Answer:
600 N upward
Explanation:
According to Newton's third law, for every action their is an equal and opposite reaction. The equal and opposite reaction to a downward force of magnitude 600 N is an upward force of magnitude 600 N
how do sound waves behave as a solid
a. they travel faster in a solid than other mediums
b. they travel slower in a solid than other solids
c. they stop when they hit a solid
d.sound waves behave the same in any medium
Answer:
A. They travel faster in a solid than other mediums
Explanation:
Sound waves travel faster in solids because the density of solids is higher than that of liquids which means that the particles are closer together and sound can be transmitted more easily.
i need working steps and answers
Explanation:
I will definitely explain you if you follow me please
You had an amazing race. You finished the 300kms race in 1hr 40 minutes. What is the average velocity?
Average Velocity
Level : JHSv = s/t
v = 300 km/(1 hour + 40/60 hour)
v = 300 km/(1.66 hour)
v = 180 km/hour
#LearnWithEXO
Suppose that John lives on a square block that is 180 yards per side, and in the evenings, he walks with his dog around the block for a little exercise.
A) If John walks once around the block, what distance does he travel?
B) If John walks once around the block, what is his final displacement?
Answer:
It's A
Explanation:
Although I'm not sure about the second one, I'm sure the first one is A
Is the answer 0.055 seconds? (Only problem 13)
Answer:
155÷8.5
=18.235294117647
A rubber duck of volume 2,500cm3 floats in water with 20% of its volume submerged. You want to hold the duck under water so it is at rest and completely submerged. How much force do you have to apply? If you release the duck, what will be its acceleration at that instant?
The force applied to the submerged rubber duck is 4.9 N.
Density of the rubber duck
The density of the rubber duck is calculated as follows;
ρ = S.G x density of water
ρ = 0.2 x 1000 kg/m³
ρ = 200 kg/m³
Force applied to the duckF = mg = (ρV)g
F = (200 x 0.0025) x 9.8
F = 4.9 N
Learn more about density and force here: https://brainly.com/question/952755
Imagine that you are immersed under a beautiful cosmic meteor shower. Which
instrument would BEST help you view the largest portion of the sky?
refracting telescope
binoculars
sextant
compound telescope
Answer:
binoculars
Explanation: I am taking astronomy
Answer: B) binoculars just took the test
Explanation:
Children start to gain control over their attention beginning in preschool. This control is related to a growth
spurt in the brain's lobe.
Answer:
occipital parietal
Explanation:
Hope this helps, plus I took the test
bus travels 6 km east and then 8 km south. What is the displacement?
Answer:
d = √(6² + 8²) = 10 km
Explanation:
displacement is a vector and subject to vector addition.
In the free-body diagram, what is the net force? (Hint-Trig.- SOH-CAH-TOA)
a. 35 N right
b. 28 N right
c. 75 N
Help on these two thanks
Answer:
8. Friction
9. Net force
Explanation:
Hope this helps you. Have a nice day. :)
A racecar begins at rest and accelerates to 25 m/s at a rate of 6.25 m/s2. What distance does the racecar cover?
a.
2 m
b.
156 m
c.
4 m
d.
50 m
Answer:
d.
50 m
Explanation:
v² = u² + 2as
s = (v² - u²) / 2a
s =(25² - 0²) / (2(6.25))
s = 50 m
A canoe is designed to have very little drag when it moves along its length. Riley, mass 62 kg, sits in a 21 kg canoe in the middle of a lake. She dives into the water off the front of the canoe, along the axis of the canoe. She dives forward at 1.7 m/s relative to the boat.
1) Just after her leap, how fast is she moving relative to the water?
2) Just after her leap, how fast is the canoe moving relative to the water?
(1) Riley velocity relative to the water after she jumps is 1.7 m/s.
(2) The velocity of the canoe relative to the water is 5.02 m/s.
The given parameters;
mass of Riley, m₁ = 62 kgmass of canoe, m₂ = 21 kg velocity of the Riley after jumping, v₁ = 1.7 m/s(1) Since the lake is still, her velocity relative to the water after she jumps is 1.7 m/s.
(2) Apply the principle of conservation of linear momentum;
m₁v₁ = m₂v₂
62 x 1.7 = 21v₂
105.4 = 21v₂
[tex]v_2 = \frac{105.4}{21} \\\\v_2 = 5.02 \ m/s[/tex]
Thus, after her leap, the velocity of the canoe relative to the water is 5.02 m/s.
Learn more here:https://brainly.com/question/12803552
How much force (in Newtons) is needed to accelerate a 160 kg object at a rate of 4 m/s2?
A. 15
B. 40
C. 640
D. .025
Answer:
C. 640
Explanation:
The minimum force would occur in a frictionless environment and act parallel to any abutting surface.
F = ma = 160(4) = 640 N
A 5.7 kg block slides along a horizontal surface toward a horizontally mounted spring with a spring constant of 150 N/m. At one instant, the block is 5.0 m from the end of the spring and has a speed of 12.0 m/s. If the surface is frictionless, what is the maximum compression of the spring
Hi there!
We can use the conservation of energy:
Ei = Ef
The initial energy involves kinetic energy while the final energy involves maximum elastic potential energy, so:
1/2mv² = 1/2kx²
We can cancel out the 1/2s for ease of solving:
mv² = kx²
Plug in given values to solve for x:
√(mv²/k) = x
√(5.7)(12²)/(150)) = x
x = 2.339 m
Write the number below in scientific notation, 35,600 O A. 3.56 x 103 O B. 3.56 x 103 O C. 3.56 x 104 O D. 3.56 x 105
the force of gravity on Mars is 3.7 m/s^2. what is the force of gravity on Earth?
How much protein would be consumed with a 3-ounce serving of
this food?
A. 0g
B. 5g
C. 10g
D.15g
Please Help me
Answer:
15kg
(i actually did this)
Explanation:
k12
hope this helped!
i hope you ace it!
Answer: B) 5g
I took the 4.11 Unit Test: Nutrition quiz.
on earth what is the weight of a large screen tv thas has amass of 75 kg
Answer:
Explanation:
F = mg
F = 75(9.8)
F = 735 N
A driver spotted a police car and he braked from a speed of 100 km/h to a speed of 80 km/h during a displacement of 88 m at a constant acceleration? What is that acceleration, and how much time is required for the given decrease in speed?
Answer:
Explanation:
100 kph = 27.8 m/s
80 kph = 22.2 m/s
v² = u² + 2as
a = (v² - u²) / 2s
a = (22.2² - 27.8²) / (2(88))
a = -1.578282828...
a = -1.58 m/s²
t negative sign means the acceleration opposes the initial velocity.
t = Δv/a
t = (22.2 - 27.8) / -1.57828
t = 3.52 s
Anne pushed a cart by 12 N. How far did the cart move if the work done was 9 J?
[tex]\\ \sf\longmapsto W=Fd[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{W}{F}[/tex]
[tex]\\ \sf\longmapsto d=\dfrac{9}{12}=0.72m[/tex]
Answer:
Anne pushed a cart by 12 N.
● Force = 12 N
Work done is 9 J
● Work = 9 J
=> Work = Force × distance
[tex]=> distance = \frac{work}{force} [/tex]
[tex]=> distance = \frac{9}{2} [/tex]
[tex]=> distance = 0.72m[/tex]
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What is three famous people you know
Answer:
Martin Luther King Jr., Mark Zuckerburg, Jeff Bezos
Explanation:
First 3 people to come to my head.
If 1 light year = 9.46x 1015.
m and 1 mile = 1.6 km, how many miles are in a light year? You
Answer:
5 912 500 000 000 = 5.91x10^12 miles
Explanation:
The first thing we need to do is convert the light year distance to kilometres, since we have the kilometre to mile conversion. There are 1000m in a kilometre, so we need to divide the light year value that we have by 1000, giving us 9.46x10^12 km for 1 light year.
Now that we have our value in kilometres, we simply need to divide it by 1.6 to get it in miles. Doing so gives us 5 912 500 000 000 miles, or 5.91x10^12 miles.
Hope that made sense, and let me know if you have any further questions!
please answer me!!! asappp
Answer:
omg this is hard
Explanation:
Yes it is lol
When you view the pendulum’s swing, it shows that at the very top of the swing KE = 0. What does that tell you about the pendulum’s motion at that point?
it tells you that it has a lot of force
Answer:
Since I couldn't find the other answers to the same question, I wrote the wrong answer to help ya'll get the sample response. So here's from Edge
Explanation:
Sample Response: If KE = 0, the pendulum is not moving. At the top of the swing, the pendulum must stop for a brief moment.
hi i think it 573 udaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa
Answer:
ummm I didn't understand the question
a ball thrown horizontally with the velocity of 20 m\s from a 20 m building .what is the time
Answer:2.02s
Explanation:
At the y component, the tract of the ball is free falling body. The initial velocity at y component is 0 m/s.
Height = 1/2 * g * t^2
20 = 1/2 * 9.8 * t^2
t = (20 * 2 / 9.8)^1/2, t = 2.02s
Write down the units for the following physical quantities:
a. Velocity
b. Acceleration
c. Momentum
d. Force
e. Power
f. Energy
g. Pressure
A 55-kg person lands on firm ground after jumping from a height of 2.8 m.
Explanation:
What are you searching for?
Potential energy?
Answer:
3018.4
Explanation:
So this velocity just before reaching the ground, the final equals square root of two times G times H. So gs 9.8 m per second squared H is 2.8 m. So it gives the velocity of 7.41 m per second squared. That's the velocity right before touching the ground. So to find the impulse required to come to rest here, we just do mass times the velocity minus zero. So zero is the final momentum, final velocity zero. So that makes the final momentum zero. So we multiply the mass with the velocity before touching the ground and after. And subject zero. That's the momentum after touching the ground. So we multiply mass 55 kg. At 7.41 velocity we got 407.45. kilograms meters per second of impulse. we know that the force will be larger for stiff stiff flex compared to bend flex. Because the stiff flex. Bring the object to rest in a short amount of time and distance. So in part C, that's calculate for stiff flex. The stopping distance, Delta Y. Is 0.1 m. This one centimeter. So we can calculate the acceleration of the body when it comes to rest. From the moment it touches the ground. equals v squared over two times Delta Y. So we use the square is 54.88. The 7.41 square divided by two times 0.01 gives us an explosion of 2744 m/s square. So you multiply this acceleration by the mass to get the force so force equals mass times acceleration gives us a large force, 159 20 newtons. Then for bent legs, repeat the same process with a different delta Y, delta Y of 200.5 m. So that's 50 centimeters and calculate acceleration the same process. Just use a different value of delta Y. And we get as much smaller acceleration 54.88 m per second square. And the force experience would just be mass times acceleration. That gives us 3018.4 newton's a lot smaller than for stiff flex.
Độ hấp thụ của dung dịch có độ truyền qua 30% ở bước sóng 640nm là bao nhiêu?