.52
Cost of each biking outfit: $50.80
Let's assume the number of outfits Tariq can purchase is represented by x.
The total cost of the items he has already purchased is:
Cost of bicycle = $291.24
Cost of 4 bicycle reflectors = $19.56 * 4 = $78.24
Cost of bike gloves = $16.52
The remaining amount Tariq has to spend can be calculated as:
Remaining amount = Total amount - (Cost of bicycle + Cost of reflectors + Cost of gloves)
Remaining amount = $640 - ($291.24 + $78.24 + $16.52)
Now, we need to determine the maximum number of outfits Tariq can purchase with the remaining amount. Each outfit costs $50.80.
Inequality: x * $50.80 ≤ Remaining amount
Substituting the values:
x * $50.80 ≤ $640 - ($291.24 + $78.24 + $16.52)
Simplifying further:
x * $50.80 ≤ $640 - $385
x * $50.80 ≤ $255
To solve for x, we divide both sides of the inequality by $50.80:
x ≤ $255 / $50.80
x ≤ 5
Therefore, the maximum number of outfits Tariq can purchase while staying within his budget is 5.
Which country is directly east of the Atlantic Ocean?
Julle is selling candy bare to raise money for new band uniforms. Candy bar x sells for $2 and candy bar y sells for $3. The number of y candy bare Julla sells must be greater than or equal to three times the number of x candy bars she sells. She has at most 36 candy bars to sell. What is the maximum revenue she can make?
Answer:
n this question, you are asked how much the maximum revenue. Since candy Y sold for a higher price than candy X, that means you have to sell candy Y as much as possible.The number of candy Y must be >= 3 times candy X. Since this won't limit candy Y selling, then you can convert all 36 candy into candy Y and 0 candy X36 candy (Y) >= 0 candy(X) ----> the requirement is met.The revenue would be 36 candy Y * $3/candy Y= $108
Step-by-step explanation:
Triangle LMIN with vertices L(2, -8), M(12, 8),
and N(14,-4): * = ½
The vertices of triangle image are L'(1, -4), M'(6, 4) and N'(7, -2).
Given that, triangle LMIN with vertices L(2, -8), M(12, 8) and N(14,-4).
Here, scale factor k=1/2
Now, by applying scale factor to the vertices, we get
L(2, -8)→1/2 (2, -8)→L'(1, -4)
M(12, 8)→1/2 (12, 8)→M'(6, 4)
N(14,-4)→1/2 (14, -4)→N'(7, -2)
Therefore, the vertices of triangle image are L'(1, -4), M'(6, 4) and N'(7, -2).
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"Your question is incomplete, probably the complete question/missing part is:"
Triangle LMIN with vertices L(2, -8), M(12, 8), and N(14,-4): k = ½.
Multiplying polynomials (7x - 5)(6x - 4)
The product of (7x - 5)(6x - 4) is 42x^2 - 58x + 20.
First, distribute the first term of the first polynomial (7x) to each term in the second polynomial (6x - 4):
7x × 6x = 42x²
7x × (-4) = -28x
Next, distribute the second term of the first polynomial (-5) to each term in the second polynomial (6x - 4):
-5 × 6x = -30x
-5 × (-4) = 20
Now, combine the like terms:
42x² - 28x - 30x + 20
Simplify the expression:
42x² - 58x + 20
Therefore, the product of (7x - 5)(6x - 4) is 42x^2 - 58x + 20.
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Each morning, Sleepwell Hotel offers its guests a free continental breakfast with pastries and orange juice. The hotel served 540 gallons of orange juice last year. This year, the hotel served 5% less orange juice than it did the previous year. How much was served this year
The amount of juice served this year is given as follows:
513 gallons.
How to obtain the amount of juice?The amount of juice served this year is obtained applying the proportions in the context of the problem.
The amount last year was given as follows:
540 gallons.
The percentage of this year's amount relative to last year's amount is given as follows:
95%, due to the decay of 5%, 100 - 5 = 95%.
Hence the amount of juice served this year is given as follows:
0.95 x 540 = 513 gallons.
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10 cm
15 cm
17 cm
5 cm
What is the volume of this figure?
6 cm
10 cm
The Volume of Trapezoidal prism is 420 cm².
From the given figure we can write the dimension of the prism as
a = 5, b=15, c= 15, d= 15
h= 7 and l = 6 cm
Now, Volume of Trapezoidal prism
= 1/2 (a+b) x h x l
= 1/2 (5+15) x 7 x 6
= 1/2 x 20 x 42
= 10 x 42
= 420 cm²
Thus, the Volume of Trapezoidal prism is 420 cm².
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Jane wants to estimate the proportion of students on her campus who eat cauliflower. After surveying 35 students, she finds 4 who eat cauliflower. Obtain and interpret a 99% confidence interval for the proportion of students who eat cauliflower on Jane's campus using Agresti and Coull's method. Click the icon to view Agresti and Coull's method. Construct and interpret the 99% confidence interval. Select the correct choice below and fill in the answer boxes within your choice. (Round to three decimal places as needed.) A. There is a 99% chance that the proportion of students who eat cauliflower on Jane's campus is between Jane's and OB. One is 99% confident that the proportion of students who eat cauliflower on Jane's campus is between OC. There is a 99% chance that the proportion of students who eat cauliflower in Jane's sample is between OD. The proportion of students who eat cauliflower on Jane's campus is between and 99% of the time. and and
Based on the information, A. There is a 99% chance that the proportion of students who eat cauliflower on Jane's campus is between 5.03% and 17.83%.
How to calculate the valueCalculate the sample proportion:
= x / n = 4 / 35
= 0.1143
Calculate the Agresti and Coull's adjustment factor:
zα/2 = z(1 - α/2) = z(1 - 0.99/2)
= 2.576
Calculate the margin of error:
= 2.576 √(0.1143(1 - 0.1143) / 35)
= 0.064
Calculate the confidence interval:
= 0.1143 ± 0.064
= (0.0503, 0.1783)
We are 99% confident that the true proportion of students who eat cauliflower on Jane's campus is between 5.03% and 17.83%.
In other words, if we were to repeat this study many times, we would expect to obtain a confidence interval that includes the true proportion of students who eat cauliflower on Jane's campus 99% of the time.
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An expression is shown. 2 + 2(x – 3) – 5x Which expression is equivalent to the expression shown? –3x – 4 –3x – 1 –x – 12 –x – 3
The other options provided, -3x - 1, -x - 12, and -x - 3, do not match the simplified form of the given expression. Only -3x - 4 corresponds to the original expression after simplification. It is important to carefully distribute and combine like terms to simplify expressions correctly.
The expression shown is 2 + 2(x – 3) – 5x. To find an equivalent expression, we need to distribute the 2 to both terms inside the parentheses, resulting in 2x - 6. Now we can simplify the expression further:
2 + 2x - 6 - 5x
Combining like terms, we have:
(2x - 5x) + (2 - 6)
This simplifies to:
-3x - 4
Hence, the expression -3x - 4 is equivalent to 2 + 2(x – 3) – 5x.
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The temperature is 12 celcius when the altitude is 3,000 meters above sea level.At a higher altitude the temperature reads 4 celcius.Was there an increase or decrease in the temperature?
Answer:
Decrease in temp.
Step-by-step explanation:
Here is the reason:
Initially, at an altitude of 3,000 meters above sea level, the temperature was 12 degrees Celsius. As the altitude increased, the temperature dropped to 4 degrees Celsius. Since the temperature decreased from 12 degrees Celsius to 4 degrees Celsius, there was a decrease in the temperature
What is the value of x?.
4
B
24
Q
R
15
40
C
X
1 2
The value of x would be,
⇒ x = 15
We have to given that;
A figure with QC is parallel to BR
Now, We can formulate that,
Triangle BDR and triangle CDQ are similar.
Hence, By using proportionality we get;
⇒ BD / DR = QD / CD
Substitute all the values we get;
⇒ (24 + 40) / (15 + x) = 40 / x
Solve for x,
⇒ 64 / (15 + x) = 40 / x
⇒ 64x = 40 (15 + x)
⇒ 8x = 5 (15 + x)
⇒ 8x = 45 + 5x
⇒ 8x - 5x = 45
⇒ 3x = 45
⇒ x = 15
Thus, The value of x would be,
⇒ x = 15
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30 points !! :) Thank you in advance
The solutions of the quadratic equation are: x = 1
The x-intercept is x = 1
What is the Solution to the quadratic equations?The formula for the equation of a line in slope intercept form is:
y = mx + c
where:
m is slope
c is y-intercept
The y-intercept is the point at which the graph crosses the y-axis and in this case it is: y = 1
The x-intercepts are where the graph touches the x-axis and in this case, it is x = 1
The zeros of the quadratic equation are the x-intercepts and since the curve does not cross, then we can say that the zeros are x = 1 and x = 1 which signifies double root and as such the solution is x = 1
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helppp!! someone help me asappp
Answer:
[(5 ± √(29)) ÷ 2]
Step-by-step explanation:
x = [(-b ± √(b² - 4ac)) ÷ 2a]
= [(-(-5) ± √((-5)² - 4(1)(-1))) ÷ 2(1)]
= [(5 ± √(25 + 4)) ÷ 2]
= [(5 ± √(29)) ÷ 2]
Brian cut of 25% of a stick which was 1.6 meters long what percent of the stick is remaining
Answer:
The remaining is 75%, the length of the stick would be 1.2
Step-by-step explanation:
According to the information given,
We know that Brian cut off 25% of a stick which was 1.6 meters long
and 1.6 is the 100% of the stick:
It is fairly easy to calculate this, subtract 25 from 100 ( 100 - 25 ), which is equal to 75.
Hence, the answer is 75% and 1.2 for the remaining length of the stick
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Which statements are true of the graph of h(x) = 3√x-4? Check all that apply.
The domain of h(x) is the set of all real numbers.
The range of h(x) is the set of all real numbers.
For all points (x, h(x)), h(x) exists if and only if x - 4
2
O The graph of h(x) is a translation of f(x) down 4 units.
O The graph of h(x) intercepts the x-axis at (4, 0).
The true statements about the graph of h(x) = ∛(x-4) are:
The domain of h(x) is the set of all real numbers.
For all points (x, h(x)), h(x) exists if and only if x - 4≥0
The graph of h(x) intercepts the x-axis at (4, 0).
The domain of h(x) is the set of all real numbers since there are no restrictions on the input variable x.
For all points (x, h(x)), h(x) exists if and only if x - 4 ≥ 0. This is because the cube root function is only defined for non-negative values, and the expression inside the cube root, x - 4, must be non-negative for h(x) to exist.
The graph of h(x) intercepts the x-axis at (4, 0) since plugging in x = 4 into the equation gives h(4) = ∛(4-4) = ∛0 = 0. This means that the point (4, 0) lies on the graph.
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b. Does there appear to be any relationship between these two variables?
a. colder average low-temperature seems to lead to higher amounts of snowfall
b. there is no relationship
c. colder average low-temperature seems to lead to lower amounts of snowfall
c. Based on the scatter diagram, comment on any data points that seem to be unusual.
an average snowfall of nearly 100 inches.
a. no city has
b. only one city has
c. two cities have
d. three cities have
e. four cities have
f. more than four cities have
1. There is no relationship
2. Two cities have an average snowfall of nearly 100 inches.
What is the scatter plot?
A scatter plot, also known as a scatter diagram or scatter graph, displays the relationship between two variables. It is particularly beneficial for identifying any patterns or trends in the data and showing how one variable might be related to another.
In a scatter plot, each data point is represented on the graph by a dot or marker. The horizontal axis (x-axis) is frequently used to represent the independent variable or predictor, while the vertical axis (y-axis) is frequently used to represent the dependent variable or reaction. Each dot's locations on the graph correspond to the values of the two variables for that particular data point.
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Find the value of x to
the nearest whole
number.
Answer: i'm kind of just guessing, but i think x = 13
Step-by-step explanation:
please don't ask me how i don't know
Consider the line 3x+2y=-1.
Find the equation of the line that is perpendicular to this line and passes through the point (5, 3).
Find the equation of the line that is parallel to this line and passes through the point (5, 3).
Note that the ALEKS graphing calculator may be helpful in checking your answer.
Equation of perpendicular line:
Equation of parallel line:
0
Pleaseseee help
Two one-step equations
Two equations that contains fractions
One equation with distributive property
One equation with decimals
One real-world problem that is solved by an equation
Remember that each equation must include at least one variable
please help
The road trip will take approximately 5 hours.
Two one-step equations:
a) 2x + 5 = 13
In this equation, the variable 'x' represents an unknown number. By performing one step of subtraction, we can find the value of 'x' that makes the equation true.
The solution is x = 4.
b) 3y - 7 = 16
Similar to the first equation, 'y' represents an unknown number.
By adding 7 to both sides of the equation, we can isolate the variable and solve for 'y.'
The solution is y = 7.
Two equations with fractions:
a) (1/3)x + 2 = 5
Here, the variable 'x' is multiplied by a fraction.
To isolate 'x,' we can subtract 2 from both sides and then multiply both sides by the reciprocal of 1/3, which is 3/1.
The solution is x = 9.
b) (2/5)y - 3 = 1
In this equation, 'y' is multiplied by a fraction.
We can isolate 'y' by adding 3 to both sides and then multiplying both sides by the reciprocal of 2/5, which is 5/2.
The solution is y = 4.
One equation with the distributive property:
a) 2(x + 3) = 10
This equation demonstrates the distributive property.
By applying it, we multiply 2 by both x and 3, resulting in 2x + 6 = 10.
We can then solve for 'x' by subtracting 6 from both sides.
The solution is x = 2.
One equation with decimals:
a) 0.4x + 0.8 = 1.6
In this equation, 'x' is multiplied by a decimal.
To isolate 'x,' we subtract 0.8 from both sides and then divide both sides by 0.4.
The solution is x = 2.
Real-world problem:
Imagine you're planning a road trip.
The distance you'll be traveling is 250 miles, and your car's average speed is 50 miles per hour.
You want to determine how long the trip will take.
Let 't' represent the time in hours it will take to complete the trip.
The equation that represents this situation is:
50t = 250
By dividing both sides of the equation by 50, we find that t = 5.
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Please only answer if u actually know pls!
At a price of $3, the total revenue will be the greatest, and the company will sell 3 units at that price.
To find the total revenue at each price, we can multiply the price by the corresponding quantity.
Price Quantity Total Revenue
$6 0 $0
$5 1 $5
$4 2 $8
$3 3 $9
$2 4 $8
$1 5 $5
To find the price at which total revenue is the greatest, we look for the highest value in the Total Revenue column.
In this case, the highest total revenue is $9, which occurs when the price is $3.
At a price of $3, the company will sell 3 units (as indicated in the Quantity column).
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What is the correct order of the functions from least to greatest according to the average rate of
change on the interval from x=-1 to x-3? (2 points)
The correct option is the second one, the order is:
g(x), f(x), h(x).
How to find the rates of change?To find the rate of change for a function f(x) on an interval [a, b] we need to get:
R = (f(b) - f(a))/(b - a)
Here the interval is [-1, 3]
The first function is:
f(x)= (x + 3)² - 2
Evaluating we get:
f(-1) = (-1 + 3)² - 2
f(-1) = 2² - 2 = 4 -2 = 2
and f(3) = (3 + 3)² - 2 = 34
Then the rate is:
R = (34 - 2)/(3 + 1) = 8
For g(x) we can use the graph, we have:
R = (0 + 2)/4 = 1/2
For the last function we need to use the table, then we will get:
R = (62 - 14)/(3 + 1) = 12
Then the order, from least to greatest is:
g(x), f(x), h(x).
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What is the meaning of "The set of all functions from X to Y"?
"The set of all functions from X to Y" refers to the collection of all possible functions that can be defined from a set X to a set Y. This set is denoted as Y^X or X→Y.
Each element of the set Y^X is a function that maps each element of set X to a unique element of set Y. The notation for such a function f is f: X → Y.
Given,
f is a function from X to Y .
Note:
The cardinality (size) of the set Y^X is given by |Y^X| = |Y|^|X|. In other words, if the set X has m elements and the set Y has n elements, then the set of all functions from X to Y has n^m elements.
It is often used to describe the space of all possible solutions to a given problem or equation.
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PLEASE ANSWER ASAP!!
Answer:
-8 and 4
Step-by-step explanation:
P= -2
-2+6 = 4
-2-8= -8
A statue that is 25 feet tall casts a shadow that is 16 feet long. A cement pose next to the statue is 4 feet tall. find the length of the cement post’s statue.
The length of the cement post's statue is 6.25 feet.
How to calculate the length of the cement post's statue?We shall use Mathematical operators to compute the length of the cement post's statue.
(Height of the statue) / (Length of the shadow) = (Height of the cement post's statue) / (Height of the cement post)
Given:
Height of the statue = 25 feet
Length of the shadow = 16 feet
Height of the cement post = 4 feet
Let x = length of the cement post's statue
25 feet / 16 feet = x / 4 feet
To find x, we cross-multiply:
25 * 4 = 16 * x
100 = 16 * x
To isolate x, we divide both sides of the equation by 16 feet:
100 / 16 = x
x ≈ 6.25 feet
Therefore, the length of the cement post's statue is 6.25 feet.
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Please answer the attached question
Answer:
∠ DFG = 48°
Step-by-step explanation:
the central angle is equal to the measure of the arc that subtends it.
since EOG is the diameter of the circle with central angle of 180° , then
arc EG = 180°
the inscribed angle EGD is half the measure of the arc ED that subtends it, so
arc ED = 2 × ∠ EGD = 2 × 42° = 84° , then
ED + DG = EG , that is
84° + DG = 180° ( subtract 84° from both sides )
DG = 96°
Then
∠ DFG = [tex]\frac{1}{2}[/tex] × EG = [tex]\frac{1}{2}[/tex] × 96° = 48°
What change in volume results if 60.0 mL of gas is cooled from 33.0°C to 5.00°C
Answer:
The change in volume is -5.5 mL (a decrease in volume of 5.5 mL) when 60.0 mL of gas is cooled from 33.0°C to 5.00°C.
Step-by-step explanation:
To calculate the change in volume, we need to use the ideal gas law equation:
V1/T1 = V2/T2
where V1 and T1 are the initial volume and temperature, and V2 and T2 are the final volume and temperature.
Given:
V1 = 60.0 mL
T1 = 33.0°C = 33.0 + 273.15 = 306.15 K
T2 = 5.00°C = 5.00 + 273.15 = 278.15 K
Now we can calculate V2, the final volume:
V1/T1 = V2/T2
(60.0 mL) / (306.15 K) = V2 / (278.15 K)
Cross-multiplying and solving for V2:
V2 = (60.0 mL) * (278.15 K) / (306.15 K)
V2 = 54.5 mL
The final volume, V2, is 54.5 mL.
To find the change in volume, we subtract the initial volume from the final volume:
Change in volume = V2 - V1
Change in volume = 54.5 mL - 60.0 mL
Change in volume = -5.5 mL
Therefore, the change in volume is -5.5 mL (a decrease in volume of 5.5 mL) when 60.0 mL of gas is cooled from 33.0°C to 5.00°C.
Show work and number
The measure of length of the triangle is solved and
a) x = 4.9 units
b) x = 14 units
c) x = 4.8 cm
d) b = 68.5 units
Given data ,
Let the triangle be represented as ΔABC
where the measure of the lengths of the sides are given as
a)
The measure of hypotenuse AC = 12
The measure of angle ∠BAC = 66°
So , from the trigonometric relations , we get
cos θ = adjacent / hypotenuse
cos 66° = x / 12
So , x = 12 cos ( 66 )°
x = 4.9 units
b)
The measure of base of triangle BC = 20 units
And , the angle ∠BAC = 55°
So , from the trigonometric relations , we get
tan θ = opposite / adjacent
tan 55° = 20/x
x = 20 / tan55°
x = 14 units
c)
The measure of base of triangle BC = 4 cm
And , the angle ∠BAC = 57°
So , from the trigonometric relations , we get
sin θ = opposite / hypotenuse
sin 57° = 4/x
x = 4 / sin 57°
x = 4.8 cm
d)
The measure of base of triangle BC = 38 units
And , the angle ∠BAC = 61°
So , from the trigonometric relations , we get
tan θ = opposite / adjacent
tan 61° = b/38
b = 38 x tan 61°
b = 68.5 units
Hence , the trigonometric relations are solved.
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